Give the negative of the following vectors: A = 6.0 units SE and B = 7.5 units 67 0
N of W.

Answer:

OptionD

The acceleration of the horse is 0.72m/s2

Explanation:

We can use the formula

\(v^2=u^2 +2as\)

we are looking for the acceleration, which is a. To find this, we can make a the  subject of the formula as shown

\(a = \frac{u^2 +v^2}{2s}\)

Where a = acceleration of the horse

s = distance covered by the horse = 100m

v = final velocity of the horse = 12m/s

u = initial velocity of the horse = 0 m/s (this is because it starts from rest)

\(a= \frac{0+12^2}{2 \times 100}=0.72m/s^2\)

The acceleration of the horse is 0.72m/s2

Answer:

d is the awnser

Explanation:

MABY?!??

Answer:

Avoid using tweezers to remove the stinger, since squeezing it may release more venom. Wash the area of the bite with soap and water. Place a cold compress or ice pack on the area for about 10 minutes at a time to help reduce pain and swelling

Explanation:

so basically B, i hope this helps and its not too late!

First, remove the stinger with mild force and wash the area thoroughly with soaps. Apply cold compress or ice packs to avoid swellings. Hence, option B is correct.

Histamines are chemical substances in our body generating allergic action on skin. When some allergens or stimuli are exposed with our skin, histamine is produced.

Similarly if an insect with stinger bite on our skin, histamine is produced and allergic reactions occurs in our body. The bitten area has to be washed for minutes with soap. If any stinger persist on skin remove it.

Cold compress or ice packs are very helpful if the skin starts to swell. If any pain occurs, lower doses of pain killers can be taken. If necessary antihistamines have to be taken.

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The vector with a magnitude of 5 and in the direction of the vector 4i - 3j + k is approximately (20/√26)i + (-15/√26)j + (5/√26)k.

The given vector can be normalized before being multiplied by the desired magnitude. This is how to locate the vector:

The vector that has been provided should be normalized by dividing each of its components by its magnitude. The Pythagorean theorem can be used to determine the magnitude of the vector 4i - 3j + k:

Magnitude = √(4² + (-3)² + 1²) = √(16 + 9 + 1) = √26

Normalize the vector by dividing each component by the magnitude:

Normalized vector = (4/√26)i + (-3/√26)j + (1/√26)k

Multiply the normalized vector by the desired magnitude:

To obtain a vector with a magnitude of 5, multiply each component of the normalized vector by 5:

Desired vector = 5 * ((4/√26)i + (-3/√26)j + (1/√26)k)

Simplifying the expression gives:

Desired vector ≈ (20/√26)i + (-15/√26)j + (5/√26)k

So, the vector with a magnitude of 5 and in the direction of the vector 4i - 3j + k is approximately (20/√26)i + (-15/√26)j + (5/√26)k.

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Answer: Rectangular frames are easy to make but can get pulled out of shape. so if the sides are still attached , then the figure formed is parallelogram. useing the given measurement use the formula of a parallelogram.

formula : A = BASE X HEIGHT

Explanation:

Answer:

It will travel 350 meters each second.

Explanation:

The unit rate, 350 m/s, tells us that the jet will travel 350 meters per every second elapsed.

Answer:

5.83 seconds

Explanation:

60 seconds in 1 minute

350 meters per second

350/60

=5.83

The force applied to small piston = 2.2 x 10³ N

Given

a radius of 5 cm and 15 cm

weight 20000 N

Required

Force applied

Solution

Pascal Law :

F₁/A₁=F₂/A₂

A₁ = π.5²

A₂ = π.15²

F₁/ π.5² cm² = 20000/π.15² cm²

F₁ = 2222.22 N⇒2.2 x 10³ N

Explanation:

Memory loss in retrograde amnesia has long been held to be larger for recent periods than for remote periods, a pattern usually referred to as the Ribot gradient. One explanation for this gradient is consolidation of long-term memories. Several computational models of such a process have shown how consolidation can explain characteristics of amnesia, but they have not elucidated how consolidation must be envisaged. Here findings are reviewed that shed light on how consolidation may be implemented in the brain. Moreover, consolidation is contrasted with alternative theories of the Ribot gradient. Consolidation theory, multiple trace theory, and semantization can all handle some findings well but not others.

Sound waves are a type of mechanical wave that propagate through a medium, typically air but also other materials such as water or solids.

Frequency: the frequency of a sound wave refers to the number of cycles or vibrations it completes per second and is measured in Hertz (Hz).

Amplitude: the amplitude of a sound wave refers to the maximum displacement or intensity of the wave from its equilibrium position. It represents the loudness or volume of the sound, with larger amplitudes corresponding to louder sounds and smaller amplitudes corresponding to softer sounds.

Wavelength: the wavelength of a sound wave is the distance between two consecutive points in the wave that are in phase, such as from one peak to the next or one trough to the next. It is inversely related to the frequency of the wave.

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K+ ions are propelled by a driving force (df) of +15 mV, and the ion movement is inwards directed.

The external effort necessary to move a charge in an electromagnetic field from one position to another is called as an electric potential difference, or voltage. A test charge with a result of +1 will experience an electromagnetic potential difference, which is a shift in electric potential.

At equilibrium, the bottom of the cell ought to be negative in relation to the outside because K+ ions have an electromotive force of Ek = -78 mV.

Since Vm = -93 mV

df = Ek - Vm

= -78 mV - (-93 mV)

= +15 mV.

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Answer:

3.1 m/s

Explanation:

The total distance she has to run is the addition of the three lengths:

47 + 63 + 76 = 186 meters.

She needs to cover it one minute (60 seconds). Therefore her speed must be:

186 m / 60 s = 3.1 m/s

At approximately 2.81 seconds the cars are at the same point. aA(t) is a linear function and xB(t) is a parabolic function.

Functions aA(t) and xB(t) describes the motion of two cars and both functions give the distance of each car from the starting point as a function of time, t.

aA(t) is a linear function and the components of the functions are constant velocity (p) and acceleration (q).

xB(t) is a parabolic function with components constant acceleration (r) and a component for constant jrk (s).

To find the time when the two cars are at the same location, we must first make the two distance expressions equal and then solve for t.

That is pt + qt² = rt² - st³

Now we have to solve this for t, we get

t = (-p + (p² + 4qr)^1/2) / (2q)

Now add the values for p,q,r,s to solve the equation

t = (-2.6 + (2.6² + 4 × 1.2 × 2.8)^0.5) / (2 × 1.2) = approximately 2.81 seconds.

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The formula for calculating density is expressed as

Density = mass/volume

From the information given,

mass = 16.5 g

volume = ?

Recall, the formula for calculating the volume of a cylinder is expressed as

volume = pi x radius^2 x height

diameter = 10.6mm

Recall, 1 cm = 10 mm

10.6mm = 10.6/10 = 1.06 cm

diameter = 1.06 cm

radius = diameter/2 = 1.06/2 = 0.53 cm

length = height = 21.8 mm

Converting 21.8 mm to cm, we have

length = height = 21.8/10 = 2.18 cm

Thus,

volume of cylinder = 3.14 x 0.53^2 x 2.18 = 1.92 cm^3

Thus,

Density = 16.5/1.92

Density = 8.6 g/cm^3

Answer:

\(d_{i}=465 cm=4.65 m\)  

Explanation:

Using the thin lens equation, we have:

\(\frac{1}{f}=\frac{1}{d_{o}}+\frac{1}{d_{i}}\)

Where:

f is the focal length

d(o) is the distance of the object

d(i) is the distance of the image

\(\frac{1}{15}=\frac{1}{15.5}+\frac{1}{d_{i}}\)

\(\frac{1}{15}-\frac{1}{15.5}=\frac{1}{d_{i}}\)    

\(d_{i}=465 cm=4.65 m\)          

Therefore, the screen is at 465 cm.

I hope it helps you!

The light waves reflecting off a red stop sign would be longer than the light waves reflecting off a violet-colored jacket. This is because red light has a longer wavelength than violet light.

Light waves, like all waves, are characterized by their wavelength. The wavelength of a wave determines its color, with shorter wavelengths appearing as blue and violet, and longer wavelengths appearing as red and orange.

Because the wavelength of red light is longer than the wavelength of violet light, the light waves reflecting off the red stop sign would be longer than the light waves reflecting off the violet-colored jacket.

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Answer:

3.8809144

Since we are looking for volume, we will look at the coin as a cylinder. The volume of a cylinder is pi x r^2 xh. Assuming pi is 3.14 the equation would go 3.14x1.1236x1.1. Which would give you the answer,

Answer:

\(a)-3346.8\;N \\ b)-4937.04\;N-m\)

Explanation:

a) - In Free-body diagram :

At point D, the free body diagram of a man :

\(D = Fn\\Fn=T+mg\\put\;values\;in\;it\\ .\;\;\;\;=300+(80)(9.81)=1084.8\;N\)

\(Mg=200\times9.81=1962\;N\)

\(\sum Fx=0\; where\; Ax=0\)

\(\sum Fy=0\; where\; Ay-Mg-Fn-T=0\)

Then, put the value in the equation.

\(Ay=3346.8\;N\)

b)-

\(Ma=Mg(AE)+Fn(AD)+T=4937.04\;N-m\)

The basic kinematic equations for horizontal and vertical motion are as follows:

s = v₀t + ¹/₂at²

Horizontal motion is:

x = v₀ₓt + ¹/₂aₓt²

x = v₀ₓt

x = v₀ cosαt

Because there is no air resistance: x = v₀ cosθt

Vertical motion is:

y = v₀\(__y\)t + ¹/₂a\(__y\)t²

y = v₀ sinαt - ¹/₂gt²

Solve both for the velocity trigonometric function term as follows:

y = v₀ sinαt - ¹/₂gt²

v₀sinαt = ¹/₂gt² + y

v₀sinα = ¹/₂gt² + y/t

and

x = v₀ cosαt

v₀cosα = x/t

Now divide these two equations and we get

v₀sinα/v₀cosα = tanα \(=\frac{1/2gt + \frac{y}{t} }{\frac{x}{t} }\)

tan α \(= \frac{1/2gt + \frac{y}{t} }{\frac{x}{t} } = \frac{gt^2}{2x} + \frac{y}{x}\)

tan α \(= \frac{gt^2}{2x} + \frac{y}{x}\)

Enter a value, x is the distance between the boarding 35.5 m, and y is the difference between the launch height and the drop point. The launch height is 15.5 m and the landing height is 11.0 m, so y = -4.5 m. Finally, we are told the projectile travel time is 2.2 s.

tan α \(= \frac{gt^2}{2x} + \frac{y}{x}\)

tan α \(= \frac{(9.8)(2.2)^2}{2(35.5)} + \frac{-4.5}{35.5}\)

tan α \(= 0.668 - 0.126\)

tan α \(= 0.542\)

     α = tan⁻¹ 0.542

     α = 28.4°

For the second launch, y₂ is +7.0 m launch altitude is still 15.5 m, but the deployment altitude is now 22.5 m, and x is still 35.5 m. The angle remains 28.4°. This time we don't know the flight time or initial velocity we are asked to find. Using horizontal distances, we can solve for time.

x = v₀.cosα.t

t² = x/v₀.cosα

Now do it for y₂:

          y₂ \(= v_0sin(\alpha) t - 1/2gt^2\)

          y₂ \(= v_0sin(\alpha) (\frac{x}{v_0cos(\alpha)} ) - 1/2g (\frac{x}{v_0cos(\alpha)} )^2\)

           y₂ \(= x tan (\alpha ) - \frac{gx^2}{2v_0cos(\alpha)^2}\)

 \(\frac{gx^2}{2v_0cos(\alpha)^2} = x tan (\alpha ) - y_2\)

We need to solve v₀:

   \(\frac{gx^2}{2v_0cos(\alpha)^2} =\frac{1}{ x tan (\alpha ) - y_2}\)

2v₀cos (α)² \(= \frac{gx}{ x tan (\alpha ) - y_2}\)

             v₀² \(= (\frac{1}{2cos(\alpha)^2} ) \frac{gx}{ x tan (\alpha ) - y_2}\)

            v₀² \(= (\frac{x^2}{cos(\alpha)^2} ) \frac{g/2}{ x tan (\alpha ) - y_2}\)

            v₀² \(= (\frac{x}{cos(\alpha)^2} ) \sqrt{ \frac{g/2}{ x tan (\alpha ) - y_2}}\)

Now we can enter values:

v₀² \(= (\frac{x}{cos(\alpha)^2} ) \sqrt{ \frac{g/2}{ x tan (\alpha ) - y_2}}\)

v₀² \(= (\frac{35.5}{cos(28.4^0)} ) \sqrt{ \frac{9.8/2}{ 35.5 tan (28.4^0) - 7.0}}\)

v₀² = 40.386 \(\sqrt{\frac{4.9}{12.17} }\)

v₀² = 40.386 (0.634)

v₀² = 25.62 m/s

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Calculate the horizontal component of the velocity. The horizontal component of the velocity is given by:

v_x = v * cos(theta)

where v is the original speed of the arrow and theta is the angle of projection.In this case, v = 2 m/s and theta is unknown. Solving for theta, we get:

theta = arccos(v_x / v)

theta = arccos(2 / 2) = 45 degrees

Calculate the vertical component of the velocity. The vertical component of the velocity is given by:

v_y = v * sin(theta)

In this case, v = 2 m/s and theta = 45 degrees. Solving for v_y, we get:

v_y = 2 * sin(45 degrees) = 1.414 m/s

Calculate the time of flight. The time of flight is given by:

t = 2 * v_y / g

In this case, v_y = 1.414 m/s and g = 10 m/s^2. Solving for t, we get:

t = 2 * 1.414 / 10 = 0.283 seconds

Calculate the height of the arrow. The height of the arrow is given by:

y = v_y * t - 0.5 * g * t^2

In this case, v_y = 1.414 m/s, t = 0.283 seconds, and g = 10 m/s^2. Solving for y, we get:

y = 1.414 * 0.283 - 0.5 * 10 * 0.283^2 = 0.303 meters

Therefore, the angle of projection is 45 degrees and the height of the arrow is 0.303 meters.

Answer:

8a = 20.   8b=4

Explanation:

Distance is total amount the object moved. It went from 10, to -2 which is 12 meters away, then to 6 which is 8, adding 8 and 12 is 20 so that is the distance. Displacement is how far it is relative to the starting position, so 10 and 6 are 4 meters away, therefore displacement is 4.

Hope I helped : )

Answer:

A. size and mass

Explanation:

The energy efficiency of the car is approximately 16.7%.

The energy efficiency of a car is the ratio of the useful work output (in this case, the kinetic energy of the car) to the total energy input (in this case, the energy released by burning the gasoline). The equation for energy efficiency is:

The useful work output can be calculated as the kinetic energy of the car using the equation:

where m is the mass of the car and v is its velocity.

Substituting the given values:

The total energy input is the energy released by burning 0.1 L of gasoline, which is:

Substituting these values into the equation for efficiency:

Therefore, the energy efficiency of the car is approximately 16.7%.

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88 generations have passed.

A generation is a collective term for all individuals who were born and are still alive at around the same period. The average time frame, commonly regarded to be between 20 and 30 years, during which children are born, grow up, become adults, and start having children is another way to put it. It is a structural term used to describe the parent-child relationship in kinship terminology.

In social science, the terms "generation" and "cohort" are sometimes used interchangeably to refer to "individuals within a defined population who experience the same key events over a certain period of time." These birth cohorts, usually referred to as "social generations," are frequently employed in popular culture and have served as the foundation for sociological study.

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First, we will find the area of the base of the stilts given by:

A = l^2 =  0.05 m * 0.05 m

A = 0.0025 m^2

The pressure applied to the ground is given by: P = F/A

P = 1029.05 N / 0.0025 m^2

P = 411620 Pa

Therefore, the pressure applied to the ground by a 105 kg man standing on square stilts that measure 0.05 m on each edge is 411620 Pa.

Yes, pressure does depend on the surface area. Pressure is defined as the force per unit area, which means that the pressure exerted on a surface is directly proportional to the force applied and inversely proportional to the area over which the force is distributed.

The force of gravity is a fundamental force that can give rise to pressure differentials in fluids and gases. The pressure within a fluid or gas is related to the weight of the fluid or gas above a point, which is related to the force of gravity acting on the fluid or gas.

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Volume of a cylinder = π r^2 h

Where:

r = radius = diameter /2 = 25/2 = 12.5 km = 12,500 m

h = height = 15 m

Replacing:

V = π (12,500)^2 (15) = 7,363,107,782 m3

Approximate volume = 7,000,000,000 = 7 x 10^9 m3 (a)

Answer:slows it down

Explanation:when something drops it slow down

Answer: increase

Explanation: Air resistance is increases with velocity. When object fall , the velocity will increase. so, resistance will increase.

The distance the bus will go, if it is travelling at a rate of 50 km/hr for 3.8 hours is 190 kilometers (Option A)

We know that speed is defined as distance travelled per unit time i.e

Speed = Distance travelled / time

Cross multiply

Distance travelled = Speed × time

With the above formula, we can calculate the distance the bus will go. Details below:

Distance travelled = Speed × time

Distance travelled = 50 × 3.8

Distance travelled = 190 kilometers

Thus, we can conclude that the distance the bus will go is 190 kilometers (Option A)

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