Find the pH of a buffer that consists of 0.63 M HBrO and 0.49 M KBrO (pKa of HBrO = 8.64). pH = ____

Answer is C my g. Don't really know how to explain it.

It is 194.88 moles of oxygen that the chemical engineer determined in the sample of methyl tert-butyl ether if there are 81.2 moles of carbon

If C5H12O the formula of methyl tert-butyl ether, it is observed that there are 5 hydrogen atoms for every 12 oxygen atoms

And if each mole contains exactly 6.022 × 10∧23 atoms, according to Avogadro's number, then a simple rule of thumb can determine how many hydrogen atoms are present.

1 mole ------------- 6.022 ×10∧23

81.2 moles ----------- x

X = 81.2 x 6.022 140 76×10∧23

x = 488,986 x 10∧23

Once again, by the rule of three, the amount of elementary oxygen particles is determined.

 5 H atoms ---------- 12 O atoms

488.986 x ×1023 H ------ x O

X = 488,986 x ×10∧23 x 12 /5

X = 1173.567 x 10∧23

And with the rule of three and Avogadro's number, the number of moles of oxygen is also determined.

6.022 ×1023 ------------- 1 mol

1173.567 x 1023----------- x mol

X moles = 1173.567 x 10∧23 x 1 / 6.022 x 10∧23

X = 194.88 moles

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Silver chloride, often used in silver plating, contains 75.27% Ag. 450mg is the  mass of silver chloride in grams required to make 4.4 g of silver plating.

Silver is stable in clean air and clean water, but tarnishes whenever subjected to ozone, hydrogen sulfide, especially sulfurous air. Silver is largely utilized in electroplating for industrial purposes, notably electrical connections.

1 mole of AgCl, 0.7527 mol of Ag present.

1 mol of Ag is obtained from 1/0.75mol of AgCl

number of moles =  4.4 g / 107.87=0.002mol

0.002364 mol of Ag will be obtained from 0.002mol/ 0.7527 =0.003 mol

mass = moles × molar mass

        = 0.03 × 143.3=0.450g=450mg

Therefore, 450mg is the  mass of silver chloride in grams required to make 4.4 g of silver plating.

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There are approximately 12.7 grams of phosphorus in a 50-gram sample of aluminum phosphate.

To determine the number of grams of phosphorus in a 50-gram sample of aluminum phosphate, we need to know the molar mass and the chemical formula of aluminum phosphate.

The chemical formula for aluminum phosphate is AlPO4. It indicates that each molecule of aluminum phosphate contains one aluminum atom (Al), one phosphorus atom (P), and four oxygen atoms (O).

To calculate the molar mass of aluminum phosphate, we can add up the atomic masses of its constituent elements based on their stoichiometric ratios:

Molar mass of AlPO4 = (molar mass of Al) + (molar mass of P) + (4 * molar mass of O)

Using the periodic table, we can find the atomic masses of the elements:

Molar mass of Al = 26.98 g/mol

Molar mass of P = 30.97 g/mol

Molar mass of O = 16.00 g/mol

Now, let's calculate the molar mass of aluminum phosphate:

Molar mass of AlPO4 = (26.98 g/mol) + (30.97 g/mol) + (4 * 16.00 g/mol)

= 121.95 g/mol

The molar mass of aluminum phosphate is 121.95 g/mol.

To determine the number of grams of phosphorus in a 50-gram sample of aluminum phosphate, we need to calculate the mass fraction of phosphorus in the compound. The mass fraction is the ratio of the molar mass of phosphorus to the molar mass of aluminum phosphate.

Mass fraction of phosphorus = (molar mass of P) / (molar mass of AlPO4)

= (30.97 g/mol) / (121.95 g/mol)

≈ 0.254

Multiplying the mass fraction by the mass of the sample gives us the grams of phosphorus:

Grams of phosphorus = (mass fraction of phosphorus) * (mass of the sample)

= 0.254 * 50 g

≈ 12.7 g

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Answer: Rutherford's model was the first propose of the existence of small, dense nucleus's.

Explanation: The atom, as described by Ernest Rutherford, has a tiny, massive core called the nucleus. The nucleus has a positive charge. Electrons are particles with a negative charge. Electrons orbit the nucleus. The empty space between the nucleus and the electrons takes up most of the volume of the atom.

Answer: Here is the correct image of the first atomic model it's in the picture!

Explanation: I did it on USA Test Prep to see which one is right

When a sucrose, is added to a solvent, it affects the boiling point of the solvent. This phenomenon is known as boiling point elevation.

Given information,

Mass of water = 1 kg

Moles of sucrose = 2 mol

The boiling point elevation: ΔTb = Kb × m

Where:

ΔTb is the change in boiling point and Kb is the molal boiling point elevation constant, and m is the molality of the solute.

m = (number of moles of solute) / (mass of solvent in kg)

m = 2.0 mol / 1.0 kg = 2.0 mol/kg

The value of Kb for water is approximately 0.512 °C/m.

Now, (ΔTb):

ΔTb = Kb × m

ΔTb = 0.512 °C/m × 2.0 mol/kg

ΔTb = 1.024 °C

Therefore, when 2.0 mol of sucrose is added to 1.0 kg of water, the boiling point of the water will increase by approximately 1.024 °C.

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In each pair, the solution that contains the weaker conjugate acid is more basic. Without any calculations, we can determine which solution is more basic by identifying the stronger conjugate acid in each pair.

In Part A, KClO is a stronger acid than NaF, so the solution in (b) is more basic in Part B, NaBrO is a stronger acid than NaBr, so the solution in (b) is more basic in Part C, HNO2 is a weaker acid than KOH, so the solution in (b) is more basic in Part D, NH4Cl is a weaker acid than HCN, so the solution in (a) is more basic.

It is important to note that while we did not perform any calculations, this method only works for comparing solutions with the same concentration. If the concentrations were different, we would need to perform calculations to determine which solution is more basic. A

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Answer:

magnesium and copper: No reaction

iron and magnesium sulfate: Reaction

Copper and Iron Nitrate: Reaction

magnesium and hydrochloric acid: Reaction

Answer:

Nuclear energy

I'm not sure ok.. Better ask some adult for making sure.

Answer: [Kr] 4d10 5s2 5p5

The density of carbon monoxide gas at 20°C and 98 kPa is 1.145 g/L.

The ideal gas law is PV = nRT

where P is the pressure, V is the volume, n is the number of moles of gas, R is the gas constant, and T is the temperature in kelvin.

To find the density of carbon monoxide gas at 20°C and 98 kPa, we can use the ideal gas law to find the number of moles of gas in 1 L of gas at these conditions and then divide the mass of 1 mole of gas by the number of moles to get the density.

First, we need to convert the temperature to kelvin:

20°C + 273.15 = 293.15 K

Rearranging the ideal gas law, we get:

n = PV/RT

We can assume that the volume is 1 L, so:

n = (98 kPa)(1 L) / [(0.0821 L·atm/mol·K)(293.15 K)] = 0.0413 mol

The molar mass of carbon monoxide is 28.01 g/mol, so the mass of 0.0413 mol is:

0.0413 mol x 28.01 g/mol = 1.152 g

Therefore, the density of carbon monoxide gas at 20°C and 98 kPa is:

1.152 g / 1 L = 1.145 g/L

What is density?

Density is a physical property of matter that relates to the amount of mass per unit of volume of a substance. It is typically expressed in units such as grams per cubic centimeter (g/cm³) or kilograms per cubic meter (kg/m³).

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Answer:

2.3 L

Explanation:

A change in pressure-volume at constant temperature is described by the Boyle's law. The mathematical relationship between initial pressure and volume (P₁ and V₁) and final pressure and volume (P₂ and V₂) is given by:

P₁V₁ = P₂V₂

We have the following data:

initial pressure: P₁= 2.5 atm

initial volume: V₁ = 9.1 L

final pressure: P₂= 9.8 atm

Thus, we introduce the data in the mathematical expression and calculate the final volume V₂, as follows:

V₂ = P₁V₁/P₂ = (2.5 atm x 9.1 L)/9.8 atm = 2.3 L

Therefore, the volume of the canister is 2.3 L.

Decomposition reaction results in the formation of the products by splitting the reactants. Moles of mercury(ii) oxide needed are 15.63 moles.

Moles are the ratio of mass and the molar mass of the compound or the molecule.

Moles of oxygen are calculated as:

\(\begin{aligned}\rm n &= \rm \dfrac {mass}{molar\; mass}\\\\&= \dfrac{250}{32}\\\\&= 7.8125 \;\rm moles\end{aligned}\)

The balanced chemical reaction can be shown as,

\(\rm 2HgO \rightarrow 2Hg + O_{2}\)

From the reaction, it can be said that 1 mole of oxygen requires 2 moles of mercury oxide.

Moles of mercury oxide are calculated as:

\(\begin{aligned} \rm n HgO& = (7.8125 \;\rm moles \; O_{2}) \times (\dfrac{2 \;\rm moles\; HgO}{1 \;\rm mole \; O_{2}})\\\\\rm n HgO &= 15.625 \;\rm moles \end{aligned}\)

Therefore, option C. 15.63 moles of mercury (II) oxide is needed.

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Answer:

no, but they contain a compound plant called amygdalin, so technocly yes

Explanation:

Using the mole concept, in a 5 M glucose solution, 1 mole of glucose would be contain in 200 mililitres that is volume of glucose is 200 ml.

The mole concept is very significant and useful in chemistry. It express the amounts of reactants as well as products that are consumed and formed during a chemical reaction. In the question, we have to calculate the volume of the glucose solution and we have

Molarity of glucose = 5 M

Number of moles = 1 moles

Volume of solution =?

Molarity of solution tells us the number moles of solute that is present in 1 L of solution.

Molarity(M) = moles of solute in 1 litre of solution

Using formula of molarity to calculate the volume of solution in liters and we will later on convert it into the desired unit i.e. millilitres. Substitute the all known values in the formula of molarity,

Molarity(M) = moles of solute/volume of solution

Volume of solution in litres = Moles of solute/ Molarity

=> Volume of glucose, V = 1 mol/5 mol/litre

=> V = 1/5 litre

Unit conversion from litres to mililiters:

1 litre = 1000 mililiters

so, Volume of glucose = 1000× 1/5 mililiters

Volume of glucose = 1000/5 = 200 ml

Hence, required value of volume is 200 mililiters.

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Calcium carbonate (CaCO3) is an important component of coral reefs. 0.986 moles are in 98.6 g of CaCO3.

The term mole is defined as the amount of substance of a system which contains as many elementary entities.

One mole of any substance is equal to 6.023 × 10²³ units of that substance such as atoms, molecules, or ions. The number 6.023 × 10²³ is called as Avogadro's number or Avogadro's constant.

Number of moles of CaCO3 = Mass / Molar mass

Number of moles of CaCO3 = 98.6 g / 100g/ mol

= 0.986 moles

The balanced chemical equation of this reaction is as follows:

CaCO₃ → CaO + CO₂

Therefore, the reaction ratio is 1:1:1.

So, 0.986 moles of CaO are formed.

Thus, 98.6 g CaCO3 = 0.986 moles CaCO3.

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Answer:

B) It is not balanced for oxidation state or for number of atoms

Explanation:

I got this question correct on my Edge quiz, so I know that this is the right answer.

The reactant side has 2 oxygen atoms, while the product side only has 1. This means the mass isn't balenced. In addition, the oxidation (charge) on the reactant side is 0, while it's -2 on the product side. This means the oxidation nor mass is balenced.

Hope that helps you!

Answer:

b

Explanation:

A single absorption band is not sufficient to distinguish between water vapor and carbon dioxide in the gas phase.

In the gas phase, both water vapor (H2O) and carbon dioxide (CO2) exhibit multiple absorption bands in the infrared region of the electromagnetic spectrum. Each molecule has its unique set of vibrational and rotational modes, which result in specific absorption frequencies. While there may be some overlap in the absorption bands of water vapor and carbon dioxide, their distinct molecular structures and vibrational characteristics lead to different absorption patterns.

To accurately differentiate between water vapor and carbon dioxide, multiple absorption bands need to be examined. Spectroscopic techniques such as infrared spectroscopy or laser absorption spectroscopy can be employed, where the absorption spectra of the gases are compared with known reference spectra or analyzed using computational methods. By examining the absorption peaks and their corresponding wavelengths, it becomes possible to identify the presence of water vapor or carbon dioxide and determine their respective concentrations.

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According to the information in the graph, it can be inferred that the amount of solute that will precipitate out of solution at 20°C is 130 grams.

To calculate the amount of solute that precipitates out of solution we must identify the solute data at 80°C and 20°C and identify the difference as shown below:

According to the above, the amount of solute that will precipitate out of solution due to the change in temperature is 130 grams of KNO3.

Note: This question is incomplete because the graph is missing. Here is the graph

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Answer:

b

Explanation:

[H3O+] = 10-pH = 10-3.4 ≅ 3.981 x 10^-4 moles/liter

you should plan to Titrate a maximum of 0.679 grams of KHP at a time using your 0.1 M NaOH solution and 50.00 mL burette.

1. Determine the maximum volume of NaOH solution to be used: Since it's recommended to use not more than two-thirds of the burette's capacity, we will calculate two-thirds of 50.00 mL.

(2/3) × 50.00 mL = 33.33 mL

2. Convert the volume of NaOH solution to moles: We have a 0.1 M NaOH solution, and we will use 33.33 mL of it. To find the moles of NaOH, we multiply the volume (in liters) by the molarity.

0.1 mol/L × (33.33 mL ÷ 1000) = 0.00333 mol NaOH

3. Determine the stoichiometry of the reaction: In the reaction between NaOH and KHP (C₈H₅KO₄), the stoichiometry is 1:1, meaning one mole of NaOH reacts with one mole of KHP.

4. Calculate the moles of KHP: Since the stoichiometry is 1:1, the moles of KHP required will be the same as the moles of NaOH.

0.00333 mol KHP

5. Convert moles of KHP to grams: To find the maximum grams of KHP to titrate at a time, we multiply the moles of KHP by its molecular weight (204.22 g/mol).

0.00333 mol × 204.22 g/mol = 0.679 g KHP

So, you should plan to titrate a maximum of 0.679 grams of KHP at a time using your 0.1 M NaOH solution and 50.00 mL burette.

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Answer:

producer of t4he food chain is the grass,the producer gets is enrgy7 by the sun and i dont4 know number 2 that4s all i know sorry

Explanation:

Water will experience a 5230 joule heat change.

What is heat change of water ?

One of its most crucial properties is the fact that heating water uses a lot of energy. To be precise, 4,184 joules of water must absorb one calorie of heat for every degree Celsius that the temperature rises. For comparison, it takes just 385 joules of heat to heat one kilogram of copper to one degree Celsius.

Specific heat capacity of water

=4.184j/g. o C

Q= m water x C water x (T f - TI)

=250.0g x4184jj/g .o C x(25.0 -20.0)o c

=5230 joules

What is heat capacity?

The ratio of heat absorbed to temperature change by a material is known as heat capacity. The actual amount of material being considered, which is often a mole, is typically expressed as calories per degree (the molecular weight in grams).

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Answer:

B. Lithium (Li) and iodine (1)

Explanation:

Ionic bond is a type of chemical bond that is formed between a metallic element and a non metallic element. The positive charge of the metallic ion is attracted to the negative charge of the non metallic ion to form an ionic bond.

According to the options given in this question, lithium and iodine will form an IONIC bond because lithium is a cation (+ve ion) while iodine is an anion (-ve).

The cell reaction is Ag(aq) + Cr3+(aq) → Ag(s) + Cr2+(aq). The standard cell potential is 0.742 V.

A voltaic cell is a device that utilizes a spontaneous chemical reaction to generate electricity. A half-cell is a component of the voltaic cell that contains either an oxidizing or reducing agent.

The salt bridge is used to connect the two half-cells and prevent mixing of the solutions.The given cell reaction is Ag(aq) + Cr3+(aq) → Ag(s) + Cr2+(aq).

This reaction takes place in two half-cells.

In one half-cell, Ag is oxidized to Ag+.

In the other half-cell, Cr3+ is reduced to Cr2+.

The cell potential, Ecell, can be calculated using the Nernst equation:

Ecell = E°cell - (RT/nF)

lnQwhere E°cell is the standard cell potential,

R is the gas constant,

T is temperature in kelvin,

n is the number of electrons transferred in the reaction,

F is the Faraday constant, and

Q is the reaction quotient.

The standard cell potential for the given cell reaction is 0.742 V.

Therefore, the cell generates 0.742 volts of electrical potential difference.

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A) The value of Ka for the weak acid C₆H₅NH₃⁺ is approximately 5.03 × 10⁻¹¹.

b) The value of Kb for the weak base ClO⁻ is approximately 1.86 × 10⁻⁵.

A) For the weak acid C₆H₅NH₃⁺, the equilibrium expression for Ka is given by: Ka = [C₆H₅NH₂][H₃O⁺] / [C₆H₅NH₃⁺].

[C₆H₅NH₃⁺] = 0.233 M

[C₆H₅NH₂] = 2.3 × 10⁻³ M

[H₃O⁺] = 2.3 × 10⁻³ M

Plugging these values into the Ka expression:

Ka = (2.3 × 10⁻³ M)(2.3 × 10⁻³ M) / (0.233 M)

Ka ≈ 5.03 × 10⁻¹¹

b) For the weak base ClO⁻, the equilibrium expression for Kb is given by: Kb = [OH⁻][HClO] / [ClO⁻].

[OH⁻] = 4.0 × 10⁻⁴ M

[HClO] = 2.38 × 10⁻⁵ M

[ClO⁻] = 0.273 M

Plugging these values into the Kb expression:

Kb = (4.0 × 10⁻⁴ M)(2.38 × 10⁻⁵ M) / (0.273 M)

Kb ≈ 1.86 × 10⁻⁵

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When a cell is placed in a solution with a very low solute concentration, water diffuses into the cell. such a solution is called a hypotonic solution. Subtract the solute's mass from the total volume of the solution.  Divide the figures you found for mass and volume to find the concentration of your solution.

The overall solute concentration of a solution is described by its osmolarity. A solution with a low osmolarity has more water molecules than solute particles; a solution with a high osmolarity contains fewer water molecules than solute particles. Solute concentration is defined as the amount of solutes and particles dissolved in a solution.

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The pair of elements that will form an ionic compound are magnesium and oxygen. Ionic compounds are formed when one element donates electrons to another element. In this case, magnesium donates two electrons to oxygen, resulting in the formation of magnesium oxide (MgO).

The transfer of electrons from magnesium to oxygen creates ions with opposite charges - magnesium becomes a positively charged ion (cation) and oxygen becomes a negatively charged ion (anion). This type of bond is characterized by the strong electrostatic forces between the ions.

Other examples of ionic compounds include sodium chloride (NaCl) and potassium iodide (KI). In these compounds, sodium, potassium, and iodine also donate electrons to chlorine and iodine atoms respectively.

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According to Henderson-Hasselbalch equation you need to prepare a buffer solution with a pH of 4.00, using NaF and HF. 0.42 ratio of [base]/[acid] should be used in making the buffer. The correct answer is B.

We can use the Henderson-Hasselbalch equation to calculate the ratio of [base]/[acid] required to create a buffer with a pH of 4.00.

pH = pKa + log([base]/[acid])

Substituting pH = 4.00 and pKa = -log(7.2 × 10^-4) = 3.12, we get:

4.00 = 3.12 + log([base]/[acid])

0.88 = log([base]/[acid])

10^0.88 = [base]/[acid]

0.42 = [base]/[acid]

Therefore, the ratio of [base]/[acid] required to create a buffer with a pH of 4.00 using NaF and HF is 0.42. The correct option is B, [base]/[acid] = 0.42.

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