find the dc operating point of the diode in steady-state. use the constant-voltage model with vd,on=800mv.

Answer:

The force exerted by one source object on another target object always creates another force at the target object that pushes back on the source object with the same ... or His third law states that for every action (force) in nature there is an equal and opposite reaction. In other words, if object A exerts a force on object B, then object B also exerts an equal and opposite force on object A.

To solve this problem, we can use the formula for the period of oscillation of a spring-mass system:

T = 2π√(m/k)

where T is the period of oscillation, m is the mass attached to the spring, and k is the spring constant.

We are given that T = 2.4 seconds and k = 100 N/m. Substituting these values into the formula, we get:

2.4 = 2π√(m/100)

Squaring both sides and rearranging, we get:

m = (100/4π²) × (2.4²) = 12.3 kg (rounded to one decimal place)

Therefore, the mass attached to the spring is 12.3 kg.
Hi! I'd be happy to help you with your question. To find the mass attached to the spring, we need to use the formula for the period of a spring-mass system: T = 2π√(m/k), where T is the period (time for one oscillation), m is the mass, and k is the spring constant.

In this case, the spring constant (k) is 100 N/m, and the period (T) is 2.4 seconds. We can rearrange the formula to solve for the mass (m):

m = (T^2 * k) / (4π^2)

Substitute the given values into the formula:

m = (2.4^2 * 100) / (4π^2)
m ≈ (5.76 * 100) / (39.48)
m ≈ 14.61

The mass attached to the spring is approximately 14.61 kg.

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Answer:

because they are underaged and prob dont care and also the gov thinks that the youth cant make a reasonable decision for them selves for sum like that and the media influnces them to by saying whats going on and who supports who

the attraction between a +3 valence cation and a -2 valence anion, whose centres are separated by a distance of 2.8 nm. The attraction between two cations is 1.76×10⁻¹⁰ forces.

given,

number of cations,n₁=3

number of anions,n₂=2

center distance between cation and anion,r=2.8 nm=2.8×10⁻⁹m

write the equation force of attraction:

\(F=\dfrac{kq_1q_2}{r^2}.\)..............(1)

Here,K is coulombs constant ,K=9×10⁹ Nm²/C²,q =n×e ,e is electronic charge,e=1.60×10⁻¹⁹ coulombs. the attraction between a +3 valence cation.

calculate the value of cation charge q₁

q₁=n₁×e

q₁=3×1.60×10⁻¹⁹

calculate the value of cation charge q₂

q₂=n₂×e

q₂=2×1.60×10⁻¹⁹

substitute the values in equation 1

\(F=\frac{(9*10^{9})*(3*1.602*10^{-19}) *(2*1.602*10^{-19} )}{(2.8*10^{-9})^{2} }\)

F=1.76×10⁻¹⁰

The force of attraction between cation is 1.76×10⁻¹⁰.

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Answer:
1.)the surface of the table is set into vibration
2.)the initial vibration was larger
3.)The entire table vibrates

Explanation:hope this helps :3 have a good day xlXCherryColaXlx..(pls mark me brainliest)

Answer:

Explanation:The Hertzsprung-Russell Diagram is a graphical tool that astronomers use to classify stars according to their luminosity, spectral type, color, temperature and evolutionary stage. Stars in the stable phase of hydrogen burning lie along the Main Sequence according to their mass.

hoped this helped

Answer:

read the explanation

Explanation:

My answer to research question one is a car with a higher mass has more inertia than a car with a lower mass. A car with a higher mass needs more force to move than a car with a lower mass. The advantage of a car with greater mass is that it takes less impact when crash happens and has more protection.

The advantage of a race car with large mass is that it will continue moving without stopping once it is already in motion.

The disadvantage of a race car with large mass is that it will be difficult to get it start moving.

The Newton's first law of motion states that, an object in a state of rest or uniform motion in a straight line will continue in that form unless it is acted upon by an external force.

This first law is also known as law of inertia because it depends on mass of the object.

Inertia is reluctance of an object to move or stop moving once it is in motion.

Thus, the advantage of a race car with large mass is that it will continue moving without stopping once it is already in motion.

The disadvantage of a race car with large mass is that it will be difficult to get it start moving.

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Answer:

The final velocity of the train and the moose after collision is approximately 19.51 m/s

Explanation:

The given mass of the moose, m₁ = 250 kg

The velocity of the moose, v₁ = 0

The mass of the oncoming train, m₂ = 10,000 kg

The velocity of the train, v₂ = 20 m/s

The velocity of the moose and the train after collision = v₃

By the principle of conservation of linear momentum, the total initial momentum before the collision = The total final momentum after collision

m₁·v₁ + m₂·v₂ = (m₁ + m₂)·v₃

Therefore, by substitution, we have;

250×0 + 10,000× 20 = (10,000 + 250) × v₃

200,000 = 10,250 × v₃

v₃ = 200,000/10,250 ≈ 19.51 m/s

The final velocity of the train and the moose after collision = v₃ ≈ 19.51 m/s

Answer:

The answer to this question is actually false not true.

Answer:

The experimental scientist

Answer:

by using v = u + at equation we can find "a"

14 = 60 - 2.7a

2.7a = 60 - 14

2.7a = 46

decceleration = 17.03

The force is  1.1 * 10^-32 N

Coulomb's law is a fundamental law in physics that describes the electrostatic interaction between charged particles. It states that the force between two point charges is proportional to the product of their charges and inversely proportional to the square of the distance between them. Mathematically, Coulomb's law can be written as:

F = k * q1 * q2 / r^2

where F is the electrostatic force between the charges q1 and q2, r is the distance between the charges, and k is the Coulomb constant, which is approximately equal to 9 x 10^9 N * m^2 / C^2. The force F is a vector quantity, meaning that it has both magnitude and direction, and is directed along the line joining the two charges.

We have that;

F = Kq1q2/r^2

F = 9 * 10^9 * 1.6*10^ -19 * 3.2*10^ -19/(0.02)^2

F = 1.1 * 10^-32 N

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The velocity of Julianna when she gets to the button of the banister, given that slides with an initial speed of 12 cm/s is 24 cm/s

From the question given above, the following parameters were obtained:

The velocity of the Julianna when she gets to the button can be obtained by using the equation of motion as shown below:

v = u + at

v = 12 + (2 × 6)

Clear bracket

v = 12 + 12

v = 24 cm/s

Thus, from the calculation made above, it is evident that the velocity at the buttom is 24 cm/s

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Answer:

The torque on the pulley, when the system is motionless is approximately 9.81 N·m

Explanation:

The given parameters are;

The mass of the object = 2 kg

The friction between the rope and the pulley = 0

The mass of the rope, \(m_r\) = 0.5 kg

The mass of the pulley, \(m_p\) = 0.01 kg

The radius of the pulley, r = 0.25 m

The torque on the pulley, τ = I·α = F × D

The torque on the pulley, when the system is motionless, τ = F × D

Where;

F = The force acting on the pulley rope = The weight of the mass ≈ 2 kg × 9.81 m/s² = 19.62 N

D = The diameter of the pulley = 2×r = 2 × 0.25 m = 0.5 m

Therefore;

τ = 19.62 N × 0.5 m = 9.81 N·m

The torque on the pulley, when the system is motionless, τ ≈ 9.81 N·m.

Answer:

exothermic change hope it help

Explanation:

it is exothermic change hope it helpful

To find the value of "do," the distance of Rebecca from David (the lens), we can use the lens formula 1/do + 1/di = 1/f.Therefore, the object distance "do" is approximately 35.294 cm when the magnification is -0.40 and the focal length is 60 cm.

Given that the focal length (f) of David's lens is 60 cm and the magnification (m) is -0.40, we can use the relationship between magnification and image distance.Calculating this expression will give you the value of do, the distance of Rebecca from David's lens.The given information does not provide sufficient details to determine the value of "do" accurately. In the context of the question, it seems that "do" refers to the object distance, which represents the distance of Rebecca from the lens.To calculate the object distance "do," we need additional information such as the image distance or the height of the object. Without these details, it is not possible to determine the specific value of "do" in this scenario.If you have any further information or additional details regarding the image distance or object height, please provide them so that I can assist you further.

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The longest possible wavelength for a standing wave on a string is: the length of the string itself

This is because, in order to create a standing wave, two traveling waves must interfere with one another and create a wave pattern that is fixed in space.

As the wavelength of the traveling waves increases, the nodes (points of zero displacements) of the standing wave become closer together. Therefore, if the wavelength is equal to the length of the string, the nodes of the standing wave are located at the two ends of the string and the wave pattern remains stationary.

This means that any longer wavelength traveling wave would not be able to interfere and form a standing wave on the string.

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The fundamental force that is most responsible for beta decay is the weak force. This force is responsible for the transformation of a neutron into a proton, electron, and antineutrino.

During beta decay, a neutron emits a W- boson which then decays into a proton, electron, and antineutrino. This results in the conversion of a neutron into a proton, with the electron and antineutrino carrying away the excess energy and momentum. In nuclear physics and particle physics, the weak interaction, which is also often called the weak force or weak nuclear force, is one of the four known fundamental interactions, with the others being electromagnetism, the strong interaction, and gravitation. The Standard Model of particle physics provides a uniform framework for understanding electromagnetic, weak, and strong interactions. An interaction occurs when two particles (typically, but not necessarily, half-integer spin fermions) exchange integer-spin, force-carrying bosons.

So, The fundamental force that is most responsible for beta decay is the weak force.

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Answer: The heat capacity and the specific heat are related by C=cm or c=C/m. The mass m, specific heat c, change in temperature ΔT, and heat added (or subtracted) Q are related by the equation: Q=mcΔT. Values of specific heat are dependent on the properties and phase of a given substance.

Explanation:

An object is definitely being accelerated when a nonzero net force is acting on it: Option B.

A net force refer to the vector sum of all the forces that are acting on an object or physical body. Thus, a net force is a single force that substitutes the effect of all the forces acting on an object or physical body.

According to Newton's Second Law of Motion, the acceleration of an object is directly proportional to the net force acting on the object and inversely proportional to its mass.

This ultimately implies that, an object is definitely being accelerated when a nonzero net force is acting on it.

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The alpha particles are capable of alternating the mass and atomic numbers in the atoms which is responsible for transmutation. This occurs in nuclear reacting.

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The conclusion are a) You need not bring a wetsuit. b) ~p & ~q c) N/A d)  N/A of the argument

a.
Premise 1: The water is 75 degrees.
Conclusion: You need not bring a wetsuit.

b.
Premise 1: ~(p v q)
Conclusion: ~p & ~q

c.
Premise 1: "Whom best I love I cross; to make my gift, The more delay'd, delighted. Be content;"
Conclusion: N/A

d.
Premise 1: "For nothing worthy proving can be proven, Nor yet disproven"
Premise 2: Therefore, one should be wise and "cleave ever to the sunnier side of doubt"
Conclusion: N/A

Argument (a):

1. The water is 75 degrees.
Conclusion: You do not need to bring a wetsuit.

Argument (b):

1. ~(p v q) is truth-functionally equivalent to ~p & ~q.
Conclusion: They are always true together or false together, no matter what the truth values of p and q are.

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The conclusion are a) You need not bring a wetsuit. b) ~p & ~q c) N/A d)  N/A of the argument

a.
Premise 1: The water is 75 degrees.
Conclusion: You need not bring a wetsuit.

b.
Premise 1: ~(p v q)
Conclusion: ~p & ~q

c.
Premise 1: "Whom best I love I cross; to make my gift, The more delay'd, delighted. Be content;"
Conclusion: N/A

d.
Premise 1: "For nothing worthy proving can be proven, Nor yet disproven"
Premise 2: Therefore, one should be wise and "cleave ever to the sunnier side of doubt"
Conclusion: N/A

Argument (a):

1. The water is 75 degrees.
Conclusion: You do not need to bring a wetsuit.

Argument (b):

1. ~(p v q) is truth-functionally equivalent to ~p & ~q.
Conclusion: They are always true together or false together, no matter what the truth values of p and q are.

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Answer:

Constructive interference is formed when the two waves attain maximum  displacement (crest) or minimum displacement (trough)  at the same time. That is, they are said to be on phase.

Explanation:

Check the image uploaded for the diagram.

The pressure exerted by the dancer;

a. when the dancer is stationary is 200000N/m²

b. if the dancer is jumping up with acceleration 4.41 m/s² is 280000N/m²

Pressure is defined to be the amount of force exerted per area. It is a vector quantity and measured in N/m²

The pressure exerted is expressed as;

P = F/A

The total force of the dancer =

F = m( g+a)

when the dancer is stationary,.a= 0

F = mg

F = 53 × 10 = 530N

Area = 26.5 cm² = 26.5 × 10^-4 = 2.65 × 10^-3

Pressure = 530/0.00265

Pressure = 200,000 N/m²

When the dancer is jumping with a= 4m/s²

F = m(g+a)

F = 53 × 14

F = 742N

Pressure = 742/0.00265

= 280,000N/m²

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The local sidereal time at the observatory located at a longitude of 30° E is approximately 208.75 degrees since Betelgeuse crossed the Greenwich meridian.

To determine the local sidereal time at the given observatory, we need to calculate the time elapsed since Betelgeuse crossed the Greenwich meridian.

First, we convert the right ascension of Betelgeuse from hours and minutes to decimal form. Since 1 hour is equal to 15 degrees of right ascension, and 1 minute is equal to 0.25 degrees, we have:

5 hours 55 minutes = (5 × 15) + (55 × 0.25) = 75 + 13.75 = 88.75 degrees.

Next, we calculate the time difference between Betelgeuse crossing the Greenwich meridian and the current time. Since 1 sidereal hour is equal to 15 degrees of Earth's rotation, and the given time difference is 6.0 sidereal hours, we have:

Time difference = 6.0 × 15 = 90 degrees.

Now, we can calculate the local sidereal time at the observatory by adding the longitude of the observatory (30° E) to the accumulated time difference:

Local sidereal time = 88.75 degrees + 90 degrees + 30 degrees = 208.75 degrees.

Therefore, the local sidereal time at the observatory located at a longitude of 30° E is approximately 208.75 degrees.

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