Example: I am shopping for school supplies at Target and I have $130 extra. I see air pods on sale for
$120. / want to determine if I have enough money to cover the total purchase price, including tax,
before i get to the register. Here's how I would organize the problem in my head (or on paper) to get
an accurate calculation...

Answer:

The student will have 130 dollars in the bank at the end of week 11.

Step-by-step explanation:

Pattern:

The pattern given by this graphic is that:

For each passing week, the student will have $10 more in the bank than at the end of the previous week. So, following this pattern:

At the end of 6 weeks, he will have $80.

At the end of 7 weeks, he will have $90.

At the end of 8 weeks, he will have $100.

At the end of 9 weeks, he will have $110.

At the end of 10 weeks, he will have $120.

At the end of 11 weeks, he will have $130.

The student will have 130 dollars in the bank at the end of week 11.

Answer:

The 3.907 is approximate.

====================================

Explanation:

x = number of hours that elapse

y = f(x) = number of tokens

If we use a graphing tool like a TI84 or GeoGebra, then the approximate solution to -3(2)^(x+1) + 90 = 0 is roughly x = 3.907

At around 3.907 hours is when the number of tokens is y = 0. Therefore, this is the approximate upper limit for the domain. The lower limit is x = 0.

The domain spans from x = 0 to roughly x = 3.907, and we shorten that down to 0 ≤ x ≤ 3.907

------------

Plug in x = 0 to find y = 84. This is the largest value in the range.

The smallest value is y = 0.

The range spans from y = 0 to y = 84, so we get 0 ≤ y ≤ 84

Keep in mind y is the number of tokens. A fractional amount of tokens does not make sense, so we must have y be a whole number 1,2,3,...,83,84.

The x value can be fractional because 3.907 hours for instance is valid.

------------

Extra info:

The money loaned at 9% annual interest was 1500 and the money loaned at 11% annual interest was 19000.

Let the amount of money loaned at 9% be x

the amount of money loaned at 11% be y

According to the question,

Total money loaned = 20,500

Thus the equation formed is,

x + y = 20,500 ------ (i)

Simple interest is calculated by

I = P * r * t

where I is the simple interest

r is the rate of interest

t is the time

Thus, the interest on x = 0.09x

the interest on y = 0.11y

Total interest gained = 2,225

Thus the equation formed is,

0.09x + 0.11y = 2225 -------(ii)

Multiply (i) by 0.09

0.09x + 0.09y = 1845

Subtract the above from (ii)

0.02y = 380

y = 19000

x = 1500

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Step-by-step explanation:

Pick any point on the graph below for a solution:

Answer:

$242.3

Step-by-step explanation:

She earns $17500 per year. Multiply that number by 0.28 to get how much she withholds for taxes and other deductions. Subtract that number from 17500. You get 12600. Since there are 52 weeks in a year, divide 12600 by 52 to get how much she earns each week minus the 28 percent.

The number you get from this is $242.3, which is the net pay of each paycheck.

Answer:

$242.31/wkly

Step-by-step explanation:

$17,500.00 × 28% = $4,900.00

$17,500.00-$4,900 = $12,600.00

$12,600.00 ÷ 52/(weeks in a year) = $242.31 a week

$12,600 ÷ 12/month = $1,050.00

$1,050 ÷ 4/weeks = $262.50

The period of the frequency factor b that is given in the diagram above would be = 0.2 sec.

The frequency of a water wave is defined as the number of times the wave completes a cycle within a given period of time. While the period is the time it takes for the completion of a cycle.

The dot the represents the frequency factor b is the green dot on the wave table. Therefore the period as traced from the graph= 0.2 sec.

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Answer:

The answer is \(\frac{9}{40}\) or 0.225

Answer:

well 5X8= 40 and 9 divided by 40= 4.4444444444444444444444444444444

Step-by-step explanation:

Hope that this has helped you out! :)

Answer:14

Step-by-step explanation: cookies

The data distribution is symmetric or moderately skewed, and the mean is likely close to the median (around 7).

We have,

From the box-and-whisker plots, we can find the shape of the distribution.

The form of the Data Distribution:

The data distribution appears to be somewhat symmetric or moderately skewed.

This conclusion can be made by considering the position of the median, lower quartile, and upper quartile.

The median (7) is located approximately in the center of the box, indicating that the data is somewhat balanced around this value.

Additionally, the lower quartile (5) and upper quartile (11) are equidistant from the median, suggesting a relatively symmetrical distribution.

From the box-and-whisker plots

Location of the Mean in Relation to the Median:

In a symmetric distribution, the mean and median are typically close to each other or approximately equal.

Since the median is given as 7, and we don't have the exact value of the mean, we cannot determine its precise location in relation to the median. However, it is reasonable to assume that the mean is likely to be close to the median (around 7) based on the assumption of a symmetric or moderately skewed distribution.

Thus,

The data distribution is symmetric or moderately skewed, and the mean is likely close to the median (around 7).

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Answer:2

Step-by-step explanation:

you just  do 6 divided by 3 and get 2

Answer:

sorry i don't knowe this, i realy want to help you

Answer:

-3/4 x + 1/2

Step-by-step explanation:

First, you're going to sort by like terms

-1/8 +5/8= 4/8=1/2

+2 1/4 x- 3x= -3/4x

then write out as

-3/4 x + 1/2

Answer:

-3/4x+1/2

Step-by-step explanation:

It’s not solving.  It’s combining like terms.

-3/4x+4/8

-3/4x+1/2

Answer:

$0.20

Step-by-step explanation:

3.95/20 = 0.1975

0.1975 would round up to 0.20

Answer:

$0.1975

Step-by-step explanation:

Do $3.95 divided by 20 so you can find the proportion of 1 ounce

We want to determine the measure of the smaller angle, which is the second angle, the answer is 87 degrees.

What is meant by supplementary angles?

Supplementary angles are two angles whose sum is 180 degrees. In other words, if you add the measure of two supplementary angles together, the result will be 180 degrees.

Since the angles are supplementary, their sum is 180 degrees. Therefore, we can write:

3x + 2x + 25 = 180

Simplifying this equation, we get:

5x + 25 = 180

Subtracting 25 from both sides, we get:

5x = 155

Dividing both sides by 5, we get:

x = 31

So the first angle is:

3x = 3(31) = 93 degrees

And the second angle is:

2x + 25 = 2(31) + 25 = 87 degrees

Since we want to determine the measure of the smaller angle, which is the second angle, the answer is 87 degrees.

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Answer: X=5/8

Step-by-step explanation:

2*x-1/4-(1)>0

Step 1 Simplify: 1/4

(2x-1/4)-1>0

Step 2 Rewrite the whole number in an equivalent fraction:

(Subtract a fraction from a whole)

2x=2x/1=2x*4/4

Adding Fractions that have a common denominator:

2x*4-(1)/4=8x*1/4

The equation at the end of step 2:

(8x-1)/4-1>0

Step 3 Rewrite the whole as an equivalent fraction:

1=1/1=1*4/4

Adding Fractions that have a common denominator:

(8x-1)-(4)/4=8x-5/4

The equation at the End of Step 3:

8x-5/4>0

Step 4:

Multiply both sides by 4 then Divide both sides by 8.

So the answer is

x>5/8

I know it seems a lot but it's just the way I learned it. I hope you understand.

The eccentric phase of plyometric movements can help a new client improve power, agility, speed, balance, coordination, and stability.

The eccentric phase of plyometric movements can be an effective way to help a new client improve their overall performance. When training the eccentric phase, the client will be performing exercises that involve quickly stretching and contracting their muscles. This helps to increase power, agility, speed, balance, coordination, and stability. It also helps to reduce the risk of injury by strengthening the muscles and tendons around the joints. By training the eccentric phase of plyometric movements, the client will be able to improve muscular strength and endurance as well. Proper instruction and form should be explained and emphasized to ensure the client is performing the exercises safely and correctly. The client should also be encouraged to progress gradually as they become more comfortable with the exercises. With proper technique, consistent training, and progression, a new client can benefit greatly from training the eccentric phase of plyometric movements.

The complete question: Training the eccentric phase of plyometric movements with a new client will help them improve which of the following?

Select one:

a. Core stability

b. Power development

c. Landing mechanics

d. Force production

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Complete Question

Newly purchased automobile tires of a certain type are supposed to be filled to a pressure of 30 psi. Let μ denote the true average pressure. Find the P-value associated with each of the following given z statistic values for testing H0: μ = 30 versus Ha: μ 30 when σ is known. (Give the answers to four decimal places.)

calculate for each

(a) z = 2.30

(b) z = -1.7

Answer:

a

\(p-value = 0.021448\)

b

\(p-value = 0.08913\)

Step-by-step explanation:

From the question we are told that

   The population mean is \(\mu = 30 \ psi\)

   The null hypothesis \(H_o : \mu = 30\)

    The alternative hypothesis is  \(H_a : \mu \ne 30\)

Considering question a  

 Here  the test statistics is (a) z = 2.30  

 From the z table  the probability of  (Z >  2.30)  is  

      \(P(Z > 2.30 ) = 0.010724\)

Generally the p-value is mathematically represented as

      \(p-value = 2 * P(Z > 2.30 )\)

=>   \(p-value = 2 * 0.010724\)

=>   \(p-value = 0.021448\)

Considering question b

 Here  the test statistics is (a) z = -1.7

 From the z table  the probability of  (Z <  -1.7)  is  

      \(P(Z < -1.7 ) = 0.044565\)

Generally the p-value is mathematically represented as

      \(p-value = 2 * P(Z < -1.70 )\)

=>   \(p-value = 2 * 0.044565\)

=>   \(p-value = 0.08913\)

The amount natalya will spend constructing the patio with concrete and brick is $4320, the correct option is D.

We are given that;

The concrete portion of the patio cost=$3 per square

To construct and the brick portion of the patio cost= $6 per square

Now,

The area of a rectangle is given by length times width. The concrete portion of the patio is a rectangle with length 6 cm and width 3 cm. Using the scale, we can convert these to feet:

6 cm = 6 x 4 ft = 24 ft 3 cm = 3 x 4 ft = 12 ft

Therefore, the area of the concrete portion is:

24 ft x 12 ft = 288 ft^2

The brick portion of the patio consists of two identical rectangles with lenth 3 cm and width 6 cm. Using the scale, we can convert these to feet:

3 cm = 3 x 4 ft = 12 ft 6 cm = 6 x 4 ft = 24 ft

Therefore, the area of one brick rectangle is:

12 ft x 24 ft = 288 ft^2

Since there are two brick rectangles, the total area of the brick portion is:

2 x 288 ft^2 = 576 ft^2

Now we can multiply the areas by their costs per square foot to get the costs of each portion:

Concrete cost = $3 x 288 ft^2 = $864 Brick cost = $6 x 576 ft^2 = $3456

The total cost of constructing the patio is the sum of the costs of each portion:

Total cost = $864 + $3456 = $4320

Therefore, by area the answer will be $4320.

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Answer:

f(8) would equal 10

Step-by-step explanation:

You just replace the t with the number in the brackets to get your answer.

Answer:

£153

Step-by-step explanation:

If Saji bought a normal ticket for all 19 games, they would have to make 19 payments of £28. So, 28*19 would let us know that he would spend £532 in total. Then it's simply 532-379 to find the answer.

1.Bricks and timber purchased for construction. (Debit: Bricks - Rs 60,000, Debit: Timber - Rs 35,000, Credit: Bank - Rs 95,000)

2.Transfer of Rs 13,000 to fixed deposit account. (Debit: Fixed Deposit - Rs 13,000, Credit: Current Account - Rs 13,000)

3.Appointment of Mr. S.N. Rao as Accountant. (Debit: Salary Expense - Rs 300, Debit: Security Deposit - Rs 1,000, Credit: Accountant - Rs 300)

4.Goods sold to Shruti with discounts. (Debit: Accounts Receivable - Shruti - Rs 80,000, Credit: Sales - Rs 80,000)

5.Goods purchased from Richa with discounts. (Debit: Purchases - Rs 60,000, Credit: Accounts Payable - Richa - Rs 60,000)

6.Goods sold to Shilpa with discounts and received payment. (Debit: Accounts Receivable - Shilpa - Rs 50,000, Credit: Sales - Rs 50,000)

7.Goods sold to Garima with discounts and received partial payment. (Debit: Accounts Receivable - Garima - Rs 1,00,000, Credit: Sales - Rs 1,00,000)

8.Purchase of land with additional charges. (Debit: Land - Rs 2,00,000, Debit: Brokerage Expense - Rs 2,000, Debit: Registration Charges - Rs 15,000, Credit: Bank - Rs 2,17,000)

9.Proprietor took goods and cash for personal use. (Debit: Proprietor's Drawings - Rs 65,000, Credit: Goods - Rs 25,000, Credit: Cash - Rs 40,000)

10.Goods sold to Charu with profit and discount. (Debit: Accounts Receivable - Charu - Rs 1,20,000, Credit: Sales - Rs 1,20,000)

11.Rent paid for the building. (Debit: Rent Expense - Rs 60,000, Credit: Bank - Rs 60,000)

12.Goods sold to Sunil with profit and discount. (Debit: Accounts Receivable - Sunil - Rs 24,000, Credit: Sales - Rs 24,000)

13.Purchased goods from Nanda and supplied to Helen. (Debit: Purchases - Rs 1,000, Debit: Accounts Payable - Nanda - Rs 1,000, Credit: Accounts Receivable - Helen - Rs 1,300, Credit: Sales - Rs 1,300)

14.Purchased goods from Rohit and Sons and supplied to Madan. (Debit: Purchases - Rs 2,700, Credit: Accounts Payable - Rohit and Sons - Rs 2,700, Debit: Accounts Receivable - Madan - Rs 3,000, Credit: Sales - Rs 3,000)

Here are the journal entries for the given transactions:

1. Bricks and timber purchased for construction:

Debit: Bricks (Asset) - Rs 60,000

Debit: Timber (Asset) - Rs 35,000

Credit: Bank (Liability) - Rs 95,000

2. Transfer to fixed deposit account:

Debit: Fixed Deposit (Asset) - Rs 13,000

Credit: Current Account (Asset) - Rs 13,000

3. Appointment of Mr. S.N. Rao as Accountant:

Debit: Salary Expense (Expense) - Rs 300

Debit: Security Deposit (Asset) - Rs 1,000

Credit: Accountant (Liability) - Rs 300

4. Goods sold to Shruti:

Debit: Accounts Receivable - Shruti (Asset) - Rs 80,000

Credit: Sales (Income) - Rs 80,000

5. Goods purchased from Richa:

Debit: Purchases (Expense) - Rs 60,000

Credit: Accounts Payable - Richa (Liability) - Rs 60,000

6. Goods sold to Shilpa:

Debit: Accounts Receivable - Shilpa (Asset) - Rs 50,000

Credit: Sales (Income) - Rs 50,000

7. Goods sold to Garima:

Debit: Accounts Receivable - Garima (Asset) - Rs 1,00,000

Credit: Sales (Income) - Rs 1,00,000

8.Purchase of land:

Debit: Land (Asset) - Rs 2,00,000

Debit: Brokerage Expense (Expense) - Rs 2,000

Debit: Registration Charges (Expense) - Rs 15,000

Credit: Bank (Liability) - Rs 2,17,000

9. Goods and cash taken away by proprietor:

Debit: Proprietor's Drawings (Equity) - Rs 65,000

Credit: Goods (Asset) - Rs 25,000

Credit: Cash (Asset) - Rs 40,000

10. Goods sold to Charu:

Debit: Accounts Receivable - Charu (Asset) - Rs 1,20,000

Credit: Sales (Income) - Rs 1,20,000

Credit: Cost of Goods Sold (Expense) - Rs 80,000

Credit: Profit on Sales (Income) - Rs 40,000

11. Rent paid for the building:

Debit: Rent Expense (Expense) - Rs 60,000

Credit: Bank (Liability) - Rs 60,000

12. Goods sold to Sunil:

Debit: Accounts Receivable - Sunil (Asset) - Rs 24,000

Credit: Sales (Income) - Rs 24,000

Credit: Cost of Goods Sold (Expense) - Rs 20,000

Credit: Profit on Sales (Income) - Rs 4,000

13. Goods purchased from Nanda and supplied to Helen:

Debit: Purchases (Expense) - Rs 1,000

Debit: Accounts Payable - Nanda (Liability) - Rs 1,000

Credit: Accounts Receivable - Helen (Asset) - Rs 1,300

Credit: Sales (Income) - Rs 1,300

14. Goods received from Rohit and Sons and supplied to Madan:

Debit: Purchases (Expense) - Rs 2,700 (after 10% trade discount)

Credit: Accounts Payable - Rohit and Sons (Liability) - Rs 2,700

Debit: Accounts Receivable - Madan (Asset) - Rs 3,000

Credit: Sales (Income) - Rs 3,000

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Answer:

The 4th option, 10g + 24 = t

Step-by-step explanation:

It costs 24 dollars per month no matter what.

$10 * the amount of GB you want

Add those two values to get the total cost per month.

In this case you want 5 GB, so substitute the g in the equation for 5. You will get:

10 * 5 +24 = t

50 + 24 = t

74 = t

So it costs 74 dollars per month to get 5 GB.

Answer:

On what?

Step-by-step explanation:

Answer:

jhshejwjabsgsgshshsnsjs

Answer:

Step-by-step explanation:

Put the equation into center-radius form.

x² + y² + 8x - 12y + 24 = 0

x² + y² + 8x - 12y = -24

(x²+8x) + (y²-12y) = -24

(x²+8x+4²) + (y²-12y+6²) = 4²+6²-24

(x+4)² + (y-6)² = 28

Center: (-4,6)

radius: √28

The value of b in x²+ bx + 16/49 is 8/7 and the squared binomial is (x + 4/7)²

From the question, we have the following parameters that can be used in our computation:

X^2+bx+16/49

Rewrite properly

So, we have the following representation

x²+ bx + 16/49

When represented as a square, we have

x²+ bx + 16/49 = (x + a)²

Expand the bracket

So, we have the following representation

x²+ bx + 16/49 = x² + 2ax + a²

By comparison, we have

bx = 2ax

a² = 16/49

Take the square root of both sides

a = 4/7

Substitute a = 4/7 in bx = 2ax

bx = 2 * 4/7x

So, we have

b = 2 * 4/7

Evaluate

b = 8/7

In (a), we have

x²+ bx + 16/49 = (x + a)²

Where

a = 4/7

So, we have

x²+ bx + 16/49 = (x + 4/7)²

Hence, the binomial is (x + 4/7)²

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Answer:

\(\textsf{1)} \quad b = \dfrac{8}{7}\)

\(\textsf{2)} \quad \left(x+\dfrac{4}{7}\right)^2\)

Step-by-step explanation:

Perfect Square Trinomial

A trinomial that can be written as the square of a binomial.

For example the perfect trinomial  x²+2dx+d² can be written  as (x+d)².

Given trinomial:

\(x^2+bx+\dfrac{16}{49}\)

To express the given trinomial as a perfect square trinomial, determine the value of b.

As the coefficient of the x² term is one, b equals twice the square root of the constant of the trinomial:

\(\implies b = 2 \sqrt{\dfrac{16}{49}}\)

\(\implies b = 2 \cdot \dfrac{4}{7}\)

\(\implies b = \dfrac{8}{7}\)

Therefore, the perfect square trinomial is:

\(x^2+\dfrac{8}{7}x+\dfrac{16}{49}\)

To factor in the form of a squared binomial (x + d)², d is half the value of b:

\(\implies d = \dfrac{1}{2}b\)

\(\implies d = \dfrac{1}{2} \cdot \dfrac{8}{7}\)

\(\implies d=\dfrac{8}{14}\)

\(\implies d=\dfrac{4}{7}\)

Therefore, the perfect square trinomial as a squared binomial is:\(\implies \left(x+\dfrac{4}{7}\right)^2\)

Answer:

A dynamic environment is a business environment that is rapidly changing. In a dynamic market, businesses have to adapt quickly to changes and develop new ideas, products and services to keep up with technology and new trends.

Step-by-step explanation:

Answer:

160 is the total

Step-by-step explanation:

Number of tables with 2 chairs: 20

Number of tables with 4 chairs:  30

40% of the tables have 2 chairs at each table. In total, there are

40  chairs at these tables.

60%  of the tables have 4 chairs at each table. In total, there are  120  chairs at these tables.

Altogether, the restaurant has a total of  160  chairs

if is wrong i'm sorry

Answer:

50.2

Step-by-step explanation:

First we would do parenthesis and then exponents which they aren't

7 x 4=28

then we would do 3 x 4=12

52 divided by 5=10.4

23 + 32=55 - our 3 x 4

55 - 12=43

so 43 - 10.4=32.6-52 divided by 5

32.6 - 10.4 =22.2

And our last step what is 22.2 + 28=50.2

Hope this helps have a great day:)

Answer:

Option 1

Step-by-step explanation:

\(\frac{2x^2 - 7x-4}{x^2 - 5x+4}=\frac{(x-4)(2x+1)}{(x-4)(x-1)}=\frac{2x+1}{x-1}\)

Answer:

m= n² + 6n + 16

Step-by-step explanation:

i hope it helps

Answer:

m= n² + 6n + 16

Step-by-step explanation:

The compound inequality that represents the range for the skull size of Chihuahuas is   47.69 ≤ D ≤ 55.38.

What is inequality?

An inequality in mathematics depicts the connection between two values in an algebraic statement that are not equal. One of the two variables on the two sides of the inequality may be greater than, greater than or equal to, less than, or less than or equal to another value, according to inequality signals.

Given:

15 ≤ 1.04D – 34.6 ≤ 23

So,

15 ≤ 1.04D – 34.6…(1)

1.04D – 34.6 ≤ 23…(2)

The 1st inequality, we have

1.04D – 34.6 ≥ 15

=>  1.04D  ≥ 15 +34.6

=>1.04D  ≥ 49.6

=> D ≥ 49.6/1.04

=> D ≥ 47.69 (On  rounding off to 2 decimal places)

=>  47.69 ≤ D.

As per the 2nd inequality,

we have

1.04D – 34.6 ≤ 23

=>  1.04D ≤ 23+34.6

=> 1.04D ≤ 57.6

=> D ≤ 57.6/1.04

=> D ≤ 55.38 (On  rounding off to 2 decimal places) .

Hence, 47.69 ≤ D ≤ 55.38.

The compound inequality that represents the range for the skull size of Chihuahuas is   47.69 ≤ D ≤ 55.38.

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