If you could somehow travel at a jet-plane speed of 2800 km/h, it would take approximately 1.20 × 10^9 years to cover a distance equivalent to one light-year.
To determine the time it would take to travel a certain distance at jet-plane speed, we need to know the distance that needs to be covered. However, in this case, the distance mentioned is one light-year, which is approximately 9.46×10^12 km.
If we consider traveling at a jet-plane speed of 2800 km/h, it is still significantly slower compared to the immense distance of one light-year. Let's calculate the time it would take to cover this distance.
Time = Distance / Speed
Time = (9.46×10^12 km) / (2800 km/h)
Converting the units, we have:
Time = (9.46×10^12 km) / (2800 km/h) * (1 h / 3600 s) * (1 year / 365 days) * (1 day / 24 h)
Calculating this, we get:
Time ≈ 1.20 × 10^9 years
Therefore, if you could somehow travel at a jet-plane speed of 2800 km/h, it would take approximately 1.20 × 10^9 years to cover a distance equivalent to one light-year.
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PLEASE HELP QUICKLY 50 POINTS
Fracturing can emit ______waves through the ground.
Answer:
Fracturing can emit seismic waves through the ground.
Explanation:
I believe the answer is seismic, I've studied this before.
A tandem bike is a bike designed for two riders. Rider 1 is pushing on the pedals with a force of 30 N and Rider 2 is pushing on the pedals with a force of 20 N. The total mass of both riders and the tandem bike is 150.0 kg. What is the approximate acceleration of the riders on the bike?
The approximate acceleration of the riders on the bike is 3 m/sec².
What is acceleration?The rate at which an item changes its velocity is known as acceleration, a vector quantity. If an object's velocity is changing, it is acceleration.The net acceleration that objects get as a result of the combined action of gravity and centrifugal force is known as the Earth's gravity, or g. It is a vector quantity whose strength or magnitude is determined by the norm and whose direction correlates with a plumb bob.
Given total force applied = 30 + 20 = 50 N
Mass of two riders = 150 Kg
So, the acceleration = 150 /50 = 3 m/sec².
The approximate acceleration of the riders on the bike is 3 m/sec².
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Energy is...
a. motion
b. stored power as heat
c. power
d. the ability to do work or cause change?
Answer:
c
Explanation:
Answer:
it's d
Explanation:
because if you had energy you could do anything but without energy you won't be able to so anything
hope this helps
A dense mix of dry, hot rock fragments and hot gas erupting from volcanic vents at high speed is pyroclastic flow. lahar. fumarole. tephra.
Magma is called for the dense mix of dry hot rock fragments and hot gas erupting from volcanic vent at high speed.
What is magma?Magma is the extremely hot liquid and flows under the surface of the earth. When this liquid comes out to the surface of earth, then called as lava.
Gas bubble, making up to lave are energetic in nature, because they keep on expanding in all directions, they will go all out to the only open are of a volcano, the vent, in an upward direction.
Hence Magma is called for the dense mix of dry hot rock fragments and hot gas erupting from volcanic vent at high speed.
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A cartoon shows two friends watching an unoccupied car in free fall after it has rolled off a diff. One friend says to the other, "It goes from zero to sixty mphin about three seconds." Is this statement correct? (Note that 60 mph converts to 26.8 m/s.)
Answer:
The statement is not correct.
Explanation:
To know if the statement is correct, we shall determine the velocity of the car after 3 s. This is illustrated below.
Data obtained from the question include:
Initial velocity (u) = 0 m/s
Acceleration due to gravity (g) = 9.8 m/s²
Time (t) = 3 s
Final velocity (v) =?
v = u + gt
v = 0 + (9.8 × 3)
v = 0 + 29.4
v = 29.4 m/s
Thus, the velocity of the car after 3 s is 29.4 m/s.
Hence, the statement made by the friend is not correct as the car has a falling velocity of 29.4 m/s after 3 s.
A skater of mass 45 kg is travelling in a circle of radius 4 m at a constant speed. What is their speed if the horizontal force they exert on the ground to prevent them from slipping is 1125 N
A 10 m/s
B. 20 m/s
C. 5 m/s
D. 100 m/s
E. The speed cannot be determined since we don't know
the time interval.
The skater moves at a 10 m/s speed. The right answer is A.
We must examine the forces operating on the skater in order to calculate their speed. The horizontal force applied to the ground creates the centripetal force, which is pointed in the direction of the circular path's center.
The centripetal force is calculated using the formula F = (mv2) / r, where m is the skater's mass, v is the speed, and r is the circle's radius.
We may convert the skater's horizontal force of 1125 N to the centripetal force as follows:
1125 N = (45 kg * v^2) / 4 m.
We rearrange the equation to find v:
1125 N * 4 m = 45 kg * v^2.
4500 N*m = 45 kg * v^2.
If you multiply both sides of the equation by 45 kg, you get:
100 N*m = v^2.
Taking the square root of both sides gives:
v = 10 m/s.
Therefore, the skater's speed is 10 m/s. The correct option is A.
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Which of the following lines could be used to describe an object that is accelerating in the positive direction on this Position vs. Time graph? (remember your lessons and resources)
The line which could be used to describe an object that is accelerating in the positive direction on this Position vs. Time graph is line a.
What is a position vs time graph?A position vs time graph can be defined as a type of graph that is used to graphically represent the distance traveled (covered) by an object from its starting position with respect to the time when it is started moving.
In a position vs time graph, the position of a physical object (body) is always plotted on the y-coordinate (y-axis) while time is always plotted on the x-coordinate (x-axis).
Generally speaking, there are different types of motion that are described by a position vs time graph and these include a motion in the positive direction and accelerating or speeding up in the positive direction as depicted by line a, which simply means that the speed of the physical is increasing.
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Show by dimension that the equation of motion is correct
V² = U²+2as
Answer:
i think its 56as
Explanation:
which is the best definition of pitch
Answer:
a black or dark viscous substance obtained as a residue in the distillation of organic materials and especially tars
Explanation:
17% Part (a) Calculate the x-component of the electric field at point P due to charge Q1. Write your answer in units of N/C.
The x component would be Ex = 412 x cos 49° = 270 N/C
Assume there is a small positive charge located at point P. By definition the magnitude of the electric field at point P due to charge Q1 is
E = kQ1/d2
where k is the coulomb constant and d is the straight line distance from Q1 to P.
The distance is the hypotenuse of the triangle formed by Q1, Q2, and P.
d = √0.065^2 + 0.075^2 = 0.099 m at an angle of θ = arctan 7.5/6.5 = 49°.
|E| = 8.99 x 10^9 Nm^2 C^-2 x 0.45 x 10^-9 C/ 0.099^2 m^2 = 412 n/C
The x component would be Ex = 412 x cos 49° = 270 N/C
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An elevator lifts a total mass of 1800 kg, a distance of 60 m in 60 s. How much power does the elevator generate?
Answer:
17640
Explanation:
Power = workdone/time
Power = (force x displacement)/time
Power = (mg x 60)/60
Power = (1800 x 9.8 x 60)/60
=> power = 17640 watt
elastic collisions in one dimension: a 2.3-kg object traveling at 6.1 m/s collides head-on with a 3.5-kg object traveling in the opposite direction at 4.8 m/s. if the collision is perfectly elastic, what is the final speed of the 2.3-kg object?
The final speed of the 2.3-kg object is 3.47 m/s. In an elastic collision, both momentum and kinetic energy are conserved. We can use these conservation principles to solve for the final speed of the 2.3-kg object.
First, we'll need to calculate the initial momentum of each object:
p1 = m1v1 = (2.3 kg)(6.1 m/s) = 14.03 kg m/s
p2 = m2v2 = (3.5 kg)(-4.8 m/s) = -16.8 kg m/s
The negative sign for p2 indicates that the object is moving in the opposite direction.
The total initial momentum of the system is:
p1 + p2 = -2.77 kg m/s
Next, we'll use conservation of momentum to find the final velocity of the system:
p1 + p2 = p1' + p2'
where p1' and p2' are the final momenta of each object. Since the objects are moving in opposite directions, their momenta have opposite signs:
p1' = m1v1'
p2' = m2v2'
We can solve for v1' and v2' in terms of the initial velocities and masses:
v1' = ((m1 - m2)/(m1 + m2))v1 + (2m2/(m1 + m2))v2
v2' = (2m1/(m1 + m2))v1 - ((m1 - m2)/(m1 + m2))v2
Plugging in the given values, we get:
v1' = (-0.6 m/s)
v2' = (2.87 m/s)
The final velocity of the 2.3-kg object is positive, indicating that it is moving in the same direction as its initial velocity. Therefore, the final speed of the object is:
v1' = 3.47 m/s
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100 degrees C equals how many degrees F?
Answer:
212 f
Explanation:
You are moving at 30 km/s with respect to the sun because the Earth ismoving. So is the chair you are sitting in. If you stood up and jumped, thechair wouldn't move out from under you because:A) The inertia of you and the chair carry both of you with the speed of the EarthB)The chair is stuck to the ground because of frictionC) You didn’t jump high enough for that speed to matterD) You have inertia that keeps you gravitationally attracted to the chair
Given that both the chair and the person are affected by Earth's movement, we can deduct that both have inertia due to Earth's speed.
Therefore, the answer is A.your mass is 50 kg. suppose you are standing on a scale in an elevator that is approaching a top floor and decreasing its speed at the rate of 2 m/s every second. what would be the reading on the scale?
The scale eventually will read a higher value during acceleration than when the elevator is at rest.
Acceleration can be defined as the rate of change of velocity of an object over time. Acceleration is a vector quantity. It means it has both magnitude and direction. The unit of measurement for acceleration is meters per second squared (m/s²). Positive acceleration means an object is speeding up, negative acceleration means it's slowing down, and zero acceleration means it's moving at a constant velocity. The scale reading during acceleration will be greater than the scale reading when the elevator is at rest. This is because during the acceleration, the force acting on the person standing on the scale is the person's weight (mg) plus the force due to the acceleration (ma). Since the elevator is accelerating upward, the force due to the acceleration is upward and adds to the person's weight. Therefore, the scale will read a higher value during acceleration than when the elevator is at rest.
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1. An object falls from rest on a high tower and takes 5.0 s to hit the ground. Calculate the object’s position from the top of the tower at 1.0 s intervals. Make a position-time graph for the object’s motion. In your response, show what you are given, the equation that you used, any algebra required, a table of data, and your graph.
g=9.8 m /s^2
Create a graph with the x-axis indicating time and the y-axis showing distance (displacement from the top) (label axes and give units for each).
A line with an upward slope that progressively becomes steeper as it continues will be the one that fits the data the best. Avoid using straight lines to connect the graph's points.
This is further explained below.
What is the object’s position from the top of the tower at 1.0 s intervals?Generally, the equation for distance is mathematically given as
d = ut + ½.at²
Therefore
For 1.0s
d = 0.5 x 9.80 x (1²)
d= 4.90 m
For 2.0s
d' = 0.5 x 9.80 x (2²)
d'= 19.60 m
For 3.0s, 4.0s, 5.0s Respectively
d'' = 44.10m
d''' = 78.40 m
d'''' = 122.50m
In conclusion, Draw a graph with the y-axis representing distance (displacement from the top) and the x-axis representing time (label axes and give units for each).
The line that provides the greatest fit will be an upwardly sloping line that gradually becomes steeper as it goes on. Do not connect the graph points with lines that are straight.
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Suppose you discover a Type Ia supernova in a distant galaxy. At maximum brilliance, the supernova reaches an apparent magnitude of 10. How far away in the galaxy
Type Ia supernova is approximately 72.38 million parsecs away in the distant galaxy.
To determine the distance to a Type Ia supernova in a distant galaxy with an apparent magnitude of 10, we will use the distance modulus formula. The distance modulus formula relates the apparent magnitude (m), absolute magnitude (M), and distance (d) in parsecs. The formula is:
m - M = 5 * log10(d) - 5
For a Type Ia supernova, the absolute magnitude is roughly -19.3. Now, we have the values for m and M, and we can solve for d:
10 - (-19.3) = 5 * log10(d) - 5
Next, isolate log10(d):
29.3 = 5 * log10(d) - 5
34.3 = 5 * log10(d)
Now, divide by 5:
6.86 = log10(d)
To find d, raise 10 to the power of 6.86:
d = 10^6.86
Finally, calculate the distance:
d ≈ 72.38 million parsecs
So, the Type Ia supernova is approximately 72.38 million parsecs away in the distant galaxy.
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Students were asked about the speed of cars involved in an accident. When the verb was changed from "contacted" to "smashed", ________.
Students were asked about the speed of cars involved in an accident. When the verb was changed from "contacted" to "smashed", students were more likely to report that there was broken glass involved in the accident.
What is a verb?A verb is one of the parts of speech in English language and it can be defined as a type of word which is used to describe an action, occurrence, experience, or a state of existence such as, smashed, living, contacted, clean, drive, etc.
What is speed?Speed can be defined as the distance covered by a physical object per unit of time. This ultimately implies that, the higher the speed of a car that is involved in a road crash or accident, the higher would be the level of impact and damage that would be caused.
In this context, we can reasonably infer and logically deduce that changing the verb from contacted to smashed, ultimately implies that the road crash or accident was ghastly and fatal and such would cause broken glasses in the cars that were involved.
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Complete Question:
Students were asked about the speed of cars involved in an accident. When the verb was changed from "contacted" to "smashed" ______,
students were more likely to report that there was broken glass involved in the accident
students were less likely to report that the cars were traveling at high speeds
students were more likely to report that no one was injured in the accident
there was no differences noted.
A rock is thrown straight up with an initial speed of 24.0 m/s. Neglect air resistance. At t = 1.0 s what are the directions of the velocity and acceleration of the rock? Is the speed of the rock increasing or decreasing? The acceleration is upward. The velocity is upward and the speed is increasing. The acceleration is downward. The velocity is downward and the speed is increasing. The acceleration is upward. The velocity is upward and the speed is decreasing. O The acceleration is downward. The velocity is upward and the speed is decreasing. O The acceleration is downward. The velocity is downward and the speed is decreasing. Submit Previous Answers Request Answer Part B At t = 3.0 s what are the directions of the velocity and acceleration of the rock? Is the speed of the rock increasing or decreasing? The acceleration is upward. The velocity is upward and the speed is decreasing. The acceleration is upward. The velocity is upward and the speed is increasing. The acceleration is downward. The velocity is upward and the speed is decreasing. The acceleration is downward. The velocity is downward and the speed is decreasing. The acceleration is downward. The velocity is downward and the speed is increasing.
The acceleration remains in the same direction (downward) throughout, but the velocity of the rock changes from positive (upward) to negative (downward).
At t = 1.0 s, the rock has an initial velocity of 24.0 m/s in the upward direction and an acceleration of 9.8 m/s2 in the downward direction. This means that the speed of the rock is increasing as it accelerates downward.
At t = 3.0 s, the rock has a velocity of -48.0 m/s in the downward direction and an acceleration of 9.8 m/s2 in the downward direction. This means that the speed of the rock is decreasing as it accelerates downward.
The acceleration of the rock remains in the same direction (downward) as it moves, but the velocity of the rock changes from positive (upward) to negative (downward).
To sum up, the rock has an initial velocity of 24.0 m/s in the upward direction and an acceleration of 9.8 m/s2 in the downward direction at t = 1.0 s.
This means that the speed of the rock is increasing as it accelerates downward. At t = 3.0 s, the rock has a velocity of -48.0 m/s in the downward direction and an acceleration of 9.8 m/s2 in the downward direction.
This means that the speed of the rock is decreasing as it accelerates downward.
The acceleration remains in the same direction (downward) throughout, but the velocity of the rock changes from positive (upward) to negative (downward).
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A high diver of mass 70kg jumps off a board 10m above the water. If, 1.0s after entering the water his downward motion is stopped, what average upward force did the water exert? Answer is 1666 N but how do you get the answer?
The average upward force exerted by the water on the high diver can be determined using the principles of motion and Newton's second law. The calculated value is 1666 N.
To find the average upward force exerted by the water, we can apply Newton's second law, which states that the force acting on an object is equal to its mass multiplied by its acceleration.
First, we need to find the initial velocity of the diver just before entering the water. Using the equation of motion,\(v = u + at\), where v is the final velocity, u is the initial velocity, a is the acceleration, and t is the time taken, we can find the initial velocity.
Since the diver's downward motion is stopped 1.0s after entering the water, the final velocity is 0 m/s. The acceleration due to gravity is approximately 9.8 m/s². Rearranging the equation, we have 0 = u + (9.8 m/s²)(1.0 s), which gives us the initial velocity u = -9.8 m/s (negative because the diver is moving downward).
Next, we can calculate the average upward force using the formula F = ma, where F is the force, m is the mass, and a is the acceleration. The acceleration is determined by the change in velocity and the time taken to stop, which is 9.8 m/s divided by 1.0 s. Substituting the values, we have F = (70 kg)(9.8 m/s²/1.0 s), which gives us the average upward force of 686 N.
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Plz help me I will give brainliest
make a rule: based on the measured force between objects that are 10 meters apart, how can you find the force between objects that are any distance apart?
By applying this rule, you can determine the force between objects at any given distance by comparing it to the force measured at a reference distance.
F1 / F2 = \((r2 / r1)^2\)
The rule based on the measured force between objects that are 10 meters apart to find the force between objects at any distance apart is as follows:
"The force between two objects is inversely proportional to the square of the distance between them."
Mathematically, this can be expressed as:
F1 / F2 = \((r2 / r1)^2\)
Where:
F1 is the measured force between objects at a distance r1.
F2 is the force between objects at a distance r2.
r1 is the initial distance between the objects where the force was measured.
r2 is the new distance between the objects at which the force is to be calculated.
By applying this rule, you can determine the force between objects at any given distance by comparing it to the force measured at a reference distance.
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Question 10
6.25 pts
A cannon is fired horizontally at 337 m/s off of a 80 meter tall, sheer vertical cliff. How many
seconds
will have elapsed before the cannonball strikes the ground?
Answer: 4 seconds are elapsed before the cannonball strikes the ground.
Explanation:
Height of tower (h) = 80m
Initital velocity in x-dir (\(u_{x}\)) = 337m/s
Initial velocity in y-dir (\(u_{y}\)) = 0m/s
Time of flight (T)
Gravitational acceleration (g) = 10 m/s
Using second equation of motion,
h = \(u_{y}\) + \(\frac{1}{2}\)g\(t^{2}\)
80 = \(\frac{1}{2}\)×10×\(T^{2}\)
\(T^{2}\) = 16
T = 4s
a material used by living things for growth and other life functions is a?
Answer:
I believe it wouled be Nutrients
Explanation:
hope this helps if not please let me know
Suppose an experiment is designed to test the durability of batteries in different conditions. All of the batteries tested are double-A (AA) Brand X. All sets of batteries are preconditioned in different environmental conditions for exactly 168 hours (1 week).
Set 1: 0°C (freezing point of water)
Set 2: 24°C (approximately room temperature)
Set 3: 37°C (approximately body temperature)
The batteries are then continuously used to power identical mechanical drummer toys. As long as the toy keeps drumming the battery is considered functional. The drumming time for each toy is measured as an indication of battery durability. In this experiment, which condition is not controlled?
A.) temperature
B.) brand of batteries
C.) test for durability
D.) type of battery (battery size)
Answer:
I assume its c. Since its talking about testing.
Explanation:
Answer:
The answer is test of durability
Explanation:
Which of these statements is true about a 'Goldilocks zone'?
1.The distance away from any star where the temperature would allow water to be a
liquid
2.A habitat anywhere in space where life can exists
3.The distance away from our sun where it is too hot or too cold for life to exist
4. A place in a solar system where it is possible for bears to live.
Answer:
3.the distance away from the sun where it to hot or too cold for life to exist
A fish is 50.0 cm below the surface of a pond (index of refraction for water is 1.33). For a viewer directly above the fish, the fish appears to be placed
O 37.6 cm below the surface of the pond.
O 50.0 cm below the surface of the pond.
O 66.5 cm below the surface of the pond.
O None of the above is correct
The fish appears to be located 37.6 cm below the surface of the pond when viewed from directly above.The correct answer is: O 37.6 cm below the surface of the pond.
This is because when light travels from water (with an index of refraction of 1.33) to air (with an index of refraction of 1.00), it undergoes refraction. This means that the light bends as it passes through the surface, which causes objects to appear shifted from their actual position.
In this case, the fish is actually located 50.0 cm below the surface of the pond. However, when the light from the fish enters the air above the pond, it bends away from the normal (a line perpendicular to the surface of the water), causing the fish to appear higher up than it actually is. Using the formula for calculating the apparent depth of an object underwater:
apparent depth = real depth / index of refraction
We can calculate the apparent depth of the fish:
apparent depth = 50.0 cm / 1.33 = 37.6 cm
Therefore, the fish appears to be located 37.6 cm below the surface of the pond when viewed from directly above.
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(PHYSC) HELPPPP Individuals suffering from somatoform disorders often see several doctors about their symptoms because __________.
A.
doctors often refer their patients for a second opinion
B.
their symptoms often fall under several specialties
C.
doctors get frustrated with them and refuse to treat them
D.
they are looking to find a doctor to give them a diagnosis
Answer:
D.
they are looking to find a doctor to give them a diagnosis
Explanation:
cause I had this answer
Individuals suffering from somatoform disorder generally see many doctors as they are often referred for a second opinion.
What is somatoform disorder?The somatoform disorder also known as a somatic symptom disorder refers to any mental disorder, which displays as physical symptoms that suggest injury or illness. However, it cannot be explained completely by a general medical condition or by the direct effect of a substance.
They are also not attributable to another mental condition like panic disorder. For the individuals diagnosed with somatoform disorder, the results of the medical test either do not explain the symptoms of the person or are either normal.
Therefore, the person with the somatoform disorder generally visits many doctors as they are often referred for a second opinion.
Thus, the correct statement is option A.
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What is the kinetic energy of a ball with a mass of 0.5 KG in a velocity of 10 m a second
Answer:
25joules
Explanation:
Scientists have changed the model of the atom as they
What experimental evidence led to the development of
have gathered new evidence. One of the atomic models
this atomic model from
the one before it?
iS shown below.
O A few of the positive particles aimed at a gold foil
seemed to bounce back.
The colors of light emitted from heated atoms had
very specific energies.
Experiments with water
vapor showed that elements
combine in specific proportions.
Cathode rays were bent in the same way whenever a
magnet was brought near them.
The experimental evidence led to the development of have gathered new evidence. One of the atomic models this atomic model from the one before it is the colors of light emitted from heated atoms had very specific energies.
As scientific knowledge about the structure of the atom has changed, so have models of the atom.
The Rutherford planetary model, which depicts electrons travelling around the nucleus like planets move around the sun in the solar system, is the direct precursor of the model illustrated in the figure attached.
This model was created as a result of the study of light hues released by heated atoms with highly particular energies.
The Bohr model of the atom is so named because Niels Bohr had a major role in developing it. The passage of electrons between energy levels caused the light hues released by heated atoms. Electrons are grouped in shells or energy levels.
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