The temperature would be raised quite high so as to increase the temperature of the water due to its specific heat capacity.
What is the specific heat?We know that the specific heat capacity of the substance has to do with the amount of heat that must be supplied so as to be able to raise the temperature of the material by 1 degree.
We know that water is a substances that has a very high specific heat capacity as such the experiment would require that we heat up the water to a very high temperature so that the temperature of the water would improve.
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Which of the following best describes the difference between the functions of carbohydrates and nucleic acids?
A)Carbohydrates store energy efficiently, while nucleic acids store and pass on a cell's genetic
information
B)Carbohydrates trigger a variety of metabolic processes in cells, while nucleic acids decode and
express genetic information as proteins.
C)Carbohydrates reinforce the structure of cells, while nucleic acids break down cell membranes.
D)Carbohydrates store energy in fats, while nucleic acids donate energy to various biochemical
reactions.
Answer:
In my knowledge
Its option A
The first vestiges of eyes in the embryo are called ________. Select one:a. optic cups b. mesenchyme c. optic discs d. optic vesicles
The first vestiges of eyes in the embryo are called d. optic vesicles.
During embryonic development, the first vestiges of eyes are formed as outgrowths from the developing brain known as optic vesicles.
The optic vesicles arise from the neural tube and give rise to various structures of the eye. These structures include the retina, lens, and optic nerve.
The optic vesicles eventually invaginate to form the optic cups, which further differentiate into different layers of the retina. The optic discs, on the other hand, refer to the region where the optic nerve exits the eye and is not specifically related to the initial development of the eyes.
Therefore, the correct answer is d. optic vesicles.
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Which of the following are correct statements about the roles of DNA and RNA in a cell?
I. DNA contains the genetic instructions used in the development and functioning of living cells.
II. mRNA carries the genetic code from the nucleus to the ribosome for the creation of proteins.
III. TRNA transfers the amino acid to the ribosome for the creation of proteins.
A. I, II, and III
B. II and III only
C. I and III only
D. I and II only
2 pts you are looking at an adult pine tree. there are no cones present on the tree. only the dominant generation is present. what generation are you observing for the adult pine tree?
The generation that is being observed for the adult pine tree is the sporophyte generation.
The sporophyte generation is the dominant generation in the life cycle of plants that belong to the phylum Coniferophyta, such as pine trees.
The sporophyte is the tree that produces cones and seeds, as well as the vegetative structures of the plant.
The adult pine tree without cones indicates that it is a mature sporophyte generation. The gametophyte generation is a short-lived generation in the life cycle of plants that belongs to the phylum Coniferophyta.
When pine trees develop male and female cones, they are in the gametophyte phase of their life cycle. A sporophyte is a generation in the life cycle of plants in which diploid sporophyte cells undergo meiosis to produce haploid spores.
The sporophyte is the dominant generation in the life cycle of higher plants, which means that it is usually the larger and more conspicuous phase of the plant's life cycle.
A gametophyte is a stage in the life cycle of plants in which haploid gametes are produced. The gametophyte stage is characterized by the production of gametes that can unite to form a zygote, which grows into a new sporophyte generation.
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28. which of the following joints could not be safely reduced in a wilderness setting?
Answer:
Explanation:
To determine which joints could not be safely reduced in a wilderness setting, it is important to consider the complexity and potential risks associated with joint reduction.
Joint reduction involves manipulating the bones and structures around a joint to realign them properly. Wilderness settings typically lack the necessary resources and medical expertise available in a clinical setting, which can limit the options for safe and effective joint reduction. While I don't have the specific options you are referring to, certain joints are generally considered more complex and riskier to reduce in a wilderness setting. These include:
Complex joints: Joints that have intricate anatomical structures, such as the temporomandibular joint (jaw), sternoclavicular joint (between the sternum and clavicle), and acromioclavicular joint (between the acromion and clavicle), often require specialized knowledge and tools for safe reduction. Wilderness settings are unlikely to have the necessary equipment or expertise.
Weight-bearing joints: Joints that bear a significant amount of weight and forces, such as the hip and knee joints, may require more controlled and precise reduction techniques. In a wilderness setting, it may be difficult to ensure proper alignment and stabilization of these joints during reduction.
Joints with associated neurovascular structures: Joints that have important neurovascular structures in close proximity, such as the elbow joint or knee joint, can be challenging to manage in a wilderness setting. Mishandling or inadequate reduction of these joints could lead to nerve or blood vessel injuries.
In general, any joint reduction procedure in a wilderness setting should be approached with caution, and it is crucial to prioritize the safety and well-being of the injured individual. It is recommended to seek professional medical assistance as soon as possible to ensure appropriate and safe management of joint injuries.
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This person has children with a partner that does not have hemophilia. Is it possible for any of their children to have hemophilia?
Answer:
A family may have children with the hemophilia gene and children without it. It is also possible for all the children in the family to inherit the normal gene or all to inherit the hemophilia gene.
Explanation:
why is biomass difficult to calculate PLEASE HURRY!!!!!!!
Answer:
There are many methods to directly measure biomass of herbaceous plants, but, it is difficult to estimate biomass of shrubs and trees. Peak standing crop may be difficult to measure in ecosystems with a large variety of species because each species will generally reach it's peak phytomass at a different time of year.
Explanation:
In pea plants there is a dominant allele (A) for green pods and a recessive allele (a) for yellow pods. Suppose a heterozygous plant is crossed with a plant that has yellow pods. Complete the sentences about this monohybrid cross with the correct terms.
The phenotype of the heterozygous plant is
The genotype of the heterozygous plant is
The genotype of the plant with yellow pods is
The genotype of the gametes produced by the heterozygous plant is
The genotype of the gametes produced by the plant with yellow pods is
The expected frequency of F_1 plants with yellow pods is
The expected frequency of F_1 plants with the genotype AA is
Aa
75% A and 25% a
25%
50% A 50% a
0%
green pods
75% AA and 25% Aa
AA
yellow pods
75%
aa
50%
100% A
100% a
Answer and Explanation:
The phenotype of the heterozygous plant is green podsThe genotype of the heterozygous plant is AaThe genotype of the plant with yellow pods is aaThe genotype of the gametes produced by the heterozygous plant is 50% A 50% aThe genotype of the gametes produced by the plant with yellow pods is 100% a The expected frequency of F_1 plants with yellow pods is 50%The expected frequency of F_1 plants with the genotype AA is 0%Cross) a heterozygous plant is crossed with a plant that has yellow pods
Parental) Aa x aa
Phenotype) Green pods Yellow pods
Gametes) A a a a
50% 50% 100%
Punnet Square) A a
a Aa aa
a Aa aa
F1) 2/4 = 1/2 = 50% Aa, Plant with Green pods
2/4 = 1/2 = 50% aa, Plant with Yellow pods
In the given case, the correct terms are:
The phenotype of the heterozygous plant is green pods The genotype of the heterozygous plant is Aa The genotype of the plant with yellow pods is aa The genotype of the gametes produced by the heterozygous plant is 50% A 50% a The genotype of the gametes produced by the plant with yellow pods is 100% a The expected frequency of F_1 plants with yellow pods is 50% The expected frequency of F_1 plants with the genotype AA is 0%It is given that A gives green color which is dominant and a gives yellow pods which is a recessive trait. So in heterozygous conditions, only the dominant character will express itself therefore green color pods
The phenotype of heterozygous plants is Green podsIn heterozygous conditions, the alleles of a genotype are different. Therefore one allele is A and the other is a
The genotype of the heterozygous plant is AaThe yellow color of pods is a recessive trait and recessive trait if expressed only in the same alleles conditions that mean it is given by allele a. Therefore, the genotype of yellow pods is aa
The genotype of the plants with yellow pods is aaThe alleles in the heterozygous conditions are A and a so half of the gametes will have A and the other half have a
The genotype of gamete produced by heterozygous plants are 50% A and 50% aThe yellow pods are obtained by genotype aa. All the gametes are a
The genotype of gametes produced by the plants with yellow pods is 100% aCross:
A a
a Aa aa
a Aa aa
In the cross, there are 2 genotypes produced as aa out of four. So 2/4 × 100 will give 50%
The expected frequency of F1 plants with yellow pods is 50%There are no genotypes obtained as AA in the cross. Therefore, 0 out of 4 offspring will give 0%
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When mammals get an infection, their internal body temperature often rises 2 to 3 degrees Celsius. The body gets the energy it needs to react to an infection by -
Answer:
The correct answer is - increasing the rate of cellular respiration in the mitochondria.
Explanation:
During the infection, the body of mammals increases its temperature to kill the pathogens that normally die at high temperatures. To increase the body temperature our body promotes the rate of cellular respiration in the cells to produce more energy.
Cellular respiration is the process that helps in converting stored energy into a form of useable energy for the cell which is ATP. It takes place in the mitochondria of the cell which is called as the powerhouse of the cell and all the function related to energy or ATP is conducted by here.
agro forestry PROJECT
i) Design a agroforestry project plan in 4 pages
ii) Draft the logical framework for the project showing the goals, input, output, indicators etc
iii) Develop the management tools that will be practiced to ensure success of the business
i) Agroforestry Project Plan: Introduction, objectives, components, implementation strategy, budget, and sustainability plan.
ii) Logical Framework: Goals, inputs, outputs, and indicators for measuring success.
iii) Management Tools: Planning, stakeholder engagement, training, monitoring, financial management, knowledge sharing, and sustainability planning.
i) Agroforestry Project Plan:
Page 1: Introduction and Objectives
- Introduction to agroforestry and its benefits
- Project objectives: Increase farm productivity, enhance environmental sustainability, and generate additional income
Page 2: Project Components
- Component 1: Agroforestry system design and implementation
- Component 2: Capacity building and training for farmers
- Component 3: Provision of necessary inputs (seeds, tools, etc.)
- Component 4: Monitoring and evaluation of project activities
Page 3: Implementation Strategy
- Timeline for project activities
- Roles and responsibilities of project team members
- Engagement with local communities and stakeholders
Page 4: Budget and Sustainability
- Project budget breakdown
- Potential sources of funding and income generation
- Long-term sustainability plan for the agroforestry system
ii) Logical Framework for Agroforestry Project:
Goal: Improve farm productivity, enhance environmental sustainability, and generate additional income through agroforestry.
Inputs:
- Land for agroforestry system
- Seeds and saplings
- Farming tools and equipment
- Training materials and expertise
Outputs:
- Established agroforestry system
- Trained farmers adopting agroforestry practices
- Increased crop and tree yields
- Reduced soil erosion and improved soil fertility
Indicators:
- Number of farmers trained in agroforestry
- Percentage increase in crop and tree yields
- Reduction in soil erosion rates
- Increase in household income from agroforestry activities
iii) Management Tools for Agroforestry Project Success:
1. Project Planning and Scheduling: Develop a detailed project plan with timelines and milestones, ensuring efficient resource allocation and progress tracking.
2. Stakeholder Engagement: Foster collaboration and communication with local farmers, community leaders, and relevant organizations to garner support and ensure project alignment with their needs.
3. Capacity Building and Training: Provide comprehensive training programs on agroforestry techniques, maintenance, and sustainable practices to empower farmers and enhance their skills.
4. Monitoring and Evaluation: Establish a robust monitoring system to track progress, evaluate outcomes, and make informed decisions for project adjustments and improvements.
5. Financial Management: Implement effective financial management practices, including budgeting, expense tracking, and reporting, to ensure proper allocation of funds and transparency.
6. Knowledge Sharing and Documentation: Document project activities, lessons learned, and best practices, and facilitate knowledge sharing among project stakeholders to promote continuous learning and replication.
7. Sustainability Planning: Develop strategies for long-term project sustainability, such as establishing farmer cooperatives, accessing markets, and creating income-generating opportunities beyond the project duration.
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What can you infer from this graph?
Answer: you can infer that I don’t give a uriruru
What makes DNA Replication possible?
Answer:
The amount of cells in the body and the genes from each parent.
Explanation:
Answer:
The initiation of DNA replication occurs in two steps. First, a so-called initiator protein unwinds a short stretch of the DNA double helix. Then, a protein known as helicase attaches to and breaks apart the hydrogen bonds between the bases on the DNA strands, thereby pulling apart the two strands.
Explanation:
An experiment in which part of a rat's hypothalamus is destroyed to examine the effects on eating behavior utilizes a technique known as
The technique used in the experiment you described, where part of a rat's hypothalamus is destroyed to examine the effects on eating behavior, is called "lesioning" or "lesion study."
Lesioning involves selectively damaging or removing specific brain regions to investigate their function and the resulting behavioral changes. Deep inside the human brain lies a structure known as the hypothalamus. It serves as the primary connection between the human neurological system and endocrine system. The human hypothalamus maintains the body's equilibrium in a steady condition known as homeostasis. The human peripheral nervous system, which also responds to signals from outside the human body, as well as nerve cells in the human brain and hypothalamus, send chemical messages to the brain.
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What is the normal/average pH level of lake in a healthy ecosystem?
Usually fresh water lakes have a pH range between 6.5 to 8.5, this is appropiate for many organisms life and development.
Which is BEST paired?
a)Phloem: water
b)Xylem: sugar
c)Phloem: gas exchange
d)Xylem: water
If pyruvate processing is blocked, what will happen to the levels of oxaloacetate and citrate in the citric acid cycle?.
There will be an increase in oxaloacetate and a decrease in citrate.
What happens if a cell doesn't have enough oxaloacetate?Since pyruvate cannot produce oxaloacetate, it is diverted to alternative pathways instead, which result in the production of lactic acid and alanine. Oxaloacetate is necessary for the urea cycle and gluconeogenesis to occur.
The citric acid cycle's importance of oxaloacetate is explained.Response and Justification: One of the crucial intermediates of the Krebs cycle is oxaloacetate. It reacts with acetyl-CoA to produce citrate as a byproduct.
When the citric acid cycle is complete, what happens to the malate or oxaloacetate?Malate is dehydrogenated to create the new oxaloacetate required for the cycle's final reaction, which allows acetyl coA to enter.
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At the end of this process in this cell, each DNA strand is...
Completely built new with a different code
Is one half the original DNA and one half new DNA with the same code as the original strand preserved
Is one half the original DNA and one half new DNA with a different code
Answer:
Is one half the original DNA and one half new DNA with the same code as the original strand preserved
Explanation:
I am assuming the process is DNA replication.
The process of DNA replication:
step 1- the DNA double helix unwinds using an enzyme called dna helicase. Proteins hold the strands apart from each other forming a Y shape called the replication fork.
step 2- At the replication fork, enzymes called DNA polymerase move along each of the DNA strands adding complementary bases to the nitrogen bases using base pairing rules.
step 3- DNA polymerases add nucleotides to a growing double helix until all the DNA is copied
result- 2 new DNA molecules, each made of one original strand and one copied strand
Why are there several structurally different pigments in the reaction centers of photosystems? group of answer choices
The reaction centers of photosystems contain multiple pigments of different types and structures. This structural diversity allows them to efficiently absorb light of different wavelengths and transfer the energy to the reaction center for the production of ATP.
Photosynthesis is the process by which plants and other organisms convert light energy into chemical energy.
In photosynthesis, there are two main photosystems, photosystem I (PSI) and photosystem II (PSII), located in the thylakoid membrane of chloroplasts.
These photosystems contain several pigments that are involved in light absorption. Some of the pigments in the reaction centers of photosystems are chlorophyll a, chlorophyll b, carotenoids, and phycobilins.
Chlorophyll a is the most abundant and primary pigment involved in photosynthesis, while other pigments act as accessory pigments that broaden the spectrum of light absorption.
These accessory pigments have different structures and absorb light of different wavelengths than chlorophyll a. Therefore, structurally different pigments are present in the reaction centers of photosystems to maximize the absorption of light and allow for efficient energy transfer to the reaction center.
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2. What is the key function of RNA?
microscopic membrane extensions that extend from the plasma membrane are calleda. cilia b. microvilli c. flagella d. mucus
Microscopic membrane extensions that extend from the plasma membrane are B, microvilli
Microvilli refers to one of many microscopic hair-like projections on the surface of a certification cell. This is an extension of the cytoplasm linked to the plasma membrane; however, there are no organelles except microfilaments. The microfilm is essentially made of actin filaments bound to each other by fimbrin and villin proteins.
Microvilli can be found on the open surface of proximal convoluted small intestine epithelial cells and renal tubules.
Microvilli should not be confused with the ultimate villi, which is a finger-like projection on the epithelial layer of the ultimate wall. This villi greatly increases the surface area for absorption. They're covered with brush borders. The brush border consists of solid microvilli. Thus, in addition to villi, microvilli further increases the absorption surface area of the small intestine.
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Suppose a farmer is in the business of growing carnations for a local flower shop. He typically grows red, white, and pink flowers. In his carnations, flower color is determined by a single locus and two alleles. The flower color phenotype exhibits incomplete dominance, so all heterozygous flowers are pink. Homozygous flowers are either red or white. The farmer would like the plants to produce enough of each color flower to meet customer demand which is conveniently the standard mendelian ratio of 1:2:1 of white:pink:red flowers. He hypothesizes this ratio can be obtained by letting the flowers self-cross. The farmer plants 1000 total seed of 250 white flowers, 250 red flowers, and 500 pink flowers and lets the plants self-fertilize and perpetuate over three growing seasons. He predicts the ratio will remain the same each generation.
Analyze the averaged collected data from the farmer\'s field trials and select the conclusion that best fits the farmer\'s results
According to the given information, a farmer grows red, white, and pink carnations for a local flower shop. He can obtain the standard Mendelian ratio of 1:2:1 of white: pink: red flowers by letting the flowers self-cross.
The flower color phenotype exhibits incomplete dominance, and all heterozygous flowers are pink. Homozygous flowers are either red or white. The farmer wants the plants to produce enough of each color flower to meet customer demand, which is conveniently the standard Mendelian ratio of 1:2:1 of white: pink: red flowers.
He hypothesizes that this ratio can be obtained by letting the flowers self-cross. He plants 1000 total seed of 250 white flowers, 250 red flowers, and 500 pink flowers and lets the plants self-fertilize and perpetuate over three growing seasons.
He predicts the ratio will remain the same each generation.Analysis of collected data: The farmer predicts that by letting the flowers self-cross, the ratio will remain the same in each generation. The ratio of white: pink: red flowers in the first generation is 1:2:1, which is exactly what the farmer wanted. If the same ratio is maintained, then the second and third generations should also have the same ratio of white: pink: red flowers. Conclusion:The farmer's results confirm that his hypothesis was correct.
The results of his self-crossing experiment showed that the ratio of white: pink: red flowers remained the same in each generation, exactly what he had predicted. Thus, he can obtain the standard Mendelian ratio of 1:2:1 of white: pink: red flowers by letting the flowers self-cross.
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In which kingdom does mold lie ? on 28th Jestha buy a bread and moisturize it with water and keep it not plate.) Moisturize daily with water. What changes do you see in bread? Pocket on a transparent polyethene bag and bring it on 5th Asar? class 9 subject science
Mold belongs to the kingdom of Fungi.
When you buy bread on the 28th of Jestha and moisturize it with water, and then keep it in a pocket on a transparent polyethylene bag until the 5th of Asar, you are creating conditions that are conducive to the growth of mold.
Mold is a type of fungus that thrives in moist environments and feeds on organic matter, such as bread.
Over time, you are likely to observe visible changes in the bread. The moisture present in the bread provides an ideal environment for mold spores to germinate and grow. Initially, you may notice the appearance of small, fuzzy spots or patches on the bread's surface, which are characteristic of mold growth.
These spots can vary in color, ranging from green, blue, or white to black, depending on the specific type of mold present. As the mold continues to grow, it may spread and cover a larger area of the bread, leading to a degradation of its texture and quality. The bread may also develop a musty or unpleasant odor.
Overall, the presence of mold on the bread is a result of the favorable conditions created by moisture and the introduction of mold spores, which belong to the kingdom Fungi.
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I NEED AN ANSWER. PLEASE!!!.
What are autotrophs and heterotrophs.
Answer:
Autorophs are living organisms that make their food through photosynthesis while heterotrophs are living organisms that can not make their own food, so they must eat it.
Explanation:
Hope it helps!
Answer: Autotrophs make their own food (plants some protists and some bacteria) and heterotrophs cannot make their own food they must obtain energy from outside sources (animals fungi and some bacteria)
Explanation:
what is haploid?
explain it
Answer:
Haploid is the quality of a cell or organism having a single set of chromosomes. ... Sexually reproducing organisms are diploid (having two sets of chromosomes, one from each parent). In humans, only their egg and sperm cells are haploid.
Answer:
Haploid cells contain a single set of chromosomes. Gametes are an example of haploid cells produced as a result of meiosis. Examples of gametes are the male and female reproductive cells, the sperm and egg cell respectively.
Explanation:
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Challenge: test tubes 11-15 all contain mixtures of three substances. run the five texts on these powers, and identify the three substances in each tube. (note: sometimes there will be more than one possible answer.)
The substances in each tube are as follows:
Tube 11: Gelatin, salt, and corn starch.Tube 12: Baking soda and corn starch.Tube 13: Corn starch.Tube 14: Salt and corn starch.Tube 15: Baking powder and corn starch.Test Tube 11: Coarse powder, acidic, no bubbles with vinegar, protein positive with biuret, no reaction with iodine - Possible substances: Sugar, salt, and gelatin.
Test Tube 12: Fine powder, basic, bubbles with vinegar, no protein reaction with biuret, no reaction with iodine - Possible substances: Baking soda, sugar, and salt.
Test Tube 13: Fine powder, both acidic and basic, no bubbles with vinegar, no protein reaction with biuret, positive reaction with iodine - Possible substances: Vinegar, sugar, and corn starch.
Test Tube 14: Coarse powder, both acidic and basic, no bubbles with vinegar, no protein reaction with biuret, no reaction with iodine - Possible substances: Salt, sugar, and gelatin.
Test Tube 15: Fine powder, both acidic and basic, bubbles with vinegar, no protein reaction with biuret, no reaction with iodine - Possible substances: Baking powder, salt, and sugar.
Please note that the identification of substances is based on the given tests and their respective reactions. However, without additional information or further confirmatory tests, the exact composition of the mixtures cannot be definitively determined. The possibilities provided are based on the observed results and common substances that could yield similar reactions.
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Before entering the Krebs cycle, an intermediate molecule bonds to a 2-carbon molecule. This intermediate complex enters into the Krebs cycle, and combines with a 4-carbon molecule to form citric acid. The name of this molecule is _____.
Answer:
The link reaction occurs after glycolysis and before the Krebs cycle. It begins with pyruvate, which loses a carbon as carbon dioxide is formed - leaving a 2-carbon molecule. The link reaction terminates with the production of acetyl coenzyme A.
Explanation:
Wich characteristic of a phospholipid membrane keeps the aqueous environment inside and outside the cell separate?
Answer: The hydrophobic, or “water-fearing,” part of a phospholipid consists of its long, nonpolar fatty acid tails. The fatty acid tails can easily interact with other nonpolar molecules, but they interact poorly with water.
The characteristic of a phospholipid membrane keeps the aqueous environment inside and outside the cell separate and the character is hydrophobic or water fearing.
What is membrane?Cell membrane has been defined as a wall that has differentiated and protect the inner structure of the cell from the outer environment. The main function of the cell membrane has to keep away the toxic material out of the cell. The cell membrane has contain channels as well as receptors that gives permission to only selective permeable membrane to enter into the cell.
Cell cycle has been defined as cycle in which the cell is able to produces, grows and divides. The cell cycle has mainly three steps the first one has been known as G1 phase in which the size of the cell increases, S phase has been synthesis of DNA takes place and the third step has been known as G2 phase in which cell ready to divide.
Cell has been defined as the base of life as it has the structural as well as functional unit of life. Cell has made up of pre existing cells and the cell contain various cell organelles such as the mitochondria, endoplasmic reticulum, ribosomes, golgi appratus, nucleus, and cytoplasm.
Therefore, The characteristic of a phospholipid membrane keeps the aqueous environment inside and outside the cell separate and the character is hydrophobic or water fearing.
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Question 28
Use specific examples to compare and contrast the flow of energy and nutrients.
Answer:
nn n
Explanation:
the c5a peptidase enzyme of streptococcus pyogenes breaks down c5a resulting in inhibition of the membrane attack complex in the complement cascade true or false
True. The c5a peptidase enzyme of streptococcus pyogenes is known to break down c5a, which is a chemotactic peptide that plays a critical role in the complement cascade.
C5a is responsible for recruiting immune cells to the site of infection and initiating the membrane attack complex (MAC) formation. However, when c5a is broken down by the c5a peptidase enzyme, the recruitment of immune cells to the site of infection is inhibited, and the formation of the MAC is prevented. This results in the suppression of the immune response, allowing streptococcus pyogenes to evade detection and survive in the host.
Therefore, the statement that the c5a peptidase enzyme of streptococcus pyogenes breaks down c5a, resulting in inhibition of the membrane attack complex in the complement cascade is true.
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What is removed to form mature eukaryotic mRNA?A. RNA primersB. ExonsC. RNA polymerasesD. Introns
From the pre-mRNA, the introns are removed in order to form the mature eukaryotic mRNA.
The correct option is option D.
The process of splicing occurs after the process of transcription and is a part of the editing of the RNA. It is a very important process as it basically allows the production of the mature mRNA and dictates the gene products which will be formed.
During the process of splicing, the introns are basically removed from the pre-mRNA, and the remaining exons are basically then stuck together in order to form a mature mRNA which does not happen to contain the intron sequences.
Hence, the correct option is option D.
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