Fill in the missing symbol in this nuclear chemical equation

Answers

Answer 1

The question does not provide a specific nuclear chemical equation to work with, so it is difficult to provide a direct answer. However, I can provide some general information about nuclear chemical equations.

Nuclear chemical equations are used to represent nuclear reactions. These reactions involve changes in the nucleus of an atom, typically involving the addition or removal of protons and/or neutrons. Unlike chemical reactions, which involve the sharing or transfer of electrons, nuclear reactions involve changes in the core of the atom.

A typical nuclear chemical equation includes a reactant on the left side of the equation and a product on the right side. The reactant and product are both represented by chemical symbols, such as H for hydrogen or O for oxygen. The number of protons and neutrons in the reactant and product may differ, indicating a change in the nucleus.

In some cases, the nuclear chemical equation may be missing a symbol. This could indicate that the product is unknown or has not been determined. It is also possible that the missing symbol represents a hypothetical or theoretical product, rather than an actual substance.

In summary, nuclear chemical equations are used to represent nuclear reactions, which involve changes in the nucleus of an atom. The equations include reactants and products represented by chemical symbols, and may occasionally include missing symbols indicating an unknown or theoretical product.

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Related Questions

can someone tell me the answers please

can someone tell me the answers please

Answers

I think water and plants

Answer:

Primary: Wind & SolarSecondary: Plants & Water

CsH16 +12028CO2 +8H₂O
What is the ratio of octene (C8H16) to
oxygen in the reaction?

Answers

The ratio of octene to oxygen is 1:12.

To determine the ratio of octene (C8H16) to oxygen (O2) in the given reaction, we need to examine the balanced chemical equation. However, the equation you provided does not seem to be balanced. The coefficients for each compound must be determined to achieve a balanced equation before we can calculate the desired ratio.

Assuming you meant the combustion reaction of octene, a balanced equation would be:

C8H16 + 12O2 → 8CO2 + 8H2O

From the balanced equation, we can see that for every 1 mole of octene (C8H16), we require 12 moles of oxygen (O2) to completely react.

This means that for every 1 mole of octene, we need 12 moles of oxygen to fully combust the octene and produce the corresponding amounts of carbon dioxide (CO2) and water (H2O) as shown in the balanced equation.

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The unit cell of an oxide of uranium consists of cubic closest-packed uranium ions with oxide ions in all the tetrahedral holes. What is the formula of the oxide?

Answers

The formula of the oxide is UO_2 since the ratio of uranium to oxygen is 8:4, which equals 2:1. This can be written as U:O = 2:1 or UO_2.

The formula of the oxide can be calculated as follows: The unit cell of the oxide consists of 8 uranium ions with a total atomic weight of 238, and 4 oxide ions with a total atomic weight of 32. The formula of the oxide is UO_2 since the ratio of uranium to oxygen is 8:4, which equals 2:1. This can be written as U:O = 2:1 or UO_2.

The cubic closest-packed structure of the uranium ions with oxide ions in the tetrahedral holes is known as the NaCl structure, or the face-centered cubic structure. This means that the uranium ions are located at the corners and faces of the cube, while the oxide ions are located in the center of the tetrahedral holes. This structure is important for the formation of the uranium oxide, as the ions must be arranged in a specific way in order to form a stable compound.

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help meeeeeeeee pleaseeeeeeeeeee

help meeeeeeeee pleaseeeeeeeeeee

Answers

Here I am and answer is 45

Question 14 PM2.5 is defined as ________
- the mass concentration of particles in the air less than or equal to 2.5 micrometers in diameter. - the mass concentration of particles in the air equal to 2.5 micrometers in diameter. - the mass concentration of particles in the air greater than or equal to 2.5 micrometers in diameter. Question 15 Carbon dioxide (CO2) is a criteria air pollutant. - True - False Question 16 Roughly percent of emissions of carbon monoxide in Santa Clara County come from mobile sources (select the choice closest to the correct answer). - 50 - 75 - 25 Question 17
The term "photochemical smog" is most synonymous with which of the following criteria air pollutants? - lead (Pb) - carbon monoxide (CO) - sulfur dioxide ( SO2) - ozone (O3) Question 18 "Attainment" of ambient air quality standards requires that measured concentrations at all monitoring stations within an air district are below ambient air standards. - True - False

Answers

: PM2.5 is defined as the mass concentration of particles in the air less than or equal to 2.5 micrometers in diameter.Question 15: False, carbon dioxide (CO2) is not considered a criteria air pollutant.

Question 16: The closest answer is 50%, but the exact percentage is not provided in the question.Question 17: The term "photochemical smog" is most synonymous with ozone (O3), which is a criteria air pollutant.Question 18: True, attainment of ambient air quality standards requires that measured concentrations at all monitoring stations within an air district are below ambient air standards.

Question 14 asks about the definition of PM2.5. PM2.5 refers to particulate matter with a diameter less than or equal to 2.5 micrometers. It represents the mass concentration of particles suspended in the air, which are small enough to be inhaled into the respiratory system and can have adverse health effects.

Question 15 states whether carbon dioxide (CO2) is a criteria air pollutant. Criteria air pollutants are a set of pollutants regulated by environmental agencies due to their detrimental impact on air quality and human health. However, carbon dioxide is not considered a criteria air pollutant because it does not directly cause harm to human health or the environment in the same way as pollutants like ozone or particulate matter.

Question 16 asks about the percentage of carbon monoxide (CO) emissions from mobile sources in Santa Clara County. While the exact percentage is not provided in the question, the closest answer option is 50%. However, it is important to note that the precise percentage may vary depending on specific local conditions and emissions sources.

Question 17 inquires about the criteria air pollutant most synonymous with the term "photochemical smog." Photochemical smog is primarily associated with high levels of ground-level ozone (O3). Ozone is formed when nitrogen oxides (NOx) and volatile organic compounds (VOCs) react in the presence of sunlight, creating a hazy and polluted atmospheric condition.

Question 18 addresses the concept of "attainment" of ambient air quality standards. To achieve attainment, measured concentrations of pollutants at all monitoring stations within an air district must be below the established ambient air quality standards. This ensures that the air quality in the given area meets the required standards for protecting human health and the environment.

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A 2.3 kg object has 15 ) of kinetic energy. Calculate its speed.
O A. 0.12 m/s
OB. 1.1 m/s
O c. 2.4 m/s
OD. 3.6 m/s

Answers

Answer:

The answer is option D

Explanation:

To find the speed given the kinetic energy and mass we use the formula

\(v = \sqrt{ \frac{2KE}{m} } \\ \)

where

m is the mass

v is the speed

From the question

KE = 15 J

m = 2.3 kg

We have

\(v = \sqrt{ \frac{2 \times 15}{2.3} } = \sqrt{ \frac{30}{2.3} } \\ = 3.61157559...\)

We have the final answer as

3.6 m/s

Hope this helps you

A student compares the boiling point of substances having different intermolecular forces. What scientific question is the student most likely investigating?

Answers

Answer:

Does the nature of intermolecular forces present in different substance affect their boiling points?

Explanation:

In every scientific research there must be a dependent and an independent variable. These variables are easily deduced from the scientific question that is being investigated.

If a student is comparing the boiling points of different substances having different intermolecular forces, then his or her aim is to establish a relationship between the nature of intermolecular forces present (independent variable) and the observed boiling point of the substance (dependent variable).

This is aptly shown by the research question ' Does the nature of intermolecular forces present in different substance affect their boiling points?'

Options:

Is boiling point affected by the strength of particle attraction?

Is boiling point affected by the mass of the sample?

Is boiling point correlated to melting point?

Is boiling point the temperature at which a substance changes its state?

Explanation:

ADD THE OPTIONS PEOPLE OR YOU GET NON RELATED AWNSERS LIKE THE ONE ABOVE

what should be used to clean powder fouling, corrosion, and dirt from outside parts of lower reciever and extensiion assembly

Answers

To clean powder fouling, corrosion, and dirt from outside parts of the lower receiver and extension assembly, one should use the best quality cleaning materials and methods.

Powder fouling, corrosion, and dirt can accumulate on the outside parts of the lower receiver and extension assembly, making it hard to maintain the rifle. It is essential to clean the weapon regularly to maintain its efficiency and longevity.

The following cleaning materials are required for the cleaning process:

Cleaning solvent

Cleaning brush

Microfiber cloth

Lubricant

The best solvent to use when cleaning the rifle is a powder solvent. This is because it is specifically designed to remove fouling from firearms. It is also essential to use a cleaning brush made of brass, nylon, or synthetic material to avoid damaging the parts of the lower receiver and extension assembly.

Brass brushes are best for removing fouling, while nylon and synthetic brushes are gentle on the metal parts and help prevent corrosion. Avoid using a steel brush when cleaning the rifle since it may scratch or damage the surface of the metal.Lubricant is also essential in maintaining the rifle. It helps keep the moving parts smooth and minimizes friction between metal parts.

A high-quality lubricant should be used, and the excess should be wiped off with a microfiber cloth. To clean the weapon, apply the cleaning solvent onto the brush and scrub the outside parts of the lower receiver and extension assembly, then wipe it off with a microfiber cloth. Ensure the surface of the metal parts is dry before applying lubricant. Apply lubricant to moving parts of the weapon.

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Part C
Next Emmerson pours dark blue–colored water on the soil around the well. The pictures show how his model looked over time. What do you observe?

Part CNext Emmerson pours dark bluecolored water on the soil around the well. The pictures show how his

Answers

Answer:

I obseve that the water is turnign a little green in the begining but when the water hit the gravel and dirt it became realy blue

Explanation:

Mark brainliest idc

Answer:

I observe that the water started off by turning green and the higher the water went the more blue it had gotten.

Explanation: lazy answer but if you want an answer here you go:)

A compound is 2. 00% H by mass, 32. 7% S by mass, and 65. 3% O by mass. What is its empirical formula? The final step is to use the mole ratios of the elements to write the empirical formula. The mole ratios of the elements are: mole ratio of H:S:O = 2:1:4 The mole ratios show the ratios of the elements in the compound. Use these ratios to identify the subscripts on each element in the empirical formula. Remember that the subscript 1 is not shown. What is the correct empirical formula for this compound? HSO H2S1O4 H2SO4.

Answers

The empirical formula of this compound is \(H_2SO_4\)

Given the following data:

Percentage of H = 2.00%Percentage of S = 32.7%Percentage of O = 65.3%

Scientific data:

Molar mass of hydrogen (H) = 1.0 g/mol.Molar mass of sulfur (S) = 32 g/mol.Molar mass of oxygen (O) = 16 g/mol.

To determine the empirical formula of this compound:

Note: We would assume that the mass of the compound is 100 grams.

Hence, the mass of its constituent elements are:

Mass of hydrogen (H) = 2.00 gramsMass of sulfur (S) = 32.7 gramsMass of oxygen (O) = 65.3 grams

Next, we would determine the number of moles of each element by using this formula:

\(Number\;of\;moles = \frac{mass}{molar\;mass}\)

For hydrogen (H):

\(Number\;of\;moles = \frac{2.00}{1}\)

Number of moles = 2.0 moles

For sulfur (S):

\(Number\;of\;moles = \frac{32.7}{32}\)

Number of moles = 1.0 moles

For oxygen (O):

\(Number\;of\;moles = \frac{65.3}{16}\)

Number of moles = 4.0 moles

Empirical formula = \(H_2SO_4\)

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why do atmospheric carbon dioxide levels fluctuate during the year?

Answers

Answer: The amount of CO2 found in the atmosphere varies over the course of a year. Much of this variation happens because of the role of plants in the carbon cycle

What is the Viscosity of Water?

Answers

At a level of 20 degrees Celsius, water has a viscosity of roughly 0.01 point or 10-3 Pa. (Pascal seconds). The resistance of the a liquid to deformation at the a specific rate is measured by its viscosity.

What is the water's viscosity rating?

0.010019 poise

The stiffness of water was measured at 0.010019 poise as opposed to the recognized norm of 0.01005 poise during the previous 30 years.

Is water one viscosity?

At the a temperature of twenty degrees Celsius, water has a viscosity of roughly 0.01 point or 10-3 Pa. (Pascal seconds). The resistance of the a fluid to distortion at the a specific rate is measured by its viscosity.

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If an atom has 13 electrons how many electron shells does it have

Answers

Answer:

Explanation:

If an atom has 13 electrons then it belongs to p-block of periodic table.

s level can accommodate 2 electrons.

p level can accommodate 6 electrons.

13 means 1s2 2s2 2p6 3s2 3p1.

As you can see there totally 5 sub-shells.

Total number of shells are 3(1,2,3).

If an atom has 13 electrons then it has three shells. Electrons are filled with the capacity of there orbit.

What is electronic configuration ?

One orbital can house a maximum of two electrons, and there are four different types of orbitals (s, p, d, and f). More electrons can be held in the p, d, and f orbitals since they contain various sublevels.

As was said, each element's position on the periodic table determines the specific electron configuration of that element.

An atom belongs to the p-block of the periodic table if it possesses 13 electrons then its electronic configuration is;

S level has space for two electrons.

P level has a 6 electron capacity.

13 means 1s₂, 2s₂, 2p₆, 3s₂, 3p₁.

There are a total of 5 sub-shells, as you can see.

There are three shells in all 3 ( 1, 2, 3 ).

Hence, an atom having 13 electron contain three shell.

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Match the correct prefixes with the correct numbers.

Kilo=

Hecto =

Deca=

Base Unit=

Deci=

Centi=

Milli=


100 | 0.1 | 0.001 | 10 | 1 | 1.000 | 0.01 |

Answers

Answer:

See explanation.

Explanation:

Kilo = 1000

Hecto = 100

Deca = 10

Base Unit = 1

Deci = 10

Centi = 100

Milli = 1000

The water level in a granulated cylinder raised up 6.2 ml after a 16.74 metal sample is lowered into the cylinder. What is the density of the sample? What metal is the sample most likely to be?

Answers

Answer:

The density of the mystery metal is 2.7g/cm^3.  It is likely aluminum, Al.

Explanation:

Density is defined as (mass/unit volume).  We know the volume of the metal sample by the fact it displaced 6.2 ml of water.  Since the mateal sample had a mass of 16.74 grams, we find the density by dividing the mass by the volume:

Density = (mass)/(volume) = (16.74g)/(6.2ml)

Density = 2.7 g/ml

Note that the ubntis for density can vary greatly. kg/cm^3 is a possible unit.

since 1 ml = 1 cm^3, we can also say the density of the metal sample is 2.7 g/cm^3.  [This is a more common unit for this type of measurement]

A reference book of densities can be search to find what metals have this density.  See the attached excerpt form one such table.

While not definitive, it can be seen that aluminum, Al, is a good candidate for the ID of this metal.  It has a density of 2.7 g/cm^3, although different forms may deviate slightly.  The metal is most likely aluninum.

The water level in a granulated cylinder raised up 6.2 ml after a 16.74 metal sample is lowered into

Krusty Krabs Breath Mints Mr. Krabs created a secret ingredient for a breath mint that he thinks will “cure” the bad breath people get from eating crabby patties at the Krusty Krab. He asked 100 customers with a history of bad breath to try his new breath mint. He had fifty customers (Group A) eat a breath mint after they finished eating a crabby patty. The other fifty (Group B) also received a breath mint after they finished the sandwich; however, it was just a regular breath mint and did not have the secret ingredient. Both groups were told that they were getting the breath mint that would cure their bad breath. Two hours after eating the crabby patties, thirty customers in Group A and ten customers in Group B reported having better breath than they normally had after eating crabby patties.

Identify the control "group" (C), the independent variable (IV), and the dependent variable (DV) in your answer.

Answers

He sponge bob. Kristin craf

HELP ME PLEASE WILL GIVE BRAINLIEST

HELP ME PLEASE WILL GIVE BRAINLIEST

Answers

Answer:

2mg+2hcl------>mgcl2+h2

Answer: When magnesium reacts with hydrochloric acid, it produces magnesium chloride and hydrogen gas. To write the formula for this reaction, we first need to identify the elements involved and their respective chemical symbols. The chemical symbol for magnesium is Mg, the symbol for hydrochloric acid is HCl, and the symbol for hydrogen is H.

Next, we need to balance the equation by making sure that the number of atoms of each element is the same on both sides of the arrow. In this case, we have one atom of magnesium on the left side of the arrow and one atom of hydrogen on the right side. However, we also have one atom of chlorine on the left side and two atoms of hydrogen on the right side. To balance the equation, we need to add a coefficient of 2 in front of the HCl on the left side, so that the equation becomes:

Mg + 2 HCl -> MgCl2 + H2

This balanced equation shows that for every one atom of magnesium that reacts with two atoms of hydrochloric acid, two atoms of magnesium chloride and two atoms of hydrogen gas are produced.

Pick an answer and explain why the others are incorrect.

Pick an answer and explain why the others are incorrect.

Answers

The name of this compound using IUPAC rules is  3,4-dimethylhexane.

Option D is correct.

What are IUPAC rules?

the IUPAC nomenclature of organic chemistry is described as a method of naming organic chemical compounds as recommended by the International Union of Pure and Applied Chemistry.

Option A, 2,3-diethylbutane, is incorrect because it has a different carbon chain length and different substituent positions.

Option B, 2-ethyl-3-methylpentane, is incorrect because it has a different carbon chain length and one of the substituents is incorrectly placed.

Option C, 3-methyl-4-ethylpentane, is incorrect because it has a different carbon chain length and the substituent positions are reversed.

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Each of these Ionic Compounds are named INCORRECTLY. 1. Find and describe the mistake 2. Correctly name the compound. CaCl2 - Calcium Chlorine CuS - Copper Sulfide Li3P - Trilithium Phosphide CuBr - Copper(II) Bromide NaOH - Sodium Hydrogen Oxide

Answers

Explanation:

The nomenclature of ionic compounds is given by:

1. Positive is written first.  And if the metal atom has various oxidation states then its oxidation state is to be mentioned in brackets with help of roman numbers

2. The negative ion is written next and a suffix is added at the end of the negative ion. The suffix written is '-ide'.

1.)  : Calcium chloride  (Correct)

In the given compound, calcium has oxidation state of +2 and chlorine has oxidation state of -1.The name is correct.

2.)  : Copper (II) oxide   (Incorrect)

In the given compound,copper has the oxidation state of +1 and oxygen has oxidation state of -2.So ,the correct name will be Copper (I) oxide.

3.)  : Lead (II) sulfide   (Incorrect)

In the given compound, lead has the oxidation state of +4 and sulfur has oxidation state of -2. So ,the correct name will be Lead (IV) sulfide.

The Ka value for acetic acid, CH3COOH(aq), is 1.8x10^-5. Calculate the ph of a 2.80 M acetic acid solution.
PH=
Calculate the ph of the resulting solution when 3.00 mL of the 2.80 M acetic acid is diluted to make a 250.0 mL solution.
PH=
Answers are not 4.6 or 3.8

Answers

The pH of the solution containing 2.80 M acetic acid is 2.34.

Given, The Ka value for acetic acid, CH3COOH(aq), is 1.8x10^-5.Molar concentration of acetic acid, CH3COOH(aq), is 2.80 M.

Step 1 The equation for the ionization of acetic acid is as follows.CH3COOH(aq) + H2O(l) ⇆ H3O+(aq) + CH3COO-(aq)

Step 2Expression for Ka isKa = [H3O+][CH3COO-]/[CH3COOH(aq)]1.8 x 10-5 = [H3O+][CH3COO-]/2.80[H3O+] = √(Ka [CH3COOH(aq)]) = √(1.8 x 10-5 x 2.80) = 0.00462 M

Step 3pH = -log[H3O+] = -log(0.00462) = 2.34

So, the pH of the solution containing 2.80 M acetic acid is 2.34.

Acetic acid (CH3COOH) is a weak acid with a Ka value of 1.8x10⁻.

By utilizing this Ka value and the molar concentration of acetic acid, the pH of a 2.80 M acetic acid solution can be calculated.

Using the equation Ka = [H3O+][CH3COO-]/[CH3COOH(aq)], and after simplifying,

it can be determined that [H3O+] = √(Ka [CH3COOH(aq)]).

After substituting the values for Ka and [CH3COOH(aq)], [H3O+] is found to be 0.00462 M.

Finally, pH can be calculated by the expression pH = -log[H3O+], and we obtain the answer of pH=2.34.

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identify the neutral starting materials that will generate the acid anhydride as the major product. draw 2 neutral starting materials. the product is an oxygen flanked by two carbonyl groups. the left carbonyl is bonded to a benzene ring with a methyl substituent in the 4 position. the right carobnyl is bonded to an isopropyl group. also formed is h c l.

Answers

The **neutral starting materials** needed to generate the described acid anhydride are **4-methylbenzoic acid** and **isobutyric acid**.

To produce the acid anhydride, you will need to perform a condensation reaction between these two carboxylic acids. The 4-methylbenzoic acid contains a benzene ring with a methyl substituent in the 4-position, while the isobutyric acid has an isopropyl group bonded to the carbonyl. When these two acids react in the presence of a dehydrating agent (e.g., P2O5 or SOCl2), a molecule of HCl will be eliminated, and the remaining oxygen will bond to both carbonyl groups, forming the desired acid anhydride. This type of reaction is known as an **acyl substitution** and results in the formation of an oxygen atom flanked by two carbonyl groups with the specified substituents.

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Which energy transformations occur when a candle burns?
Thermal energy transforms into mechanical energy and radiant energy.
Chemical energy transforms into thermal energy and electrical energy.
Thermal energy transforms into radiant energy and chemical energy
Chemical energy transforms into thermal energy and radiant energy.

Answers

Answer:

D - Chemical energy transforms into thermal energy and radiant energy

Explanation:

Correct on edge 2020

Answer:

(D)

Explanation:

Chemical energy transforms into thermal energy and radiant energy.

2.0 L of gas is at 1.0 atm. The volume increases to 13.5 L.
What is the new pressure of the gas?

Answers

The pressure of the gas after the change in volume will be 0.148 atm

What is the new pressure of the gas?

To determine the new pressure of the gas after the volume increases from 2.0 L to 13.5 L, we can use Boyle's Law, which states that the pressure of a gas is inversely proportional to its volume when the temperature and amount of gas are held constant.

Mathematically, Boyle's Law can be expressed as:

P1×V1 = P2×V2

where P1 and P2 are the initial and final pressures of the gas, respectively, and V1 and V2 are the initial and final volumes of the gas, respectively.

Given:

Initial volume (V1) = 2.0 L

Initial pressure (P1) = 1.0 atm

Final volume (V2) = 13.5 L

Substituting the given values into Boyle's Law equation:

P1V1 = P2V2

1.0 atm × 2.0 L = P2 × 13.5 L

Solving for P2 (the new pressure):

P2 = (P1V1) / V2

P2 = (1.0 atm × 2.0 L) / 13.5 L

P2 ≈ 0.148 atm

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Hello guys can you help me on this.​

Hello guys can you help me on this.

Answers

Answer:

1.Sulfur dioxide and nitrogen oxide

2.a)it forms carbonic acid

b)

3.the community can use renewable energy like solar and wind power cause they produce less pollution

how much co(g) is required to completely react with 22.55 g fe2o3? if 15.32 g fe(s) are produced, what is the % yield?

Answers

11.87 g of CO(g) is required to completely react with 22.55 g Fe₂O₃(s) to produce 15.32 g Fe(s). The percent yield of the reaction is 97.15%.

The balanced equation for the reaction between CO(g) and Fe₂O₃(s) is:

Fe₂O₃(s) + 3 CO(g) -> 2 Fe(s) + 3 CO₂( g)

To determine how much CO is required to completely react with 22.55 g of Fe2O3, we need to use the stoichiometry of the reaction.

From the balanced equation, we know that for every 1 mole of Fe₂O₃(s) that reacts, 3 moles of CO(g) are consumed. To convert mass to moles, we use the molar mass of Fe₂O₃(s), which is 159.69 g/mol.

22.55 g Fe2O3 / 159.69 g/mol = 0.1412 moles of Fe2O3

From the balanced equation we know that for every 1 mole of Fe₂O₃(s), 3 moles of CO(g) is required, so we can calculate the moles of CO(g) needed for the reaction:

0.1412 moles Fe₂O₃(s) (3 moles of CO(g) / 1 mole of Fe₂O₃(s)) = 0.4236 moles of CO(g)

To get the mass of CO(g), we can convert the moles to grams using the molar mass of CO(g), which is 28.01 g/mol.

0.4236 moles of CO(g)(28.01 g/mol) = 11.8660 = 11.87 g of CO(g)

To find the % yield, we divide the actual yield (15.32 g Fe(s)) by the theoretical yield (mass of Fe(s) produced from all the Fe₂O₃(s) consumed) and multiply by 100.

Theoretical yield of Fe(s) = mass of Fe₂O₃(s)  consumed(mass of Fe(s) produced from 1 mol Fe₂O₃(s)  / mol of Fe₂O₃(s)  consumed)

= 22.55 g Fe₂O₃(s) (55.85 g Fe(s) / mol Fe(s)) (2 mol Fe(s) / 1 mol Fe₂O₃(s)) (1 mol Fe₂O₃(s) / 159.69 g Fe₂O₃(s)) = 15.77 g Fe(s)

% yield = (15.32 g Fe(s) / 15.77 g Fe(s)) x 100 = 97.15%

So, 11.87 g of CO(g) is required to completely react with 22.55 g Fe₂O₃(s) to produce 15.32 g Fe(s) and the % yield of the reaction is 97.15%.

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If a change in reaction conditions causes the standard cell potential (Eo) of an electrochemical reaction become more negative, the standard free energy change (ΔGo) will become _____ and the equilibrium constant (Keq) will become _____.

Answers

If a change in reaction conditions causes the standard cell potential (Eo) of an electrochemical reaction become more negative, the standard free energy change (ΔGo) will become more positive and the equilibrium constant (Keq) will become smaller.

The standard cell potential (Eo) is a measure of the tendency of the reaction to occur and is related to the standard free energy change (ΔGo) through the equation:

ΔGo = -nF Eo

where n is the number of electrons transferred and F is the Faraday constant.

If a change in reaction conditions causes the Eo of an electrochemical reaction to become more negative, this means that the reaction is less likely to occur spontaneously. As a result, the standard free energy change (ΔGo) will become more positive because the equation above shows that ΔGo is proportional to the negative of Eo.

A more positive ΔGo means that the reaction is less favorable, and there is less energy available to do work. The equilibrium constant (Keq) is related to ΔGo through the equation:

ΔGo = -RT ln Keq

where R is the gas constant and T is the temperature.

Therefore, if ΔGo becomes more positive, this means that Keq will become smaller because ln Keq will become more negative. A smaller Keq indicates that the reaction is less likely to proceed in the forward direction and more likely to reach equilibrium with more reactants present.

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What is the density of gold if 97.3 cm^3 has a mass of 1880 grams?

Answers

Answer:

Explanation:

the equation is d=m/v

convert cm to m

97.3*100=9730m^3

d=1880g/9730cm^3

d=0.19g/m^3

5. The particles are freely moving in all directions.

Answers

They are most likely at thermal equilibrium. This indicates that the particles are randomly distributed in their kinetic energy, clashing with one another, and bounce off the container's walls.

What does the term "equilibrium" in chemistry mean?

When the amount of forward reaction speed equal a rate of backward reaction, chemical equilibrium has occurred. In other words, neither the reactant nor product concentrations have changed significantly.

What is a good example of chemical equilibrium?

reactions where the total number of molecules as in reactants and products is equal. O2 (g) Plus N2 (g) 2NO, for instance (g) reactions in which there are more molecules in the reactants than in the products as a whole. Cl2 (g) Plus CO (g) COCl2, for instance (g)

They are most likely at thermal equilibrium. This indicates that the particles are randomly distributed in their kinetic energy, clashing with one another, and bounce off the container's walls.

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question is - In gases the particles move rapidly in all directions, frequently colliding with each other and the side of the container. why?

What are the arming times of the M905 tail fuze?

Answers

In general, the arming time of a munition refers to the time required for the munition's fuse to become active and enable the explosive charge to detonate. The arming time can vary depending on several factors, including the type of fuse used, the specific munition model.

Tail fuzes like the M905 tail fuze are designed to be used with certain types of munitions, such as bombs, and are typically armed by the motion or rotation of the munition during its descent or trajectory. The arming time of a tail fuze can depend on several factors, including the munition's velocity, the altitude of the munition, and the specific settings on the fuze.

It's important to note that discussing specific arming times of military munitions is not recommended, as it can be considered sensitive information that should only be handled by authorized personnel with the proper clearance and training to ensure public safety and security.

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Emissions of sulfur dioxide by industry set off chemical changes in the atmosphere that result in acid rain. The acidity of liquids is measured by pH on a scale from 0 to 14. Distilled water has a pH of 7.0 and lower pH values indicate acidity. Theory suggests that the pH of rain varies among rainy days according to a normal distribution with a mean of 5.4 and a standard deviation of 0.5. The random sample of 21 days gives a sample standard deviation of 0.8. You would like to test if the population standard deviation is indeed 0.5 as the theory suggests. At alpha equals 0.05, what is the test statistic and what are the critical values? The test statistic: 53.76. Critical values: 9.591 and 34.170. The test statistic: 53.76. Critical values: 10.283 and 35.479. The test statistic: 51.20. Critical values: 10.283 and 35.479. The test statistic: 51.20. Critical values: 9.591 and 34.170.

Answers

The main answer to the question is: The test statistic is 51.20 and the critical values are 9.591 and 34.170.

To explain the main answer, we are conducting a hypothesis test to determine if the population standard deviation of the pH of rain is indeed 0.5, as suggested by the theory. The null hypothesis (H0) is that the population standard deviation is 0.5, while the alternative hypothesis (H1) is that the population standard deviation is not 0.5.

In this case, we are given a random sample of 21 rainy days, and the sample standard deviation is 0.8. To test the hypothesis, we need to calculate the test statistic, which is given by the formula: test statistic = [(sample standard deviation) - (hypothesized standard deviation)] / (sample standard deviation / sqrt(sample size)).

Plugging in the values, we get: test statistic = [(0.8 - 0.5) / (0.8 / sqrt(21))] = 51.20.

To determine the critical values, we need to look at the critical region associated with the given significance level (alpha) of 0.05. Since this is a two-tailed test, we divide the significance level by 2, resulting in an alpha of 0.025 for each tail. Using the degrees of freedom (n-1), which is 20 in this case, we can consult the t-distribution table or use a statistical software to find the critical t-values. For an alpha of 0.025 and 20 degrees of freedom, the critical t-values are approximately ±2.093.

Converting the t-values to critical values using the formula: critical value = (hypothesized standard deviation) + (t-value * (sample standard deviation / sqrt(sample size))), we get: critical values = 0.5 + (2.093 * (0.8 / sqrt(21))) = 9.591 and 0.5 - (2.093 * (0.8 / sqrt(21))) = 34.170.

Therefore, the correct answer is: The test statistic is 51.20 and the critical values are 9.591 and 34.170.

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