Answer:
4.12 m/s^2
Explanation:
unbalanced force means the presence of resultant force (net force)
\(net \: force \: = mass \times accleration\)
f = 28N
m = 6.8kg
a = ?
? = 28/6.8
= 4.1176...
approximately = 4.12 m/s^2
The diagram below depicts a game of tug of war between Person A and Person B. Person A pulls the rope with a force of FA while Person B pulls with force FB.
If FB is greater than FA, what describes the movement of the center flag?
It moves in the direction of FB at a changing rate of speed.
It moves in the direction of FA at a constant rate of speed.
It moves in the direction of FB at a constant rate of speed.
It moves in the direction of FA at a changing rate of speed.
Answer:
It moves in the direction of FB at a constant rate of speed.
Explanation:
In order to answer this question, the Newton's Second Law of motion shall be used. The Newton's Second Law of Motion states that when an unbalanced force is applied to an object, it produces an acceleration in that object. This acceleration is in the direction of the unbalanced force. So, when the person A and person B are applying forces FA and FB, the force FB is greater than FA. Hence, the unbalanced force will be in the direction of FB, the greater force. So, the flag will move in the direction of FB at a acceleration (rate of speed). So, the correct option is:
It moves in the direction of FB at a constant rate of speed.
HELP I NEED THIS NOW: Block 1 of mass m1 and block 2 of mass m2 are sliding along the same line on a horizontal frictionless surface when they collide at time tc. The graph above shows the velocities of the blocks as a function of time.
Question
Which block has the greater mass, and what information indicates this?
Shannon and Chris push on blocks with identical force. SHannon's block is twice as massive as Chris'. After pushing for 5 seconds, who did more work?
A U-tube manometer is used to measure the pressure at the stagnation point of a model in a wind tunnel. One side of the manometer goes to an orifice at the stagnation point; the other side is open to the atmosphere ( Fig. P1.24 ). If there is a difference of 3.0 cm in the mercury levels in the two tubes, what is the pressure difference in N>m2 .
Answer:
ΔP = 3.98 10³ Pa
Explanation:
We use that the pressure is given
P = ρ g y
where ρ is the density of mercury (ρ = 13534 kg / m³) and y the height of the column
In this case, to measure the pressure, a line is drawn at the lowest point of the mercury column, on the right side of the U-shaped tube, for this point the pressure on both sides of the tube is the same
ΔP = P_l{eft} - P_{right}
ΔP = (P_a + P) - P_a
done P is the gauge pressure on the left side and P_a is the atmospheric pressure
ΔP = ρ g h
let's calculate
ΔP = 13534 9.8 0.03
ΔP = 3.98 10³ Pa
remember that [Pa] = [N / m²]
Why are the noble gases the least reactive elements?
What is the minimum diameter necessary for a radio telescope working at f=1×10^10 Hz to be able to separate two objects 1 deg apart?
[a] 0.03 m
[b] 0.037 m
[c] 0.47 m
[d] 2.1 m
[e] 6.3 m
PLEASE PROVIDE EXPLANATION.
THANK YOU!!
Answer:
11,000 kg
(a) 11.2 m/s
(b) 1.6 m/s
Explanation:
Momentum is conserved.
m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂
(2200 kg) (60.0 km/h) + m (0 km/h) = (2200 kg) (10 km/h) + m (10 km/h)
132,000 kg km/h = 22,000 kg km/h + m (10 km/h)
110,000 kg km/h = m (10 km/h)
m = 11,000 kg
Momentum is conserved.
m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂
(m) (-v) + (2m) (5v) = (m) (v₁) + (2m) (v₂)
-mv + 10mv = m v₁ + 2m v₂
9mv = m (v₁ + 2 v₂)
9v = v₁ + 2 v₂
Since the collision is elastic, kinetic energy is also conserved.
½ m₁u₁² + ½ m₂u₂² = ½ m₁v₁² + ½ m₂v₂²
m₁u₁² + m₂u₂² = m₁v₁² + m₂v₂²
(m) (-v)² + (2m) (5v)² = m v₁² + (2m) v₂²
mv² + 50mv² = m v₁² + 2m v₂²
51mv² = m (v₁² + 2 v₂²)
51v² = v₁² + 2 v₂²
We know v = 1.60 m/s. So the two equations are:
14.4 = v₁ + 2 v₂
130.56 = v₁² + 2 v₂²
Solve the system of equations using substitution.
130.56 = (14.4 − 2 v₂)² + 2 v₂²
130.56 = 207.36 − 57.6 v₂ + 4 v₂² + 2 v₂²
0 = 6 v₂² − 57.6 v₂ + 76.8
0 = v₂² − 9.6 v₂ + 12.8
v₂ = [ 9.6 ± √(9.6² − 4(1)(12.8)) ] / 2(1)
v₂ = 1.6 or 8
If v₂ = 1.6 m/s, then v₁ = 14.4 − 2 v₂ = 11.2 m/s.
If v₂ = 8 m/s, then v₁ = 14.4 − 2 v₂ = -1.6 m/s.
We know v₁ can't be -1.6 m/s, since that would mean puck A didn't change speeds after the collision. Therefore, v₁ = 11.2 m/s and v₂ = 1.6 m/s.
A piano tuner stretches a steel piano wire with a tension of 765 N. The steel wire has a length of 0.800 m and a mass of 6.00 g . What is the frequency f1 of the string's fundamental mode of vibration
Answer:
the frequency of the fundamental mode of vibration is 199.6 Hz
Explanation:
Given;
tension of the piano wire, T = 765 N
length of the steel wire, L = 0.8 m
mass of the steel wire, m = 6.00 g = 6 x 10⁻³ kg
The frequency of the fundamental mode of vibration is calculated as;
\(f_o = \frac{1}{2l} \sqrt{\frac{T}{\mu} }\)
where;
μ is the mass per unit length \(= \frac{6.0 \times 10^{-3}}{0.8} = 7.5 \times 10^{-3} \ kg/m\)
\(f_o = \frac{1}{2l} \sqrt{\frac{T}{\mu} } \\\\f_o = \frac{1}{2\times 0.8} \sqrt{\frac{765}{7.5 \times 10^{-3}} } \\\\f_o = 199.6 \ Hz\)
Therefore, the frequency of the fundamental mode of vibration is 199.6 Hz
Explain how constructive interference is formed by the waves. Include in your answer the effect on your senses if they are sound waves.
When two wave superposed in same phase, constructive interference is formed.
What is interference?According to the definition of interference, it is the phenomenon in which two or more waves combine to create a new wave that has a bigger, smaller, or the same amplitude.
The resulting sound wave is created by adding the amplitudes of two sound waves that are travelling in the same direction and in phase with one another. In this instance, it is claimed that the sound waves experienced constructive interference. The waves experience upward displacement when they encounter constructive interference.
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which object has a weight of about 22.5 n the book the rock the box the fish
Answer: The rock
Explanation:
Three blocks m, m and M are kept on a frictionless floor as shown in figure. The left most block is given velocity v towards right. All the collisions between the blocks are perfectly inelastic. The loss in kinetic energy after all the collisions is 5/6th of initial kinetic energy. The ratio of M/m will be:
( a ) 1/8
( b ) 1/4
( c ) 4
( d ) 2
The ratio of M/m is approximately 0.155, which is closest to option (b) 1/4.
What is the ratio of M/m?
Let's consider the motion of the system before and after the collisions. We'll use the conservation of momentum and the conservation of energy to solve the problem.
Before the collisions, the leftmost block of mass m has velocity v towards the right and the other two blocks are at rest. The total initial momentum of the system is therefore mv.
At the first collision, the leftmost block collides with the middle block of mass m. The two blocks stick together and move as a single unit. By conservation of momentum, the velocity of the combined block after the collision is mv/(2m) = v/2 towards the right.
At the second collision, the combined block collides with the block of mass M. Again, the two blocks stick together and move as a single unit. By conservation of momentum, the velocity of the combined block after the collision is (mv/2 + 0)/ (m+M) = v/2(m+M) towards the right.
After the collisions, the three blocks move as a single unit with velocity v/2(m+M) towards the right. The total final momentum of the system is therefore (m+2m+M)(v/2(m+M)) = mv/2.
The loss in kinetic energy after all the collisions is given as 5/6th of the initial kinetic energy. Therefore, the final kinetic energy is 1/6th of the initial kinetic energy. Let's use this to solve for M/m.
The initial kinetic energy of the system is (1/2)m(v^2) = (1/2)mv^2.
The final kinetic energy of the system is;
(1/2)(m+2m+M)((v/2(m+M))^2) = (1/2)(mv^2)/(4(m+M)^2).
Therefore, we have:
(1/2)mv^2 - (1/2)(mv^2)/(4(m+M)^2) = (1/6)(1/2)mv^2
Multiplying both sides by 12 and simplifying, we get:
3(m+M)^2 = 8m
Expanding the left side and simplifying, we get:
3M^2 + 6mM - 4m^2 = 0
Solving for M/m using the quadratic formula, we get:
M/m = (-6 ± √(36 + 48))/6 = (-6 ± 2√(3))/6 = (-1 ± √(3))/3
Since M/m is a ratio of masses, it must be positive, so we take the positive root:
M/m = (-1 + (3))/3 ≈ 0.155 ≈ 1/4
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2 A rectangular storage tank 4 m long by 3 m wide is filled with paraffin to a depth
of 2 m. Calculate:
a the volume of paraffin
c the weight of paraffin
b the mass of paraffin
d the pressure at the bottom of the tank due
to the paraffin
1m
For a rectangular storage tank filled with paraffin to a depth of 2 m, the volume, weight, mass of paraffin, and pressure at the bottom of the tank are:
a. The volume is 24 m³.
b. weight is 240,000 N,
c. mass is 24,490 kg, and
d. pressure is 23,530 Pa.
a) The volume of paraffin in the rectangular storage tank can be calculated using the formula:
Volume = Length x Width x Depth
Given:
Length = 4 m
Width = 3 m
Depth = 2 m
Substituting the values into the formula, we have:
Volume = 4 m x 3 m x 2 m
Volume = 24 m³
Therefore, the volume of paraffin in the tank is 24 cubic meters.
b) The weight of the paraffin can be calculated using the formula:
Weight = Volume x Density x Acceleration due to gravity
The density of paraffin varies, but we can assume a typical value of 10,000 kg/m³. The acceleration due to gravity is approximately 9.8 m/s². Substituting these values into the formula:
Weight = 24 m³ x 10,000 kg/m³ x 9.8 m/s²
Weight = 240,000 N
Therefore, the weight of the paraffin in the tank is 240,000 Newtons.
c) The mass of the paraffin can be calculated using the formula:
Mass = Density x Volume
Substituting the given values:
Mass = 10,000 kg/m³ x 24 m³
Mass = 24,490 kg
Therefore, the mass of the paraffin in the tank is 24,490 kilograms.
d) The pressure at the bottom of the tank due to the paraffin can be calculated using the formula:
Pressure = Weight / Area
The area of the bottom of the tank is equal to the length multiplied by the width. Substituting the values:
Area = 4 m x 3 m
Area = 12 m²
Pressure = 240,000 N / 12 m²
Pressure = 20,000 Pa
Therefore, the pressure at the bottom of the tank due to the paraffin is 20,000 Pascals (Pa).
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What do we call the material such as air that light travels through
Answer:
Transparent or Translucent
Explanation:
A 1.8 m tallman stand in an elevator accelerating upward at 12 m/s?,
what is the blood pressure in the brain and foot.
Take the height difference between the heart and the brain to be
0.35 m?
13.3 x 103 Pa] & [Pblood = 1060 kg.m-3]
Note: [: P Heart
Answer:
12.483 Kpa
46.806 Kpa
Explanation:
Man's height = 1.8m
Pheart = 13.3 * 10^3
Density of blood (ρ) = 1060 kg/m³
Height difference between heart and brain (Hh - Hb) = 0.35m
g = acceleration due to gravity = 9.8 m/s²
Acceleration (a) = 12 m/s²
Blood pressure in brain :
Pbrain = Pheart - ρ(a - g) * (Hh - Hb)
Pbrain = 13.3 * 10^3 - 1060(12 - 9.8) * 0.35
Pbrain = 13300 - (2332 * 0.35)
Pbrain = 13300 - 816.2
Pbrain = 12483.8 pascal = 12.483 Kpa
Blood pressure in feet :
Pbrain = Pheart + ρ(a + g) * 1.8 - (Hh - Hb)
Pbrain = 13.3 * 10^3 + 1060(12 + 9.8)*(1.8 - 0.35)
Pbrain = 13300 + 1060(21.8 * 1.45)
Pbrain = 13300 + 33506.6
Pbrain = 46806.6 pascal = 46.806 Kpa
According to the Keynesian view, manipulating foreign sector spending is not a reliable way to move the U.S. economy toward a more acceptable equilibrium because __________.
According to the Keynesian view, manipulating foreign sector spending is not a reliable way to move the U.S. economy toward a more acceptable equilibrium because it does not address the fundamental causes of economic instability.
Keynesian economics focuses on the role of domestic demand in driving economic growth and stability. The government can use fiscal and monetary policy to stimulate aggregate demand and promote full employment. However, changes in foreign sector spending can be unpredictable and beyond the control of domestic policymakers. For instance, an increase in foreign demand for U.S. exports could boost economic growth and employment in the short run, but it may not be sustainable if the foreign demand later decreases. Similarly, a decrease in foreign demand for U.S. exports could have negative short-term effects on the economy, but it may not necessarily lead to a long-term decline. In short, Keynesian economics emphasizes the importance of domestic demand management and stabilizing the economy through government intervention. While changes in foreign sector spending can have some impact on the economy, they are generally seen as unreliable and unpredictable, and therefore not a reliable tool for achieving economic stability in the long run.
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A room of volume 33 m³ contains air having
an average molar mass of 43.5 g/mol.
If the temperature of the room is raised
from 16.4°C to 25°C, what mass of air will
leave the room? Assume that the air pressure
in the room is maintained at 121.8 kPa.
Answer in units of kg.
The mass of air that will leave the room is 2.1 kg.
What is the number of moles of air in the room?
The number of moles of air in the room is calculated by applying Ideal gas law as shown below.
PV = nRT
where;
P is the pressure of the roomV is the volume of the air = 33m³ = 33,000 Ln is the number of moles of the airR is ideal gas constant = 8.314 kPa.L/K.molT is temperature of the roomWhen the temperature = 25⁰C = 298 K
n = PV / RT
n = (121.8 x 33,000) / (8.314 x 298)
n = 1,622.3 moles
when the temperature = 16.4⁰C = 289.4 K
n = PV / RT
n = (121.8 x 33,000) / (8.314 x 289.4)
n = 1,670.5 moles
difference in number of moles = 1,670.5 moles - 1,622.3 moles = 48.22 moles
mass of the air that will leave the room = 43.5 g/mol x 48.22 moles = 2,097.73 g = 2.1 kg
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Hang the block of mass 50 g to the spring on the left and measure the period of oscillation T using the stop watch located on the right of the screen (drag the stop watch outside its box). It might be easier if Slow speed is selected. Repeat ten times your measurements of the period and record your data.
What is average value of T? What is the standard deviation of T? Use your average value of T and Eq to find the sprint constant k (N/m)
Once the average value of T and its standard deviation are determined, the spring constant k can be calculated using the equation k = 4π^2m/T^2, where m is the mass of the block.
To find the average value of T, the ten measurements of T are added together and divided by ten. The standard deviation of T is calculated using the formula that involves finding the square root of the variance.
This experiment aims to demonstrate the relationship between the period of oscillation and the spring constant of the spring. By measuring the period of oscillation of the spring with a known mass hanging from it, the spring constant can be determined, which is a fundamental property of the spring.
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A/An breaks down a complicated goal into daily action to make it more manageable?
A routine breaks down a complicated goal into daily action to make it more manageable.
What is a routine?A routine can be described as the sequence of actions regularly followed which do help individuals as well as the organization so they can acheive their goals.
It should be noted that a routine is neccessary in an organization because it will help help them to breakdown the task as well as the activities and this will help to achive the goals as well as the neccessary things on time because allcomplicated goals woud have been included as well as how it will be carried out.
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An evacuated tube uses an accelerating voltage of 40 kV to accelerate electrons to hit a copper plate and produce x rays. Nonrelativistically, what would be the maximum speed of these electrons
Answer:
1.187 x 10^8 m/s
Explanation:
the potential of the electric field V = 40 kV = 40000 V
the charge on an electron e = 1.6 x 10^-19 C
The energy of an accelerated electron in an electric field is given as
E = eV
E = 1.6 x 10^-19 x 40000 = 6.4 x 10^-15 J
This energy is equal to the kinetic energy with which the electron moves, according to the conservation of energy.
The kinetic energy = \(\frac{1}{2}mv^{2}\)
where
m is the mass of the electron = 9.109 x 10^-31
v is the speed of the electron.
Equating the energy, we have
6.4 x 10^-15 = \(\frac{1}{2}*9.109*10^-31*v^{2}\)
6.4 x 10^-15 = 4.55 x 10^-31 \(v^{2}\)
\(v^{2}\) = 1.41 x 10^16
\(x^{2} v = \sqrt{1.41*10^{16}}\) = 1.187 x 10^8 m/s
A 2800-lbm car climbs a 1160 ft. long uphill road which is inclined at 15o (to the horizontal) and covers the distance in 12 sec. Determine the power required if the car covers the distance (a) at constant velocity, (b) from an initial velocity, at the bottom of the hill, of 10 mph to a final velocity of 50 mph at the top of the hill and (c) from an initial velocity of 45 mph to a final velocity of 15 mph. Neglect the effects of friction and wind resistance.
Answer:
a) P = 70054.3 W, b) P = 18820 W, c) P = 14116.7 W
Explanation:
Power is defined as work per unit of time
P = W / t = F x / t
P = F v
a) in this case the velocity is constant, let's use the equilibrium relation to find the force.
Let's set a reference system with the x axis parallel to the plane
F - Wₓ = 0
F = Wₓ
with trigonometry let's decompose the weight
sin θ = Wₓ / W
Wₓ = W sin θ
F = W sin 15
F = 2800 sin 15
F = 724.7 lb
we look for the speed, as it rises with constant speed we can use the relations of uniform motion
v = x / t
v = 1160/12
v = 96.67 ft / s
we calculate the power
P = 724.7 96.67
P = 70054.3 W
b) In this case, the speed of the vehicle changes during the ascent, so we use the relationship between work and the change in kinetic energy
W = ΔK
W = ½ m v_f² - ½ m v₀²
let's reduce to the SI system
v₀ = 10 mph (5280 ft / 1 mile) (1h / 3600 s = 14.67 ft / s
v_f = 50 mph (5280 ft / 1 mile) (1 h / 3600s) = 73.33 ft.s
mass : m = w / g
W = ½ 2800/32 (73.33² - 14.67²)
W = 225841 J
we calculate the average power
P = W / t
P = 225841/12
P = 18820 W
c) we repeat the previous procedure
v₀ = 45 mph = 66 ft / s
v_f = 15 mph = 22 ft / s
W = ½ 2800/32 (22² - 66²)
W = -169400 J
P = W / t
P = 169400/12
P = 14116.7 W
How do our attitudes help us organize our reality?
Answer:
If we are upset, often our mind cannot think straight. we need to take deep breaths, and focus on reality. When we are upset we do things out of anger.
Explanation:
Hope this helps!
determine the value of the resultant and its location from O.
see attach image.
Answer:
Explanation:
In the x direction the force will be
½(-w₀)L/2 = -¼w₀L
acting ⅔(L/2) = L/3 below the x axis.
In the y direction the force will be
½(-w₀)L + ½w₀L/2 = -¼w₀L
the magnitude of the resultant will be
F = w₀L √((-¼)² + (-¼)²) = w₀L√⅛
in the direction
θ = arctan(-¼w₀L / -¼w₀L) = 225°
to find the distance, we balance moments
(w₀L√⅛)[d] = ½(w₀)L[⅔L] + ¼w₀L[⅔L/2] - ¼w₀L[L - ⅓L/2]
(√⅛)[d] = ½ [⅔L] + ¼ [⅔L/2] - ¼ [L - ⅓L/2]
(√⅛)[d] = ½[⅔L] + ¼[⅔L/2] - ¼[L - ⅓L/2]
(√⅛)[d] = ⅓L + ⅟₁₂L - ¼L + ⅟₂₄L
(√⅛)[d] = 5L/24
d = 5L/24 / (√⅛)
d = 5√⅛L/3
Water flows at a speed of 13 m/s through a pipe that has a diameter of 1.2 m. What is the
diameter of the smaller end of the pipe that the water comes out with a speed of 30 m/s?
The diameter of the smaller end of the pipe is approximately 0.78 meters.
To determine the diameter of the smaller end of the pipe, we can use the principle of conservation of mass. According to this principle, the mass flow rate of water should remain constant throughout the pipe.
The mass flow rate is given by the equation:
Mass flow rate = density of water * cross-sectional area * velocity
Since the density of the water remains constant, we can write:
Cross-sectional area1 * velocity1 = Cross-sectional area2 * velocity2
Given that the velocity1 is 13 m/s, the diameter1 is 1.2 m, and the velocity2 is 30 m/s, we can solve for the diameter2 using the equation:
(pi * (diameter1/2)^2) * velocity1 = (pi * (diameter2/2)^2) * velocity2
Simplifying the equation:
(1.2/2)^2 * 13 = (diameter2/2)^2 * 30
Calculating the equation:
(0.6)^2 * 13 = (diameter2/2)^2 * 30
0.36 * 13 = (diameter2/2)^2 * 30
4.68 = (diameter2/2)^2 * 30
Dividing both sides by 30:
0.156 = (diameter2/2)^2
Taking the square root of both sides:
0.39 = diameter2/2
Multiplying both sides by 2:
0.78 = diameter2
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1. A material emits electrons when the electromagnetic radiation with a frequency equal to or less than the material's threshold frequency strikes the material.
True
False
2. In a particle model to show energy transfer, which of the following is correct?
a. Energy jumps are best described of electrons in packages known as photons
b. In energy transfers, electrons can absorb or emit energy
c. Photons carry energy from one location or object to another
d. All of the above are correct of particle models
1) The photoelectric effect is the phenomena by which, the metals release electrons when they are exposed to electromagnetic radiation with the suitable frequency. The photoelectrons are the electrons that are released in this process.
So, the statement is true.
2) In a particle model, energy transfer can be done through many ways such as:
The energy jumps between the particles in the form of photons.
Electrons can absorb or emit energy during energy transfer.
The energy is transferred between different objects in the form of photons.
So, all of them are true.
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Laasya is lifting a table and moving it to another room to expand the space in her room. What mode of
strength-training
is Laasya performing?
Laasya is performing resistance training by lifting a table and moving it to another room to expand the space in her room. The correct option to this question is D.
Strength training By putting your muscles up against resistance, resistance training builds muscle strength. Free weights, weight machines, resistance bands, and your own body weight are all used in various types of resistance training. To get the most out of their training, beginners should go two or three times per week.Resistance training is founded on the idea that, when called upon, the body's muscles will struggle to overcome a resisting force. Resistance exercise has both advantages and disadvantages.Resistance exercises include planks, sit-ups, squats, push-ups, leg raises, and leg extensions. You and a small amount of room are all that are needed for these strength training exercises.For more information on resistance training kindly visit to
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Complete question : Laasya is lifting a table and moving it to another room to expand the space in her room. What mode of strength-training is Laasya performing?
a. Endurance
b. Isometric
c. Isotonic
d. Resistance
For the summer 5th grade trip, the students
traveled for 90 miles. The trip took 3 hours. What
was the buses' average speed?
Answer:
30 miles/hour
Explanation:
Bus traveled 90 miles and took 3 hours if you take the average per hour it should be around, 30 miles every hour
an electric kettle takes 2kw at 240v. Calculate the current and the resistance of the heating element
The power output is given 2000 watt and voltage is 240 v. Then the current through the heating element is 8.3 A and the resistance is 29 ohms.
What is power ?The power used by an object is the rate of its work done or energy. It is the energy divided by time. The power output in a circuit is the product of the potential difference V and current I.
P = I V
Given,
P = 2 kw = 2000 W
v = 240 V.
Then I = P/v
I = 2000 w/240 v = 8.3 A.
According to Ohm's law, voltage v is the product of the current and resistance through the material.
hence,
V = I R
then, R = V/I
R = 240 V/8.33 A
= 29 Ω.
Therefore, the current and resistance through the heating element are 8.3 A and 29 ohms respectively.
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Define each of the three heat transfer methods:
Conduction
Convection
Radiation
40 points
For this assignment, you will research how to design and build a solar cooker. Search reliable online sites
for “solar cookers.” After getting the materials you need from your teacher, you will present your initial
design as a drawing or illustration. You will then build your device and test its efficiency by warming up a
hot dog until it reaches an internal temperature of 165°F, recording how long it took you to reach this
temperature. Based on your tests, you will make recommendations on how to improve the design of your
solar cooker, and then present your final design and the logic that supports it in a lab report. Your lab
report should include a title, a list of materials that you used to build your solar cooker, a drawing of your
initial design, observations from your experimental tests, recommendations for a final design based on
what you know about radiation, a drawing of your final design, and the results of the efficiency test. To
help you write your lab report, there is a Student Worksheet on the last few pages of this document.
Answer:
Ideas for Prototype Design
Similar to a cardboard oven just smaller and solar powered
Preliminary Sketches (attach separate paper, if needed)
Option A: i gave the picture
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Advantages: Disadvantages:
● the tin foil will attract the sun● if theres enough heat for the food to warm up
●the plastic will keep bugs and/or animal away from getting it ● it might take longer
●the box gives the food something to be in instead of the ground
Option B: i think im going to stay with my original plan i can always make changes
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More advantages and disadvantges
Advantages: Disadvantages:
●reducing my carbon footprint by alot ● heat varies so the food my take really really long
●using no energy other than the sun
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Which of the three designs will you move forward with? Explain your reasons for selecting this design.
I will be moving forward with option A bc i personally can't think of another way or design and i think option A has more advantages than disadvantages
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Building the Prototype
What modifications, if any, did you make to the basic design during the construction process?
I used skewers to hold the flap up
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Predictions
Will your device warm the hot dog to a temperature of 165°F? How will your device do this?
Well i guess it depends n alot of things such as where i will place my solar cooker and the weather changes i will most likely put my solar cooker on the black paper because darker colors absorb more heat then lighter ones, then i will wait maybe 10 -20 minutes and check on my hotdog
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Will your device efficiently warm the hot dog in 20 to 25 minutes? How will your device do this? so my device will do this by attracting the suns rays and energy towards the box
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Will your device reach a temperature well above that of its surroundings? How will your device do this?
I think so especially if i put it in direct sunlight around a darker surface and of course the aluminium foil will help with this as well
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Observations
Record your observations and the results of the experimental tests of your device below. Temperature of the surroundings (in °F): ______68_______
Maximum temperature reached inside the solar cooker (in °F): _____59_____
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i added a picture but i will also put the numbers here althought keep in mind u might want to switch them up because its based off of my temperatures
Use this table to record the internal temperature of the hot dog every 2 minutes. Use a separate sheet of paper, if necessary.
time: Temperature (°F)
4:00 20
4:02 20
4:04 25
4:06 26
4:08 30
4:10 34
4:12 38
4:14 40
4:16 44
4:18 46
4:20 50
4:22 55
4:24 57
4:26 60
4:28 65
4:33 72
4:35 75
4:37 76
4:39 80
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Evaluating Your Prototype
What worked well?
i would say definitely the black paper and tin foil sin they attracted most of the suns energy
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Which features can be improved upon?
i think maybe if i did t on a different day it would have gotten hotter
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How could the overall design of this device be improved?
Position the flap more so that the hotdogs can get more sun
Doing it on a hotter day
Letting it cook longer
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Why would this change be an improvement? What concepts related to thermal energy transfer is this improvement based on?
this change would be an improvement by the hotdogs getting warmed to the right temperature this is related to thermal energy by the position of the flap i think if i angled it more in an abtuse angle the sun would have transferred to the foil to the bottom foil with the hotdogs
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Sketch of Your Final Design
Draw a well-labeled sketch of the final design.
i provided a sketch it should be the last picture
OKAY FINALLY PLZ DONT REORT THIS I WORKED SO HARD ON IT LAST TIME AND IT GOT DELETED IF U HAVE ANY QUESTIONS ABOUT THE PROJECT I WILL TRY TO HELP YOU IN THE COMMENTS THANK YOUUUU - ( if your wndering what grade i got on this got a 100 percent )
OH AND PEACE.
Answer:
I am simply adding another answer so the one above can get a brainliest
Explanation:
I do not care about the points that I will wind up getting for this and they are right here just answer with gibberish
https://brainly.com/question/26856060
edit: in an attempt to return your points my question was taken down ill will return these
somehow
someway
sometime
2.(01.01 LC)
Which of the following is true for gravitational force? (3 points)
Decreases with increase in mass
Increases with increase in mass
Increases with increase in distance
Decreases with decrease in distance
Answer:
Increases with increase in mass
Explanation:
gravity is proportional to mass and inversely proportional to the square of the distance between them
F = GMm/d²