Gamma radiation is used for...Select one:a. communication.b. cancer therapy.c. radar.d. heating objects.

Answer:

because both petrol and diesel are oil

Explanation:

oil floats on water that's why if we will try to extinguish with water so the fire will float on water

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Answer:

Which of the following has kinetic energy?

A)  A book on a shelf

B)  A girl sprinting

C)  A stretched spring

Explanation:

Answer:

The period of the swing depends on only the length of the string and not on the mass of the bob and the period of the pendulum depends on only the horizontal component of g.

Explanation:

The period of the swing depends on only the length of the string and not on the mass of the bob. Since the length of the string and the mass of the bob define the pendulum.

Also, the properties that define the motion are the component of the weight of the bob in the horizontal direction which determines the to and fro movement of the bob. So, the period of the pendulum depends on only the horizontal component of g.

So, T = 2π√(l/g) where l = length of pendulum and g = acceleration due to gravity.

Answer:

180

Explanation:

1) E=F*L, where E - energy of the baseball, F - the required force, L - backward moving (0.35m);

2) E=mV²/2, where E - energy of the baseball, m - the mass of the baseball (0.14kg), V - the velocity of the baseball (30m/s).

3) if E=F*L and E=mV²/2, then F*L=mV²/2, from which

\(F=\frac{mV^2}{2L};\)

4) according to the last formula

\(F=\frac{0.14*900}{2*0.35}=\frac{126}{0.7}=180(N).\)

The force exerted by the ball on the glove is 180 Newtons.

In mechanics, a force is any action that has the potential to change, maintain, or deform a body's motion. The three principles of motion outlined by Isaac Newton in his Principia Mathematica are frequently used to illustrate the concept of force (1687).

Newton's first law states that a body at rest or moving uniformly in a straight line will stay in that state until a force is applied to it. According to the second law, a body will accelerate (change in velocity) in the direction of any external force acting on it.

Given:

A baseball (m = 140 g) traveling at 30 m/s moves a fielder's glove backward 35 cm when the ball is caught,

Calculate the value of force as shown below,

Force = m × V² / 2L

Force = 0.140 × 30² / 2 × 0.35

Force = 0.140 × 900 / 0.70

Force = 126 / 0.7

Force = 180 N

Thus, the force exerted by the ball is 180 Newtons.

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People use drugs for many reasons: they want to feel good, stop feeling bad, or perform better in school or at work, or they are curious because others are doing it and they want to fit in. The last reason is very common among teens.Drugs excite the parts of the brain that make you feel good. But after you take a drug for a while, the feel-good parts of your brain get used to it. Then you need to take more of the drug to get the same good feeling. Soon, your brain and body must have the drug just to feel normal. You feel sick, awful, anxious, and irritable without the drug. You no longer have the good feelings that you had when you first used the drug. This is true if you use illegal drugs or if you misuse prescription drugs. Misuse includes taking a drug differently than how your doctor tells you to (taking more or crushing pills to "shoot up" or snort), taking someone else’s prescription, or taking it just to get “high.”

Answer:

It means how much input work you put into the machine, which then becomes output from the machine. So you're putting 80% of work into the machinie. To find the efficency of a machine, it's output divided by input work.

Explanation:

Answer:

efficiency is the ratio of the power ouput to the power input

Explanation:

It compares how much energy is used to do work versus how much is lost or wasted to the environment, the more efficient the machine, the less energy wasted.

The dipole moment is 2.2 x 10^-5 Cm, The electric force due to dipole is  1.47 x 10^-18 N and it's final speed is  1.43 x 10^-8 m/s. The small charge will move a distance of approximately 1.90 x 10^-10 m during the time interval of 0.0133 s.

Let's first calculate the magnitude of the force between the two massive charges using Coulomb's law:

F = k * Q^2 / s^2

where k is Coulomb's constant, Q is the magnitude of the charge, and s is the separation between the charges.

Substituting the given values, we get:

F = (9 x 10^9 N m^2 / C^2) * (11e)^2 / (2s)^2

= 5.79 x 10^-9 N

Since the two charges are equal in magnitude and opposite in sign, they form an electric dipole. The dipole moment p is given by:

p = Qs

Substituting the given values, we get:

p = 11e x 2s

= 2.2 x 10^-5 Cm

The electric force on the small charge due to the dipole is given by:

F = k * p * q / R^3

where q is the magnitude of the small charge.

Substituting the given values, we get:

F = (9 x 10^9 N m^2 / C^2) * (2.2 x 10^-5 Cm) * (5e) / (63 m)^3

= 1.47 x 10^-18 N

Assuming the small charge starts from rest, its final speed after a time t is given by:

v = sqrt(2Ft / m)

where m is the mass of the small charge.

Substituting the given values, we get:

v = sqrt(2 x 1.47 x 10^-18 N x 0.0133 s / 0.035 kg)

= 1.43 x 10^-8 m/s

(4) The distance travelled by the small charge during the time interval t is given by:

d = vt

Substituting the given values, we get:

d = (1.43 x 10^-8 m/s) x (0.0133 s)

= 1.90 x 10^-10 m

Therefore, the small charge will move a distance of approximately 1.90 x 10^-10 m during the time interval of 0.0133 s.

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____The given question is incomplete, the complete question is given below:

Two massive charges +Q, +11e, and -Q, -11e, orbit each other in a circle of radius =8×10−6. A comparatively small charge -q, -5e, with mass 0.035 kg is placed initially at rest far from the dipole a distance R, 63 m. During the ensuing motion of all the three charges, you can assume that the force on does not affect the motion of the dipole. You may also safely ignore the gravitational interaction of these particles.

(2) Calculate the magnitude of the electric force acting on the small charge due to the dipole at the instant shown in the diagram. In the instant shown in the diagram, the charges of the dipole lie on an axis perpendicular to a line connecting the center of the dipole to the small charge -q.

(3) Assuming the small charge starts from rest, determine the speed of the charge a short time 0.0133 s later.

(4) Predict how far the small charge will move during this time interval.

i) The initial deceleration of the car is -1.6 m/s² and  the time taken is 5 seconds

ii) The final deceleration is -1 m/s²

iii) The total dispalcement = 1016 m

The initial deceleration of the car is given by the formula below:

v² = u² + 2as

where;

Solving for a;

12² = 20² + 2 * a * 80

a = -1.6 m/s²

Time taken, t = v - u / a

t = 12 - 20 / (-1.6)

t = 5 seconds

Final deceleration:

a = v - u / t

a = 0 - 12 / 12

a = -1 m/s²

iii) Displacement at constant velocity = 12 * 1 * 60

Displacement at constant velocity = 720 m

Final displacement, s = ut + 0.5at²

s = 12 * 12 + 0.5 * 1 * 12²

s = 216 m

Total dispalcement = 80 + 720 + 216

Total dispalcement = 1016 m

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Here is your answer,

As the heat capacities are equal , so m₁S₁ = m₂S₂

Let S be the specific heat of the composite body. Then,

(m₁ + m₂) S = m₁S₁ + m₂S₂

= m₁S₁ + m₁S₁ = 2 m₁S₁

S = 2 m₁S₁/m₁+ m₂ = 2 m₁S₁/ m₁ + m₁ + m₁ S₁/S₂

= 2 S₁S₂/S₁ + S₂

Answer:

The ambient temperature is 35°C.

It takes 15 minutes to cool the substance from 40°C to 35°C.

Explanation:

Using Newton's Law of Cooling to answer the given problem.

\(\boxed{\left\begin{array}{ccc}\text{\underline{Newton's Law of Cooling:}}\\\\ \frac{dT}{dt} =-k(T-T_a)\end{array}\right}\)

Given:

The time it takes to cool from 50°C to 45°C = 3 minutes

The time it takes to cool from 45°C to 40°C = 5 minutes

Find:

Time ambient temperature and the time it takes to cool the substance from 40°C to 35°C

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

(1) - Using first initial condition:

\(\text{Avg temp =} \ \frac{50+45}{2}=\boxed{47.5 \textdegree C}\\\\\Longrightarrow \frac{50-45}{3}=-k(47.5-T_a) \\\\\Longrightarrow \boxed{ \frac{5}{3}=-k(47.5-T_a)}\)

(2) - Using the second initial condition:

\(\text{Avg temp =} \ \frac{45+40}{2}=\boxed{42.5 \textdegree C}\\\\\Longrightarrow \frac{45-40}{5}=-k(42.5-T_a) \\\\\Longrightarrow \boxed{1=-k(42.5-T_a)}\)

(3) - Now we have a system of equations.

\(\left \{ \frac{5}{3}=-k(47.5-T_a)}} \atop {1=-k(42.5-T_a)}}} \right.\)

(4) - Solve the system by dividing the top equation by the bottom equation.

\(\Longrightarrow \frac{\frac{5}{3}=-k(47.5-T_a)}{1=-k(42.5-T_a)} \\\\\Longrightarrow\frac{5}{3}=\frac{47.5-T_a}{42.5-T_a}\\ \\ \Longrightarrow 5(42.5-T_a)=3(47.5-T_a)\\\\\Longrightarrow 212.5-5T_a=142.5-3T_a\\\\\Longrightarrow 2T_a=70\\\\\therefore \boxed{T_a=35 \textdegree C}\)

Thus, the ambient temperature is 35°C.

(5) - Find the value of "k" using either of the two previous equations

\(1=-k(42.5-T_a)\\\\\Longrightarrow 1=-k(42.5-35)\\\\\Longrightarrow 1=-7.5k\\\\\Longrightarrow \boxed{ k \approx -0.133}\)

(6) - Now finding "dt"

\(\text{Avg temp =} \ \frac{40+35}{2}=\boxed{37.5 \textdegree C}\\\\\Longrightarrow \frac{40-35}{dt}=0.133(37.5-35) \\\\\Longrightarrow \frac{5}{dt}=0.3325\\\\\therefore \boxed{dt \approx15 \ min}\)

Thus, it take 15 minutes to cool the substance from 40°C to 35°C.

The magnitude of the resultant vector to round the answer to the nearest tenth, we look at the digit in the hundredth's place. If this digit is 5 or greater, we round up. If it is less than 5, we round down.

In the study of physics, we use vectors to represent quantities that have both direction and magnitude. It is often the case that we want to add two or more vectors together to obtain a single vector that represents the net result of these additions. The process of adding two or more vectors together is known as vector addition.The magnitude of the resultant vector is the length of the line that represents it on a scale drawing.

When we add two or more vectors together, the resultant vector is the vector that represents the net result of these additions. To find the magnitude of the resultant vector, we use the Pythagorean theorem, which states that the square of the hypotenuse of a right triangle is equal to the sum of the squares of the other two sides.

In the case of vector addition, the hypotenuse is the resultant vector, and the other two sides are the component vectors. If we have two vectors a and b, the magnitude of the resultant vector is given by the following equation:|R| = √(ax2 + bx2)where R is the resultant vector, a and b are the component vectors, and x is the angle between the vectors.

For example, if the answer is 12.345, we would round it to 12.3.

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Explanation:

A one-kilogram mass is still a one-kilogram(as mass is an intrinsic property of the object) but the downward force due to gravity, and therefore it's weight, is only one-sixth of what the object would have on the Earth. So man of mass 180 pounds weights only about 30 pounds-force when visiting the moon

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Answer:

the small angle measurement from the central maximum is

Explanation:

The computation of the small angle measurement is as follows:

The constructive interference condition is

\(d \sin \theta = m \lambda \\\\Now \\\\\theta = sin^{-1} (\frac{\lambda}{d}) \\\\= sin^{-1}(\frac{610\times10^{-9}}{0.0250\times10^{-3}} )\\\\= 1.40^{\circ}\)

hence the small angle measurement from the central maximum is \(1.40^{\circ}\)

The weight of 15N should be hung at a distance of 4/3 units from the fulcrum, on the opposite side of the bar to a weight of 20N.

The fulcrum is attained equilibrium when the principle of moments is equal to zero. The principle of momentum is defined as the body is said to be balanced when the clockwise movement about the point is equal to the anticlockwise movement about the same point.

When a weight of 15N is hung on the bar, it produces an anticlockwise movement with the same magnitude, opposes the clockwise moment produced by the weight of 20N on the fulcrum.

To find the distance (d) at which the 15N weight should be hung, the distance from the 20N weight to the fulcrum is 1 unit.

20×1 = 15×d

d = 20/15

  =4/3 m

Thus, the weight of 15N should be hung by the distance of 4/3 units from the fulcrum, on the opposite side of the bar having the weight of 20N, to make the fulcrum to be at equilibrium.

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The amount indicated by is not fixed and changes over time. In situations where the linear acceleration is not zero, the velocity is always changing.

The first case is true

Since it depends on time, is not constant?

The amount indicated by is not fixed and changes over time. In situations where the linear acceleration is not zero, the velocity is always changing.

The dimension of the quantity albo will be ufa au av u t when calculating a particle's velocity as a function of time t using the formula v = a(1 - eb), where a and b are constants. (1 - e-b) Greutate, urb'a 221 Aich, a zat a2b3c faut Eleft.

The amount indicated by is not fixed and changes over time. When linear acceleration is absent  .

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The quantity represented by v is a function of time (i.e., is not constant).

True or false

A  particle moves with constant acceleration a. The expression VI +80 represents the particles velocity at what instant in time.

A. At a time T=zero

B. At the initial time

A particle starts from the origin at time t = 0 and moves along the positive x - axis. The graph of velocity with respect to time is shown in figure. What is the position of the particle at time t = 5s?

Answer:

0.49 seconds, 4.8(02)m/s

Explanation:

a) first convert 120cm to metres

that is 1.2m

suvat says that s = ut + ½ at²

let's rearrange that for time

t = -((u ± √(u² + 2as))/a)

u = 0

a = 9.8

s = 1.2

t = -((0 ± √(0 + 2(9.8)(1.2)))/9.8)

t = -((±√23.52)/9.8)

t = either 0.49 or -0.49 seconds.

since it cannot happen in negative time, the answer is 0.49 seconds

b) a = (v - u) / t

rearrange for v

v = u + at

a = 9.8

t = 0.49

u = 0

v = 0 + 9.8(0.49)

v = 4.8

or to be more specific, 4.802 m/s

GREETINGS!

Answer is 553 m/s

By the formula of,

       Vf = Vi + at

  where,

             Vi is initial velocity

             a is acceleration due to gravity

             t is time.

As we know that,

                            F = ma

so,

                   \(a = \frac{F}{m}\)

put this in the final velocity formula,

                  Vf = Vi + (F/m)t

                  Vf = 125 + (25000/440)7.5

                  Vf = 551.13 m/s

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Explanation:

a boy walks at 2m/s for 30sec and run at 5m/s for 20sec. what is his average speed

Answer:

time will it take for the car to stop = 8.75 s

Explanation:

The formula linking final velocity(v), initial velocity(u), acceleration(a) and time(t) is

v = u + at

The final velocity is 0 m/s since the car comes to a stop

Initial velocity u = 35 m/s

a = -4 m/s²

We have to find t

Plug in values

0 = 35 + (-4)t

-4t + 35 = 0

-4t = -35

t = -35/-4 = 8.75 s

From the question;

1) It takes 15.75 years to decrease to 1/8

2) It takes 8.36 years to decrease to 1/3

Half-life is the length of time it takes for a chemical to degrade or go through a particular process. It frequently refers to the length of time it takes for half of a radioactive substance to decay into a stable form in the context of radioactive decay.

We know that;

\(N/No = (1/2)^t/t1/2\)

No = initial amount

N = amount at time t

t = Time taken

t1/2 = half life

\(1/8 = (1/2)^t/5.252^-3 = 2^-t/5.25\)

t = 15.75 years

Again;

\(1/3 = (1/2)^t/5.25\)

ln0.33 = t/5.25ln0.5

t = ln0.33/ln0.5 * 5.25

t = 8.36 years

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Hellow!

For this use the next formula:

Vf = Vo + gt

Initial velocity is zero, so the formula simplificate:

Vf = gt

Data:

Vf = Final velocity = ?

g = Gravity = 9.8 m/s²

t = Time = 12 s

Replacing according our data:

Vf = 9.8 m/s² * 12 s

Vf = 117.8 m/s

The final velocity will be 117.8 meters per second.

"Kinetic" energy is the energy of motion.

The ball in the glove is not moving. It's just laying there. (B)

So it has no kinetic energy.

All the other choices describe something moving, so they all have some.

The minimum value of h is 3.75 meters.

To determine the minimum value of h, we need to consider the geometry of the situation.

From the given information, we know that the observer's eye is 1 m from the wall and 1.5 m above the ground. The vertical post-PQ is 3 m tall and located 4 m behind the observer. The observer can see the whole image of the post in the mirror.

Since the observer can see the entire image of the post, we can conclude that the line of sight from the top of the post to the observer's eye must be parallel to the line of sight from the bottom of the post to the observer's eye. This is because the mirror reflects light rays at equal angles of incidence and reflection.

Let's denote the height of the observer's eye from the ground as x. We can set up a proportion to find the height of the image of the post in the mirror:

(Height of post-PQ) / (Distance from observer to post) = (Height of the image in the mirror) / (Distance from mirror to image)

Using the given values, we have:

3 m / 4 m = h / (4 m + 1 m)

Simplifying the equation:

3/4 = h/5

Cross-multiplying:

4h = 15

h = 15/4 = 3.75 m

Therefore, the minimum value of h is 3.75 meters.

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The average speed of the motorist in the second half of the journey is determined as 7 km/h.

The average speed of an object is the ratio of total distance to total time of motion.

21 = (35 + x) / 2

35 + x = 42

x = 42 - 35

x = 7 km/h

Thus, the average speed of the motorist in the second half of the journey is determined as 7 km/h.

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