find the wavelength of an electron that has energy of 19 ev. (the energy of the electron is its kinetic energy.)

The bat must be flying away from you at a speed of 193 mph so that you can barely be able to hear the chirp at 20 khz

With the observer at rest, this is a Doppler shift issue (\(v_{0}\) = 0) and the

observed sound shifted to a lower frequency \(f_{o}\) = 20 kHz. So, we start with the general

Doppler shift equation

\(f_o} = f_{s}\) {(1 ± \(\frac{v_{0} }{v}\)) / (1 ± \(\frac{v_{s} }{v}\))}

with \(f_{s}\) = 25 kHz and taking \(v\)= 343 m/s. The bat must be escaping from you because

\(f_o} = f_{s}\) \((\frac{1}{1+\frac{v_{s} }{v} } )\) < \(f_{s}\)

Now solve for \(v_{s}\), the bat's velocity, to provide

\(v_{s} = v\) \((\frac{f_{s} }{f_{o} } - 1)\)

   = (25/20 − 1)343 = 85.8 m/s.

As a check, 1 m/s = 2.25 mph. The bat would have to travel at a speed of 193 mph. Is that likely?

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Answer:

Second choice

Explanation:

I suppose ME is the same as POTENTIAL energy

ME = mgh =  70 * 10 * 12 = 8400j

  Half way down,   4200 j is converted to Kinetic Energy

       1/2 m v^2 = 4200

       1/2 (70)  v^2 = 4200       v = 10.95 m/s

  Just before impact ALL of the 8400 j is now KE
      1/2 (70)v^2 = 8400          v = 15.49 m/s

Answer:

In order to convert density to grams, you have to put the mass on one side of the equation, and the density and the volume on the other. Therefore, d * v = m. Multiply the density by the volume. Using the example in step 1, you would multiply 2 g/mL by 4mL.

Explanation:

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Answer: Explanation:

Carbonated drinks are mixtures of water, sugar, flavorings, and dissolved carbon dioxide gas. They are homogeneous because the ingredients are mixed together to form a consistent liquid.

The Ares 4 MAV (Mars Ascent Vehicle) has been designed to be as light as possible to make it easier to get into a high Martian orbit.

The main body of the vehicle is constructed out of lightweight materials such as aluminium and titanium. This helps reduce the overall weight of the MAV, making it easier to launch into orbit.

Additionally, the MAV is powered by an advanced propulsion system that is designed to provide maximum efficiency with minimal fuel use. This ensures that the MAV is able to reach its destination with minimal fuel, helping to keep the weight of the craft to a minimum.

Finally, the MAV is equipped with a range of advanced navigation and guidance systems that help to keep the craft on its desired trajectory.

These systems help to ensure the MAV is able to reach its destination with minimal fuel, keeping the craft light and helping it to reach its desired orbit.

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An object in motion, such as a car or a bird, has kinetic energy but not potential energy.

An object in motion has kinetic energy, but it doesn't necessarily have potential energy. Potential energy is the energy that an object possesses due to its position in a gravitational field or an electric field. An object that has the potential to move, but isn't moving, has potential energy. However, if an object is already in motion, it doesn't have the potential to move, and hence it doesn't have potential energy. This is because potential energy is directly proportional to an object's position or height above a surface with a gravitational or electric field.For instance, when a car is traveling down a road, it has kinetic energy, which is proportional to its mass and velocity, but it doesn't have potential energy because it's not at any height or position above the ground that can produce potential energy. Similarly, a bird that's flying through the air has kinetic energy because it's in motion, but it doesn't have potential energy because it's not above the ground or any surface with a gravitational or electric field.

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The International System of Units is the modern form of the metric system. It is the only system of measurement with an official status in nearly every country in the world.

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SMM2 refers to the Standard Method of Measurement 2. It is a document that specifies the method and processes used in measuring buildings and civil engineering works. SMM2 is commonly used in the construction industry.

The following are explanations of the clauses under Standard Method of Measurement 2 (SMM2):

i. D.10: This clause under SMM2 relates to the painting of metal and timber surfaces. It stipulates that when painting the surfaces of timber or metal, the preparation of surfaces and application of paint must conform to manufacturer specifications. It also specifies that the paint must be applied using a brush, roller, or spray. The clause then goes on to outline specific measurements for the thickness of paint coating to be applied on surfaces.

ii. D.12.4: This clause under SMM2 refers to the construction of walls using concrete blocks. It states that the concrete blocks used should have a minimum density of 1500 kg/m3. It also outlines specific measurements for the thickness of the mortar to be used for bonding the blocks together. The clause further specifies the measurement of the joint thickness between blocks.

iii. D.12.6: This clause under SMM2 refers to the rendering of walls with a cement mortar mix. It specifies that before rendering, the surface of the wall must be clean, dry, and free of debris. It also outlines specific measurements for the thickness of the rendering to be applied to the wall. The clause then stipulates that the rendering should be finished with a smooth surface that conforms to the architect's specifications.

iv. D.12.8: This clause under SMM2 refers to the painting of interior plastered walls. It stipulates that the preparation of surfaces and application of paint must conform to manufacturer specifications. It also specifies that the paint must be applied using a brush, roller, or spray. The clause then goes on to outline specific measurements for the thickness of paint coating to be applied on surfaces.

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Answer:

25N

Explanation:

Answer:

the answer is A

A is 25N

The magnitude of the friction force on the box is 36N.

The force applied by the man to push the box of mass 80kg is 180N.

the acceleration of the block is 1.80m/s².

Now, we know,

Acceleration = Net force/mass

A = F/M

Now, the net force will be applied force minus frictional force.

So, if the frictional force is Fr and the applied force is F, then we can write,

a = F-Fr/M

Putting values,

1.80 = 180-Fr/80

Fr = 36N.

So, the frictional force is 36N in magnitude.

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Answer:

pie chart as it shows the whole

Answer:

v = 10m/s.

Explanation:

100 = 1/2×2×v^2

100 = 1×v^2

v^2 = √100

v=10 m/s

The  centripetal acceleration of the rock will be 385.3 m/s²

The  tension in the string will be 137.5 N

The acceleration felt when moving uniformly in a circle is known as centripetal acceleration (ac). It consistently faces the rotational axis. Its magnitude is ac=v2r;ac=r2, and it is orthogonal to the linear velocity v.

Given, speed, v = 17m/s

radius, r = 0.75m

mass of rock. m = 0.357 kg

a) centripetal acceleration, ac = v²/r

ac = 17×17/0.75

ac = 385.3 m/s²

b) Tension in string, T = ma = m×v²/r

T = 0.357×385.3

T = 137.56 N

a)The  centripetal acceleration of the rock will be 385.3 m/s²

b) The  tension in the string will be 137.5 N

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Answer:

2) 6.22 × 10^-13

3) 4.56 × 10^-4

Explanation:

when running a line, in a right-triangle, from the 90° angle perpendicular to its opposite side, we will end up with three similar triangles, one Small, one Medium and a containing Large one.  Check the picture below.

\(\cfrac{x}{11}~~ = ~~\cfrac{4}{x}\implies x^2=44\implies x=\sqrt{44}\implies x=2\sqrt{11}\)

Answer:

20 steps is his displacement

Answer:

(a) The height of the mercury on the open side if the gauge pressure is measured to be 13.3 kPa is 9.97395 cm

(b) When the gauge pressure is doubled;

The height of the mercury on the open side becomes 19.9479 cm

The height of the mercury on the side connected to the gas becomes 12.02605 cm

Explanation:

(a) The given parameters are;

The height of the mercury column on the side connected to the gas = 22.0 cm

The gauge pressure = 13.3 kPa

The gauge pressure is the pressure in the gas container relative to the atmospheric pressure, therefore, we have;

ΔP = P - P₀ = ρ × g × h

Where;

ΔP = The gauge pressure = P - P₀ = 13.3 kPa = 13,300 Pa

P₀ = The atmospheric pressure

P = The pressure of the gas in the container

ρ = The density of the mercury = 13593 kg/m³

g = The acceleration due to gravity = 9.81 m/s²

ΔP = ρ × g × h, by substitution gives

13,300 = 13593 × 9.81 × h

h = 13,300/(13593 × 9.81) ≈ 0.0997395 m = 9.97395 cm

The height of the mercury on the open side if the gauge pressure is measured to be 13.3 kPa is 9.97395 cm

(b) Given that the gauge pressure for the gas doubles, we have;

13,300 × 2 = 13593 × 9.81 × h

Therefore, h = 2 × 9.97395 = 19.9479 cm

The height of the mercury on the open side, h = 19.9479 cm

Therefore, the height of the mercury on the side connected to the gas becomes, 22 - 9.97395 = 12.02605 cm

Strong storms and hurricanes are the consequences of how the Earth is heated by the sun.

The upper troposphere becomes warmer as the lower stratosphere warms. When the troposphere and the planet's surface are at opposite temperatures, significant updrafts result, which intensifies storms and hurricanes. Updrafts and storm power are diminished during the height of the 11-year solar cycle.

Troposphere, stratosphere, mesosphere, and thermosphere are the layers of the atmosphere. The stratosphere, which contains the ozone layer, is the part of the Earth's atmosphere that is most affected by the sun. The stratosphere, which is where weather happens, is followed by the troposphere.

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Answer:

7.69km/hr due east

Explanation:

Given parameters:

Displacement due west  = 3km

Displacement due east = 2km

Time taken  = 8 minutes

Unknown:

Average velocity  = ?

Solution:

Average velocity is the rate of change of displacement with time.

  Velocity  = \(\frac{displacement}{time }\)

 Displacement is deals with the start and the end;

  Here, displacement  = 3km - 2km  = 1km due east

Time  = 8min

     60min  = 1hr

       8min = \(\frac{8}{60}\)   = 0.13hr

 Average velocity = \(\frac{1km}{0.13hr}\)   = 7.69km/hr due east

Answer:

Computer hard drives use magnetism to store the data on a rotating disk. More complex applications include: televisions, radios, microwave ovens, telephone systems, and computers. An industrial application of magnetic force is an electromagnetic crane that is used for lifting metal objects.

Answer:

Examples of magnetic force is a compass, a motor, the magnets that hold stuff on the refrigerator, train tracks, and new roller coasters. All moving charges give rise to a magnetic field and the charges that move through its regions, experience a force.

I Hope this will help you if not then sorry :)

Answer:

lithosphere

Explanation:

the least densest layer is the outer most layer

the densest layer is the inner most layer and the inner most layer is the inner core

Answer:

lithosphere

Explanation:

i took the test and i got it right

No, the evidence for dark matter is too strong to think it could be in error.

While there is still much to learn about this mysterious substance, its existence has been supported by multiple independent lines of observational evidence, including the dynamics of galaxies and galaxy clusters, the cosmic microwave background radiation, and gravitational lensing. While it's possible that our current understanding of gravity may need to be refined, it's highly unlikely that all of the evidence for dark matter is the result of errors or biases in our observations. Therefore, while it is possible that there could be something wrong with our current understanding of how gravity should work on large scales, and that dark matter may not exist, the evidence for it is too strong to think it could be in error.

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Answer:

A = 0.188 m²

Explanation:

First we find the distance between the plates by using the formula of electric field intensity:

E = ΔV/d

d = ΔV/E

where,

d = distance between plates = ?

ΔV = Potential Difference = 4 KV = 4000 V

E = Electric Field = 2 x 10⁸ V/m

Therefore,

d = 4000 V/(2 x 10⁸ V/m)

d = 2 x 10⁻⁵ m

Now, we find the Area of Plates by using formula of capacitance:

C = A∈₀∈r/d

where,

C = Capacitance = 0.25 μF = 0.25 x 10⁻⁶ F

A = Area of Plates = ?

∈₀ = Permittivity of free space = 8.85 x 10⁻¹² C/N.m²

∈r = Dielectric Constant = 3

Therefore,

0.25 x 10⁻⁶ F = A(8.85 x 10⁻¹² C/N.m²)(3)/(2 x 10⁻⁵ m)

A = (0.25 x 10⁻⁶ F)(2 x 10⁻⁵ m)/(3)(8.85 x 10⁻¹² C/N.m²)

A = 0.188 m²