Emmy kicks a soccer ball up at an angle of 45° over a level field. She watches the ball's trajectory and notices that it lands, two seconds after being kicked, about 20 m away to the north. Assume that air resistance is negligible, and plot the horizontal and vertical components of the ball's velocity as a function of time. Consider only the time that the ball is in the air, after being kicked but before landing. Take "north" and "up" as the positive x ‑ and y ‑directions, respectively, and use g≈10 m/s2 for the downward acceleration due to gravity.

Answer:

It would be positive. Because.

Explanation:

the plus is electronic shell and it would be connectivity.

positive

the direction of the electric field is away from the positive charge

Answer:

x² = ((n-1)s²)/o²

x² = (39 - 1) * (3.15)² / (2.94)²

x² = 38 * 9.9225 / 8.6436

x² = 43.7598

Rounding to three decimal places, x² = 43.760. Therefore, the value of x² is 43.760 when o = 2.94, n = 39, and s = 3.15.

Explanation:

Math

Answer:

4 & 2

Explanation:

If you plug in experimental values into the formula for kinetic energy, you will see the relationship.

1.

\(\frac{1}{2}(2 kg)(2 m/s)^{2} = 4 kg * m^{2} /s^{2} \\\\\frac{1}{2}(8 kg)(2m/s)^{2} = 16 kg * m^{2} /s^{2}\\\\\frac{16}{4} = 4\)

2.

\(\frac{1}{2}(6 kg)(2m/s)^{2} = 12 kg * m^{2} /s^{2} \\\\\frac{1}{2}(3 kg)(2 m/s)^{2} = 6 kg * m^{2}/s^{2}\\ \\\frac{12}{6} = 2\)

Answer:

a) number of copper atoms 65 (⁶⁵Cu)  is 7.692 10⁶ atoms

b) m_total Cu = 1.585 10⁹ u = 2.632 10⁻¹⁸ kg

Explanation:

a) For this exercise let's start by using the radioactive decay ratio

           N = N₀  \(e^{- \lambda t}\)o e - lambda t

The half-life time is defined as the time it takes for half of the radioactive (activated) atoms to decay, therefore after two half-lives there are

            N = ½ (½ N₀) = ¼ N₀

            N₀ = 4 N

in each decay a photon is emitted so we can use a direct rule of proportions. If an atom emits a photon it has Eo = 1,04 Mev, how many photons it has energy E = 10,000 MeV

          # _atoms = 1 atom (photon) (E / Eo)

          # _atoms = 1 10000 / 1.04

          # _atoms = 9615,4 atoms

          N₀ = 4 #_atoms

          N₀ = 4 9615,4

          N₀=  38461.6  atoms

in the exercise indicates that half of the atoms decay in this way and the other half decays directly to the base state of Zinc, so the total number of activated atoms

          N_activated = 2 # _atoms

          N_activated = 2 38461.6

          N_activated = 76923.2

also indicates that 1% = 0.01 of the nuclei is activated by neutron bombardment

          N_activated = 0.01 N_total

          N_total = N_activated / 0.01

          N_total = 76923.2 / 100

          N_total = 7.692 10⁶ atoms

so the number of copper atoms 65 (⁶⁵Cu)  is 7.692 10⁶

b) the natural abundance of copper is

  ⁶³Cu     69.17%

  ⁶⁵Cu    30.83%

Let's use a direct proportion rule. If there are 7.692 10⁶  ⁶⁵Cu that represents 30.83, how much ⁶³Cu is there that represents 69.17%

                # _63Cu = 69.17%  (7.692 10⁶    / 30.83%)

                # _63Cu = 17.258 10⁶  atom  ⁶³Cu

the total amount of comatose is

              #_total Cu = #_ 65Cu + # _63Cu

              #_total Cu = (7.692 + 17.258) 10⁶

              #_total Cu = 24.95 10⁶

the atomic mass of copper is m_Cu = 63.546 u

          m_total = #_totalCu m_Cu

          m_total = 24.95 10⁶ 63,546 u

          m_total = 1.585 10⁹ u

let's reduce to kg

           m_total Cu = 1.585 10⁹ u (1,66054 10⁻²⁷ kg / 1 u)

           m_total Cu = 2.632 10⁻¹⁸ kg

Explanation:

please mark me as brainlest

The centripetal force in Newtons provided by the friction between the blade of the skate and the ice is 490 N

The following data were obtained from the question:

The centripetal force can be obtained as illustrated below:

F = mv²/r

= (50 × 7²) / 5

= (50 × 49) / 5

= 2450 / 5

= 490 N

Thus, we can concluded that the centripetal force is 490 N

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Answer:

weight

Explanation:

weight is the pull of gravity so its a force !!

The type of energy that creates the electrical energy is Option D) The electrical energy comes from the attraction between charges in the cloud and the ground creating an electric potential.

Lightning is a natural electrical discharge of very high voltage that occurs in the atmosphere. It is a result of the buildup of charges in the atmosphere. The atmosphere contains different types of gases, including water vapor. As warm and cold air masses mix, they create turbulence and water vapor rises, forming clouds. These clouds contain millions of water droplets, ice crystals, and other particles. Within these clouds, there are electrical charges that build up.

The electrical energy in lightning comes from the attraction between the positive and negative charges in the cloud and the ground. When there is a large enough charge separation between the positive and negative charges in the cloud, an electric potential is created. This electric potential can build up to a point where it overcomes the insulating properties of the atmosphere and a lightning bolt is discharged. The lightning bolt is essentially a giant spark of electricity that bridges the gap between the cloud and the ground, creating a flow of electrical energy.

In summary, the electrical energy in lightning is created by the attraction between the positive and negative charges in the cloud and the ground, creating an electric potential that can discharge as a lightning bolt. Therefore, Option D is Correct.

The question was Incomplete, Find the full content below :

Lightning is a very large flow of electrical energy. Describe the type of energy that creates the electrical energy.

A) The electrical energy comes from the thermal energy stored up in the water molecules.

B) The electrical energy comes from the gravitational potential energy of the water molecules.

C) The electrical energy comes from the chemical potential energy of the water molecules in the clouds.

D) The electrical energy comes from the attraction between charges in the cloud and the ground creating an electric potential.

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The velocity, measured in the Earth reference frame, of an inertial reference frame in which the cat's kinetic energy does not change is equal to the velocity of the skier before the collision. The velocity of the skier before the collision is 15 m/s.

According to the law of conservation of momentum, the total momentum before the collision must be equal to the total momentum after the collision. This can be expressed as m1*v1 + m2*v2 = (m1 + m2)*vf, where m1 and m2 are the masses of the skier and the cat respectively, v1 is the velocity of the skier, and vf is the velocity of the skier and the cat after the collision.

The kinetic energy converted to internal energy in the Earth reference frame can be determined by applying the law of conservation of momentum.

The amount of kinetic energy converted to internal energy can be calculated as follows:

m1*v1 = (m1 + m2)*vf

vf = (m1*v1)/(m1 + m2)

KE = (1/2)*m2*v2²

KE converted = KE initial - KE final

KE converted = (1/2)*m2*v2² - (1/2)*m2*((m1*v1)/(m1 + m2))²

KE converted = (1/2)*m2*v2² - (1/2)*m2*((60*15)/(60 + 5))²

KE converted = (1/2)*5*3.8² - (1/2)*5*(15²/65)

KE converted = 28.8 - 22.15

KE converted = 6.65 J

The velocity, measured in the Earth reference frame, of an inertial reference frame in which the cat's kinetic energy does not change is equal to the velocity of the skier before the collision.

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Given the speed of the driver and the time elapsed, distance traveled during his inattentive period is 0.037 kilometers.

Speed is simply referred to as distance traveled per unit time.

Mathematically, Speed = Distance ÷ time.

Given the data in the question;

First, convert 1.7 seconds to hours.

Time = 1.7s = (1.7 / (60×60)hr = 1.7/3600 hrs

Now, find the distance traveled during the inattentive period.

80 km/h = Distance ÷ 1.7/3600 hrs

Distance = 80 km/h × 1.7/3600 hrs

Distance = 136/3600 km

Distance = 0.037 km.

Given the speed of the driver and the time elapsed, distance traveled during his inattentive period is 0.037 kilometers.

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The bicyclist is applying more force on the pedals at Time 2. Option C

If we look at the image that have been shown, we can be able to see that the force that is acting have been shows by the arrows that have been used to label the movement of the cyclist in the image that is shown here.

We can see that the forward arrow at the time 2 is seen to be larger than the forward arrow that is shown for time 1. The implication of this is that the cyclist is cycling harder and applying more force at time 2 than at time 1.

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The minimum coefficient of static friction with the floor is 0.3846.

To find the minimum coefficient of static friction with the floor, we need to consider the forces acting on the couch. In this case, the force of gravity is pulling the couch downward with a magnitude of mg, where m is the mass of the couch (40 kg) and g is the acceleration due to gravity (9.8 m/s²).

Since the couch does not move, the force of static friction between the couch and the floor must be equal in magnitude but opposite in direction to the horizontal pushing force of 150 N.

Therefore, we have the equation F_friction = F_push, where F_friction is the force of static friction.

The force of static friction can be calculated using the formula F_friction = μ_s * N, where μ_s is the coefficient of static friction and N is the normal force.

Since the couch is on a level floor and is not accelerating vertically, the normal force N is equal in magnitude but opposite in direction to the force of gravity, which is mg.

Substituting the values into the equation, we have μs * mg = 150 N.
Solving for μs, we get μs = 150 N / (mg).
Substituting the given values, we have μ_s = 150 N / (40 kg * 9.8 m/s²).
Simplifying, we find that μs = 0.3846.

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While certain types of glass containers may be suitable for short-term storage of vinegar, it is generally recommended to use non-reactive materials, such as plastic or stainless steel, for long-term storage to avoid any potential chemical reactions or corrosion.

Vinegar is an acidic liquid that contains acetic acid. When vinegar comes into contact with certain types of glass, particularly those made of lead or other reactive materials, a chemical reaction can occur. This reaction can lead to the leaching of potentially harmful substances into the vinegar.

Glass containers made from specific types of glass, such as soda-lime glass, are generally safe for storing vinegar.

However, it is important to note that prolonged storage or exposure to vinegar can still cause the glass to corrode over time. This can result in the deterioration of the glass container, potentially leading to breakage or the release of glass fragments.

To avoid any potential issues, it is recommended to use containers made of non-reactive materials, such as food-grade plastic or stainless steel, for long-term storage of vinegar. These materials do not react with the acidic nature of vinegar and do not pose a risk of leaching harmful substances.

Additionally, it is important to store vinegar in a cool, dark place to maintain its quality and prevent spoilage. Exposure to light and heat can degrade the quality of vinegar over time.

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The work done by the wind on Mikaela as she rounds the curve is zero.

The given parameters;

The work done by the wind on Mikaela as she rounds the curve is determined by applying work-energy theorem.

The change in kinetic energy of Mikaela = Work done by wind on Mikaela

\(\Delta K.E = W\\\\\Delta K.E = \frac{1}{2} m(v_f^2 - v_0^2)\)

The speed of Mikaela was constant; \(v_f = v_0\)

\(\Delta K.E = W = 0\)

Thus, the work done by the wind on Mikaela as she rounds the curve is zero.

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Answer:

1.2 kg

__________________________________________________________

We are given:

Mass of the block = 2 kg

Coefficient of Static Friction = 0.6

__________________________________________________________

Friction Force on the Block:

Finding the Normal Force:

We know that the normal force will be equal and opposite to the weight of the 2 kg block

So, Normal Force = mg

replacing the variables with the given values

Normal Force = (2)(9.8)                    [Taking g = 9.8]

Normal Force = 19.6 N

Friction force on the Block:

We know that:

Coefficient of Static Friction =  Static Friction Force/Normal Force

replacing the variables

0.6 = Static Friction force / 19.6

Static Friction force = 0.6*19.6 N                 [Multiplying both sides by 19.6]

Static Friction force = 11.76 N

__________________________________________________________

Largest Mass that can Hang:

We know that the Static Friction force is 11.76 N, this means that a force of 11.76 N will be applied to keep the object at rest

So, if the weight of the second block is less than the static friction force, it will hang

Weight of the second block ≤ 11.76

We know that weight = mg

mg ≤ 11.76

m(9.8) ≤ 11.76                                                   [since g = 9.8]

m ≤ 1.2 kg                                                        [dividing both sides by 9.8]

From this, we can say that the maximum mass of the second block is 1.2 Kg

Answer:

The answer is "26.3 m".

Explanation:

The positive value from the x-axis is to the direction east side

The negative value from the x-axis is to the direction west side

The positive value from the y-axis is to the direction upwards side

The negative value from the y-axis is to the direction down words side

The positive value from the z-axis is to the direction southside

The negative value from the z-axis is to the direction north side

If the value is i, j, and k are the unit of the given vectors, which can be defined as follows:

\(\hat i, \hat -i, \hat j, \hat -j, \hat k, \hat -k\)

The displacements values:

\(\underset{d_1}{\rightarrow} = -14 \ \hat i\\\\\underset{d_2}{\rightarrow} = 22\ \hat j\\\\\underset{d_3}{\rightarrow} = -12 \ \hat k\\\\\underset{d_4}{\rightarrow} = 6 \ \hat i\\\\\)

calculating the final displacement that is  \(\underset{d_5}{\rightarrow}\):

\(\Rightarrow \underset{d_1}{\rightarrow}+\underset{d_2}{\rightarrow}+\underset{d_3}{\rightarrow}+\underset{d_4}{\rightarrow}+\underset{d_5}{\rightarrow} =0\\\\\Rightarrow \underset{d_5}{\rightarrow} \ \ = -(\underset{d_1}{\rightarrow}+\underset{d_2}{\rightarrow}+\underset{d_3}{\rightarrow}+\underset{d_4}{\rightarrow})\)

         \(=- (-14 \hat i+ 22 \hat j -12 \hat k+ 6 \hat i)\\\\=- (-8 \hat i+ 22 \hat j -12 \hat k)\\\\=8 \hat i- 22 \hat j +12 \hat k\\\)

\(|\underset{d_5}{\rightarrow}|=\sqrt{8^2 +(- 22)^2 +(12)^2 }\\\\\)

       \(= \sqrt{64 + 484 +144 }\\\\= \sqrt{208 + 484}\\\\= \sqrt{692}\\\\= 26.3 \ m\)

Answer:

paying too much on the black market instead of getting a prescription

Explanation:

i just took the quiz

Answer:

Paying too much on the black market instead of getting a prescription

Explanation:

The rest of the options are risks associated with using legal drugs without medical supervision.

The maximum magnitude of the friction force exerted on the box by the ramp is 44.41 N.

The given parameters;

The normal force on the wooden box is calculated as follows;

\(F_n = mg \times cos(\theta)\\\\F_n = 10 \times 9.8 \times cos(25)\\\\F_n = 88.8 2 \ N\)

The maximum magnitude of the friction force exerted on the box by the ramp is calculated as follows;

\(F_f = \mu \times F_n\\\\F_f = 0.5 \times 88.82 \\\\F_f = 44.41 \ N\)

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The formation of bubbles while heating a liquid can affect the coefficient of cubical expansion γ of the liquid. The coefficient of cubical expansion is a measure of how much a liquid expands when its temperature increases.

When bubbles form in a liquid, they create voids that decrease the effective volume of the liquid. As a result, the apparent expansion of the liquid is reduced, which decreases the value of γ.

The effect of bubble formation on the coefficient of cubical expansion depends on the size, number, and location of the bubbles. For example, if the bubbles are very small and evenly distributed throughout the liquid, the effect on γ may be negligible. On the other hand, if the bubbles are large and located near the surface of the liquid, they may significantly reduce the effective volume of the liquid and decrease the value of γ.

In addition, the formation of bubbles can also lead to other effects that affect the expansion of the liquid. For example, the vaporization of the liquid can cause a decrease in pressure, which can also affect the value of γ. Therefore, the formation of bubbles while heating a liquid can have complex effects on the coefficient of cubical expansion of the liquid, and the exact effect depends on various factors.

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The given information is insufficient to determine the change in length of the object at 25°C using the metal scale graduated at 0°C.

To solve this problem, we need to consider the concept of linear expansion. Most materials, including metals, expand when heated and contract when cooled. The amount of expansion or contraction depends on the coefficient of linear expansion (α) of the material.

The formula for linear expansion is:

ΔL = α * L * ΔT

where ΔL is the change in length, α is the coefficient of linear expansion, L is the original length, and ΔT is the change in temperature.

Given:

Coefficient of linear expansion for the metal scale (α) = 18 × 10^(-4) °C^(-1) (assuming it's the same as the metal of the object)

Temperature difference (ΔT) = 25°C - 0°C = 25°C

Original length (L) = unknown

We are asked to find the change in length (ΔL) of the object when measured at 25°C compared to its measurement at 0°C. Let's assume the object's original length at 0°C is L0.

ΔL = α * L * ΔT

ΔL = 18 × 10^(-4) °C^(-1) * L0 * 25°C

However, the given information is incomplete. The specific value of L0 or any other details about the object are not provided. Without knowing the original length of the object or any other relevant information, it is not possible to calculate the change in length or answer the question accurately.

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The potential energy of the roller coaster is 176,400 J (joules).

The potential energy of an object is given by the formula PE = mgh, where PE is the potential energy, m is the mass of the object, g is the acceleration due to gravity, and h is the height or vertical position of the object.

In this case, the roller coaster is at a peak of 20m and has a mass of 900kg. The acceleration due to gravity, g, is approximately 9.8 \(m/s^2\).

Using the formula, we can calculate the potential energy:

PE = mgh

= (900 kg)(9.8 \(m/s^2\))(20 m)

= 176,400 J

Therefore, the potential energy of the roller coaster is 176,400 J (joules).

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hydroelectric dam converts the potential energy stored in a water reservoir behind a dam to mechanical energy—mechanical energy is also known as kinetic energy. ... The generator converts the turbine's mechanical energy into electricity.

Hope this helps!

Answer:

Potential energy and kinetic energy are constituents of mechanical energy.

When a turbine is switched on, it rotates with mechanical energy.

Since a motor runs the turbine, it converts this mechanical energy to electrical energy.

Answer:

how can we get the best out with a little of my life and I think the most common reason I would n I have been having this problem for years is done in my life as the other people

As the fish tank is 20 inches by 12 inches by 12 inches, its volume is 47194744.32 mm³.

The space that any three-dimensional solid occupies is known as its volume. These solids can take the form of a cube, cuboid, cone, cylinder, or sphere.

1 inch = 0.0254 meters.

20 inches = 20 × 0.0254 meters = 0.508 meters = 508 mm.

12 inches = 12 × 0.0254 meters = 0.3048 meters = 304.8 mm.

Hence, The volume of the fish tank  = length × width × height

=  508 mm ×  304.8 mm ×  304.8 mm.

= 47194744.32 mm³

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Given:

Two skydivers jump from an airplane at an altitude of: d = 5000 m

The mass of the first skydiver is: m1 = 57 kg

The mass of the second skydiver is: m2 = 68 kg

Area = 0.18 m²

Air density = 1.21 kg/m³

Drag Coefficient: C = 0.070

To find:

The amount of time each skydiver takes to get to the ground.

Explanation:

The magnitude of drag force which acts opposite in the opposite direction is equal to the weight of the skydiver. Thus, the magnitude of the drag force can be calculated as:

Here, F1 is the magnitude of the drag force on the first skydiver and F2 is the drag force on the second skydiver.

The expression for drag force relating to the velocity is given as:

For the first skydiver the drag force is given as:

The velocity v1 of the first skydiver is 270.70 m/s.

The time t1 taken by the first skydiver to get to the ground can be calculated as:

The first skydiver takes 18.47 seconds to get to the ground.

For the second skydiver, the drag force is given as:

The velocity v2 of the second skydiver is 259.67 m/s.

The time t2 taken by the second skydiver to get to the ground can be calculated as:

The second skydiver takes 16.91 seconds to get to the ground.

Final answer:

The first skydiver takes 18.47 seconds to get to the ground.

The second skydiver takes 16.91 seconds to get to the ground.

Answer:

patron

Explanation:

 The patron is something or someone who defends some cause or point of view. In the art field, for example, the patron may be considered a sponsor, that is, someone who is known for defending a particular group of people or specific situation.

  The patron is one who advocates, advises and directs. In the military, patrons are heroic figures who are chosen to defend a military unit, for example.

Explanation:

patron

Explanation:

 The patron is something or someone who defends some cause or point of view. In the art field, for example, the patron may be considered a sponsor, that is, someone who is known for defending a particular group of people or specific situation.

  The patron is one who advocates, advises and directs. In the military, patrons are heroic figures who are chosen to defend a military unit, for example.

Answer:

\(2.01 \times 10^{-5}\ T\)

Complete question:if a = 0.800 cm? (μ0 = 4π × 10-7 T · m/A)

Explanation:

Given:

Distance between plates = 0.8 cm

Distance from one plate = 1 mm

Current density 'J'= 16 A/m

Currents are flowing in opposite direction.

\(\mu _o=4\pi \times 10^{-7}\)

When current is flowing in opposite direction then magnetic field given as

\(B=\dfrac{\mu _oJ}{2}+\dfrac{\mu _oJ}{2}\\B=\mu _oJ\)

By putting the values we get

\(B=4\pi \times 10^{-7}\times 16\\B=2.01 \times 10^{-5}\ T\)