The temperature of an ideal gas being quasi-statically compressed by 700 j of work to one-third of its initial volume can be found using the first law of thermodynamics, which states that the change in internal energy of a system is equal to the work done on the system plus the heat added to the system.
Since the gas is considered ideal, the heat added is assumed to be zero. Therefore, the change in internal energy is simply equal to the work done, which is 700 j. Since internal energy is proportional to temperature, the temperature of the gas can be found by dividing the work done by the gas's specific heat capacity.
The temperature will increase as the gas is compressed, and the final temperature can be determined by multiplying the initial temperature by the ratio of the final volume to the initial volume. In this case, the final temperature would be three times the initial temperature.
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A 1.0 kg rock is suspended by a massless string from one end of a 1 m measuring stick. What is the mass of the measuring stick if is balanced by a support force at the 0.25 m mark? Hint1: There is NO need to break up the measuring stick into left and right. Just consider it as an extended object. Where is its weight applied? Hint2: Draw the forces acting on the measuring stick. ○ 0.25 kg O 0.5 kg ○ 1.0 ㎏ ○ 2.0 kg O 4.0 kg
The mass of the measuring stick if it is balanced by a support force at the 0.25 m mark is 0.75 kg.The mass of the measuring stick can be found using the principles of torque.
Given that a 1.0 kg rock is suspended by a massless string from one end of a 1 m measuring stick, and is balanced by a support force at the 0.25 m mark. Thus, taking clockwise as the negative direction of torque and counterclockwise as the positive direction, the torques at the 0.25 m mark are:T clockwise = weight of the rock x distance from support forceT clockwise = (1.0 kg)(9.8 m/s²)(0.75 m) = 7.35 NmT counterclockwise = weight of the measuring stick x distance from support forceT counterclockwise = (mass of measuring stick)(9.8 m/s²)(0.25 m) = 2.45 NmFor balance, T clockwise = T counterclockwise. Substituting values,7.35 Nm = 2.45 Nm(mass of measuring stick) = (7.35 Nm)/(2.45 Nm) = 3 kg.
Therefore, the mass of the measuring stick is 3 kg.Subtracting the weight of the rock, the mass of the measuring stick is:mass of measuring stick = 3 kg - 1 kg = 2 kgSo, the mass of the measuring stick if it is balanced by a support force at the 0.25 m mark is 0.75 kg.
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A manometer using oil (density 0.900 g/cm 3 ) as a fluid is connected to an air tank. Suddenly the pressure in the tank increases by 8.03mmHg. Density of mercury is 13.6 g/cm 3
. By how much does the fluid level rise in the side of the manometer that is open to the atmosphere?
The fluid level in the open side of the manometer rises by 9.77 mm.
The pressure difference between the inside of the tank and the atmospheric pressure can be calculated using a manometer.
A manometer can be used to measure fluid pressure. It can also be used to measure the density of a liquid. A manometer that uses oil as the fluid is connected to an air tank.
When the pressure in the tank suddenly increases by 8.03 mmHg, the fluid level rises in the open side of the manometer. The density of oil is 0.900 g/cm3.
The density of mercury is 13.6 g/cm3. The pressure difference between the inside of the tank and the atmospheric pressure can be calculated using the manometer's fluid level. We know that ΔP = ρgh and that ρmercury > ρoil. Therefore, hoil < hmercury.
So, we use the density of mercury to calculate the height difference. Let's say the height difference is hmercury.
ΔP = ρghmercury + ρairgΔh
= ΔP = 8.03 mmHg
= 8.03 × 1.01325 × 10-3 mHg/mmHg
= 0.00816 mHg. (Atmospheric pressure = 1.01325 × 105 Pa).
We can calculate the height difference using the density of mercury.
Δh = (ΔP - ρoilghoil)/ρairg
= (0.00816 - 0.9 × 9.81 × hoil)/101325
= (0.00816 - 8.83 hoil) × 10-5 m.
We can now calculate hoil as follows: hoil = (0.00816 × 105)/(8.83 × 9.81)
= 9.77 mm.
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A car is moving at a velocity of 25 km/h and increases velocity to 1200 km/h in 2 min. what is the acceleration?
plz help me out, thanks guys
Answer:
a = 2.72 [m/s2]
Explanation:
To solve this problem we must use the following kinematics equation:
\(v_{f} =v_{o} + a*t\)
where:
Vf = final velocity = 1200 [km/h]
Vo = initial velocity = 25 [km/h]
t = time = 2 [min] = 2/60 = 0.0333 [h]
1200 = 25 + (a*0.0333)
a = 35250.35 [km/h2]
if we convert these units to units of meters per second squared
\(35250.35[\frac{km}{h^{2} }]*(\frac{1}{3600^{2} })*[\frac{h^{2} }{s^{2} } ]*(\frac{1000}{1} )*[\frac{m}{km} ] = 2.72 [\frac{m}{s^{2} } ]\)
An electron’s position cannot be known precisely. Only its probability of being in a certain location can be known true or false?.
The exact position of an electron cannot be known. Instead, we can calculate the probability that an electron is in a specific area based on electron cloud model.
What is electron cloud model?
The electron cloud model is a model of an atom in which the atom consists of a small but massive nucleus surrounded by a cloud of rapidly moving electrons.
The electron cloud model says that we cannot know exactly where an electron is at any given time, but the electrons are more likely to be in specific areas.
Thus, the exact position of an electron cannot be known. Instead, we can calculate the probability that an electron is in a specific area based on electron cloud model.
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Helium gas is compressed by an adiabatic compressor from an initial state of 14 psia and 50°F to a final temperature of 320°F in a reversible manner. Determine the exit pressure of helium.
Answer:
The value is \(P_2 = 40.54 \ psla\)
Explanation:
From the question we are told that
The initial pressure is \(P_1 = 14\ psla\)
The initial temperature is \(T_1 = 50 \ F = (50 - 32) * [\frac{5}{9} ] + 273 = 283 \ K\)
The final temperature is \(T_2 = 320 \ F = (320 - 32) * [\frac{5}{9} ] + 273 =433 \ K\)
Generally the equation for adiabatic process is mathematically represented as
\(PT^{\frac{\gamma}{1- \gamma} } = Constant\)
=> \(P_1T_1^{\frac{\gamma}{1- \gamma} } = P_2T_2^{\frac{\gamma}{1- \gamma} }\)
Generally for a monoatomic gas \(\gamma = \frac{5}{3}\)
So
\(14 * 283^{\frac{\frac{5}{3} }{1- [\frac{5}{3} ]} } =P_2 * 433^{\frac{\frac{5}{3} }{1- [\frac{5}{3} ]} }\)
=> \(14 * 283^{-2.5} =P_2 * 433^{-2.5}\)
=> \(P_2 = 40.54 \ psla\)
If a wave vibrates back and forth 12 times each second, what is period of the wave?
Answer:
I think it might be 9 hz but not 100% shore though
Explanation:
How is Pythagorean Theorem used in baseball?
Bill James came up with the Pythagorean Theorem of Baseball, which connects the amount of runs a club has scored and given up to its actual winning %.
Its uses are:The Pythagorean Theorem is the idea that a baseball team's record may be roughly estimated by taking the square of team runs scored and dividing it by the square of team runs scored plus the square of team runs allowed. Bill James, a baseball analyst, made this idea famous.
The Pythagorean Winning % approach uses the relationship between a team's victories and losses and the number of points scored and allowed to calculate the predicted winning percentage. To follow Pythagorean winning percentages for the seasons, consult the team statistics.
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Which of the 4 necessities of life can Mars easily provide for us now?
Astronauts could use Mars's natural resources to grow food. Mars's atmosphere consists mostly of carbon dioxide, an essential gas for plant survival, and Martian soil has the essential nutrients plants need to survive.
¿Cuál de las siguientes no es un tipo de fuerza de roce
If a 25 kg object is moving at a velocity of 5 m/s, the object has energy
Answer:
Since the KE is proportional to velocity squared, if you increase the KE by a factor of
2
, you increase
v
by a factor of
2
2
=
4
Detailed explanation :
25
=
0.5
⋅
m
⋅
(
5
2
)
Find
m
:
25
=
25
m
2
m
=
2
Hence the new KE:
KE
=
0.5
⋅
2
⋅
10
2
KE
=
100
J
A hammer drives a nail into a piece of wood. Identify an action-reaction pair.Group of answer choicesThe hammer exerts a force on the nail; the wood exerts a force on the nail.The hammer exerts a force on the nail; the hammer exerts a force on the wood.The nail exerts a force on the hammer; the hammer exerts a force on the wood.The hammer exerts a force on the nail; the nail exerts a force on the hammer.
Newton's third law states that if an object A exerts a force on object B, then object B must exert a force of equal magnitude and opposite direction back on object A.
Let:
A = Hammer
B = Nail
so:
\(F_{AB}=-F_{BA}\)Therefore:
The hammer exerts a force on the nail; the nail exerts a force on the hammer.
A radio announcer's voice is transmitted via radio waves a distance of 998.25 km. How much time, in microseconds, will it take to transmit the wave over this distance?
A radio wave travels at the speed of light, which is equal to approximately 300,000 km/s.
So, to travel a distance of 998.25 km, the time needed is:
\(\begin{gathered} distance=speed\cdot time\\ \\ 998.25=300000\cdot time\\ \\ time=\frac{998.25}{300000}\\ \\ time=0.0033275\text{ seconds}\\ \\ time=3327.5\text{ microseconds} \end{gathered}\)Therefore the time required is approximately 3327.5 microseconds.
The surface of which jovian moon most resembles the pack ice of the Arctic Ocean? A) Amalthea B) Io C) Europa D) Ganymede E) Callisto.
15 percent input work is lost due to friction,then what is the efficiency of machine?
Answer:
{ (x/y )*100 } - 0.15 y
Explanation:
The efficiency of a machine is the percent of output work divided by input work minus work lost from friction and heat.
Assume work output = x
Assume work input percent as =y
Work lost through friction is given as : 15% input work = 0.15 y
Then efficiency of the machine will be :{ (x/y )*100 }- 0.15 y
Use real values for x and y to find the correct efficiency of the machine.
If a book with a mass of 5.0 kg, is pushed across a table with a net force of 30. N, what is its acceleration?
Answer:
\(a=6\ m/s^2\)
Explanation:
Given that,
Mass of a block, m = 5 kg
It is pushed with a net force of 30 N
We need to find its acceleration. The net force acting on an object is given by :
F = ma
a is the acceleration of the block
\(a=\dfrac{F}{m}\\\\a=\dfrac{30\ N}{5\ kg}\\\\a=6\ m/s^2\)
So, the acceleration of the block is \(6\ m/s^2\).
what will happen if you increse the amplitude of a drum hit
The sound is perceived as louder if the amplitude increases, and softer if the amplitude decreases. As the amplitude of the sound wave increases, the intensity of the sound increases. Sounds with higher intensities are perceived to be louder.
Low, warm, dark-colored, sinking clouds in Jupiter's atmosphere are known as:
Answer: Low, warm, dark-colored, sinking clouds in Jupiter's atmosphere are known as: belts.
Cuando una persona sube y baja una escalera, Cuanto vale su desplazamiento y cual es la medida de su trayectoria.
Answer:
Primero, definimos el desplazamiento como la distancia entre la posición final y la posición inicial.
Así, si comenzamos abajo, luego subimos la escalera, y luego bajamos, la posición final y la posición inicial serán la misma
por lo que el desplazamiento es igual a cero.
La medida recorrida es el espacio total recorrido.
Es decir, si entre el principio y el final de la escalera hay una distancia D.
La persona que sube y baja, recorre esta distancia dos veces.
Entonces cuando una persona sube y baja la escalera, la medida de su trayectoria será 2*D.
The midpoint of jk is m (3, 7) one endpoint is j(1, -1). find the coordinates of the other endpoint k.
Coordinates of endpoint K: (5, 15)
What are the coordinates of the other endpoint K, given that the midpoint of JK is M(3, 7) and one endpoint is J(1, -1)?To find the coordinates of the other endpoint K, we can use the midpoint formula. The midpoint formula states that the coordinates of the midpoint M between two endpoints J and K can be found by taking the average of the x-coordinates and the average of the y-coordinates.
Given that the midpoint M is (3, 7) and one endpoint J is (1, -1), we can substitute these values into the midpoint formula to find the coordinates of endpoint K.
Let's denote the coordinates of endpoint K as (x, y).
Using the midpoint formula:
x-coordinate of midpoint M = (x-coordinate of J + x-coordinate of K) / 2
3 = (1 + x) / 2
Solving for x:
6 = 1 + x
x = 5
y-coordinate of midpoint M = (y-coordinate of J + y-coordinate of K) / 2
7 = (-1 + y) / 2
Solving for y:
14 = -1 + y
y = 15
Therefore, the coordinates of the other endpoint K are (5, 15).
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Please help I'll mark brainliest NO LINKS
Answer:C
Explanation:
For parallel connection
1/R=1/R1+1/R2+1/R31/R=1/12+1/6+1/41/R=1+2+3/121/R=1/2R=2ohmFor series connection
Net resistance
R=2+3=5ohmwhat is the one standard atmosphere of pressure in kilopascals
One standard atmosphere of pressure in kilopascals is 101.325 kPa.
Standard pressure is equivalent to a pressure of 1 atmosphere, which is defined as 101,325 Pa or 101.3 kPa. Standard pressure is defined as the atmospheric pressure measured at sea level.One atmosphere (atm) is defined as the force per unit area generated by a column of mercury of 760 mm high at 0 °C at the standard acceleration due to gravity.The atmospheric pressure changes with altitude because the column of air above the surface decreases as altitude increases.Kilopascals (kPa) are a larger unit of pressure than pascals. 1 kPa is equal to 1000 Pa.
The standard atmosphere is used in many scientific and engineering calculations. It is also used to measure the pressure of gases and liquids.
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Explain how the shape of a river's stream bed can affect the river's speed and its power to cause erosion.
Answer:
Possiable answer by edge:
The shape of a river’s stream bed affects the speed and eroding power of a river by influencing the amount of friction between the water flowing through the river and the stream bed below. Friction is the force that opposes the motion of one surface as it moves across another surface. In a river, there is friction between the flowing water and the stream bed beneath it. Where a river is deep, less water comes into contact with the stream bed, so there is less friction. The reduced friction means there is less opposition to the water’s motion, so the river flows at a greater speed and has more kinetic energy for erosion. On the other hand, where a river is shallow, more water comes into contact with the stream bed, so there is more friction. The increased friction means there is more opposition to the water’s motion, so the river flows at a lesser speed and has less kinetic energy for erosion. Also, the roughness of a stream bed covered with boulders and other obstacles causes the water to flow through the river in a turbulent fashion. This could cause the river to move slower in some cases or erode more in other cases.
Explanation:
summary of answer:
influencing the amount of friction between the water flowing through the river and the stream bed below.
Which change would decrease the total current, I, flowing through this circuit?
A. Increasing the voltage of the battery
B. Decreasing the length of the wires
C. Rewiring the two resistors in a series
D. Adding a third resistor in parallel
Answer:
A. Increasing the voltage of the battery
Explanation:
The relationship between voltage, V, current, I and resistance, R, is given as follows;
V = I × R
∴ I = V/R
From the above relationship, the current flowing in the circuit is directly proportional to the voltage of the battery, and inversely proportional to the resistance, 'R', of the circuit
Therefore, increasing the voltage, 'V', of the battery, increases the total current, 'I', flowing in the circuit.
what is gas pressure
in fig. 5-64, a force f of mag- nitude 12 n is applied to a fedex box of mass m2 ???? 1.0 kg. the force is directed up a plane tilted by u ???? 37°. the box is connected by a cord to a ups box of mass m1 ????3.0kg on the floor. the floor, plane, and pulley are frictionless, and the masses of the pulley and cord are negligible. what is the tension in the cord?
The tension in the cord is 4.6 N
Applying Newton's Second Law to each box:According to Newton's second law, an object's acceleration is determined by two factors: the net force acting on the object and the mass of the object.
So, if we chose the positive +x uphill for the FedEx box of mass m2= 1.0 kg and +ve axis for m1 = 3.0 kg such that their accelerations have the same magnitude.
As we apply Newton's second law to each box, we discover that:
\(\mathbf{F - T -m_2gsin\theta = m_2a}\)
where;
\(\mathbf{T=m_1a}\)Thus, the first equation can be rewritten as:
\(\mathbf{F-m_2gsin\theta = (m_1+m_2)a}\)
Now, the acceleration moving in the same direction can be computed as:
\(\mathbf{a=\dfrac{12N (1.0 kg)(9.8 \ m/s^2)sin 37^0}{(1.0+3.0)kg}}\)
a = 1.53 m/s²
Finally, the tension \(\mathbf{T=m_1a}\) = (3.0 kg) (1.53 m/s²)
= 4.6 N
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What type of phase change occurs when water vapor in the atmosphere changes to liquid water in clouds?
Answer:
condensation, the process of changing from a gas to a liquid
what do we call a group of objects that orbit a star?
A group of objects that orbit a star is called a planet.
What is star?A small sized object that enlightens in the night sky in the infinite universe.
The group of objects is a large sized object which orbits a star called Sun.
This group of object is called planets.
Thus, a group of objects that orbit a star is called a planet.
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A construction crane is on top of a skyscraper which has height 45m. The crane itself is 10m in height. What is the gravitational potential energy in joules of a 60kg worker who is standing on top of the crane? (Use g=9.81 in your calculations)
Answer:
32340J
Explanation:
Given parameters
Height of skyscraper = 45m
Height of crane = 10m
Mass of worker = 60kg
g = 9.81m
Unknown:
Gravitational potential energy = ?
Solution:
The gravitational potential energy of a body is the energy due to the position of the body.
It is expressed as:
G.P.E = mgh
m is the mass
g is the acceleration due to gravity
h is the height = 45 + 10 = 55m
G.P.E = 60 x 9.8 x 55 = 32340J
By using the Zonal Factor Method and dividing the space into conic zones of 10 ∘
angular width, calculate the total luminous flux of a laminaire with the following luminous intensity distribution. f(y)={ 1500cos 2
γ
0
for 0≤γ≤ 2
π
otherwise
(Unit: cd) Equations given: Φ=∑I y
ZF F
ZF ′
=2π(cosγ 1
−cosγ 2
)
(12 marks) (b) Use the graph paper given, plot the fuminous intensity distribution (Polar curve) of the luminaire in Past (a). What is the type of this luminaire, direct, indirect or directindirect? What is the advantage of using this type of lighting? (7 marks) (c) Task-ambient lighting is said to be an cuergy saving strategy. Explain in what ways this lighting strategy can save energy. (6 marks) (a) By using the Zonal Factor Method and dividing the space into conic zones of 10 ∘
angular width, calculate the total luminous flux of a luminaire with the following luminous intensity distribution. I(γ)={ 1500cos 2
γ
0
for 0≤γ≤ 2
π
otherwise
(Unit: cd) Equations given: Φ=∑I γ
ZF γ
ZF=2π(cosγ 1
−cosγ 2
)
(12 marks) (b) Use the graph paper given, plot the luminous intensity distribution (Polar curve) of the luminaire in Part (a). What is the type of this luminaire, direct, indirect or directindirect? What is the advantage of using this type of lighting? (7 marks) (c) Task-ambient lighting is said to be an energy saving strategy. Explain in what ways this light ing strategy can save energy.
The total luminous flux of the luminaire can be calculated using the Zonal Factor Method and dividing the space into conic zones of 10° angular width. The luminous intensity distribution is given by f(y) = 1500cos²γ₀ for 0≤γ≤2π, otherwise 0 (Unit: cd).
First, determine the values of γ₁ and γ₂ for each zone. Since the zones have an angular width of 10°, we can calculate γ₁ and γ₂ as follows:
γ₁ = zone number * 10°
γ₂ = (zone number + 1) * 10°
Next, calculate the Zonal Factor (ZF) for each zone using the equation ZF = 2π(cosγ₁ − cosγ₂).
Then, calculate the luminous flux Φ for each zone using the equation Φ = ∑(Iγ * ZF).
Finally, sum up the luminous flux values for all zones to obtain the total luminous flux of the luminaire.
To determine the type of luminaire (direct, indirect, or direct-indirect), we need to analyze the polar curve of the luminous intensity distribution. Plot the values of f(y) on the graph paper provided, indicating the angle (γ) on the x-axis and the luminous intensity (f(y)) on the y-axis. Based on the shape of the curve, determine whether the luminaire emits light predominantly in the upward direction (indirect), downward direction (direct), or both (direct-indirect).
The advantage of using this type of lighting is that it provides a combination of direct and indirect lighting, which can enhance the overall illumination in a space. Direct lighting illuminates the immediate environment, while indirect lighting bounces light off surfaces, providing a more diffuse and ambient illumination. This combination creates a visually comfortable and balanced lighting environment.
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Can the sun explain global warming? ( 2 points) Suppose that the Earth has warmed up by 1 K in the last hundred years. i) How much would the solar constant have to increase to explain this? ii) Compare this to the observed fluctuation of the solar constant over the past 400 years (shown in class) For part (i), begin with the standard 'blackbody' calculation from class, that is: set α=0.30, and assume that the Earth acts as a blackbody in the infrared.
No, the sun cannot explain global warming. Global warming is a phenomenon in which the temperature of the Earth's surface and atmosphere is rising continuously due to human activities such as deforestation, burning of fossil fuels, and industrialization.
This increase in temperature cannot be explained only by an increase in solar radiation.There are several factors which contribute to global warming, including greenhouse gases such as carbon dioxide, methane, and water vapor. These gases trap heat in the Earth's atmosphere, which causes the planet's temperature to rise. The sun's radiation does contribute to global warming, but it is not the main cause.
i) To calculate the increase in solar radiation that would cause the Earth to warm up by 1 K, we can use the following formula:ΔS = ΔT / αWhere ΔS is the increase in solar constant, ΔT is the increase in temperature, and α is the Earth's albedo (reflectivity).α = 0.30 is the standard value used for the Earth's albedo.ΔS = ΔT / αΔS = 1 K / 0.30ΔS = 3.33 W/m2So, to explain the increase in temperature of 1 K over the last hundred years, the solar constant would need to increase by 3.33 W/m2.
ii) The observed fluctuation of the solar constant over the past 400 years has been around 0.1% to 0.2%. This is much smaller than the 3.33 W/m2 required to explain the increase in temperature of 1 K over the last hundred years. Therefore, it is unlikely that the sun is the main cause of global warming.
The sun cannot explain global warming. While the sun's radiation does contribute to global warming, it is not the main cause. The main cause of global warming is human activities, particularly the burning of fossil fuels, which release large amounts of greenhouse gases into the atmosphere.
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