Dos masas de 8kg es tan unidas en el extremo de una varilla de aluminio de 400mm de longitud. La varilla está sostenida en su parte media hora en círculos y solo puede soportar una tensión máxima de 800 N ¿cuál es la frecuencia máxima de revolución

Answer:

kinetic or mechanical cant remember

Explanation:

Answer:

Hey!!

Kinetic Energy is your answer!

Explanation:

I hope this helped you!

The specific heat capacity of the substance is 444 J/kg.°C.

The specific heat capacity is defined as the quantity of heat (J) absorbed per unit mass (kg) of the material when its temperature increases 1 K (or 1 °C).

To calculate the specific heat capacity of the substance, we use the formula below

Formula:

Where:

From the question,

Given:

Substitute these values into equation 1

Hence, the specific heat capacity is 444 J/kg.°C.

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Is this supposed to be a true or false question? If so, then it's true.

Answer:

diffuse

Explanation:

EDGE

Time taken to accelerate the golf ball is 3.33s.

The acceleration is the time rate of change of velocity.

Given is the initial velocity u=0 m/s, final velocity v =50m/s and  acceleration a =15m/s²

a =v-u/t

t =50 -0 /15

t =3.33 m/s

Thus, the time taken to accelerate is 3.33 s.

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Answer:

b

Explanation:

The angular displacement can be expressed in terms of the final angular velocity, initial angular velocity, and time as θ = (1/2)*(ω_f + ω_i)*t.

What is Angular Velocity?

Angular velocity is a measure of how fast an object is rotating around a central point or axis. It is defined as the change in angle over time, usually measured in radians per second. Angular velocity can be either positive or negative, depending on the direction of rotation, and it is a vector quantity, meaning it has both magnitude and direction. It is often used in the study of rotational motion and is an important concept in physics and engineering.

The angular displacement (θ) of an object rotating with a constant angular acceleration (α) can be found using the following equation:

θ = ω_i*t + (1/2)αt^2

where ω_i is the initial angular velocity of the object, t is the time elapsed, and the other variables are as defined in the question.

If the object starts from rest (ω_i = 0), then the equation simplifies to:

θ = (1/2)αt^2

If the object starts with an initial angular velocity ω_i, and the final angular velocity is ω_f, then we can use the equation for angular acceleration:

α = (ω_f - ω_i) / t

and substitute it into the first equation to get:

θ = (ω_ft - ω_it) + (1/2)*((ω_f - ω_i) / t)*t^2

Simplifying, we get:

θ = ω_ft - ω_it + (1/2)*(ω_f - ω_i)*t

or, equivalently:

θ = (1/2)*(ω_f + ω_i)*t

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(1) The force of gravity between the Earth and the satellite is 8.91 * 10^6 N.

(2)  The orbital period of the satellite is 6,132 seconds i.e. 1 hour and 42 minutes.

(3) The tangential velocity required to keep the satellite in orbit is approximately 7.94 km/s.

(4) The angular velocity of the satellite is 0.0011 radians per second.

(1)  The force of gravity between two objects can be calculated using Newton's law of universal gravitation. The formula is F = (G * m1 * m2) / \(r^2\), where F is the force of gravity, G is the gravitational constant, m1 and m2 are the masses of the objects, and r is the distance between their centers. In this case, the mass of the Earth is much larger than the mass of the satellite, so we can consider the satellite's mass negligible compared to the Earth's mass. Plugging in the values, we get\(F = (6.67 \times 10^{-11} N m^2/kg^2) \times (5.97 \times 10^{24} kg) \times (900 kg) / (6,371,000 m)^2 = 8.91 \times 10^6 \ Newtons\)

(2) The orbital period of a satellite can be determined using Kepler's third law of planetary motion, which states that the square of the orbital period is proportional to the cube of the semi-major axis of the orbit. Since the satellite is orbiting at a radius equal to one Earth radius above the surface, the semi-major axis is the sum of the Earth's radius and the altitude of the satellite. Using the formula \(T = 2\pi \times\sqrt{(a^3 / (G \times M)}\), where T is the orbital period, a is the semi-major axis, G is the gravitational constant, and M is the mass of the Earth, we can calculate the value. Plugging in the values, we get \(T = 2\pi \times\sqrt{6,371,000}\) meters +\((6,371,000 \ m)^3 / (6.67 \times 10^{-11} N m^2/kg^2 \times 5.97 \times 10^{24} kg)\) = 6,132 seconds.

(3) The tangential velocity required to keep a satellite in orbit can be determined using the formula \(v = \sqrt{G \times M / r\) where v is the tangential velocity, G is the gravitational constant, M is the mass of the Earth, and r is the distance between the center of the Earth and the satellite. Plugging in the values, we get v = √((6.67 x 10^-11 N m^2/kg^2 * 5.97 x 10^24 kg) / \(v = \sqrt{\frac{(6.67 \times 10^{-11} N m^2/kg^2 \times 5.97 \times 10^{24} kg) }{(6,371,000 m + 6,371,000 m)}\)) = 7,906 m/sec.

(4) The angular velocity of a satellite in orbit can be calculated using the formula ω = v / r, where ω is the angular velocity, v is the tangential velocity, and r is the distance between the center of the Earth and the satellite. Plugging in the values, we get ω = 7,906 meters per second / (6,371,000 meters + 6,371,000 meters) = 0.0011 radians per second.

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The electrical operating conditions are typically measured with Multimeter, Oscilloscope, and Clamp Meter. Thus, option D is the accurate answer.

A multimeter is the most common and versatile instrument which is used to measure the voltage, resistance, and current passing through the conductors. IT can able to provide continuous frequency. An Oscilloscope is also a device used to measure electrical waveforms

A clamp Meter is a small handheld device that can able to measure both AC and DC currents in the circuit in digital format. It uses a small induction coil to measure the amount of current passing through the conductor.

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The complete question is:

the electrical operating conditions are typically measured with a(n):

a. Multimeter

b. Oscilloscope

c. Clamp Meter

d. All the above

The efficiency of the engine is 60%.

The efficiency of a heat engine describes the amount of input energy converted into useful work.

It also entails the amount of useful work done by the engine. The greater the amount of useful work done by the engine, the greater the efficiency of the engine.

The efficiency of an engine ranges from 0 to 100%.

If there four stages in the energy conversion cycle, and 10% energy is wasted in each cycle, the total energy wasted in the four cycles is calculated as;

Total wasted energy = 4 x 10% = 40%

Efficiency of the engine = Useful energy = 100% - 40% = 60%

Thus, the efficiency of the engine is the useful work done by the engine.

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Answer:

Gamma radiation .

Explanation:

Three types of emission result at the time of nuclear emission .

alpha emission

Beta emission

Gamma radiation emission

Gamma radiation results in the emission of gamma ray . This is a very high frequency radiation . It is not a particle having charge and mass like alpha and beta emission . So it has no effect on the mass and charge of the product that is formed after gamma radiation . The only effect it has on the product is that it reduces the kinetic energy of the emitting particles or it reduces the internal energy of the product . It causes negligible change in the mass of the product and no change in the charge of the product.

That is why , generally this product is not written in the nuclear reaction .

Answer:

The answer is Gamma ray

Explanation:

Because this is a very high frequency radiation, is not a particle having charge and mass like alpha and beta emission, so it has no effect on the mass and charge of the product that is formed after gamma radiation. The only effect it has on the product is that it reduces the kinetic energy of the emitting particles or it reduces the internal energy of the product, it causes negligible change in the mass of the product and no change in the charge of the product.

Answer:

people play basket ball on espn every year

Explanation:

i just need points

Answer:

mehoy noy

Explanation:

The distance covered by the car as it comes to rest is 13 m.

To calculate the distance covered before the car come to stop, we use the formula below.

Formula:

v² = u²+2as............... Equation 1

Where:s = distance covered by the car

v = final velocity

u = initial velocity

a = acceleration of the car

make s the subject of the equations

= (v²-u²)/2a........................Equation 2

From the question,

Given:

v = 50 mi/h = (50×0.447) = 22.35 m/su = 0

m/sa = 50 ft/s² = (50×0.3048)

= 15.24 m/s²

Substitute these values into equation

2s = (22.35²-0²)/(2×15.24)s

= 13m

Hence, the distance covered by the car as it comes to rest is 13 m.

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Answer:

Meteoroids are objects in space that range in size from dust grains to small asteroids. Think of them as “space rocks." When meteoroids enter Earth's atmosphere (or that of another planet, like Mars) at high speed and burn up, the fireballs or “shooting stars” are called meteors.

Explanation:

thx to the internet

The east component of the car's displacement to the nearest tenth is 17.3 miles.

The given parameters:

The east component of the car's displacement to the nearest tenth is calculated as follows;

\(D_x = 20 \ miles \times cos(30)\\\\D_x = 17.3 \ miles\)

Thus, the east component of the car's displacement to the nearest tenth is 17.3 miles.

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Using this formula m=W/g, the mass of an object if its weight on earth is 1150N is 117.347 kg

Let mass of an object be m, weight be W and acceleration due to gravity is g.

From the formula m=W/g

mass m =?

weight w = 1150N

g=9.8 m/\(s^{2}\)

So,  the mass of an object if its weight on earth is 1150N will be calculated as:

m=1150/9.8

m=117.347 kg

Hence using the formula m=W/g, the mass of an object if its weight on earth is 1150N will be 117.347 kg.

This is in acceptance with Newton's laws of motion as well and thus calculated according to given formula.

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Imaging techniques that use wave behaviors are -

Ultrasound is used to improve absorption of a radioactive pellet by a tumor. The radioisotope in a radiopharmaceutical releases sound waves into surrounding cells. Beams of X-rays are targeted at a cancerous tumor from outside the body.

HIFU is a cancer treatment that uses high-frequency sound waves. You have HIFU from a machine. The machine gives off the sound waves which deliver a strong beam to a specific part of a cancer. This heats and destroys the cancer cells.

HIFU can treat a single tumour or part of a large tumour. But it is not suitable for people with cancer that has spread to more than one place in their body.

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Answer:

The kinetic energy of the molecules increases as it heats up causing it to vibrate faster and faster.

Explanation:

Sound travels at approximately 343 meters (or 1,125 feet) per second in dry air at room temperature.

To determine how far away lightning is when thunder sounds 10 seconds after the lightning flash, we can use the speed of sound.

Distance = Speed × Time

Distance = 343 m/s × 10 s

Distance = 3,430 meters

Therefore, if thunder sounds 10 seconds after the lightning flash, the lightning is approximately 3,430 meters (or 3.43 kilometers) away.

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Answer:

saddle weighs 250 newtons. The mass of the saddle is ____250/9.8 kg______ kilograms. Use g = 9.8 N/kg for gravity.

Answer:  weight on Jupiter = 869.75 N

              mass  on Earth = mass on Jupiter = 35.5 Kg

Explanation:

W = mg

W = weight

m = mass

g = gravitational acceleration [ on the Earth, g₁ = 9,8 N/kg ]

On the Earth,

G₁ = m x g₁  = 347,9 N

On the Jupiter,

G₂ = mg₂  

mass on the Earth = mass on the Jupiter !  

m = G₁ : g = 347.9 N : 9,8 N/kg = 35.5 kg

G2 : G1 = 2.5

G₂ = 2,5 G₁ = 2,5 x 347.9 N =  869,75 N

As per the law of conservation of energy, the potential energy of the roller coaster is conserved and converted into some other energy.

The potential energy of the roller coaster is converted into kinetic energy.

The potential energy can be defined as the energy stored in an object due to its position.

Given that a roller coaster moves down a hill.

The roller has a large amount of potential energy due to its relative position from the ground.

When the roller coaster starts, some of its potential energy is used in changing its position. When the roller coaster changes its position and starts moving, it gains kinetic energy to move. This kinetic energy is gained from the potential energy of the coaster.

The kinetic energy gained by the coaster from its potential energy depends on the mass of the coaster and moving speed.

Hence we can conclude that the potential energy of the roller coaster is converted into kinetic energy.

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A measure of mass per unit of volume. It is how much material a certain volume contains. ... If the volume of the object stays the same but the mass of the object increases then its density becomes greater.

Answer: Food chain: cheese a product of the sun.

Explanation:

Food chain: The energy taken from the sun through photosynthesis enables plants to exist and grow.

The animal like cow takes chemical energy from plants by eating plants product.

The cow is able to produce the milk because of the energy that has been taken from the plant.

Since the cheese came out from the milk, we can therefore conclude that the food is initially a product of the sun.

Answer: C6H6

Explanation:

I did it and got it right

Answer:

Yes the answer is C6H6

Explanation:

I just took the test

48% is percentage of the power of the battery is dissipated across the internal resistance and hence is not available to the bulb.

Define resistance

A circuit's opposition to current flow is measured by its resistance. The unit of resistance is one ohm.

A resistor is an electrical component with two terminals that implements electrical resistance as a circuit element. Restricting current flow, adjusting signal levels, dividing voltages, biasing active parts, and terminating transmission lines are just a few of the functions for resistors in electronic circuits.

P = VI

I = V/R

P =  V²/R

R= r + R

P =  12*12(26+3.5)

P = 4.8W

48% is percentage of the power of the battery is dissipated across the internal resistance and hence is not available to the bulb.

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The value of k is 3, and the Taguchi loss function represents the economic loss associated with deviations from the target value.

In the context of quality control, the value of k represents the number of standard deviations that can fit within the tolerance range. In this case, the tolerance range is ±0.04 cm, which means it spans a total of 0.08 cm. To find the value of k, we divide the total tolerance by six times the standard deviation. Since the tolerance is 0.08 cm and the standard deviation is 0.04 cm, we have k = 0.08 / (6 * 0.04) = 3.

The Taguchi loss function is an economic model that quantifies the cost associated with deviations from the target value or specifications. It states that the loss increases quadratically as the actual value deviates from the target value. In this case, the target value is 0.200 cm, and any deviation from this target value will result in an economic loss.

To calculate the loss associated with a specific value, we use the formula Loss = k * (deviation from target)^2. For x = 0.208 cm, the deviation from the target is 0.208 - 0.200 = 0.008 cm. Plugging this value into the loss formula, we have Loss = 3 * (0.008)^2 = $0.00192.

Regarding the economic design specifications, they refer to the optimal range or target value that minimizes the total cost considering inspection and adjustment expenses. To determine the economic design specifications, the cost of inspection and adjustment ($7.50) needs to be taken into account, along with other factors such as the Taguchi loss function, production costs, and customer requirements.

Understanding the concept of Taguchi loss function and its application in quality control helps organizations make informed decisions regarding product specifications, target values, and associated economic costs. By considering the trade-off between the cost of deviations from the target value and the cost of inspection and adjustment, businesses can optimize their processes and minimize losses. Additionally, incorporating customer preferences and market demands into the economic design specifications can enhance customer satisfaction and competitiveness.

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Answer:

Explanation:

Here,

Final mass(m)=150g

Final Temperature(t)=60°C

Temperature of hot water(t1)=90C

Temperature of cold water(t2)=14C

Let the grams of water to be used per face be m1 grams and (150-m1) grams for hot and cold water respectively.

We know that,

Heat lost by hot body=Heat gained by cold body

or, m1 s1 Δt1=m2 s2 Δt2

or, m1 (t1-t)=(150-m1) (t-t2)  [∵s1=s2, SHC of water is taken to be same]

or, m1 (90-60)=(150-m1) (60-14)

or, 30m1=6900-46m1

or, 76m1=6900

∴m1=90.79g

(150-m1)=59.21g

Hence, 90.79g and 59.21 g hot and cold water must be used respectively.

Answer:

"The tendency of an object to resist changes in its state of motion varies with mass. Mass is that quantity that is solely dependent upon the inertia of an object. The more inertia that an object has, the more mass that it has. A more massive object has a greater tendency to resist changes in its state of motion."

Explanation:

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