Discuss the final result if the ice you had in the calorimeter was actually at less than 0. 0c?

In Europe, angles are sometimes measured in grads, where there are 100 grads in one-quarter of a circle. To determine the number of grads in 1.96 radians, we can use a conversion factor.

To convert radians to grads, we need to know that there are 2π radians in a full circle. Since there are 100 grads in one-quarter of a circle, we can set up a proportion:

(1.96 radians) / (2π radians) = (x grads) / (100 grads)

Cross-multiplying and solving for x, we find:

x = (1.96 radians) * (100 grads) / (2π radians)

Evaluating the expression, we can calculate the number of grads in 1.96 radians.

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The partial pressure of carbon dioxide in dry air, when the atmospheric pressure is \(1.01 * 10^5\) \(N/m^2\), is \(41.107\) \(N/m^2\).

We must first get the total pressure of dry air and then multiply it by the fractional concentration of carbon dioxide in order to determine the partial pressure of carbon dioxide in dry air. The total pressure of dry air is the atmospheric pressure given, which is \(1.01 * 10^5\) \(N/m^2\).

The fractional concentration of carbon dioxide is 0.0407%, which can also be written as a decimal fraction of 0.000407. So, the partial pressure of carbon dioxide can be calculated as:

partial pressure of \(CO_2\) = (total pressure) × (fractional concentration of \(CO_2\))

⇒ partial pressure of \(CO_2\)  \(= (1.01 * 10^5) * 0.000407\)

⇒ partial pressure of \(CO_2\) \(= 41.107\) \(N/m^2\).

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Answer:

It is C the kelvin scale

Explanation:

Have a great day

Answer:

she saw it in a movie

Explanation:

she said her mom and her saw it in Step up 3 and fell in love

The purpose of the Future Business Leaders of America and Business Professionals of America is to to help young people learn management skills.

The name Future Business Leaders of America and Business Professionals of America is a group that has been put together as a means of helping the young business people to be able to reach their maximum potentials.

This organization was specifically put together for the young high school students in America hence the purpose of the Future Business Leaders of America and Business Professionals of America is to to help young people learn management skills.

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Answer: the awnser is 19k

Explanation:

Answer:

hope the answer helped you. pls mark as brainliest

Explanation:

Newton's second law states that the acceleration an object experiences due to a given force is inversely proportional to its mass, that is --

a=Fm

If the acceleration is 10m/s2 and the object's mass is 2kg , we can use Newton's second law to find that:

10m/s2=F2kg

F=20kg m/s2 , or 20N .

Answer:

papi sus

Explanation:

TOTAL FLIGHT TIME

Rising Projectile

vi = initial velocity = 58.8 m/s

vf = final velocity = 0

g = gravity acceleration = -9.81 m/s²

t = elapsed time = to be determined

vf = vi + gt

vf - vi = gt

(vf - vi)/g = t

t = (vf - vi)/g

t = (0 - 58.8)/-9.81

t = -58.0/-9.81

t = 5.99 s ≈ 6.00 s

Falling Projectile

vi = initial velocity = 0

vf = final velocity = 58.8 m/s

g = gravity acceleration = 9.81 m/s²

t = elapsed time = to be determined

vf = vi + gt

vf - vi = gt

(vf - vi)/g = t

t = (vf - vi)/g

t = (58.8 - 0)/9.81

t = 58.0/9.81

t = 5.99 s ≈ 6.00 s

t(total) = t(up) + t(down) = 6.00 s + 6.00 s = 12.0 s Total Flight Time

HORIZONTAL DISTANCE TRAVELED

v = velocity, horizontal = 20.0 m/s

d = to be determined

t = elapsed time = 12.0 s

v = d/t

vt = d

d = vt

d = (20.0 m/s)(12.0 s)

d = 240 m Horizontal Distance Traveled

00

The tension in the string supporting the rod and the attached weights is 7.11 N.

The tension in the string supporting the rod and the attached weights is the sum of the weights supported by the strings.

T = (m1 + m2)g

where;

0.4lb + 1.2lb = 1.6lb = 0.725 kg

T = 0.725 x 9.8

T = 7.11 N

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Viewed from the same place, it will lag by about 4 minutes per day.

7 days later puts it at roughly 8:28 PM.

The fixed shell representing the distant stars would need to orbit the Earth at a speed that allows it to cover a distance equal to the circumference of its orbit in 24 hours.

If Ptolemy's estimate assumes that the fixed stars are 20,000 Earth radii apart, it implies that the fixed shell, representing the distant stars, would need to complete one full orbit around the Earth in a single day.

The fixed shell would need to orbit the Earth at a speed that allows it to cover a distance equal to the circumference of its orbit in 24 hours. The speed required for this orbit depends on the radius of the Earth's orbit.

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Answer:

Brightness.

Explanation:

very bright.

Light energy with very high amplitude would be perceived as very bright or intense light.

Waves with a big maximum displacement or height relate to light energy with a very high amplitude.

This large amplitude equates to a greater intensity or brightness of light in terms of perception.

When high-amplitude light waves enter our eyes, they excite light-sensitive cells, such as the cones in our retinas, more powerfully.

As a result of the increased stimulation, the sense of a bright or powerful light source is formed. The magnitude of the light's amplitude is interpreted by the human visual system as a measure of its intensity, allowing humans to distinguish between dimmer and brighter light sources.

Thus, in human visual experience, light energy with a very high amplitude is related with a heightened feeling of brightness or intensity.

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The length of the tungsten filament should be approximately 5.96 meters.

To calculate the length of the tungsten filament, we can use the formula for resistance:

Resistance (R) = \(\[R = \rho \times \left(\frac{L}{A}\right)\]\)

The resistivity of tungsten at 20.0°C is approximately \(\[R = 5.6 \times 10^{-8} \, \Omega \cdot \text{m}\)

The cross-sectional area of the filament can be calculated using the formula for the area of a circle:

Area (A) =\(\[A = \pi \times \text{radius}^2\]\)

Given that the diameter of the filament is 0.100 mm, the radius (r) can be calculated by dividing the diameter by 2:

Radius (r) = 0.100 mm / 2

                = 0.050 mm

                = 5 × \(10^{(-5)\) m

Now we can calculate the cross-sectional area:

Area (A) = \(\pi \times (\)5 × \(10^{(-5)\) \(m)^2\)

Next, we rearrange the resistance formula to solve for length:

         Length (L) =

          \(\[R = \frac{R \times A}{\rho}\]\)

Given that the resistance (R) is 0.200 Ω, we can substitute the values into the formula:

Length (L) = \(\frac{0.200 \, \Omega \times \pi \times \left(5 \times 10^{-5} \, \text{m}\right)^2}{5.6 \times 10^{-8} \, \Omega \cdot \text{m}}\\)

After performing the calculation, we find that the length of the tungsten filament should be approximately 5.96 meters.

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Part 1. To find the force function F(x) for the spring described, where it takes a force of 17 N to compress the spring 0.5 m from the equilibrium position, we use Hooke's law. According to Hooke's law, F(x) = kxF(x) = 17 N when x = 0.5 m17 = k(0.5)k = 34The force function for the spring described is given by:F(x) = kx = 34x.Part 2.

To set up the integral that will give the work required to stretch the spring 1.5 m from the equilibrium position, we use the work-energy theorem which states that the work done by a force is equal to the change in kinetic energy of the object acted upon. So, if we want to stretch the spring from its equilibrium position, we will apply a force that is greater than or equal to the force function that we just found above.

The work done to stretch the spring from its equilibrium position to a position x = 1.5 m is given by:W = ∫a b F(x)dx, where a = 0 and b = 1.5, and F(x) = 34x.The integral is given by:W = ∫0 1.5 34xdx= 34[x2/2]1.5 0= 34(1.52/2) = 38.25 JPart 3. To calculate the work done by the force described above, which was found to be W = 38.25 J, we use the work-energy theorem which states that the work done by a force is equal to the change in kinetic energy of the object acted upon.

Since the spring was at rest before the force was applied, the work done by the force is equal to the potential energy stored in the spring. Therefore, the work done by the force described above is 38.25 J.

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The distance the wave traveled between the two-point is the path difference. The path difference will be 2200 nm and 3 orders of bright lines do this equal red light with a wavelength of 650 nm.

A diffraction grating is a type of optical instrument obtained with a continuous pattern. The pattern of the diffracted light by a grating depends on the structure and number of elements present.

The equation of diffraction grating is given as

\(\rm n\lambda=dsin\phi\\\\\rm n\lambda=0.50\times10^{-3}\times sin(0.25) \\\\ n\rm \lambda=2.18\times10^{-6} \;m \\\\\rm n\lambda=2200\;nm\)

Hence the path difference will be 2200 nm.

\(\rm n\lambda=2200\;nm \\\\\rm n\times650=2200 \\\\\rm n=3.38\)

n= 3

Hence 3 orders of bright lines do this equal red light with a wavelength of 650 nm.

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Answer: The Sun's energy is more concentrated on the equator than the poles. This is because the Sun's energy (in the form of warmth) is more direct at the equator, and less direct at the poles.

Explanation: You can see this with a flashlight. When you point the flashlight directly toward a tale, the light is very concentrated and right. However, when you point the flashlight toward the table at an angle, the light becomes more spread out and less concentrated.  This is why even though sometimes the North Poles and South Poles have 24 hours of sunlight, it never actually reaches a high temperature and instead, keeps it's cold temperature.

The friction between two surfaces depends on the nature of the surfaces involved. Friction is generally greater between two solid surfaces compared to a solid surface and a fluid surface.

When two solid surfaces come into contact, the irregularities and bumps on their surfaces interlock, creating more friction. This is known as dry friction. For example, if you try to slide a book across a table, you will feel resistance due to the friction between the book and the table.

On the other hand, when a solid surface interacts with a fluid surface (such as air or water), the friction is typically lower. This is because fluids have less resistance compared to solid surfaces. For example, a ball rolling on a smooth surface will experience less friction compared to the same ball rolling on a rough surface.

In conclusion, friction is greater between two solid surfaces compared to a solid surface and a fluid surface. This is because the interlocking of surface irregularities in solids increases friction, while fluids offer less resistance to motion.

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Hi there!

1.

The period of a pendulum can be calculated using the following equation:
\(\large\boxed{T = 2\pi \sqrt{\frac{L}{g}}}\)

T = period (s)

L = length of string (m)
g = acceleration due to gravity (m/s²)

Plug in the values:

\(T = 2\pi \sqrt{\frac{4}{9.8}} = \boxed{4.014 s}\)

2.

Calculate the period:

\(T = \frac{\text{Time}}{\# of oscillations} = \frac{5}{20} = \boxed{0.4 s }\)

Frequency is the reciprocal of the period, so:

\(f = \frac{1}{T} = \frac{1}{0.4} = \boxed{2.5 Hz}\)

Answer:

.21

Explanation:

i see everyone got it wrong so ill give you the answer, good luck :)

If the time period of the pendulum in earth is 1 seconds, then the length  L is 0.24 m. If length in mars is L/2 and acceleration due to gravity is 1/3rd of that of earth, the time period of the pendulum on mars is 1.216 seconds.

The time period of oscillation of a pendulum is the time taken to complete oscillation. It is related to the length l, and acceleration due to gravity g as:

T = 2π √l/g

T for earth = 1 s

g for earth = 9.8 m/s²

then l = T/4π² × g

l = 1/4π²× 9.8 m/s²

 = 0.24 m

If in mars L = L/2 = 0.24 /2 = 0.12 m

g = 9.8 m/s²/3 = 3.22m/s²

Then time period T = 2π × √0.12 m/3.22m/s²

T = 1.216 s.

Therefore, the time period of the Rover's pendulum in mars is 1.216 seconds.

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Answer:

18301.4Kg

Explanation:

Step 1:

Data obtained from the question. This include the following:

Mass 1 (M1) = 0.512Kg

Mass 2 (M2) =..?

Distance apart (r) = 0.0250m

Force (F) = 0.001N

Gravitational force constant (G) = 6.67x10^-11Nm²/Kg²

Step 2:

Determination of the mass, M2 needed to create a force of 0.001N.

This can be obtained as follow:

F = GM1M2/r²

0.001 = 6.67x10^-11 x 0.512 xM2/0.025²

Cross multiply

6.67x10^-11 x 0.512 xM2 = 0.001x0.025²

Divide both side by 6.67x10^-11 x 0.512

M2 = (0.001x0.025²)/(6.67x10^-11x0.512)

M2 = 18301.4Kg

Therefore, a mass of 18301.4Kg is needed

Answer:

See below

Explanation:

Assuming no resistance

DISTANCE =  1/2 a t^2

443 = 1/2 (9.81)t^2      Shows t = 9.5 seconds

The acceleration of elevator is \(3 m/s^{2}\).

We know that from Newton's equation of motion,

                                         v = u + at

Where,

v = final velocity = 12 m/s

u = initial velocity = 0

a = acceleration

t = time = 4s

Putting these values in above equation we get:

                              v = at

                         ⇒ a = v/t

                         ⇒ a = 12 / 4 = \(3 m/s^{2}\).

So the acceleration of elevator is \(3 m/s^{2}\).

Newton’s 2nd law states that the acceleration of an object as produced by a net force is directly proportional to the magnitude of the net force, in the same direction as the net force, and inversely proportional to the object’s mass.

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Answer:

Below are some of the important dates that led to the creation of the Constitution: 1775 — The Revolutionary War between the Colonies and Britain begins. ... 1781 — The last battle of the Revolutionary War takes place; the 13 states set up a federal government under laws called the Articles of Confederation.

Explanation:

please give me a heart

The net force exists 0 when the forces are in equilibrium. They have the same impact as if there were no forces at all.

Net Force, which is essentially the total of all the forces operating on an item, is the combination or consequence of those forces.

The total of all forces exerted on an object is known as the net force. A mass can accelerate due to net force. A body is subject to another force whether it is at rest or in motion. When there exists a lot of forces acting on a system, the term "net force" exists employed.

Equal in size and directed in the opposite direction, balanced forces are. When forces are evenly distributed, motion remains unchanged. One of your scenarios from the previous section involved pushing or pulling an object with the equal amount of force in opposite directions.

The complete question is:

Directions: Answer each question by circling the correct choice. After you have completed all of the questions, color the picture using the assigned colors.

Question

Choice A

1. The sum of all forces acting on an object is known as...

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Answer:

No. ... UV light causes sunburn, whereas visible light does not.

Explanation:

The light energy produced from a light bulb is far low compared to the light energy produced by the sun. The heat energy also greatly differ in both.

Light energy is a form of energy produced by stars and man made devices. One form of energy can be transformed into other form without destroying the energy.

The source of light and heat energy in stars is nuclear fusion. Fusing of two light nuclei forming a heavy nuclei accompanies the release of tremendous amount of energy.

In a light bulb, the electrical energy is converted to light energy and some energy is lost in the form of heat energy. The light the white light produced by a bulb cannot be as intense as the white lite from sun.

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Answer:

the answer for your question is that they are unbalanced

The emission spectrum for the collection of quantum harmonic oscillators can be determined by considering the energy differences between the levels. Given that the spacing between levels is 0.4 eV, the energy differences between adjacent levels are also 0.4 eV.

To find the complete emission spectrum, we need to consider all possible energy transitions between the levels. Starting from the ground state, the transitions to higher energy levels will have energies of 0.4 eV, 0.8 eV, and 1.2 eV, respectively.

Thus, the emission spectrum will consist of photons with energies of 0.4 eV, 0.8 eV, and 1.2 eV. These energies correspond to wavelengths of approximately 3.10 μm, 1.55 μm, and 1.03 μm, respectively.

The emission spectrum for the system of quantum harmonic oscillators includes photon energies of 0.4 eV, 0.8 eV, and 1.2 eV, which correspond to infrared wavelengths.

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The work done by the elevator motor to lift the elevator is given by:

W = mgh

where m is the mass of the elevator, g is the acceleration due to gravity, and h is the height the elevator is lifted.

Plugging in the given values, we get:

W = (1300 kg) x (9.81 \(m/s^2\)) x (200 m) = 2.54 x \(10^6 J\)

Therefore, the elevator motor does 2.54 x \(10^6\) Joules of work to lift the 1300 kg elevator a height of 200 m.

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