g 0 g bullet is fired horizontally into a 1.20 kg wooden block resting on a horizontal surface. The coefficient of kinetic friction between block and surface is 0.20. The bullet remains embedded in the block, which is observed to slide 0.390 m along the surface before stopping. Part A What was the initial speed of the bullet? Express your answer with the appropriate units. v = nothing
Answers
Answer:
vb = 298 m/s
Explanation:
Given:-
- The mass of the bullet, mb = 5.00 g
- The mass of the wooden block, mw = 1.2 kg
- The coefficient of kinetic friction between block and horizontal surface, \(u_k = 0.2\)
- The bullet and block combined moves a distance after impact, s = 0.390
Solution:-
- We will first consider the motion of the block and bullet combined after the bullet is embedded into the block.
- We are told that the wooden block is rested on a horizontal floor with coefficient of kinetic friction ( uk ).
- When the bullet is embedded into the block. Both combined will move with a velocity ( V ). Both will eventually loose all of their kinetic energy by doing work against the friction.
- We will apply the work - energy principle to the system ( block + bullet ) as follows:
\(W = dE_k\)
Where,
W: Work done against friction
dEk: The change in kinetic energy of the system
- The work-done against friction is the product of frictional force ( Ff ) and the displacement over which the system travels ( s ).
- The frictional force ( Ff ) is proportional to the contact force ( N ) between the system and the surface.
- Apply static balance on the system in the direction normal to the surface as follows:
\(N - ( m_b + m_w )*g = 0\\\\N = ( m_b + m_w )*g\)
- The frictional force is defined as:
\(F_f = u_k*N\\\\F_f = u_k* ( m_b + m_w ) * g\)
- The work done against friction ( W ) is defined as:
\(W = F_f*s\\\\W = u_k*(m_b + m_w )*g*s\)
Where,
g: the gravitational acceleration constant = 9.81 m/s^2
- Now use the energy balance to determine the velocity of the system after impact ( V ):
\(u_k*( m_b + m_w )*g*s = 0.5*( m_b + m_w )*V^2\\\\V = \sqrt{2*u_k*g*s } \\\\V = \sqrt{2*0.2*9.81*0.39 }\\\\V = 1.23707 m/s\)
- Now we will again consider an independent system of bullet and the wooden block resting on the horizontal surface.
- The bullet is fired with velocity ( vb ) towards the wooden block. The system can be considered to be isolated and all other fictitious effects can be ignored. This validates the use of conservation of linear momentum for this system.
- The conservation of linear momentum denotes:
\(P_i = P_f\)
Where,
Pi: the inital momentum of the system
Pf: the final momentum of the system
- Initially the block was at rest and bullet had a velocity ( vb ) and after striking the bullet is embedded into the block and moves with a velocity ( V ).
\(m_b*v_b = ( m_b + m_w )*V\\\\v_b = \frac{ ( m_b + m_w )}{m_b}*V\\\\v_b = \frac{ ( 0.005 + 1.2 )}{0.005}*(1.23707)\\\\v_b = 298 m/s\)
Answer: The initial speed of the bullet is equivalent to the speed of the bullet just before the impact as vb = 298 m/s. This is under the assumption that forces like ( air resistance or gravitational or impulse) have negligible effect.
Related Questions
A woman on a bicycle travels at 9 m/s relative to the ground as she passes a little boy on a tricycle going in the opposite direction. If the boy is traveling at 1 m/s relative to the ground, how fast does the boy appear to be moving relative to the woman
Answers
Answer:
Useless
Explanation:
Question
Question is attached below
Answers
(a) the shell's horizontal range = 285839 m.
(b) the amount of time the shell is in motion is: 273.11 sec.
What is horizontal range?The length of the horizontal axis is a projectile's horizontal range. In addition, it would move before returning to the original vertical position.
Horizontal range is equal to Initial Speed in the horizontal direction, multiplied by the time the shell is in motion. Therefore, both questions can be solved at the same time.
Step 1. Find Velocity in the Horizontal direction by:
Vx = (1.70 x 10³) × cos(52°)
Vx = 1046.6 m/sec
Step 2. Find Velocity in the Vertical direction by:
Vy = (1.70 x 10³) × sin (52°)
Vy = 1339.6 m/sec
Step 3. Find the amount of time the shell is in motion by:
t= (2 × Vy)/gravity
t = (2 × 1339.6) / 9.81 [ Gravity = 9.81m/s²]
t = 273.11 sec
Step 4. Find the shell's horizontal range:
Distance = Vx × t
or, distance = (1046.6 × 273.11)
or, distance = 285839 m
Thus, (a) the shell's horizontal range = 285839 m.
(b) the amount of time the shell is in motion is: 273.11 sec.
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7 , 1 , 5 , 3 , multiple choice quiz is on apex
Answers
From the histogram given, there were at approximately 7 downloads between 3pm and 4pm . This can be derived by counting the rows in that time period.
What is a histogram?A histogram is a graph that depicts the frequency distribution of a few data points from a single variable.
Histograms frequently divide data into "bins" or "range groups" and count the number of data points that belong to each of those bins.
Histograms are frequently used to depict the key properties of data distribution in a handy format. It is especially beneficial when working with huge data sets (more than 100 observations). It can aid in the detection of uncommon observations (outliers) or gaps in the data.2
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40 points
For this assignment, you will research how to design and build a solar cooker. Search reliable online sites
for “solar cookers.” After getting the materials you need from your teacher, you will present your initial
design as a drawing or illustration. You will then build your device and test its efficiency by warming up a
hot dog until it reaches an internal temperature of 165°F, recording how long it took you to reach this
temperature. Based on your tests, you will make recommendations on how to improve the design of your
solar cooker, and then present your final design and the logic that supports it in a lab report. Your lab
report should include a title, a list of materials that you used to build your solar cooker, a drawing of your
initial design, observations from your experimental tests, recommendations for a final design based on
what you know about radiation, a drawing of your final design, and the results of the efficiency test. To
help you write your lab report, there is a Student Worksheet on the last few pages of this document.
Answers
Answer:
Ideas for Prototype Design
Similar to a cardboard oven just smaller and solar powered
Preliminary Sketches (attach separate paper, if needed)
Option A: i gave the picture
____________________________________________________________
Advantages: Disadvantages:
● the tin foil will attract the sun● if theres enough heat for the food to warm up
●the plastic will keep bugs and/or animal away from getting it ● it might take longer
●the box gives the food something to be in instead of the ground
Option B: i think im going to stay with my original plan i can always make changes
__________________________________________________________
More advantages and disadvantges
Advantages: Disadvantages:
●reducing my carbon footprint by alot ● heat varies so the food my take really really long
●using no energy other than the sun
__________________________________________________________
Which of the three designs will you move forward with? Explain your reasons for selecting this design.
I will be moving forward with option A bc i personally can't think of another way or design and i think option A has more advantages than disadvantages
__________________________________________________________
Building the Prototype
What modifications, if any, did you make to the basic design during the construction process?
I used skewers to hold the flap up
__________________________________________________________
Predictions
Will your device warm the hot dog to a temperature of 165°F? How will your device do this?
Well i guess it depends n alot of things such as where i will place my solar cooker and the weather changes i will most likely put my solar cooker on the black paper because darker colors absorb more heat then lighter ones, then i will wait maybe 10 -20 minutes and check on my hotdog
__________________________________________________________
Will your device efficiently warm the hot dog in 20 to 25 minutes? How will your device do this? so my device will do this by attracting the suns rays and energy towards the box
__________________________________________________________
Will your device reach a temperature well above that of its surroundings? How will your device do this?
I think so especially if i put it in direct sunlight around a darker surface and of course the aluminium foil will help with this as well
__________________________________________________________
Observations
Record your observations and the results of the experimental tests of your device below. Temperature of the surroundings (in °F): ______68_______
Maximum temperature reached inside the solar cooker (in °F): _____59_____
__________________________________________________________
i added a picture but i will also put the numbers here althought keep in mind u might want to switch them up because its based off of my temperatures
Use this table to record the internal temperature of the hot dog every 2 minutes. Use a separate sheet of paper, if necessary.
time: Temperature (°F)
4:00 20
4:02 20
4:04 25
4:06 26
4:08 30
4:10 34
4:12 38
4:14 40
4:16 44
4:18 46
4:20 50
4:22 55
4:24 57
4:26 60
4:28 65
4:33 72
4:35 75
4:37 76
4:39 80
__________________________________________________________
Evaluating Your Prototype
What worked well?
i would say definitely the black paper and tin foil sin they attracted most of the suns energy
__________________________________________________________
Which features can be improved upon?
i think maybe if i did t on a different day it would have gotten hotter
__________________________________________________________
How could the overall design of this device be improved?
Position the flap more so that the hotdogs can get more sun
Doing it on a hotter day
Letting it cook longer
__________________________________________________________
Why would this change be an improvement? What concepts related to thermal energy transfer is this improvement based on?
this change would be an improvement by the hotdogs getting warmed to the right temperature this is related to thermal energy by the position of the flap i think if i angled it more in an abtuse angle the sun would have transferred to the foil to the bottom foil with the hotdogs
__________________________________________________________
Sketch of Your Final Design
Draw a well-labeled sketch of the final design.
i provided a sketch it should be the last picture
OKAY FINALLY PLZ DONT REORT THIS I WORKED SO HARD ON IT LAST TIME AND IT GOT DELETED IF U HAVE ANY QUESTIONS ABOUT THE PROJECT I WILL TRY TO HELP YOU IN THE COMMENTS THANK YOUUUU - ( if your wndering what grade i got on this got a 100 percent )
OH AND PEACE.
Answer:
I am simply adding another answer so the one above can get a brainliest
Explanation:
I do not care about the points that I will wind up getting for this and they are right here just answer with gibberish
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edit: in an attempt to return your points my question was taken down ill will return these
somehow
someway
sometime
the centre of mass of a metre rule is at the 50cm mark. state what is meant by Centre of mass
Answers
Answer:
Centre of mass of any body is a point where all mass of a body is supposed to be concentrated
it lies in geometrical centre....
what is refraction? How does it occur?
Answers
Answer:
Refraction is an effect that occurs when a light wave, incident at an angle away from the normal, passes a boundary from one medium into another in which there is a change in velocity of the light
Answer:
Refraction is an effect that occurs when a light wave, incident at an angle away from the normal, passes a boundary from one medium into another in which there is a change in velocity of the light. ... The wavelength decreases as the light enters the medium and the light wave changes direction.
What is the potential energy of a 2.85-kg object at the bottom of a well 12.7 m deep as measured from ground level? answer:___J
Answers
The potential energy U of an object with mass m located a distance h above the ground is given by the expression:
\(U=mgh\)Where g=9.81m/s^2 is the gravitational acceleration on the surface of Earth.
Since the 2.85kg object is located 12.7 meters below the ground, we can consider h to be negative. Replace m=2.85kg, g=9.81m/s^2 and h=-12.7m to find the potential energy of the object measured from the ground level:
\(U=mgh=(2.85kg)(9.81\frac{m}{s^2})(-12.7m)=-355.07...J\)Therefore, the potential energy of the object measured from the ground level is approximately 355J.
Q₁ -8 μC 5.3.1 44 mm 5.3.2 Q₂ +2μC Define Coulomb's Law in words. Calculate: 44 mm 5.2.1 The magnitude and direction of the force of Q₁ on Q₂ 5.2.2 The magnitude of the resultant Force of Q₁ and Q3 on Q₂. The direction of the resultant Force of Q₁ and Q3 on Q2. 5.2.3 Q2 is now replaced with a charge of -2 nC. Explain how this change influence... Q3 -8 μC the magnitude of the net Force on it. Only use INCREASE DECREASE or REMAIN THE SAME. the direction of the net Force on it.
Answers
Coulomb's Law states that the force between two charges is directly proportional to the product of their magnitudes and inversely proportional to the square of the distance between them.
Using Coulomb's Law, we can calculate:
5.2.1 The force of Q₁ on Q₂:
The magnitude of the force is given by:
F = k * |Q₁| * |Q₂| / r²
where k is Coulomb's constant, r is the distance between the charges, and |Q₁| and |Q₂| are the magnitudes of the charges.
Plugging in the values given:
F = 9 x 10^9 Nm²/C² * 8 x 10^-6 C * 2 x 10^-6 C / (0.044 m)²
F = 1.8 x 10^-2 N
How does this change influence... Q3 -8 μC the magnitude of the net Force on it?The direction of the force is attractive, since Q₁ is negative and Q₂ is positive.
5.2.2 The resultant force of Q₁ and Q₃ on Q₂:
The magnitude of the force is given by:
F = k * (|Q₁| * |Q₂| / r₁² + |Q₃| * |Q₂| / r₂²)
where r₁ and r₂ are the distances between Q₁ and Q₂ and Q₃ and Q₂, respectively.
Plugging in the values given:
F = 9 x 10^9 Nm²/C² * (8 x 10^-6 C * 2 x 10^-6 C / (0.044 m)² - 8 x 10^-6 C * 3 x 10^-6 C / (0.053 m)²)
F = -1.32 x 10^-2 N
The direction of the force is attractive, since the magnitude of the force due to Q₁ is greater than the magnitude of the force due to Q₃.
5.2.3 When Q₂ is replaced with a charge of -2 nC:
The magnitude of the net force on Q₂ will decrease, since the magnitude of the charge has decreased. However, the direction of the net force will remain attractive, since both Q₁ and Q₃ are negative charges.
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An electron is accelerated by a potential difference of 3000V and enters a region of a uniform magnetic field. As a result the electron bends along a path with a radius of curvature of 26.0 cm.Find the magnitude of the magnetic field in [µT]The speed is 32.5 Mm/s (from previous question answer)
Answers
Given:
The potential difference V=3000 V
The radius of curvature of the curved path of the electron, r=26.0 cm=0.26 m
The velocity of the electron, v=32.5 Mm/s=32.5×10⁶ m/s
To find:
The magnitude of the magnetic field.
Explanation:
The magnetic force acting on the electron provides it the neccessary centripetal force to trace a curved path.
Thus the centripetal force acting on the electron is equal to the magnetic force acting on it.
Therefore,
\(\frac{mv^2}{r}=\text{evB}\)Where m is the mass of the electron, e is the charge of the electron, and B is the magnitude of the magnetic field.
On rearranging the above equation,
\(B=\frac{mv}{er}\)On substituting the known values,
\(\begin{gathered} B=\frac{9.1\times10^{-31}\times32.5\times10^6}{1.6\times10^{-19}\times0.26} \\ =7.1\times10^{-4} \\ =710\text{ }\mu\text{T} \end{gathered}\)Final answer:
The magnitude of the magnetic field is 710 μT.
Demario's biology class has a quiz every other Friday. This is the third time Demario has been so worried about other personal matters that he hasn’t done quite as well on the quizzes as he might have otherwise. What has Demario upset is the fact that the professor leaves the room while the students take the quiz, and over half the class is taking the opportunity to cheat. Demario knows personally several of the other students in the class, and some of the ones Demario hangout with are among those who are cheating. Demario knows that a failure to speak to the professor about the cheating will result in his own grade being lower, since the school grades on the curve system. But if Demario does say something to the professor he will be doing his friends and the others a great harm, since cheating is taken very seriously at the school and can lead to expulsion. If Demario doesn’t “turn in” the classmates, the only other alternative is he will get a worse grade than he deserves. He will also be labled as a snitch among is peers and a cheater at the school, either of which Demario has never done. Further, if the professor somehow discovers that Demario is hiding the cheating of others, Demario will be considered an accessory to the cheating, and may be reprimanded for not turning others in, since the school operates on an honor system.
Critical thinking About Ethics Right vs Wrong
What should Demario do?
Should Demario cheat?
Should Demario turn in the cheating classmates?
Should Demario say nothing and not cheat himself?
Be specific in your answer about exactly what Demario should do. (Remember to use one of the three moral theories to solve this dilemma.)
Answers
1. It is unethical for Demario to cheat
2. Demario should not engage in cheating himself
3. Demario should not turn in cheating classmates without careful consideration
4. Reporting classmates may harm relationships, create animosity, and potentially lead to severe disciplinary actions.
What is ethics?A virtue ethics perspective may also be useful in this circumstance. Demario should make an effort to respect moral principles like honesty, fairness, and integrity while taking the potential repercussions into account and exhibiting empathy for his fellow students.
By employing this strategy, Demario behaves responsibly, deals with the problem subtly, encourages fairness in the educational setting, and upholds his or her own moral standards.
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Cindy gains utility from consumption C and leisure L. The most leisure she can consume in any given week is 110 hours. Her utility function is U(C, D) = Cx L. This functional form implies that Cindy's marginal rate of substitution is C/L. Cindy earns $10 per hour after taxes. She also receives $660 each week from her great-grandmother-regardless of how much Cindy works.
a) Write out Cindy's budget constraint?
b) Draw Cindy's budget constraint and mark all important points?
c) What is Cindy's reservation wage?
d) How many hours will Cindy devote to leisure and to work? What will be her level of consumption in $?
Answers
a. 10(W-L) + 660 = C, b A straight line with an intercept of 660 on the y-axis and a slope of -10 on the x-axis
a) Write out Cindy's budget constraint?a) Cindy's budget constraint is expressed as follows: 10(W-L) + 660 = C
Where W is the maximum number of hours Cindy can work in a week, L is her leisure time, and C is her total consumption.
b) Draw Cindy's budget constraint and mark all important points?b) A straight line with an intercept of 660 on the y-axis and a slope of -10 on the x-axis can be used to represent the budget constraint (since the price of leisure is the wage she could earn, which is 10 dollars per hour). Cindy's maximum leisure time is 110 hours, so the budget constraint intersects the leisure axis at (0, 660) and the work axis at (W, 0), where W is the maximum number of hours.
c) What is Cindy's reservation wage?c) Cindy's reservation wage is the wage at which she is unconcerned about working or not working. In this case, her reservation wage is zero because she receives $660 per week from her great-grandmother irrespective of how much she works.
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The sun appears to move across the sky each day. What time of day will the shadow be shortest?
A. Sunrise
B. Noon
C. Sunset
D. Midnight
Answers
hope this helps a lottt
A car travels from point A to B in 3 hours and returns back to point A in 5 hours. Points A and B are 150 miles apart along a straight highway. Calculate: a) Total distance and total displacement (in mile and meter) b) Average speed and Average velocity (in mile/hr and m/s
Answers
The total distance covered by the car is 300 miles.
The total displacement covered by the car is zero.
The average speed of the car is 17.88 m/s.
The average velocity of the car is also zero.
Distance between the points A and B, d = 150 miles
Time taken by the car to travel from A to B, t₁ = 3 hours
Time taken by the car to travel from B to A, t₂ = 5 hours
a) Given that the car travelled from A to B and then back to A.
Therefore, the total distance covered by the car is,
Distance = 2 x d
Distance = 2 x 150
Distance = 300 miles
Since the car is travelling from A to B and then returning back to the initial point A, the total displacement covered by the car is zero.
b) The speed with which the car travelled from A to B is,
v₁ = d/t₁
v₁ = 150/3
v₁ = 50 miles/hr
v₁ = 22.35 m/s
The speed with which the car travelled from B to A is,
v₂ = d/t₂
v₂ = 150/5
v₂ = 30 miles/hr
v₂ = 13.41 m/s
Therefore, the average speed of the car is,
v = (v₁ + v₂)/2
v = (22.35 + 13.41)/2
v = 17.88 m/s
As, the total displacement of the car is zero, the average velocity of the car is also zero.
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In an experiment a block of copper metal with a mass of 1.3 kg is heated
from 25 °C to 45 °C. The specific heat capacity of copper is 380 J/kg °C.
Calculate the energy needed to heat the copper to 45 °C.
Answers
The energy needed to heat the copper from 25 °C to 45 °C if the specific heat capacity of copper is 380 J/kg °C is 9880 J
ΔT = T - To
ΔT = Change in temperature
T = Final temperature
To = Initial temperature
T = 45 °C
To = 25 °C
ΔT = 45 - 25
ΔT = 20 °C
q = m C ΔT
q = Heat Energy
m = Mass
C = Specific heat capacity
m = 1.3 kg
C = 380 J / kg °C
q = 1.3 - 380 * 20
q = 9880 J
Therefore, the energy needed to heat the copper to 45 °C is 9880 J
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An 8.20 kg object is pulled along a horizontal surface by a force of 22.0 N. If its acceleration is 1.1 m/s2, what is the coefficient of friction between the two surfaces?
Answers
Answer:
0.5
Explanation:
In this picture,
A cylindrical water tank open to the atmosphere, 10 m tall and 6 m in diameter, is mounted with its base 25 m above ground level, and filled with water. Calculate a) the water pressure and force at the base of the tank?
Answers
The water pressure at the base is 98,000 Pa, and the force exerted at the base of the tank is 2,768,460 N.
To find the water pressure at the base of the tank, take the formula:
Pressure = density × gravity × height
In which
Density = density of water (1000 kg/m³)
Gravity = acceleration due to gravity (9.8 m/s²)
Height = height of the column
According to question:
Height of the water column = 10 m
Take the formula:
P = 1000 kg/m³ × 9.8 m/s² × 10 m
= 98,000 Pa
To find the force at the base of the tank, take the formula:
Force = Pressure × Area
In which
Pressure = pressure at the base of the tank
Area = base area of the tank
The base area of a cylindrical tank can be found by the formula:
Area = π × r²
In which:
Diameter of the tank = 6 m
To find the radius, divide the diameter by 2:
Radius = 6 m ÷ 2
= 3 m
Put the values into the formula:
Area = π × (3 m)²
= 28.27 m²
Now, find the force:
Force = 98,000 Pa × 28.27 m²
= 2,768,460 N
Thus, the water pressure at the base is 98,000 Pa, and the force exerted at the base of the tank is 2,768,460 N.
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A race car makes one lap around a track of radius 50 m in 9.0 s. What was the car's centripetal acceleration?
Answers
The velocity of the car is 5.5 m/s. Then the centripetal acceleration of the car will be 0.6 m/s².
What is centripetal acceleration?Acceleration is a physical quantity measuring the rate of change in velocity. It has both magnitude and direction.
Centripetal acceleration is the acceleration of an object moving through a circular path. Thus its measures the rate of change in velocity of the body moving in the curvature path.
The centripetal acceleration = V²/R.
Where R is the radius of the curvature path.
The car moves 50 m in 9 seconds. Its velocity is 50/9 = 5.5 m/s.
Thus, centripetal acceleration = (5.5 × 5.5) m/s/ 50 m = 0.6 m/s².
Therefore, the centripetal acceleration of the car moving at a speed of 9 m/s through curvature path is 0.6 m/s².
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What will be the purple spring's change in length if a 311 g mass is hung from the bottom?
Answers
The change in length of the purple spring be 6.77 cm.
What is spring constant?The spring stiffness is how we define the term "spring constant." In other words, we can define the spring constant as the force that was used to cause the spring's displacement to be one unit. It follows that a spring's spring constant would increase as it becomes more rigid.
Given parameters:
Spring constant: k = 45 N/m.
Mass of the load: m = 311 g = 0.311 kg.
So, weight of the load: w = mg = 0.311 × 9.8 N = 3.0478 N.
Hence, the purple spring's change in length be = w/k = 3.03478/45 m = 0.0677 m = 6.77 cm.
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Using a simple model of an electromagnet, describe the factors that increase the magnetic field strength of an electromagnet.(2 points)
Answers
Answer:
Factors Affecting the Strength of the Magnetic Field of an Electromagnet: Factors that affect the strength of electromagnets are the nature of the core material, strength of the current passing through the core, the number of turns of wire on the core and the shape and size of the core
Explanation:
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The following factors affect the strength of an electromagnet; number of turns, wire size, current and the presence of iron core.
What is electromagnet?This is a type of magnet in which the magnetic field is produced by an electric current.
Factor affecting electromagnetThe following factors affect the strength of an electromagnet;
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Mr. Bateman creates a standing wave in the front of the classroom with the spring. S nodes form. The distance from Mr. Bateman to the cabinet is 6m. If a student times the spring moving back and forth and gets 0.2s for one cycle of the spring, how fast are the
waves moving?
Answers
Answer:
The speed of a wave is equal to the wavelength divided by the period. The wavelength is the distance between two consecutive nodes, and the period is the time it takes for one complete cycle of the wave.
In this case, the wavelength is 6 m and the period is 0.2 s. Therefore, the speed of the wave is 30 m/s.
The answer is 30 m/s.
Explanation:
How wide is the central diffraction peak on a screen 2.30 m behind a 0.0368-mm-wide slit illuminated by 558-nm light
Answers
Answer:
The value \(y = 0.0349 \ m\)
Explanation:
From the question we are told that
The distance of the screen is \(D = 2.30 \ m\)
The width of the slit is \(d = 0.0368 \ nm = 0.0368 *10^{-3} \ m\)
The wavelength is \(\lambda = 558 \ nm = 558 *10^{-9} \ m\)
The width of the central diffraction peak is mathematically represented as
\(k = 2 * y\)
Where y is the distance from the center to the high peak which is mathematically represented as
\(y = \frac{\lambda * D }{d }\)
substituting values
\(y = \frac{ 558 *10^{-8} * 2.30 }{0.0368 *10^{-3} }\)
\(y = 0.0349 \ m\)
A bus with a maximum speed of 20m/s takes 21sec to travel 270m from stop to stop. Its acceleration is twice as great as its deceleration.
Find
1. The acceleration
2. The distance travelled at maximum speed
Answers
The acceleration can be calculated using the formula:
Acceleration = (Final velocity - Initial velocity) / Time taken
Given that the bus starts from rest, the initial velocity is 0 m/s.
Acceleration = (20 m/s - 0 m/s) / 21 sec = 20/21 m/s².
The distance travelled at maximum speed can be calculated by subtracting the distances covered during acceleration and deceleration from the total distance.
Distance during acceleration = (1/2) * acceleration * time² = (1/2) * (20/21 m/s²) * (21 sec)² = 210 m.
Distance during deceleration is the same as distance during acceleration.
Distance travelled at maximum speed = Total distance - 2 * distance during acceleration = 270 m - 2 * 210 m = -150 m.
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Net force causes motion.
Answers
Answer: If you want me to write them for you here they are
Explanation:
Net force causes change in motion because a net external force causes a change in motion; thus, we see that a net external force causes acceleration.
Not more likely to be Net force motion because if it doesnt say change then its gonna stay the same so Net force does cause change in a motion because take for example if you are going to bounce a basketball its gonna change its position from one place to another thats how Net force causes Change in motion.
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1. A box contains 10 blue chips. 5 red chips, and 15 yellow chips. Find the odds of choosing the
following:
blue chip
b. yellow chip
c. yellow chip
Answers
Answer:
Explanation:
Blue: 10/30
Red: 5/30
Yellow: 15/30
The probability of finding the blue red and yellow chips is 1/3, 1/6 and 1/2
What is the probability?
The extent to which an event is likely to occur, measured by the ratio of the favorable cases to the whole number of cases possible.
Given that
Blue chips =10
Red chips = 5
Yellow chips = 15
Number of the total samples =10+15+5=30
Probability of choosing Blue chips = \(\dfrac{10}{30}= \dfrac{1}{3}\)
Probability of Red chips =\(\dfrac{5}{30}=\dfrac{1}{6}\)
Probability of Yellow chips =\(\dfrac{15}{30}=\dfrac{1}{2}\)
Thus the probability of finding the blue red and yellow chips is 1/3, 1/6 and 1/2
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A person has a mass of 1000 g and an acceleration of 20 M/S/S what is the force on the person
Answers
Answer:
The answer is 20 NExplanation:
The force acting on an object can be found by using the formula
force = mass × accelerationFrom the question
mass = 1000 g = 1 kg
acceleration = 20 m/s²
We have
force = 20 × 1
We have the final answer as
20 NHope this helps you
A small bag of sand is released from an ascending hot‑air balloon whose constant, upward velocity is 0=2.95 m/s. Knowing that at the time of the release the balloon was 37.8 m above the ground, determine the time it takes for the bag to reach the ground from the moment of its release. Use =9.81 m/s2.
Answers
The time taken is approximately 2.08 seconds for the bag of sand to reach the ground from the moment of its release.
To determine the time it takes for the bag of sand to reach the ground, we can use the kinematic equation for vertical motion. The equation is given as:
h = ut + (1/2)gt^2
Where:
h = height (37.8 m)
u = initial velocity (0 m/s)
g = acceleration due to gravity (-9.81 m/s^2, considering downward motion)
t = time
Since the balloon is ascending with a constant upward velocity of 2.95 m/s, the initial velocity of the bag is also 2.95 m/s in the upward direction. Therefore, we need to consider the initial velocity as negative.
Substituting the known values into the equation, we have:
37.8 = (-2.95)t + (1/2)(-9.81)t^2
Simplifying the equation further, we get:
-4.905t^2 - 2.95t + 37.8 = 0
Solving this quadratic equation for time, we find two solutions: t = 2.08 s and t = -3.61 s. Since time cannot be negative, we discard the negative value.
Therefore, it takes approximately 2.08 seconds for the bag of sand to reach the ground from the moment of its release.
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PLEASE HELP SOON! For the circuit below , the battery has 4.2V calculate power giving and power receiving
Answers
For this circuit, the voltage is 4.2 V. then power given is 0.9 W and receiving across 55Ω resistance is 0.07 W and that of 30Ω resistance is 0.14 W. Resistor are connected in parallel, its equvalent resistance is R₁R₂/R₁+R₂.
Both resistor are connected in parallel hence their equivalent resistance in parallel combination is given as,
R = 55*30/(55+30)
R = 19.4 Ω
Power given to the circuit is,
P = V²/R = 4.2/19.4 = 0.9 W
Receiving power taken from 55Ω resistor
P = V²/R = 4.2/55 = 0.07 W
Receiving power taken from 30Ω resistor
P = V²/R = 4.2/30 = 0.14 W
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In the context of energy transfers with hot and cold reservoirs, the sign convention is that _______________.
Answers
Answer:
Qc>0; Qh>0
Explanation:
In the context of energy transfers with hot and cold reservoirs, the sign convention is QC > 0; QH < 0.
What is energy transfer?The conversion of one form of energy into another, or the movement of energy from one place to another is known as energy transfer.
Given that there are two energy reservoirs. Heat and work sign convention is:
If the heat is adding to the system then it is considered positive and if heat is going out from the system then it is considered negative. If the work is done on the system then it is taken as negative and if the work is done by the system then it is taken as positive.As, heat is going out that from the hot reservoir ,it is taken as negative- QH < 0.
As heat is coming inside the cold reservoir that is why it is taken as positive - QC > 0.
Therefore, QC > 0 and QH < 0 is the correct answer.
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A bug crawls 3.0 mm east, 4.0mm north, and then 5.0 mm at 45 north of east. Draw a diagram showing its displacements and determine its resultant displacement vector by use of the diagram.
Answers
Answer:
Explanation is given
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For your senior project, you would like to build a cyclotron that will accelerate protons to 10% of the speed of light. The largest vacuum chamber you can find is 54 cm in diameter. What magnetic field strength will you need?
Answers
Answer:
The magnetic field is 1.16 T.
Explanation:
speed, v = 10% of speed of light = 3 x 10^7 m/s
diameter, d = 54 cm
radius, r = 0.27 m
charge, q = 1.6 x 10^-19 C
mass, m = 1.67 x 10^-27 kg
Let the magnetic field is B.
The centripetal force is balanced by the magnetic force.
\(qvB=\frac{mv^2}{r}\\\\B =\frac{mv}{qr}\\\\B =\frac{1.67\times 10^{-27}\times 3\times 10^{7}}{1.6\times 10^{-19}\times 0.27}\\\\B =1.16 T\)