During taylor's first test of a car with a mass of 250 grams, she recorded 10 seconds, 10.3 seconds, and 10.4 seconds for her 3 trials. what would be the mean value she would use to compare with the other cars?

Answers

Answer 1

The mean value Taylor would use is 10.23 seconds.

What is the mean value of Taylor's recorded times for her car's trials?

To calculate the mean value for Taylor's recorded times, we add up the individual times (10 seconds, 10.3 seconds, and 10.4 seconds) to obtain a total of 30.7 seconds.

we divide this total by the number of trials, which in this case is 3.

30.7 seconds divided by 3 equals approximately 10.23 seconds.

The mean value of Taylor's recorded times for her car's trials is approximately 10.23 seconds.

The mean value is often used as a measure of central tendency to represent the average of a set of values.

In this case, it represents the average time recorded by Taylor during her trials.

By calculating the mean, we can compare this value with the mean times of other cars to assess performance.

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Related Questions

Find the quotient.

4.58 ÷ 0.5

Answers

Answer:

9.16

Step-by-step explanation:

4.58/.5

Answer:

9.16

Step-by-step explanation:

4.58

--------

0.5

45.8

--------

5

5 into 45 is 9

9 x 5 = 45

45-45= 0

5 into 8 is 1

1 x 5 = 8

8 - 5 = 3

Bring down the zero: 30

5 into 30 is 6

5 x 6 = 30

30 - 30 = 0

the solution for long division of 4.58

                                                    -------- = 9.16

                                                       5

Hope this helps

Can you solve this graph problem?
a) what is the difference in temperatures between 7 am to 5 pm
b) which part of the day was the temperature rising the fastest a, b, c, d, or e?

Can you solve this graph problem?a) what is the difference in temperatures between 7 am to 5 pmb) which

Answers

Answers:

a) The difference in temperature is 25 degrees Fahrenheit. b) The temperature was rising fastest during interval 'a'

=========================================================

Explanations:

a) We subtract the y coordinates of the left and right endpoints. We get 65-40 = 25b) The fastest rising temperature will visually correspond to the steepest part of the curve. That would be region 'a'. After this interval, region b is still increasing, but not as much as the previous interval (since it's not as steep here). Then it gets less steep for region c, and d sort of flattens out as well. So during the morning hours it appears the temperature is going up the fastest.

WILL REWARD BRAINLIEST PLS HELP ASAP Find the total surface area.

WILL REWARD BRAINLIEST PLS HELP ASAP Find the total surface area.

Answers

The surface area of the rectangular prism is 88 square inches.

Given that:

Length, L = 6 inches

Width, W = 2 inches

Height, H = 4 inches

Let the prism with a length of L, a width of W, and a height of H. Then the surface area of the prism is given as

SA = 2(LW + WH + HL)

SA = 2(6 x 2 + 2 x 4 + 4 x 6)

SA = 2 (12 + 8 + 24)

SA = 2 x 44

SA = 88 square inches

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sat math scores follow a normal distribution with a mean of 511 and a standard deviation of 110. suppose we choose a student at random. what is the probability that the student scores between 450 and 600?

Answers

The probability that a student scores between 450 and 600 on the SAT math section is approximately 0.4147 or 41.47%.

To find the probability that a student scores between 450 and 600 on the SAT math section, we need to use the properties of the normal distribution. We know that the mean is 511 and the standard deviation is 110.

First, we need to standardize the values of 450 and 600 using the formula:

z = (x - μ) / σ

where x is the value we want to standardize, μ is the mean, and σ is the standard deviation.

For 450:

z = (450 - 511) / 110 = -0.55

For 600:

z = (600 - 511) / 110 = 0.81

Next, we need to find the area under the normal curve between these two standardized values. We can use a table or a calculator to find that the area between z = -0.55 and z = 0.81 is approximately 0.4147.

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What is the value of a

What is the value of a

Answers

Answer: Multiplying 3x and -x we obtain A= -3x^2

Can someone please help me out with this question?

Can someone please help me out with this question?

Answers

Answer:

Dependent

Step-by-step explanation:

Since the marble is not returned, the result of the second probability is dependent upon which marble was 1st drawn.

Graph the line whose y-intercept 5 is and whose x-intercept is 1 .

Answers

Answer:

Graph a dot at the coordinates (0, 5) and (1, 0). Afterwards, connect the two dots!

Step-by-step explanation:

You just want a line that has a y-intercept of 5 and an x-intercept of 1. This is quite easy to make by just plotting the x-intercept at 1, thus (1, 0) and plotting the y-intercept at 5, thus (0, 5), and connecting the two dots and extending them to make a line.

traslate 2 units right and 5 untis up

Answers

Answer:

The slope would be positive 5/2

Step-by-step explanation:

When finding slope you do rise over run. Or rise/run.

This is rise |

This is run __

So going up or down is a rise.

And going left or right is a run.

Did this help??

t=r/r-3
make r the subject of the formula

Answers

Step-by-step explanation:

\(T=r/r-3\\T+3=r/r\\(T+3)*r=r\\r=(T+3)*r\)

A seamstress needs to cut 15 pieces of ribbon
A7
B35
C135
D8100

Answers

B kdkdjendncjcjdcjndmrmfmfciv

Given the conditional statement: "If it is Wednesday, then Kayden doesn't
have baseball practice." What is the hypothesis of this statement? *

Answers

Answer:

if it's wednesday

Step-by-step explanation:

A bag contains 20 coloured marbles. Copy and
complete the table below to show the probability of
picking each colour at random and the number of
each colour marble in the bag. What is the
probability, as a percentage (%), of picking a purple
marble at random? How many purple marbles are in
the bag?
Colour
Yellow
Blue
Green
Purple
Probability
10%
15%
Number of marbles
6

A bag contains 20 coloured marbles. Copy andcomplete the table below to show the probability ofpicking

Answers

Yellow No. of balls = 2
Blue Probability = 30 %
Green No. of balls = 3
Purple Probability = 45 %
Purple No. of balls = 9

Two interacting populations of hares and foxes can be modeled by the recursive equations:h(t+1)=4h(t)-2f(t)f(h+1)=h(t)+f(t)For each of the initial populations given in parts (a) through (c), find closed formulas for h(t) and f(t).a. h(0)=f(0)=100b. h(0)=200, f(0)=100c. h(0)=600, f(0)=500

Answers

The closed formula of h(t) and f(t) for

h(0)=f(0)=100b => h(t) = 100(2t+1), f(t) = 100(2t-1) ,

h(0)=200, f(0)=100 => h(t) = 200(2t+1), f(t) = 100(2t-1)

h(0)=600, f(0)=500 =>h(t) = 300 + 200(2t+\((-1)^{t}\)), f(t) = 200 - 100\((-1)^{t}\)

The recursive equations for the given two interacting population of hares and foxes are

h(t+1)=4h(t)-2f(t)

f(h+1)=h(t)+f(t)

for the given initial population in parts from a to c we need to create a close formula for h(t) and f(t)

where h(0) = f(0) =100

h(t) = 100(2t+1)

f(t) = 100(2t-1)

where h(0) = 200, f(0) =100

h(t) = 200(2t+1)

f(t) = 100(2t-1)

where  h(0) = 600, f(0) = 500

h(t) = 300 + 200(2t+\((-1)^{t}\))

f(t) = 200 - 100\((-1)^{t}\)

The closed formula of h(t) and f(t) for

h(0)=f(0)=100b => h(t) = 100(2t+1), f(t) = 100(2t-1) ,

h(0)=200, f(0)=100 => h(t) = 200(2t+1), f(t) = 100(2t-1)

h(0)=600, f(0)=500 =>h(t) = 300 + 200(2t+\((-1)^{t}\)), f(t) = 200 - 100\((-1)^{t}\)

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2(x + 4) - 6 = 5x - 17

Answers

Answer:

x=6.3  :)

Step-by-step explanation:

2(x+4)-6=5x-17

2x+8-6=5x-17

2=3x-17

19=3x

19/3=6.3

Answer:

2(x+4) -6 = 5x-17

2x + 8 - 6 = 5x - 17

8 -6 + 17 = 5x - 2x

2 + 17 = 3x

19 = 3x

divide both side by the coefficient of x which is 3

19/3 = 3x/3

x = 19/3

x = 6 1/3. or 6.33

Create an expanded for this simplifies expression:
10x+4y-12

Answers

Answer:

10×x + 4×y -(10+2)

Step-by-step explanation:

we will simplify it

Please help! If possible please show your work :D Thank you!

Solve.

Please help! If possible please show your work :D Thank you!Solve.

Answers

Equation at the end of step1: (7x + 18) (4) - 4x = 0 2 STEP2:Equation at the end of step 2 2 • (7x + 18) - 4x = 0 STEP3:STEP4:Pulling out like terms

 4.1     Pull out like factors :

   10x + 36  =   2 • (5x + 18) 

Equation at the end of step4: 2 • (5x + 18) = 0 STEP5:Equations which are never true:

 5.1      Solve :    2   =  0

This equation has no solution.

A a non-zero constant never equals zero.

Solving a Single Variable Equation:

 5.2      Solve  :    5x+18 = 0 

 Subtract  18  from both sides of the equation : 

                      5x = -18

Divide both sides of the equation by 5:

                     x = -18/5 = -3.600

An object is moving ata speed of 63 centimeters every 2 days. Express this speed in meters per hour. Round your answer to the nearest hundredth. "Note: you must use these exact conversion factors to get this question right. Distance / length 1 foot (ft) = 12 inches (in) 1 yard (yd) = 3 feet (ft) 1 mile (mi) = 528o feet (ft) 1 meter (m) = 100 centimeters (cm) 1inch (in) = 2.54 centimeters (cm) 1 foot (ft) = 0.305 meters (mn) Time 1 mile (mi) = 1.609 kilometers (km) 1 minute (min) = 60 seconds (sec) 1 hour (hr) = 60 minutes (min) 1 kilometer (km) = 1000 meters (m) 1 month (month) = 30 days (days) 1 day (day) = 24 hours (hr) 1 week (week) = 7 days (days) 1 year (year) = 365 days (days)​

Answers

Step-by-step explanation:

the given speed is

63 cm / 2 days

1 m = 100 cm

therefore, m = cm/100.

so,

63 cm = 0.63 m

1 day = 24 h

therefore,

2 days = 24×2 = 48 h

so, we have a speed of

0.63 m / 48 h

we need to get the speed of meters in 1 hour.

so, we need to do a normal fraction operation.

e.g. when we have 43/10, but we want to have 1 in the denominator (bottom part).

what do we do ? well, we divide top and bottom (to keep the total value of the fraction unchanged) by 10 and get

4.3/1 = 4.3

we do the same with

0.63 m / 48 h

as we want to have only 1 hour in the denominator.

we divide top and bottom by 48 :

0.63/48 / 1 h = 0.013125 m/h ≈ 0.01 m/h

determine the miss term 3:5:7:?:25:

Answers

7x5=(35) is the missing term

2. Mr. Hoffman has a circular chicken coup with a radius of 2.5 feet. He wants to put a chain link fence around the coup to protect the chickens. Which measurement is closest to the length of fence he will need?
A: 19.63ft
B: 31.42ft
C: 15.7ft
D:7.85ft

Answers

Answer:

C

Step-by-step explanation:

using the formula for circumference of a circle.

2πr is the formula.

closest answer is 15.7 ft

Which of the following shows the equation of a line with slope - 2 passing through (3,-2)?
(1) y = 2x +7
(3) y=-2x-1
(2) y = 2x - 8
(4) y=-2x+4

Answers

Do you need me to answer them or give u the anwser?

Inide a park of length 400m and breath 300m there i an area of walking track 4 m wide built all around. What i the area left for children for playing

Answers

The area left for children for playing 114464 sq. m

As per the given data inside a park:

The length of the park is 400 m

The breadth of the park is 300 m

The formula for the area of the park = Length × Breadth

= (400 × 300) sq. m

= 120000 sq. m

The width of the walking track inside the park is 4 m

The length of the park without the walking track

= 400 − (4 + 4) m

= 400 − 8 m

= 392 m

The breadth of the park without the walking track

= 300 − (4 + 2) m

= 300 − 8 m

=292 m

Area of the park without the walking track:

= 392 × 292

= 114464 sq. m

Therefore the area left for children for playing other than the walking track is 114464 sq. m.

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If side a = 3 and b = 4 what is the length of leg c in a right triangle using the
pythagorean theorem?

Answers

Answer: 5

Step-by-step explanation: Leg A + Leg B= Leg C

9+16=25 the square of 25 is 5

Answer:

5 = c

Step-by-step explanation:

pythagorean theorem is simply a^2 + b^2 = c^2

so a=3 and b=4 so we plug them in

3^2 + 4^2 = c^2

which is

9 + 16 = c^2

so

25 = c^2

then we take the square root for the answer!!

sqrt(25) = sqrt(c^2)

5 = c

Let x be a binomial random variable with p = 0.1 and n = 10. calculate the following probabilities

Answers

The probabilities from the binomial probability mass function P(x ≤ 2) will be 0.9298.

What is binomial distribution?

Frequency distribution of the percentage of successful outcomes that might occur in a certain number of trials with the same chance of success. If X~B(n, p), then the probability is given as

\(\rm P(X=x) = \ ^nC_x \times p^x \times (1-p)^{n - x}\)

q = 1 - p = 1 - 0.10 = 0.90

Let x be a binomial random variable with p = 0.1 and n = 10.

The probabilities from the binomial probability mass function P(x ≤ 2) will be

P(x ≤ 2) = P(x = 0) + P(x = 1) + P(x = 2)

P(x ≤ 2) = ¹⁰C₀ × (0.1)⁰ × (0.9)¹⁰ + ¹⁰C₁ × (0.1) × (0.9)⁹ + ¹⁰C₂ × (0.1)² × (0.9)⁸

P(x ≤ 2) = 0.3487 + 0.3874 + 0.1937

P(x ≤ 2) = 0.9298

Your question was incomplete but the complete question is given below.

Let x be a binomial random variable with p = 0.1 and n = 10. Calculate the probability from the binomial probability mass function less than or equal to 2.

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solve each of the equations
2b+8-5b+3=-13+8b-5

Answers

Answer:

b= 29/11

Step-by-step explanation:

solve each of the equations 2b+8-5b+3=-13+8b-5

2b+8-5b+3=-13+8b-5

8-5b+3=-13+8b-5-2b

8-5b+3=-13+6b-5

8+3=-13+6b-5+5b

8+3=-13+11b-5

8+3=-18+11b

11=-18+11b

29=11b

b=2.63

help me please I will mark as brainlist ​

help me please I will mark as brainlist

Answers

Answer:

\( \frac{ \alpha + \beta + \gamma }{ - d} \)

Step-by-step explanation:

If we simplify that fraction, we get

\( \frac{ \alpha + \beta + \gamma }{ \alpha \beta \gamma } \)

Keep that in mind.

If y, a ,b are zeroes of the cubic polynomial, then that means

\((x - \alpha )(x - \beta )(x - \gamma )\)

make up the polynomial.

Notice that leading xoeffeicent will be 1, so the roots will multiply to

\( - d\)

so

\( \alpha \beta \gamma = - d\)

which gives us

\( \frac{ \alpha + \beta + \gamma }{ - d} \)

Proof:

Consider the function

\((x - 2)(x - 3)(x - 5)\)

The roots are 2, 3, 5.

D is -30 so we get

Using the value,

\( \frac{2 + 3 + 5}{ 30} = \frac{1}{3} \)

If we use the orginal equation, we get

\( \frac{1}{6} + \frac{1}{10} + \frac{1}{15} = \frac{10}{30} = \frac{1}{3} \)

Answer:

Hey,mate

Notice that leading xoeffeicent will be 1, so the roots will multiply to

The roots are 2, 3, 5.

\(\sqrt{2} \sqrt{3} \sqrt{5}\)

D is -30

You are driving on the freway and notice your speedometer says to. The car in front of you appears to be coming towards you at speed
4
1

to. and the car behind you appears to be gaining on you at the same speed
4
1

to. What speed would someone standing on the ground say each car is moving? (b) Suppose a certain type of fish always swim the same speed. You watch the fish swim a certain part of a river with length L. You notice that it takes a time
6
1

t
0

for the fish to swim downstream but only
3
1

t
0

to swim upstream. How fast is current of the river moving? (c) You now want to swim straight across the same river. If you swim (in still water) with a speed of
10
3L

, what direction should you swim in? (d) How long does it take to get across if the river has a width of
3
1

L. Problem 7 Relative (a) You are driving on the freeway and notice your speedometer says t
0

. The car in front of you appears to be coming towards you at speed
4
1

t
0

, and the car behind you appears to be gaining on you at the same speed
4
1

t
0

. What speed would someone standing on the ground say each car is moving? (b) Suppose a certain type of fish always swim the same speed. You watch the fish swim a certain part of a river with length L. You notice that it takes a time
6
1

t
0

for the fish to swim downstream but only
3
1

t
0

to swim upstream. How fast is current of the river moving? (c) You now want to swim straight across the same river. If you swim (in still water) with a speed of
f
a


3L

, what direction should you swim in? (d) How long does it take to get across if the river has a width of
3
1

L.

Answers

a) The speed of the car in front of you appears to be coming towards you is 41t₀. The speed of the car behind you appears to be gaining on you at the same speed is 41t₀. Someone standing on the ground would say that the two cars are moving at t₀ + 41t₀ = 82t₀.

b) We know that the speed of the fish in still water is V, and the speed of the current is C. And the time the fish takes to swim downstream is 61t₀ and upstream is 31t₀. So:

Downstream: V + C = L / (61t₀)

Upstream: V - C = L / (31t₀)

Adding the two equations we get:

2V = (4L / 61t₀) → V = (2L / 61t₀)

Therefore, C = (L / 61t₀) which is the speed of the current.

c)In order to get across the river, you have to swim at a speed perpendicular to the current (so that you don't get drifted away) and with a speed of fa * 3L, as given. Therefore, the required angle can be found by:

f a3L = (V cos α)sin α

= (C cos α)sin αtan α

= (fa * 3L) / C

= 3fa * 61t₀ / Ld)

The width of the river is 31L. The time taken to get across can be found using the formula:

Time = (Distance) / (Speed)

Since the speed of the current is C, the effective speed (in still water) is fa * 3L, the distance to be crossed is 31L, and the time taken is:

Time = (31L) / (fa * 3L - C)  

= (31L) / (3fa * 61t₀ / L)

= (31L²) / (3fa * 61t₀)

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Liang's solution of a system of linear equations is shown. Explain her error. 3x − 2y = 12 −x − 2y = −20 2x + 0 = −8 x = −4 −(−4) − 2y = −20 4 − 2y = −20 − 2y = −24 y = 12 Enter the solution as an ordered pair. (−4, 12) Complete the explanation for Liang's error and give the correct solution. Liang (select) the two equations, but (select) the y−terms. The equations should be (select) . The solution is .

Answers

Step-by-step explanation:

bro what kind of class got u doing these math equations

Combine like terms:

3x + 8 + 2y + 6 + 2x



21xy

3x +4y + 14

19x + 2y

5x + 2y + 14

Answers

Answer:

5x+2y+14

Step-by-step explanation:

3x+2x+2y+8+6

5x+2y+14

When you have to solve absolute deviation how do you do it?

Answers

Take each number in the data set, subtract the mean, and take the absolute value. Then take the sum of the absolute values. Now compute the mean absolute deviation by dividing the sum above by the total number of values in the data set. Finally, round to the nearest tenth.

find the number of ways the digits 0,1,2 and 3 can be permuted to give rise to a number greater than 2000

Answers

You have to have the 2 or 3 as the first digit.

After that, the other 3 digits can be done in 3! = 6 ways.

So, the total is 2*3! = 12

The number of ways the digits 0,1,2 and 3 can be permuted to give rise to a number greater than 2000 is 9.

What is permutation?

A permutation is a word that describes the number of ways things can be ordered or arranged.​

Given are numbers, 0,1, 2, 3

We asked for numbers greater than 2000, so those numbers will start either from 2 or 3.

2 _ _ _ = 3! = 6

3 _ _ _ = 3!/2! = 3

Hence, total possible ways are 6+3 = 9

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What steps are needed to make this a working program?2. Create the Java coding. Create in your own style and words the code that is needed to generate this result. Make sure that you post your name and this assignment at the top of your comments. Make sure you leave comments when needed.3. Display the result. Provide screenshots or paste results of the working application.4. Summarize. The client of the casino is inquiring what is the program going to do. Let them know in just a few sentences.5. Will there be a need for maintenance or any updates in the future?6. Is there a need to train anyone to run this program? Answer in a few sentences. Estimate the area under the graph of f(x) = x2 + x + 1 over the interval [0, 4] using ten approximating rectangles and right endpoints. Rn Repeat the approximation using left endpoints. Ln Report answers accurate to places. Remember not to round too early in your calculations. 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He was charged with numerous strictly indictable offences including 'aggravated break, enter and steal' and 'aggravated detain for advantage'. You are the Crown Prosecutor briefed in the matter. You have a meeting with Mr and Mrs Smith. They want to know everything about the process. Please provide a written advice to Mr and Mrs Smith explaining the entire process from charging to committal to trial in the District Court and what, if any, appeal processes may be followed after trial. Please include an explanation of their rights as victims of crime. Which of these viruses only causes acute infections (i.e., doesn't cause persistent infections)? varicella zoster virus (chickenpox and shingles) influenza virus herpes simplex virus type 1 (cold sores) hepatitis B virus Gina, a mechanical engineer, is designing a roller coaster for a theme park. When shetested her prototype, the roller coaster car came off the track. To continue theengineering design process, Gina should A. keep working on this project by herself with the same prototype.B. make a completely new prototype with several structural changes.C. work with others to identify why her prototype failed and test new iterations.D.stop working on the roller coaster project and find a different problem to solve. The institution which coordinates actions of consumers and producers to establish prices for goods and services is known as: The hyperlink function syntax has two arguments. Which argument has the path and file name to the document to be opened?. Sugar became so lucrative in the Caribbean Islands during the Columbian Exchange that plantation owners would take up fields and .... A. import foods B. create their own businesses C. start their own trading systems discuss and clarify any problematic terms and how the biblical idea of prophecy differs from our modern understanding x - = 22x = 6 Which equation represents the line that is parallel to y= 3 and passes through (-2,-8)?A.x = -2B.x= 3C.y=-8D. y= 3x - 2 What do the FBI & NSA have in common? HURRY PLEASEQ.27This passage is taken from a book that chronicles a man's exploration of Alaska.(1)It was now near dark, and I made haste to make up my flimsy little tent. The ground was desperately rocky. I made out, however, to level down a strip large enough to lie on, and by means of slim alder stems bent over it and tied together soon had a home. While thus busily engaged I was startled by a thundering roar across the lake. Running to the top of the moraine, I discovered that the tremendous noise was only the outcry of a newborn berg about fifty or sixty feet in diameter, rocking and wallowing in the waves it had raised as if enjoying its freedom after its long grinding work as part of the glacier. After this fine last lesson I managed to make a small fire out of wet twigs, got a cup of tea, stripped off my dripping clothing, wrapped myself in a blanket and lay brooding on the gains of the day and plans for the morrow, glad, rich, and almost comfortable.(2)It was raining hard when I awoke, but I made up my mind to disregard the weather, put on my dripping clothing, glad to know it was fresh and clean; ate biscuits and a piece of dried salmon without attempting to make a tea fire; filled a bag with hardtack, slung it over my shoulder, and with my indispensable ice-axe plunged once more into the dripping jungle. I found my bridge holding bravely in place against the swollen torrent, crossed it and beat my way around pools and logs and through two hours of tangle back to the moraine on the north side of the outlet,a wet, weary battle but not without enjoyment. The smell of the washed ground and vegetation made every breath a pleasure, and I found Calypso borealis1, the first I had seen on this side of the continent, one of my darlings, worth any amount of hardship; and I saw one of my Douglas squirrels on the margin of the grassy pool. The drip of the rain on the various leaves was pleasant to hear. More especially marked were the flat low-toned bumps and splashes of large drops from the trees on the broad horizontal leaves of Echinopanax horridum2, like the drumming of thundershower drops on veratrum and palm leaves, while the mosses were indescribably beautiful, so fresh, so bright, so cheerily green, and all so low and calm and silent, however heavy and wild the wind and the rain blowing and pouring above them. Surely never a particle of dust has touched leaf or crown of all these blessed mosses; and how bright were the red rims of the cladonia cups beside them, and the fruit of the dwarf cornel! And the wet berries, Nature's precious jewelry, how beautiful they were!huckleberries with pale bloom and a crystal drop on each; red and yellow salmon-berries, with clusters of smaller drops; and the glittering, berry-like raindrops adorning the interlacing arches of bent grasses and sedges around the edges of the pools, every drop a mirror with all the landscape in it. A' that and a' that and twice as muckle's a' that in this glorious Alaska day3, recalling, however different, George Herbert's "Sweet day, so cool, so calm, so bright.4"(3)In the gardens and forests of this wonderful moraine one might spend a whole joyful life.1 A rare orchid found in northern, mountainous areas.2Also called Devil's Club, Echinopanax is a large-leafed shrub that grows in moist, dense forests mostly in the Pacific Northwest of the United States.3 Reference to Scottish poet, Robert Burns's poem that rejoices over the wide variety of positive traits in his wife.4 Reference to a George Herbert poem that celebrates the glory found in nature and mourns the fact that it all must die.It can be inferred from the last sentence of paragraph two and from footnotes three and four that the authorA. is ScottishB. has a science backgroundC. is detail-orientedD. is well-readE. is environmentally conscious Please provide details steps, thanks3. For each of the following, find an equation for the tangent line at the given value of 2. (a) y= Let2-9 at x = -3 If f(x) = 4x + 5, what is the value of f(-3)?1. -22.43. -74. 17Please help me