every magnet has two poles which can be separated true or false​

a) The image is attached to this answer

b) The kinetic friction force affects the forward force of the ball.

The force that opposes a rolling ball's motion is called rolling friction. It slows the ball down by acting in the opposite direction to that of the ball's motion. The weight of the ball and the type of the surface are two variables that affect rolling friction.

The force that a surface uses to maintain the weight of an object that is resting on it is known as the normal force. When a ball is rolling, the normal force exerts itself perpendicular to the surface the ball is moving on. It maintains the ball's weight balance and offers the required reaction force for rolling motion.

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Answer:

\(3.5\:\mathrm{m/s^2}\)

Explanation:

Newton's 2nd law is given as \(\Sigma F = ma\).

To find the acceleration in the horizontal direction, you need the horizontal component of the force being applied.

Using trigonometry to find the horizontal component of the force:

\(\cos 45^{\circ}=\frac{x}{5},\\\frac{\sqrt{2}}{{2}}=\frac{x}{5},\\x=\frac{5\sqrt{2}}{2}\)

Use this horizontal component of the force to solve for for the acceleration of the object:

\(\frac{5\sqrt{2}}{2}=1.0\cdot a,\\a=\frac{5\sqrt{2}}{2}\approx \boxed{3.5\:\mathrm{m/s^2}}\)

Answer:

as it 8s based upon to fundamental units distance and Time

Answer: it is constructed in such a way that possible answers can be tested

Explanation:

The statement that describes a characteristic of a question that can be answered through scientific inquiry is it can be answered through making observations. The correct option is B.

The goal of scientific inquiry is to establish answers for this phenomenon by a continuous and creative process of questioning, observing and inferring, experimentation, collecting and organising data, finding evidence, drawing conclusions, and repeating the experiment numerous times.

The following phrases define scientific inquiry:

Therefore, the correct option is B. It can be answered by making observations.

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The question is incomplete. Your most probably complete question is given below:

A. It can be answered by gathering opinions.

B. It can be answered through making observations

C. It must be asked by a person who is a working scientist.

D. It must have a simple “yes or “no” answer

Answer:

my friend give options .............

Answer:

2 m/s

Explanation:

The momentum of the colliding system is conserved . Therefore, the velocity of the ball B with the same mass as A is 0.52 m/s.

Momentum of a body is the ability to bring the applied force makes maximum displacement. it is the product of mass and velocity. For a collision, the sum of initial momentum of the two bodies is equal to the sum of their final momentum.

Thus, u be the initial velocity and v be the final velocity.

Then, m1 u1+ m2 u2 = m1 v1 + m1 v2

m1 =  0.17 kg

u1 = 4 m/s

m2 = 0.17 kg

u2 = 0

Then initial momentum = 0.17 × 4 m/s + 0 = 0.68 kg m/s

v1 = 3.5 m/s

0.68 kg m/s = (0.17 × 3.5 m/s ) +  (0.17 × v2)

then v2 = 0.52 m/s.

Therefore, the velocity of ball B after collision will be 0.52 m/s.

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The velocity time graph would have the velocity used instead of the position in this position time graph.

This is referred to a plot between velocity and time and it helps to show the motion of the object that moves in a straight line.

We should note that the velocity-time graph reveals the speed of an object (and whether it is slowing down or speeding up), while the position-time graph describes the motion of an object over a period of time which is therefore why it was chosen as the correct choice.

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The electric field of magnitude 16 N/C will be at a distance of 6.0 meters from the charged object.

The magnitude of the electric field due to a point charge object follows the inverse square law, which states that the magnitude of the electric field is inversely proportional to the square of the distance from the charged object. Mathematically, this is expressed as:

\(E = k*q/r^2\)

where E is the electric field, k is Coulomb's constant (\(k = 9 x 10^9 N*m^2/C^2\)), q is the charge of the object, and r is the distance from the object.

We can use this formula to find the distance at which the electric field has a magnitude of 16 N/C. Let's call this distance x:

16 = \(k*q/x^2\)

We can rearrange this equation to solve for x:

x = \(\sqrt(k*q/16)\)

To find q, we need another piece of information. We know that the electric field has a magnitude of 9 N/C at a distance of 4.0 m. Using the same formula as before, we can solve for q:

9 = \(k*q/4^2\)

q = \(9*4^2/k\)

Now we can substitute this value for q into the equation for x:

x =\(\sqrt(k*(9*4^2/k)/16)\)

x =\(\sqrt(9*4^2/16)\)

x = \(\sqrt(36)\)

x = 6.0 meters

Therefore, the electric field of magnitude 16 N/C will be at a distance of 6.0 meters from the charged object.

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Answer:

Put some melted plastic over the print and let it harden

Explanation:

I think that's how the police do it

Air blows from one place to another because gases move from high-pressure areas to low-pressure areas

In simple words

it happens because of pressure differences.

Answer:

Gases moving from high-pressure places to low-pressure places. The bigger the difference of pressure the faster the air moves from both. Giving the movement of air we experience.

OR:

The high-pressure air will raise up to the low-pressure air and will come down causing the air will blow from one place to another.

Answer and Explanation:

A well-coated structure is defined as having a coating that meets a certain standard of quality. The answer to this particular question depends on the specific criteria being used to evaluate the coating. This would typically require a coating coverage of 90% or better, if not higher.

However, in general, a well-coated structure would typically refer to a surface that has been thoroughly and evenly covered with a coating material such as paint or varnish. This ensures that the underlying material is protected from environmental factors such as moisture and UV radiation. In addition, a well-coated structure can also improve the overall appearance of the surface, making it more aesthetically pleasing. Regarding the options provided in the question, the answer would depend on the specific criteria being used to evaluate the coating. However, it is safe to say that a well-coated structure would require a high level of coating coverage, with minimal areas left uncovered or with an uneven application. This would typically require a coating coverage of 90% or better, if not higher. Ultimately, the specific answer would depend on the standards and expectations set by the evaluating body.

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A well-coated structure is defined as having a coating that meets a certain standard of quality. The answer to this particular question depends on the specific criteria being used to evaluate the coating. This would typically require a coating coverage of 90% or better, if not higher.

However, in general, a well-coated structure would typically refer to a surface that has been thoroughly and evenly covered with a coating material such as paint or varnish. This ensures that the underlying material is protected from environmental factors such as moisture and UV radiation. In addition, a well-coated structure can also improve the overall appearance of the surface, making it more aesthetically pleasing.

Regarding the options provided in the question, the answer would depend on the specific criteria being used to evaluate the coating. However, it is safe to say that a well-coated structure would require a high level of coating coverage, with minimal areas left uncovered or with an uneven application. This would typically require a coating coverage of 90% or better, if not higher. Ultimately, the specific answer would depend on the standards and expectations set by the evaluating body

n = 1.50. In this case, the index of refraction is 1.50, which demonstrates that the lens is able to refract light in order to form an image.

Let us calculate the focal length of the lens:

F = 1/[(1/r1)+(1/r2)]

F = 1/[(1/3.00 cm)+(1/3.00 cm)]

F = 1.50 cm

Calculate the index of refraction:

n = 1/(1/f - 1/d)

n = 1/(1/1.50 cm - 1/1.98 cm)

n = 1.50

Both of these surfaces cause light rays to bend and converge at a focal point on the other side of the lens. The index of refraction of the lens can be calculated by using the equation n = 1/(1/f - 1/d), where f is the focal length and d is the distance of the image.

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Therefore, the answer is (a) 1292 cm is stick has a shadow when held vertical.

Additionally, since light moves in a straight path from its source to an object, the shadow of the object moves with the light source.

Let's use h centimetres to represent the tree's height. We have the following percentage in the problem:

height of tree/length of its shadow = height of meter stick/length of its shadow

or

h / 4200 = 100 / 325

We can solve this proportion for h:

h = 4200 * 100 / 325 = 1292.31 cm

Rounding to the nearest centimeter, we get:

h ≈ 1292 cm

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Explanation:

Speed is the distance an object travel per unit of time

Answer:

I think it's A

Explanation:

It's definitely not B on edge

The correct option for the given question about Einstein's general

theory of relativity is Option A) Mars, Venus, Uranus, Neptune.

As a Conclusion, we can state that the planets who would cause curvature in space time from the least amount of curvature to the greatest will be in order Mars, Venus, Uranus, Neptune.

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Answer:

The last one

Explanation:

on the exam

Among the following the derived demands are options 1 and 3 only. Because in each case, the demand for one thing is originated  by the demand for another.

The phrase derived demand in economics refers to the demand for a factor of production or intermediate good that results from the demand for another intermediate or final good. In essence, consumer demand for the firm's product determines how much a firm will need.

Additionally, if activity in one area rises, any sector that contributed to the success of the first sector may also experience growth. Here, the school is hiring more teachers because enrollment is increased. Thus, enrolling more teachers satisfies the demand by greater enrollments.

Similarly by recruiting more construction workers the increased demand for new house by people can be solved. However, the second case for filling the attendance is a necessary and not a derived demand.

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The volume of the gas at standard temperature and pressure (STP) is 1,239.2 L.

The given parameters;

The volume of the gas at standard condition is calculated by applying general gas law as shown below;

\(\frac{PV}{T} = \frac{P_1V_1}{T_1} \\\\V = \frac{P_1V_1T}{T_1P} \\\\V = \frac{140 \times 9.5 \times 273}{293 \times 1} \\\\V = 1,239.2 \ L\)

Thus, the volume of the gas at standard temperature and pressure (STP) is 1,239.2 L.

"Your question is not complete, it seems be missing the following information;"

A compressed air tank carried by scuba divers has a volume of 9.5 L and a pressure of 140 atm at 20∘C.

If the gas was instead in a cylinder with a floating, massless, frictionless piston, what would the volume of the gas be (in liters) at STP.

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The object would have traveled a distance of 143 mili-meters in 13 Giga-seconds at a speed of 11 pico-meters per second.

To calculate the distance traveled by an object, we need to multiply the object's speed by the time it has been moving.

Distance = speed x time

Recall that:

pico = 10⁻¹²

Giga = 10⁹

mili = 10⁻³

Information available in the problem:

speed = 11 pico-meters = 11 x 10⁻¹² m

time = 13 Giga-seconds = 13 x 10⁹

Hence,

Distance = 11 x 10⁻¹²  x 13 x 10⁹

               = 143 x 10⁻³ meters

               = 143 mili-meters

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Answer:

238 cm3

Explanation:

You take the formula for volume, V = 2500.0 g/10.5 g/cm3 = 238.095 = 238 cm3. The answer is rounded to 3 significant figures.

Answer:

C , E , A , D , B

Explanation:

We evaluate the accelerations for each case, using the formula: a = (vf - vi) / t

A)  a = (10.3 - 0.5 ) / 1 = 9.8 m/s^2  --> magnitude: 9.8 m/s^2

B)  a = (0 - 20) / 1 = - 20 m/s^2  -->  magnitude : 20 m/s^2

C)  a = (0.02 - 0.004) / 1 = 0.016 m/s^2 -->  magnitude : 0.016  m/s^2

D)  a = (4.3 - 0) / 0.4 = 10.75 m/s^2  -->  magnitude : 10.75 m/s^2

E)  a = (1 - 2) / 8.3 = - 0.12 m/s^2  -->  magnitude: 0.12 m/s^2

Then, comparing magnitudes from least to greatest:

C , E , A , D , B

The order of the magnitude of the acceleration, from least to greatest is:

C < E < A < D < B

In physics, acceleration (a) is the rate at which velocity changes (Δv) with time (t).

We will calculate the acceleration for each scenario using the following expression.

\(a = \frac{v-u}{t}\)

where,

Data

\(a = \frac{10.3m/s-0.50m/s}{1.0s} = 9.8 m/s^{2}\)

Data

\(a = \frac{0m/s-20m/s}{1.0s} = -20 m/s^{2}\\\\|a| = 20 m/s^{2}\)

Data

\(a = \frac{2.0cm/s-0.40cm/s}{0.50s} = 3.2cm/s^{2} \times \frac{1m}{100cm} = 0.032 m/s^{2}\)

Data

\(a = \frac{4.3m/s-0m/s}{0.40s} = 11 m/s^{2}\)

Data

\(a = \frac{1.0m/s-2.0m/s}{8.3s} = -0.12 m/s^{2}\\\\|a| = 0.12 m/s^{2}\)

The order of the magnitude of the acceleration, from least to greatest is:

C < E < A < D < B

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The approximate heat transfer through 1.65 cm of air with a temperature difference of 23.0 °C is approximately 24.4 J/s.

To approximate the heat transfer through the air layer in the double-paned window, we can assume that the glass layers have a negligible impact on the heat flow. The heat transfer can be calculated using Fourier's Law of Heat Conduction, which states that the heat flow (Q) is proportional to the temperature difference (ΔT) and inversely proportional to the thickness (L) and thermal conductivity (k) of the material.

First, we need to calculate the effective thermal conductivity of the air layer due to its thickness and the thermal conductivity ratio between air and glass. Let's denote the thermal conductivity of air as k_air and the thermal conductivity of glass as k_glass. Since glass has a thermal conductivity roughly 36 times greater than air, we have k_glass = 36 * k_air.

Next, we calculate the effective thermal conductivity of the air layer as:

k_eff = (k_air * L_air) / (L_air + k_glass)

Substituting the given values, we have:

k_eff = (k_air * 0.0165 m) / (0.0165 m + 0.005 m) = 0.01309 * k_air

Now, we can calculate the heat flow per second through the air layer using the formula:

Q = (k_eff * A * ΔT) / L_air

Substituting the given values, we get:

Q = (0.01309 * k_air * 0.760 m^2 * 23.0 K) / 0.0165 m = 24.4 J/s

Therefore, the approximate heat transfer through 1.65 cm of air with a temperature difference of 23.0 °C is approximately 24.4 J/s.

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The work-energy theorem states that the change in the kinetic energy of an object will be equal to the net work done on the object.

Mathematically, it can be expressed as;

ΔKE = W

Where; ΔKE represents the change in kinetic energy of the object,

W represents the net work done on the object.

This theorem states that when work is done on an object, it results in a change in its kinetic energy. If work is done on an object, its kinetic energy increases, and if work is done by an object, its kinetic energy decreases.

This theorem is a fundamental principle in physics that relates the concepts of work and energy, and it is often used to analyze the motion and behavior of objects in various physical systems.

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At the end of the Electroweak era, matter and antimatter annihilate each other. Because of a small imbalance in the ratio, the universe is left with only matter.

The baryogenesis process refers to the hypothetical mechanism or mechanisms that generated the observed baryon asymmetry in the universe which refers to the fact that there is much more matter than antimatter

If the universe were perfectly symmetric between matter and antimatter the particles and antiparticles would have annihilated each other completely leaving behind only radiation.

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Answer:

3.38atm

Explanation:

Using data from the steam table we have that

Moles of water vapour = 907.19 / 18

= 50.4 moles

So

p1 = 30 psi = 30 x 0.68 = 2.04 atm

v1 = 4ft³= 113.2 L

Then from

PV= nRT

Then to find T we use

T1 = p1 V1 / n R

= 2.04 x 113.2 / 50.4 x 0.0821

= 55.8 K

Then to find volume two

v2 = 2v1 + v1

So

3 v1 = 339.6 K

The pressure two we use

P2 = n R T2 / V2

= 50.4 x 0.0821 x 277.6 / 339.6

So we have

= 3.38 atm =

Answer:

The correct solution is "\(8.012\times 10^{13} \ per/sec\)".

Explanation:

Given:

Power,

P = 1.00 W

Time,

t = 1 sec

Average energy,

E₀ = 78.0 KeV

Or,

    = \(78.0\times 10^3\times 1.6\times 10^{-19}\)

    = \(124.8\times 10^{-16} \ J\)

As we know,

⇒ \(Power =\frac{Total \ energy}{Time}\)

or,

⇒         \(P=\frac{nE_0}{t}\)

⇒      \(1.00=\frac{n(124.8\times 10^{-16})}{1}\)

⇒          \(n=8.012\times 10^{13} \ per/sec\)  

That Pacific Plate the Northern American Plate are separated from one another by San Andreas Fault. While a Northern American Plate is migrating the southwest and east, it Pacific Plate moves a north west.

A transform fault, the 1,200-kilometer-long the San Andreas fault zone forms a section of the boundary between both the Pacific or North American plates. It links the Mendocino fissure zone or the Cascade subduction junction to the north with the Pacific Plate Rise inside the Gulf of California.

Southwestern North America is home to the San Andreas Fault, a significant Earth's crustal fissure. From the northern end of a Gulf of California across western California in the United States, the fissure trends northwestward for further than 800 miles (1,300 km), heading out to sea into the Pacific Ocean not far from San Francirsco.

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