Fixed in the frame F is a sheet of charge, of uniform surface density sigma, which bisects the dihedral angle formed by the x-y and the y-z planes. The E-field of this stationary sheet is of course perpendicular to the sheet. How will this be described by observers in the frame F' that is moving in the direction with velocity 0.6c with respect to F? What is the surface charge density sigma prime and what is the direction and strength of the E-field in F'? Is it perpendicular to the sheet?

Answers

Answer 1

The electric field in the moving frame F' is increased by a factor of 1.67. Yes, the direction of the electric field  is perpendicular to the sheet.

According to special relativity, the electric field E' measured in the moving frame F' will be different from the electric field E measured in the stationary frame F. This is due to length contraction and time dilation effects, which cause the charge density and electric field to appear different in the moving frame.

To find the electric field in the moving frame F', we need to use the Lorentz transformation for the electric field:

E' = γ(E + v × B)

where γ is the Lorentz factor, v is the relative velocity between F and F', and B is the magnetic field, which we assume to be zero in this case.

In the stationary frame F, the electric field of the charged sheet is perpendicular to the sheet and has a magnitude of E = σ/2ε0, where σ is the surface charge density and ε0 is the permittivity of free space.

Since the sheet bisects the dihedral angle formed by the x-y and the y-z planes, we can assume that the charge density is uniformly distributed on both sides of the sheet, with opposite signs.

Therefore, the surface charge density in the moving frame F' will be different on the two sides of the sheet due to length contraction. The charge density on the side of the sheet moving toward the observer in F' will be increased, while the charge density on the side moving away will be decreased.

The surface charge density σ' on the moving sheet can be found using the formula:

σ' = γ(σ - vρ)

where ρ is the perpendicular distance from the sheet to the observer in F'.

Since the observer in F' is moving in the x direction with a velocity of 0.6c, we can assume that ρ is the same in both frames, and we can set ρ = 0 without loss of generality.

Thus, we have:

σ' = γσ

Plugging in the given values, we get:

σ' = (1/√(1-0.6²))σ = 1.67σ

Therefore, the surface charge density in the moving frame F' is increased by a factor of 1.67.

To find the electric field in the moving frame F', we can use the Lorentz transformation formula:

E' = γ(E + v × B)

Since B is zero, we have:

E' = γE

Plugging in the given values, we get:

E' = (1/√(1-0.6²))E = 1.67E

Therefore, the electric field in the moving frame F' is increased by a factor of 1.67 as well. The direction of the electric field in F' is perpendicular to the sheet, as it is in the stationary frame F.

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Related Questions

HELP!!! When fat comes in contact with sodium hydroxide, it produces soap and glycerin. Determine whether this is a physical change or a chemical change. Explain your answer.

Answers

Answer:it's a chemical change.physical changes occur without 2 or more reactants,a reaction,and a product

Explanation:

1
7 The resultant force on the trolley was 0.375 N.
The mass of the trolley was 0.60 kg.
Calculate the acceleration of the trolley.
Give your answer to 2 significant figures.

Answers

Acceleration = Force \ mass

0,375N/0,60kg=0.6ms-2

solar panels generate electricity using photovoltaic cells that receive sunlight. to protect these cells from moisture while allowing sunlight to pass through, engineers must design a cover for the solar panel that is
1. waterproof and transmits light.

2. very flexible and reflects lights.

3. stronger than steel and bends light.

4. cold to touch and absorbs light

Answers

Answer:

waterproof and transmits light.

Answer:

waterproof and transmits light.

Explanation:

A rock moving through a gravitational field is analogous to a _______________ charge moving through an electric field.

Answers

Answer:A rock moving through a gravitational field is analogous to a "massive" charge moving through an electric field.

Just as a charged particle experiences a force when moving through an electric field, a massive object experiences a force when moving through a gravitational field. The strength of the force depends on the mass of the object and the strength of the field. This is described by Newton's law of gravitation.

Explanation:

A rock moving through a gravitational field is analogous to a positive or negative charge moving through an electric field

Comparison between gravitational field and electric field:

A rock moving through a gravitational field is analogous to a positive or negative charge moving through an electric field, depending on the direction of the gravitational force and the sign of the charge.

Both the gravitational field and the electric field are conservative fields that exert a force on objects or charges within their respective fields.

However, the strength and nature of the force depend on the mass or charge of the object or particle, as well as the distance and direction from the source of the field.

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what was the hiker's average velocity during part b of the hike? responses 0.6 km/h north 0.6 km/h north 0.17 km/h south 0.17 km/h south 6 km/h south 6 km/h south 10 km/h southeast

Answers

The hiker's average velocity during part B of the hike is 6 km/h South.

Given the following data:

Total distance = 6 km, South.

Start time = 9:45 am

Ending time = 10:45 am

To determine hiker's average velocity during part B of the hike:

First of all, we would determine the total time.

Total time = Ending time - starting time

Total time = 10:45 - 9:45

Total time = 1 hour.

Mathematically, the average velocity is given by the formula:

Average velocity = total distance / total time

Substituting the parameters into the formula, we have;

Average velocity = 6/1

Average velocity = 6 km/h South.

Therefore, the average velocity of the biker is 6 km/h South

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what was the hiker's average velocity during part b of the hike? responses 0.6 km/h north 0.6 km/h north

True/false: dark nebulae are opaque to all wavelengths of electromagnetic radiation.

Answers

The answer is False, dark nebulae are not opaque to all wavelengths of electromagnetic radiation. Dark nebulae are interstellar clouds of dust and gas that obscure the light from stars and other celestial objects behind them, primarily in the visible light spectrum.

However, they do allow certain wavelengths of electromagnetic radiation to pass through, particularly longer wavelengths such as infrared and radio waves. Observations in these wavelengths enable astronomers to study the structures and properties of dark nebulae, as well as the star formation processes occurring within them. In summary, dark nebulae are not completely opaque to all forms of electromagnetic radiation, but rather selectively absorb and scatter specific wavelengths, particularly visible light.

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The heart working with the blood vessels to pump blood is which body system?
Digestive
Nervous
Respiratory
Cardiovascular

Answers

I think it’s the cardiovascular system

Adam is driving his truck at 18 m/s for a distance of 46 m, how much time was Adam driving?

Answers

Answer:

2.6 seconds

Explanation:

You have to divide the distance by the velocity to find the time:

46/18 = 2.55 ≈ 2.6 seconds

The answer you are looking for is approximately 2.6 seconds.

Solution/Explanation:

To get the correct answer, you must divide the distance and velocity.

This means that 46÷18=2.5556.

2.5556≈2.6.

So, therefore, the final answer is approximately 2.6 seconds.

I hope that this has helped you. Enjoy your day, and take care.

A boy is exerting a force of 70 N at a 50-degree angle on a lawn mower. He is accelerating at 1.8 m/s2. Round the answers to the nearest whole number.

What is the mass of the lawn mower?

⇒ 25 kg

What is the normal force exerted on the lawn mower?

⇒ 299 N

Answers

Explanation:

Given that,

Force, F = 70 N

Angle, \(\theta=50^{\circ}\)

Acceleration of the boy, a = 1.8 m/s²

(a) Net force is equal to the product of mass and acceleration. So,

\(m=\dfrac{F}{a}\\\\m=\dfrac{70}{1.8}\\\\m=38.89\ kg\)

(2) Normal force = upward force

So,

\(F=mg\cos\theta\\\\F=38.89\times 9.81\times \cos(50)\\F=245.23\ N\)

Hence, mass is 38.89 kg and the normal force is 245.23 N.

Which vehicle has an acceleration of 5 m/s²?

A a bicycle, when its speed changes from rest to 2.5 m/s in 2s

B a car, when its speed changes from rest to 15 m/s in 5s

C a lorry, when its speed changes from rest to 20 m/s in 15s

D a motorbike, when its speed changes from rest to 50 m/s in 10s

Answers

The vehicle has an acceleration of 5 m/s² -  A motorbike, when its speed changes from rest to 50 m/s in 10s


What is an acceleration ?

Acceleration is the rate at which the speed and direction of a moving object vary over time. A point or object going straight ahead is accelerated when it accelerates or decelerates. Even if the speed is constant, motion on a circle accelerates because the direction is always shifting. Both effects contribute to the acceleration for all other motions.

Acceleration is a vector quantity since it has both a magnitude and a direction. A vector quantity is also velocity. The velocity vector change during a time interval divided by the time interval is the definition of acceleration.


All the vehicles have an initial velocity ( u) = 0
A- For bicycle
Final velocity (v) = 2.5m/s    time (t) = 2s
acceleration = 2.5/2 = 1.25m/s2

B- For car
Final velocity (v) = 15m/s    time (t) = 5s
acceleration = 15/5 = 3m/s2

C- For lorry
Final velocity (v) = 20m/s    time (t) = 15s
acceleration = 20/15= 1.33m/s2

D- For motorbike
Final velocity (v) = 50m/s    time (t) = 10s
acceleration = 50/10= 5m/s2


Option D is the correct answer as the motorbike will have an acceleration of 5m/s2.
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Process-Facts-Explanation What would most likely cause the cycle to continue?

Answers

Answer:

The correct answer is option an explanation inspires new questions and the process of making new observations

Explanation:

New things are being discovered and invented in a scientific field due to the "skeptical nature of humans" that is asking the questions.

The basis of scientific revolution is that a new question can be derived from the explanation of the earlier answered scientific hypothesis as the explanations consists of the data obtained after the assumptions, observations and related experiments. This generates new ideas of 'if and but conditions" in the mind which leads to the formation of a new hypothesis thus continuing the cycle of a a scientific research.

please help me with my question I will like and mark as brainliest for the first correct answer due tomorrow morning​

please help me with my question I will like and mark as brainliest for the first correct answer due tomorrow

Answers

Answer:

1845.26 ?

Explanation:

18.46 × 99.96= 1845.2616 = 1845.26

im not entirely sure though

An electron moves in a circular path of radius 20 cm in a uniform magnetic field of 2 x 10³ T Find the speed of the electron and period of revolution. Mass of electron = 9.1 x 10-31 kg. [Ans: 7.02 x 10 m/sec and 5.6 x 10 rev/sec] ​

Answers

The linear speed of the electron is 7.03 x 10¹³ m/s and the angular speed of the electron is 5.6 x 10¹³ rev/s.

Speed of the electron

The speed of the electron is calculated as follows;

F = ma = mv²/r  ---(1)

F = qvB  ----- (2)

mv²/r = qvB

mv/r = qB

mv = qBr

v = qBr/m

where;

m is mass of the electronB is magnetic fieldr is radius of the circleq is charge of the electron

v = (1.6 x 10⁻¹⁹ x 2 x 10³ x 0.2) / (9.1 x 10⁻³¹)

v = 7.03 x 10¹³ m/s

Angular speed of the electron

ω = v/r

ω = (7.03 x 10¹³ m/s) / (0.2 m) = 3.51 x 10¹⁴ rad/s

ω = 3.51 x 10¹⁴ rad/s  x 1 rev/2π rad

ω = 5.6 x 10¹³ rev/s

Thus, the linear speed of the electron is 7.03 x 10¹³ m/s and the angular speed of the electron is 5.6 x 10¹³ rev/s.

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A digital audio compact disc (CD) carries data along a continuous spiral track from the inner circumference of the disc to the outside edge. Each bit occupies 0.6 mm of the track. A CD player turns the disc to carry the track counterclockwise above a lens at a constant speed of 1.30 m/s. Find the required angular speed (a) at the beginning of the recording, where the spiral has a radius of 2.30 cm, and (b) at the end of the record-ing, where the spiral has a radius of 5.80 cm. (c) A full-length recording lasts for 74 min, 33 s. Find the average angular acceleration of the disc. (d) Assuming the acceleration is con-stant, find the total angular displacement of the disc as it plays. (e) Find the total length of the track.

Answers

(a) The required angular speed at the beginning of the recording is approximately 52.38 radians per second.

(b) The required angular speed at the end of the recording is approximately 20.95 radians per second.

(c) The average angular acceleration of the disc is approximately -0.000286 radians per second squared.

(d) Assuming constant acceleration, the total angular displacement of the disc as it plays is approximately -0.343 radians.

(e) The total length of the track is approximately 5.28 kilometers.

(a) To find the required angular speed at the beginning of the recording, we can use the relationship between linear speed, angular speed, and radius. The linear speed is given as 1.30 m/s, and the radius is 2.30 cm (or 0.023 m). The formula to relate these quantities is:

Linear Speed = Angular Speed * Radius

Solving for angular speed:

Angular Speed = Linear Speed / Radius

Plugging in the given values:

Angular Speed = 1.30 m/s / 0.023 m

Angular Speed ≈ 56.52 radians/second

Therefore, the required angular speed at the beginning of the recording is approximately 52.38 radians per second.

(b) Similarly, to find the required angular speed at the end of the recording, we use the same formula and plug in the linear speed of 1.30 m/s and the radius of 5.80 cm (or 0.058 m):

Angular Speed = 1.30 m/s / 0.058 m

Angular Speed ≈ 22.41 radians/second

Therefore, the required angular speed at the end of the recording is approximately 20.95 radians per second.

(c) To find the average angular acceleration, we can use the formula:

Average Angular Acceleration = (Final Angular Speed - Initial Angular Speed) / Time

The final angular speed is the angular speed at the end of the recording, which is approximately 20.95 radians per second. The initial angular speed is the angular speed at the beginning of the recording, which is approximately 52.38 radians per second. The time is given as 74 minutes and 33 seconds, which is equivalent to 4473 seconds.

Average Angular Acceleration = (20.95 radians/second - 52.38 radians/second) / 4473 seconds

Average Angular Acceleration ≈ -0.000286 radians/second squared

Therefore, the average angular acceleration of the disc is approximately -0.000286 radians per second squared.

(d) Assuming constant angular acceleration, we can use the formula to find the angular displacement:

Angular Displacement = Initial Angular Speed * Time + (1/2) * Average Angular Acceleration * Time^2

The initial angular speed is approximately 52.38 radians per second, and the average angular acceleration is approximately -0.000286 radians per second squared. The time is given as 74 minutes and 33 seconds, which is equivalent to 4473 seconds.

Angular Displacement = 52.38 radians/second * 4473 seconds + (1/2) * -0.000286 radians/second squared * (4473 seconds)^2

Angular Displacement ≈ -0.343 radians

Therefore, the total angular displacement of the disc as it plays is approximately -0.343 radians.

(e) To find the total length of the track, we need to calculate the arc length of each bit and sum them up. Each bit occupies 0.6 mm of the track, which is equivalent to 0.0006 m.

The total number of bits can be calculated by multiplying the circumference of the spiral track by the number of revolutions. The circumference is given by 2π times the average of the initial and final radii.

Circumference = 2π * (2.30 cm + 5.80 cm) / 2

Circumference ≈ 27.77 cm

Converting the circumference to meters:

Circumference = 27.77 cm * 0.01 m/cm

Circumference ≈ 0.2777 m

The number of revolutions can be calculated by dividing the track length by the length of each bit:

Number of Revolutions = Track Length / Length of Each Bit

Number of Revolutions = 0.2777 m / 0.0006 m

Number of Revolutions ≈ 462.83 revolutions

Finally, we can calculate the total length of the track:

Total Length of the Track = Number of Revolutions * Circumference

Total Length of the Track ≈ 462.83 revolutions * 0.2777 m/revolution

Total Length of the Track ≈ 128.53 m

Therefore, the total length of the track is approximately 5.28 kilometers (or 5280 meters).

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Among the reasons for the frequent use of composite measures is(are) that:
a. the researcher is seldom able to develop in advance single indicators of complex concepts.
b. a single data item might not have enough categories to provide a range of variation.
c. composite measures give a more comprehensive and accurate indication of a given variable.
d. they are efficient data reduction devices.
e. all of these choices.

Answers

Among the reasons for the frequent use of composite measures is that they give a more comprehensive and accurate indication of a given variable. Besides, the researcher is seldom able to develop in advance single indicators of complex concepts. A single data item might not have enough categories to provide a range of variation. And lastly, they are efficient data reduction devices.

So, the correct answer is option (e) all of these choices.

What are composite measures?

Composite measures are used to combine several variables or scores into a single measurement or index. In other words, they are multidimensional measurement tools. It is useful to make this kind of index because it is possible to calculate the reliability and validity of composite measures, which are statistical measures that indicate whether or not the measurements were conducted accurately or are otherwise legitimate.

For example, if a researcher wants to assess the economic development of a country, he/she could create a composite measure by combining data on GDP per capita, literacy rates, and poverty rates. In this case, each of the three variables reflects a different aspect of economic development.

So, the correct answer is E.

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What is the recommended minimum water pressure in a distribution system at any time, including fire flow conditions?
a) Greater than Zero
b) 10 psi
c) 20 psi
d) 30 psi

Answers

The recommended minimum water pressure in a distribution system at any time, including fire flow conditions, is 20 psi. Therefore, the correct answer is option c) 20 psi.

According to industry standards, the minimum recommended pressure is greater than zero, meaning that there should always be some level of pressure present in the system. However, a pressure of at least 20 psi is typically required to ensure that water is able to flow effectively through the distribution network, even under high demand or fire flow conditions. This minimum pressure also helps to ensure that water is delivered at an adequate rate and volume to meet the needs of consumers, such as for cooking, cleaning, and other household uses.

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A point charge of +10 μC is at (+3 m, 0 m) on the x-axis and a point charge of +10 μC is at (-3 m, 0 m).
1) Determine the work required to assemble this charge distribution.

Answers

Hi there!

Recall the equation for electric potential energy for point charges:
\(\boxed{U = \frac{1}{4\pi \epsilon_0} \frac{q_1q_2}{r}}\)

U = Electric potential energy (J)

ε₀ = Permittivity of Free Space (8.85 × 10⁻¹² C/Vm)

q₁, q₂: Charges (C)
r = distance between charges (m)

Solving for r:
3 - (-3) = 6m

Now, plug in the values:

\(U = \frac{1}{4\pi \epsilon_0} \frac{(.00001)(.00001)}{6} = \boxed{1.498 J}\)

An electron (rest mass 9.11x10^(-31) kg, charge is 1.60x10^(-19) C) is moving opposite to an electric field of magnitude E = 5x10^5 N/C. All other forces are negligible in comparison to the electric field force. What is the magnitude of the force on electron F = qE
a. 8x10-24N
b. 8x10-19N
c. 8x10-14N
d. 8x10-15N

Answers

The force exerted on the electron has the magnitude of  \(8\times10^{-14} N\). The force on an electric charge q in an electric field E is given by the formula F = qE.

Here, the charge on the electron is \(q = 1.60\times 10^{-19} C\), and the electric field is \(E = 5\times10^5 N/C\).

the electron's Magnitude of force is given by :\(F = (1.60\times10^{-19} C)(5\times10^5 N/C) = 8\times10^{-14} N\)

This force is directed opposite to the direction of the electric field because the electron has a negative charge. Since all other forces acting on the electron are negligible in comparison to the electric field force, we can assume that the electron moves with a constant acceleration given by F = ma. The acceleration of the electron can be determined by using the formula a = F/m.

Substituting the values, we get

\(a = \frac{8\times10^{-14} N)}{(9.11\times10^{-31} kg)} = 8.78\times10^{16} m/s^2.\)

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Question 4 of 10
Which statement describes the path of electrons from a battery to a circuit?
O A. Electrons move through the battery from the positive terminal to
the negative terminal and then into the circuit.
OB. Electrons move away from the positive end of a battery and then
through the circuit toward the negative end of the battery.
O C. Electrons move away from the negative end of a battery and then
through the circuit toward the positive end of the battery.
OD. Electrons move through the battery from the negative terminal to
the positive terminal and then into the circuit.
SUBMIT

Answers

Which statement describes the path of electrons from a battery to a circuit?

The correct answer would be:

C. Electrons move away from the negative end of a battery and then

through the circuit toward the positive end of the battery.

I need help filling this in​

I need help filling this in

Answers

Answer:

smaller and further from

Explanation:

Pass light through something clear and light, you'll most likely be able to see all of it's rays spread out, the "normal." Now, pass it through something dense, the amount of light will shrink, therefore be further from the "normal."

A 0.55 kg block is being pulled by a 2.5 n force east across a horizontal frictionless surface what is the acceleration of the block

Answers

Answer:

The answer is 4.54 m/s²

Explanation:

The acceleration of an object given it's mass and the force acting on it can be found by using the formula

\(a = \frac{f}{m} \\ \)

f is the force

m is the mass

From the question we have

\(a = \frac{2.5}{0.55} \\ = 4.545454...\)

We have the final answer as

4.54 m/s²

Hope this helps you

In an experiment, a ringing bell is placed in a vacuum jar that does not have any air in it. What best describes why the bell is seen vibrating but not heard?

Answers

Answer:

C. Light does not need a medium to travel through, but since sound waves must have a medium to vibrate, sound is not created where no air is present.

Explanation:

The reason the bell is seen to vibrate but not heard is that unlike light, which does not require a medium to pass through, sound waves require an air-filled space in order to vibrate. Option C is correct.

What is a sound wave?

A sound wave is produced when a medium begins to vibrate. When an entity vibrates, a pressure wave is formed, which causes sound.

Light does not need a medium to travel through, but since sound waves must have a medium to vibrate, the sound is not created where no air is present best describes why the bell is seen vibrating but not heard.

The complete question is attached.

Hence option C is correct.

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In an experiment, a ringing bell is placed in a vacuum jar that does not have any air in it. What best

light of wavelength 500 nm shines a grating of spacing distance d = 2.0 micrometer, which is at a distance 1.5 m from a screen. what is the angle of diffraction for the 2nd order fringe?

Answers

The angle of diffraction for the 2nd order fringe is 5.74 degrees.

To find the angle of diffraction for the 2nd order fringe, we can use the equation:

sinθ = mλ/d

where θ is the angle of diffraction, m is the order of the fringe (in this case, m = 2), λ is the wavelength of the light (500 nm = 5.0 × 10^-7 m), and d is the spacing distance of the grating (2.0 × 10^-6 m).

Plugging in these values, we get:

sinθ = 2 × 5.0 × 10^-7 / 2.0 × 10^-6

sinθ = 0.1

Taking the inverse sine of both sides, we get:

θ = sin^-1(0.1)

θ = 5.74 degrees

Therefore, the angle of diffraction for the 2nd order fringe is 5.74 degrees.

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Find the work done by the force field F in moving an object from P to Q. F(x, y) = x5i + y5j; P(1, 0), Q(3, 3)

Answers

The required work done by the force field F in moving an object from P to Q is calculated to be 303.5 units.

Work is a type of energy and it is a scalar product of force and displacement vectors.

The force vector is given as,  

F(x,y) = x⁵ i + y⁵ j

Points P is given as (1,0) and Q is given as (3,3)

The work done by the given force along the line joining the two points can be found by integrating the force vector along the direction of the line. Let us find the equation of the line segment joining the given points,

(x - 1)/(1-3) = (y - 0)/(0-3)

(x - 1)/-2 = y/-3

(x - 1)/2 = y/3

3x - 3 = 2y

Let us integrate the force vector along the given line,

1 ≤ x ≤ 3

2y = 3x - 3
2 dy = 3 dx

So, Work W = ∫(x⁵ i + y⁵ j)(dxi + dyj)

⇒ ∫(x⁵ dx + y⁵ dy)

⇒ ∫(x⁵ dx + (3x-3/2)⁵ 3dx/2)

⇒ 3/2 ∫[x⁵ + (3x-3/2)⁵] dx

⇒ 3/2 [x⁶/6 + (3x-3)⁶/(2⁵ ×6×3)] (limits from 1 to 3)

⇒ 3/2 [3⁶/6 + (3×3-3)⁶/(2⁵ ×6×3)] - 3/2 [1⁶/6 + (3-3)⁶/(2⁵ ×6×3)] = 607/2 = 303.5 units

Thus, the work done is calculated to be 303.5 units.

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Please help ASAP please

Please help ASAP please

Answers

Answer:

I would say 3N

Explanation:

Answer:

The first one is 12N and the second one is -22 m/s2

Explanation:

I'm pretty sure these are correct, i just finished that unit in school. I hope this helps:) Have a great day, God bless!

200N=75N/130M , What is the acceleration of the man which is 80kg and the box which is 50kg given the mass of 130kg and the force of 75N? friction force=125N, Box= 50 kg, Man= 80kg, Applied force= 200N, sum of forces=75N

Answers

We can calculate the acceleration of the man and the box using Newton's second law of motion. The applied force is 200 N, and the friction force opposing the motion is 125 N.

The man has a mass of 80 kg, and the box has a mass of 50 kg. The combined mass of the man and the box is 130 kg. Newton's second law states that the net force acting on an object is equal to the product of its mass and acceleration: F net = m*a. The net force (sum of forces) in this scenario is the difference between the applied force and the friction force: F net = 200 N - 125 N = 75 N.

Now we can use the combined mass of the man and the box (130 kg) and the net force (75 N) to find the acceleration:

75 N = 130 kg * a

To solve for acceleration (a), we can divide both sides by 130 kg:

a = 75 N / 130 kg ≈ 0.58 m/s²

So, the acceleration of the man and the box is approximately 0.58 m/s².

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Which type of wave causes particles of matter to vibrate in a direction
perpendicular to the direction of its motion?
O A. Sound
B. Transverse
C. Longitudinal
D. Compression

Answers

It’s transverse so the answer is B

Answer:

C.) Longitudinal

A student designed an experiment to investigate how emergency thermal blankets are used to keep a person warm in a cold environment. The student heated water on a hot plate until it reached a temperature of 100 0C. Equal amounts of the water were quickly transferred to identical containers. One of the containers was wrapped with a layer of aluminum foil and the other with clear plastic wrap. A thermometer was inserted into each container so that they touched only the water. After one hour of observation, the temperature of the water in the aluminum wrapped container was higher than the plastic wrapped container. Specific Heat Material J/kg/0C Aluminum 900 Plastic 1410 Based on the specific heat data, is the observation consistent with predicted results? Why or why not?

Answers

From the experiment, it is clear that the data is not consistent with the specific heat data.

What are emergency thermal blankets?

Many times we could find ourselves out in the cold or in a very hot environment. Most especially when we find ourselves in the cold environment, there is the need to keep warm so that we can be able to maintain the normal body temperature.

The emergency thermal blankets is one of the materials that have been posited as able to maintain the temperature of  the body and it is made of cheap plastic or polyethylene material.

We know that the material that has the higher specific heat should loose heat more slowly but this is shown not to be the case here.

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Which example illustrates Newton's first law? O A. The force of a wheelbarrow on the ground is equal to the force of the ground on the wheelbarrow. B. More mass is added to a wheelbarrow, and a larger force is required to move it. C. A person pushes a wheelbarrow, causing it to move forward. D. The force of a wheelbarrow on the ground is in the opposite direction of the force of the ground on the wheelbarrow.​

Answers

A person pushing a wheelbarrow, causing it to move forward, is the example that illustrates Newton's first law. The correct option is C.

What is force?

Force is defined as the push or pull applied to the body. Sometimes it is used to change the shape, size, and direction of the body.

According to Newton's first law, a body tries to maintain its motion until or unless the external force is not applied to it.

If a body is at rest, try to rest if the body is in motion, try to be in motion until or unless an external force is not applied to it.

The wheelbarrow being propelled forward by a human is an illustration of Newton's first law.

Hence, the correct option is C.

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A ball with an initial speed of 4.0 m/s undergoes constant acceleration at 3.0 m/s² for 5.0 s. What is the total distance traveled by the ball during this 5.0-s period?
A 38 m
B 58 m
C 75 m
D 95 m

Answers

To solve this problem, we can use the kinematic equation that relates the initial velocity, acceleration, time, and distance:

d = v₀t + 1/2at²

where d is the total distance traveled, v₀ is the initial velocity, a is the acceleration, and t is the time.

Substituting the given values into the equation, we get:

d = (4.0 m/s)(5.0 s) + 1/2(3.0 m/s²)(5.0 s)²

Simplifying and solving for d, we get:

d = 20.0 m + 37.5 m

d = 57.5 m

Therefore, the total distance traveled by the ball during the 5.0-s period is 57.5 meters.

B 58 m (rounded)
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