Draw the major organic product(s) of the following reaction. H20 + NaOH

Polarity affects the melting point of a pure compound because it can affect the strength of intermolecular forces between molecules.

Polar molecules tend to have stronger intermolecular forces, which results in higher melting points for compounds that have a greater degree of polarity. This means that molecules with higher molar masses and that are polar will have the highest melting points.

Polarity of a pure compound refers to the degree to which the electrons in the compound are shared unequally between the atoms. This can be determined by looking at the electronegativity of the atoms involved in the compound. If the atoms have similar electronegativities, the electrons will be shared equally and the bond will be nonpolar.

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When there is the two of the same element on the product side, you can balance chemical reactions by placing the coefficient in front of the element.

It should be noted that coefficients are whole numbers and should be chosen in such a way that they give the smallest possible whole numbers in the ratio of atoms.

Before that, let us revise how to balance chemical equations and then we will learn how to balance equations when there are two of the same element on the product side.

Balancing chemical equations:When we write an equation for a chemical reaction, the number of atoms on both sides of the equation should be equal. Balancing the equation is the process of making the number of atoms equal. 

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Given data:

Mole% of benzene (B) = 30%

Mole% of toluene (T) = 25%

Balance = xylene (X)

Bottom product contains mole% of X = 98%

The overhead product from the second column contains mole% of B in the feed to this column = 97%Composition of overhead product = 94% B

Mole% of X recovered in the bottoms product = 96%

Let's solve the problem:Since the sum of mole% of benzene, toluene, and xylene is 100%, the mole% of X = 100 - 30 - 25 = 45%

In the feed, mole% of B = 30%, mole% of T = 25%, and mole% of X = 45%.

Calculation of benzene emerging in the overhead product from the second column:

Let's consider the flow rate of feed as 100 units, so the flow rate of B in the feed = 100 × 0.3 = 30 units.The flow rate of B in the overhead product of the first column = 30 × 0.03 = 0.9 units (since 97% of benzene in the feed is recovered in the overhead product).

Thus, the flow rate of benzene in the feed to the second column is 0.9 units.The composition of the overhead product from the second column is 94% benzene. Thus, the flow rate of benzene in the overhead product from the second column = 0.9 × 0.94 = 0.846 units.

The percentage of benzene emerging in the overhead product from the second column = (0.846/30) × 100 = 2.82%.

Hence, the percentage of benzene in the process feed that emerges in the overhead product from the second column is 2.82%.Calculation of toluene emerging in the bottom product from the second column:

Let's consider the flow rate of feed as 100 units, so the flow rate of T in the feed = 100 × 0.25 = 25 units.The flow rate of T in the overhead product from the first column = 25 × 0.04 = 1 unit (since 96% of the X in the feed is recovered in the bottoms product).

Thus, the flow rate of T in the feed to the second column is 25 - 1 = 24 units.The composition of the bottom product from the second column is 98% X. Thus, the flow rate of X in the bottom product from the second column = 24 × 0.98 = 23.52 units.

The flow rate of T in the bottom product from the second column = 100 - 30 - 23.52 = 46.48 units.The percentage of toluene in the process feed that emerges in the bottom product from the second column = (46.48/25) × 100 = 185.92%.

Hence, the percentage of toluene in the process feed that emerges in the bottom product from the second column is 185.92%.

Thus, the required answers are:

(i) The percentage of benzene in the process feed that emerges in the overhead product from the second column = 2.82%

(ii) The percentage of toluene in the process feed that emerges in the bottom product from the second column = 185.92%.

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Answer:

D

Explanation:

Because of their complementary nature, the oxidation and reduction processes together are referred to as redox reactions. The reactant that brings about the oxidation is called the oxidizing agent, and that reagent is itself reduced by the reducing agent. Examples are, mercury(II) oxide, oxygen, and the copper(II) ion are oxidizing agents, and carbon, hydrazine, and zinc are the reducing agents.

Answer:D

Explanation:Because of their complementary nature, the oxidation and reduction processes together are referred to as redox reactions. The reactant that brings about the oxidation is called the oxidizing agent, and that reagent is itself reduced by the reducing agent. Examples are, mercury(II) oxide, oxygen, and the copper(II) ion are oxidizing agents, and carbon, hydrazine, and zinc are the reducing agents.

Answer:

a. insoluble.

Explanation:

This is the opposite of soluble, which means things can dissolve in a liquid, so insoluble means a solid cannot dissolve in a liquid.

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Reflecting telescopes are preferred for scientific research because they are better suited for gathering large amounts of light and producing high-quality images. However, refracting telescopes are still popular for amateur astronomers and for viewing objects on Earth.

Reflecting telescopes are different from refracting telescopes because reflecting telescopes use mirrors, whereas refracting telescopes use lenses. The reflecting telescope was invented in 1668 by Sir Isaac Newton, and it has since become one of the most popular types of telescopes.
Reflecting telescopes use a mirror to gather and focus light, while refracting telescopes use a lens to do the same thing. Reflecting telescopes can be made much larger than refracting telescopes because it is easier to make large mirrors than it is to make large lenses. The mirror in a reflecting telescope is placed at the back of the telescope, and it gathers and reflects light back to a secondary mirror, which then reflects the light to the eyepiece. The eyepiece is where the observer looks through the telescope.In contrast, the lens in a refracting telescope is placed at the front of the telescope, and it gathers and bends light as it passes through. The lens focuses the light onto an eyepiece at the back of the telescope. Refracting telescopes are generally smaller than reflecting telescopes because of the difficulty of making large lenses.
Another difference between reflecting and refracting telescopes is the way they are constructed. Reflecting telescopes have a simple tube that houses the mirrors and eyepiece, while refracting telescopes have a more complex design with a long tube that contains the lens and eyepiece.

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Answer:

The amount of energy that would be burnt in climbing stairs all day is approximately 52,738,560 Joules

Explanation:

The question is with regards to an experiment with details that can be obtained from the U Oregon website

The given parameters of the question are;

The energy consumed by a human each day =  2,500 kcal = 10,450,000 J

The required parameters obtained from U Oregon website are;

The average weight of a student, W ≈ 60 kg × 9.81 m/s² = 588.6 N

The average time it takes a student to run up a flight of stairs = 5.4 s

The height of the stairs, h = 0.2 m × 28 = 5.6 meters

Therefore, we get;

Work done in climbing up the stares = W × h = 588.6 N × 5.6 meters = 3,296.16 J

The height the student can climb in a day is given as follows;

The time of 1 day in seconds, t = 86,400 s

The height the student climbs in 5.4 s = 5.6 m

∴ Vertical velocity, \(v_y\) = 5.6 m/(5.4 s) = (28/27) m/s

The vertical height the student climbs in a day, \(h_{(v \, all \, day)}\) = \(v_y\) × t

∴ \(h_{(v \, all \, day)}\) = (28/27) m/s × 86,400 = 89,600 m

The work done all day = W × \(h_{(v \, all \, day)}\) = 588.6 N × 89,600 m = 52,738,560 J

The amount of energy in joules that would be burnt in climbing stairs all day = The work done all day = 52,738,560 Joules

The number of moles of PbSO₄(s) precipitated from the resulting solution would be 0.0141 moles.

A precipitation reaction will take place in which the Na₂SO₄(aq) and Pb(NO₃)₂(aq) will react and form PbSO₄(s) solid and NaNO₃(aq).

This is the balanced chemical reaction that takes place:Na₂SO₄(aq) + Pb(NO₃)₂(aq) → PbSO₄(s) + 2NaNO₃(aq)

We first need to determine the number of moles of Na₂SO₄(aq) that is available:0.0200 L × 0.00187 mol/L = 3.74 × 10⁻⁵ mol Na₂SO₄(aq)

Since the reaction has a 1:1 molar ratio between Na₂SO₄(aq) and PbSO₄(s), the number of moles of PbSO₄(s) that will form will be the same.

Therefore, 3.74 × 10⁻⁵ mol PbSO₄(s) will form.In order to calculate the mass of PbSO₄(s) that will precipitate out, we can use the formula:m = n × MM

where m = mass in grams, n = number of moles, and MM = molar mass of PbSO₄The molar mass of PbSO₄ is:1 Pb + 1 S + 4 O = 207.2 g/molSo, mass of PbSO₄(s) = 0.00775 g

We can use the solubility product constant (Ksp) to determine if all of the PbSO₄(s) will precipitate out.Ksp = [Pb²⁺][SO₄²⁻] = 2.5 × 10⁻⁸[Pb²⁺] = [SO₄²⁻] = xMoles of Pb²⁺ and SO₄²⁻ = 0.0141 mol

The molarity of PbSO₄(s) is thus:0.0141 mol ÷ 0.051 L = 0.276 M

This is greater than the Ksp of 2.5 × 10⁻⁸, so not all of the PbSO₄(s) will precipitate out.

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Answer:

Zinc Carbonate

Zinc Nitrate

Explanation:

Answer:

B

Explanation:

They use energy from sunlight to synthesise glucose from carbon dioxide and water.  

Kb1 = 1.61 × 10^-10 and Kb2 = 4.35 × 10^-9. The basicity constant, or Kb, is a measure of the strength of a base in a particular chemical reaction. The products of a reaction of a weak base and water with the corresponding acid determine the base constant.

For example, for a given acid and base, Kb1 and Kb2 are the basicity constants for the first and second base dissociations, respectively, of the base. The formulas and charges of the conjugate acid and base, as well as the acid dissociation constants, Ka1 and Ka2, are needed to calculate Kb1 and Kb2.

The following reactions are balanced chemical reactions that represent the dissociation of succinic acid:

Reaction 1: H2C4H4O4(aq) + H2O(l) ⇌ HC4H4O4(aq) + H3O+(aq) Ka1 = 6.2 × 10−5
Reaction 2: HC4H4O4(aq) + H2O(l) ⇌ C4H4O42-(aq) + H3O+(aq) Ka2 = 2.3 × 10−6

The values of Ka1 and Ka2 can be used to calculate Kb1 and Kb2, respectively, using the following equation:

Ka1 × Kb1 = Kw

where Kw is the ion-product constant for water, which is 1.0 × 10−14 at 25°C.

Kb1 can be calculated as follows:

Kw = Ka1 × Kb1

Kb1 = Kw / Ka1

Kw = 1.0 × 10^-14

Ka1 = 6.2 × 10^-5

Kb1 = Kw / Ka1

Kb1 = 1.0 × 10^-14 / 6.2 × 10^-5

Kb1 = 1.61 × 10^-10

Kb2 can be calculated using the same method:

Kw = Ka2 × Kb2

Kb2 = Kw / Ka2

Kw = 1.0 × 10^-14

Ka2 = 2.3 × 10^-6

Kb2 = Kw / Ka2

Kb2 = 1.0 × 10^-14 / 2.3 × 10^-6

Kb2 = 4.35 × 10^-9

Therefore, Kb1 = 1.61 × 10^-10 and Kb2 = 4.35 × 10^-9.

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The Ksp for hydroxide is D. 5.25 x 10⁻⁷.

The solubility product constant (Ksp) is a measure of the equilibrium solubility of a compound in water. It represents the product of the concentration of the ions raised to the power of their respective stoichiometric coefficients in the balanced chemical equation.

The balanced chemical equation for the dissociation of Mn(OH)₂ is:

Mn(OH)₂(s) ⇌ Mn⁺²(aq) + 2OH⁻(aq)

From the given solubility of Mn(OH)₂ in pure water (7.18 x 10⁻¹⁰ g/L), we can convert it to molar solubility:

7.18 x 10⁻¹⁰ g/L / molar mass of Mn(OH)₂ = x mol/L

Now, we can use the stoichiometry of the equation to determine the concentrations of Mn⁺² and OH⁻ ions in the equilibrium state. Since the ratio of Mn(OH)₂ to Mn⁺² is 1:1, the concentration of Mn⁺² is also x mol/L.

The concentration of OH⁻ ions is twice the concentration of Mn⁺², so it is 2x mol/L.

Substituting these values into the expression for Ksp:

Ksp = [Mn²⁺)] * [OH⁻]²

= (x) * (2x)²

= 4x³

Given that the solubility of Mn(OH)2 is 7.18 x 10^(-10) mol/L, we substitute this value into the expression for Ksp:

Ksp = 4(7.18 x 10⁻¹⁰)³

= 5.25 x 10⁻²⁷

Therefore, the correct answer is D. 5.25 x 10⁻⁷.

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204 amu is the relative atomic mass of thallium

Isotopes of Thallium and % abundances

Tl-203 : 29.5%

Tl-205: 70.5%

Formula:

Relative atomic mass = Σ(Isotope-mass x abundance)/100

It is given by the summation of the product of all the isotope masses and their % abundances

For Thallium:

Relative atomic mass = (203 x 29.5 +205 x 70.5)/100 = 204

Since the number of significant digits is 3, the relative atomic mass = 204 amu

A dimensionless physical quantity known as relative atomic mass (symbol: Ar) or atomic weight is defined as the ratio of the average mass of atoms of a chemical element in a particular sample to the atomic mass constant. The mass of an atom of carbon-12 is one-twelfth of the atomic mass constant, or mu (symbol).

Since the ratio's two components are masses, the final number has no dimensions, which is why it is referred to as relative.

The weighted arithmetic mean of the masses of the individual atoms (including their isotopes) that are present in the sample is the relative atomic mass of a certain element for a specific sample. This amount can vary greatly between samples since the origin of the sample (and therefore its radioactive or diffusion history) may have caused different isotopic abundance combinations.

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In the context of atomic orbital (AO) wavefunctions, the terms "radial node" and "nodal plane" refer to different aspects of the wavefunction's behavior.

A radial node is a region in the AO wavefunction where the probability of finding an electron is zero along the radial direction. In other words, it represents a spherical shell where the electron is unlikely to be found. The number of radial nodes is determined by the principal quantum number (n) of the orbital. For example, the 2s orbital has one radial node, while the 2p orbital has no radial nodes.

On the other hand, a nodal plane is a flat plane within the AO wavefunction where the probability of finding an electron is zero along a particular direction. It represents a surface that divides the orbital into two regions of opposite phases. The number of nodal planes is determined by the angular quantum numbers (l and m) of the orbital. For example, the 2s orbital has no nodal planes, while the 2p orbital has one nodal plane (the xz or yz plane).

Radial nodes arise from the radial part of the wavefunction because they depend on the distance from the nucleus. The radial part determines the distribution of the electron density as a function of distance, and the nodes correspond to regions where the density drops to zero.

On the other hand, nodal planes arise from the angular part of the wavefunction because they depend on the orientation and shape of the orbital. The angular part describes the angular distribution of the electron density around the nucleus, and the nodal planes correspond to regions where the phase of the wavefunction changes sign.

In summary, radial nodes are related to the distance from the nucleus and arise from the radial part of the wavefunction, while nodal planes are related to the orientation and shape of the orbital and arise from the angular part of the wavefunction. The 2s orbital has one radial node and no nodal planes, while the 2p orbital has no radial nodes and one nodal plane.

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Answer:

See attached image.

Explanation:

The explanations are on the attachment.  The numerical results are below.

1.  63g/7cm^3 = 9 g/cm^3

2.  The m or mm must be converted so that the units are the same.  1 m = 1000 mm.  I'll convert the meters to mm:  0.080 m = 80 mm.

480 mm^2/80 mm = 6 mm

3.  L times L makes no physical sense, unless this is a new Star Wars technique for making dark matter.  Entertaining, but useless.

To find the mass percentage of arsenic in the pesticide, we can use the following formula:

mass percentage of arsenic = (mass of arsenic / total mass of pesticide) * 100%

where the mass of arsenic is the mass of arsenic in the solution that was used to reach the equivalence point, and the total mass of pesticide is the total mass of pesticide in the sample.

We are given the following information:

The titration solution contained 0.108 M Ag.

It took 25.0 mL of the titration solution to reach the equivalence point.

Using these values, we can calculate the mass of arsenic in the solution as follows:

mass of arsenic = volume of solution * molar mass of Ag

mass of arsenic = 25.0 mL * 107.87 g/mol = 275.75 g

We can then use the formula above to find the mass percentage of arsenic in the pesticide:

mass percentage of arsenic = (mass of arsenic / total mass of pesticide) * 100%

mass percentage of arsenic = (275.75 g / total mass of pesticide) * 100%

where the total mass of pesticide is not given in the problem.

We will need to use another piece of information from the problem to find the total mass of pesticide:

The pesticide was diluted to 0.10 M.

Using this information, we can calculate the total mass of pesticide as follows:

total mass of pesticide = volume of pesticide * molar mass of pesticide

total mass of pesticide = 100 mL * 5.25 g/mL * 1.0 g/mol = 525 g

Substituting the values into the formula above, we get:

mass percentage of arsenic = (275.75 g / 525 g) * 100% = 53.48%

Therefore, the mass percentage of arsenic in the pesticide is approximately 53.48%.

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Answer:

Calcium

Explanation:

I just checked the periodic table! This is right checked twice, I hope this helped first time answering a question. Good luck!

Answer:

3. Mitochondria

Explanation:

Numerous mitochondria are found in each muscle cell to provide metabolic energy for muscle contraction.

hope i helped (:

Answer

7.53% 97% if you divide it you can get the answer

Explanation:

Answer:

C. A statement that explains an event or observation because it has been tested many times by

many different scientists.

The nucleus more easily, increasing the probability of causing fission many nuclei like U234, U236, and U238 undergo fission only by fast neutrons.

Fission can be caused by slow as well as fast neutrons. It is the energy of the neutron which determines its effectiveness in causing fission. Fast neutrons are more effective in causing fission. Hence, many nuclei like U234, U236, and U238 undergo fission only by fast neutrons.

Fission is a nuclear reaction process in which the nucleus of an atom is split into two smaller nuclei with the release of a large amount of energy and two or three neutrons. Uranium-235 (U-235) and Plutonium-239 (Pu-239) are the most commonly used fissile materials, but other materials like U-234, U-236, and U-238 can also undergo fission. When a neutron is absorbed by the nucleus of a fissile material like U-235 or Pu-239, it becomes unstable and splits into two smaller nuclei with the release of a large amount of energy.

The fission process also releases two or three neutrons, which can cause further fission of other nuclei, leading to a chain reaction. The chain reaction can be controlled by using a neutron moderator, which slows down the fast neutrons, making them more effective in causing fission. The efficiency of the fission reaction depends on the energy of the neutron.

Fast neutrons are more effective in causing fission than slow neutrons, which have less energy. This is because fast neutrons can penetrate the nucleus more easily, increasing the probability of causing fission. Hence, many nuclei like U234, U236, and U238 undergo fission only by fast neutrons.

Fast neutrons are more effective in causing fission than slow neutrons, which have less energy.

This is because fast neutrons can penetrate the nucleus more easily, increasing the probability of causing fission. Hence, many nuclei like U234, U236, and U238 undergo fission only by fast neutrons.

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Answer:

72.72%

Explanation:

Answer:

Argon

Explanation:

I'm pretty sure it's argon.

The rank of the following from best to worst nucleophile in an aprotic solvent is as follows: I- > Br- > Cl- > F-

In aprotic solvents, nucleophilicity increases as the size of the halogen increases. This is because the larger halogens have more electrons and a greater ability to donate those electrons to form a new bond. Additionally, fluoride (F-) is a poor nucleophile because it is a small, highly electronegative ion that forms a strong bond with the solvent molecules, making it less available to participate in reactions.

In an aprotic solvent, the nucleophilicity follows the trend based on the size and polarizability of the anions. Here's the ranking of the given nucleophiles from best to worst:

1. I-
2. Br-
3. Cl-
4. F-

Iodide (I-) is the best nucleophile in this case because it is the largest and most polarizable anion, while fluoride (F-) is the worst nucleophile due to its small size and lower polarizability.

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Therer are 0.494 moles of H₂ are formed by the complete reaction of 0.329 mol of Al.

To find the number of moles of H₂ formed by the complete reaction of 0.329 mol of Al, \it is required to balanced chemical equation for the reaction between Al and H₂.

The reaction is as observe:

2Al + 6HCl → 2AlCl3 + 3H2

According to balanced equation, it is observed that 2 moles of Al react to make 3 moles of H₂.

Thus, set up a ratio:

2 mol Al : 3 mol H₂

Next, use this ratio to find the number of moles of H₂ formed.

According to question 0.329 mol of Al, set the proportion:

2 mol Al / 3 mol H₂ = 0.329 mol Al / x

By cross-multiplication:

2 mol Al × x = 3 mol H₂  × 0.329 mol Al

2x = 0.987

Dividing both sides by 2:

x = 0.987 ÷ 2

x = 0.494

Thus, 0.494 moles of H₂ are formed by the complete reaction of 0.329 mol of Al.

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Answer:

Large Cargo Ship

Explanation:

Hope it helped!

The term "pyo-" (py/o/rrhea; pyo/genic) means "pus" or "related to pus."

The prefix "pyo-" is derived from the Greek word "pyon," which means pus. When used as a prefix in medical terminology, "pyo-" indicates a condition or process related to pus or the presence of pus.

For example, "pyorrhea" refers to a condition characterized by the discharge of pus from a wound or an infection of the gums. In this case, the term combines "pyo-" (meaning pus) and "-rrhea" (meaning discharge or flow).

Similarly, "pyogenic" refers to something that causes or is related to the production of pus. It is often used to describe bacteria or microorganisms that can lead to the formation of pus in infected tissues.

In summary, the prefix "pyo-" in medical terminology denotes pus or the involvement of pus in a specific condition, indicating a discharge, infection, or pus-forming process.

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Answer:

D. Healthy fish populations

Explanation:

took the quiz and got it right

Answer:

D. Healthy fish populations

Explanation: