g A small car travels up the hill with a speed of v = 0.2 s (m/s) where s is the distance measured from point A in meters. Determine the magnitude of the car’s acceleration when it reaches s = 50 (m) where the road’s radius of curvature is r

Answer: Air resistance

Explanation: If you subtract the net force from the weight of a falling object, you would be solving for a force that is not being balanced from the other forces.

The net force (with no external forces) on the falling object would just be the force of gravity. So, any force that unbalances the force of gravity would be what you are solving for. This can be air resistance, friction (if the object is sliding against a wall), or applied forces (pushing the object while it falls).

The nature of the image formed by the convex lens is virtual, the position of the image is 30 cm away from the lens on the same side as the object, and the size of the image is twice the size of the object. The magnification is 2, meaning the image is magnified.

Given:

Object height (h) = 5 cm

Focal length of the convex lens (f) = 10 cm

Object distance (u) = 15 cm (positive since it's on the same side as the incident light)

To determine the nature, position, and size of the image, we can use the lens formula:

1/f = 1/v - 1/u

Substituting the given values:

1/10 = 1/v - 1/15

To simplify the equation, we find the common denominator:

3v - 2v = 2v/3

Simplifying further:

v = 30 cm

The image distance (v) is 30 cm. Since the image distance is positive, the image is formed on the opposite side of the lens from the object.

To find the magnification (M), we use the formula:

M = -v/u

Substituting the values:

M = -30 / 15 = -2

The magnification is -2, indicating that the image is inverted and twice the size of the object.

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Ohm's law :

V = I x R

V= voltage = 134 V

R = resistance = 8 Ω

I = current

I = V / R

Replacing:

I = 134/8 = 16.75

Current = 16.75 Ampere [A]

The Big Bang theory is the most widely accepted explanation for the origins of the universe, but it does not necessarily imply that the universe emerged from nothing.

It is possible that new discoveries or insights may shed light on this fundamental question in the future. The universe may have arisen from a pre-existing state or through some other natural process that we do not yet understand.

Instead, the theory describes how the universe underwent a rapid expansion from a very dense and hot state. The conditions and laws of physics that applied during the earliest moments of the universe may not necessarily be the same as those we observe today, and there are many unknowns and uncertainties in our understanding of these early stages.

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This question involves the concepts of the thin lens formula, focal length, and image distance.

The image of the house is "16 ft" away from the lens.

According to the thin lens formula:

\(\frac{1}{f}=\frac{1}{p}+\frac{1}{q}\)

where,

f = focal length = 8 ft

p = object distance = 16 ft

q = image distance = ?

Therefore,

\(\frac{1}{8\ ft}=\frac{1}{16\ ft}+\frac{1}{q}\\\\\frac{1}{q}=\frac{1}{8\ ft}-\frac{1}{16\ ft}\\\\\frac{1}{q}=0.125\ ft^{-1}-0.0625\ ft^{-1}\\\\q=\frac{1}{0.0625\ ft^{-1}}\\\\\)

q = 16 ft

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Answer: Environmental factors are the abiotic factors that interact with and influence the biotic factors. The amount of carbon dioxide, and water clarity affects the sunlight reaching the aquatic organisms.

Answer: the answer is d

Explanation:

The earthquake would occur 13 minutes before 10:05 a.m. which will be at 9.52 am.

The p-waves travel with a constant velocity of 7 km/s

The time can be calculated by using the formula

t = d / v

where

T1 =  10:05 a.m

d is the distance they take to travel from the epicenter

v is the speed of the p-waves

On average, the speed of p-waves is

v = 7 km/s

d = 5600 km (given)

Substituting the values in the formula;

t = d / v

t = 5600 ÷ 7

t = 800 seconds

Converting into minutes,

t = 800 ÷ 60

t = 13.3

≈ 13 mins

T1 -  13 mins = T2

10:05 - 13 mins = 9.52 am

It means the earthquake occurred prior 13 minutes, that is at 9.52 am.

Therefore, the earthquake occurred at 9.52 am.

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Because of friction and air resistance, every moving object will eventually come to rest unless a continuous net force is applied to it.

Friction is the opposition offered to motion of a body over another body.

Friction can either be:

The law of inertia states that an object will remain in its state of rest or state of motion in a straight line unless acted upon by an external force.

However, due to friction and air resistance, every moving object will eventually come to rest unless a continuous net force is applied to it.

In conclusion, moving objects come to rest because of friction and air resistance.

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Answer:

Below

Explanation:

You can use this formula to find the velocity of an object

     velocity = displacement / change in time

For this problem, we need to find displacement first

To find displacement all you need to do is find the difference between the two distances!

So our displacement here would be

     73 - 62 = 11 m

Now that we have displacement we can find velocity

      velocity = 11 / 15

                    = 0.733333....

                    = 0.73 m/s

Hope this helps! Best of luck <3

The velocity of an object that moves from 73 m to 62 m in 15 s is 0.73 m / s.

When an item is moving, its velocity indicates how quickly its location is changing as seen from a specific point of view and as measured by a specific unit of time.

If a point travels a specific distance along its path in a predetermined amount of time, its average speed throughout that time is equal to the traveled distance divided by the travel time. For instance, a train traveling 100 km in two hours is moving at an average speed of 50 km/h.

Given:

The distance of the object = 73 m to 62 m,

The time taken by the object, t = 15 s,

Calculate the displacement of the object = 73 - 62 = 11 m

Calculate the velocity by the formula given below,

\(v = d /t\)

v = 11 / 15

v = 0.73 m / s

Therefore, the velocity of an object that moves from 73 m to 62 m in 15 s is 0.73 m / s.

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Answer:

0.05cos10t

Explanation:

X(t) = Acos(wt+φ)

The oscillation angular frequency can be calculated using below formula

w = √(k/M)

Where K is the spring constant

But we were given body mass of 5.0 kg

We know acceleration due to gravity as 9.8m)s^2

The lenghth of spring which stretches =10 cm

Then we can calculate the value of K

k = (5.0kg*9.8 m/s^2)/0.10 m

K= 490 N/m

Then if we substitute these values into the formula above we have

w = √(k/M)

w = √(490/5)

= 9.90 rad/s=10rads/s(approximately)

Its position as a function of time can be calculated using the below expresion

X(t) = Acos(wt+φ)

We were given amplitude of 5 cm , if we convert to metre = 0.05m

w=10rads/s

Then if we substitute we have

X(t)=0.05cos(10×t)

X(t)= 0.05cos10t

Therefore,Its position as a function of time=

X(t)= 0.05cos10t

Answer:

Explanation:

We can use the kinematic equation v^2 = u^2 + 2as to solve for the length of the driveway. Here, u = 0 (since the car starts from rest), v = 3.8 m/s, a = F/m = 4.0 x 10^3 N / 2.1 x 10^3 kg = 1.9 m/s^2. Solving for s, we get:

s = (v^2 - u^2) / 2a = (3.8^2) / (2 x 1.9) = 3.8 m

So the length of the driveway is 3.8 meters.

Answer:

Explanation:

Given

Horizontal velocity = 9.00m/s

time taken = 0.550 s

Required

How far does the projectile fall in the vertical direction

Using the formula for finding the maximum height of the projectile

H = U²sin²θ/2g where;

U = 9.00m/s

θ = 90° (object launched in the vertical direction)

g = 9.81m/s²

Substituting the given parameters into the formula;

H = 9²sin²90/2(9.81)

H = 81(1)/19.62

H = 81/19.62

H = 4.128 m

H ≈ 4.13m

Hence the distance that the projectile fall in the vertical direction is 4.13m

5 second is the time it takes for Theodore to splash down running at 2m/s  velocity as he runs off a bluff and drops 10 meters into a water filled rock

quarry.

velocity= 2m/s

distance=10 meters

velocity=distance/time

time=distance/velocity

time=10 meters/2m/s

time=5 second

A vector number known as velocity describes "the pace at which an item changes its location." Imagine a person moving quickly, taking one stride ahead, one step back, and then beginning from the same place each time. A vector quantity is velocity. As a result, velocity is aware of direction. One must consider direction while calculating an object's velocity. Saying that an item has a velocity of 55 miles per hour is insufficient. The direction must be included in order to adequately characterize the object's velocity. Simply said, the velocity vector's direction corresponds to the motion of an item

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A. When an object's acceleration vector points in the same direction as its velocity, the object speeds up without turning.

The average acceleration vector is defined as the rate at which the velocity changes with time.

When an object is slowing down, the acceleration of the object is in the opposite direction as the velocity.

Also, when an object is speeding up, the acceleration of the object is in the same direction as the velocity.

Thus, when an object's acceleration vector points in the same direction as its velocity, the object speeds up without turning.

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Answer:

2.94 s

Explanation:

v = u + at

where:

v = final velocity = 9 m/s

u = initial velocity = 0 m/s (rest)

a = acceleration

t = time taken to reach final velocity

We can rearrange the equation to solve for time:

t = (v - u) / a

Substituting the given values, we get:

t = (9 m/s - 0 m/s) / a

Now, we need to find the acceleration. We can use another kinematic equation:

s = ut + (1/2)at^2

where:

s = displacement = 1500 m

u = initial velocity = 0 m/s

a = acceleration

t = time taken to cover the displacement

We can rearrange the equation to solve for acceleration:

a = 2(s - ut) / t^2

Substituting the given values, we get:

a = 2(1500 m - 0 m) / (1500 m / 9 m/s)^2

Simplifying, we get:

a = 3.06 m/s^2

Now, we can substitute this value of acceleration in the earlier equation to find the time taken:

t = (9 m/s - 0 m/s) / 3.06 m/s^2

Simplifying, we get:

t = 2.94 s

Answer:

c

Explanation:

energy isn't stored and it doesn't change to mass

The ball has some kinetic energy when it hits the floor, but some of it is changed, so it loses some of it each time it bounces. After a few bounces, the ball has so little kinetic energy remaining that it stops bouncing. Thus, option C is correct.

Since the gravitational potential energy, which can be transformed back into kinetic energy on the rebound, increases with the drop height, the consequent bounce height will likewise rise.

Because it has the most elasticity, the rubber ball will rebound the highest when all three balls are dropped from the same height. Because rubber is incredibly elastic, it squishes or compresses as it touches the ground but immediately snaps back to its original shape.

Therefore, Additionally, some energy is changed into other forms like heat and sound. The majority of these additional energy sources are lost and not recovered, causing the ball to bounce back to a lesser height.

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Given data:

* The mass of the child is 40kg.

* The reading of the scale is 30 N.

Solution:

(a). The free body diagram of the given system is,

(b). The weight of the child is,

The Scale reading is,

The net force acting on the box in terms of the weight of the box is,

According to the Newton's second law,

Answer:

The time required is t = 9.39 [s]

Explanation:

To solve this problem we must use the following equation of kinematics.

\(v_{f}=v_{o} +(a*t)\)

where:

Vf = final velocity = 77 [m/s]

Vo = initial velocity = 0

a = acceleration = 8.2 [m/s²]

t = time [s]

The initial speed is zero, since the airplane begins its movement from rest. The initial speed is zero, since the aircraft begins its movement from rest. Another important fact is that the sign of acceleration is positive since the plane is accelerating, that is, its speed is increasing.

Now replacing:

77 = 0 + (8.2*t)

t = 9.39 [s]

Answer:

300

Explanation Hope I'm not wrong.

Distance= Time×Speed

= 1800×1.5

= 2700 m

I am not sure it's right. the question itself is confusing.

Answer: D. movement of material along a coast by waves that approach at an angle to the shore.​

Explanation:

Longshore drift is also referred to as the littoral druft and it means the sediment that is moved by the longshore current.

Longshore drift is the movement of material along a coast by waves which approach at an angle to the shore but then recede down the beach.

Therefore, the correct option is D.

Answer:

औडंठः की दुनिया कार्टून दर्शन होली है और यह बियर का अच्छा विकल्प है। विकल्प है। यो कुरा मेरो आफ्ना लागि विचार र त्यहाँको बडेमाको बिल्डिङ भित्र म जिन्दगी एक यात्रा हो कहाँबाट शुरु भइ कहाँ पुगेर अन्त हुन्छ

Here ya go-!

Mass is both a property of a physical body and a measure of its resistance to acceleration (a change in its state of motion) when a net force is applied. An object's mass also determines the strength of its gravitational attraction to other bodies. The basic SI unit of mass is the kilogram (kg).

(um im sorry if its wrong-)

The electron number cannot be used instead because electrons can be removed from or added to an atom (option C)

The element of an atom is determined by its proton count, while the electron count can exhibit variability. Take, for instance, a sodium atom, which encompasses 11 protons and 11 electrons. However, it has the capacity to relinquish one electron, transforming into a sodium ion housing only 10 electrons.

This occurs due to the relatively loose binding of electrons to the nucleus, enabling their removal through the influence of an electric field or alternative mechanisms.

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A VfL (Vertical Field LED) backlighting system is commonly used in LCD (Liquid Crystal Display) televisions.

LCD TVs rely on a backlight to illuminate the liquid crystal layer, which controls the passage of light to create the visual image. The VfL technology is a specific type of LED backlighting arrangement used in certain LCD TV models. In a VfL backlighting system, the LEDs (Light-Emitting Diodes) are positioned vertically along the edges of the LCD panel.

The light emitted by these LEDs is directed across the panel using light guides or optical films, illuminating the liquid crystal layer uniformly. One advantage of VfL backlighting is its ability to provide consistent illumination across the LCD panel, reducing any potential inconsistencies in brightness or color uniformity. The vertical orientation of the LEDs allows for more precise control over light distribution, improving overall image quality.

Additionally, VfL backlighting offers potential advantages in terms of power efficiency. By selectively dimming or turning off specific zones of LEDs, local dimming techniques can be employed to enhance contrast and black levels, resulting in improved picture quality while conserving energy. It's important to note that VfL backlighting is just one of several backlighting technologies available for LCD TVs.

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