We will have the following:
For a positive charge, the field lines point away from the charge. [Option D]
An army tank division leaves base and travels 30 miles at [W30*S] and then turns and travels 70 miles at [W10*N]. What is their total displacement from base at the end of the trip?
The tank division's total displacement from the base is approximately 75.9 miles at a bearing of W67.4S.
How to calculate the displacement?To calculate the total displacement of the tank division, we need to find the vector sum of the two legs of their journey.
We can see that the tank division travelled 30 miles to the west (W30) and then 70 miles to the north (N70), so their total displacement is the vector sum of these two legs.
To add vectors, we need to break them down into their horizontal and vertical components.
For the first leg, the tank division travelled 30 miles to the west, so its horizontal component is -30 (since it's to the left of the base) and its vertical component is 0 (since it didn't travel up or down).
For the second leg, the tank division travelled 70 miles to the north, so its horizontal component is 0 (since it didn't travel left or right) and its vertical component is 70 (since it travelled directly north).
Now we can add these components to get the total displacement:
Horizontal component = -30 + 0 = -30
Vertical component = 0 + 70 = 70
So the total displacement is a vector with a horizontal component of -30 and a vertical component of 70.
We can use the Pythagorean theorem to find the magnitude of this vector:
|displacement| = √((-30)² + 70²) ≈ 75.9 miles
And we can use trigonometry to find the direction of this vector:
\(\theta = tan^{-1}\dfrac{70} { -30}\)
θ ≈ -67.4°
So the tank division's total displacement from the base is approximately 75.9 miles at a bearing of W67.4S.
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Calculate the absolute pressure at an ocean depth of 1.0 x 10³ m. Assume that the density of the water is 1.025 x 10³ kg/m³ and that Po = 1.01 x 10^5 Pa.
The absolute pressure at an ocean depth of 1.0 x 10^3 m is 1.002 x 10^8 Pa.
What is hydrostatic pressure?Hydrostatic pressure is the pressure that a fluid exerts on a surface due to the weight of the fluid above it. It is the result of the force of gravity acting on a column of fluid, and it is directly proportional to the height of the column of fluid and the density of the fluid.
The absolute pressure at an ocean depth of 1.0 x 10^3 m can be calculated using the hydrostatic pressure equation:
P = ρgh + Po
where:
P is the absolute pressure at the given depth
ρ is the density of the water
g is the acceleration due to gravity (assumed to be 9.81 m/s²)
h is the depth of the ocean
Po is the atmospheric pressure at the surface (assumed to be 1.01 x 10^5 Pa)
Substituting the given values, we get:
P = (1.025 x 10^3 kg/m³) x (9.81 m/s²) x (1.0 x 10^3 m) + 1.01 x 10^5 Pa
P = 1.025 x 9.81 x 10^6 Pa + 1.01 x 10^5 Pa
P = 1.002 x 10^8 Pa.
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If a paratroopers legs have enough strength to support five times her weight, and they can do so over a travel distance of 0.5 m as they flex, from what height can she free fall to a solid surface without injury
Answer: the required height is 2.5 m
Explanation:
given the given data in question
Lime to come in rest;
using S = ((U1 + U2)/2) t
⇒ 0.5 = ((√(2gh) + 0)/2) t
t = (0.5 × 2) / √(2gh)
now fat = impulse = change in momentum dp
F = 5mg = dp/dt = [(m√(2gh))/(0.5 × 2)] × √(2gh)
5mg = 2mgh/(0.5 × 2)
5 = h / 0.5
h = 5 × 0.5
h = 2.5 m
Therefore the required height is 2.5 m
(b) Figure 11.1 shows a uniform meter rule balanced horizontally on a knife-edge placed at the 58cm mark when a mass of 20g is suspended from the end. 0cm 58cm Figure 11.1 (i) Find the mass of the rule. (ii) What is the weight of the rule. (taking g = 10m/s²)? 100cm 20g [2] [2]
The mass of the rule is 3.36 kg and the weight of the rule is 33.6 N.
A knife should be balanced somewhere, right?The butt of the blade is designed to balance the majority of fine chef's knives. This is due to the fact that a pinch grip is used in both Western and Eastern cutting styles for improved control. Therefore it makes sense that you'd want your knife to be balanced where you'll be holding it.
To balance the meter rule, Assume the mass of the rule "M".
It is possible to determine the rule's magnitude and weight, which act downward:
weight of rule = M * g
where g = acceleration due to gravity.
weight of rule * (50 cm) = (20 g) * (100 cm - 58 cm)
M * g * (50 cm) = (20 g) * (42 cm)
M = (20 g * 42 cm) / (50 cm * g)
M = 33.6 g / g
M = 33.6 g / 10 m/s^{2}
M = 3.36 kg
(ii) The weight of the rule:
weight of rule = M * g
weight of rule = 3.36 kg * 10 m/s^{2}
weight of rule = 33.6 N
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Is black made of all colors?
Black is not a color, but rather a shade. In color theory, a shade is a pure color mixed with black. It decreases its lightness while nearly conserving its chromaticity. Strictly speaking, a "shade of black" is always a pure black itself and a "tint of black" would be a neutral gray. Unlike these, many off-black colors possess a hue and a colorfulness (also called saturation).
Attached is an image showing a few of the different shades of black.
Hope this helps! Brainliest would be much appreciated! Have a great day! :)
The answer is "no" because black is not made of all colors, in fact black is not a color, but black is the absence of light.
What is Light?Light is an electromagnetic radiation which can be recognized by the human eye. Electromagnetic radiation occurs at a wide variety of wavelengths, from cosmic rays with wavelengths smaller than around 1 1011 meters to radio waves estimated in meters.
Within that large spectrum, the colors visible to humans comprise a relatively small band, ranging from around 700 nanometers for red light to roughly 400 nm for violet light. The spectral areas close to the visible band are also referred to as light, with infrared at one side and ultraviolet the other.
The absence or full assimilation of visible light produces the color black. It is an anamorphic lens color with no tint, similar to white and gray. It is frequently used symbolically or colloquially to denote darkness.
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What is the momentum of a 2.3 kg ball rolling at 6 m/s?
Show your work
Answer:
13.8 (kgm)/s
Explanation:
p(momentum) = m (mass) * v (velocity)
p= 2.3 * 6
p = 13.8
How far does a person travel in coming to a complete stop in 38 ms at a constant acceleration of 60 g ?
The distance traveled by the person to come to a complete stop in 38 ms at a constant acceleration of 60 g is approximately 273.42 meters.
The distance that a person covers to come to a complete stop in 38 ms at a constant acceleration of 60 g can be calculated using the kinematic equation.
The formula is given by, d = (v^2 - u^2) / 2a, where d is the distance traveled, v is the final velocity, u is the initial velocity, and a is the acceleration given in g units.
To solve the problem, we need to first convert the acceleration given in g units to meters per second squared (m/s²). We know that 1 g is equivalent to 9.8 m/s².
Hence, 60 g is equivalent to 60 × 9.8 m/s² = 588 m/s².
Substituting the values in the above formula, we get,d = (0 - u^2) / 2a= u^2 / 2a, since the final velocity is 0 when the person comes to a complete stop= u^2 / 2 × 588= u^2 / 1176 m
The time taken, t = 38 ms = 0.038 s.
Now, we know that acceleration, a = (v - u) / t.
We can rearrange the above equation to find the final velocity, v. We get,v = u + at
Substituting the values, we get,588 = u + (588 × 0.038)u = 588 - (588 × 0.038)u = 567.816 m/s
Using the value of u, we can now find the distance traveled using the kinematic equation as, d = u^2 / 1176= (567.816)^2 / 1176≈ 273.42 m.
Therefore, the distance traveled by the person to come to a complete stop in 38 ms at a constant acceleration of 60 g is approximately 273.42 meters.
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A 62 kg skydiver is falling toward the earth near the end of his free fall at a constant velocity of -110 m/s. What net force on the sky diver?
The net force on the skydiver is 607.8 N.
What is the time of motion of the skydiver?The time taken for the skydiver to hit the ground is calculated as follows;
v = u + gt
where;
u is the initial velocity = 0v is the final velocity = 110 m/sg is acceleration due to gravity110 = 0 + 9.8t
t = 110/9.8
t = 11.22 s
The net force on the skydiver is calculated as follows;
F = ma = mv/t
where;
a is acceleration of the sky diverm is mass of the skydiverF = (62 x 110) / 11.22
F = 607.8 N
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what exercises most beneficial for your overall health
Answer:
Endurance, or aerobic
Strength, or resistance training
Balance
Flexibility
Explanation:
Answer:
Walking. Walking is simple, yet powerful. It can help you stay trim, improve cholesterol levels, strengthen bones, keep blood pressure in check, lift your mood, and lower your risk for a number of diseases (diabetes and heart disease, for example).
When looking at a sample of potatoes, what biomolecule would there be a lot of?
Potatoes mostly consist of starch, a complex carbohydrate produced by plants as a means of storing energy.
Are potatoes proteins or lipids?As starch accounts for the majority of potatoes' calories, they are categorised as a carbohydrate vegetable rather than a lipid. Potatoes, like the majority of foods, are a balance of fat, protein, and carbohydrates.
What biomolecule is the most prevalent in living things?The most prevalent biomolecules on earth are carbohydrates, which include cellulose, starch, creatine, glucose, fructose, and others. Through the process of photosynthesis, carbohydrates are created by reducing the carbon dioxide in the atmosphere with the aid of light energy.
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can the average speed ever be zero explain
Explanation : The average speed of a moving body can never be zero but the average velocity of a moving body can be zero.
Explain how the graphic organizer helped you formulate your decision and participate in the discussion.
Answer:
The graphic organizers help to keep track of the details. They are a visual representation of knowledge that rescue the important aspects of a concept using labels within a scheme. They also present information in a concise manner, highlighting the organization and the relationship of the concepts. Graphic organizers help students organize their thinking process and their writing.
Explanation:
Question 3 of 15
Which of the following statements are not true about gravity? Check all that
apply.
A. Gravity exists in the whole universe.
B. Gravity exists only on Earth.
C. Gravity is a force that pulls two objects together.
D. Gravity exists between two objects that have mass.
E. Gravity doesn't exist between Earth and the sun.
The statement "B. Gravity exists only on Earth" and the statement "E. Gravity doesn't exist between Earth and the sun" is not true about gravity.
Gravity is a fundamental force of nature that exists in the whole universe, not just on Earth. It is a force that acts between any two objects that have mass. This means that statement "C. Gravity is a force that pulls two objects together" and "D. Gravity exists between two objects that have mass" are both true. Gravity plays a significant role in the functioning of our solar system. The sun's gravitational force acts on the planets, including Earth, keeping them in their orbits. Similarly, Earth's gravitational force attracts objects towards its center, giving weight to objects on its surface. Gravity is the force that holds Earth in orbit around the sun and is responsible for the planets' motion in the solar system. Gravity is a universal force that exists throughout the universe, acts between objects with mass, and plays a crucial role in celestial bodies' movements, including the interaction between Earth and the sun.
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Greta 30 m away her truck she noticed she forgot her tea and returns back to his house. Her total travel time is 240 seconds what is greta average velocity ?
Finding average speed distance
avg = distance/time
time1 – 30 ml + 30 ml
240 s60 m240 s= 0.25m/s
The correct answer is:
• average velocity = 0 m/s
• average speed = 0.25 m/s
What is average speed?The pace at which an object's direction changes as it is traveling is referred to as its velocity and is measured by a particular unit of time and from a particular point of view.
Greta returns to his house after realizing she forgot her tea 30 meters from her pickup. Her journey takes 240 seconds in all.
What is Greta average velocity ?Avg = distance/time time for calculating average speed distance
1 - 30 ml + 30 ml
240 s60 m
240 s= 0.25m/s
The right response is:
• Average speed: 0 m/s
• The typical speed is 0.25 m/s
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If a force of 50 N is exerted on two objects, one with a mass of 14.0 kg and the other with a mass of 41.0 kg, which object will have the greater acceleration?
Recall Newton's 2nd law of motion
\(\begin{gathered} F=m\cdot a \\ a=\frac{F}{m} \end{gathered}\)The above equation means that the acceleration of an object is dependent upon the net force acting upon the object and the mass of the object.
The acceleration is directly proportional to the net force acting upon the object.
The acceleration is inversely proportional to the mass of the object.
For the given case, the net force acting upon both the objects is the same that is 50 N.
So, the mass of the objects will determine which object will have the greater acceleration.
\(\begin{gathered} a_1=\frac{F}{m_1}=\frac{50}{14.0}=3.57\; \; \frac{m}{s^2} \\ a_2=\frac{F}{m_2}=\frac{50}{41.0}=1.22\; \; \frac{m}{s^2} \end{gathered}\)As expected, the acceleration of the object is greater for the object having a smaller mass.
Therefore, the object with a mass of 14.0 kg has a greater acceleration (3.57 m/s^2)
A very bouncy mushroom can be modeled as mass of 30g(the mushroom cap) on top of a spring(the mushroom stalk) when spring constant 20 N/m. A bird of mass 50g lands on the mushroom gently so that its velocity is zero when it lands. Questions are in the image.
The motion of the bouncy mushroom can be described as a simple
harmonic motion, SHM.
a) The equilibrium height of the mushroom is 0.024525 m below its initial heightb) The frequency of resulting oscillation is 0.5 Hzc) The maximum compression of the mushroom 0.03924 md) The equation that describes the oscillation of the mushroom as a function of time is; \(\underline{x(t) = 0.014715 \cdot cos(0.5\cdot t)}\)Reasons:
The given parameters are;
Mass of the mushroom cap, m = 30 g = 0.03 kg
Mass of the bird = 50 g = 0.05 kg
The spring constant, K = 20 N/m
a) The equilibrium height of the mass spring system, is given as follows;
F = -K·x
\(x = \dfrac{F}{K}\)
The applied force, F = The weight of the bird
∴ F = (0.05 kg) × 9.81 m/s² = 0.4905 N
\(x = \dfrac{0.05 \, kg \times 9.81 \ m/s^2}{20 \, N/m} = 0.024525 \, m\)
The equilibrium height of the mushroom is 0.024525 m below its initial height.
b) The frequency of oscillation of a spring, ω, is given as follows;
\(\omega = \sqrt{\dfrac{K}{m} }\)
Therefore;
\(\omega = \sqrt{\dfrac{20 \, N/m }{80 \, kg} } = \dfrac{1}{2} \, Hz\)
The frequency of resulting oscillation, ω = \(\dfrac{1}{2} \, Hz\) = 0.5 Hz
c) The applied force, F = The weight of the bird and the mushroom cap
F = (0.03 kg + 0.05 kg) × 9.81 m/s² = 0.7848 N
\(x = \dfrac{0.7848 \, N}{20 \, N/m } = 0.03924 \, m\)
The maximum compression of the mushroom = 0.03924 m
d) The motion of the mushroom is a Simple Harmonic Motion, SHM.
The equation of a SHM as a function of time is; x(t) = A·cos(ω·t + Φ)
For the mushroom, we have;
The amplitude, A = 0.03924 m - 0.024525 m = 0.014715 m
Ф = The phase angle
When t = 0, cos(ω × 0 + Φ) = 1
cos(Φ) = 1
Ф = arcos(1) = 0
The equation is therefore;
x(t) = 0.014715·cos(0.5·t)
Equation of the oscillation of the mushroom is; \(\underline{x(t) = 0.014715 \cdot cos(0.5\cdot t)}\)
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The diagram represents a ball being kicked by a foot and rising at an angle of 30 degrees from the horizontal. The ball has a velocity of 5.0 meters per second. (Neglect Friction) If the angle between the horizontal and the direction of the 5.0 meters per second decreases from 30 degrees to 20 degrees, what is the magnitude of the horizontal component of the balls initial velocity
The magnitude of the horizontal component of the balls initial velocity if the angle between the horizontal and the direction of the 5.0 meters per second decreases from 30 degrees to 20 degrees is 4.7 m / s
cos θ = Adjacent side / Hypotenuse
θ = 20°
V = 5 m / s
Since the direction of ball makes a right angled triangle with the horizontal,
cos θ = \(V_{x}\) / V
\(V_{x}\) = cos 20° * 5
\(V_{x}\) = 0.94 * 5
\(V_{x}\) = 4.7 m / s
The formula used to solve is called as trigonometric ratios formulas. The basic formulae are:
sin θ = Perpendicular/Hypotenuse
cos θ = Base/Hypotenuse
tan θ = Perpendicular/Base
Therefore, the magnitude of the horizontal component of the balls initial velocity is 4.7 m / s
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did theoretical and experimental values agree? if they did not agree, explain why. in newton second law atwoood lab
Conclusion/Discussion In conclusion, we tested the theory of Newton's Second Law of Motion using the Atwood Machine. In order to test the proportionalities the second law suggests, I was able to plot two graphs and successfully calculate the acceleration of each of my trials.
The second law of Newton will be thoroughly investigated in this experiment. According to Newton's second law, force is defined as mass times acceleration (F=mxa). Simply said, his law outlines the connection between an object's mass, acceleration, and required force to move it.
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the lorenz curve: group of answer choices is located farther from the diagonal when income is defined to include the value of noncash transfers. is located closer to the diagonal today than it was in 1975. plots graphically the distribution of income. plots graphically the poverty rate over time
Lorenz curve is the curve that plots graphically the distribution of income. Therefore, the correct statement is statement 3.
The Lorenz curve depicts the distribution of income (or wealth) within an economy. Max O. Lorenz created it in 1905 to symbolize the distribution of income. The Lorenz curve displays the total percentage of income earned by various demographic groups.
The graph shows cumulative income or wealth on the vertical axis and percentiles of the population according to income or wealth on the horizontal axis. Lorenz curves and the statistics derived from them are frequently utilized to assess inequality within a population.
An empirical measurement of the wealth or income distribution within a population, based on information from tax returns, which detail income for a significant section of the people, is the common starting point for a Lorenz curve.
Therefore, statement 3 is correct.
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define prism and itz colo plz tell me fast
Answer:
A prism is a clear crystal that refracts light
Explanation:
The first P-wave of an earthquake travels 5600 kilometers from the epicenter and arrives at a seismic station at 10:05 a.m. At what time did this earthquake occur?
Ahhhhhh I have a Regent's test in 2 hours and I don't know how to solve this type of question! Any help would be appreciated.
Anyone know what the steps to do this are? I dont even need an answer, just how to get to it. Thank you!
The earthquake would occur 13 minutes before 10:05 a.m. which will be at 9.52 am.
The p-waves travel with a constant velocity of 7 km/s
The time can be calculated by using the formula
t = d / v
where
T1 = 10:05 a.m
d is the distance they take to travel from the epicenter
v is the speed of the p-waves
On average, the speed of p-waves is
v = 7 km/s
d = 5600 km (given)
Substituting the values in the formula;
t = d / v
t = 5600 ÷ 7
t = 800 seconds
Converting into minutes,
t = 800 ÷ 60
t = 13.3
≈ 13 mins
T1 - 13 mins = T2
10:05 - 13 mins = 9.52 am
It means the earthquake occurred prior 13 minutes, that is at 9.52 am.
Therefore, the earthquake occurred at 9.52 am.
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A corpse is discovered in a room that has its temperature held steady at 25oC. The CSI ocers ar- rive at 2pm and the temperature of the body is 33oC. at 3pm the body's temperature is 31oC. Assuming Newton's law of cooling and that the temperature of the living person was 37oC, what was the approximate time of death
Answer: Around 0:35 Pm or 12:35 Am
Explanation:
The equation that describes the cooling of objects can be written as:
T(t) = Ta + (Ti - Ta)*e^(k*t)
Where Ta is the ambient temperature, here Ta = 25°C.
Ti is the initial temperature of the body, we have Ti = 37°C.
t is the time.
k is a constant.
So our equation is:
T(t) = 25°C +12°C*e^(k*t)
at 2pm, the temperature was 33°C
at 3pm, the temperature was 31°C.
we want to find the hour where we have our t = 0, suppose this hour is X.
then we can write our times as:
2pm ---> 2 - X
3pm ----> 3 - X
and our equations are:
33°C = 25°C + 12°C*e^(k2 - k*X)
31° = 25°C + 12°C*e^(k3 - k*X)
So we have two equations and two variables, let's solve the system.
first, simplify it a bit, for the first eq:
33 - 25 = 12*e^(k2 - k*X)
8/12 = e^(k2 - k*X)
ln(8/12) = k*2 - k*X
for the second equation we have:
31 - 25 = 12*e^(k3 - k*X)
6/12 = e^(k3 - k*X)
ln(6/12) = k*3 - k*X
So our equations are:
1) ln(2/3) = 2*k - X*k
2) ln(1/2) = 3*k - X*k
First, let's isolate one of the variables in one of the equations. let's isolate k in the first equation.
ln(2/3)/(2-X) = k
now we can replace it in the second equation:
ln(1/2) = 3*ln(2/3)/(2 - X) - X*ln(2/3)/(2-X)
now let's solve it for X, i will take a = ln(1/2) and b = ln(2/3) so it is easier to read.
a = 3*b/(2 - X) - X*b/(2 - X)
a*(2 - X) = 3*b - X*b
2a - aX = 3b - Xb
X(a - b) = 2a - 3b
X = (2*ln(1/2) - 3*ln(2/3))/(ln(1/2) - ln(2/3)) = 0.590
now, knowing that one hour has 60 minutes, then this is:
0.59*60m = 35 minutes
So the hour of death is 0:35 Pm or 12:35 Am
4. A plane accelerates down a runway due to the constant resultant force of
2.7 x 10^6 N. Assume air resistance acting on the plane is a constant
6.8 x 10^4 N, and friction between the wheels and the runway is a constant
8.5 x 10^5 N. If the plane travels 1.4 km down the runway before taking off,
calculate how much work the engines do on the plane to get it up to speed.
Answer:
See below
Explanation:
Net force acting on the plane after overcoming frictional forces is
2.7 x 10^6 - 6.8 x 10^4 - 8.5 x 10^5 = 1 782 000 N
Work = F x d
= 1 782 000 x 1400 m = 2.5 x 10^9 J or 2.5 x 10^6 kJ
a roller coaster weighs 2000 kg This ride includes an initial vertical drop of 59.3 m.
Assume that the roller coaster has a speed of nearly zero as it crests the top of the hill.
If the track was frictionless, find the speed of the roller coaster at the bottom of
the hill.
The speed of the roller coaster at the bottom of the hill if the track was frictionless is 34.04 m/s.
Given that the weight of the roller coaster is 2000 kg and the initial vertical drop of the ride is 59.3 m. We are to find the speed of the roller coaster at the bottom of the hill if the track was frictionless.We know that the roller coaster will lose potential energy due to the vertical drop. Assuming there is no friction, the potential energy will be converted into kinetic energy at the bottom of the hill.Considering the conservation of energy between the potential and kinetic energy, we can set the initial potential energy equal to the final kinetic energy. We can use the formula to calculate potential energy, which is PE = mgh where m = 2000 kg, g = 9.8 m/s², and h = 59.3 m. Therefore,PE = 2000 kg × 9.8 m/s² × 59.3 m = 1,157,924 JWe can use the formula to calculate kinetic energy, which is KE = 1/2mv² where m = 2000 kg and v is the final velocity. Therefore,KE = 1/2 × 2000 kg × v².The total energy remains constant as we know there is no friction. Therefore the final kinetic energy will be equal to the initial potential energy,1,157,924 J = 1/2 × 2000 kg × v²v² = (2 × 1,157,924 J) / 2000 kgv² = 1157.924v = √1157.924v = 34.04 m/s.
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1.Briefly describe the wind motion of the stationary front
.
2.What is another name for stationary front.
Answer:
stationary front is when it is not moving that is why weather is the same in some areas
Explanation:quasi-stationary front
Remember: Weight (newtons) = mass* gravity and 1 kg = 2.2 pounds. 14. A typical NFL lineman weighs around 314 pounds. Calculate the weight in Newtons.
1,401.88 N is the required weight of the man using the given conversion factor.
Determining the weight of an objectTo calculate the weight of a typical NFL lineman in Newtons, we need to first convert the weight from pounds to kilograms using the conversion factor of 1 kg = 2.2 pounds:
314 pounds ÷ 2.2 pounds/kg = 142.73 kg
Next, we can use the formula Weight (newtons) = mass * gravity, where gravity is approximately 9.81 m/s^2 (meters per second squared):
Weight (newtons) = 142.73 kg * 9.81 m/s^2 = 1,401.88 N
The required weight in Newton of the man is 1,401.88 N
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Kepler’s second law states that1) the orbits of the planets are elliptical.2) the speed of a planet’s orbit varies depending on which part of the ellipse it is occupying.3) the square of the ratio of the periods of any two planets revolving around the Sun is equal to the cube of the ratio of their average distance from the Sun.4) objects attract other objects with a force that is directly proportional to the product of their masses, and inversely proportional to the square of the distance between
Kepler's second law states that the speed of planet's orbit varies depending on which part of the ellipse it is occupying. Thus, option (2) is correct.
What is the cost per month to operate an A.C. 10hours per day whose power is 3kW and 1KWH cost 79francs
The cost of operation for an A.C for 10 hours per day for a month will be 71,100 francs.
What is Power?Power is the amount of energy transferred or converted per unit time. The unit of power is the watt, equal to one joule per second. Power is a scalar quantity.
Cost of operation for 10 hours a day;
Daily consumption = 3kW x 10 hours
Daily Consumption = 30kW
Since 1kWH = 79 francs;
Daily consumption amount = 30 x 79 francs
Daily consumption amount = 2,370 francs
Therefore, the monthly consumption (using 30days) will be;
2,370 francs x 30 = 71,100 francs
In conclusion, 71,100 francs will be spent in a month (30 days) to run the 3kW rated A.C for 10 hours a day at 1kWH.
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1)What is the pressure at point D in kPa ?
2)Temperature at point D
3)What is the net work done on the gas as it is taken through four cycles?
4)What is the internal energy of the gas when it is at point A?
5)What is the total change in internal energy of this gas during four complete cycles?
The answer is 1) The pressure at point D is 80 kPa. 2) The temperature at point D is 800 K. 3) The net work done on the gas over four cycles is zero. 4) The internal energy of the gas at point A is 100 J. 5) The total change in internal energy during four complete cycles is zero.
The total change in internal energy of this gas during four complete cycles is zero. The given diagram represents the Carnot cycle involving four stages. The four stages of the Carnot cycle are reversible and follow an ideal gas that is placed in a cylinder with a movable piston.Let's solve each question asked one by one.1) From the graph, it can be observed that the pressure at point D is 0.08 M Pa, which is equal to 80 kPa. Hence, the pressure at point D in kPa is 80 kPa.2) Temperature at point D The isotherm at point D is about 800 K. Hence, the temperature at point D is 800 K.3) The net work done on the gas as it is taken through four cycles is zero because the Carnot cycle is a cycle that has four stages. In each cycle, the net work done is the area enclosed by the cycle. Therefore, for a complete cycle, the net work done is zero because the area enclosed is a loop.4) The internal energy of the gas when it is at point A is 100 J because the internal energy of the gas is directly proportional to the temperature and volume. Here, at point A, the temperature is 500 K, and the volume is 2 m³, so the internal energy of the gas when it is at point A is 100 J.5) The Carnot cycle is a reversible cycle that is used to determine the efficiency of heat engines. It is a closed cycle that does not involve any net energy exchange with the surroundings. Therefore, the total change in internal energy of this gas during four complete cycles is zero since the initial and final states are the same. Hence, the total change in internal energy of this gas during four complete cycles is zero.For more questions on the Carnot cycle, click on:
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allung d Uall, Wily
In which condition is mirage seen ? Why is light dispersed ?
Answer:
Mirage is a phenomenon which can be seen when the surface air gets heated up and it becomes lighter. Lighter air moves up in the atmoshphere.
Explanation:
When the lighter air from cooler areas to warmer areas are refracted and they bent upwards.and it dispers
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