The common name of the compound with the condensed formula\(CH_3-CH_2-CH_2-O-CH_2-CH_2-CH_2-CH_3\) is "di-n-butyl ether."
Di-n-butyl ether is a colorless liquid with a faint odor that is highly flammable and volatile. It is soluble in organic solvents and has a low solubility in water. Di-n-butyl ether is commonly used as a solvent for fats, oils, resins, and waxes, as well as for industrial cleaning and paint stripping.
It is also used as a fuel additive in diesel engines to improve the cetane number, which is a measure of the fuel's ignition quality. However, di-n-butyl ether is not as commonly used as other ethers, such as diethyl ether, due to its high flammability and toxicity. In high concentrations.
It can cause irritation to the eyes, skin, and respiratory system, and may be harmful if ingested or absorbed through the skin.
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How electrons if n=3 and (l=2 or m=0)
Answer:
2 e
Explanation:
d orbit contain 10 electrons .
2. What element is steel mainly
composed of?
A Iron
B. Carbon
C. Manganese
D. Silver
Answer:
Carbon
Explanation:
Steel is an alloy of iron and carbon. Stainless steels are steels containing at least 10.5% chromium, less than 1.2% carbon and other alloying elements
Answer: B
Explanation:Steel is an alloy of iron and carbon.
when humans burn fossil fuels, most of the the carbon quickly enters the atmosphere as carbon dioxide in the atmosphere in the process called
•transpiration
•combustion
•decomposition
•photosynthesis
Hi! I need help on 1-4 ASAP! Thanks!
Answer:
5. a. false b. true c. false d. true e. false
6. it has to be something that can be supported or refuted through carefully crafted experimentation or observation
how will you know if one sugar is fermented more easily than another?
When it comes to determining whether one sugar is fermented more easily than another, there are several factors to consider. First, it's important to understand the process of fermentation itself. Fermentation is a metabolic process that converts sugar into alcohol, gases, and organic acids through the action of yeast or bacteria.
The ease of fermentation depends on the chemical structure of the sugar molecule. For example, simple sugars like glucose and fructose are typically easier to ferment than complex sugars like sucrose or lactose. This is because the simpler sugar molecules are easier for the yeast or bacteria to break down and utilize as a food source.
Another factor to consider is the presence of inhibitors or other substances that may interfere with the fermentation process. Some sugars may contain compounds that inhibit the growth or activity of yeast or bacteria, making fermentation more difficult. Conversely, other sugars may contain nutrients or other substances that promote fermentation and make it easier for the microorganisms to thrive.
Ultimately, the best way to determine whether one sugar is fermented more easily than another is to conduct experiments and measure the rate and extent of fermentation under controlled conditions. This may involve monitoring factors like temperature, pH, oxygen levels, and the presence of other microorganisms or substances that could impact the fermentation process. By carefully controlling these variables and comparing the results across different sugar sources, it may be possible to identify which sugars are most easily fermented by a particular type of yeast or bacteria.
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what qualities of a chemical reaction are affected by enzymes? select all that apply. check all that apply the speed of the reaction the speed of the reaction the products of the reaction the products of the reaction the net energy released during the reaction the net energy released during the reaction the net energy gained during the reaction the net energy gained during the reaction the energy required to start the reaction the energy required to start the reaction
The correct options are:
The speed of the reaction.The products of the reaction.The energy required to start the reaction.The qualities of a chemical reaction that are affected by enzymes include:
The speed of the reaction: Enzymes can significantly increase the rate of a chemical reaction by lowering the activation energy barrier required for the reaction to proceed. This allows the reaction to occur more quickly.
The products of the reaction: Enzymes can influence the outcome of a chemical reaction by promoting specific reaction pathways or facilitating the formation of particular products.
The energy required to start the reaction: Enzymes lower the activation energy, which is the energy required to initiate a chemical reaction. By reducing this energy barrier, enzymes make it easier for the reaction to start.
Hence, the correct options are:
The speed of the reaction.The products of the reaction.The energy required to start the reaction.Learn more about Chemical reaction from the link given below.
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rank the following carbonyl‑containing compounds in order of reactivity towards nucleophilic acyl substitution.Most reactive Least reactive benzoyl chloride butyl acetate acetic anhydride propionamide
The correct order of reactivity towards nucleophilic acyl substitution is: Benzoyl chloride > Acetic anhydride > Propionamide > Butyl acetate.
Benzoyl chloride is the most reactive due to the presence of a highly electronegative chlorine atom, which makes the carbonyl carbon more electrophilic and thus more susceptible to nucleophilic attack.
Acetic anhydride is the second most reactive due to the presence of two carbonyl groups in close proximity, which increases the electrophilicity of the carbonyl carbon.
Propionamide is less reactive than acetic anhydride due to the presence of an amide group, which is less electrophilic than a carbonyl group. Butyl acetate is the least reactive due to the presence of an ester group, which is even less electrophilic than an amide group.
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what causes the electron groups around a central atom to similarly spread out as much as possible?
Electron groups around a central atom tend to spread out as much as possible because of the electron-electron repulsion principle, also known as the Pauli exclusion principle. According to this principle, electrons in an atom tend to occupy different energy levels, or orbitals, to minimize the repulsive interactions between them.
When electron groups are spread out as much as possible, the energy of the system is minimized, and the atoms are more stable. This is because the repulsive forces between the electrons are reduced when they are farther apart. This is known as the octet rule, which states that atoms tend to gain or lose electrons in such a way as to have eight valence electrons in their outermost shell, which is the most stable configuration.
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Give the formula for the compound formed when magnesium oxide reacts with water. Express your answer as a chemical formula.
The compound formed when magnesium oxide reacts with water is magnesium hydroxide (Mg(OH)₂).
Magnesium oxide (MgO) is an ionic compound consisting of magnesium cations (Mg²⁺) and oxide anions (O²⁻). When it reacts with water (H₂O), the oxygen atom in water attracts the magnesium cation, leading to the formation of magnesium hydroxide.
The reaction can be represented as follows:
MgO + H₂O → Mg(OH)₂
In the resulting compound, magnesium hydroxide, there are two hydroxide ions (OH-) for every magnesium ion (Mg²⁺). The chemical formula Mg(OH)₂ represents this ratio.
Magnesium hydroxide is an alkaline compound and is commonly used as an antacid to treat heartburn and indigestion. It is also used in various industrial applications.
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Molarity of Kool Aid solutions can be calculated by comparing the concentrations of Kool Aid powder and sugar added to a given volume of water. The molar mass of Kool Aid will be the same as that of sugar for our purpose. The molecular formula for sugar is C12H22O11- Your objective for this lab will be to calculate the molarity of Kool Aid desired based on package directions. You will then be provided two concentrated Kool Aid solutions. You will use dilution calculations to determine the amount of water and concentrated solution you will need in order to prepare 65 mL of the desired molarity.
Calculate the molarity of Kool Aid desired based on the following information from the package directions.
1 package Kool Aid powder = 4. 25 grams 1 cup sugar = 192. 00 grams
2. 00 quarts of water (1. 06 quarts = 1 liter)
The amount of concentrated solution needed is (0.286 M)(65 mL) / C M, and the amount of water needed is 65 mL minus the volume of the concentrated solution.
To calculate the molarity of Kool Aid desired, we need to determine the number of moles of Kool Aid powder and sugar in the package. Since the molecular formula for sugar is C12H22O11, we can calculate its molar mass as follows:
Molar mass of C12H22O11 = (12 * 12.01) + (22 * 1.01) + (11 * 16.00)
= 144.12 + 22.22 + 176.00
= 342.34 g/mol
Given that the package contains 4.25 grams of Kool Aid powder, we can calculate the number of moles of Kool Aid powder using its molar mass:
Number of moles of Kool Aid powder = Mass / Molar mass
= 4.25 g / 342.34 g/mol
≈ 0.0124 mol
Similarly, for the sugar, which has a molar mass of 342.34 g/mol, we can calculate the number of moles of sugar using its mass:
Number of moles of sugar = Mass / Molar mass
= 192.00 g / 342.34 g/mol
≈ 0.5612 mol
Now, to calculate the molarity of the desired Kool Aid solution, we need to determine the volume of water. Given that 1.06 quarts is equal to 1 liter, and we have 2.00 quarts of water, we can convert it to liters as follows:
Volume of water = 2.00 quarts * (1.06 liters / 1 quart)
= 2.12 liters
To find the molarity, we use the formula:
Molarity (M) = Number of moles / Volume (in liters)
Molarity of Kool Aid desired = (0.0124 mol + 0.5612 mol) / 2.12 L
≈ 0.286 M
To prepare 65 mL of the desired molarity, we can use dilution calculations. We need to determine the volume of concentrated solution and the volume of water needed.
Let's assume the concentration of the concentrated Kool Aid solution is C M. Using the dilution formula:
(C1)(V1) = (C2)(V2)where C1 is the initial concentration, V1 is the initial volume, C2 is the final concentration, and V2 is the final volume.
Given that C1 = C M and V1 = V mL, and we want to prepare a final volume of 65 mL (V2 = 65 mL) with a final concentration of 0.286 M (C2 = 0.286 M), we can rearrange the formula to solve for the volume of the concentrated solution:
(C M)(V mL) = (0.286 M)(65 mL)
V mL = (0.286 M)(65 mL) / C M
So, the amount of concentrated solution needed is (0.286 M)(65 mL) / C M, and the amount of water needed is 65 mL minus the volume of the concentrated solution.
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A cylindrical shell is 3 m long; 1 m in diameter and the thickness of metal is 10 mm. It is subjected to an internal pressure of 150 N/cm 2
. Calculate the change in dimensions of the shell and the maximum intensity of shear stress induced. Given E=200GPa and Poisson's ratio =0.3.
A. The change in dimensions of the cylindrical shell can be calculated using the formula for longitudinal strain and Poisson's ratio. The maximum intensity of shear stress induced can be determined using the formula for the hoop stress in a cylindrical shell.
To calculate the change in dimensions of the cylindrical shell, we can use the formula for longitudinal strain:
ε = ΔL / L
where ε is the longitudinal strain, ΔL is the change in length, and L is the original length of the shell. Given that the shell is 3 m long and subjected to an internal pressure of 150 N/cm^2, we can calculate the change in length as follows:
ΔL = (P * L) / (E * t)
where P is the internal pressure, E is the Young's modulus, and t is the thickness of the shell. Substituting the values, we have:
ΔL = (150 N/cm^2 * 300 cm) / (200 GPa * 10 mm)
Next, we can calculate the maximum intensity of shear stress induced using the formula for hoop stress:
σ_hoop = (P * r) / (2t)
where σ_hoop is the hoop stress, P is the internal pressure, r is the radius of the shell (which is half the diameter), and t is the thickness of the shell. Substituting the values, we have:
σ_hoop = (150 N/cm^2 * 50 cm) / (2 * 10 mm)
By calculating these expressions, we can determine the change in dimensions of the shell and the maximum intensity of shear stress induced.
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The chemical equation below shows the photosynthesis reaction.
6CO2 + 6H2O → C6H12O6 + 6O2
A reaction uses 528 g of CO2. How many grams of water are used in this reaction?
Answer:
12
Explanation:
The activation energy (E*) for 2N2O ---> 2N2 + O2 is 250 KJ. If the k for this reaction is 0.380/M at 1001oK, what will k be at 298oK? What will the half-life be at both temperatures?
Answer:
Explanation:
GIven that:
The activation energy = 250 kJ
k₁ = 0.380 /M
k₂ = ???
Initial temperature \(T_1 =\) 1001 K
Final temperature \(T_2 =\) 298 K
Applying the equation of Arrhenius theory.
\(In \dfrac{k_2}{k_1 }= \dfrac{Ea}{R}( \dfrac{1}{T_1 }- \dfrac{1}{T_2})\)
where ;
R gas constant = 8.314 J/K/mol
\(In \dfrac{k_2}{0.380 }= \dfrac{250 * 10^3}{8,314}( \dfrac{1}{1001 }- \dfrac{1}{298})\)
\(In \dfrac{k_2}{0.380 }= -70.8655\)
\(\dfrac{k_2}{0.380 }= e^{-70.8655}\)
\(\dfrac{k_2}{0.380 }= 1.67303256 \times 10^{-31}\)
\({k_2}= 1.67303256 \times 10^{-31} \times {0.380 }\)
\({k_2}= 6.3575 \times 10^{-32}\) /M .sec
Half life:
At 1001 K.
\(t_{1/2} = \dfrac{In_2}{k_1}\)
\(t_{1/2} = \dfrac{0.693}{0.38}\)
\(t_{1/2} =\) 1.82368 secc
At 298 K:
\(t_{1/2} = \dfrac{0.693}{6.3575 \times 10^{-32}}\)
\(t_{1/2} =1.09 \times 10^{31} \ sec\)
PLEASE ANSWER!! DUE TONIGHT!! 10 POINTS!!
Find the density of a cube (to the nearest tenth) with a side of 4 cm. and a mass of 1235 grams. (You do not need to include units in your answer.)
Answer:
19.3
Explanation:
V=4^3 a^3, to find volume with sides
p= 1235/64, Mass/ Volume= Density
A 4.5-cm-diameter, 0.50-mm-thick spherical plastic shell holds carbon dioxide at 2.0 atm pressure and 25∘C. CO2 molecules diffuse out of the shell into the surrounding air, where the carbon dioxide concentration is essentially zero. The diffusion coefficient of carbon dioxide in the plastic is 2.5×10−12 m2/s What is the diffusion rate in molecules/s of carbon dioxide out of the shell? Express your answer in molecules per second. Part B If the rate from part A is maintained, how long in hours will it take for the carbon dioxide pressure to decrease to 1.0 atm ? The actual rate slows with time as the concentration difference decreases, but assuming a constant rate gives a reasonable estimate of how long the shell will contain the carbon dioxide. Express your answer in hours.
The diffusion rate of carbon dioxide out of the shell can be calculated using Fick's first law of diffusion, which states that the diffusion rate is proportional to the diffusion coefficient, the surface area, and the concentration difference.
First, we need to calculate the surface area of the shell:
The diameter of the shell is given as 4.5 cm, so the radius is half of that, which is 2.25 cm.
The surface area of a sphere is given by the formula A = 4πr^2.
Plugging in the radius, we get A = 4π(2.25 cm)^2 = 63.59 cm^2.
Next, we need to calculate the concentration difference:
The carbon dioxide concentration inside the shell is given as 2.0 atm, while the concentration outside the shell is essentially zero. The concentration difference is therefore 2.0 atm - 0 atm = 2.0 atm.
Now we can calculate the diffusion rate using the formula diffusion rate = diffusion coefficient * surface area * concentration difference. Plugging in the given values, we get diffusion rate = (2.5×10^(-12) m^2/s) * (63.59 cm^2) * (2.0 atm) = 3.18×10^(-9) cm^3·atm/s.
To convert this to molecules per second, we need to use Avogadro's number, which is 6.022×10^23 molecules/mol. Since carbon dioxide has a molar mass of approximately 44 g/mol, we can convert the diffusion rate to molecules per second by multiplying it by Avogadro's number and dividing by the molar mass of carbon dioxide. The molar mass of carbon dioxide is 44 g/mol = 44000 mg/mol.
diffusion rate (in molecules/s) = (3.18×10^(-9) cm^3·atm/s) * (6.022×10^23 molecules/mol) / (44000 mg/mol) = 4.34×10^14 molecules/s.
So, the diffusion rate of carbon dioxide out of the shell is 4.34×10^14 molecules/s.
For Part B, we can use the diffusion rate from Part A to calculate the time it takes for the carbon dioxide pressure to decrease to 1.0 atm.
The initial pressure is 2.0 atm and the final pressure is 1.0 atm.
Since the rate is constant, we can use the formula time = (final pressure - initial pressure) / diffusion rate.
Plugging in the values, we get time = (1.0 atm - 2.0 atm) / (4.34×10^14 molecules/s) = -2.3×10^(-15) s.
To convert this to hours, we divide by 3600 s/hour and take the absolute value to get time = |(-2.3×10^(-15) s) / (3600 s/hour)| = 6.4×10^(-19) hours.
So, it will take approximately 6.4×10^(-19) hours for the carbon dioxide pressure to decrease to 1.0 atm, assuming a constant diffusion rate.
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Your friend has just started a mining company and has asked you to help and talk to his newly recruited staff about identification of rocks and minerals
Prepare a presentation (not more than 200 words) to be delivered to the staff about rocks and minerals and how they can be identified.
Answer:
Good day everyone, I am here to talk to you about rocks and minerals and how to identify them.
First, let's define what rocks and minerals are. Rocks are made up of two or more minerals and can be classified into three main types: igneous, sedimentary, and metamorphic. Minerals, on the other hand, are naturally occurring inorganic substances with a definite chemical composition and crystal structure.
Now, when it comes to identifying rocks and minerals, there are a few key things to look out for. One is the color - minerals can come in a wide range of colors, and certain colors can indicate specific types of minerals. Another factor to consider is the texture - does the rock feel smooth or rough, and are there any visible grains or crystals? Additionally, the hardness of a mineral can be a helpful clue, as can its reaction to acid or other chemicals.
There are also various tools and techniques that can be used to aid in the identification process, such as a magnifying glass, streak test, and acid tests. It's important to use caution when handling certain minerals, as some can be toxic or contain harmful substances.
If 2.22g of NaCl was recovered after the reaction of 0.050L of hydrochloric acid and 0.033L of sodium hydroxide. What was the molarity of the base used in this experiment?
The molarity of the base used in the experiment, which was determined based on the recovered NaCl and the volumes of hydrochloric acid and sodium hydroxide, was approximately 1.15 M.
To determine the molarity of the base used in the experiment, we need to use the stoichiometry of the balanced chemical equation and the given data.
The balanced chemical equation for the reaction between hydrochloric acid (HCl) and sodium hydroxide (NaOH) is:
HCl + NaOH → NaCl + H2O
First, we need to find the number of moles of NaCl produced. We can do this by using the given mass of NaCl (2.22 g) and its molar mass (58.44 g/mol):
moles of NaCl = mass of NaCl / molar mass of NaCl
moles of NaCl = 2.22 g / 58.44 g/mol
moles of NaCl = 0.038 moles
Next, we can use the stoichiometry of the balanced equation to determine the number of moles of NaOH that reacted. Since the mole ratio between NaCl and NaOH is 1:1, the number of moles of NaOH is also 0.038 moles.
Now, we can calculate the molarity of the base (sodium hydroxide) using the given volume of sodium hydroxide solution (0.033 L):
Molarity of NaOH = moles of NaOH / volume of NaOH solution
Molarity of NaOH = 0.038 moles / 0.033 L
Molarity of NaOH ≈ 1.15 M
Therefore, the molarity of the base used in the experiment is approximately 1.15 M.
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Pls help me I don’t know what to dooooo
What is the final, balanced equation that is formed by combining these two half reactions?
CO
Cu-
> Cu2+
+ 2e-
NO3 + 2e + 2H
>NO2+H20
o Cu2+ + NO3 + + 4e + 2H+ -> Cu + NO3 + H20
o Cu + NO3 + 2H*
>Cu2+ + NO3 + H20
o 2Cu + NO3 + 2H+ —>2Cu?* + NO3 + H20
O Cu+ NO3 + 2H+—
+ NO2 + 2H20
Answer: Balanced equation that is formed by combining these two half reactions is \(Cu + NO^{-}_{3} + 2H^{+} \rightarrow Cu^{2+} + NO^{-}_{2} + H_{2}O\).
Explanation:
A chemical equation which contains same number of atoms on both reactant and product side is called a balanced chemical equation.
For example, \(Cu \rightarrow Cu^{2+} + 2e^{-}\)
\(NO^{-}_{3} + 2e^{-} + 2H^{+} \rightarrow NO^{-}_{2} + H_{2}O\)
On cancelling the common species from both these half-reactions, the complete balanced equation will be as follows.
\(Cu + NO^{-}_{3} + 2H^{+} \rightarrow Cu^{2+} + NO^{-}_{2} + H_{2}O\)
Thus, we can conclude that balanced equation that is formed by combining these two half reactions is \(Cu + NO^{-}_{3} + 2H^{+} \rightarrow Cu^{2+} + NO^{-}_{2} + H_{2}O\).
What is the molar concentration a a 12 % sodium chloride solution (MW 58.5)
The molar concentration of a 12% sodium chloride solution is approximately 2.05 M.
To determine the molar concentration of a 12% sodium chloride solution, we need to convert the given percentage concentration into molarity.
First, we need to understand that the percentage concentration refers to the mass of the solute (sodium chloride) relative to the total mass of the solution.
In this case, a 12% sodium chloride solution means that there are 12 grams of sodium chloride in 100 grams of the solution.
To convert this into molar concentration, we need to consider the molar mass of sodium chloride, which is 58.5 g/mol.
We can start by calculating the number of moles of sodium chloride in 12 grams:
Moles of sodium chloride = mass of sodium chloride / molar mass of sodium chloride
Moles of sodium chloride = 12 g / 58.5 g/mol = 0.205 moles
Next, we calculate the volume of the solution in liters using the density of the solution. Since the density is not provided, we assume a density of 1 g/mL for simplicity:
Volume of solution = mass of solution / density
Volume of solution = 100 g / 1 g/mL = 100 mL = 0.1 L
Finally, we calculate the molar concentration (Molarity) by dividing the number of moles by the volume in liters:
Molar concentration = moles of solute / volume of solution
Molar concentration = 0.205 moles / 0.1 L = 2.05 M
Therefore, the molar concentration of a 12% sodium chloride solution is approximately 2.05 M.
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1- Draw the potential energy for system of two atoms versus the internuclear separation distance for these two atoms U(r) 2- Bohr's model of the hydrogen atom
1- U(r) has a repulsive region at small r due to electron-electron repulsion, followed by an attractive region at intermediate r due to electron-nucleus attraction, and a negligible potential at large r.
The potential energy, U(r), for a system of two atoms can be represented graphically as a function of the internuclear separation distance, r. At small values of r, the atoms experience repulsion due to the electron-electron interactions, resulting in a steep increase in potential energy. This repulsive region prevents the atoms from getting too close to each other.
As the internuclear separation distance increases, the attractive force between the electrons and the nuclei becomes dominant, leading to a decrease in potential energy. This attractive region is typically characterized by a shallow potential well. At intermediate values of r, the potential energy reaches a minimum, indicating a stable configuration where the atoms are bonded.
2- Bohr's model describes the hydrogen atom as a nucleus with an electron orbiting it in quantized energy levels. Electrons can transition between levels by absorbing/emitting photons with energy given by ΔE = hf. The model has limitations but introduced the concept of discrete energy states in atoms.
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SENSORCAINE/EPINEPHRINE is an injectable solution that contains 0.25% w/v bupivacaine HCl and 1:200,000 w/v epinephrine. How much epinephrine (mg) would be contained in a 50-mL vial of this solution? Please round to the nearest hundredth. Please show the work up steps. (answer is 0.25 mg)
A 50-mL vial of SENSORCAINE/EPINEPHRINE solution contains approximately 0.25 mg of epinephrine. This is calculated based on the concentration of 1:200,000 w/v in the solution.
To determine the amount of epinephrine (mg) in a 50-mL vial of SENSORCAINE/EPINEPHRINE solution, we need to consider the concentration of epinephrine in the solution. The solution contains 1:200,000 w/v epinephrine, which means that for every 1 part of epinephrine, there are 200,000 parts of the solution.
To calculate the amount of epinephrine in the solution, we can use the following formula:
Amount of epinephrine = Total volume of solution (mL) × Concentration of epinephrine (mg/mL)
In this case, the total volume of the solution is 50 mL, and the concentration of epinephrine is 1:200,000 w/v. To convert the concentration to mg/mL, we divide 1 mg by 200,000 mL:
Concentration of epinephrine (mg/mL) = 1 mg / 200,000 mL = 0.000005 mg/mL
Finally, we can calculate the amount of epinephrine in the 50-mL vial:
Amount of epinephrine = 50 mL × 0.000005 mg/mL = 0.00025 mg
Rounding to the nearest hundredth, the amount of epinephrine in a 50-mL vial of SENSORCAINE/EPINEPHRINE solution is 0.25 mg.
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name two enzyme used to make alcohol
Answer:
here is your answer
Cellulase and proteases are two enzymes are used for making alcohol
hope it helps you
Explanation:
pwlss giv meh brainless
Choose ALL of the statements below that are stated as a hypothesis.
The brighter the color of an orange, the juicler the fruit
The faster a river flows, the greater the erosion.
Most apples are red, but some are yellow.
Baking powder is used in biscuits.
Brass contains copper and zinc.
Answer:
the first 2, the. rest are facts
Can someone please correct these answers and tell me what I’m doing wrong?! Much appreciated!!!
match the oxygen administration route to the corresponding definition.
Here are the oxygen administration routes matched with their corresponding definitions:1. Nasal cannula: Oxygen delivered through two prongs placed in the nostrils.
Simple face mask: Oxygen delivered through a mask that covers the nose and mouth.3. Partial rebreather mask: Oxygen delivered through a mask with a reservoir bag attached.4. Non-rebreather mask: Oxygen delivered through a mask with a one-way valve that prevents exhaled air from entering the bag.5. Venturi mask: Oxygen delivered through a mask with a valve that allows for precise oxygen concentration.
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What best describes how the testing of the initial version and the testing of the beta version fit into the four stages of the process of technological design
Answer:
C. The initial version is tested during the third stage to determine what needs to be improved, and the beta version is tested during the fourth stage to ensure that criteria are met.
Explanation:
Edge 2021
The Testing of the initial version is carried out in the third stage to determine what needs to be improved, while the testing of the beta version is carried out during the fourth stage to ensure that all necessary criteria are met.
The process of technological design involves several distinctive processes which can be broken down into four stages.
The four stages involved in the process of technological design are :
Identify a need : during this process the engineer identifies a problem that needs to be resolved design a solution : an initial design is created to provide a solution to the problem identified in stage 1Implement the solution : The design is tested and implemented if successfulevaluate the solution : In this stage the result from the solution ( beta version ) is subjected to ensure that all criteria are methence the testing of the initial version is to determine what needs improvement while the testing of the beta version is to ensure all criteria are met
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PLEASE ANSWER 30 POINTS!!!!!
How many grams of NH3 form when 22g H2 react completely?
3H2 + N2 ---> 2NH3
H2: 2 g/mol NH3: 17 g/mol
22g H2 ----> gNH3
Answer:
122 grams of NH3 will be produced when 22 grams of H2 react completely.
Explanation:
First, we need to calculate the number of moles of H2 present in 22g of the substance:
Number of moles of H2 = Mass of H2 / Molar mass of H2
Number of moles of H2 = 22g / 2 g/mol = 11 mol
According to the balanced chemical equation, the reaction between H2 and N2 produces NH3 in a 3:2 ratio. This means that for every 3 moles of H2, 2 moles of NH3 are produced. We can use this ratio to calculate the number of moles of NH3 produced:
Number of moles of NH3 = (2/3) x Number of moles of H2
Number of moles of NH3 = (2/3) x 11 mol = 22/3 mol
Finally, we can use the molar mass of NH3 to convert the number of moles of NH3 to grams:
Mass of NH3 = Number of moles of NH3 x Molar mass of NH3
Mass of NH3 = (22/3) mol x 17 g/mol = 122 g (rounded to three significant figures)
What is the proper safety response to a trash-can fire in a lab?
A throw chemicals on the fire
B leave the room to seek help
C watch the fire to see if it spreads
D use the appropriate fire extinguisher
Answer:
D) Use the appropriate fire extinguisher
Explanation:
stay safe my friend :)
Find the Valence Electrons. From top to bottom. List them in order for 5 number code.
Answer:
1.2.6.4.8, in order top to bottom
Explanation:
Answer:
if you want to order them from top to bottom then the order would be 1,2,6,4,8 I think.
Explanation: