Answer:
42.86 m
Explanation:
the frequency, speed, and wavelength are related with the following equation
v = λf
Where v is the speed, λ is the wavelength and f is the frequency.
Solving for λ, we get:
λ = v/f
Then, we can replace v = 1500 m/s and f = 35 Hz to get
\(\begin{gathered} \lambda=\frac{v}{f} \\ \\ \lambda=\frac{1500\text{ m/s}}{35\text{ Hz}}=42.86\text{ m} \end{gathered}\)Therefore, the wavelength of the sound is 42.86 m
Part A
Find the water pressure at the bottom of the 54-m-high water tower in the following figure.
Express your answer to two significant figures and include the appropriate units.
Incorrect; Try Again; 5 attempts remaining
Enter your answer with a different unit type. Review a list of acceptable units.
The water pressure at the bottom of the 54-m-high water tower is
0.53 M Pa0.53 M N/m²How to calculate the pressure of waterpressure of water at a certain depth is calculated using the formula
Pressure, P = height * density * acceleration due to gravity
density of water is given by = 1000 kg/m³
acceleration due to gravity is given by = 9.82 m/s²
the given height, at the bottom of the 54-m-high water tower = 54 m
Pressure = 1000 kg/m³ * 9.82 m/s² * 54 m
Pressure = 530280 N/m²
Pressure = 0.53 M N/m²
Pressure = 0.53 M Pa
The pressure at the bottom of the 54-m-high water tower is 0.53 MPa
The unit of pressure used here is Pa which is equal to N/m² other unit include pound - force foot
1 N/m² = 0.73756 pound-force foot
530280 N/m² = 530280 * 0.73756 = 391113.32 pound-force foot
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Landslides are an example of
Answer: Landslides are a type of "mass wasting," which denotes any down-slope movement of soil and rock under the direct influence of gravity. ... Debris flows (commonly referred to as mudflows or mudslides) and rock falls are examples of common landslide types. Almost every landslide has multiple causes.
When both distance and direction are indicated, it becomes a
WHEN AN OBJECT IS DROPPED WHAT HAPPENDS TO THE POTENTIAL AND KENETIC ENERGY AS IT FALLS?
Answer:
The sum of an object's potential and kinetic energies is called the object's mechanical energy. As an object falls its potential energy decreases, while its kinetic energy increases. The decrease in potential energy is exactly equal to the increase in kinetic energy.
Explanation:
Answer:
the potential decrease and kinetic increase
Explanation:
because it goes from a state of rest to a state of movement
Six identical cells with an EDS of 3 V connected in a battery. Resistors R₁ and R₂=16Ω are connected to the battery, the total resistance of the external circuit is R=6Ω and the current flowing in it is 1 A. Determine the resistance of the first resistor and the EDS and internal resistance of the battery.
- The resistance of the first resistor (R₁) is 12 Ω.
- The electromotive force (EMF) of the battery is 18 V.
- The internal resistance of the battery is 12 Ω.
To solve the given problem, we can apply Kirchhoff's laws and Ohm's law to determine the resistance of the first resistor (R₁) and the electromotive force (EMF) and internal resistance of the battery.
Let's start by calculating the resistance of the first resistor (R₁):
1. Apply Ohm's law to find the voltage drop across the external circuit:
V = I * R
V = 1 A * 6 Ω
V = 6 V
2. The voltage drop across the external circuit is equal to the EMF minus the voltage drop across the internal resistance of the battery:
V = E - Ir
6 V = E - (1 A * r) (where r is the internal resistance of the battery)
3. We also know that the EMF of the battery is the sum of the voltage drops across each cell in the battery:
E = 6 cells * 3 V/cell
E = 18 V
4. Substitute the value of E in the equation from step 2:
6 V = 18 V - r
r = 12 Ω
Therefore, the resistance of the first resistor (R₁) is 12 Ω.
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In a sinusoidally driven series RLC circuit, the inductive resistance is XL = 100 Ω, the capacitive reactance is XC = 200 Ω, and the resistance is R = 50 Ω. The current and applied emf would be in phase if
Answer:
The current and the applied emf can be in phase if either of the two changes are made.
1) The inductance of the inductor is doubled, with everything else remaining constant.
2) The capacitance of the capacitor is doubled, with everything else remaining constant.
Explanation:
The current and applied emf for this type of circuit would be in phase when there is no phase difference between the two quantities. That is, Φ = 0°.
The phase difference between current and applied emf is given as
Φ = tan⁻¹ [(XL - Xc)/R]
XL = Impedance due to the inductor
Xc = Impedance due to the capacitor
R = Resistance of the resistor.
For Φ to be 0°, tan⁻¹ [(XL - Xc)/R] = 0
But only tan⁻¹ 0 = 0 rad
So, for the phase difference to be 0,
[(XL - Xc)/R] = 0
Meaning
XL = Xc
But for this question,
XL = 100 Ω, Xc = 200 Ω
For them to be equal, we have to find a way to increase the impedance of the inductor or reduce the impedance of the capacitor.
The impedance are given as
XL = 2πfL
Xc = (1/2πfC)
f = Frequency
L = Inductance of the inductor
C = capacitance of the capacitor
The impedance of the inductor can be increased from 100 Ω to 200 Ω by doubling the inductance of the inductor.
And the impedance of the capacitor can be reduced from 200 Ω to 100 Ω by also doubling the capacitance of the capacitor.
So, these are either of the two ways to make the current and applied emf to be in phase.
Hope this Helps!!!
An object with a mass of 70.5 kg is placed on a 2-meter strand of metal (with a 2-millimeter radius) hanging from the ceiling. It stretches 1 millimeter. What is this strand made of?
Based on the value of the Young's modulus, the strand of the metal is made of copper.
Young's modulus of the metalThe Young's modulus of the metal is calculated as follows;
E = stress/strain
Stress of the metalThe stress of the metal is calculated as follows;
σ = F/A = mg/A
where;
A is area of the metal
A = πr²
A = π( 2 x 10⁻³)²
A = 1.257 x 10⁻⁵ m²
σ = (70.5 x 9.8) / (1.257 x 10⁻⁵)
σ = 5.5 x 10⁷ N/m²
Strain of the metalThe strain is calculated as follows;
strain = x/L
where;
x is extension
L is original length
strain = (1 x 10⁻³ m) / 2 m
strain = 5 x 10⁻⁴
Young's modulus of the metal
E = stress/strain
E = (5.5 x 10⁷ ) / (5 x 10⁻⁴)
E = 1.1 x 10¹¹ N/m²
E = 110 Gpa
The Young's modulus of copper metal is 110 Gpa
Thus, based on the value of the Young's modulus, the strand of the metal is made of copper.
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The first P-wave of an earthquake travels 5600 kilometers from the epicenter and arrives at a seismic station at 10:05 a.m. At what time did this earthquake occur?
Ahhhhhh I have a Regent's test in 2 hours and I don't know how to solve this type of question! Any help would be appreciated.
Anyone know what the steps to do this are? I dont even need an answer, just how to get to it. Thank you!
The earthquake would occur 13 minutes before 10:05 a.m. which will be at 9.52 am.
The p-waves travel with a constant velocity of 7 km/s
The time can be calculated by using the formula
t = d / v
where
T1 = 10:05 a.m
d is the distance they take to travel from the epicenter
v is the speed of the p-waves
On average, the speed of p-waves is
v = 7 km/s
d = 5600 km (given)
Substituting the values in the formula;
t = d / v
t = 5600 ÷ 7
t = 800 seconds
Converting into minutes,
t = 800 ÷ 60
t = 13.3
≈ 13 mins
T1 - 13 mins = T2
10:05 - 13 mins = 9.52 am
It means the earthquake occurred prior 13 minutes, that is at 9.52 am.
Therefore, the earthquake occurred at 9.52 am.
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What is the equation for Newton’s second law?
force = mass + acceleration
force = mass * acceleration
force = mass / acceleration
force = mass - acceleration
Answer:
the second one force=mass*acceleration
Explanation:
Newton explains that taking the mass of an object times its acceleration will determine the force the so-called object will exert.
if an 80kg object has 632 J of PE, how high is it
The object is on 81 cm high.
What is potential energy?The energy that an item has or acquires when its location changes as a result of being in a gravitational field is known as gravitational potential energy. Gravitational potential energy can be defined as an energy that has a connection to gravitational force or gravity.
Given that: an 80kg object has 632 J of Potential energy.
Let the height is h: then,
mgh = PE
80 kg × 9.8× m/s^2 × h = 632 Joule
h = 0.81 m = 81 cm.
The object is on 81 cm high.
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A high-resistance material is used as an insulator between the conductors of a length of coaxial cable. The resistance material, which forms a hollow tube, has an inner radius a and an outer radius b, and the insulator provides a resistance R between the conductors. If a second insulator, made of the same material and having the same length, is made with double both the inner radius and the outer radius of the first, what resistance would it provide between the conductors
This question is incomplete, the complete question is;
A high-resistance material is used as an insulator between the conductors of a length of coaxial cable. The resistance material, which forms a hollow tube, has an inner radius a and an outer radius b, and the insulator provides a resistance R between the conductors. If a second insulator, made of the same material and having the same length, is made with double both the inner radius and the outer radius of the first, what resistance would it provide between the conductors
a) (In2)R
b) 4R
c) R/(In2)
d) 2R
e) R
Answer: Option e) R is the correct answer.
Explanation:
Given that;
Inner radius = a
Outer radius = b
Conical Cylinder
∫dR = ∫(edr/2πrL)
R = e/2πL In e |ᵇₐ
R = e/2πL In(b/a) ------------- let this be equation 1
Taking a look at the second cone
a' = 2a
b' = 2a
R' = e/2πL In(2b/2a)
{L = L'}
R' = e/2πL In(b/a) -------let this be equation 2
now lets compare the two equation
R = e/2πL In(b/a)
R' = e/2πL In(b/a)
so R' = R
Therefore Option e) R is the correct answer.
Suppose that the current in the solenoid is i(t). The self-inductance L is related to the self-induced EMF E(t) by the equation E(t)=−Ldi(t)/dt. Find L for a long solenoid with n turns. (Hint: The self-inductance L will always be a positive quantity.), Epxress in μ0, di, dt, R and n
Answer:
L = μ₀ n r / 2I
Explanation:
This exercise we must relate several equations, let's start writing the voltage in a coil
\(E_{L}\) = - L dI / dt
Let's use Faraday's law
E = - d Ф_B / dt
in the case of the coil this voltage is the same, so we can equal the two relationships
- d Ф_B / dt = - L dI / dt
The magnetic flux is the sum of the flux in each turn, if there are n turns in the coil
n d Ф_B = L dI
we can remove the differentials
n Ф_B = L I
magnetic flux is defined by
Ф_B = B . A
in this case the direction of the magnetic field is along the coil and the normal direction to the area as well, therefore the scalar product is reduced to the algebraic product
n B A = L I
the loop area is
A = π R²
we substitute
n B π R² = L I (1)
To find the magnetic field in the coil let's use Ampere's law
∫ B. ds = μ₀ I
where B is the magnetic field and s is the current circulation, in the coil the current circulates along the length of the coil
s = 2π R
we solve
B 2ππ R = μ₀ I
B = μ₀ I / 2πR
we substitute in
n ( μ₀ I / 2πR) π R² = L I
n μ₀ R / 2 = L I
L = μ₀ n r / 2I
The self-inductance of the solenoid is determined as \(\L = \frac{\mu_o N^2 \pi R^2}{l}\).
The emf induced in a solenoid is given by Faradays law;
\(emf = \frac{d\phi}{dt} \\\\emf = \frac{Ldi}{dt} \\\\d\phi = Ldi\\\\\phi = BA\\\\\)
For "N" number of turns in the solenoid, we will have total flux;
\(NBA = LI\\\\\phi = LI\)
Magnetic field at any point on a long solenoid is given as;
\(B = \frac{\mu_0 NI}{l}\)
The total magnetic flux is given as;
\(\phi = NBA\\\\\phi = N \times \frac{\mu_0 NI}{l} \times A\\\\\phi = \frac{\mu_o N^2 IA}{l}\)
\(Recall, LI = \phi\\\\LI = \frac{\mu_o N^2 I A}{l} \\\\L = \frac{\mu_o N^2 A}{l}\\\\L = \frac{\mu_o N^2 \pi R^2}{l}\)
Thus, the self-inductance of the solenoid is determined as \(\L = \frac{\mu_o N^2 \pi R^2}{l}\)
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A 0.0780 kg lemming runs off a
5.36 m high cliff at 4.84 m/s. What
is its potential energy (PE) when it
lands?
The potential energy of the lemming when it lands is 0.9108672 J.
To determine the potential energy (PE) of the lemming when it lands, we need to consider the conservation of energy. The potential energy of an object is given by the formula PE = mgh, where m is the mass of the object, g is the acceleration due to gravity, and h is the height.
Given:
Mass of the lemming (m) = 0.0780 kg
Height of the cliff (h) = 5.36 m
First, let's calculate the potential energy when the lemming is on the cliff. Using the given formula, we have:
PE = mgh
PE = 0.0780 kg * 9.8 m/s² * 5.36 m
PE = 0.413616 J
Next, we need to determine the final kinetic energy of the lemming just before it lands. We can use the equation for kinetic energy (KE) given by KE = (1/2)mv², where v is the velocity of the lemming.
Given:
Velocity of the lemming (v) = 4.84 m/s
Calculating the kinetic energy, we have:
KE = (1/2) * 0.0780 kg * (4.84 m/s)²
KE = 0.9108672 J
According to the conservation of energy, the potential energy at the top of the cliff is equal to the kinetic energy just before landing.
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A proton traveling due west in a region that contains only a magnetic field experiences a vertically upward force (away from the surface of the earth). What is the direction of the magnetic field?
South
Explanation:
The magnetic force F on a point charge moving with a velocity v in the presence of a magnetic field B is given by
\(\vec{\textbf{F}} = q\vec{\textbf{v}}\textbf{×}\vec{\textbf{B}}\)
and according to the right-hand rule, an upward magnetic force on a proton moving westward is only possible if the magnetic field is directed southward.
the following curves shows stress-strain analyses of the vertebrae bone of a normal and immobilized rhesus monkey. explain which law governs this phenomenon and what principle it stipulates. provide another example in everyday life. explain what major biological and mechanical property changes occur after immobilization
After immobilization, the biological and mechanical properties of the vertebrae bone change. The biological properties include changes in the cells, tissues, and organelles, which can cause the material.
What is mechanical ?Mechanical is the branch of physics that deals with the motion and behavior of physical objects and the application of forces to them. It is a science that combines engineering, materials science, and physics to design, analyze, manufacture, and maintain mechanical systems.
The stress-strain analysis of the vertebrae bone of a normal and immobilized rhesus monkey is an example of Hooke’s Law. This law states that the force (or stress) applied to a material is directly proportional to the resulting strain (or deformation).
An example of Hooke’s Law in everyday life is the behavior of a spring. When a force is applied to a spring, it will compress or extend in direct proportion to the force applied.
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What is the average velocity if the initial velocity of an object is 10 m/s & the final velocity is 28 m/s
Answer:
\(v_{1} = 19 m/s\)
Explanation:
\(v_{1} = \frac{(v_{2} + u)}{2}\), where \(v_1\) = avg. velocity, \(v_2\) = final velocity, and \(u\) = initial velocity.
What is the motion of the particles in this kind of wave? A hand holds the left end of a set of waves. The waves themselves make a larger set of waves in the same direction as that of the smaller waves. A label Wave motion is above the series of waves and an arrow next to the label points right. The particles will move up and down over large areas. The particles will move up and down over small areas. The particles will move side to side over small areas. The particles will move side to side over large areas.
Answer:
D
Explanation:
The particles will move side to side over large areas
Answer:
→A←Explanation:
D its incorrect in edge
A 2000 kg test car travels around a circular track with a radius of 100 m. If the
magnitude of the centripetal acceleration is 3 m/s2, what is the car's speed?
Answer:
V=0.38 m/s
Explanation:
ac=3 m/s^2
m=2000kg
r=100m
ac=mv^2/r
Solve for v^2
3=2000(v^2)/100
3=20v^2
3/20=.15
sqrt of .15= 0.38 m/s
V=0.38 m/s
If the electrical resistance of a household appliance becomes four times larger than the original value, how much current does the appliance then use
If the electrical resistance of a household appliance becomes four times larger than the original value, AND the voltage at the outlet doesn't change, then the appliance starts to use 1/4 of the original current.
I = E / R
What is sound waves
Sound waves are a type of mechanical wave that propagate through a medium, typically air but also other materials such as water or solids.
Characteristics of sound wavesFrequency: the frequency of a sound wave refers to the number of cycles or vibrations it completes per second and is measured in Hertz (Hz).
Amplitude: the amplitude of a sound wave refers to the maximum displacement or intensity of the wave from its equilibrium position. It represents the loudness or volume of the sound, with larger amplitudes corresponding to louder sounds and smaller amplitudes corresponding to softer sounds.
Wavelength: the wavelength of a sound wave is the distance between two consecutive points in the wave that are in phase, such as from one peak to the next or one trough to the next. It is inversely related to the frequency of the wave.
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Two cars collide head-on and stick together.
Car A, with a mass of 2000 kg, was initially
moving at a velocity of 10 m/s to the east. Car
B, with an unknown mass, was initially at rest.
After the collision, both cars move together at
a velocity of 5 m/s to the west. What is the
mass of Car B?
OF
The mass of Car B is -6000 kg.
To solve this problem, we can apply the principle of conservation of momentum, which states that the total momentum before the collision is equal to the total momentum after the collision.
Therefore, we can write the equation for the conservation of momentum as:
(mass of Car A * velocity of Car A) + (mass of Car B * velocity of Car B) = (mass of Car A + mass of Car B) * velocity after collision
Let's substitute the given values into the equation:
(2000 kg * 10 m/s) + (mass of Car B * 0 m/s) = (2000 kg + mass of Car B) * (-5 m/s)
Simplifying the equation:
20000 kg*m/s = -5 m/s * (2000 kg + mass of Car B)
Dividing both sides by -5 m/s:
-4000 kg = 2000 kg + mass of Car B
Subtracting 2000 kg from both sides:
mass of Car B = -4000 kg - 2000 kg
mass of Car B = -6000 kg
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PHYSICS : MODULE 01 GALILEO GARDENS : 01.02 GRAPHING DATA
Graphing Activity
Let’s take another look at the experimental data given to you in the exploratory activity. Graph the data once again, applying the knowledge and skills you have learned.
Procedure:
Table 1 shows some data that Rafael and Cristine collected during an experiment to measure the stretch of a spring as more force was applied.
Graph the data from Table 1 on your graph paper. Do not use a graphing program.
The experimental value of the expression due to gravity through the experiment will come out to be 8.41u, the error in the value has Accord because of air friction.
What is acceleration due to gravity?Acceleration due to gravity is a form of acceleration that is exercised by the gravitational pull of the earth its value is fixed at the surface n is equal to 9.8u.
What is air friction?Aries composed of molecules and their food when an object passes through air strikes the a molecules they are molecules according to Newton's third law strike back at the object therefore reducing its speed. This force by the molecule is known as air friction.
The setup of the given experiment consists of:
A bob of mass m
A stopwatch with high accuracy
An inch tape
A speedometer
Experiment is conducted in the following manner:
First the bob will be released and from the point that it is being released we will measure the distance using the inch tape we will also calculate the time it takes for the bob to hit the ground.Using the speedometer will measure the final velocity before it is the ground.Now using Newton's first law of motion we can derive the acceleration due to gravity we know the final velocity using the speedometer the distance it has covered and the time it has taken to complete that distance.Using Newton's first law of motion
i.e. v = u + a × t
Where,
u is initial velocity
v is final velocity
a is acceleration due to gravity
t is time taken to cover distance
From the data given v = 16.82m/s
t is 2 seconds
Substituting value in Newton's first law of motion we get
Value of acceleration due to the gravity = 8.41
Therefore, The experimental value of the expression due to gravity through the experiment will come out to be 8.41u, the error in the value has Accord because of air friction.
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The pressure of liquid varies as per it's depth.
Answer: The pressure in a liquid is different at different depths. Pressure increases as the depth increases. The pressure in a liquid is due to the weight of the column of water above. The greater pressure at the bottom would give a greater 'force per unit area' on the wall.
Explanation:
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Answer:
hello me
Explanation:
help me thisanswer
What is the displacement (in miles, with direction) from the
Aquarium to the Cemetery?
Look up "Everything You Need To Know About Math In One Big Fat Notebook pdf." It's the best thing I've ever been given, I have it with me in math class all the time and I've aced every test. I have it with me right now and it has everything I've ever been taught about math in it so it might help you.
what evidence supports the information consolidation theory?
PLEASE HELP ME ITS DUE NEXT PERIOD
Explanation:
Memory loss in retrograde amnesia has long been held to be larger for recent periods than for remote periods, a pattern usually referred to as the Ribot gradient. One explanation for this gradient is consolidation of long-term memories. Several computational models of such a process have shown how consolidation can explain characteristics of amnesia, but they have not elucidated how consolidation must be envisaged. Here findings are reviewed that shed light on how consolidation may be implemented in the brain. Moreover, consolidation is contrasted with alternative theories of the Ribot gradient. Consolidation theory, multiple trace theory, and semantization can all handle some findings well but not others.
will give brainliest pls help
Answer:
a and c
Explanation:
(Figure 1) is the potential-energy diagram for a 500 g particle that is released from rest at A . What is the particle's speed at B ?
Answer:
Explanation:
according to the graph at B the potential energy of the particle is 2J
therefore we can use the kinetic energy equation to calculate the particle's velocity or speed.
\(E_{k} =1/2mv^{2}\)
2J= 1/2*1/2kg*v^2
8=v^2
v= 2√2 ms-1
An arrangement of two pulleys, as shown in the figure, is used to lift a 64.3-kg crate a distance of 4.36 m above the starting point. Assume the pulleys and rope are ideal and that all rope sections are essentially vertical.What is the change in the potential energy of the crate when it is lifted a distance of 4.36 m? (kJ)How much work must be done to lift the crate a distance of 4.36 m? (kJ)What length of rope must be pulled to lift the crate 4.36 m? (m)
Given data:
* The mass of the crate is m = 64.3 kg.
* The height of the crate is h = 4.36 m.
Solution:
(a). The potential energy of the crate at the initial state is zero (as the height of the crate is zero at the initial state), thus, the change in the potential energy of the crate is,
\(\begin{gathered} dU=\text{mgh}-0 \\ dU=mgh \end{gathered}\)where g is the acceleration due to gravity,
Substituting the known values,
\(\begin{gathered} dU=64.3\times9.8\times4.36 \\ dU=2747.4\text{ J} \\ dU=2.75\times10^3\text{ J} \\ dU=2.75\text{ kJ} \end{gathered}\)Thus, the change in the potential energy is 2.75 kJ.
(b). The work done to lift the crate is equal to the change in the potential energy of the crate.
Thus, the work done on the crate is 2.75 kJ.
(c). As the single is pulling the two ropes to increase the height of the crate, thus, the length of the rope pulled in terms of the height of the crate is,
\(l=2h\)Substituting the known values,
\(\begin{gathered} l=2\times4.36 \\ l=8.72\text{ m} \end{gathered}\)Thus, the length of the rope pulled to lift the crate is 8.72 meters.
if the police are chasing a runaway car why is knowing the velocity of the car important
If you only know its speed, that's not enough information to catch it. You could even chase it at DOUBLE that speed, and you'd never catch it if you were chasing in the wrong direction.
You also have to know the DIRECTION the runaway car is going, so that you can chase in the same direction.
Now that you know its speed AND direction, you know its velocity. You need that information to have any chance of catching it.