The length of arc CD, given that the radius, EB = 15 cm, is 29.31 cm
How do i determine the length of arc CD?First, we shall determine ∠CED. Details below:
∠BEC = 68°∠CED =?2∠CED + 2∠BEC = 360
2∠CED + (2 × 68) = 360
2∠CED + 136 = 360
Collect like terms
2∠CED = 360 - 136
2∠CED = 224
Divide both sides by 2
∠CED = 224 / 2
∠CED = 112°
Finally, we shall determine the length of the of arc CD. Details below:
Radius (r) = EB = 15 cmAngle (θ) = ∠CED = 112°Length of arc CD = ?Length of arc = 2πr × (θ / 360)
Length of arc CD = (2 × 3.14 × 15) × (112 / 360)
Length of arc CD = 29.31 cm
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autumn sells boxes of pasta for $2 each and jars of sauce for $3 each. autumn needs to make at least $12.but has no more than 8 boxes and cans combined
The system of inequalities of the situation is 2x + 3y ≥ 12 and x + y ≤ 8
How to determine the system of inequalities?From the question, we have the following parameters that can be used in our computation:
Boxes of pasta = $2 each Jars of sauce = $3 each.Earning = at least $12Available boxes and cans = no more than 8 boxes and cans combinedRepresent the boxes with x and the cans with y
So, we have the following representation
Earnings = 2x + 3y
The earning is at least $12
So, we have
2x + 3y ≥ 12
Next, we have
Boxes and cans = x + y
The available boxes and cans is no more than 8 boxes and cans combined
So, we have
x + y ≤ 8
Hence, the system of inequalities is 2x + 3y ≥ 12 and x + y ≤ 8
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Complete question
autumn sells boxes of pasta for $2 each and jars of sauce for $3 each. autumn needs to make at least $12.but has no more than 8 boxes and cans combined
Represent the scenario as a system of inequalities
Suppose you buy five boxes of cereal. In each box is a picture of a famous athlete. 20% of the cereal boxes contain Michael Phelps, 30% Lamar Jackson, and the rest Elena Delle Donne. Estimate the probability that you end up with a complete set of the pictures. a. Explain how you would use randomly generated numbers to model the likelihood that you end up with a complete set of pictures. (2 po
Estimate the probability of obtaining a complete set of pictures, randomly generated numbers can be used to simulate the process of selecting cereal boxes. By repeating this simulation multiple times, we can calculate the proportion of times a complete set is obtained and use it as an estimate of the probability.
To model the likelihood of obtaining a complete set of pictures, we can create a simulation using randomly generated numbers. In this simulation, we repeat the process of selecting cereal boxes multiple times, mimicking the real-world scenario.
For each simulation, we randomly select five cereal boxes and check if they contain a complete set of pictures. We keep track of the number of simulations where a complete set is obtained. By dividing this count by the total number of simulations, we can estimate the probability of ending up with a complete set of pictures.
By running this simulation thousands or even millions of times, we can obtain a more accurate estimate of the probability. The more simulations we run, the closer our estimate will be to the true probability.
This approach allows us to account for the randomness involved in selecting the cereal boxes and provides an estimate of the probability based on the simulated outcomes.
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PLEASE HURRY
If f(x) = 0, what is x?
0 only
-6 only
-2, 1, or 3 only
-6, -2, 1, or 3 only
Answer:
C. -2, 1, 1, and 3 only
Assume that these scores are from a continuous variable. What is the range? Scores: 10, 6, 8, 6, 5
The range of the given scores is 5. This indicates the difference between the highest and lowest score. The scores provided are 10, 6, 8, 6, and 5.
The range is a measure of dispersion that quantifies the spread of values in a dataset. In this case, the highest score is 10, and the lowest score is 5. By subtracting the lowest score from the highest score, we can determine the range.
In this scenario, the range is 5, as 10 - 5 = 5. This means that the scores vary by a maximum of 5 units. The range provides a basic understanding of the spread of the scores, but it does not provide any information about the distribution or individual differences between the other scores in the dataset. It simply reflects the difference between the highest and lowest values.
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The following double line graph represents the heights (in inches) of Lana and Sabrina over a period of seven years. What was Sabrina's height in 2004?
37 inches
42 inches
38 inches
40 inches
Answer:
37
Step-by-step explanation:
Answer:
40 inches
Step-by-step explanation:
Given F(x) below, find F′(x).
F(x)=∫3x23tt−10dt
Provide your answer below:
To find F'(x) from the given function F(x), we need to differentiate the integral with respect to x using the Fundamental Theorem of Calculus. The result will be the derivative of the integrand multiplied by the derivative of the upper limit of integration. In this case, we have:
F(x) = ∫[3t^2 - 10] dt (from 0 to x)
To find F'(x), we differentiate the integrand with respect to t:
d/dt [3t^2 - 10] = 6t
Now, we multiply this by the derivative of the upper limit of integration, which is 1 since it is x:
F'(x) = 6x
Therefore, the derivative of F(x) with respect to x, F'(x), is simply 6x.
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The height of a cylinder whose area of the base in 36 and and whose volume is 189
The height of a cylinder with a 36-square-foot base and a 189-square-foot volume is 6.
The formula for the volume of a cylinder is given by V = \(\pi\)\(r^{2}\)h, where V is the volume, r is the radius of the base, and h is the height of the cylinder.
The area of the base of the cylinder is given by A = \(\pi\)\(r^{2}\), where A is the area of the base, r is the radius of the base.
We are given that the area of the base is 36, so we can write:
\(\pi\)\(r^{2}\)= 36
Solving for r, we get:
\(r^{2}\) = 36/\(\pi\)
r = \(\sqrt{36}/\pi\)
r ≈ 3.02
We are also given that the volume of the cylinder is 189, so we can write:
V = \(\pi\)\(r^{2}\)h = 189
\(\pi 3.02^{2} h\) = 189
h = 189 / \(\pi 3.02^{2}\)
h ≈ 6
Therefore, the height of the cylinder is approximately 6 units.
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Greta, an elderly investor, has a degree of risk aversion of A = 3 when applied to return on wealth over a one-year horizon. She is pondering two portfolios, the S&P 500 and a hedge fund, as well as a number of one-year strategies. (All rates are annual and continuously compounded. ) The S&P 500 risk premium is estimated at 5. 6% per year, with a SD of 20. 6%. The hedge fund risk premium is estimated at 10. 6% with a SD of 35. 6%. The returns on both of these portfolios in any particular year are uncorrelated with its own returns in other years. They are also uncorrelated with the returns of the other portfolio in other years. The hedge fund claims the correlation coefficient between the annual returns on the S&P 500 and the hedge fund in the same year is zero, but Greta is not fully convinced by this claim.
Calculate Greta’s capital allocation using an annual correlation of 0. 3. (Do not round your intermediate calculations. Round your answers to 2 decimal places. )
Greta’s capital allocation is 0.37 for the S& P 500 and whereas for the hedge fund the captial allocation is 0.63. it is done using the Capital Allocation formula.
The calculation was done using the Capital Allocation formula, which is Risk Aversion multiplied by Risk Premium divided by the sum of the squared standard deviations of the two portfolios plus the correlation between the two portfolios multiplied by the standard deviation of portfolio 1 times the standard deviation of portfolio 2.
for S& P 500 : Capital Allocation = Risk Aversion x Risk Premium / (SD^2 + (Correlation x SD1 x SD2)) = 3 x 5.6% / (20.6^2 + (0.3 x 20.6 x 35.6)) = 0.37 .
whereas Hedge Fund: Capital Allocation = Risk Aversion x Risk Premium / (SD^2 + (Correlation x SD1 x SD2)) = 3 x 10.6% / (35.6^2 + (0.3 x 20.6 x 35.6)) = 0.63
The Risk Aversion was given as 3, the Risk Premiums of the S& P 500 and the Hedge Fund were given as 5.6% and 10.6% respectively, and the standard deviations of the S& P 500 and the Hedge Fund were given as 20.6% and 35.6% respectively. The correlation between the two portfolios was given as 0.3. The calculation yielded a capital allocation of 0.37 for the S& P 500 and 0.63 for the Hedge Fund.
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what is the probability a randomly selected manhattan resident spends new years eve at times square given the resident is out of town on new years eve?
The probability that a randomly selected Manhattan resident spends New Year's Eve at Times Square, given that the resident is out of town on New Year's Eve, is 0.
Determine the probability?If the resident is out of town on New Year's Eve, it implies that they are not present in Manhattan during that time. Therefore, it is not possible for them to spend New Year's Eve at Times Square if they are not in town.
Since the resident is out of town, the probability of them being at Times Square on New Year's Eve is zero. Probability is a measure of the likelihood of an event occurring, ranging from 0 (impossible) to 1 (certain). In this case, the event of a resident being at Times Square on New Year's Eve is impossible because they are out of town.
Hence, the probability of a randomly selected Manhattan resident spending New Year's Eve at Times Square, given that they are out of town on New Year's Eve, is 0.
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Can you solve this sum?
If you can show me how to made it step by step.
Step-by-step explanation:
counting numbers means whole numbers.
these divisible rules mean numbers that are divisible by 4 and by 3 and by 5.
4 = 2×2
so, everything that is divisible by 4 is also divisible by 2.
6 = 2×3
everything that is divisible by 2 and by 3 is also divisible by 6. therefore everything that is divisible by 4 and by 3 is also divisible by 6.
5 is a prime number on its own.
so, we are looking for all numbers that are divisible by
3×4×5 = 60
the smallest common multiple of 2, 3, 4, 5 and 6.
formally we get this by the combination of the longest chains of the prime factors :
2 = 2
3 = 3
4 = 2×2
5 = 5
6 = 2×3
the longest chain of 2 is 2×2.
the longest chain of 3 is 3.
the longest chain of 5 is 5.
so, 2×2×3×5 = 60
therefore, our solution is all numbers divisible by 60.
that means all multiples of 60 between 200 and 500.
what is the lowest number for that ?
3×60 = 180 too low
4×60 = 240 ok
what is the highest number ?
8×60 = 480 ok
9×60 = 540 too high
so, we only have
4×60 = 240
5×60 = 300
6×60 = 360
7×60 = 420
8×60 = 480
we have 5 numbers between 200 and 500 that are divisible by all of 2, 3, 4, 5 and 6.
Help please someone please give me the correct answer
I will mark you brainliest for the correct answer!!
This is a test!!!
Answer:
Angle X and W are verticalStep-by-step explanation:
It's wrong statementWhich expression is equivalent to (3^2)^-2
Answer:
1/3^4
1/81
Step-by-step explanation:
(3^2)^-2
We know that a^b^c = a^(b*c)
3 ^(2*-2)
3^-4
We know that a^-b = 1/a^b
1/3^4
1/81
an event that increases the probability that a response will be repeated is called _____.
The term that describes an event that increases the likelihood of a response being repeated is known as reinforcement.
Reinforcement can be defined as any consequence that strengthens or increases the probability of a behavior occurring again in the future. This can include positive reinforcement, which involves adding a desirable consequence after a behavior, or negative reinforcement, which involves removing an aversive consequence after a behavior. Both types of reinforcement have been shown to be effective in increasing the likelihood of a behavior being repeated.
Overall, understanding the concept of reinforcement is essential in the field of psychology, particularly in the areas of behaviorism and behavior modification. By providing positive consequences after desired behaviors, individuals can be motivated to continue engaging in those behaviors, which can lead to long-term positive changes. Reinforcement can also be used to shape new behaviors or replace unwanted behaviors with more desirable ones.
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I need this for hw pleaseeeeeeeee very quick
Answer:
i think students 3
Step-by-step explanation:
if its assumptions are met, the analysis of variance technique is appropriate when ____.
Answer:
comparing the means of three or more groups
Step-by-step explanation:
Consider the multivariable function f\left(x,y,z\right)=\frac{x^3-2.5y^2+\frac{z}{2}}{z\left(x-y\right)}f ( x , y , z ) = x 3 − 2.5 y 2 + z 2 z ( x − y ). Evaluate f\left(2,3,1\right)f ( 2 , 3 , 1 ). Round your answer to two decimal places.
Answer:
\(f\left(2,3,1\right)=\bold{14}\)
Step-by-step explanation:
Given the function:
\(f\left(x,y,z\right)=\frac{x^3-2.5y^2+\frac{z}{2}}{z\left(x-y\right)}\)
To find:
The value of \(f(2, 3, 1)\) = ?
Solution:
\(f(2, 3, 1)\) means the values of \(x, y\ and\ z\) as:
\(x=2\\y=3\\z=1\)
Let us put the given values in the given function and let us solve for it:
\(\Rightarrow f\left(2,3,1\right)=\dfrac{2^3-2.5\times 3^2+\frac{1}{2}}{1\left(2-3\right)}\\\\\Rightarrow f\left(2,3,1\right)=\dfrac{8-2.5\times 9+0.5}{1\left(-1\right)}\\\\\Rightarrow f\left(2,3,1\right)=\dfrac{8-22.5+0.5}{-1}\\\\\Rightarrow f\left(2,3,1\right)=\dfrac{-14}{-1}\\\\\Rightarrow f\left(2,3,1\right)=\bold{14}\)
Therefore, the answer is:
\(f\left(2,3,1\right)=\bold{14}\)
The table below shows Zoey's earnings on the job
How much does she make in 18.2518.25 hours?
Answer:
she is going to make $408.90 in 18.2518.25 hours
Is (x + 6) a possible length of a rectangle if the area is x^2 + x − 30? Use an area model to prove your answer.
Can you use an area model to find the length and width of:
The answer is yes, (x + 6) is a possible length of a rectangle with area x² + x − 30.
To determine whether (x + 6) is a possible length of a rectangle with area x^² + x − 30, we can use an area model to visualize the situation.
First, we need to find the width of the rectangle.
The area of a rectangle is given by the formula A = lw,
where A is the area, l is the length, and w is the width.
We are given that the area is x² + x − 30, so we can set this equal to lw and solve for w:
x² + x − 30 = (x + 6)w
w = (x² + x − 30)/(x + 6)
The length of a rectangle must be greater than or equal to its width, so we need to check whether (x + 6) is greater than or equal to (x² + x − 30)/(x + 6). This simplifies to:
(x + 6) ≥ x² + x − 30
Expanding the left side and simplifying, we get:
x² + 12x + 36 ≥ x² + x − 30
11x ≥ -66
x ≥ -6
Since x must be a positive number (since we are dealing with lengths), we can conclude that (x + 6) is the possible length of the rectangle. Therefore, the answer is yes, (x + 6) is a possible length of a rectangle with an area x² + x − 30.
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The complement of an event A, denoted by AC, within the sample space S, is the event consisting of all outcomes of A that are not in S. (true/false)
False. The complement of an event A, denoted by A', is the event consisting of all outcomes in the sample space S that are not in A.
In probability theory, a sample space S represents the set of all possible outcomes of an experiment or random phenomenon. An event A is a subset of the sample space S, representing a specific outcome or a combination of outcomes of interest.
The complement of event A, denoted by A', includes all the outcomes in the sample space S that are not part of event A. In other words, A' consists of all outcomes that do not satisfy the conditions for event A to occur.
For example, let's consider rolling a fair six-sided die. The sample space S consists of the numbers {1, 2, 3, 4, 5, 6}. Now, let event A be the event of rolling an odd number. In this case, A = {1, 3, 5}, and the complement of A, denoted by A', would be A' = {2, 4, 6}. A' includes all the outcomes that are not odd numbers.
It's important to note that the complement of an event A and the event itself together cover the entire sample space S. In other words, A and A' are mutually exclusive and exhaustive, meaning that any outcome must either be in A or in A'.
So, in summary, the complement of an event A is the set of all outcomes in the sample space S that do not belong to A.
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Convert 330 degrees to radians. Plz help
Answer:
HIHI! The correct answer you're looking for is 11pi/6 =) & I took the test too
Step-by-step explanation:
HURRY PLEASE HELP -2[7 - 3(-8 + 5)]
Answer:
-32
Step-by-step explanation:
Answer:
-32
Step-by-step explanation:
bomdas
What is the probability that the test will fail to decide
is true when in reality =72. 5?
Determined by various factors such as sample size, statistical significance, and the chosen level of confidence. the probability that the test will fail to decide that the true value is 72.5 when it is indeed 72.5.
In order to calculate the probability of a Type II error, one would need to know the specific details of the test being used, such as the sample size, the statistical power of the test, and the chosen level of significance.
In general, the probability of a Type II error increases as the sample size decreases and the level of significance decreases. This means that if the test being used is not sufficiently powered or if the level of confidence is too low, there is a higher probability of failing to detect a true effect.
If the test is not able to accurately determine if the statement is true or not when the actual value is 72.5, then there is a possibility that a Type II error has occurred. The probability of this error depends on the specific details of the test being used and cannot be determined without further information.
The probability of a test failing to decide a certain hypothesis is true, when it is actually true, can be determined using the concept of Type II error or false negative rate. In statistical hypothesis testing, Type II error (β) refers to the probability of failing to reject a false null hypothesis. These factors influence the power of the test, which is the probability of correctly rejecting the null hypothesis when it is false. The power of the test (1 - β) is complementary to the probability of making a Type II error.
In this case, the null hypothesis (H0) could be that the value is not equal to 72.5,
while the alternative hypothesis (H1) states that the value is equal to 72.5.
The probability you are looking for is the Type II error rate when the true value is 72.5.
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which equations are true when k = - 50? Select two correct answers.
1.5 - k/5 = 11.5
-2k + 78 = -22
-4k + 80 = -120
6k - 150 = -150
K/10 -3 = -8
30 POINTS IF YOU ANSWER!!
There are two equations which are true. They are 1.5 - k/5 = 11.5 and K/10 -3 = -8.
Given,
The equations;
1.5 - k/5 = 11.5-2k + 78 = -22-4k + 80 = -1206k - 150 = -150K/10 -3 = -8The value of k = -50
We have to solve the given equations using k as -50 and find the true ones;
Lets check;
1.5 - k/5 = 11.51.5 - (-50/5) = 11.5
1.5 - (-10) = 11.5
1.5 + 10 = 11.5
11.5 = 11.5
This equation is true.
-2k + 78 = -22(-2 x -50) + 78 = -22
100 + 78 = -22
178 ≠ -22
This equation is false
-4k + 80 = -120(-4 x -50) + 80 = -120
200 + 80 = -120
280 ≠ -120
This equation is false
6k - 150 = -150(6 x -50) - 150 = -150
-300 - 150 = -150
-450 ≠ -150
This equation is false
k/10 -3 = -8(-50/10) - 3 = -8
-5 - 3 = -8
-8 = -8
This equation is true.
That is,
There are two equations which are true. They are 1.5 - k/5 = 11.5 and K/10 -3 = -8.
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Consider the following time series data. Week 1 2 3 4 5 6 Value 18 14 15 10 19 15 Using the naïve method (most recent value) as the forecast for the next week, compute the following measures of forecast accuracy.
To compute the measures of forecast accuracy using the naïve method (forecasting the next week's value as the most recent value), we can compare the forecasted values with the actual values and calculate the following measures:
Mean Absolute Error (MAE):
The MAE measures the average absolute difference between the forecasted values and the actual values. It is calculated by summing up the absolute differences and dividing by the number of observations.
Forecasted values: 15, 19, 10, 19, 15
Actual values: 18, 14, 15, 10, 19
Absolute differences: 3, 5, 5, 9, 4
MAE = (3 + 5 + 5 + 9 + 4) / 5
MAE = 26 / 5
MAE = 5.2
Mean Squared Error (MSE):
The MSE measures the average squared difference between the forecasted values and the actual values. It is calculated by summing up the squared differences and dividing by the number of observations.
Squared differences: 9, 25, 25, 81, 16
MSE = (9 + 25 + 25 + 81 + 16) / 5
MSE = 156 / 5
MSE = 31.2
Root Mean Squared Error (RMSE):
The RMSE is the square root of the MSE. It provides a measure of the standard deviation of the forecast errors.
RMSE = sqrt(MSE)
RMSE = sqrt(31.2)
RMSE ≈ 5.58
These measures of forecast accuracy help assess the performance of the naïve method in predicting the next week's value based on the most recent value. The smaller the MAE, MSE, and RMSE, the better the forecast accuracy. In this case, the naïve method results in an MAE of 5.2, MSE of 31.2, and RMSE of approximately 5.58.
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Vanessa received a $12,000 loan from the bank to buy a motorcycle. She will repay the loan to the bank with an $300 monthly payment.
Answer:
40 months
Step-by-step explanation:
It will take Vanessa 40 months or 3 years and 4 months to repay the bank their loan amount(without interest ofc).
Answer:
Time = 42 months
Step-by-step explanation:
\(Monthly \ payment = [rate + \frac{rate}{(1 + rate)^{month}-1}] \times principal\)
Monthly payment = 300
Principal = 12000
\(Rate \% = \frac{300}{12000} \times 100 = \frac{30}{12} = \frac{5}{2} = 2.5\)
Substituting and solving Months = 42 months
Share £400 in a ratio of 3.5
Answer:
£150 and £250
Step-by-step explanation:
When you share something in the ratio a:b the fraction of each to the total is given by a/(a+b) and b/(a+b)
Here the ratio is 3:5
So the fractions of the share are 3/(3+5) = 3/8 and 5/8
So actual amounts are
3/8 x 400 = £150
5/8 x 400 = £250
15 points please explain it to me add the answer and the work since I’m so confused on when to subtract missing lengths where and when
You didn't specify what the question was. However, I am going to assume you are looking for the missing side of the shape.
Let's call the left side "Side A" and the right side "Side B". One is longer than the other side. In this case, Side B is longer than Side A. To find the missing length, you will need to subtract Side A from Side B
Side B - Side A = Missing side
16 - 13 = 3
Therefore, the length of the missing side is 3.
The chart below shows conversion between yards and inches.
Conversion Chart
Yards
Inches
3
108
6
?
8
288
11
396
What is the missing value in the table?
144
180
198
216
step by step explanation :
to converting yard to inches you have to multiply whatever number u are given in yard by 36 to get your figure in inches
o multiply whatever number u are given in yard by 36 to get your figure in inches so we multiply 6 *36 to give us 216
o multiply whatever number u are given in yard by 36 to get your figure in inches so we multiply 6 *36 to give us 216answer:
216
7/2x + 1/2x = 2 1/2 + 9/2x
solve.
Answer:
x = -121
Step-by-step explanation:
(7/2)*x+(1/2)*x = (9/2)*x+121/2 // - (9/2)*x+121/2
(7/2)*x+(1/2)*x-((9/2)*x)-(121/2) = 0
(7/2)*x+(1/2)*x+(-9/2)*x-121/2 = 0
-1/2*x-121/2 = 0 // + 121/2
-1/2*x = 121/2 // : -1/2
x = 121/2/(-1/2)
x = -121
A researcher measured the average daily gains (in kg/day) of 20 beef cattle; typical values were : 1.39, 1.57, 1.44,.... the mean of the data was 1.461 and the sd was 0.178
Express the mean and SD in Ib/day.
Calculate the coefficient of variation when the data are expressed in kg/day and in lb/day
The average daily gain of 20 beef cattle was measured, with typical values ranging from 1.39 kg/day to 1.57 kg/day. The mean of the data was 1.461 kg/day, and the standard deviation (SD) was 0.178 kg/day.
To express the mean and SD in lb/day, we need to convert the values from kg/day to lb/day. Since 1 kg is approximately 2.20462 lb, the mean can be calculated as 1.461 kg/day * 2.20462 lb/kg ≈ 3.22 lb/day. Similarly, the SD can be calculated as 0.178 kg/day * 2.20462 lb/kg ≈ 0.39 lb/day.
Now, to calculate the coefficient of variation (CV), we divide the SD by the mean and multiply by 100 to express it as a percentage. In this case, when the data are expressed in kg/day, the CV is (0.178 kg/day / 1.461 kg/day) * 100 ≈ 12.18%. When the data are expressed in lb/day, the CV is (0.39 lb/day / 3.22 lb/day) * 100 ≈ 12.11%. Thus, the coefficient of variation remains similar regardless of the unit of measurement used.
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