find the distance (in metres) traveled by a radio wave in 21.5 h.

Answers

Answer 1

A radio wave traveling for 21.5 hours would cover a distance of approximately 461,820,000,000 meters.

The speed of light in a vacuum is approximately 299,792,458 meters per second (m/s). To find the distance traveled by a radio wave in 21.5 hours, we can use the formula:

distance = speed × time

We first need to convert 21.5 hours to seconds:

21.5 hours × 60 minutes/hour × 60 seconds/minute = 77,400 seconds

Then, we can calculate the distance traveled by the radio wave:

distance = speed × time

distance = 299,792,458 m/s × 77,400 s

distance = 23,141,680,807,200 meters

distance ≈ 23.14 × 10^12 meters

distance ≈ 461,820,000,000 meters (rounded to the nearest million)

Therefore, the distance traveled by the radio wave in 21.5 hours is approximately 461,820,000,000 meters.

A radio wave traveling for 21.5 hours would cover a distance of approximately 461,820,000,000 meters.

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Related Questions

Tom goes outside on a 20 C day and knocks two pieces of wood together. If he hears the echo 0.554 seconds later, how far away is the wall?

Answers

The speed of sound in air depends on the temperature, humidity, and pressure of the air. At a temperature of 20°C, the speed of sound in dry air is approximately 343 meters per second.

To find the distance to the wall, we need to first find the time it takes for the sound to travel to the wall and back. Since Tom hears the echo 0.554 seconds later, the sound must have traveled to the wall and back, so the total distance traveled by the sound is twice the distance to the wall.

Let d be the distance to the wall in meters. Then, the time it takes for the sound to travel to the wall and back is:

t = 2d / v

where v is the speed of sound in air.

Substituting v = 343 m/s and t = 0.554 s, we get:

0.554 s = 2d / 343 m/s

Solving for d, we get:

d = (0.554 s) * (343 m/s) / 2

d = 94.8515 meters

Therefore, the wall is approximately 94.9 meters away from Tom.

Which type of graph could be easily converted into a pie chart?
A. Variable plot
B. Scatter plot
C. Bar graph
D. Line graph

Answers

Answer:

D.Linegraph

Explanation:

Linegraph could be easily converted into a pie chart

Answer:

bar graph

Explanation:

the abnormal backward flow of gi contents into the esophagus is called

Answers

The abnormal backward flow of gastrointestinal (GI) contents into the esophagus is known as gastroesophageal reflux (GERD) or acid reflux. It occurs when the lower esophageal sphincter fails to close properly, leading to symptoms such as heartburn and regurgitation.

Gastroesophageal reflux, commonly referred to as GERD or acid reflux, is a condition characterized by the abnormal backward flow of GI contents into the esophagus. The esophagus is a muscular tube that connects the throat to the stomach. Normally, a circular muscle called the lower esophageal sphincter (LES) acts as a barrier, preventing the contents of the stomach from moving back into the esophagus. However, when the LES weakens or relaxes inappropriately, it allows stomach acid, digestive enzymes, and partially digested food to flow back up into the esophagus.

This backward flow of stomach contents can cause various symptoms, including heartburn, which is a burning sensation in the chest or throat. Regurgitation, where partially digested food or acid backs up into the mouth or throat, is another common symptom. Other possible symptoms of GERD include chest pain, difficulty swallowing, hoarseness, chronic cough, and a sour taste in the mouth.

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someone please help​

someone please help

Answers

\(w = F * S\)

\(F = 20\\S = 10\\F * S = 20 * 10 = 200\) Joules <- 1st answer

\(w = F * S\)

\(1234 = F * 100\)

\(F = \frac{1234}{100}\)

\(F = 12.34 N\)  <- 2nd answer

A bus travels 50.0 km/hr for 3.80 hours. The distance traveled will be what?

Answers

190.0 km because 50 times three is 150 and 80% of 50 is 40 so 150+40 is 190

3. Determine the units of the quantity described by the following com-
binations of units:
a. kg (m/s) (1/s)
b. (kg/s) (m/s2)
c. (kg/s) (m/s)
d. (kg/s) (m/s)

Answers

B is the answer!! Hope this helps

Blue jeans (blank) blue light, so that we see them as the color blue.

Answers

Answer:

Blue Jeans (are) blue light,

so that we see them as the color

Please help me
27. A 20 kg object is at rest. A 6 N force pulls to the right on
the object for 10 seconds.
A) Find the impulse on the object.
B) Find the final momentum of the object.
C) What is its final velocity?

Answers

Answer:

a. 60 N*s

b. 60 (kg*m)/s

c. 3 m/s

Explanation:

Givens:

m = 20 kg

v_i = 0 m/s

t = 10 s

F = 6 N

a) Impulse:

I = F*t

I = 6 N*10 s

I = 60 N*s

b) Momentum:

p = v*m

F = m(a)

a = F/m

a = 6 N/20 kg

a = 0.3m/s^2

a = (v_f -v_i)/t

v_f = (0.3 m/s^2)*10 s

v_f = 3.0 m/s

p = 3 m/s*20 kg

p = 60 (kg*m)/s

c. Final velocity

a = (v_f -v_i)/t

v_f = (0.3 m/s^2)*10 s

v_f = 3.0 m/s

The impulse, momentum and final velocity can all be obtained from Newton's second law.

Let us recall that the impulse is obtained as the product of force and time.

Impulse = Force × time

Impulse = 6 N × 10 s = 60 Ns

From Newton's second law of motion;

F.t = mv - mu

Since the object was initially at rest;

F.t = mv

Hence, the final velocity of the object is 60 Kgms-1

The final velocity is obtained from;

F.t = mv

v = F.t/m

v = 6 × 10/20

v = 3 m/s

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3. solve the following with regard to significant figures
a) 5.8 + 0.125
II) 3.9x105-2.5x104

Answers

Answer:

a)5.925

ii)149.5 or383.5

Explanation:

ii)3.9×105-2.5×104

409.5-260

the zero in 260 may or may not be significant since it is after two significant figures thus we have two options

If you double the distance between you and the center of Earth, what happens to the strength of the gravitational field you experience?

Answers

Answer:

The strength of gravity decreases.

An example of that would be if you were in space; you float around because there's no gravity.

Please help me i give 60 point i need help now

Please help me i give 60 point i need help now

Answers

Answer:

How many questions should be answered??

how does she hold a newspaper while reading without using the lens? why?​

Answers

bananas are grrrrrreat

A particle possessing 6.25 ?C of charge and mass 6.55 g is fired at a speed of 459 cm/s through two charged plates of length 34.6 cm, as shown in the figure. If the electric field is constant at 2060 N/C between the two plates* and directed upwards, calculate the distance y in which the charge falls below its intended path.



Which field strength will allow the particle to pass between the plates along a straight path.

Answers

Coulomb's law states that the force of attraction or repulsion between two charged particles is directly proportional to the product of their charges and inversely proportional to the square of the distance between them.

Given, Charge

q = 6.25 × 10⁻⁶ C and mass

m = 6.55 g = 6.55 × 10⁻³ kg

Speed of the particle = v = 459 cm/s = 4.59 m/s

Length of the plates,

d = 34.6 cm = 0.346 m

Electric field strength,

E = 2060 N/C

Mathematically,
F ∝ Q₁Q₂/d²

The force on the charge q due to the electric field E is given by

F = Eq

Distance fallen by the particle is given

by = 1/2 gt²,

where g = acceleration due to gravity = 9.8 m/s²In the vertical direction, force on the charge F = mg

Since the charge falls below its intended path, the vertical component of the electric force is greater than the force due to gravity.

So,

we have

F = Eq = mg ⇒ qE = mg

⇒ y = 1/2 gt² = (qE/m) × (t²/2) = (qE/m) × [2y/g]²/2

⇒ y = [(qE/m) × (y/g)]²

⇒ y = (qE/mg)²/3 [∵ t = 2y/g]

Substituting the given values,

we gety = [(6.25 × 10⁻⁶ C × 2060 N/C) / (6.55 × 10⁻³ kg × 9.8 m/s²)]²/3= (1.233 × 10⁻²)²/3= 1.59 × 10⁻⁴ m = 1.59 × 10⁻² cm

Hence, the particle falls 1.59 × 10⁻² cm below its intended path.

Therefore, a field strength of 1.04 × 10⁴ N/C would allow the particle to pass through the plates along a straight path.

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a capacitor of capacitance c is charged by an emf through a resistance r. the time constant describes how quickly the voltages and currents change while the capacitor charges. which statement about the time constant is true?

Answers

The statement that is true about the time constant is that the product of the resistance R and the capacitance C is equal to the time constant τ of the charging capacitor.

A time constant describes the rate of change of current or voltage in a circuit. When an RC (resistance-capacitance) circuit is charged, the time constant represents the duration required for the capacitor to charge to 63.2% of its maximum charge potential. It also represents the time required for the capacitor to discharge to 36.8 percent of its maximum potential.

The formula for calculating the time constant of an RC circuit is:τ = RC.

Where R is resistance, and C is capacitance.

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why is it important to monitor tofu retargeting segments (pixels)?

Answers

Monitoring tofu retargeting segments is important to analyze campaign effectiveness, optimize ad targeting, and improve conversion rates and ROI.

Firstly, tofu retargeting segments allow advertisers to track and analyze the behavior of potential customers who have shown initial interest in their products or services. By monitoring these segments, advertisers can gain insights into the effectiveness of their marketing campaigns and adjust their strategies accordingly.
Secondly, monitoring tofu retargeting segments helps in optimizing ad targeting and personalization. By understanding the preferences and actions of users at the top of the funnel, advertisers can deliver more relevant and engaging ads to capture their attention and nurture them through the conversion journey.
Furthermore, tracking tofu retargeting segments enables advertisers to measure the impact of their retargeting efforts on conversion rates and return on investment (ROI). By assessing the performance of retargeting campaigns, advertisers can make data-driven decisions to optimize their advertising spend and maximize the effectiveness of their overall marketing efforts.
Overall, monitoring tofu retargeting segments provides valuable insights, aids in ad optimization, and helps advertisers make informed decisions to improve their marketing strategies and drive better results.

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10. A pitcher in a professional baseball game throws a fastball, giving the baseball
a momentum of 5.83 kg. m/s. Given that the baseball has a mass of 0.145 kg,
what is its speed?

Answers

Answer: 40.2m/sec

Work: v=p/m= 5.83kg/0.145k=40.2cm/sec

A car on flat ground accelerates at 0.785 m/s2 when a net force of 1050 N acts on it. How much normal force acts on it?

A car on flat ground accelerates at 0.785 m/s2 when a net force of 1050 N acts on it. How much normal

Answers

Answer:

13108.3N

Explanation:

Given parameters:

Acceleration = 0.785m/s²

Net force  = 1050N

Unknown:

Normal force acting on car  = ?

Solution:

The normal force on this car is the weight of the car;

   Normal force  = mg

where m is the mass of the car

           g is the acceleration due to gravity = 9.8m/s²

Now solve for the mass;

             Net force  = mass x acceleration

                1050  = mass x 0.785

                 mass  = \(\frac{1050}{0.785}\)   = 1337.6kg

So,

     Normal force  = 1337.6kg x 9.8m/s² = 13108.3N

13108 works as well for acellus

what is the speed of a transverse wave in a rope of length 3.5 m and mass 35 g under a tension of 420 n?

Answers

The speed of the transverse wave in the given rope is approximately 64.8 m/s.

What is the velocity of a transverse wave?

The speed of a transverse wave in a rope of length 3.5 m and mass 35 g under a tension of 420 N can be calculated using the formula v = sqrt(T/μ), where T is the tension, μ is the linear density (mass per unit length) of the rope, and v is the speed of the wave.

To find the linear density, we divide the mass of the rope by its length:

μ = m/L = 0.035 kg / 3.5 m = 0.01 kg/m

Now we can calculate the speed of the wave:

v = sqrt(T/μ) = sqrt(420 N / 0.01 kg/m) = 64.8 m/s

Therefore, the speed of the transverse wave in the given rope is approximately 64.8 m/s.

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Mr. Chowder ties an eraser to a string and swings it in a circle with a radius of 0.974 meters. The eraser makes 127 revolutions in a minute. Determine its acceleration (in m/s/s).

Answers

The acceleration of the eraser is 169.19 m/s².

What is centripetal acceleration?

A body travelling in a circle has centripetal acceleration. Due to the fact that velocity is a vector quantity (i.e., it has both a magnitude and a direction), when a body travels in a circle, its direction is continually changing, which causes a change in velocity, which results in an acceleration.

Given that angular velocity of the eraser: ω = 127 rpm

= 126×2π/60 radian/second

= 13.2 radian/second.

radius of the circle: r = 0.974 meter.

Hence, its centripetal acceleration is = ω²r

= 13.2×13.2×0.974 m/s²

=169.19 m/s².

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Xplain to someone who knows nothing about fossils the study of paleobotany and how it helps scientists understand the history of the earth. Be sure your explanation contains a minimum of two complete sentences.

Answers

Answer:

They're impressions of organisms preserved in rock. Paleontologists use fossil remains to understand different aspects of extinct and living organisms.  They do this by analyzing invertebrate fossils. All of this, all this studying helps to know our past.

Explanation:

the efficiency of a machine is always less than 100% because part of the energy input is used to

A. stop the machine after work
B. perform useful work on the load
C. overcome friction
D. lift the machine up​

Answers

Answer:

C. Overcome Friction

Explanation:

When using any machine usually those with moving parts, you may notice heat forming near the areas where most movement occurs. As friction continues, more energy is used up and released as heat. For that reason, the efficiency of a machine will forever be less than 100%

A 3.1 x 1023 kg object and a 7.3 x 105 kg object are orbiting each other in deep space. If these two objects are 4.3 x 1010 meters apart, what is the magnitude of their gravitational force?

Answers

The gravitational force on the object of masses 3.1×10²³ kg and  7.3×10⁵ kg respectively is 8.16×10⁻³ N.

What is gravitational force?

Gravitational force is the most prevalent force in the universe, pulling together on any two objects with mass in the universe.

To calculate the magnitude of the gravitational force, we use the formula below.

Formula:

F = GmM/r²............... Equation 1

Where:

F = Gravitational forcem = Mass of the first objectM = Mass of the second objectr = Distance between the objectsG = Universal constant.

From the question,

Given:

m = 3.1×10²³ kgM = 7.3×10⁵ kgG = 6.67×10⁻¹¹ Nm²/kg²r = 4.3×10¹⁰ m

Substitute these values into equation 1

F = (3.1×10²³× 7.3×10⁵×6.67×10⁻¹¹)/(4.3×10¹⁰ )²F = 8.16×10⁻³ N

Hence, the gravitational force is 8.16×10⁻³ N.

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You can calculate an average ________ if you know both the total distance and the total time of the trip. *

Answers

Answer:

speed

Explanation:

Given: an incomplete sentence

To fill: the blank

Solution:

Speed is not a vector quantity but a scalar quantity as it has magnitude but no direction.

Speed = Distance ÷ Time

You can calculate an average speed if you know both the total distance and the total time of the trip.

Average speed = Total distance ÷ Total time

A change of position is called
o distance
O velocity
O speed
O displacement

Answers

Displacement would be your Awnser
Displacement :))))))

just need help with question 35

just need help with question 35

Answers

I. Horizontal motion can be uniform because there is no force acting in the horizontal direction to change the velocity of the object.

II. Vertical motion is accelerated due to the force of gravity acting on the object.

III. When drag due to air resistance is taken into consideration, the motion of a projectile is affected because it experiences a resistive force that opposes its motion.

Why is Horizontal motion uniform?

According to Newton's first law of motion, in the absence of air resistance or any other forces, an object moving horizontally will continue to move at a constant speed in a straight line.

On the other hand, vertical motion is accelerated due to the force of gravity acting on the object. Gravity pulls the object downwards, causing it to accelerate towards the ground.

When drag due to air resistance is taken into consideration, the motion of a projectile is affected because it experiences a resistive force that opposes its motion. As a result, the projectile's velocity decreases over time, causing it to cover a shorter distance and reach a lower maximum height than it would without air resistance.

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two charges q1 and q2 have a total charge of 10 c. when they are separated by 4.2 m, the force exerted by one charge on the other has a magnitude of 8 mn. find q1 and q2 if both are positive so that they repel each other, and q1 is the smaller of the two. (for the universal constant k use the value 8.99 109 n m2/c2.)

Answers

The force exerted between two charges is given by Coulomb's law:

F = k * (q1 * q2) / r^2

where:

F = force (N)

k = Coulomb's constant (8.99 x 10^9 N m^2/C^2)

q1, q2 = charges (C)

r = distance between charges (m)

Given that the magnitude of the force exerted is 8 mN and the distance between the charges is 4.2 m, we can substitute these values and the value of k into the equation and solve for q1 and q2:

8 x 10^-3 N = k * (q1 * q2) / (4.2 m)^2

q1 * q2 = (8 x 10^-3 N * (4.2 m)^2) / k

Given that q1 + q2 = 10C and q1 < q2, and q1,q2 are positive, so they repel each other.

By solving this equation, we can find q1 and q2:

q1 = x and q2 = 10 - x

substituting the above values into q1 * q2 = (8 x 10^-3 N * (4.2 m)^2) / k we can find the value of x

x(10-x) = (8 x 10^-3 N * (4.2 m)^2) / k

x^2 - 10x + (8 x 10^-3 N * (4.2 m)^2) / k = 0

By solving the above equation we can find the value of x which is q1.

q1 = (10 + sqrt(100 - (32 * 8 * 10^-3 * (4.2)^2) / 8.99 * 10^9))/2

q2 = 10 - q1

q1 = 3.32 C

q2 = 6.68 C

So, q1 is 3.32 C and q2 is 6.68 C

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PLEASE HELP

atoms are split at power plant to create electricity

A. radiant to mechanical
B. nuclear to electrical
C. chemical to radiant
D. mechanical to electrical

Answers

Answer:

C. nuclear to electrical

Answer:

c its c noob

Explanation:

It was a children versus grown-ups competition at school. One event required the adult to throw a basketball as far as he could. When it was the child's turn, he had to throw a baseball instead. The event coordinator said, "It's only fair!" Based on Newton's laws, was this event fair?

Yes, because acceleration doesn't depend on the size of the object.
Yes, because an adult can apply more force than a child can. Making the adult's object bigger than the child's object helps to even out the acceleration.
No, because you must have the same size object in a competition.
No, because a basketball is bigger than a baseball, and objects that are bigger accelerate slower.

Answers

Answer:

No, because a basketball is bigger than a baseball, and objects that are bigger accelerate slower.

Explanation:

the soft ballplayer does 9876 joules of work when hitting a ball into center field. Assuming the ball landed 100 meters away from home plate, how much force did the player use to hit the ball?

Answers

Answer:

F = 987600 N

Explanation:

Force Equation

F=ma

Newton's second law states that force is proportional to what is required for an object of constant mass to change its velocity. This is equal to that object's mass multiplied by its acceleration. We use Newtons, kilograms, and meters per second squared as our default units, although any appropriate units for mass (grams, ounces, etc.) or velocity (miles per hour per second, millimeters per second2, etc.) could certainly be used as well - the calculation is the same regardless.

Solve

F = m * a

F = 100 kg * 9876 m/s2

F = 987600 N

Newtons are derived units, equal to 1 kg-m/s². In other words, a single Newton is equal to the force needed to accelerate one kilogram one meter per second squared.

I need help writing a short abstract for my science project.

Topic: Does temperature change viscosity in liquid

Answers

yes it does

well i hope this helps

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