Find L , the magnitude of the angular momentum of the satellite with respect to the center of the planet.
Express your answer in terms of m - mass of satalite,M - mass of planet,G - 6.67*10^-11, and R- radius from center of planet to satalite.
Answers
The angular momentum of the satellite with respect to the center of the planet is given by:
where r is the position vector of the satellite with respect to the center of the planet and p is the momentum of the satellite. Since the gravitational force is the only force acting on the satellite, its momentum is constant and given by:
where m is the mass of the satellite and v is its velocity.
The position vector of the satellite can be expressed as:
where R is the distance from the center of the planet to the satellite and is a unit vector in the direction of the satellite's motion.
Therefore, the angular momentum of the satellite is:
Using the law of gravitation, we can express the velocity of the satellite in terms of the mass of the planet
Solving for v, we get:
Substituting this expression for v into the expression for L, we get:
Therefore, the magnitude of the angular momentum of the satellite with respect to the center of the planet is:
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Related Questions
Two aircraft are flying toward each other at the same speed. They each emit a 800 HZ whine. what speed (km/hr) must each aircraft have an order that pitch they both hear is 2 times the emitted frequency. Hint: the speed of sound is 343m/s
Answers
Each aircraft must be moving at a speed of 85.75 km/hr towards each other to hear a pitch that is 2 times the emitted frequency.
What is frequency ?
Frequency is a physical quantity that describes the number of occurrences of a repeating event per unit of time. It is often measured in Hertz (Hz), which represents the number of cycles or vibrations per second.
In the context of waves, such as sound waves or electromagnetic waves, frequency refers to the number of complete cycles of the wave that occur in one second. A high frequency wave has more cycles per second than a low frequency wave.
Frequency is also an important concept in physics, particularly in the study of oscillations and waves. It is used to describe the behavior of systems that oscillate or vibrate, such as a simple pendulum or a guitar string. In these cases, the frequency of the oscillation is related to the natural frequency of the system, which is determined by its mass, stiffness, and other properties.
When two aircraft are moving towards each other, the sound waves from each aircraft are compressed, leading to a higher pitch than the emitted frequency. The pitch heard by the pilots of the aircraft can be calculated using the following formula:
Pitch heard = Emitted frequency * (Speed of sound + Speed of observer) / (Speed of sound - Speed of source)
Since the two aircraft are flying towards each other at the same speed, we can assume that the speed of one aircraft is x km/hr, and the speed of the other aircraft is also x km/hr. Therefore, the relative speed between the two aircraft is 2x km/hr.
Substituting the values given in the formula, we get:
2 * Emitted frequency = Emitted frequency * (343 + 2x) / (343 - x)
Simplifying this equation, we get:
686 - 2x = 343 + 2x
4x = 343
x = 85.75 km/hr
Therefore, each aircraft must be moving at a speed of 85.75 km/hr towards each other to hear a pitch that is 2 times the emitted frequency.
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The flow rate of blood through the average human aorta, of radius 1.0 cm, is about 90 cm3/s. What is the speed of the blood flow through the aorta?
Answers
The speed of blood flow through the average human aorta is approximately 28.7 cm/s.
What is the speed of the blood flow through the aorta?The speed of blood flow through the average human aorta, which has a radius of 1.0 cm and a flow rate of about 90 cm³/s.
To find the speed, we'll use the formula: Flow rate = Cross-sectional area × Speed
Calculate the cross-sectional area (A) of the aorta using the formula A = πr², where r is the radius of the aorta (1.0 cm).
A = π(1.0 cm)² = π(1) = π cm²
Rearrange the formula to find the speed: Speed = Flow rate / Cross-sectional area
Plug in the values for the flow rate (90 cm³/s) and the cross-sectional area (π cm²) and solve for the speed:
Speed = (90 cm³/s) / (π cm²) ≈ (90 / 3.14) cm/s ≈ 28.7 cm/s
The average human aorta moves blood at a speed of around 28.7 cm/s.
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The blue, hotter stars tend to have shorter lifetimes than the red, cooler stars.
true
false
Answers
Answer:
A. True
Explanation:
edge 2022
The blue, hotter stars tend to have shorter lifetimes than the , cooler stars; this is a true fact as the lifespan of a star is determined by its mass. Blue, hotter stars have higher masses than red, cooler stars.
What is the lifespan of a star?The lifespan of a star is largely determined by its mass because a star's mass affects its internal pressure, temperature, and nuclear fusion rate, and more massive stars have stronger gravitational forces, which lead to higher pressures and temperatures in their cores. The rate of nuclear fusion reactions in a star determines how quickly it consumes its fuel, which in turn affects the lifespan of the star. Blue, hotter stars have a higher rate of nuclear fusion reactions and consume their fuel much more quickly than red, cooler stars.
Hence, the blue, hotter stars tend to have shorter lifetimes than the redder, cooler stars.
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In air, a sound wave with a frequency of 196 Hz has a wavelength of about 1.76 meters. What is the wavelength of a wave of the frequency is increased to 784 Hz?
0.44 meters
0.57 meters
0.88 meters
1.76 meters
Also if anyone has the whole test PLEASE help me out!!!
Answers
The wavelength of a wave of the frequency is increased to 784 Hz will be 0.57 metre.
What is wavelength ?The distance between two successive troughs or crests is known as the wavelength. The peak of the wave is the highest point, while the trough is the lowest.
The given data in the problem is;
f₁ is the frequency of a sound wave in case 1 = 196 Hz
\(\lambda\)₁ is the wavelength for the = 1.76 meters.
f₂ is the frequency of a sound wave in case 2 = 784 Hz
\(\lambda_2\) is the wavelength for case 2=?
The speed of the wave for the same medium is same which is given as;
\(\rm v = \lambda_1 f_1 \\\\ \rm v = 1.76 \times 196 \\\\ \rm v =344.96\ m/sec\)
For case 2;
\(\lambda_2 = \frac{v}{f_2} \\\\ \lambda_2 = \frac{344.96}{784} \\\\ \lambda_2=0.44\)
Hence the wavelength of a wave of the frequency is increased to 784 Hz will be 0.57 metre.
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A wire carrying a current of 0.25 A is 0.5 m long. If the wire is perpendicular to a magnetic field of 0.6 T, how much is the magnetic force on the wire
Answers
The magnetic force on a current-carrying wire in a magnetic field can be calculated using the formula F = BIL, where F is the magnetic force, B is the magnetic field, I am the current, and L is the length of the wire. In this case, the wire is perpendicular to the magnetic field, so we can simplify the equation to F = BIL. F = 0.075 N
The magnetic force on the wire carrying a current of 0.25 A and perpendicular to a magnetic field of 0.6 T is 0.075 N. It is important to note that the direction of the magnetic force is perpendicular to both the direction of the current and the direction of the magnetic field. To find the magnetic force on a wire carrying a current in a perpendicular magnetic field, we can use the following formula Magnetic Force (F) = Current (I) × Length of wire (L) × Magnetic Field (B) × sin(θ)
Here, θ is the angle between the current direction and the magnetic field. Since the wire is perpendicular to the magnetic field, the angle θ is 90 degrees. The sine of a 90-degree angle is 1, so sin(θ) = 1. Current (I) = 0.25 A Length of wire (L) = 0.5 m Magnetic Field (B) = 0.6 T Magnetic Force (F) = (0.25 A) × (0.5 m) × (0.6 T) × sin (90°) F = (0.25 A) × (0.5 m) × (0.6 T) × 1 F = 0.075 N The magnetic force on the wire is 0.075 N.
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which part of the picture shows evidence of matter scattering light waves on many diffrent directions
Answers
Answer:
A- The image of the moon on the waters surface is distorted.
Explanation:
On a dry winter day, if you scuff your feet across a carpet, you build up a charge and get a shock when you touch a metal doorknob. In a dark room you can actually see a spark about 2 cm long. Air breaks down at a field strength of 3 × 10^6 N/C. How much charge have you built up? As- sume that just before the spark occurs, all the charge is in your finger, drawn there by in- duction due to the proximity of the doorknob. Approximate your fingertip as a sphere of di- ameter 1.42 cm, and assume that there is an equal amount of charge on the doorknob 2 cm away. Answer in units of C How many electrons does this correspond to? The elemental charge is 1.60218 × 10-19 C.
Answers
The number of electrons that corresponds to the number of charges is 2.71 × 10¹⁰ electrons.
How much charge have you built up?
The breakdown field strength of air is 3 × 10⁶ N/C, and the distance between the fingertip and the doorknob is 2 cm, so the electric field between the two is given by:
E = 3 × 10⁶ N/C
The electric field causes the charge on the fingertip to be drawn towards the doorknob, so we can calculate the charge on the fingertip using the formula:
q = 4π ε_0 x Er²
where;
r is the radius of the fingertip (0.71 cm) and
ε_0 is the permittivity of free space (8.854 × 10^-12 C^2/Nm²).
q = 4 x π x 8.854 × 10⁻¹² x 3 × 10⁶ x 0.71²
q = 2.17 × 10⁻⁸ C
The charge on the doorknob is equal and opposite to the charge on the fingertip, so the total charge on both is calculated as;
Q_total = 2 x 2.17 × 10⁻⁸ C
= 4.34 × 10⁻⁸ C.
The number of electrons is calculated as follows;
number of electrons = q / e
where;
e is the elementary charge (1.60218 × 10⁻¹⁹ C).number of electrons = ( 4.34 × 10⁻⁸ C / 1.60218 × ⁻¹⁹ C )
number of electrons = 2.71 × 10¹⁰ electrons
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A hockey puck, with an initial velocity of 65 km/h [W], ricochets off the boards. After 0.76 s in contact with the boards, its final velocity is 47 km/h [E]. Determine the acceleration of the puck.
Answers
Answer:
a = 40.937 m / s²
Explanation:
For this exercise let's use the relationship between momentum and momentum variation
I = Δp
F t = m v_f - mv₀
F = m (v_f -v₀) / t
let's reduce the magnitudes to the SI system
v_f = 47 km / h (1000m / 1 km) (1h / 3600 s) = 13.056 m / s
v₀ = - 65 km / h = -18.056 m / s
the negative sign is bearing the speed is west
let's calculate
F = m (13.056 + 18.056) / 0.76
F = m 40.937
now we can use Newton's second law
F = m a
m 40.937 = m a
a = 40.937 m / s²
The figure below shows a shooting competition, where air rifles fire soft metal at distant targets
Answers
Answer:
where is the figure?
Explanation:
can someone do this for me please?! Just the answer pls
Answers
Problem 2
Answer: Choice D only
Explanation:
Let's go through the list of possible answers
A) She only would feel a force pulling her toward the chair, hence making her feel heavier, only when the space ship is accelerating faster. In this case, she is moving a constant speed of 0.5c (aka half the speed of light). Despite going this fast, she is moving at a constant speed and therefore not accelerating at this current time. The speed isn't changing. Therefore, she would not feel a force pushing her into the chair. Choice A is off the list.B) This is also off the list as well. The lack of accelerating force means her lungs aren't compressed and breathing should be normal. This is assuming she doesn't have any medical conditions hindering her breathing. We can cross choice B off the list.C) This is similar to choice B. We can cross it off the list.D) The faster you go, the more time dilation will occur. This effectively compresses time and makes it slow down. The more detailed explanation involves relativity which is very complicated. Therefore, choice D is the answer.E) This is false because choice D was mentioned to be true.An electron moves in an electric field. Does it move toward regions of higher potential or lower potential? explain.
Answers
The electric fields is always directed from higher potential to the lower potential.
An electron moves in an electric field. Does it move toward regions of higher potential or lower potential?
The electric fields always aiming from the region of higher potential to the region of lower potential. So the force of electrostatic and the direction of the travel of electrons will be always from lower potential to the region of higher potential.
An electric field is defined as the physical field which covers the electrically charged particles and also they can apply force on all other charged particles.
So we can conclude that the electric fields is always directed from higher potential to the lower potential.
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The kinetic product of a reaction is the product with the _____________ the kinetic product is favored when the temperature is _________
Answers
The kinetic product of a reaction is the product with the lower activation energy and the kinetic product is favored when the temperature is high.
The kinetic product of a reaction is the product with the lower activation energy, meaning it can be formed more quickly. This product is favored when the temperature is high because it allows more molecules to overcome the activation energy barrier and proceed with the reaction.
To understand this concept better, we can look at an example reaction between two isomeric products: 2-butene and 1-butene. When the reaction is carried out at a low temperature, the thermodynamic product (1-butene) is favored because it has a lower energy state and is more stable. However, at a higher temperature, the kinetic product (2-butene) is favored because it can be formed more quickly due to its lower activation energy.
It's important to note that the favored product (kinetic vs thermodynamic) depends on the reaction conditions and may not always be the same.
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The probable question may be:
The kinetic product of a reaction is the product with the _____________ and the kinetic product is favored when the temperature is _________
if this speed were increased by just 9.0 % , how much longer would the jump be? express your answer using two significant figures.
Answers
If the initial speed was 10 m/s, then a 9.0% increase in speed would result in a 19% increase in distance.
What is increase in speed?We can see that the increase in distance is proportional to the square of the initial speed, so even a small increase in speed will result in a significant increase in distance.
\(d = (v^2)/2g\)
where d is the distance traveled during the jump, v is the speed of the object or person during the jump, and g is the acceleration due to gravity.
If the speed is increased by 9.0%, then the new speed will be:
\(v_new = v + 0.09v = 1.09v\)
So the new distance traveled during the jump will be:
\(d_new = (v_new^2)/2g = [(1.09v)^2]/2g = 1.19(v^2)/2g\)
The increase in distance is therefore:
\(d = d_new - d = 1.19(v^2)/2g - (v^2)/2g = 0.19(v^2)/2g\)
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24) an electromagnetic wave has a peak electric field of 3.0 kv/m. what is the intensity of the wave? (c
Answers
The intensity of the wave is 4.5 MW/m².
What is the intensity of the electromagnetic wave?The intensity of an electromagnetic wave can be calculated using the formula I = (E² / 2μ₀c), where I represents the intensity, E is the electric field amplitude, μ₀ is the vacuum permeability, and c is the speed of light in a vacuum.
Given that the peak electric field of the wave is 3.0 kV/m, we need to convert it to volts per meter (V/m) by multiplying by 1000. This gives us an electric field amplitude of 3000 V/m.
Plugging this value into the formula, along with the known values for μ₀ (vacuum permeability, approximately 4π × 10⁻⁷ T·m/A) and c (speed of light in a vacuum, approximately 3 × 10⁸ m/s), we can calculate the intensity.
I = (3000² / (2 × 4π × 10⁻⁷ × 3 × 10⁸)) = 4.5 × 10⁶ W/m², which is equivalent to 4.5 MW/m².
The intensity of the wave is 4.5 MW/m². This indicates the power per unit area carried by the electromagnetic wave.
It represents the amount of energy passing through a given surface area per unit of time.
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The average distance from Earth to the sun is 9.3 × 107 miles. How many kilometers isthis?A) 1.5 × 108 km D) 1.7 × 10-8 kmB) 1.5 × 105 km E) 1.5 × 1011 kmC) 5.6 × 107 km
Answers
The distance from Earth to the sun is approximately 1.5 x 10^8 kilometers.
To convert miles to kilometers, we can use the conversion factor 1 mile = 1.609344 kilometers.
So, to find the distance from Earth to the sun in kilometers, we can multiply the given distance in miles by the conversion factor:
d (km) = 9.3 x 10^7 miles x 1.609344 km/mile
d (km) = 1.496 x 10^8 km
Therefore, the distance from Earth to the sun is approximately 1.5 x 10^8 kilometers.
The closest answer choice is A) 1.5 x 10^8 km, which is the correct answer.
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the spontaneous emission rate for the 21-cm hyperfine line in hydrogen (section 7.5) can be obtained from equation 11.63, except that this is a magnetic dipole transition, not an electric one
p->1/c m=1/c (1|(πe+πp)|0)
where
πe=-e/mese, πp=5.59e/2mp sp
are the magnetic moments of the electron and proton (Equation 7.89), and |0〉, |1〉are the singlet and triplet configurations (Equations 4.175 and 4.176). Because mp ≫ me, the proton contribution is negligible, so
a=w30 e2/3π€0hc5m2e|(1|se|0)|2
Work out |〈1| Se |0〉|2 (use whichever triplet state you like). Put in the actual numbers, to determine the transition rate and the lifetime of the triplet state. Answer: 1.1 × 107 years.
Answers
The spontaneous emission rate for the 21-cm hyperfine line in hydrogen can be determined by considering the magnetic dipole transition. Due to the mass difference between the electron (me) and proton (mp), the proton contribution is negligible. Therefore, we focus on the electron's magnetic moment (πe = -e/me se) and the singlet-triplet configurations.
The transition rate (a) can be expressed as:
a = w30 e²/3πε₀hc⁵m²e |〈1|se|0〉|²
To find |〈1|se|0〉|², we need to choose a triplet state (e.g., |1〉) and use the relevant formulas from Equations 4.175 and 4.176.
After calculating |〈1|se|0〉|², plug in the actual numbers for the fundamental constants (e, ε₀, h, c, and me). Then, compute the transition rate (a) and the lifetime of the triplet state.
Based on the given answer, the lifetime of the triplet state is approximately 1.1 × 10⁷ years.
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which of the following terms describes a machine that converts heat into work?
A. Entropy pump
B. Heat engine
C. Heat pump
D. Entropy engine
Answers
Answer: A
Heat engine
Explanation: just took the test
a negative charge of 2 c and a positive charge of 3 c are separated by a distance of 40m.what is theforce between the two charges?
Answers
Answer: A negative charge of 2 c and a positive charge of 3 c are separated by a distance of 40 m. The force between these two charges are 33750000 N.
Explanation:
Force is an external agent that brings a change into body's state, direction, size or shape etc. It is measured in terms of newtons (N).
We know that
F= 9* 10∧9 Nm∧2 (charge1) (charge 2)/ C∧2 (distance)∧2
F= 9* 10∧9 Nm∧2 (-2 C) (3 C)/ C∧2 (40 m)∧2
F= -54* 10∧9/1600
F=3.375* 10∧7
F= 33750000 N
Therefore, The force between these two charges are 33750000 N.
Please help asap.
6. Gravity is a force that can be changed. T/F
7. The bigger an object is, the smaller the force of gravity. T/F
8. As one object gets closer to another object, the force of gravity will increase. T/F
9. The Sun has a greater gravitational force than Jupiter. T/F
Answers
6. True, because gravity is determined by how much mass a given material has, so the more mass an object has, the stronger its gravitational pull.
7. False, because force of gravity proportional to b.
8. True, force inversely proportional to the distance.
9. True, Greater mass has greater force.
In physics, a force is a power that can change the motion of an item. A force can purpose an object with mass to alternate its pace. Pressure also can be described intuitively as a push or a pull. A force has both value and path, making it a vector quantity.
A pressure is a push or a pull and it affects our each day lives because without force, people might not be capable of open and near stuff or lift up our arms or legs .
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Someone give me 3 paragraphs why professional athletes are getting paid too much (language arts)
Answers
Answer: some may argue that while teacher’s only provide service to a single classroom, superstar athletes are entertaining fans all around the world, enticing people with a feeling of relaxation and excitement. Obviously, what these individuals must not be aware of is the most important man in our nation, the president, who makes critical decisions that affect the entire world every day, only makes $400,000 a year. While President Obama is hard at work reviving the economy, the unproven rookie in the MLB is earning way over that figure. Furthermore, police officers, firefighters, and doctors save lives while risking their own for a fraction of what sports stars make. People in the military leave their families at home to defend and protect the country knowing they may never return. It's truly a pity that none of these true heroes are given the same recognition by society as athletes such as Brett Favre or Michael Jordan are given. While I do understand that making it into the pros is not an easy thing to do, and that it takes a tremendous number of hours of hard work and dedication every day to earn a job in professional sports, these people do nothing more than entertain the general public.
Explanation:
Answer:
Wouldn't it be great to make nearly $111 million a year simply to play a game? Tiger Woods, along with many other professional athletes, certainly think so. But do these athletes really deserve all that money?
In my mind, absolutely not. Professional athletes are making too much money in a society where salaries and wages are traditionally based on the value of one's work. In today's society, one should be paid according to the job’s economic importance and their value to society.
Teaching is one of the most economically important occupations because our future economy relies on the education of its youth, yet teachers are paid astronomically less than the average professional athlete is. In fact, each basket Kobe Bryant scores earns him equivalent to the average classroom teacher’s yearly salary.
However, some may argue that while teacher’s only provide service to a single classroom, superstar athletes are entertaining fans all around the world, enticing people with a feeling of relaxation and excitement.
Obviously, what these individuals must not be aware of is the most important man in our nation, the president, who makes critical decisions that affect the entire world every day, only makes $400,000 a year. While President Obama is hard at work reviving the economy, the unproven rookie in the MLB is earning way over that figure.
Furthermore, police officers, firefighters, and doctors save lives while risking their own for a fraction of what sports stars make. People in the military leave their families at home to defend and protect the country knowing they may never return. It's truly a pity that none of these true heroes are given the same recognition by society as athletes such as Brett Favre or Michael Jordan are given.
While I do understand that making it into the pros is not an easy thing to do, and that it takes a tremendous number of hours of hard work and dedication every day to earn a job in professional sports, these people do nothing more than entertain the general public.
Moreover, in my mind, if these athletes want to continue to be rewarded with the fame and fortune that is unfairly bestowed upon them, they must prove to the world that they are going to be positive role models for future athletes, and those who admire them.
Explanation:
found if off some website lol hope it helps! <3
You are asked to calculate the energy consumption of a supercharging electric vehicle (EV) in kWh as well as the cost in US dollars. The supercharging stations usually require 15 minutes, and their charging capacity varies from 90 kW to 250 kW. For the electricity rate, we know for the first 50 kW, the rate is 12 cents per kWh and after the 50 kW, the rate is 10 cents per kWh.
Answers
The energy consumption of the supercharging EV is 42.5 kWh, and the cost is $6.00.
To calculate the energy consumption and cost of supercharging an electric vehicle (EV), we need to consider the charging capacity of the station, the charging time, and the electricity rates.
Given:
Charging time = 15 minutes
Charging capacity range = 90 kW to 250 kW
Electricity rate for the first 50 kW = $0.12/kWh
Electricity rate after 50 kW = $0.10/kWh
First, we convert the charging time to hours:
Charging time = 15 minutes = 15/60 = 0.25 hours
Next, we calculate the energy consumption (in kWh) based on the charging capacity:
If the charging capacity is within the range of 90 kW to 250 kW, we assume an average charging capacity of (90+250)/2 = 170 kW.
Energy consumption = Charging capacity × Charging time
Energy consumption = 170 kW × 0.25 hours
Energy consumption = 42.5 kWh
To calculate the cost, we need to consider the electricity rates:
For the first 50 kWh, the rate is $0.12/kWh.
After 50 kWh, the rate is $0.10/kWh.
Cost for the first 50 kWh = 50 kWh × $0.12/kWh = $6.00
Cost for the remaining kWh (42.5 kWh - 50 kWh) = (42.5 - 50) kWh × $0.10/kWh = -$0.75 (negative value indicates a credit)
Since the energy consumption is less than 50 kWh, we only need to consider the cost for the first 50 kWh.
Therefore, the energy consumption of the supercharging EV is 42.5 kWh, and the cost is $6.00.
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a series lr circuit contains an emf source of 14 v having no internal resistance, a resistor, a 34 h inductor having no appreciable resistance, and a switch. if the emf across the inductor is 80% of its maximum value 4.0 s after the switch is closed, what is the resistance of the resistor?
Answers
To solve this problem, we can use the equation for the voltage across an inductor in a series LR circuit:
V_L = V_emf (1 - e^(-t/(L/R)))
Where V_L is the voltage across the inductor, V_emf is the emf of the source, t is the time since the switch was closed, L is the inductance, and R is the resistance.
We know that the emf source has no internal resistance, so we can assume that R is equal to the resistance of the resistor in the circuit.
At t = 4.0 s, the voltage across the inductor is 80% of its maximum value. We can use this information to solve for R:
0.8 = 1 - e^(-4.0/(34/R))
e^(-4.0/(34/R)) = 0.2
-4.0/(34/R) = ln(0.2)
R = -4.0/(34*ln(0.2))
R ≈ 22.1 ohms
Therefore, the resistance of the resistor in the series LR circuit is approximately 22.1 ohms.
In a series LR circuit, the time constant (τ) is given by the formula τ = L/R, where L is the inductance (34 H in this case) and R is the resistance of the resistor.
When the EMF across the inductor is 80% of its maximum value, the voltage across the resistor would be the remaining 20% of the total voltage (14 V). Therefore, the voltage across the resistor is 0.2 * 14 V = 2.8 V.
After 4.0 seconds, the inductor has reached 80% of its maximum EMF, so the circuit is 1 - 0.8 = 0.2 or 20% away from its steady-state condition. Using the formula V(t) = V₀ * (1 - e^(-t/τ)), where V(t) is the voltage across the resistor at time t and V₀ is the initial voltage (14 V), we can solve for τ:
2.8 V = 14 V * (1 - e^(-4.0 s / τ))
Divide both sides by 14 V:
0.2 = 1 - e^(-4.0 s / τ)
Subtract 1 and multiply by -1:
0.8 = e^(-4.0 s / τ)
Take the natural logarithm of both sides:
ln(0.8) = -4.0 s / τ
Rearrange to find τ:
τ = -4.0 s / ln(0.8)
Now, using the time constant τ and the formula τ = L/R, we can find the resistance R:
R = L / τ
R = 34 H / (-4.0 s / ln(0.8))
Solve for R:
R ≈ 15.96 Ω
The resistance of the resistor is approximately 15.96 Ω.
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A car accelerates from rest to 32 m/s in four seconds. What is the car’s acceleration?
Answers
Answer:
A)24m B)17.6m
Explanation: Explanation: 1. From t=2 to t=3 ,. First, we'll find the velocity at time 2s. v=u+at =32ms+(−3.2)ms2⋅2s =25.6ms.
A box has a volume of 0.38m² and is 70% filled with iron filling at 25°C. Calculate Lotal mass of the iron filling quantity of heat absorbed (Density of iron = 8x10² kg/m³ Specific heat capacity of iron = 460 Jkg-¼k-1 temperative of iron=1500°c
Answers
The iron filling's mass is equal to 0.38 x 0.7 x 8 x 102 kg.
5,023,360 J of heat are absorbed.
Explain about the law of energy conservation.This question uses the rule of conservation of energy, which states that energy cannot be created or destroyed but can only be transformed from one form to another.
In this instance, the energy is changed from kinetic energy (force) to thermal energy (heat) (motion of the iron particles).
Determine the iron filling's mass in step one.Mass of iron filling is calculated as follows: Volume of box x Fill Ratio x Iron Density
= 0.38m² x 0.7 x 8 x 10²
= 22.08 kg
Calculate how much heat is absorbed in step two.Amount of heat absorbed = Mass of the iron filler x Iron's specific heat capacity x (Temperature of Iron - Temperature of Box)
= 1.500° to 25°C x 22.08 kg x 460 Jkg-14k-1
= 5,023,360 J
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What is an example of the strong nuclear force
Answers
100 times stronger than electromagnetic force. And 10,000 times stronger than the weak force. With radioactive decay, it's a hundred millionss times stronger than gravity.
9. What is the mass of an objectnat is experiencingum.net force of 200/N akd an ageleration of 500
m/s??
10. During a test crash, an air bag inflates to stop a dummy's forward motion. The dummy's mass is 75
kg. If the net force on the dummy is 825 N toward the rear of the car, what is the dummy's
deceleration?
Answers
Explanation:
9.
Given parameters:
Net force on object = 200N
Acceleration = 500m/s²
Unknown:
Mass of the object = ?
Solution:
According to newton's second law of motion, force is the product of mass and acceleration;
force = mass x acceleration
Insert the parameters and solve;
200 = mass x 500
mass = \(\frac{200}{500}\) = 0.4kg
10:
Given parameters:
Mass of dummy = 75kg
Net force on dummy = 825N
Unknown:
Dummy's deceleration = ?
Solution:
Deceleration is the negative form of acceleration;
Force = mass x acceleration
Acceleration = \(\frac{force }{mass}\)
Acceleration = \(\frac{825}{75}\) = 11m/s²
The deceleration is -11m/s²
6CO2 + 6H20 + (energy)
Answers
Answer:6CO2 + 6H20 + (energy) → C6H12O6 + 6O2 Carbon dioxide + water + energy from light produces glucose and oxygen
Explanation:
suppose the suspension system of the average car can be fairly well modeled by an underdamped harmonic oscillator with a natural period of 2 seconds. how far apart should speed bumps be placed so that a car traveling at 10 miles per hour over several bumps will bounce more and more violently with each bump?
Answers
The distance between each speed bump should be approximately 0.00556 miles or 29.3 feet (assuming a standard length of 14 feet for each speed bump).
To ensure that a car traveling at 10 miles per hour over several bumps will bounce more and more violently with each bump, we need to place the speed bumps at regular intervals that coincide with the natural period of the underdamped harmonic oscillator.
The natural period of the oscillator is given as 2 seconds. To convert this to miles per hour, we need to use the formula:
v = d ÷ t
where v is the velocity, d is the distance, and t is the time.
d = v × t
where d is the distance, v is the velocity (10 miles per hour), and t is the time (the natural period of the oscillator, 2 seconds).
Substituting the values, we get:
d = 10 × 2 ÷ 3600
d = 0.00556 miles
To convert 0.00556 miles to feet, we can use the conversion factor
1 mile = 5280 feet:
0.00556 miles × 5280 feet/mile = 29.2848 feet
Therefore, 0.00556 miles is approximately equal to 29.3 feet.
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(figure 1) is a snapshot graph at t = 0 s of two waves on a string approaching each other at 1 m/s.
Answers
Six values of the displacement of the string exist at x = 5.0 m at 1 s from t = 0 s to t = 6 s.
All the numbers existing between two specific integers are called as an interval. Out of these whichever umbers fall between these actual values are termed as range.
Intervals contain real numbers falling between two set numbers.
A snapshot graph at t = 0 s of two waves on a string coming towards one other at time interval of 1 m/s is provided. Then, the values of the string displacement at x = 5.0 m at 1 s from t = 0 s to t = 6 s are,
At t = 0
s,= Y₀= 0 cm
At t =1
s,= Y₁= 0 cm
At t = 2
s,= Y₂= 0 cm
At t =3
s,= Y₃= 0 cm
At t =4
= Y₄= 0 cm
At t = 5 s,
= Y₅=0 cm
At t = 6
s,= Y₆= 0 cm
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The complete question:
(Figure 1) is a snapshot graph at t = 0 s of two waves on a string approaching each other at 1 m/s.
1. List the values of the displacement of the string at x = 5.0 m at 1 s intervals from t = 0 s to t = 6 s.
Which wire has the most total charge carriers flowing past a point in the wire during the specified time interval
Answers
The wire 2 has the most charge flowing in it at the given time interval.
Charge flowing in each wireThe total charge flowing in each wire is calculated using the following equation;
Q = It
where;
I is the currentt is the time of current flowCharge in wire 1The charge flowing in wire 1 is calculated as follows;
Q = 1 x 60 = 60 C
Charge in wire 2The charge flowing in wire 2 is calculated as follows;
Q = 2 x 45 = 90 C
Charge in wire 3The charge flowing in wire 3 is calculated as follows;
Q = 3 x 10 = 30 C
Thus, the wire 2 has the most charge flowing in it at the given time interval.
The complete question is below
The current across three identical current carrying wires is measured during a certain time interval. The reading is reported in the table
Current (A) Time Interval (S)
Wire 1 1 60
Wire 2 2 45
Wire 3 3 10
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