Gas molecules rotate or vibrate because the binding force between the gas molecules is _____.

Answer:

1)Black pigment is the absorption of red, green, and blue light.

3)White light is the combination of red, green, and blue light

The acceleration of the plane will be −8 m/s²

How to find the acceleration of a plane?

Acceleration is the rate of change in velocity over time (Δv/t).

Given, that the initial velocity of the plane u=480 m/s

The final velocity of the plane is zero after landing, v= 0 m/s

t= 1 minute= 60 seconds

we know, v=u + at

0= 480 + 60a

a=\(\frac{-480}{60}\)  = -8m/s²

Thus, the acceleration of the plane is -8 m/s²

(negative acceleration implies that the object is slowing down)

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Answer:

Its B

Explanation:

a p e x

It is proved for gravitational radius that Rg=GMs/c^2 .

Given,

The mass of sun = Ms

Sphere of radius = Rg

Sun collapses to a sphere such that the work required to remove a small mass (m) from the surface would be equal to its rest energy mc^2 .

The given radius (Rg) is called as gravitational radius for sun.

We know,

gravitational potential energy Ug = G ×Ms×m/Rg

given, the rest energy, E =mc^2

As it is given that work required to remove small mass is equal to rest energy,

thus, Ug=E

G×Ms×m/Rg = mc^2

Rg =GMs/c^2

Hence, it is proved for gravitational radius that Rg=GMs/c^2 .

Total work done in assembling bodies together,in their respective places, is called gravitational potential energy of the system.

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Answer:

If you put the metal extract into the water there will be no reaction but if you put it into the acid it will liberate H2 (hydrogen gas) Hence it is the difference

Explanation:

this should sum it down

This cart would move with constant velocity or be at rest because the net force is equal to zero (0), which means the three (3) forces acting on the cart opposes each other.

Given the following data:

To find the net force acting on the cart:

A net force can be defined as the vector sum of all the forces that are acting on a physical object or body.

This ultimately implies that, a net force is a single (one) force that substitutes the effect of all the forces acting on a physical object or body.

Mathematically, net force is given by the following:

\(Net \;force = F_1 + F_2 + F_3 + F_4 + .....F_n\)

Where:

\(Net\; force = 60 + 30 + (-90)\\\\Net\; force = 90 - 90\)

Net force = 0 Newton

Based on Newton's First Law of Motion, this cart would move with constant velocity or be at rest because the net force is equal to zero (0), which means the three (3) forces acting on the cart opposes each other.

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Answer:

1. The correct way a cell phone call goes out is;

The phone call goes out, transmits through radio waves, then moves to the central hub. Then the signal go to the nearest tower to the receiver of the call

2. Long wavelength

3. Microwave

Explanation:

1. When making a call through a cell phone, the speech made is digitized such that it is converted to electrical signals which are then converted into number strings that are transmitted out of the antenna of the phone as radio waves which are then picked up by the closest cellphone tower mast which then transmit the signal to the applicable central hub from where the signal is transmitted to the tower closest to the intended call receiver

Therefore, the correct option is that the phone call goes out, transmits through radio waves, then moves to the central hub. Then the signal go to the nearest tower to the receiver of the call

2. The property of AM frequencies that allow them to travel over long distances is long wavelength

The frequency of AM radio waves is between 540 kHz and 1600 kHz, which can be propagated as ground wave or by the ionosphere at night

3. Cell phones makes use of the subcategory of microwave which is the super high frequency (SHF) band which with a range of 3 GHz to 30 GHz

The correct statement about the Electron Transport Chain (ETC) is option d, which states that the electron transport chain pumps protons into the matrix to form a proton gradient.

The ETC is a series of protein complexes that transfer electrons from electron donors to electron acceptors, ultimately generating ATP. During the process, protons are pumped from the mitochondrial matrix across the inner membrane to the intermembrane space, creating a proton gradient. This gradient is then used by ATP synthase to generate ATP through oxidative phosphorylation.

Option a is incorrect as Complex II is also an entrance point for electrons in the ETC. Option b is incorrect as the electron transport reactions are not directly coupled to substrate-level phosphorylation. Option c is also incorrect as NADH and FADH2 have high reduction potentials compared to other electron carriers in the ETC. Lastly, option e is incorrect as Complex IV is involved in proton pumping during the ETC process. Hence the answer is option d.

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A cooperative method for combining the knowledge and skills of professionals in two or more professions

The integration of concepts and traits from several fields is made possible by interdisciplinary study. In addition, it helps kids gain critical, adaptable abilities while addressing their unique individual differences.

Interdisciplinary research integrates information, data, methodologies, methods, viewpoints, concepts, or theories from two or more fields of study.

Interdisciplinary science is the collaborative process of fusing the knowledge/expertise of trained people from two or more disciplines, utilizing multiple viewpoints, approaches, and research methods/methodologies, to produce progress beyond the capacity of one discipline.

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Answer:

1.Environmental science is a discipline in the sciences that deals with the relationship between living and non-living things and the effects they have on one another, whether positive or negative. It focuses specifically on the effects of humans on the environment. Environmental science is a highly interdisciplinary field that includes both basic and applied aspects

2.An applied science is a science that seeks to solve an immediate problem.

3.The main feature of an interdisciplinary science is its collaboration across differing disciplines. Experts from different fields use their skills to piece together complex answers from a variety of perspectives.

4.c

5.a

6.f

7.e

8.b

9d

Explanation:

PF

#4

Resistors are connected in parallel circuit

#5

They differs

Because

For series connection

\(\\ \rm\rightarrowtail R_{net}=R_1+R_2\dots\)

For parallel connection

\(\\ \rm\rightarrowtail \dfrac{1}{R_{net}}=\dfrac{1}{R_1}+\dfrac{1}{R_2}\dots\)

So, here for question no. 4 and 5, we are given a Diagram, which have 3 resistors connected in parallel each having a resistance of \({\bf{2\Omega}}\), \({\bf{3\Omega}}\) and \({\bf{4\Omega}}\). And we are told to find a factor which will change for the given combination, and a factor which will not change, So here, as the resistors are connected in parallel, so the voltage will remain same for all the resistors, while the Current will be different for every resistor, And that's what the reason of why we always do connection in parallel for home purposes, because, we need voltage same in every resistor of the circuit. So, the factor which will change is \({\boxed{\bf{Current}}}\) and the factor which willn't change is \({\boxed{\bf{Voltage}}}\), and if the resistors were connected in Series combination, then current should be same for all resistors, while voltage will change.

Well, if the resistors are connected in the above way we have, and if we call our Resistors as \({\bf{R_{1}}}\), \({\bf{R_{2}}}\) and \({\bf{R_{3}}}\), then the equivalent resistance we will be having is :

\({:\implies \quad \boxed{\bf{\dfrac{1}{R_{eq.}}=\dfrac{1}{R_1}+\dfrac{1}{R_2}+\dfrac{1}{R_3}}}}\)

Also, we can prove this fact just with the help of the reason provided in the above question, i.e that in Parallel combination, voltage remains same, but current changes, while in Series combination, current remains same but voltage changes, so we are just gonna prove the formula for both series combination and Parallel as well

So, let's prove the formula for series combination first, so consider n resistors connected in series, let Resistors as \({\bf{R_{1},R_{2},R_{3}\cdots \cdots R_{n}}}\), now as current will be same through all the resistors as connected in series, so if the current \({\bf{I}}\) from then, same current will flow through the whole circuit and each resistors, also let the voltages of every resistors being \({\bf{V_{1},V_{2},V_{3}\cdots \cdots V_{n}}}\), so now by Ohm's law, we can deduce that, the current from first circuit will be \({\bf{V_{1}=IR_{1}}}\)...and so on for all Resistors, and now if we add all resistors, so the equivalent Voltage will just be ;

\({:\implies \quad \sf V_{eq.}=V_{1}+V_{2}+V_{3}+\cdots \cdots +V_{n}}\)

\({:\implies \quad \sf IR_{eq.}=IR_{1}+IR_{2}+IR_{3}+\cdots \cdots IR_{n}}\)

\({:\implies \quad \sf I(R_{eq.})=I(R_{1}+R_{2}+R_{3}+\cdots \cdots R_{n})}\)

\({:\implies \quad \boxed{\bf{R_{eq.}=R_{1}+R_{2}+R_{3}+\cdots \cdots R_{n}}}}\)

Therefore, we proved for series.

Now, consider n resistors connected in parallel, with resistances, \({\bf{R_{1},R_{2},R_{3}\cdots \cdots R_{n}}}\), now as voltage will be same through all the resistors as connected in parallel,while current will change, so let total voltage be \({\bf{V}}\), and current for each resistor as \({\bf{I_{1},I_{2},I_{3}\cdots \cdots I_{n}}}\),so by using the same concept as above we can write by using ohm's law :

\({:\implies \quad \sf I_{eq.}=I_{1}+I_{2}+I_{3}+\cdots \cdots +I_{n}}\)

Rewrite using ohm's law :

\({:\implies \quad \sf \dfrac{V}{R_{eq.}}=\dfrac{V}{R_1}+\dfrac{V}{R_2}+\dfrac{V}{R_3}+\cdots \cdots +\dfrac{V}{R_n}}\)

\({:\implies \quad \sf V\dfrac{1}{R_{eq.}}=V\bigg(\dfrac{1}{R_1}+\dfrac{1}{R_2}+\dfrac{1}{R_3}+\cdots \cdots +\dfrac{1}{R_n}\bigg)}\)

\({:\implies \quad \boxed{\bf{\dfrac{1}{R_{eq.}}=\dfrac{1}{R_{1}}+\dfrac{1}{R_{2}}+\dfrac{1}{R_{3}}+\cdots \cdots +\dfrac{1}{R_{n}}}}}\)

Hence, we proved for Parallel combination too

Also, refer to the attachment for a better understanding, and just a point that Voltmeter is always connected in parallel while ammeter in series, and all the things above are taken in SI units

As the moon phase approaches full we say the Moon has now completed one half of the lunar month.

This is defined as the time it takes the Moon to pass through all of the phases.

When the moon approaches full then itn has completed one half of the lunar month which is the time taken to form a new moon.

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Answer:

A barcode reader (or barcode scanner) is an optical scanner that can read printed barcodes, decode the data contained in the barcode and send the data to a computer. Like a flatbed scanner, it consists of a light source, a lens and a light sensor translating for optical impulses into electrical signals.

Explanation:

A barcode reader (or barcode scanner) is an optical scanner that can read printed barcodes, decode the data contained in the barcode and send the data to a computer. Like a flatbed scanner, it consists of a light source, a lens and a light sensor translating for optical impulses into electrical signals.

The given amplifier circuit is a common-source amplifier. The equivalent circuit diagram of the amplifier includes a MOSFET N5486 transistor. We can determine the drain current (ID) and drain-source voltage (VDS) using the following equations:

1. Voltage at the source terminal (VS) is calculated using Ohm's law: VS = IS x RS.2. The drain current (ID) can be calculated using the equation ID = IS (1 + GVin), where Vin is the input voltage, G is the voltage gain, and IS is the current flowing through RD.Let's calculate the values of ID and VDS:

Given:- IS = VDD / RD = 10V / 10Ω = 1A- Vin = -1V / (1.5 x 10^6Ω + 0.47μF) = -0.6666667μA (using voltage divider rule)- G = -RD / RS = -10Ω / 3kΩ = -0.003333 Calculating ID:ID = 1A (1 - 0.003333 x 0.6666667 x 10^6)≈ 0.997A = 997mACalculating VDS:VDS = VDD - IDRD= 10V - 997mA x 10Ω≈ 10V - 9.97V≈ 0.03VTherefore, the values of ID and VDS are approximately ID = 997mA and VDS ≈ 0.03V, respectively.

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During eeg measurements, 6-10 electrodes are attached to the scalp and produce line drawings that represent brain waves.

EEG stands for electroencephalogram and eeg measurements refer to the recording of brain activities in the form of neuron signals.

In this test, micro sized sensors or electrodes are attached to the head or scalp of a person and electrical signals are recorded released by the brain neurons.

On the EEG recorder, the brain activities show up in the form of wave signals or wavy lines indicating that brain communicates through electrical currents signals.

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Answer:

brain waves

Explanation:

Answer:

They are also called the gas planets because they consist mainly of hydrogen, or the giant planets because of their size. These planets usually have complicated system of many moons and often even rings of ice and/or dust. There are four Jovian planets in the Solar System: Jupiter, Saturn, Uranus and Neptune.

Answer:

They are also called the gas planets because they consist mainly of hydrogen, or the giant planets because of their size. These planets usually have complicated system of many moons and often even rings of ice and/or dust. There are four Jovian planets in the Solar System: Jupiter, Saturn, Uranus and Neptune.

Explanation:

i hope this helps :)

If a ball has twice the mass but the same initial velocity, it would have less displacement (neglecting air resistance).

Kinematics deals with the motion of objects without consideration of the cause of motion. One of the kinematic quantities is displacement. The displacement of an object refers to the distance travelled by the object in a straight line in a specific direction. The magnitude of the displacement is the shortest distance between the initial and final points of the object. For instance, if a ball is thrown vertically upward, the displacement of the ball at its highest point is zero because it is the same as the starting point. However, the distance travelled by the ball is not zero because it has travelled a vertical distance equal to its maximum height.

In regards to the question, if a ball has twice the mass but the same initial velocity, it would have less displacement (neglect air resistance). This is because the mass of an object is a measure of its resistance to change its state of motion. The more massive an object, the greater the force needed to move it. If the initial velocity of two objects is the same but the mass is different, the object with the lesser mass will cover more distance than the one with the greater mass. This is because the greater mass requires more force to move hence it will slow down quickly and travel less distance than the lighter object

If a ball has twice the mass but the same initial velocity, it would have less displacement (neglecting air resistance). This is because the mass of an object is a measure of its resistance to change its state of motion. The more massive an object, the greater the force needed to move it.

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During the first year of life, babies go through a series of developmental milestones in terms of sounds and gestures. Here is the order of the sequence, beginning with the earliest form at the top:1. Crying: Crying is one of the first forms of communication that babies use to express their needs or discomfort.

It is a natural instinct and serves as a way to get attention and assistance from caregivers.2. Cooing: Around 2 to 3 months, babies begin to produce cooing sounds. These are soft, vowel-like sounds that babies make when they are content and happy. It is an early attempt at vocalization.

3. Babbling: Between 6 to 8 months, babies start babbling. This is when they produce repetitive syllables such as "ba-ba" or "da-da." It is an important step in language development and helps babies practice using their vocal cords.
4. Gesturing: By around 9 to 12 months, babies start to use gestures to communicate. This includes waving goodbye, pointing at objects, or reaching out to be picked up. These gestures are their way of expressing their desires and interacting with their environment.

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Under constant acceleration, we have

\(v^2-{v_0}^2 = 2ax\)

where \(v\) is final velocity, \(v_0\) is initial velocity, \(a\) is acceleration, and \(x\) is distance.

Solving for \(x\) gives

\(x = \dfrac{v^2-{v_0}^2}{2a}\)

Then if the car starts with speed 25 m/s and acceleration -7.0 m/s², and comes to a rest (so that \(v=0\)), we have

\(x = \dfrac{-\left(25\frac{\rm m}{\rm s}\right)^2}{2\left(-7.0\frac{\rm m}{\mathrm s^2}\right)} \approx \boxed{45\,\mathrm m}\)

Answer: 5.42 kg

Explanation:

The formula for kinetic energy is:

KE = 1/2 * m * v^2

where KE is the kinetic energy, m is the mass of the object, and v is the velocity of the object.

We are given the kinetic energy (KE) and velocity (v), so we can rearrange the formula to solve for the mass (m):

m = 2 * KE / v^2

Substituting the given values, we get:

m = 2 * 390 J / (12 m/s)^2

m = 2 * 390 J / 144 m^2/s^2

m = 5.42 kg (rounded to two decimal places)

Therefore, the mass of the stone is approximately 5.42 kg.

Answer:

y = 33.93 10⁵ m

Explanation:

This is an interference exercise, for the contributory interference is described by the expression

           d sin θ = m λ

let's use trigonometry for the angle

           tan θ = y / L

how the angles are small

          tan θ = sin θ / cos tea = sin θ

we substitute

         sin θ = y / L

        d y / L = m λ

         y = m λ L / d

the light fulfills the relation of the waves

       c = λ f

       λ = c / f

       λ = 3 10⁸ /375

       λ = 8 10⁵ m

first order m = 1

let's calculate

        y = 1  8 10⁵  4030 10-9 / 950 10-9

        y = 33.93 10⁵ m

Specific heat capacity is the amount of energy needed to raise the temperature of a unit mass of a substance by one degree Celsius (or Kelvin).

We know that the heat lost by the object is gained by the water

m1c1ΔT1 = m2c2ΔT2

Where, m1 = Mass of the object

c1 = Specific heat capacity of the object

ΔT1 = Change in temperature of the object

m2 = Mass of the water

c2 = Specific heat capacity of the water

ΔT2 = Change in temperature of the water

We know that density of water = 1000 kg/m³

Density of object = Mass/Volume

⇒ Volume of the object = Mass/Density of the object

Given, Mass of the object = 0.075 kg Density of the object = ?

Volume of the object = Mass/Density of the object

                                   = 0.075 kg/ Density of the object

Initial temperature of water, T2 = 25 Celsius

Final temperature of water, T1 = 29 Celsius

Mass of the water, m2 = 0.15 kg

\(m1c1ΔT1 = m2c2ΔT2\\⇒ 0.075 kg × c1 × (-4) Celsius\\ = 0.15 kg × 4186 J/kg°C × 4 Celsius\\⇒ -0.3c1 = 25116 J/°C⇒ c1 = -25116 J/°C / -0.3 = 83720 J/°C\)

The specific heat capacity of the object is 83720 J/°C which can also be written as J/(kg°C) by dividing the answer by the mass of the object.

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The wavelength of the radio waves emitted by the station is approximately 3.39 meters.

To calculate the wavelength of the radio waves, we can use the formula λ = c/f, where λ represents wavelength, c is the speed of light, and f is the frequency.

The speed of light is approximately 3.00 x 10^8 meters per second.

Given the frequency of the radio station as 88.7 megahertz (MHz), we need to convert it to hertz by multiplying it by 10^6.

Thus, the frequency becomes 88.7 x 10^6 hertz.

Substituting the values into the formula, we get λ = (3.00 x 10^8 m/s) / (88.7 x 10^6 Hz), which simplifies to approximately 3.39 meters.

Therefore, the wavelength of the radio waves emitted by the station is approximately 3.39 meters.

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The pressure exerted by the water at the bottom of the well is 170000 Pa.

We can use the formula for pressure due to a liquid:

pressure = density × gravity × height

where;

Assuming the density of water is 1000 kg/m³ and the acceleration due to gravity is 9.81 m/s², we can calculate the pressure at the bottom of the well as:

pressure = 1000 kg/m³ × 9.81 m/s² × 17 m

pressure = 166970 Pa

Rounding off to two significant figures, the pressure exerted by the water at the bottom of the well is 170000 Pa.

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Answer:

M = 4.5

Explanation:

He ran 3 meters, which is three meters. Then he ran back half of 3, which is 1.5 meters. 3 + 1.5 is 4.5

Answer:

A

Explanation:

a small force results in a large acceleration

Answer:

Option (3)

Explanation:

Formula used to calculate acceleration is,

F = ma

Where F = force exerted on a mass

m = mass

a = acceleration due to force exerted on the mass

Option (1),

When F = 100 N and m = 100 kg

100 = 100a

a = 1 m per sec²

Option (2)

For F = 1 N and m = 100 kg

1 = 100a

a = \(\frac{1}{100}\)

a = 0.01 m per sec²

Option (3)

For F = 100 N and m = 1 kg

100 = 1(a)

a = 100 m per sec²

Option (4)

For F = 1 N and m = 1 kg

1 = 1(a)

a = 1 m per sec²

Therefore. acceleration in Option (3) is the maximum.

The mass is undergoing to the greatest amount of acceleration is 1 kg subjected to a force of 100 N.

The given parameters:

The acceleration of each of the given masses is calculated by applying Newton's second law of motion as follows;

\(F = ma\\\\\a = \frac{F}{m}\)

When mass = 100 kg and force = 100 N, the acceleration is calculated as;

\(a = \frac{100}{100} \\\\a = 1 \ m/s^2\)

When mass = 100 kg and force = 1 N, the acceleration is calculated as;

\(a = \frac{1 }{100} \\\\a = 0.01 \ m/s^2\)

When mass = 1 kg and force = 100 N, the acceleration is calculated as;

\(a = \frac{100}{1} \\\\a = 100 \ m/s^2\)

When mass = 1 kg and force = 1 N, the acceleration is calculated as;

\(a = \frac{1}{1} \\\\a = 1 \ m/s^2\)

Thus, the mass is undergoing to the greatest amount of acceleration is 1 kg subjected to a force of 100 N.

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The rest of the original candle’s mass was changed to gases.

The law of conservation of mass states that during a chemical reaction in an enclosed medium that there is neither generation or lost if it's mass but that it can be transformed.

Mass is defined as the scalar quantity that defines the quantity of matter found in a particular component or object.

The candle is made up of carbonic compounds that decreases in mass to form a puddle of wax when burnt.

The original mass of the candle was not lost but while some where converted to puddle of wax the rest escaped as gas to the atmosphere.

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Starting from rest on a circular track with a radius of 300 m and a constant tangential acceleration of 0.75 m/s², the car will travel a distance of approximately 0.2119 meters or 21.19 centimeters in 0.75 seconds.

To determine the distance traveled and the time elapsed by the car starting from rest on a circular track with a radius of 300 m and a constant tangential acceleration of 0.75 m/s², we can use the equations of circular motion.

The tangential acceleration is the rate of change of tangential velocity. Since the car starts from rest, its initial tangential velocity is zero (v₀ = 0).

Using the equation:

v = v₀ + at

where v is the final tangential velocity, v₀ is the initial tangential velocity, a is the tangential acceleration, and t is the time, we can solve for v:

v = 0 + (0.75 m/s²) * t

v = 0.75t m/s

The tangential velocity is related to the angular velocity (ω) and the radius (r) of the circular track:

v = ωr

Substituting the values:

0.75t = ω * 300

Since the car starts from rest, the initial angular velocity (ω₀) is zero. So, we have:

ω = ω₀ + αt

ω = 0 + (0.75 m/s²) * t

ω = 0.75t rad/s

We can now substitute the value of ω into the equation:

0.75t = (0.75t) * 300

Simplifying the equation gives:

0.75t = 225t

t = 0.75 seconds

The time elapsed is 0.75 seconds.

To calculate the distance traveled (s), we can use the equation:

s = v₀t + (1/2)at²

Since the initial velocity (v₀) is zero, the equation becomes:

s = (1/2)at²

s = (1/2)(0.75 m/s²)(0.75 s)²

s = (1/2)(0.75 m/s²)(0.5625 s²)

s = 0.2119 meters or approximately 21.19 centimeters

Therefore, the car travels a distance of approximately 0.2119 meters or 21.19 centimeters.

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