Determine whether the given points represent the vertices of a trapezoid If so, determine whether it is isoscoles or not

A(-4,-1),B((-4,6),C(2,6),D(2,-4)

The value of the function is 8.

A function has an input and an output.

A function can be one-to-one or onto one.

It simply indicated the relationships between the input and the output.

Example:

f(x) = 2x + 1

f(1) = 2 + 1 = 3

f(2) = 2 x 2 + 1 = 4 + 1 = 5

The outputs of the functions are 3 and 5

The inputs of the function are 1 and 2.

We have,

h(x) + 4

Substitute h(x) = 4

= 4 + 4

= 8

Thus,

The value of the function is 8.

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Answer:

1 ft

Step-by-step explanation:

A^2+B^2=C^2

We have A and C

So 24+B^2=25

Subtract 24 from both sides

B^2=1

Square root both sides

B=1

Answer:

7 ft

Step-by-step explanation:

eh don't wana explain but I'm 80% sure that's the answer

Answer:

√259 or 16.09

Step-by-step explanation:

Hello!

I'll be labeling the vertices so that it is easier to understand the sides.

These are both right triangles, and we can find the measures of right triangles (given two other sides) by using the Pythagorean theorem:

\(a^2 + b^2 = c^2\)

In Triangle BCD, we have the measures of the hypotenuse and a leg. We can use that to find the missing side: CB

Since DB is the hypotenuse, it would be side c, and we can say that CD can be side a.

CB in simplest radical form is 5√21.

We can now solve for x, because now in triangle ABC, we have the measures of two sides: hypotenuse AC and leg CB.

AB in simplest radical form is √259, which is approximately 16.09.

The solution for x is √259 or 16.09.

The dual linear program can be obtained by interchanging the coefficients of the objective function and constraints. The complementary slackness conditions can be used to check the optimality of the solutions

The given problem is a linear programming problem with the objective of minimizing the function 3x1 + 4x2, subject to the following constraints: x1 + 3x2 ≥ 9, 2x1 + x2 ≥ 8, and x1 - 2x2 ≥ 4.

a) To solve the problem algebraically, we need to find the feasible region, which is the region that satisfies all the constraints.

We can also graphically represent the constraints and find the feasible region.

By finding the intersection of the feasible region and the objective function, we can determine the optimal solution.

b) To verify the solution using Excel, we can set up a spreadsheet with the objective function, constraints, and solver tool. By adding the solver tool, we can find the optimal solution and check if it matches the algebraic or graphical solution.

c) The dual linear program is formed by taking the coefficients of the objective function as the constraints and the coefficients of the constraints as the objective function.

The dual program's objective function will be to maximize, and the constraints will be to minimize. We can write the dual linear program by interchanging the coefficients of the objective function and constraints.

d) To solve the dual linear program using Excel, we can set up a new spreadsheet with the dual objective function and constraints. By adding the solver tool, we can find the optimal solution and check if it matches the algebraic or graphical solution.

e) The complementary slackness conditions state that if a primal variable is positive, the corresponding dual constraint is binding (has a value of zero), and if a dual constraint is positive, the corresponding primal variable is binding.

The product of the primal and dual variables should be zero. In conclusion, to solve the given linear program, we can use algebraic or graphical methods.

We can verify the solution using Excel by setting up a spreadsheet and using the solver tool. The dual linear program can be obtained by interchanging the coefficients of the objective function and constraints. The complementary slackness conditions can be used to check the optimality of the solutions

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Answer:

25 ft

Step-by-step explanation:

Got it right on EDG2020

The ball will reach the maximum height in a second. Then the maximum height the ball reaches will be 25 ft.

The rate of change of a function with respect to the variable is called differentiation. It can be increasing or decreasing.

Lori tosses a ball into the air. The equation models the height, y, in feet, of the ball after x seconds.

\(\rm y = -16(x - 1)^2 + 25\)

Differentiate the equation with respect to x, then we have

\(\begin{aligned} y' &= 0\\\\\dfrac{d}{dx}[-16(x - 1)^2 + 25] &= 0\\\\ -32(x-1) &= 0\\\\x &= 1 \end{aligned}\)

Then the maximum height the ball reaches will be

\(\rm y = -16(1 - 1)^2 + 25\\\\y = -16*0^2 + 25\\\\y = 25\)

Then the maximum height the ball reaches will be 25 ft.

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Based on the information provided, we cannot conclude with certainty that the average pickup order has a higher amount than the average delivery order.

Based on the information given, we can conclude that there is a 95% chance that the true mean for pickup orders falls between $33 and $51, and the true mean for delivery orders falls between $21 and $41. However, we cannot conclude with certainty that the average pickup order has a higher amount than the average delivery order.

To determine if there is a significant difference between the means of the two groups, we need to perform a hypothesis test. We can set up our null hypothesis as "there is no significant difference between the means of the pickup and delivery orders" and our alternative hypothesis as "the average pickup order has a higher amount than the average delivery order."

We can use a two-sample t-test to test this hypothesis. Assuming equal variances, we would calculate the test statistic as

t = (xpickup - xdelivery) / (s / √n)

where xpickup and xdelivery are the sample means for pickup and delivery orders, s is the pooled standard deviation, and n is the sample size for each group.

If our calculated t-value is greater than the critical value at a chosen significance level (e.g. 0.05), we can reject the null hypothesis and conclude that there is a significant difference between the means of the two groups.

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Answer:

3.9 pounds

Step-by-step explanation:

Box A=1.4 lbs

Box B=2.5 lbs

Answer= Box A + Box B = 1.4+2.5 lbs

1.4+2.5= 3.9 lbs

Thus, the friend's bank account has the higher balance in it as -26.85 is greater than -27.11.

The net amount, which includes all debits and credits, is always the account balance. An account balance that is negative indicates a net debt, such as when a checking account is overdrawn.

Given data:

my account = -27.11 dollars in debt

My friend's account = -26.85 dollars in debt

-26.85 > -27.11

It means higher the debt, lesser is the account balance.

Thus, the friend's bank account has the higher balance in it as -26.85 is greater than -27.11.

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Answer:

$82.31

Step-by-step explanation:

First, we need to find the total amount of money paid

\(82 * 25 = 2050\\\)

Next, add the new price for the new total

\(2050 + 90 = 2160\)

Now divide by total members (25 +1 = 26)

\(2160 / 90 = $82.31\)

The new mean price paid when the new musician is included is $82.3.

Given that, an orchestra of 25 members bought tickets, at all different prices, to a concert, and the mean price paid was $82. A new musician joined the orchestra and spent $90 on his ticket to the same concert.

We need to find what is the new mean price paid when the new musician is included.

The mean (aka the arithmetic mean, different from the geometric mean) of a dataset is the sum of all values divided by the total number of values. It's the most commonly used measure of central tendency and is often referred to as the “average.”

Now, the sum of money spent on tickets=82×25=$2050

A new musician joined the orchestra and spent $90 on his ticket.

So, the new sum of money spent on tickets=2050+90= $2140

New mean=2140/26=$82.3

Therefore, the new mean price paid when the new musician is included is $82.3.

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Answer:

C. y = - 0.5 (x - 6)² + 18

Step-by-step explanation:

Because it is "Correct Answer"

The fencing around the perimeter of semicircular statuary garden of diameter 21 feet will altogether cost $300

given that the diameter of the garden is 21 feet

cost per linear foot is  $9.50

perimeter of semicircle = \(\pi r\)

hence the perimeter of the garden will be  \(3.14*\frac{21}{2}\)

which is equal to 32.97 feet

now since the cost of fencing per linear foot is $9.50

the cost of fencing the perimeter will be \(32.97*9.50\)

i.e $313.215≈  $300

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c) 2x^2 > 10

The inequality graphed on the number line is:

c) 2x^2 > 10

This inequality represents a quadratic function that opens upwards with its vertex at (0,0) and its axis of symmetry along the y-axis. The inequality indicates that all values of x that make the function greater than 10 on the y-axis are solutions to the inequality.

On the number line, the solution to the inequality would be all values of x such that x is greater than the square root of 5 or less than the negative square root of 5.

This would be represented on the number line by shading the region to the right of the positive square root of 5 and the region to the left of the negative square root of 5.

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Answer: height = 1.91 m

Step-by-step explanation: Using the formula

V=πr2h

Solving for h

h=V

πr2=37.5

π·2.52≈1.90986m

Answer:

60

Step-by-step explanation:

1. The marginal PDF of X is f(x) = (3/2) - 3x.

2. E[X] = ∫[-∞,∞] x((3/2) - 3x) dx.

3. f(x|A) = f(x,y)/f(x), for x < 1.5.

4. The marginal PDF of Y is f(y) = ∞.

5. E[Y] = ∫[-∞,∞] y∞ dy.

6. f(y|E) = f(x,y)/f(y), for y > 1.5.

1. To find the marginal PDF of X, we integrate the joint PDF f(x,y) with respect to y over the range of possible y values:

f(x) = ∫[0,1] (6(y-x)/2) dy.

Splitting the integral into two parts, we get:

f(x) = ∫[0,1] (3y - 3x) dy

= (3/2)y^2 - 3xy | [0,1]

= (3/2) - 3x.

Therefore, the marginal PDF of X is f(x) = (3/2) - 3x.

2. The blind estimate of X is obtained by taking the expected value of X, which is calculated by integrating X times its marginal PDF:

E[X] = ∫[-∞,∞] x*f(x) dx.

Plugging in the marginal PDF of X, we have:

E[X] = ∫[-∞,∞] x((3/2) - 3x) dx.

Evaluating this integral gives us the blind estimate of X.

3. To compute the minimum mean square estimate of X given event A={X < 1.5}, we need to find the conditional PDF of X given A, denoted as f(x|A). This is obtained by dividing the joint PDF f(x,y) by the marginal PDF of X, evaluated at the event A:

f(x|A) = f(x,y)/f(x), for x < 1.5.

Compute the conditional PDF f(x|A) and then calculate the mean of the conditional distribution to find the minimum mean square estimate of X given A.

4. To find the marginal PDF of Y, we integrate the joint PDF f(x,y) with respect to x over the range of possible x values:

f(y) = ∫[-∞,∞] (6(y-x)/2) dx.

Splitting the integral into two parts, we get:

f(y) = ∫[-∞,∞] (3y - 3x) dx

= 3yx - 3x^2/2 | [-∞,∞]

= ∞ - (-∞)

= ∞.

Therefore, the marginal PDF of Y is f(y) = ∞.

5. The blind estimate of Y is obtained by taking the expected value of Y, which is calculated by integrating Y times its marginal PDF:

E[Y] = ∫[-∞,∞] y*f(y) dy.

Plugging in the marginal PDF of Y, we have:

E[Y] = ∫[-∞,∞] y∞ dy.

Evaluating this integral gives us the blind estimate of Y.

6. To compute the minimum mean square estimate of Y given event E={Y > 1.5}, we need to find the conditional PDF of Y given E, denoted as f(y|E). This is obtained by dividing the joint PDF f(x,y) by the marginal PDF of Y, evaluated at the event E:

f(y|E) = f(x,y)/f(y), for y > 1.5.

Compute the conditional PDF f(y|E) and then calculate the mean of the conditional distribution to find the minimum mean square estimate of Y given E.

In summary, we have calculated the marginal PDFs of X and Y, obtained the blind estimates of X and Y by taking their expected values, and explained how to compute the minimum mean square estimates of X and Y given specific events. The specific calculations and evaluations of integrals are required to obtain the numerical values for the blind estimates and minimum mean square estimates.

It is important to note that without the specific values of the variables and the events A and E, we cannot provide the exact numerical answers.

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The graph that shows the solution to the system of linear equations is the third graph, which has one line passing through the points (3,-3) and (0,-2), and another line passing through the points (0,0) and (3,1).

The  system of linear equations is shown below:

y = (1/3)x

x + 3y = -6

we substitute the first equation into the second equation, in order to find the solution to this system

x + 3(1/3)x = -6

x + x = -6

2x = -6

x = -3

Substituting x = -3 into the first equation, we get:

y = (1/3)(-3) = -1

In conclusion, the solution to the system is (x,y) = (-3,-1).

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The three major chords built on white notes without accidentals are:

1. C major chord (C, E, G)

2. F major chord (F, A, C)

3. G major chord (G, B, D)

These chords are formed by taking the root note, skipping one white note, and adding the next white note on top. For example, in the C major chord, the notes C, E, and G are played together to create a harmonious sound.

Similarly, the F major chord is formed by playing F, A, and C, and the G major chord is formed by playing G, B, and D. These three major chords are commonly used in various musical compositions and are fundamental building blocks in music theory.

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Answer:

Answers are in the file.

Step-by-step explanation:

For each and every equation I plugged in whatever it told me x would equal and I used it to solve the equations.

Answer: 10/250

Don't overcomplicate it! It says fraction or decimal.

1 ticket = 1/250 chance

10 tickets = 10/250 chance

hope this helps

Answer:

37.8 litres

Step-by-step explanation:

V=a*b*c

a=1.5m=150cm

b=1.8m=180cm

c=1.4cm

1l=1000cm³

V=150cm*180cm*1.4cm=37800cm³

(37800cm³:1000cm³)*l=37,8l

Answer:

Step-by-step explanation:

The following ordered pair is given as {(1, -1), (2,0), (3,1)} for the given data of movement of arrow.

A set comprises elements or members that can be mathematical objects of any sort, including numbers, symbols, points in space, lines, other geometric forms, variables, or even other sets. A set is the mathematical model for a collection of various things.

An ordered pair consists of two items. The order of the objects in the pair matters because, unless a = b, the ordered pair differs from the ordered pair. Ordered pairs are also known as 2-tuples, or 2-length sequences.

An ordered pair is made up of the ordinate and the abscissa of the x coordinate, with two values given in parenthesis in a certain sequence. In order to understand a point visually, it might be helpful to position it on the Cartesian plane. An ordered pair's numerical values may be fractions or integers.

The following ordered pair is given as {(1, -1), (2,0), (3,1)} for the given data of movement of arrow.

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Answer:

D

Step-by-step explanation:

Answer:

8

Step-by-step explanation:

10sin(53) = 7.986... = 8.0

The number of players the team can bring to the tournament would be = 24 players

The softball game is the type of game that involves two teams which is made up of 9. - 10 players.

The total amount of money raised by a softball team=

$2089.50

The amount of money spent on rented bus = $1087.50

The amount left after rent deductions= 2,089.50 - 1,087.50 = 1,002

The amount budgeted for meals for each player= $41.75

The number of players that would be brought for tournament= 1,002/41.75

= 24 players.

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Answer:

y=-2/3x-6

Step-by-step explanation:

An angle is the two rays sharing a common endpoint.

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The amount of land the railroad companies received for each mile of track they laid varied depending on the specific circumstances and agreements.

However, a common benchmark used during the construction of railroads in the United States was the granting of land through the Homestead Act of 1862. Under this act, railroad companies were granted approximately 6,400 acres (10 square miles) of land for every mile of track laid. This land was typically located alongside the tracks and served as an incentive for the companies to expand and develop the rail network across the country.

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Check the picture below.

now, keeping in mind that ratio of the sides is the same as the ratio of the perimeters.

\(\cfrac{\stackrel{small}{trapezoid}}{\stackrel{large}{trapezoid}}\qquad \stackrel{sides}{\cfrac{6}{9}}~~ = ~~\stackrel{perimeters}{\cfrac{20}{p}}\implies \cfrac{2}{3}=\cfrac{20}{p}\implies 2p=60 \\\\\\ p=\cfrac{60}{2}\implies p=30 \\\\[-0.35em] ~\dotfill\)

\(\cfrac{\stackrel{small}{trapezoid}}{\stackrel{large}{trapezoid}}\qquad \stackrel{sides^2}{\cfrac{6^2}{9^2}}~~ = ~~\stackrel{areas}{\cfrac{A}{45}}\implies \cfrac{36}{81}=\cfrac{A}{45}\implies \cfrac{4}{9}=\cfrac{A}{45} \\\\\\ 180=9A\implies \cfrac{180}{9}=A\implies 20=A\)

Answer:

-17 < -5 < 0 < 3

Step-by-step explanation:

The bookstore has 4 copies of the magazine left.

A bookstore had 42 copies of a magazine. Yesterday, it sold 2/3 of them. Today, it sold 5/7 of what remains.

After selling 2/3 copies of a magazine, the bookstore is left with 1/3 copies of the magazine. Out of the 1/3 copies, today the bookstore sold 5/7 of the remaining copies.

Therefore, we can find the answer as follows:

Remaining copies from yesterday sale:1/3 × 42 = 14

After today's sale, the number of copies of the magazine left in the bookstore is:

14 - 5/7 × 14 = 14 - 10= 4 copies.

So, the bookstore has 4 copies of the magazine left.

Answer: The bookstore has left 4 copies.

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