Engineers and science fiction writers have proposed designing space stations in the shape of a rotating wheel or ring, which would allow astronauts to experience a sort of artificial gravity when walking along the inner wall of the station's outer rim. (a) Imagine one such station with a diameter of 117 m, where the apparent gravity is 3.10 m/s2 at the outer rim. How fast is the station rotating in revolutions per minute

Answer:

Waxing Gibbous

Explanation:

New Moon Rises at sunrise, transits meridian at noon, sets at sunset

Explanation:

Bluetooth works through radio waves in the ISM band, that is, they work by radio frequency. For that use the wireless networks of personal area (WPAN).

Bluetooth is a form of communication that works through radio waves by which there can be a transfer of data such as music, documents, images, etc. It works at a short distance so the devices must be close for the data transfer to occur correctly

Therefore, we can confirm that Bluetooth works through radio waves in the ISM band, that is, they work by radio frequency. For that use the wireless networks of personal area (WPAN).

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Given,

The speed of the turkey, s=2 m/s

The time duration, t=5 s

The speed is given by the ratio of the distance traveled to the time period in which that distance is covered.

Thus

Where d is the distance.

Thus, on substituting the known values in the above equation,

Thus the distance covered by the turkey is 10 m

Thus the correct answer is option 2.

The skater's final angular velocity is approximately 9.86 rad/s.

The skater's final angular velocity can be calculated using the principle of conservation of angular momentum. The equation for angular momentum is given by:

L = Iω

where L is the angular momentum, I is the moment of inertia, and ω is the angular velocity.

Initially, the skater has an angular momentum of:

L_initial = I_initial * ω_initial

Substituting the given values:

L_initial = 2.12 kg m² * 3.25 rad/s

The skater's final angular momentum remains the same, as angular momentum is conserved:

L_final = L_initial

The final moment of inertia is given as 0.699 kg m². Therefore, the final angular velocity can be calculated as:

L_final = I_final * ω_final

0.699 kg m² * ω_final = 2.12 kg m² * 3.25 rad/s

Solving for ω_final:

ω_final = (2.12 kg m² * 3.25 rad/s) / 0.699 kg m²

Hence, the skater's final angular velocity is approximately 9.86 rad/s.

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The electric potential at x=3.0m is  - 180 Volt according to the figure 1.

An electric field is a physical field that surrounds electrically charged particles and acts as an attractor or repellent to all other charged particles in the vicinity. Additionally, it refers to a system of charged particles' physical field.

Electric charges and time-varying electric currents are the building blocks of electric fields.

The electric potential at x=3.0m is given by = initial potential energy + electric field× distance

= - 180 Volt + 0 Volt/meter×3 meter

= - 180 Volt.

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Answer:

A

Explanation:

you cannot change the length and direction

number A is right I think

The Big Bang theory is the most widely accepted explanation for the origins of the universe, but it does not necessarily imply that the universe emerged from nothing.

It is possible that new discoveries or insights may shed light on this fundamental question in the future. The universe may have arisen from a pre-existing state or through some other natural process that we do not yet understand.

Instead, the theory describes how the universe underwent a rapid expansion from a very dense and hot state. The conditions and laws of physics that applied during the earliest moments of the universe may not necessarily be the same as those we observe today, and there are many unknowns and uncertainties in our understanding of these early stages.

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The net force is negative, which means it is directed towards q₂ and q₃, in the opposite direction to q1.

Coulomb's constant (k) is a proportionality constant found in Coulomb's law. Coulomb's law describes the electrostatic force between two point charges and states that the force is proportional to the product of the charges and inversely proportional to the square of the distance between them.

The mathematical expression for Coulomb's law is:

F = k *q₁* q₂ / r²

where F is the electrostatic force between two point-charges q1 and q2, separated by a distance r. The constant k is known as Coulomb's constant and has a value of approximately 9 × 10⁹ N·m²/C².

The net force on particle q1 is the vector sum of the forces exerted on it by particles q₂ and q₃, which can be calculated using Coulomb's law:

F12 = k * q₁ * q₂ / r₁₂²

F23 = k * q₂ * q₃ / r₂₃²

where k is Coulomb's constant (9 × 10⁹ N·m²/C²), r₁₂ and r₂₃ are the distances between q₁ and q₂, and q₂ and q₃, respectively.

Since the particles are in a straight line, the forces F₁₂ and F₂₃ will be in opposite directions and will cancel each other out to some extent. q1will have net force:

F net = F₁₂ +  F₂₃

To calculate the net force, we need to plug in the given values:

q₁ = -2.35 × 10⁻⁶ C

q₂ =-2.35 × 10⁻⁶ C

q₃= -2.35 × 10⁻⁶ C

r₁₂ = r23 = 0.100 m

Substituting these values, we get:

F₁₂ = (9 × 10⁹ N·m²/C²) * (-2.35 × 10⁻⁶ C)² / (0.100 m)²

= -4.396 N

F₂₃ = (9 × 10⁹ N·m²/C²) * (-2.35 × 10⁻⁶ C)² / (0.100 m)²

= -4.396 N

Therefore, the net force on q1 is:

F net = F₁₂ + F₂₃

= -4.396 N + (-4.396 N)

= -8.792 N

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Answer:

920000

Explanation:

Each kg contains 1,000 grams

Answer:

(a) magnitude: 9.96 m/s

Direction: 64.67°

(b) 158268.16 Joules

Explanation:

Part (a)

We need to apply the conservation of momentum in each direction, so

Solving for vfy, we get:

For the horizontal direction, we get:

Now, we can calculate the magnitude and direction of the final velocity as follows

Part (b)

Then, the loss in kinetic energy can be calculated as:

Therefore, the loss in kinetic energy was 158,268.16 Joules.

Answer:

I think its d

Explanation:

I'm not sure I'm sorry if I'm wrong

The final velocity of the skydiver after one second is -9.81 m/s (i.e., a velocity of 9.81 m/s downward).

To determine the skydiver's velocity after one second, we need to know the acceleration due to gravity and the initial velocity of the skydiver.

Let's assume that the skydiver is falling straight down and that their initial velocity is zero (i.e., they are released from rest). In this case, the acceleration of the skydiver is simply the acceleration due to gravity, which is approximately \(9.81 m/s^2\) . We can use the following kinematic equation to find the final velocity of the skydiver after one second:

\(v_f = v_i + a*t\)

where \(v_f\) is the final velocity, \(v_i\)  is the initial velocity, a is the acceleration, and t is the time.

Substituting the known values, we get:

\(v_f = 0 + (9.81 m/s^2)*1 s\)

= 9.81 m/s

Since the skydiver is falling straight down, the velocity is in the downward direction, which we can denote as negative. Therefore, the final velocity of the skydiver after one second is -9.81 m/s (i.e., a velocity of 9.81 m/s downward).

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Answer:

true, there are certain forms of bacteria in water that can cause permanent brain damage (although its rare) so further contamination of water can lead to higher chances of contracting serious illnesses caused by such bacteria.

Answer:

Approximately \(3.1\; \rm m \cdot s^{-1}\).

Explanation:

The content of this pail is in a centripetal motion because its path forms part of a vertical circle. Let \(m\) denote the mass of the contents of this pail, let \(v\) denote the (linear) velocity of the content, and let \(r\) denote the radius of this circle. The net force on the contents of this pail will thus be:

\(\displaystyle F(\text{net}) = \frac{m\, v^2}{r}\) towards the center of the circle.

Assume that there is no friction between the content and walls of the pail. The only two possible forces on the contents pail towards the center would be:

Note that at the top of the circle, both the gravitational pull and the normal force from the bottom point towards the center of the circle. On the other hand, the normal force from the walls of the pail would be perpendicular to the line towards the center of the circle. At that point in the circle, there's no upward force to support the content of the pail. The uniform rotation will be sufficiently fast if it could allow the content to stay in the pail at the top of the circle.

Let \(g\) denote the gravitational field strength at the top of this circle. The size of the gravitational pull on the content would be \(m\cdot g\). Let \(F(\text{normal})\) denote the normal force from the bottom of the pail on the contents. The sum of these two forces should be equal to the vertical net force on the contents of this pail. That is:

\(F(\text{net}) = m\cdot g + F(\text{normal})\).

From the centripetal motion of the content:

\(\displaystyle \frac{m\, v^2}{r} = m\cdot g + F(\text{normal})\).

Rearrange to obtain an expression for the normal force:

\(\displaystyle F(\text{normal}) = \frac{m\, v^2}{r} - m\cdot g\).

Note, that the normal force the bottom of the pail exerts on the contents should be greater than or equal to zero. While the pail is at the top of the circle, the normal force from the bottom of the pail cannot pull the contents upwards. Hence:

\(\displaystyle \frac{m\, v^2}{r} - m\cdot g = F(\text{normal}) \ge 0\).

\(\displaystyle \frac{m\, v^2}{r} - m\cdot g \ge 0\).

Rearrange and simplify to obtain:

\(\displaystyle \frac{v^2}{r} - g \ge 0\).

\(v^2 \ge g\cdot r\).

\(v \ge \sqrt{g \cdot r}\).

In other words, if the gravitational field strength is \(g\) and the radius of the circle is \(r\), the minimum linear velocity required to keep the content in the pail at the top of the circle is \(\sqrt{g \cdot r}\).

If \(g = 9.81\; \rm N \cdot kg^{-1} = 9.81\; \rm m \cdot s^{-2}\) and \(r = 0.82 \; \rm m + 0.185\; \rm m \approx 1.005\; \rm m\), then the minimum value of \(v\) would be approximately:

\(\sqrt{9.81 \; \rm m \cdot s^{-1} \times 1.005\; \rm m} \approx 3.1\; \rm m \cdot s^{-1}\).

Answer:

the required height is 0.2449 m only

Explanation:

Given the data in the question;

Initial height = 2m

so speed of the puck before hitting the ground will be;

u² = 2gh

Initial speed u_ball = √2gh

u_ball = √( 2 × 9.8 × 2 )

u_ball =  √39.2

u_ball = 6.26 m/s

given that; FOR THE FROZEN PUCK, coefficient of restitution = 0.35 only

R = - (v_ball - v_ground / u_ball - u_ ground)

so

0.35 = - (v_ball - 0 / 6.26 - 0)

0.35 = -v_ball / - 6.26

-v_ball = 0.35 × (- 6.26)

-v_ball = -2.191 m/s

v_ball = 2.191 m/s

to get the height;

v² = 2gh

h = v² / 2g

we substitute

h = (2.191)² / 2×9.8

h = 4.800481 / 19.6

h = 0.2449 m

Therefore, the required height is 0.2449 m only

Since the acceleration is constant this is a uniform accelerated motion.

We know that the acceleration is 3 meters per second per second and that the initial velocity is zero (since it starts at rest).

To find the velocity after 12 seconds we use the formula:

plugging the values given ans solvin for the final velocity we have:

Therefore after 12 seconds the ball has a velocity of 36 m/s.

Now, to find the distance travelled we use the formula:

Plugging the values we know we have that:

Therefore the ball travelled 216 meters.

Answer:

B) One group of scientists had data showing widespread microwave radiation that theorists at another institution needed.

Explanation:

I originally put C and I got it wrong.

One group of scientists had data showing widespread microwave radiation that theorists at another institution needed, this piece of evidence justifies the sharing of information to form a scientific theory, therefore the correct answer is option B.

Scientific claims are statements made in science based on an experiment.

These Scientific claims are backed by experimental data and their true results obtained from scientific investigation and experimentation.

Physics, Chemistry, and Biology are all considered to be forms of pure science. There is no direct application of pure science to everyday life. They are not applicable to businesses or production procedures.

This piece of evidence validates the exchange of knowledge to construct a scientific theory since one group of scientists had data indicating ubiquitous microwave radiation that theorists at another institution needed.

Thus, the correct answer is option B.

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Vehicles need to be serviced for several reasons such as preventing costly repairs and improving fuel economy.

First, regular maintenance can help to prevent costly repairs down the road. Second, maintenance can help to improve fuel economy and emissions. Third, maintenance can help to keep your vehicle safe and reliable.

The servicing requirements for petrol/diesel and electric vehicles differ in a number of ways. Petrol/diesel vehicles require oil changes more frequently than electric vehicles. This is because petrol/diesel engines use oil to lubricate the moving parts, while electric motors do not. Petrol/diesel vehicles also require tune-ups more frequently than electric vehicles.

This is because petrol/diesel engines have more moving parts that need to be synchronized, while electric motors have fewer moving parts.

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Answer:

1) k = 10 [N/m]

2) a-) x = 0.4 [m]

b)  x = 0.075 [m]

Explanation:

To be able to solve this type of problems that include springs we must use Hooke's law, which relates the force to the deformed length of the spring and in the same way to the spring coefficient.

F = k*x

where:

F = force [N] (units of Newtons]

k = spring constant  [N/m]

x = distance = 10 [cm] = 0.1 [m]

Now, the weight is equal to the product of the mass by the gravity

W = m*g = F

where:

m = mass = 100 [g] = 0.1 [kg]

g = gravity acceleration = 10 [m/s²]

F = 0.1*10 = 1 [N]

Now clearing k

k = F/x

k = 1/0.1

k = 10 [N/m]

2)

a ) if the force is 4 [N]

clearing x

x = F/k

x = 4/10

x = 0.4 [m]

m = 75 [g] = 0.075 [kg]

W = m*g = F

F = 0.075*10 = 0.75 [N]

x = .75/10

x = 0.075 [m]

Answer:

uniformly accelerated motion

Explanation:

The motion of the body where the acceleration is constant is known as uniformly accelerated motion. The value of the acceleration does not change with the function of time.

The direction in which the electrons flow is the primary distinction between AC and DC. Whereas electrons continuously change directions in AC, moving ahead then backward, they move smoothly in one direction in DC.

While alternating current regularly changes its direction, direct current constantly flows in one direction. Alternating current in India has a frequency of 50 hertz and undergoes two direction changes every cycle. As a result, 100 times each second, AC reverses direction.

When the current flows in a single, predictable direction, it is called direct current (DC).

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Answer:

~4%

Explanation:

% = |(7.6 - 7.9)|/7.9

= 0.3/7.9 ≈ 0.04 = 4%

The ratio of the rise/run has to be the same in order to have a constant slope (option C).

Slope, in mathematics, is the ratio of the vertical and horizontal changes between two points on a surface or a line.

The slope is zero if the line is horizontal and undefined if it is vertical.

The vertical change between two points is called the rise while the horizontal change is called the run. This means that the slope equals the rise divided by the run.

Therefore, this suggests that the ratio of the rise/run has to be the same in order to have a constant slope.

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The time between when the bat emits the sound and when it hears the echo is 0.05 s

From the question given above, the following data were obtained:

Velocity of sound (v) = 343 m/s

Distance (x) = 8.42 m

We can obtain obtained the time as illustrated below:

v = 2x / t

343 = 2 × 8.42 / t

343 = 16.84 / t

Cross multiply

343 ×  t = 16.84

Divide both side by 343

t = 16.84/343

Thus, the time between  when the bat emits the sound and when it hears the echo is 0.05 s

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Answer:

0.0491

Explanation:

Answer:

yes u can flag football has everything that pad football has so you can enlist on being offensive position but you have to play like you want that position

Explanation:

If the impulse is strong enough and lasts for a sufficient amount of time, the go-kart will eventually come to a stop.

Option A is correct.

impulse is described as the integral of a force, F, over the time interval, t, for which it acts. Since force is a vector quantity, impulse is also a vector quantity.

If the force is insufficient to stop the go-kart entirely, it will slow down but continue to move. The force and duration of the impulse, along with the mass and speed of the go-kart, will all affect how much deceleration occurs.

Given that momentum plus impulse equals zero, the go-kart's change in momentum as a result of the impulse will be equal in amount but will move in the opposite direction of its original momentum.

As a result, the go-kart's final momentum will be zero, suggesting that it has either stopped or is travelling very slowly.

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Answer:

Explanation:

To solve this, we start by using one of the equations of motion. The very first one, in fact

1

V = U + at.

V = 0 + 0.8 * 3.4 = 2.72 m/s.

2.

V = 0 + 0.8 * 4.3 = 3.44 m/s.

3.

d = ½ * 0.8 * 4.3² + 3.44 * 12.9

d = 7.396 + 44.376

d = 51.77 m.

4.

d = 62 - 51.77 = 10.23 m. = Distance

traveled during deceleration.

a = (V² - Vo²) / 2d.

a = (0² - 3.44²) / 20.46

a = -11.8336 / 20.46 = -0.58 m/s²

5.

t = (V - Vo)/a =(0 - 3.44) / -0.58

t = -3.44/-.58 = 5.93 s

= Stop time.

T = 4.3 + 12.9 + 5.93 = 23.13 s. = Total

time the hare was moving.

6.

d = Vo * t + ½ * a * t² = 62 m.

0 + 0.5 * (23.13)² * a = 61

267.5a = 61

a = 61/267.5

a = 0.23 m/s²

It is true that parallel rays of light do not form an image on the focal plane or retina, but refractive properties of cornea and lens in the eye and the objective lens in a telescope make it possible to focus light and form an image, however small, on the retina.

When light rays from distant objects, such as the Sun and the Moon, enter our eyes or telescopes, they are nearly parallel. In this case, image is not formed on the retina of our eye or on telescope's focal plane, as it would be for an object that is close to observer.

The parallel rays of light entering the pupil are refracted by cornea and the lens in such a way that they converge to a point on retina. Size of the image formed on retina depends on distance of object and the shape of lens in eye.

In telescope, parallel rays of light entering the objective lens are refracted in such a way that they converge to point on focal plane, where the image of distant object is formed. The size of the image formed on the focal plane depends on the focal length of the objective lens and the distance of the object.

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Answer:

b

Explanation: