Answer: water freezes and expands in the crevice
Explanation:
Answer:
Water freezes and expands in the crevice
Explanation:
A rover vehicle weighs 37 N on Mars. How much would the rover weigh on Earth?
The weight of the rover vehicle on Earth, given that it weighs 37 N on Mars is 99.5 N
How do determine the weight of the vehicle on earth?We'll begin by obtaining the mass of the rover vehicle. This is shown below:
Weight (W) = 37 NAcceleration due to gravity on Mars (g) = 3.72 m/sMass of rover vehicle =?Weight (W) = mass (m) × Acceleration due to gravity (g)
W = mg
Divide both sides by g
m = W /g
m = 37 / 3.72
m = 9.95 Kg
Now, we shall determin the weight of the rover vehicle on Earth. Details below:
Mass (m) = 9.95 KgAcceleration due to gravity on Earth (g) = 10 m/s² Weight (W) = ?Weight (W) = mass (m) × Acceleration due to gravity (g)
Weight (W) = 9.95 × 10
Weight = 99.5 N
Thus, we can conclude that the weight on Erath is 99.5 N
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a 0.145 kg pitched baesball moving horizontally at 35 m/s strikes a bat and is popped straight up to a height of 55.6 m before turning around. If the contact time is 0.50 ms, calculate the average force on the ball during contact.
Answer:
The average force on the ball during the contact is 13,951.9 N.
Explanation:
Given;
mass of the ball, m = 0.145 kg
initial horizontal velocity, uₓ = 35 m/s
the contact time, t = 0.5 ms = 0.5 x 10⁻³ s.
vertical height reached by the ball, h = 55.6 m
The initial vertical velocity of the ball is calculated as;
v² = u² - 2gh
where;
v is the final vertical velocity at maximum height = 0
u is the initial vertical velocity
\(0 = u_y^2 - 2(9.8 \times 55.6)\\\\0 = u_y^2 - 1089.76\\\\u_y^2 = 1089.76\\\\u_y = \sqrt{1089.76} \\\\u_y = 33.01 \ m/s\)
The resultant velocity is calculated as;
\(u = \sqrt{u_x^2 + u_y^2} \\\\u = \sqrt{35^2 + 33.01^2} \\\\u = 48.11 \ m/s\)
The acceleration of the ball is calculated as;
\(a = \frac{u}{t} \\\\a = \frac{48.11}{0.5\times 10^{-3}} \\\\a = 96220 \ m/s^2\\\\\)
The average force on the ball during the contact is calculated as;
F = ma
F = (0.145)(96220)
F = 13,951.9 N
Therefore, the average force on the ball during the contact is 13,951.9 N.
Someone help me please !!!! Will mark Brianliest !!!!!!!!!!!!!!!!
Answer:
Decant it.
Explanation:
Pour the water/sugar solution off the sand. When the sand wants to start coming out as well, Stop and add fresh water to the beaker, stir to rinse the remaining solution into a less concentrated solution and decant again.
Repeat the dilution process until the mix is essentially sand and water, then drive the remaining water from the sand by drying.
A man throws a penny down 4 m/s off the top
of the empire state building. If it accelerates at 9.8 m/s^2 the whole way
down for 8.42 s, what is the height it fell from?
The velocity of penny is 4 m/s with an acceleration of 9.8 m/s² within 8.42 s. Then, the height from which it fell down is 381 m.
What is acceleration ?Acceleration of an object is the measure of its rate of change in velocity. It is a vector quantity having direction and magnitude. It is the ratio of change in velocity to the change in time.
Given velocity of the penny u = 4 m/s
acceleration = 9.8 m/s²
time = 8.42 s.
Then the height from which the penny is fell down is calculated as follows:
h = ut + 1/2 at²
h = 4 m/s × 8.42 s + 1/2 9.8 m/s² × 8.42 ×8.42 = 381 meters.
Therefore, the height from which the penny fell from is 381 m.
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Really need help! ;(
Could you please explain it? :)
GIVING 10 POINTS
Answer:b
Explanation: If you look at the line on the graph, you can see that it is going downward, meaning it has a negative slope, and choice b is the only one that has a negative slope
A person kicks a ball off of a 50m high cliff with a speed of 10 m/s. How long will it take the ball to hit the ground? * 7 points 2.3 sec 6.3 sec 4.5 sec 3.2 sec
Presumably, the ball is kicked parallel to the ground below the cliff, so its altitude y at time t is
\(y(t)=50\,\mathrm m-\dfrac12gt^2\)
where g = 9.80 m/s^2 is the acceleration due to gravity.
The ball hits the ground when y = 0:
\(0 = 50\,\mathrm m-\dfrac12gt^2\)
\(t^2=\dfrac{100\,\mathrm m}g\)
\(t=\dfrac{10}{9.80}\,\mathrm s\approx\boxed{3.2\,\mathrm s}\)
Two motorcycles are traveling due east with different velocities. However, 3.63 seconds later, they have the same velocity. During this 3.63-second interval, motorcycle A has an average acceleration of 4.55 m/s2 due east, while motorcycle B has an average acceleration of 18.9 m/s2 due east. (a) By how much did the speeds differ at the beginning of the 3.63-second interval, and (b) which motorcycle was moving faster
Answer:
52.095 m/s
Motorcycle a was moving faster
Explanation:
We start by using one of the equations of motion
V = u + at
If the first motorcycle starts with an initial speed of u(a) and accelerates at a value of a(a) = 4.55 m/s², then the final speed after a time of 3.63 seconds is V(a). We then represent it as
V(a) = u(a) + a(a).t
If the second motorcycle starts with an initial speed of u(b) and accelerates at a value of a(b) = 18.9 m/s², then the final speed after a time of 3.63 seconds is V(b). We then represent it as
V(b) = u(b) + a(b).t
Assuming that the final speeds v(a) = v(b), and then subtract the equation of the second motorcycle from that of the first, we have
0 = u(a) - u(b) + a(a).t - a(b).t
-u(a) + u(b) = a(a).t - a(b).t, on rearranging, we have
u(b) - u(a) = [a(a) - a(b)]t
Since we have the values for acceleration and the time, we substitute so that
u(b) - u(a) = (4.55 - 18.9)3.63
u(b) - u(a) = -14.35 * 3.63
u(b) - u(a) = -52.095, or we rearrange to get
u(a) - u(b) = 52.095 m/s
a spanner is dropped from a sixth floor window and take 2.2s to hit the ground. A)calculate the height from wich it was drop.b)its impact velocity
a) The spanner was dropped from a height of 24.2 meters. b)The impact velocity of the spanner is 21.6 meters per second.
What exactly are velocity and example?Simply put, velocity is the rate at which something travels in a specific direction.
We can use the equations of motion to solve this problem.
a) To calculate the height from which the spanner was dropped, we can use the equation:
\(h = (1/2)gt^2\)
where h is the height, g is the acceleration due to gravity, and t is the time taken to fall.
Substituting the given values, we get:
\(h = (1/2) \times 9.81 m/s^2 \times (2.2 s)^2 \\= 24.2 meters\)
Therefore, the spanner was dropped from a height of 24.2 meters.
b) To calculate the impact velocity of the spanner, we can use the equation:
v = gt
where v is the final velocity, g is the acceleration due to gravity, and t is the time taken to fall.
Substituting the given values, we get:
\(v = 9.81 m/s^2 \times 2.2 s \\= 21.6 m/s\)
Therefore, the impact velocity of the spanner is 21.6 meters per second.
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Is Geothermal Energy renewable? Why or why not? Use in your own words.
Answer:
Yes, geothermal energy is a renewable energy resource because the water can be heated by pumping it through the rocks.
A water jet that leaves a nozzle at 78 m/s at a flow rate of 120 kg/s is to be used to generate power by striking the buckets located on the perimeter of a wheel. Determine the power generation potential of this water jet. Assume that the water jet flows steadily at the specified speed and flow rate. (Round the final answer to two decimal places.) The power generation potential is kW.
Answer:
The value is \(E = 365040 J/s \)
Explanation:
From the question we are told that
The speed of the water jet is \(v = 78 \ m/s\)
The flow rate of the water jet is \(\r m = 120 \ kg /s\)
Generally the mechanically energy possessed by a water flow is mathematically represented as
\(E = \r m * e\)
Here here e is the specific mechanical energy generated which is mathematically represented as
\(e[KJ/kg] = FE + KE + PE\)
Here
FE - flow energy
KE - kinetic energy
PE - potential energy
Generally give that we are only considering the power generation due to the kinetic energy of the water we have that
\(E = \r m * KE \)
Here
\(KE = \frac{v^2}{2}\)
\(E = \r m * \frac{v^2}{2} \)
=> \(E = 120 * \frac{78^2}{2} \)
=> \(E = 365040 J/s \)
A baby carriage is sitting at the top of a hill that is 21 m high. The carriage with the baby weighs 20
kg. The carriage has
energy. Calculate it
Answer:
Energy in carriage (Potential energy) = 4,116 J
Explanation:
Given:
Mass of baby = 20 kg
Height = 21 m
Find:
Energy in carriage (Potential energy)
Computation:
The energy accumulated in an object as a result of its location relative to a neutral level is known as potential energy.
In carriage accumulated energy is potential energy.
Energy in carriage (Potential energy) = mgh
Energy in carriage (Potential energy) = (20)(9.8)(21)
Energy in carriage (Potential energy) = 4,116 J
A 0.032 g plastic bead hangs from a lightweight thread. Another bead is fixed in position beneath the point where the thread is tied. If both beads have charge q, the moveable bead swings out to the position shown in (Figure 1).
The magnitude of the charge of the given moveable beads is 9.33 nC.
What is the tension in the string?
The tension in the string is calculated as follows;
Tcos45 = mg
where;
T is the tensionm is the massF = Tsin45
\(\frac{kq^2}{r^2} = Tsin(45)\\\\\frac{kq^2}{r^2} = \frac{mg}{cos45} \times sin(45)\\\\\frac{kq^2}{r^2} = mg\\\\q = \sqrt{\frac{mgr^2}{k} }\)
Magnitude of the charge\(q = \sqrt{\frac{(0.032 \times 10^{-3})(9.8)(0.05)^2}{9\times 10^9} } \\\\q = 9.33\times 10^{-9} \ C\\\\q = 9.33 \ nC\)
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You can buy 50 rolls of toilet paper for $12.50. Write a ratio showing the unit rate of rolls per $1.
Answer:
\(\frac{4R}{1D}\Rightarrow\text{ 4 rolls per \$1}\)Explanation: We need to find the unit rate or rate of rolls per $1:
\(50\text{rolls }\Rightarrow\text{ 4=\$12.50}\)To find the number of rolls per one dollar we simply need to take the ratio of the two as follows:
\(\frac{50R}{12.50D}\Rightarrow(1)\)Simplifying (1) gives the answer as follows:
\(\begin{gathered} \frac{50R}{12.50D}=\frac{4R}{1D} \\ \end{gathered}\)The answer therefore is:
\(\text{4 rolls per \$1}\)Please help to Calculate the lower and upper bound for 3.2 + 4.6
Answer:
i think it is 7.10Explanation:
I dont have an explenation
the same task can be processed in a 5-segment pipeline with a clock cycle of 60ns. determine the speedup ratio of the pipeline for 100 tasks.
The maximum speedup that could be achieved is approximately 4.81.
From the question, we have:
Speed up ratio is calculated as the difference between the time required by pipelined and non-pipelined processors.
The speed-up ratio is equal to (n * T) / ((n + (k - 1)) * Tk).
Where:
100 jobs make up the number n.
T = Number of ns it takes a non-pipelined system to complete a job, which is 300
k = Pipeline segment type = 5
Tk = The kind of segment pipeline's clock cycle count in ns, which is equal to 60
When we enter the aforementioned into equation, we get:
Speed-up ratio is equal to (100 * 300) / (100 + (5 - 1)) * 60) and equals 4.81.
Therefore, 4.81 is about the highest speedup that could be accomplished.
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Please help me with the attached image.
a. The two cars are moving at the same speed at t = 3.88 seconds.
b. The two autos are moving at a speed of 4.18 cm/s at that moment.
c. The cars pass each other at time t = 1.05 s and t = 2.54 s, respectively.
d. At t = 1.05 seconds, the first car is located at 12.15 cm, and the second car is located at 16.55 cm. At t = 2.54 seconds, the first car is located at 10.69 cm, and the second car is located at 17.39 cm.
What is the speed of the two cars?
The speed of the cars is derived using the formula for linear velocity.
The velocity of the first car is calculated as follows:
v = v₀ + at
where;
v₀ is the initial velocity,a is the acceleration, andt is the time elapsed.The velocity of the second car can be calculated as:
v = v₀
where;
v₀ is the initial velocity since there is no acceleration.
We equate the two velocities of the two cars and solve for time:
-4.40 + 2.70t = 6.10
2.70t = 10.50
t = 3.88 seconds
b. To find the speeds of the cars at time t, we can substitute t = 3.88 seconds in the velocity equation for the first car:
For the first car:
v = -4.40 + 2.70 * 3.88
v = 4.18 cm/s
c. Solving for the time when the positions of the cars are equal allows us to determine when they pass one another.
The position of the first car will be:
x = x₀ + v₀t + 1/2 at²
where x₀ is the initial position.
The position of the second car will be:
x = x₀ + v₀t
equating the two positions equal and solving for time:
13.5 - 4.40t + 1/2 * 2.70t² = 10.5 + 6.10t
1.35t² + 1.70t + 3.00 = 0
Solving the quadratic equation, we get two times:
t = 1.05 s and t = 2.54 s
d. We can re-insert the time values into the position equation for each car to determine where the automobiles were at the times indicated in (c).
For t = 1.05 seconds:
First car:
x = 13.5 - 4.40 * 1.05 + 1/2 * 2.70 * 1.05²
x = 12.15 cm
Second car:
x = 10.5 + 6.10 * 1.05
x = 16.55 cm
For t = 2.54 seconds:
First car:
x = 13.5 - 4.40 * 2.54 + 1/2 * 2.70 * 2.54²
x = 10.69 cm
Second car:
x = 10.5 + 6.10 * 2.54
x = 17.39 cm
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Someone please help me, I’m so lost my brain hurts
-- It takes 100 calories of heat to make 10 grams of the stuff 20° warmer.
How much of the heat warms each gram ?
-- It takes 10 calories of heat to make each gram of the stuff 20° warmer.
How much of the heat warms that gram each degree ?
-- It takes 1/2 calorie of heat to make each gram of the stuff 1° warmer.
The specific heat of that stuff is
(1/2 calorie) per gram per °C.
That's choice-3 .
Explanation:
The answer is No. 3
0.5 cal/g°C
Calculate how much work the force of gravity does on the sphere from B to C .
(a) The work done by the force of gravity from A to B is 4.41 Joules.
(b) The work done by the force of gravity from B to C is zero.
(c) The work done by the force of gravity from A to C is 4.41 Joules.
a) To calculate the work done by the force of gravity from A to B, we need to consider the change in potential energy. The potential energy at point A is maximum due to the maximum angle of 35.0∘ to the left of vertical, while at point B, the string is vertical, and the potential energy is zero.
The change in potential energy (ΔPE) is given by:
ΔPE = m * g * h
where m is the mass of the sphere (0.500 kg), g is the acceleration due to gravity (9.8 m/s^2), and h is the change in height.
Since the potential energy at point A is maximum, the change in height is equal to the length of the string (0.900 m).
ΔPE = 0.500 kg * 9.8 m/s^2 * 0.900 m = 4.41 J
Therefore, the work done by the force of gravity from A to B is 4.41 Joules.
b) From B to C, the change in height is zero since the string is already vertical. Hence, the work done by the force of gravity from B to C is zero.
c) The total work done by the force of gravity from A to C is the sum of the work done from A to B and from B to C.
Total work = Work from A to B + Work from B to C = 4.41 J + 0 J = 4.41 J
Therefore, the work done by the force of gravity from A to C is 4.41 Joules.
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I think it is the question:
A Pendulum Is Made Up Of A Small Sphere Of Mass 0.500 Kg Attached To A String Of Length 0.900 M. The Sphere Is Swinging Back And Forth Between Point A, Where The String Is At The Maximum Angle Of 35.0∘ To The Left Of Vertical, And Point C, Where The String Is At The Maximum Angle Of 35.0∘ To The Right Of Vertical. The String Is Vertical When The Sphere Is At
A pendulum is made up of a small sphere of mass 0.500 kg attached to a string of length 0.900 m. The sphere is swinging back and forth between point A, where the string is at the maximum angle of 35.0∘ to the left of vertical, and point C, where the string is at the maximum angle of 35.0∘ to the right of vertical. The string is vertical when the sphere is at point B.
a) Calculate how much work the force of gravity does on the sphere from A to B.
b) Calculate how much work the force of gravity does on the sphere from B to C.
c) Calculate how much work the force of gravity does on the sphere from A to C.
whare the temperatures found in each layer of the atmosphere
The temperature in the stratosphere ranges from negative 60 degrees Fahrenheit (negative 51 degrees Celsius) at the troposphere boundary to negative 5 degrees Fahrenheit (negative 15 degrees Celsius) at the top. The temperature increase is due to the ozone layer that absorbs ultraviolet light from solar radiation.
The _____ is locked into a gravitational pull with our Milky Way, so both are actually
orbiting each other and slowly closing the gap between the them.
Kepler-22
Andromeda galaxy
PSR B1620-26 b
O Proxima-b
Answer:
Andromeda galaxy is the correct answer.
What is sound waves
Sound waves are a type of mechanical wave that propagate through a medium, typically air but also other materials such as water or solids.
Characteristics of sound wavesFrequency: the frequency of a sound wave refers to the number of cycles or vibrations it completes per second and is measured in Hertz (Hz).
Amplitude: the amplitude of a sound wave refers to the maximum displacement or intensity of the wave from its equilibrium position. It represents the loudness or volume of the sound, with larger amplitudes corresponding to louder sounds and smaller amplitudes corresponding to softer sounds.
Wavelength: the wavelength of a sound wave is the distance between two consecutive points in the wave that are in phase, such as from one peak to the next or one trough to the next. It is inversely related to the frequency of the wave.
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Select the correct answer.
Which statement is true for a series circuit?
• A.
The voltage is the same
across all resistors in the circuit.
O B. As more resistors are added, the current will increase.
O C. The average of the voltage drops will be the total voltage in the circuit.
O D.
The current is the same across all resistors in the circuit.
O E.
The equivalent resistance will be less than the
resistance of each individual resistor.
Reset
Next
Answer:
D. The current is the same across all resistors in the circuit.
Explanation:
In a series circuit, all circuit elements are connected so that there is exactly one current path. That path goes through each of the elements of the circuit.
The current is the same through all resistors in a series circuit.
a student standing in an elevator at rest notices that her pendulum has a frequency of oscillation of 0.5 Hz. a. what is the length of the pendulum's string? b. the elevator starts to accelerate upwards. what effect will this have on the oscillation? explain.
Explanation:
Given that,
The frequency of oscillation, f = 0.5 Hz
(a) Let the length of the pendulum string is l. So,
\(T=2\pi \sqrt{\dfrac{l}{g}}\)
T is time period, T = 1/f
So,
\(l=\dfrac{(\dfrac{1}{f})^2g}{4\pi ^2}\\\\l=\dfrac{(\dfrac{1}{0.5})^2\times 9.8}{4\times 3.14 ^2}\\\\l=0.993\ m\)
(b) When the elevator starts to accelerate upwards, new acceleration is a+g. If accelerating upward, the value of g has increased, because of inertia. So it will feel heavier and the period will decrease.
Twelve identical point charges q are equally spaced around the circumference of a circle of radius R. The circle is centered at the origin. One of the twelve charges, which happens to be on the positive x axis, is now moved to the center of the circle.
A) Determine the magnitude of the total electric force exerted on this charge.
Express your answer in terms of Coulomb's constant k and the variables q and R .
F total = ?
B)Determine the direction of the total electric force exerted on this charge.
Express your answer as an integer.
θ = ? degrees
Answer:
For B it is 0
Explanation:
I think
Can someone please help me
With the application of resolution of vector, the net force is 197 N and the direction is 59 degree.
Resolution of ForcesResolution of forces can simply be solved by resolving to horizontal and vertical component.
In the given figure, we will resolve the forces into horizontal and vertical components.
Horizontal component
Fh = 80 cos 80 + 60 cos 30 + 70 cos 60
Fh = 13.89 + 51.96 + 35
Fh = 100.85 N
Vertical Component
Fv = 80 sin 80 + 60 sin 30 - 70 sin 60
Fv = 78.78 + 30 + 60.62
Fv = 169.4 N
Resultant force = √( Fh² + Fv²)
Resultant force = √(100.85² + 169.4²)
Resultant force = √(10170.7 + 28696.4)
Resultant force = √38867.06
Resultant force = 197.15 N
The direction will be
Tan Ф = Fv/Fh
Tan Ф = 169.4 / 100.85
Tan Ф = 1.68
Ф = \(tan^{-1}\)(1.68)
Ф = 59.23
Therefore, the magnitude of resultant force is 197.15 N and the direction is 59 degree north east
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Water has a specific heat capacity of 1.00 cal/g °C, and copper has a specific heat capacity of 0.092 cal/g °C. If both are heated to 100 °C, which takes longer to cool?
Answer:
The water takes longer, because it is the better insulator here.
Explanation:
Conductors and insulators work similarly in "reverse".
If something is a good heat conductor, then it's good at both absorbing heat energy and giving it away. Insulators are good at resisting temperature changes, but also take longer to cool down once they are heated up.
So because copper is the better conductor here, it will cool faster than the water at the same temperature.
Excellent human jumpers can leap straight up to a
height of 95 cm off the ground.
To reach this height, with what speed would a person need to leave the ground?
The speed that the person needs to leave the ground will be 4.32m/s
From the question given,
Height = 95cm
Since the person leave the ground v = 0m/s
acceleration due to gravity g = 9.8m/s²
Using the equation of motion
v² = u² + 2as
a = -g (upward motion)
s = h (distance changes to height)
The equation will become:
0² = u² - 2gh
0² = u² - 2(9.8)(0.95)
u² = 18.62
u = √18.62
u = 4.32
Hence the speed that the person needs to leave the ground will be 4.32m/s
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A contestant in a winter games event pulls a 36.0 kg block of ice across a frozen lake with a rope over his shoulder as shown in Figure 4.29(b). The coefficient of static friction is 0.1 and the coefficient of kinetic friction is 0.03.
Figure 4.29
(a) Calculate the minimum force F he must exert to get the block moving.
40.873
(b) What is its acceleration once it starts to move, if that force is maintained?
m/s2
(a) The minimum force F he must exert to get the block moving is 38.9 N.
(b) The acceleration of the block is 0.79 m/s².
Minimum force to be applied
The minimum force F he must exert to get the block moving is calculated as follows;
Fcosθ = μ(s)Fₙ
Fcosθ = μ(s)mg
where;
μ(s) is coefficient of static frictionm is mass of the blockg is acceleration due to gravityF = [0.1(36)(9.8)] / [(cos(25)]
F = 38.9 N
Acceleration of the blockF(net) = 38.9 - (0.03 x 36 x 9.8) = 28.32
a = F(net)/m
a = 28.32/36
a = 0.79 m/s²
Thus, the minimum force F he must exert to get the block moving is 38.9 N.
The acceleration of the block is 0.79 m/s².
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Two small objects A and B are fixed in place and separated by a distance of 3.00 cm in a vacuum. Object A has a
charge of +2.00 С and object B has a charge of -2.00 C. How many electrons must be removed from object A and
placed on object B to make the electrostatic force into an attractive force with a magnitude of 68.0 N.
The number of electrons that must be removed from object A and placed on object B is 1.24 * \(10^{19}\)
We know that,
E = k \(q_{1}\) \(q_{2}\) / r²
where,
E = Electrostatic force
k = Coulomb's constant
\(q_{1}\), \(q_{2}\) = Point charges
r = Distance between two charges
Given that,
\(q_{1}\) = 2 + ne C
\(q_{2}\) = - 2 - ne C
r = 3 cm
k = 9 * \(10^{9}\) N m² / C²
E = - 68 N ( Since it is attractive )
- 68 = 9 * \(10^{9}\) ( 2 - ne ) ( - 2 + ne ) / ( 3 * \(10^{-2}\) )²
68 * \(10^{-4}\) / 3 * \(10^{9}\) = ( 2 - ne )²
2.27 * \(10^{-12}\) = ( 2 - ne )²
1.5 * \(10^{-6}\) = 2 - ne
ne = 1.98
n = 1.98 / 1.6 * \(10^{-19}\) = 1.24 * \(10^{19}\)
The given problem is an electrostatic attractive force because the two point charges are unlike charges. If the charges are like, then the electrostatic force will be repulsive.
Therefore, the number of electrons that must be removed from object A and placed on object B is 1.24 * \(10^{19}\)
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How is the sun used to make food?
Answer:
Plants use a process called photosynthesis to make food. During photosynthesis, plants trap light energy with their leaves. Plants use the energy of the sun to change water and carbon dioxide into a sugar called glucose. Glucose is used by plants for energy and to make other substances like cellulose and starch.
Thank you
Answer:
Plants use a process called photosynthesis to make food. During photosynthesis, plants trap light energy with their leaves. Plants use the energy of the sun to change water and carbon dioxide into a sugar called glucose.