g You have a suction cup that creates a circular region of low pressure with a 30 mm diameter. It holds the pressure to 78 % of atmospheric pressure. What "holding force" does the suction cup generate in N

The moment of inertia is 0.00625 kg·m^2 for both the initial and final speeds

To calculate the moment of inertia when the speed of the wheel increases, we need to know the distribution of mass in the body. Assuming the body is a thin ring with the mass concentrated on the rim, we can use the formula for the moment of inertia of a thin ring:

I = m * \(r^2\)

where I is the moment of inertia, m is the mass, and r is the radius.

Given:

Mass of the body (m) = 100 g = 0.1 kg

Diameter of the circular path = 500 mm

Radius (r) = Diameter / 2 = 500 mm / 2 = 250 mm = 0.25 m

Calculate the initial moment of inertia:

Initial speed = 450 rpm

Initial angular velocity (ω1) = 450 rpm * 2π / 60 = 47.12 rad/s

Using the formula for moment of inertia:

I1 = m * r^2

I1 = 0.1 kg * (0.25 m)^2

I1 = 0.00625 kg·m^2

Calculate the final moment of inertia:

Final speed = 750 rpm

Final angular velocity (ω2) = 750 rpm * 2π / 60 = 78.54 rad/s

Using the formula for moment of inertia:

I2 = \(m * r^2\)

I2 = \(0.1 kg * (0.25 m)^2\)

I2 = \(0.00625 kgm^2\)

Therefore, the moment of inertia remains the same as the mass and radius do not change. The moment of inertia is 0.00625 kg·m^2 for both the initial and final speeds.

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Answer:

Sample Response: If the speed of an object increases, then its kinetic energy will increase proportionally because speed and kinetic energy have a linear relationship when graphed.

Explanation:

edge

Answer:

plz write your questions in English

In social psychology, a stereotype is a generalized belief about a particular category of people.

A stereotype can be described as the accepted, condensed, and essentialist opinion  with regards to certain population.

I should be nted hat his can be related to  gender identity, race  as well as ethnicity, country,  however there are other things that an be used frequently used to stereotype groups. Stereotypes are pervasively present in both the larger social structure and culture.

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The magnitude of the electric flux through the sheet is 4.05 N m² C⁻¹ (Option E).

The electric flux through a surface is given by the product of the electric field strength and the area of the surface projected perpendicular to the electric field.

In this case, the electric field strength is 18 N C⁻¹, and the area of the sheet projected perpendicular to the electric field is 0.450 m²

(since the normal to the sheet makes an angle of 60° with the electric field). Multiplying these values gives the electric flux:

Electric flux = Electric field strength × Area

Electric flux = 18 N C⁻¹ × 0.450 m²

Electric flux = 8.1 N m² C⁻¹

In summary, the magnitude of the electric flux through the sheet is 4.05 N m² C⁻¹. This value is obtained by multiplying the given electric field strength by the projected area of the sheet perpendicular to the electric field.

The angle of 60° is taken into account to determine the effective area for calculating the flux.(Option E).

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Answer:

From Earth, the Sun looks like it moves across the sky in the daytime and appears to disappear at night. This is because the Earth is spinning towards the east. The Earth spins about its axis, an imaginary line that runs through the middle of the Earth between the North and South poles.

Answer:

Explanation:

2) Draw a horizontal line below the squiggle and call it your reference origin.

Highest potential energy is farthest above the origin.

I would suggest for highest to lowest

GACE(D = F)B

3) I have no way of knowing how to compare kinetic and potential energies because we are given no reference levels for either.

IF we ASSUME it is a typo and they want highest to lowest KINETIC energies, then the values will be the reverse of #2 because, in the lack of friction, Kinetic and Potential energies will always be swapping keeping the total mechanical energy constant.

B(D = F)ECAG

Answer:

-259322.03N

Explanation:

\(F=m*(\frac{v}{t})\\ F=4500kg*(\frac{0-102m/s}{1.77s} )\\F=-259322.033898\\\\\)

The seasons in the Northern Hemisphere are the opposite of those in the Southern Hemisphere. Seasons occur because Earth is tilted on its axis relative to the orbital plane, the invisible, flat disc where most objects in the solar system orbit the sun.

Answer:

Explanation:

20

The formula for potential difference (also known as voltage) is, V = ΔE/q, where V is the potential difference in volts (V), ΔE is the change in electric potential energy in joules (J), and q is the charge in coulombs (C).

Electric potential difference, also known as voltage, is a measure of the electric potential energy per unit of charge required to move a charge from one point to another in an electric circuit. It is the difference in electric potential between two points in an electric circuit.

The formula for potential difference, V = ΔE/q, reflects this relationship. The numerator, ΔE, represents the change in electric potential energy between the two points, while the denominator, q, represents the charge that moves between the two points.

For example, if a charge of +1 C moves from a point A to a point B in an electric circuit, and the electric potential energy at point B is greater than at point A by 1 J, then the potential difference between points A and B is 1 V. This means that it takes 1 J of energy to move a unit of charge from point A to point B in the circuit.

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The exploded star is called a black hole.

The time horizon of the black hole is an area of spacetime where gravitational pull is so intense that nothing, not even light or other electromagnetic waves, have the energy to pass through it.

It is believed that the first black holes appeared shortly after the big bang, in the beginning of the cosmos. When the core of an extremely massive star is collapsed on itself, stellar black holes are created.

A supernova, also known as an exploding star, is also brought on by this collapse and sends a portion of the star into space.

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Answer:

2.74 × 10^33 J

Explanation:

the formula to calculate kinetic energy is:

1/2mv²

m= mass (kg)

v= velocity (m/s)

given that,

m = 5.97 × 10^24

v = 30.29 km s-1

  = 30290 m s-1

1/2× 5.97 × 10^24 × 30290²

=2.74 × 10^33 J

Answer:

    wo = 18.75 rev / s

Explanation:

This is an exercise in endowment kinematics, it indicates that the final angular velocity is w_f = 109 rad / s, the time to reach this velocity is t = 1.87 s and the deceleration a = 4.7 rad / s²

         w_f = w₀ - a t

         w₀ = w_f + a t

         w₀ = 109 + 4.7 1.87

         w₀ = 117.8 rad / s

let's reduce to revolutions / s

         w₀ = 117.8 rad / s (1 rev / 2pi rad)

         w₀ = 18.75 rev / s

Kepler's second law states that the radius vector drawn from the sun to the planet seeps out equal areas in equal intervals of time. The second law is referred to as the law of equal areas. Thus, the correct option is A

Answer:

No i cannot

Explanation:

because i haven't learnt it yet

I am so sorry

On average, the individuals who received the incentive took 3.5 extra minutes to answer the subjects who did not. Financial incentive had a kind of mental block effect that made it more difficult to think.

Dollars, hugs, stamps, family outings, and placards are examples of constructive rewards. "Consequences," which are unfavorable incentives, make people's lives worse. Negative motivations include missing out on TV time, bathing, physical education class, and moment out. Users are against all of these events happening.

Incentives and benefits are employed as incentives to promote advantageous work practices. These come in a variety of forms, such as paying for college, providing more vacation time for employees, and granting companies more flexibility.

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Answer:

Refer to the step-by-step Explanation.

Step-by-step Explanation:

Simplify the equation with given substitutions,

Given Equation:

\(mgh+(1/2)mv^2+(1/2)I \omega^2=(1/2)mv_{_{0}}^2+(1/2)I \omega_{_{0}}^2\)

Given Substitutions:

\(\omega=v/R\\\\ \omega_{_{0}}=v_{_{0}}/R\\\\\ I=(2/5)mR^2\)\(\hrulefill\)

Start by substituting in the appropriate values: \(mgh+(1/2)mv^2+(1/2)I \omega^2=(1/2)mv_{_{0}}^2+(1/2)I \omega_{_{0}}^2 \\\\\\\\\Longrightarrow mgh+(1/2)mv^2+(1/2)\bold{[(2/5)mR^2]} \bold{[v/R]}^2=(1/2)mv_{_{0}}^2+(1/2)\bold{[(2/5)mR^2]}\bold{[v_{_{0}}/R]}^2\)

Adjusting the equation so it easier to work with.\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{2} \Big[\dfrac{2}{5} mR^2\Big]\Big[\dfrac{v}{R} \Big]^2=\dfrac12mv_{_{0}}^2+\dfrac12\Big[\dfrac25mR^2\Big]\Big[\dfrac{v_{_{0}}}{R}\Big]^2\)

\(\hrulefill\)

Simplifying the left-hand side of the equation:

\(mgh+\dfrac{1}{2} mv^2+\dfrac{1}{2} \Big[\dfrac{2}{5} mR^2\Big]\Big[\dfrac{v}{R} \Big]^2\)

Simplifying the third term.

\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{2} \Big[\dfrac{2}{5} mR^2\Big]\Big[\dfrac{v}{R} \Big]^2\\\\\\\\\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{2}\cdot \dfrac{2}{5} \Big[mR^2\Big]\Big[\dfrac{v}{R} \Big]^2\\\\\\\\\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2\Big]\Big[\dfrac{v}{R} \Big]^2\)

\(\\ \boxed{\left\begin{array}{ccc}\text{\Underline{Power of a Fraction Rule:}}\\\\\Big(\dfrac{a}{b}\Big)^2=\dfrac{a^2}{b^2} \end{array}\right }\)

\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2\Big]\Big[\dfrac{v^2}{R^2} \Big]\\\\\\\\\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2 \cdot\dfrac{v^2}{R^2} \Big]\)

"R²'s" cancel, we are left with:

\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2\Big]\Big[\dfrac{v^2}{R^2} \Big]\\\\\\\\\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5}mv^2\)

We have like terms, combine them.

\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2\Big]\Big[\dfrac{v^2}{R^2} \Big]\\\\\\\\\Longrightarrow mgh+\dfrac{7}{10} mv^2\)

Each term has an "m" in common, factor it out.

\(\Longrightarrow m(gh+\dfrac{7}{10}v^2)\)

Now we have the following equation:

\(\Longrightarrow m(gh+\dfrac{7}{10}v^2)=\dfrac12mv_{_{0}}^2+\dfrac12\Big[\dfrac25mR^2\Big]\Big[\dfrac{v_{_{0}}}{R}\Big]^2\)

\(\hrulefill\)

Simplifying the right-hand side of the equation:

\(\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac12\cdot\dfrac25\Big[mR^2\Big]\Big[\dfrac{v_{_{0}}}{R}\Big]^2\\\\\\\\\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac15\Big[mR^2\Big]\Big[\dfrac{v_{_{0}}}{R}\Big]^2\\\\\\\\\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac15\Big[mR^2\Big]\Big[\dfrac{v_{_{0}}^2}{R^2}\Big]\\\\\\\\\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac15\Big[mR^2\cdot\dfrac{v_{_{0}}^2}{R^2}\Big]\\\\\\\\\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac15mv_{_{0}}^2\Big\\\\\\\\\)

\(\Longrightarrow \dfrac{7}{10}mv_{_{0}}^2\)

Now we have the equation:

\(\Longrightarrow m(gh+\dfrac{7}{10}v^2)=\dfrac{7}{10}mv_{_{0}}^2\)

\(\hrulefill\)

Now solving the equation for the variable "v":

\(m(gh+\dfrac{7}{10}v^2)=\dfrac{7}{10}mv_{_{0}}^2\)

Dividing each side by "m," this will cancel the "m" variable on each side.

\(\Longrightarrow gh+\dfrac{7}{10}v^2=\dfrac{7}{10}v_{_{0}}^2\)

Subtract the term "gh" from either side of the equation.

\(\Longrightarrow \dfrac{7}{10}v^2=\dfrac{7}{10}v_{_{0}}^2-gh\)

Multiply each side of the equation by "10/7."

\(\Longrightarrow v^2=\dfrac{10}{7}\cdot\dfrac{7}{10}v_{_{0}}^2-\dfrac{10}{7}gh\\\\\\\\\Longrightarrow v^2=v_{_{0}}^2-\dfrac{10}{7}gh\)

Now squaring both sides.

\(\Longrightarrow \boxed{\boxed{v=\sqrt{v_{_{0}}^2-\dfrac{10}{7}gh}}}\)

Thus, the simplified equation above matches the simplified equation that was given.  

The force acting on the system of two blocks connected by a rope passing over a pulley is -13.26 N.

The system of two blocks connected by a rope passing over a pulley are M1 and M2, where M1 rests on the triangle edge to the left of the pulley, which makes an angle of theta subscript 1 with the base of the triangle. The coefficient of friction between box M1 and the surface is mu subscript 1. M2 rests on the triangle edge to the right of the pulley, which makes an angle of theta subscript 2 with the base of the triangle.

The coefficient of friction between box M2 and the surface is mu subscript 2. The system sits atop a scalene triangle whose long edge forms the base. The pulley is attached to the apex of the triangle.M1 has a mass of 2.25 kg and is on an incline of angle 1=42.5∘ that has a coefficient of kinetic friction 1=0.205. M2 has a mass of 5.55 kg and is on an incline of angle 2=33.5∘ that has a coefficient of kinetic friction 2=0.105.The free-body diagram of M1 shows that the weight of M1 acts straight downwards (vertically) and the normal force acts perpendicular to the slope.

The force of friction opposes the motion and acts opposite to the direction of motion.M1 = 2.25 kgTheta subscript 1 = 42.5 degreesMu subscript 1 = 0.205g = 9.81 m/s²In the free-body diagram of M2, the normal force acts perpendicular to the incline of the slope, the weight of the object acts vertically downwards and parallel to the incline, and the force of friction opposes the motion and acts opposite to the direction of motion.M2 = 5.55 kgTheta subscript 2 = 33.5 degreesMu subscript 2 = 0.105g = 9.81 m/s²The tension in the string is the same throughout the rope. Since the masses are being pulled by the same rope, the acceleration of the objects is the same as the acceleration of the rope.

The tension in the string is directly proportional to the acceleration of the objects and the rope.A system of two blocks connected by a rope passing over a pulley has a total mass of M. The acceleration of the system is given by the formula below:a = [(m1-m2)gsin(θ1) - μ1(m1+m2)gcos(θ1)] / (m1 + m2)Where, μ1 = 0.205 is the coefficient of friction of block M1θ1 = 42.5 degrees is the angle of the incline of block M1M1 = 2.25 kg is the mass of block M1M2 = 5.55 kg is the mass of block M2g = 9.81 m/s² is the acceleration due to gravitysinθ1 = sin 42.5 = 0.67cosθ1 = cos 42.5 = 0.75The acceleration of the system is:a = [(2.25-5.55)(9.81)(0.67) - (0.205)(2.25+5.55)(9.81)(0.75)] / (2.25 + 5.55)a = -1.7 m/s² (the negative sign indicates that the system is accelerating in the opposite direction).

The force acting on the system is given by:F = MaWhere M is the total mass of the system and a is the acceleration of the system. The total mass of the system is:M = m1 + m2M = 2.25 + 5.55M = 7.8 kgThe force acting on the system is:F = 7.8(-1.7)F = -13.26 N (the negative sign indicates that the force is acting in the opposite direction).

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By the work energy theorem we know that the net work done on an object is equal to its change in kinetic energy, that is:

where

Then, the work energy theorem can be express as:

In this case we know that the work done is 1450 J, that the mass is 21.325 kg and the initial velocity is 6 m/s; plugging these values and solving for the final velocity we have:

Therefore, the final velocity is 13.115 m/s and the correct option is A.

The average discharge of the Mississippi River at New Orleans (in cubic feet per second) is 657000 cubic feet per second

Given the average velocity (v) = 2.5miles per hour

Average width of river (w) = 2,000 feet

Average depth of river (d) = 90 feet

Discharge (D) = velocity (ft/sec) x river width (ft) x river depth (ft)

Given 1 mile = 5280ft and 1 hour = 3600 sec

1 mile/hour = 5280/3600 = 1.46ft/sec

2.5 miles per hour = 2.5x1.46 = 3.65ft/sec

D = 3.65X2000X90 = 657000 ft^3/sec

Hence the discharge of the Mississippi River is 657000 ft^3/sec

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Answer: 1 hour

Explanation: Focus on the units; 70 miles per hour means that each hour, you will travel 70 miles

or you can use the equation time = distance/speed. You have 70miles/ 70mph = 1hour

Answer:

4.80 seconds

Explanation:

The velocity of sound is obtained from;

V= 2d/t

Where;

V= velocity of sound = 329.2 ms-1

d= distance from the wall = 790.5 m

t= time = the unknown

t= 2d/V

t= 2 × 790.5/ 329.2

t= 4.80 seconds

The time is taken by the sound to reach the hiker will be  t= 4.80 seconds

The sound velocity is defined as the distance traveled by the sound wave in a particular direction with respect to time.

The velocity of sound  is given by the formula:

\(V=\dfrac{2d}{t}\)

Here;

V= velocity of sound = 329.2  \(\frac{m}{s^2}\)

d= distance from the wall = 790.5 m

t= time = the unknown

The time will be calculated as:

\(t=\dfrac{2d}{V}\)

\(t=\dfrac{2\times 790.5}{329.2}\)

\(t=4.80\ seconds\)

Hence the time is taken by the sound to reach the hiker will be  t= 4.80 seconds

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As a derivative of behaviorism, the learning principles that are the basis for behavior modification are considered empirically valid.

The concepts of operant conditioning, which were created by behaviourist B.F. Skinner, are the foundation of behaviour modification, a therapeutic strategy. In order to increase desired behaviours and decrease undesirable ones, it entails altering an individual's behaviour through reinforcement, punishment, or extinction.

The concepts of operant conditioning have been thoroughly investigated and put to the test through empirical research, and it has been discovered that they are successful in changing behaviour. As a result, because they are backed by research, the learning principles that underlie behaviour modification are regarded as empirically valid.

Behaviorism is a psychological perspective that places more emphasis on outward influences and observable behaviours than it does on internal mental processes. Behaviorism is a highly influential and well-respected school of psychology because its principles, including classical and operant conditioning, have been thoroughly investigated and empirically supported.

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Answer:

An asteroid impact could affect the tilt of the Earth due to the force it applies onto the planet. This would change Earth's seasons due to the fact that Earth's tilt causes seasons.

Answer:

Plane mirror

Explanation:

A virtual image is a copy of an object formed at the location from which the light rays appear to come.

Answer: headline, dateline, introduction

Explanation: its correct im not explaining