Answers
the answer is 1.5 Ω
Explanation
the rule to add resistance in parallel is:
\(\frac{1}{R_{eq}}=\frac{1}{R_1}+\frac{1}{R_2}+++\frac{1}{R_n}\)and, the rule to add resistances in serie is
\(R_{eq}=R_1+R_2+R_3+...R_n\)The total resistance of a series circuit is equal to the sum of individual resistances
so
Step 1
add the resistance in parallel :
so.Consider R1 = 3.3 Ω , R2 = 4.5 Ω , R3 = 2.3 Ω , R4 = 3.7 Ω , R5 = 8.7 Ω , and R6 = 7.0 Ω .
hence
left side:
\(\begin{gathered} \frac{1}{R_{eq12}}=\frac{1}{R_1}+\frac{1}{R_2} \\ \frac{1}{R_{eq12}}=\frac{1}{3.3}+\frac{1}{4.5} \\ \frac{1}{R_{eq12}}=0.5252 \\ R_{eq12}=\frac{1}{0.5252} \\ R_{eq12}=1.90 \end{gathered}\)top
\(\begin{gathered} \frac{1}{R_{eq345}}=\frac{1}{R_3}+\frac{1}{R_{42}}+\frac{1}{R_5} \\ hence \\ \frac{1}{R_{eq345}}=\frac{1}{2.3}+\frac{1}{3.7}+\frac{1}{8.7} \\ \frac{1}{R_{eq345}}=0.81999 \\ R_{eq345}=\frac{1}{0.8199} \\ R_{eq345}=1.2195 \end{gathered}\)hence, we have the equivalent circuit
Step 2
b)now, w have resistance (345) and resistance 6 in serie, so we can add using the formula
\(\begin{gathered} R_{eq}=R_1+R_2+R_3+...R_n \\ R_{345}a\text{ and R}_5\text{ are in serie , so} \\ R_{3456}=1.2195+7.0 \\ R_{3456}=8.2195 \end{gathered}\)so, the new circuit would be
Step 3
finally, we have two resistances in parallel, so
.
\(\begin{gathered} \frac{1}{R_{eq}}=\frac{1}{R_{12}}+\frac{1}{R_{3456}} \\ \frac{1}{R_{eq}}=\frac{1}{1.90}+\frac{1}{8.2195} \\ \frac{1}{R_{eq}}=0.6479 \\ isolate\text{ R}_{eq} \\ 1=0.6479\text{ *R}_{eq} \\ divide\text{ both sides by 0.6479} \\ \frac{1}{0.6479}=\frac{0.6479*R_eq}{0.6479} \\ hence \\ R_{eq}=1.543 \\ rounded \\ R_{eq}=1.5 \end{gathered}\)therefore, the answer is 1.5 Ω
I hope this helps you
Related Questions
convert 1 Celsius to Fahrenheit
Answers
To convert Celsius to Fahrenheit, use the formula:
(°C × 9/5) + 32 = °F
Hope this helped
What is the distance in m between lines on a diffraction grating that produces a second-order maximum for 775-nm red light at an angle of 62.5°?
Answers
Answer:
The distance is \(d = 1.747 *10^{-6} \ m\)
Explanation:
From the question we are told that
The order of maximum diffraction is m = 2
The wavelength is \(\lambda = 775 nm = 775 * 10^{-9} \ m\)
The angle is \(\theta = 62.5^o\)
Generally the condition for constructive interference for diffraction grating is mathematically represented as
\(dsin \theta = m * \lambda\)
where d is the distance between the lines on a diffraction grating
So
\(d = \frac{m * \lambda }{sin (\theta )}\)
substituting values
\(d = \frac{2 * 775 *1^{-9} }{sin ( 62.5 )}\)
\(d = 1.747 *10^{-6} \ m\)
Radar; atomic & molecular research, microwave ovens, cell phones are possible because of which type of wave? Pic attached below
Answers
Radar; atomic & molecular research, microwave ovens, cell phones are possible because of microwaves.
What are microwaves?Microwave is described as a form of electromagnetic radiation with wavelengths ranging from about one meter to one millimeter corresponding to frequencies between 300 MHz and 300 GHz respectively.
In conclusion, Microwave radiation has its effects as it can heat the body tissue the same way it heats food. Uneccessary exposure to high levels of microwaves can cause a painful burn.
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A 2.4-kg ball falling vertically hits the floor with a speed of 2.5 m/s and rebounds with a speed of 1.5 m/s. What is the magnitude of the impulse exerted on the ball by the floor
Answers
Answer:
9.6 Ns
Explanation:
Note: From newton's second law of motion,
Impulse = change in momentum
I = m(v-u).................. Equation 1
Where I = impulse, m = mass of the ball, v = final velocity, u = initial velocity.
Given: m = 2.4 kg, v = 2.5 m/s, u = -1.5 m/s (rebounds)
Substitute into equation 1
I = 2.4[2.5-(-1.5)]
I = 2.4(2.5+1.5)
I = 2.4(4)
I = 9.6 Ns
The magnitude of impulse will be "9.6 Ns".
According to the question,
Mass,
m = 2.4 kgFinal velocity,
v = 2.5 m/sInitial velocity,
u = -1.5 m/sBy using Newton's 2nd law of motion, we get
→ Impulse, \(I = m(v-u)\)
By substituting the values, we get
\(= 2.4[2.5-(1.5)]\)
\(= 2.4(2.5+1.5)\)
\(= 2.4\times 4\)
\(= 9.6 \ Ns\)
Thus the above answer is right.
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A current of 17.0A is maintained in a single circular loop of 2.00m circumference. A magnetic field of 0.800T is directed parallel to the plane of the loop. (a) Calculate the magnetic moment of the loop. [5] (b) What is the magnitude of the torque exerted on the loop by the magnetic field?
Answers
A. The moment of the loop is 5.4 x \(10^{-3} Am^{2}\)
B. The torque exerted on the loop by the magnetic field is 4.32 \(10^{-3}\) Nm.
Given that the current I in the circular loop is 17.0 mA and the circumference of the loop is 2.00 m.
The radius of the circular loop is calculated as given below.
2πr = 2
r = 2/2 x 3.14
r = 0.18m
The moment in the circular loop is calculated as given below.
M = in
M = 17 x \(10^{-3}\) x 3.14 x 0.318²
M = 5.4 x \(10^{-3} Am^{2}\).
The torque exerted on the loop by the magnetic field is given below:
T = MB
T = 5.4 x \(10^{-3}\) x 0.800
T = 4.32 x \(10^{-3} Nm\).
This is the torque of the current-carrying loop in a uniform magnetic field. This formula can be shown to be valid for loops of any shape. The loop carries a current I, has N turns, and the plane A and the normal to the loop each make an angle θ with the field B. The net force on the loop is zero. A magnetic field exerts a force on a straight wire through which an electric current flows. Apply torque to the loop of the wire carrying the current. A torque rotates an object around a fixed axis.
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An object completes 50 cycles in 150 s.
a. What is the period of its rotation?
b. What is the frequency of its rotation?
Answers
Answer:
a. 3 seconds
b. 0.33 Hz
Explanation:
a. Period is defined by how long, in seconds, it takes for an object to complete one revolution, or cycle. If the object completes 50 cycles in 150 seconds, then it must complete one cycle every 150/50 = 3 seconds. Therefore, the period of the object is \(\boxed{3\text{ seconds}}\).
b. Frequency is given by \(f=\frac{1}{T}\) where \(T\) is the period, in seconds. Since we just found that the period is 3 seconds, plug in \(T=3\):
\(f=\frac{1}{3}\approx \boxed{0.33\text{ Hz}}\)
In the days before scuba gear, some divers descended to underwater depths in diving bells, which are basically just upside-down containers whose open ends face down. The bell allows the person inside to breathe the air trapped inside it, observe underwater objects and marine life, and work under the water.
Required:
a. If the bell is submerged to a depth of 30m below sea level, what is the water pressure at the air-water interface inside the bell?
b. If the air pressure inside the bell before submersion into the water was 1 atm (101.825 kPa), what air pressure does the person experience at that depth?
Answers
Answer:
a) P = 4.03 10⁵ Pa, b) P = 4.03 10⁵ Pa
Explanation:
a) The pressure as a function of the depth of a fluid is
P =\(P_{atm}\) + ρ g y
where Patm is the atmospheric pressure, the sea density of about 1025 kg / m³
let's calculate
P = 1.01825 10⁵ + 1025 9.8 30
P = 4.03 10⁵ Pa
b) When the hood is submerged, the water exerts a perpendicular force on the entire surface, in the equilibrium position, the air is compressed by this force until the pressure it exerts is equal to the external pressure (open at the lower), therefore the air pressure is
P = 4.03 105 Pa
"\(3.958\times 10^5 \ Pa\)" would be the pressure outside the bell .as well as the air pressure inside it. A further explanation is below.
According to the question,
Depth,
\(d = 20 \ m\)Pressure,
\(P_o = 1 \ atm\)\(= 1.018\times 10^{5} \ Pa\)
Now,
→ The water pressure outside the bell will be:
= \(P_o +p\times g\times d\)
By putting the values, we get
= \(1.018\times 10^5+1000\times 9.8\times 30\)
= \(3.958\times 10^5 \ Pa\)
And inside the air pressure will be same as the water pressure.
Thus the response above is right.
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Why is it that when riding in a car, you don't feel like you're moving?
Answers
This may shock you:
We NEVER feel speed, velocity, or motion, as long as it's constant.
We only feel CHANGES in speed, velocity, or motion.
That means speeding up, slowing down, or changing direction.
As long as we're moving in a straight line at a constant speed, we don't feel anything.
The gravity on Earth is 9.8m/s2, the mass of a bowling ball is about 5kg. What is the weight of the bowling ball on the Earth?
Answers
Answer:
yo can someone answer i need this
Explanation:
Mel adjusted, in a futile attempt to strengthen his pectoral muscles, stretches a spring exercise device 0.73 meters by exerting a force of 177N. What is the stiffness constant
Answers
In the case, Mel stretches a spring exercise device by 0.73 meters with a force of 177 N. We can use Hooke's law, which states that the force applied to a spring is directly proportional to the displacement of the spring from its equilibrium position, to calculate the stiffness constant.
Hooke's law is given by the equation:
F = kx, where F is the force applied to the spring, k is the stiffness constant, and x is the displacement of the spring from its equilibrium position.
Plugging in the given values:
Force (F) = 177 N Displacement (x) = 0.73 m
We can rearrange the equation to solve for the stiffness constant (k):
k = F / x
Plugging in the values:
k = 177 N / 0.73 m
k ≈ 242.47 N/m (rounded to two decimal places)
Therefore, the stiffness constant of the spring exercise device is approximately 242.47 N/m.
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L 2.5.2 Test (CST): The Brain and the Body
Question 4 of 10
The
lobes are important for decision making and judgment.
A. frontal
B. temporal
O c. parietal
D. occipital
SUBMIT
Answers
Answer:
I believe it's A frontal. Hope this can help
The frontal lobes are important for decision-making and judgment. The correct answer is A.
What are frontal lobes?The frontal lobes are located at the front of the brain and are involved in a variety of cognitive functions, including reasoning, problem-solving, planning, decision-making, and judgment. The prefrontal cortex, which is located in the frontal lobes, is especially important for these functions.
In addition, the frontal lobes are involved in the control of voluntary movements, speech production, and the regulation of emotions and social behavior. Damage to the frontal lobes can lead to a variety of cognitive and behavioral deficits, including difficulty with decision-making and judgment, impaired impulse control, and changes in personality.
The temporal lobes are located on the sides of the brain and are involved in the processing of auditory information, as well as memory formation and recognition of faces and objects. The parietal lobes are located at the top and back of the brain and are involved in the processing of sensory information from the body, such as touch and proprioception. The occipital lobes are located at the back of the brain and are primarily involved in the processing of visual information.
Therefore, The correct answer is A i.e Frontal lobes are important for decision-making and judgment.
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4. Which of the following quantities remain the same in all parts of a series circuit?
A. Voitage B. Current C. Power D. Resistance.
Answers
The current remains the same in all parts of a series circuit.
The correct option is B.
What is a circuit?A circuit is a complete path for the flow of electric current.
A series circuit is a circuit that the component of the circuit are connected end-to-end and the flow of current is in one direction.
Another form of connection is the parallel connection in which current flows through alternate paths.
In a series circuit, the flow of current is constant and remains the same in all parts of a series circuit. However, the voltage across the circuit varies.
In a parallel circuit, the voltage is constant and remains the same in all parts of a parallel circuit. However, the flow of current across the circuit varies.
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The diagram shows a proposed design for a ship that could be used for long-distance space travel. Explain why the ship must rotate so that passengers feel effects similar to gravity.
Answers
Answer:
I don't know this for sure, but I think its because they need to be able to sit in their seats without flying in the air.
Explanation:
Because of the centrifugal force he ship must rotate so that passengers feel effects similar to gravity.
What is Centrifugal force ?''Centrifugal force is force acting on a body performing circular motion, which is along radius of the circle and directed outwards from the center of circle". Since Centrifugal force acts at right angle to the tangential velocity of the body, there is no displacement in the direction of the force, hence no work done. It has newton(N) as Si unit.
centripetal force is given by,
F= mv²÷r
Where m is mass of the body v is velocity of the body r is radius of circle at which body is moving.
When space ship rotate to the certain angular velocity, centrifugal force will act on each object in the space ship. that force will force the object radially outwards as result all will stuck on the floor and all will experience the feel of gravity.
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Estimate the weight of a 1000kg car that is accelerating at 3 m/s/s.
Answers
Answer:
W = 9800 N
Explanation:
Given that,
Mass of a car, m = 1000 kg
Acceleration of the car, a = 3 m/s²
We need to find the weight of the car. Weight of an object is given by the product of mass and acceleration due to gravity on the Earth.
W = mg
Put all the values,
W = 1000 kg × 9.8 m/s²
= 9800 N
So, the weight of the car is 9800 N.
The rate constant of a certain reaction is known to obey the Arrhenius equation, and to have an activation energy E_a = 30.0 kJ/mol. If the rate constant of this reaction is 5.0 times 10^4 M^-1 s^-1 at 201.0 degreeC, what will the rate constant be at 172.0 degreeC? Round your answer to 2 significant digits.
Answers
The rate constant be at 172.0°C is 1.11 x10⁵ m⁻¹s⁻¹
We employ the Arrhenius equation, which is: to determine the rate constant for the reaction at two different temperatures.
Ln(k 172.0°C/ k 201°C) = Ea/R (1/T₁ - 1/T₂)
where,
k 201°C = equilibrium constant at 201°C = 5x 10⁴m⁻¹s⁻¹
k 172.0°C = equilibrium constant at 172.0°C = ?
Ea = Activation energy = 30.0 kJ/mol = 30000 J/mol (Conversion factor: 1 kJ = 1000 J)
R = Gas constant = 8.314 J/mol K
T₁ = initial temperature = 201°C = 474°K
T₂ = final temperature = 172.0°C = 445 °K
Putting the value
Ln(k 172.0°C/ k 201°C) = 30000 J/mol /8.314 J/mol K (1/ 474°K - 1/445 °K)
k 172.0°C = 1.11 x10⁵ m⁻¹s⁻¹
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What are the reactants in a chemical formula?(1 point) Responses the substance created by chemical change the substance created by chemical change the atoms after the chemical reaction, found on the right side of the equation the atoms after the chemical reaction, found on the right side of the equation the atoms left over after the formation of the new substance the atoms left over after the formation of the new substance the atoms prior to the chemical reaction, found on the left side of the equation
Answers
The reactants in a chemical formula is the atoms prior to the chemical reaction, found on the left side of the equation. That is option D.
What is a chemical formula?A chemical formula is defined as the scientific way of representation of chemical compounds either singly or during a chemical reaction.
During a chemical reaction, a chemical formula is made up of a right side and a left side with an arrow at its middle indicating the movement of the energy of the chemical reaction.
The reactants are found located at the left hand side of the chemical formula.
The reactants are made up of elements and compounds which combines to form a new product through the formation of new chemical bonds.
For example in the formation of water,
2H2. + O2. --> 2H2O
Here, Hydrogen and oxygen molecules are the reactants which are seen on the left-hand side of the chemical reaction.
Therefore, The reactants in a chemical formula is the atoms prior to the chemical reaction, found on the left side of the equation.
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Answer: D
Explanation: I took the quick check
Which correctly describes latent heat?
A. The heat of molecules that are under pressure
B. The heat held inside of ice crystals colder than -2°C
C. The heat absorbed or lost by a substance while it's changing state
D. The heat used to change the temperature of a liquid
Answers
Option C. The heat absorbed or lost by a substance while it's changing state correctly describes latent heat
Latent heat is the heat absorbed or lost by a substance while it is changing state.
The latent heat is a type of heat that is transferred during phase change, i.e., while a substance undergoes a change of state.
For example, when ice melts into liquid water, or when liquid water evaporates into water vapor, heat is absorbed from the surroundings.
Latent heat is not associated with a temperature change; rather, it's associated with a change of state.
For instance, the temperature of water remains at 100°C while boiling.
When water is boiling, the latent heat of vaporization is absorbed and utilized to break the hydrogen bonds holding water molecules together to change water from the liquid phase to the gaseous phase.
When the water is boiling, adding more heat won't increase the water's temperature, instead, the extra heat will be absorbed to change the phase of water molecules.
Therefore, the correct answer to the given question is option C: The heat absorbed or lost by a substance while it is changing state.
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2. The following diagram shows a metal ball and ring apparatus. The ring and ball are both made of brass. At room temperature, the ball is just the right size to pass through the ring. When the ball is heated, it is unable to pass through the ring. Which of the following is NOT true? A The volume of the ball increased. B The mass of the ball increased. C. The speed at which the particles move increased. D The spaces between the particles increased. Not True
Answers
The statement that is NOT true is "the spaces between the particles increased.
option D.
What is effect of temperature on volume?If we consider the solids and liquids, when the temperature increases the molecules gain energy and start moving in all directions. This expands the substance and the volume of the substance increases.
Similar, when the ball is heated, the volume of the ball increases due to thermal expansion.
As the temperature increases, the average kinetic energy of the particles within the ball also increases, causing them to move faster.
However, the spaces between the particles do not necessarily increase. In fact, the expansion of the ball occurs due to the particles themselves moving farther apart, but the intermolecular spacing within the ball remains relatively constant.
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Solve for the mass of a planet with an orbital radius of 4 AU and an orbital period of 4 Earth years,
orbiting a star whose mass is 3 solar masses.
Answers
The mass of the planet orbiting through the path can be calculated using its period of orbit, and radius . Here, the mass of the planet be 7.11 × 10³⁰ kg.
What is orbital period ?The orbital period of a spatial object is the time taken to revolve around a star or another spatial object through out an elliptical orbit.
The mass of the star can be calculated using the formula :
m = 4 π r³/G T²
given,
r = 4 Au = 4 × 1.5 × 10¹¹ m
T = 4 years = 12.6 × 10⁷ seconds.
G = gravitational constant 6.67 × 10⁻¹¹ m³/kg s²
Then M = 4 × 3.14 × (4 × 1.5 × 10¹¹ m)³/ 6.67 × 10⁻¹¹ m³/kg s² × ( 12.6 × 10⁷ s)²
= 7.11 × 10³⁰ kg.
Therefore, the mass of the planet is 7.11 × 10³⁰ kg..
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9. A circular coil of radius 10 cm and with 125 turns is initially oriented perpendicular to a uniform magnetic field of strength 2.50 mT directed out of the page. The wire carries a current of .250 A. a) Sketch the situation. b) Indicate the direction of the magnetic moment of the coil. c) What is the torque on the coil
Answers
Answer:
Explanation:
Given that:
The radius = 10 cm
No of turns = 125
Current in the coil (I) = 0.250 A
Uniform magnetic field B = 2.50 mT = 2.5 × 10⁻³ T
a) The sketch of the situation can be seen below
b)The magnetic moment of the coil is \(\mu^{\to} = ni A^{\to}\)
where the direction of the magnetic moment is the same and equivalent to the direction of the area vector in the diagram. The region vector of the coil is parallel to the magnetic field.
In this manner, the direction of magnetic moment is perpendicular to the current loop by right-hand rule direction; which implies out of the page.
(c)
The torque \(\tau = \mu^{\to} \times B^{\to}\)
\(= \mu B sin \theta\)
where;
\(\theta\) between \(\mu\) and B = 0
Thus;
\(\tau = \mu B sin (0)\)
\(\tau = 0\)
Someone please help
Answers
The displacement of Willy worm is 7 m.
Displacement of an object is defined as the change in position of the object. It is a vector quantity, which means it has both a direction and magnitude. It is shown by using an arrow that leads from the initial position to the final position.
Distance is a scalar quantity.
In the given graph, the travelling path of Willy worm is shown.
From the graph, we can calculate the displacement of Willy worm by measuring the difference between its final and initial positions.
So,
Displacement of the Willy worm, s = 4m + 5m - 2m - 5m + 5m
Displacement, s = 4 + 5 - 2
s = 7 m
Distance travelled by the Willy worm, d = 4m + 5m + 2m + 5m + 5m
Distance, d = 21 m
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coefficient of the kinetic friction between the object and the surface (3) 3 Distance the object travels on the horizontal surface before it comes to a stop. (5
Answers
Based on the coefficient of kinetic friction, the object will travel a distance of approximately 37 meters before coming to a stop.
The correct option is C.
What is the distance traveled by the object?The distance an object will travel before coming to a stop can be calculated using the equation:
vf² = vi² + 2ad
where
vf is the final velocity (which is zero when the object comes to a stop)vi is the initial velocity,a is the acceleration, andd is the distance traveled.The acceleration of the object can be determined using the equation:
a = -μk * g
where
μk is the coefficient of kinetic friction andg is the acceleration due to gravity.Substituting the given values, we get:
a = -0.050 * 9.81 m/s²
a = -0.491 m/s²
Now we can use the first equation to solve for d:
0 = (6.0 m/s)² + 2(-0.491 m/s²)d
d = (6.0 m/s)^2 / (2 * 0.491 m/s^2)
d = 37 m
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Complete question:
An object is given an initial velocity of 6.0 m/s. The coefficient of kinetic friction between the object and the horizontal surface it slides across is 0.050. How far will the object travel before coming to a stop?
A) 19 m B) 25 m C) 37 m D) 57 m E) 102 m
A 6.00 nC is 2.00 m from a 3.00 nC charge. Find the magnitude of the electric field at a point midway between
the two charges? Which way does the electric field point, towards the positive or the negative charge?
Answers
Answer:
E_total = 26.97 N/C
Electric field points towards the positive charge
Explanation:
We are given;
Charge 1; q1 = 6 nC = 6 × 10^(-9) C
Charge 2; q2 = 3 nC = 3 × 10^(-9) C
Distance between both charges; R_o = 2 m
Since we want to find electric field midway, the distance midway is r = 2/2 = 1 m
Using coulumbs law;
E = kq/r²
Where k is a constant with a value of 8.99 × 10^(9) N.m/C²
Thus;
E1 = kq1/r²
E1 = (8.99 × 10^(9) × 6 × 10^(-9))/1²
E1 = 53.94 N/C
Similarly;
E2 = kq2/r²
E2 = (8.99 × 10^(9) × 3 × 10^(-9))/1²
E2 = 26.97 N/C
Since both electric fields are positive, it means that they are both moving towards the midpoint of the distance between both charges.
This implies they will have opposite directions.
Thus, total electric field at the midway point is;
E_total = E1 - E2
E_total = 53.94 - 26.97
E_total = 26.97 N/C
What is the shape of a line graph that shows the temperature change over time of the liquid before it starts to boil.
Answers
The shape of a line graph displaying temperature change over time before boiling is typically linear and increasing.
In a line graph showing the temperature change over time of a liquid before it starts to boil, the shape is generally linear and increasing.
This is because as heat is applied to the liquid, its temperature increases at a consistent rate.
During this phase, the heat energy is used to increase the kinetic energy of the molecules in the liquid, causing a rise in temperature.
Once the boiling point is reached, the graph may show a plateau, as the energy is then used to change the liquid's state rather than further increase the temperature.
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1. A ball is at rest on the top of a hill (see the figure).
At the top of the hill, the ball will have [the maximum value of its, no, the minimum value of its] gravitational potential energy and [no, the maximum value of its] kinetic energy. If the ball rolls down the hill then, its [gravitational potential energy, kinetic energy] is converted to [gravitational potential energy, kinetic energy] when it gets to the ground.
2. Get your stopwatch ready and prepare to drop the object from the height h you selected in the previous step. You should drop the object so its [bottom, top, middle] part is initially at the height h. The initial speed of the ball [zero, 9.8 m/s, 9.8 m/s^2, depends on the height h] You'll need to measure the time from when the ball leaves your hand to exactly when it hits the ground [ for the first time it bounces, after it bounces and then comes to rest, both the first time and then after it bounces; then average the two times]
.
Answers
2. When dropping the object, you should drop it so its top part is initially at the height h. The initial speed of the ball will be zero since it starts from rest. To measure the time it takes for the ball to hit the ground, you should start the stopwatch when the ball leaves your hand and stop it when the ball hits the ground for the first time. It is recommended to perform multiple trials and calculate the average time to minimize errors.
A bat emits a 40 kHz chirp to locate flying insects. If the speed of sound is 340 m/s and a bat hears the echo from the moth after 0.6 seconds, then how far away is the moth?
Answers
102 m
Explanation:
The time 0.6 sec is the time it took for the sound to travel from the bat to the moth and back. So it took 0.3 sec for the sound to reach the moth. From the definition of speed, the distance of the moth d to the bat is given by
v = d/t ---> d = vt = (340 m/s)(0.3 sec) = 102 m
if the period of the pendulum in the preceding sample problem were 24 degree, how tall would the tower be?
Answers
The tower's height would be around 143 m tall.
How to calculate height of tower?Solve for the length of the pendulum using the equation for the period of a simple pendulum.
T = 2π√(l/g)
where l = length of pendulum which is equal to height of tower because it touches the almost the floor
T = time, 24 seconds and
g = acceleration due to gravity 9.8 m/s².
Substitute the given values:
24s = 2π√(l/ 9.8 m/s²)
24/2π = √(l/ 9.8 m/s²)
l = (24/2π)² x 9.8 m/s²
l = (12/π)² x 9.8 m/s²
l = 14.59 x 9.8 m/s²
l = 142.982
Therefore, the height of the tower would be 143 m approximately.
Find out more on pendulum here: https://brainly.com/question/26449711
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Which is true of gamma radiation? O A. It increases the number of protons. O B. It is the heaviest of the three types. O C. It does not cause transmutation. O D. It has a positive charge.
Answers
Answer: Your answer Is A)
Explanation:
Its direction of deflection shows it possitively charged
It brings one element into another by bombardment(transmutation)
I need help with number 3!!!!!!!!!!!!
Answers
Answer:
3. The frequency of the wave is 3 Hz.
Explanation:
3. Determination of the frequency of the wave.
Frequency is simply defined as the number of complete circle or oscillation made in 1 seconds. Mathematically, it can be expressed as:
f = n / t
Where:
f => is the frequency.
n => is the number of circle.
t => is the time.
With the above formula, we can obtain the frequency of the wave as follow:
Number of complete circle (n) = 3
Time (t) = 1 s
Frequency (f) =?
f = n / t
f = 3 / 1
f = 3 /s = 3 Hz
Therefore, the frequency of the wave is 3 Hz
a car accelerates from 4 meters/second to 16 meter/second in 4 seconds. The cars acceleration is how many meter/seconds.
Answers
Answer:
=3 metre per second ^2
Explanation:
Formula for acceleration is
V-U÷T
In the given information
V=16
U=4
T=4
Acceleration =16-4/4
=3 metre per second ^2