Find the magnitude of the sum of these two vectors: B 101 m 60.0 ° 85.0 m A​

Find The Magnitude Of The Sum Of These Two Vectors: B 101 M 60.0 85.0 M A

Answers

Answer 1

Answer:

M= 161.1 m Deg= 32.9

Explanation:


Related Questions

A 15 kg flywheel has all its mass around its outer rim. A string is wrapped around it and a m = 3.7 kg weight is hanging on the string. The flywheel has radius R = 0.25 m.

a) When the 3.7 kg weight is dropping with a speed of 1.7 m/s, what is the angular velocity of the flywheel?

w = ?? rad/s

b) When the 3.7 kg weight is moving with a speed of 1.7 m/s, what is the kinetic energy of the entire system?

K.E. = ?? J

c) If the system started from rest, how far has the weight fallen?

hfall = ?? m

d) What is the angular acceleration at this point?

a = ?? rad/s2

Answers

A 15 kg flywheel has all its mass around its outer rim. A string is wrapped around it and a m = 3.7 kg weight is hanging on the string. The flywheel has radius R = 0.25 m.

a) When the 3.7 kg weight is dropping with a speed of 1.7 m/s,  the angular velocity of the flywheel 6.8 rad/s.

b) When the 3.7 kg weight is moving with a speed of 1.7 m/s,  the kinetic energy of the entire system is 22.5 J.

c) If the system started from rest, the height weight fallen is 0.719 m

d)  the angular acceleration at this point is 39.2 rad/s².

a) Angular velocity of the flywheel is given by :

w = v / r

Where, w = angular velocity of flywheel v = velocity of weight R = radius of flywheel

Therefore,w = v / r = 1.7 m/s / 0.25 m = 6.8 rad/s

Therefore, the angular velocity of the flywheel is 6.8 rad/s.

b) Kinetic energy of the entire system is given by :

K.E. = 1/2 * I * w²

Where, I = moment of inertia = mass of the flywheel * radius²

Thus,I = 15 kg * (0.25 m)²I = 0.9375 kg.m²

Therefore, K.E. = 1/2 * I * w²= 1/2 * 0.9375 kg.m² * (6.8 rad/s)²= 22.5 J

Therefore, the kinetic energy of the entire system is 22.5 J.

c) Potential energy of the weight at the top of the wheel is given by:

U = mgh

Where, m = mass of the weight = 3.7 kg g = acceleration due to gravity = 9.8 m/s² h = height fallen

Thus,U = 3.7 kg * 9.8 m/s² * h

Therefore, h = U / (mg) = (1.7 * 3.7 * 9.8) / (15 * 9.8)= 0.719 m

Therefore, the height fallen by the weight is 0.719 m

d) At this point, angular acceleration is given by:

a = alpha * r

Where, alpha = angular acceleration of flywheel

Therefore, alpha = a / r = g / r= 9.8 m/s² / 0.25 m= 39.2 rad/s²

Therefore, the angular acceleration at this point is 39.2 rad/s².

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part a - a particular sensitizer can absorb photons of one wavelength and release photons of a longer wavelength. why must the radiation be at a longer wavelength?

Answers

Because a particular sensitizer can absorb photons of one wavelength and release photons of a longer wavelength. The radiation must be at a longer wavelength because The energy produced by light is inversely proportional or related to the wavelength of light.

What is the explanation for the above?

Fluorescence is emitted by most sensitizers as a result of some of the energy from the initial excited singlet state. Because emitted light is generally less energy than absorbed light, the emitted light has a longer wavelength.

The physical or chemical adsorption of colored materials absorbs visible or solar light and excites it to the singlet or triplet excited state in the surface sensitizer process.

When an excited molecule (the donor or photosensitizer) generates photochemical reactions in molecules (the acceptor or quencher) which are not photochemically reactive by themselves, i.e. do not absorb light in the specified wavelength range, the process is deemed photosensitized.

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2) what would you expect the sky color to be at an altitude of 50km? why? what factors explain the lower atmospheres blue color?

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At an altitude of 50km, you would expect the sky color to be a darker shade of blue, almost black.

This is because the atmosphere becomes thinner as you go higher in altitude, leading to less scattering of sunlight.

The lower atmosphere's blue color can be explained by several factors, including Rayleigh scattering and absorption of light. Rayleigh scattering occurs when sunlight interacts with gas molecules and small particles in the atmosphere. This scattering is more effective for shorter wavelengths of light, such as blue and violet.

However, our eyes are more sensitive to blue light, which is why we perceive the sky as blue. Additionally, some of the violet light is absorbed by the ozone layer, further contributing to the sky's blue appearance.

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a basketball player makes a jump shot. the 0.610-kg ball is released at a height of 1.90 m above the floor with a speed of 7.03 m/s. the ball goes through the net 3.04 m above the floor at a speed of 4.29 m/s. what is the work done on the ball by air resistance, a nonconservative force?

Answers

To determine the work done on the basketball by air resistance, we need to calculate the change in kinetic energy of the ball. The work done by air resistance is equal to the negative change in kinetic energy.

Mass of the ball (m) = 0.610 kg

Initial height (h1) = 1.90 m

Final height (h2) = 3.04 m

Initial speed (v1) = 7.03 m/s

Final speed (v2) = 4.29 m/s

The initial kinetic energy (KE1) of the ball is given by:

KE1 = (1/2)mv1^2

The final kinetic energy (KE2) of the ball is given by:

KE2 = (1/2)mv2^2

The work done by air resistance is given by:

Work = -(KE2 - KE1)

Substituting the given values into the equations:

KE1 = (1/2)(0.610 kg)(7.03 m/s)^2

KE2 = (1/2)(0.610 kg)(4.29 m/s)^2

Work = -[(1/2)(0.610 kg)(4.29 m/s)^2 - (1/2)(0.610 kg)(7.03 m/s)^2]

Calculating the work:

Work = -[(1/2)(0.610 kg)(18.3841 m^2/s^2) - (1/2)(0.610 kg)(34.2909 m^2/s^2)]

Work = -[5.63586705 J - 10.42909715 J]

Work = -(-4.7932301 J)

Work ≈ 4.793 J

Therefore, the work done on the ball by air resistance, a nonconservative force, is approximately 4.793 Joules.

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a water supply pipe of diameter 2.50 cm carries water from the water main to a sprinkler that is at the top of a small hill. the sprinkler nozzle is 0.50 cm in diameter and the water exits the sprinkler nozzle with a speed of 10.0 ms-1 . if the sprinkler is 8.00 m above the supply pipe, find:

Answers

The volume of the sprinkler for the given water supply is V1 = 0.32m/s, by using Bernoulli's equation.

What is Bernoulli's equation?

According to Bernoulli's principle of fluid dynamics, a fluid's speed increases at the same time as its static pressure or potential energy decreases. The Bernoulli equation is regarded as the definition of energy conservation for flowing fluids. This is thought to be the qualitative behaviour that reduces pressure in high-velocity zones. Also, referred to as the Bernoulli effect.

Calculations:

Using continuity equation, Bernoulli's equation.

A1×V1 = A2×V2

Where,

A1 = area of the supply pipe

V1 = volume of supply pipe

A2 = area of sprinkler

V2 = volume of sprinkler

Given,

Diameter of supply pipe = 2.5cm therefore radius = 1.25cm.

Diameter of sprinkler = 0.5cm therefore radius = 0.25cm.

V1 = (A2×V2) /A1

V1 = (π \(r_{2}\)²× V2) / (π \(r_{1}\)²)

V1 = {π (0.25) ² × 8} / { π (1.25) ²}

V1 = 0.32m/s.

Hence, the volume of the sprinkler for the given water supply is V1 = 0.32m/s, by using Bernoulli's equation.

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When wood burns, a small amount of ashes is produced and gas is given off. How does this reaction demonstrate the law of conservation of mass?.

Answers

The law of conservation of mass states that matter can neither be created nor destroyed. When wood burns, the mass of the wood is converted into a small amount of ashes and gas. The total mass of the ashes and gas is equal to the mass of the wood before it was burned, demonstrating that the law of conservation of mass holds true.

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when a body is completely immersed in liquid what are the two forces acting on it?​

Answers

A Body Held Completely Immersed Inside a Liquid Experiences Two Forces: (I) F1, the Force Due to Gravity and (Ii) F2, the Buoyant Force.

What are the latitude and longitude coordinates for Location C? 1) 50N, 68S 2) 50N, 68W 3) 50S, 68E 4) 50S, 68W Which is farther- the distance between Location B and the Equator or the distance between Location C and the Equator? 1) Location B and the Equator 2) Location C and the Equator 3) Locations B and C are the same distance from the Equator 4) Cannot discern from the information provided

Answers

The latitude and longitude coordinates for Location C are given as 50S, 68W. Therefore, the correct answer is 4) Cannot discern from the information provided.

Latitude and longitudinal lines are shown on a globe of Earth as parallel and vertical lines. To determine which distance is farther, we need to compare the distance between Location B and the Equator with the distance between Location C and the Equator.

However, the latitude and longitude coordinates for Location B and the specific direction or coordinates of the Equator are not provided. Without this information, it is not possible to determine which distance is farther between Location B and the Equator or Location C and the Equator.

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Which statement describes an example of static electricity?
A. Negatively charged particles are repelled by other negatively
charged particles
B. An insulator prevents electric charge from moving through it.
C. Electric charge flows past a point in a circuit.
D. A battery provides electrical energy to power a phone.

Answers

Answer:it’s a

Explanation:

Static electricity refers to the buildup or imbalance of electric charges on the surface of objects. The correct answer is B. An insulator prevents electric charge from moving through it.

An insulator prevents electric charge from moving through it. This statement describes an example of static electricity because insulators, such as rubber or plastic, do not allow electric charges to flow freely. When an insulator is rubbed or comes into contact with another object, it can cause the transfer of electrons between the two surfaces, leading to a buildup of static charge.

The charges remain stationary on the surfaces of the objects, resulting in an electrical imbalance without the flow of charges through the insulator.

Therefore, the correct answer is B. An insulator prevents electric charge from moving through it.

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A basketball is dropped from a walkway above Bartow Arena. It falls from rest with a constant acceleration of 9.8 m/s
2
until it reaches the floor 2 seconds later. A physics class is modeling the 1-D straight line motion as part of a class project They want construct a simple, but accurate, data table using the following equations: v
i+1

=v
i

+a t and x
i+1

=x
i

+v
i

t which are familiar to you. Their instructor requires them to make the constant time interval Δt between rows in their table sufficiently small so that they have only a 4 percent error in the total distance traveled by the ball during the 2 seconds. What should be the value of Δt in their data table to cover the entire time interval and achieve the desired error?

Answers

The value of Δt in the data table to cover the entire time interval and achieve the desired error is 0.1 seconds.


Given that the basketball is dropped from a walkway above Bartow Arena and it falls from rest with a constant acceleration of 9.8 m/s2 until it reaches the floor 2 seconds later.

The equations required to construct the data table are

v i+1 =v i +a t and x i+1 =x i +v i t.
The class project requires that the constant time interval Δt between rows in their table should be sufficiently small so that they have only a 4 percent error in the total distance traveled by the ball during the 2 seconds.
The total distance traveled by the ball in 2 seconds can be calculated using the kinematic equation, x = ½ a t2.

The distance covered is x = 0.5*9.8*22 = 19.6 m.

If Δt is the time interval, then the total number of intervals is 2/Δt.

The distance traveled by the ball for each interval is 0.5 a (Δt)2.

Hence, the total distance covered is given by 0.5 a (Δt)2(2/Δt).

On simplifying, we get the expression,

Δt2 = (0.04*2*19.6/9.8).

Therefore, Δt = 0.1 seconds.

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how much does it cost to light six 100w light bulbs for six hours if the price of electrical energy is $0.09/kwh?

Answers

It will cost 0.324 Dollars to light six 100w light bulbs for six hours if the price of electrical energy is $0.09/ kwh.

kwh is commercial unit of electric energy. 1 unit= 1 kwh.

When 100 w power device is run for 1 hour, the amount of electrical energy consumed is 1 kwh.

We will find total units of electrical energy consumed in the given question.

energy consumed by 6 bulbs = 6×100= 600 w( joules per second).

The value in kwh is = 600÷1000

                                = 0.6kwh

Total energy consumed in 6 hours is = 0.6×6 = 3.6 kwh

So, the cost is = 3.6×0.09 = 0.324 dollars.

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Gamma radiation can be significantly reduced by…

A sheet of paper

Air

A 3 mm thickness of aluminium

Several cm of lead

Answers

Answer:

Several cm of lead

Explanation:

In the figure shown, if angle i is increased, angle r will _____.

Answers

Answer: I am assuming it is decreases

Explanation: a straight line is 180 degrees. 2 angles both add up to 180 degrees on a straight line. When one increases, the other has to decrease to keep it 180 degrees on a straight line

Two similar objects are moved by two bulldozers. if the work accomplished by bulldozer #2 was three times greater than bulldozer #1 then: both bulldozers did equal work because the objects are similar. bulldozer #2 had to move 3 times greater distance. bulldozer # 1 had to move 3 times greater distance. bulldozer #2 had to require 3 times greater power.

Answers

If the work accomplished by bulldozer #2 is three times greater than bulldozer #1, it can mean that bulldozer #2 exerted three times the force or that bulldozer #1 had to move three times greater distance.

If the work accomplished by bulldozer #2 is three times greater than bulldozer #1, it means that bulldozer #2 had to exert more force or move the object over a greater distance. However, since the objects being moved are similar, it does not necessarily mean that both bulldozers did equal work.

To understand this better, let's consider an example:

Suppose bulldozer #1 moved an object with a force of 100 units and bulldozer #2 moved a similar object with a force of 300 units. In this case, bulldozer #2 exerted three times the force of bulldozer #1.

Alternatively, if we consider the distance covered, bulldozer #1 had to move three times greater distance than bulldozer #2. This is because the work done is equal to the force multiplied by the distance. So if the work done by bulldozer #2 is three times greater, it implies that bulldozer #1 had to move a greater distance.

It is important to note that the power required by bulldozer #2 may or may not be three times greater than bulldozer #1. Power is defined as the rate at which work is done, so it depends on the time taken to perform the work. The given information does not provide enough details to determine the power required by each bulldozer.

In summary, if the work accomplished by bulldozer #2 is three times greater than bulldozer #1, it can mean that bulldozer #2 exerted three times the force or that bulldozer #1 had to move three times greater distance. However, the information provided does not allow us to determine the power required by each bulldozer.

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Rosa was looking for patterns to help predict the products of chemical reactions. She recorded three similar decomposition reactions in the table.

A 2-column table with 3 rows. The first column labeled reactants has entries 2 N a C l O subscript 3, 2 K C l O subscript 3, 2 L i C l O subscript 3. The second column labeled products has entries 2 N a C l + 3 O subscript 2, 3 O subscript 2 + 2 K C l, empty.

What products should she record in the last row of the table?

2LiCl + 3O2
3LiCl + 2O2
2LiO + 3Cl2
3LiO+ 2Cl2

Answers

Answer:

It's A

Explanation:

Because I know it is

The record in the last row should be 2LiCl + 3O2.

What is a chemical reaction equation?

A chemical reaction equation has two parts;

The left hand side that contains the reactants.The right hand side that contains the products.

The interaction between the atoms of the reactants lead to rearrangement hence products are formed.

For the reaction, the record in the last row should be 2LiCl + 3O2.

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What do you feel when you receive your homework? ​

Answers

Very bad, it’s extremely draining I dread it a lot maybe it’s just cause I have a lot

The feeling can either be positive or negative.

How one feels depends on number of factors

A positive feeling can occur when one performs very well in the given home. Also, a positive feeling can come from a high level of satisfaction in the homework. When you complete your homework on time using the recommended steps, you will be sure to do well on the homework.

In other hand, a negative feeling may result from poor performance in the homework. In ability to complete the homework or missing some steps in the homework can increase your level of trepidation even before seeing your score.

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Two people leave points A and B at the same time. They intend to meet at point C at the same time. The person who leaves point A walks at a speed of 3 miles per hour. You and a friend are trying to determine how fast the person who leaves point B must walk. Your friend claims you need to know the length of . Is your friend correct? Explain your reasoning.

Answers

Your friend is correct. In order to determine the speed at which the person who leaves point B must walk, you need to know the length of AC and BC.

This is because the time it takes for each person to reach point C is dependent on the distance they must travel and the speed at which they are traveling.

Using the formula time = distance / speed, you can calculate the time it takes for each person to reach point C.

For the person leaving point A, the time it takes to reach point C is tA = AC / 3, since they are traveling at a speed of 3 miles per hour.

For the person leaving point B, the time it takes to reach point C is tB = BC / x, where x is the speed at which they are traveling.

Since both people are intended to reach point C at the same time, you can set the two equations equal to each other:

AC / 3 = BC / x

Cross-multiplying and solving for x gives you the speed at which the person leaving point B must walk:

x = 3BC / AC

Without knowing the length of AC and BC, you cannot determine the speed at which the person leaving point B must walk. Therefore, your friend is correct.

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Work Done By Friction Definition
Work done by a frictional force on an object is force exerted by friction multiplied by the displacement of the object in the direction of the frictional force. SI unit of work done by the frictional force is joules.

Answers

Yes, the statement 'Work done by a frictional force on an object is force exerted by friction multiplied by the displacement of the object in the direction of the frictional force. SI unit of work done by the frictional force is joules' is the correct definition of Work Done By Friction.

Work done by a frictional force on an object is a measure of the energy exerted by friction.

This energy is equal to the magnitude of the frictional force multiplied by the displacement of the object in the direction of the frictional force.

The SI unit of work done by the frictional force is the joule, which is a unit of energy. In other words, the work done by friction is the amount of energy expended by the frictional force on the object.

This definition applies to any object which experiences a frictional force.

Although a part of your question is missing, you might be referring to this question:

Is 'Work done by a frictional force on an object is force exerted by friction multiplied by the displacement of the object in the direction of the frictional force. SI unit of work done by the frictional force is joules' the correct definition of Work Done By Friction.

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a torpedo fired from a submerged submarine is propelled through the water eit ha speed of 20.00m/s and explodes upon impact with a target 2000.0m away. if the sound of the impact in heard 101.4s after the torpedo was fired, what is the speed of sound in water

Answers

The speed of sound in water made by a torpedo with a speed of 20.00m/s and explodes upon impact with a target 2000.0m away is 19.72 m / s

v = d / t

v = Velocity

d = Distance

t = Time

d = 2000 m

t = 101.4 s

v = 2000 / 101.4

v = 19.72 m / s

Velocity of an object is the object's rate of change of position with respect to time. It is mostly denoted as m / s.

Therefore, the speed of sound in water is 19.72 m / s

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when is the image virtual in a concave mirror?

Answers

If the object is found between the focal point(F) and the pole(P) the image formed by concave mirror will be virtual, erect and larger in size

The total energy of the body executing S.H.M. is 10 J. Then the kinetic energy when the displacement is half of the amplitude is 5.73 7.5J 5J 2.5 J 12.5 J

Answers

The kinetic energy of the body executing S.H.M. is 7.5 J when the displacement is half of the amplitude.

The total energy of the body executing S.H.M. is 10 J, let's find the kinetic energy when the displacement is half of the amplitude.

In S.H.M., the total energy (E) is the sum of the kinetic energy (K) and potential energy (U). We are given that E = 10 J.

1. The potential energy (U) is given by: U = (1/2)kx², where k is the spring constant and x is the displacement

At maximum amplitude, all the energy will be potential energy.

Let maximum amplitude is A and spring constant be k.

\(10 = 1/2kA^2\)

\(A = \sqrt{20/k}\)

Now potential energy at half the displacement of the amplitude.

\(U = 1/2k(\sqrt{20/k}/2)^2\)

U = 20/8

2. The kinetic energy (K) is given by: K = E - U, where E is the total energy and U is the potential energy.

K = 10 -20/8 = 7.5 J

Therefore the kinetic energy of the body at half of the amplitude is 7.5 J.

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A 3500 N is force is applied to a spring that has a spring of constant of k= 14000 N/m. How far from equilibrium will the spring be displaced?

Answers

Answer:

the spring be displaced by 25.0 cm

Explanation:

The computation is shown below:

As we know that

F= -K × x

So,

\(x = \frac{-F}{K}\)

Now  

\(x = \frac{-3500}{14000} \\\\\)

= -0.250m

= 25.0 cm

Hence, the spring be displaced by 25.0 cm

A bus leaves Houston at 6am headed toward Austin at a constant speed of 54.3 miles/hr. If Austin is located 190 miles west of Houston, approximately when will the bus arrive in Austin?

Answers

resolved for the constant speed as the ratio of distance and time. We have B as the speed, the, as the distance at the at the time it is given that the bus leaves easter and other exactly six o'clock in the morning In Travis at a constant speed of 54.3 mph to Austin, which is located at a distance of 190 miles away. We want to find the arrival time. So first is that satisfying the time of travel to suffer the time from the given equation. And we have B equals distance divided by the speed. The distance is 190 miles and the speed is 54.3 mph. We get time here in terms of R. S. S 3.5, So it takes three hours and three hours and 30 minutes to travel, he said distance. So if it's if the bus departs at the at the time of six of clubs, So three hours and 30 minutes after that, it will arrive to Austin. So that means the arrival time will be nine 30 in the morning, So that's three hours and 20 minutes. Oh, after six o'clock. So I hope everything is clear.

What is the minimum work needed to push a 1000 kg car 300 m upa 17.5 degree incline? (a) Ignore friction. (b) Assume theeffective coefficient of friction is 0.25.

Answers

The minimum work needed to push a 1000 kg car 300 m up a 17.5-degree incline

Given by the following steps;

Step-We calculate the gravitational potential energy (GPE) of the car as it's lifted up the incline. This will be equal to the minimum work required to push the car up the incline. The GPE is given by;GPE = mgh. Where m = mass of the car = 1000 kg; g = acceleration due to gravity = 9.81 m/s²; h = height gained = 300 sin(17.5°) = 84.4 mGPE = mgh = 1000 × 9.81 × 84.4 = 829,944 J

Step 2If we consider friction, we can calculate the minimum work required as follows:Total work done = work done against gravity + work done against frictionW = GPE + work done against friction

Where the work done against friction is given by; Wf = friction force × distance × cos(θ)Here θ = angle of incline = 17.5° and the friction force is given by the product of the effective coefficient of friction (µ) and the normal force. The normal force is equal to the component of the weight of the car that acts perpendicular to the incline.Nf = mg cos(θ)Wf = µNf × distance × cos(θ) = µmg cos²(θ) × distance × cos(θ) = µmgdcos²(θ)W = mgh + µmgdcos²(θ)Substituting m, g, h, d, and µ into the equation gives;W = 1000 × 9.81 × 84.4 + 0.25 × 1000 × 9.81 × 300 × cos²(17.5)W = 1,454,392 J

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What is promising evidence of a habitat that might support life
on the planet Mars?
Detailed Answer please, will give thumb up rating definitely

Answers

A promising evidence of a habitat that might support life on the planet Mars is water.

There is evidence supporting the existence of liquid water on Mars from numerous sources. The finding of repeated black streaks on Martian slopes and the presence of hydrated minerals suggest the potential of seasonal or location-specific briny water flows. A necessary component of life as known is liquid water.

Additionally, Mars possesses underground ecosystems that could provide defence against radiation and severe surface conditions. Researchers have found evidence of ancient underground hydrothermal systems as well as beneath ice. These settings might offer consistent conditions for the development of microbial life.  Methane gas has been found in the Martian atmosphere, along with variations over time, and this has led to questions regarding its origin. Both geological and biological processes can result in the production of methane.

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QUESTION
Energy can only be used in it's original
form.
false
true

Answers

Answer:

False

Explanation:

Energy keeps on converting from one form to another and it is useful in each of its forms.

For instance, the kinetic energy get converts into potential energy, mechanical energy of motor converts into electrical energy, sound energy (phone) converts into electrical energy etc. but in all these forms energy is useful in one or the other way.

Hence, the given statement is false.

A stone is thrown horizontally from the top of a 25.00-m cliff. The stone lands at a distance of
40.00 m from the edge of the cliff. What is the initial horizontal velocity of the stone?

Answers

The time taken to fall t
s= 1/2 g t^2
25 = 1/2 x 9.8 x t^2
t^2= 5.1
t= 2.26 s

Horizontal velocity = 40/2.26 = 17.6 m/s

The projectiles launch allows to find the answer for the initial velocity of the stone is:

            v = 17.71 m / s

Projectile launching is an application of kinematics for motion in two dimensions, where there is no acceleration on the x axis and the acceleration on the y axis is the gravity acceleration.

In the attached diagram we can see a corner of the movement. Where the x axis is horizontal and the y axis is vertical, where the zero of the system is at the base of the cliff

In this case the stone is thrown horizontally, therefore its initial vertical speed is zero, let's find the time it takes to reach the base of the cliff

           y = y₀ + \(v_{oy}\) t - ½ g t²

where y and y₀ are the current and initial position, \(v_{oy}\) is the initial vertical velocity, g the acceleration of gravity and t the time

When reaching the bottom its height is zero (y = 0) and the highest part its initial height is y₀ = 25.00 m

           0 =y₀ + 0 - ½ g t²

          t = \(\sqrt{\frac{2y_o}{g} }\)

Let'se calculate

           \(t = \sqrt{ \frac{2 \ 2.25 }{9.8 } }\)

           t = 2,259 s

They indicate that the stone fell at a horizontal distance of 40 m,

           x = \(v_{ox}\) t

            v_{ox} = \(\frac{x}{t}\)

           v_{ox}  = \(\frac{40}{2.259}\)

           v_{ox} = 17.71 m / s

In conclusion, using theprojectiles launch we can find the answer for the initial velocity of the stone is:

            v = 17.71 m / s

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A stone is thrown horizontally from the top of a 25.00-m cliff. The stone lands at a distance of40.00

3 – Marshmallow Muscles Larry was told that a certain muscle cream was the newest best thing on the market and claims to double a person’s muscle power when used as part of a muscle-building workout. Interested in this product, he buys the special muscle cream and recruits Patrick and SpongeBob to help him with an experiment. Larry develops a special marshmallow weight-lifting program for Patrick and SpongeBob. He meets with them once every day for a period of 2 weeks and keeps track of their results. Before each session Patrick’s arms and back are lathered in the muscle cream, while Sponge Bob’s arms and back are lathered with the regular lotion.
Control Group __________________________ Experimental Group ____________________________


Independent Variable _________________________ Dependent Variable ________________________


Constants ___________________________________________________________________________
What should the conclusion be?

Answers

Control Group: SpongeBob's arms and back lathered with regular lotion.

Experimental Group: Patrick's arms and back lathered with the special muscle cream.Independent Variable: The type of lotion used (Special muscle cream vs regular lotion)Dependent Variable: Muscle strength and powerConstants: Same muscle-building workout, same duration of the experiment, same initial muscle strength, same diet, and same environmental conditions.

The conclusion should be based on the results of the experiment, for example, if the results show that Patrick's muscle strength and power increased more than SpongeBob's after using the special muscle cream, it would be reasonable to conclude that the muscle cream has a positive effect on muscle strength and power when used as part of a muscle-building workout.

What is the experiment about?

A single experiment is not enough to prove that the muscle cream is effective in increasing muscle strength and power. The experiment should be repeated multiple times with different sample groups and the results should be consistent.

Additionally, the muscle cream should be tested against other muscle-building products and compared to a control group that does not use any muscle-building products.

However, it's important to note that this conclusion is only valid if the experiment is well-designed and executed, and the results are accurately and objectively measured. Additionally, the experiment should be repeated with a larger sample size and over a longer period of time to increase the confidence in the conclusion.

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Which is not true about the variables in the relationship F = ma?

A. Acceleration is directly proportional to mass.

B. Force is directly proportional to mass.


C. Force is directly proportional to acceleration.

D. Acceleration will double if force is doubled.​

Answers

Answer:

A

Explanation:

Because D is definitely true and there is only one false sentence what means if that non of B or C is false because if one is false so other one needs to be too.

What do scientists use to study the patterns and impacts of climate change over time?
A. all of the above
B. tree rings and ice formed thousands of years ago
C. fossilized pollen and tree rings
D. chemical isotopes in foraminifera shells and fossilized pollen

Answers

Scientists use the following to study the patterns and impacts of climate change over time :

Tree rings and ice formed thousands of years agoFossilized pollen and tree ringsChemical isotopes in foraminifera shells and fossilized pollen

What is Climate?

This is defined as the atmospheric condition of a place over a long period of time.

Scientists use physical, chemical and biological methods to study impacts of climate change which makes option A the most appropriate.

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