HALP MEEEE

Alice, Maggie, Luna, and Zeinab were making necklaces for the school fair. Alice made 52 necklaces that are each 8.2 inches long. Maggie made 46 necklaces that are each 7.8 inches long. Luna made 21 necklaces that were each 7.7 inches long. And Zeinab made 31 necklaces that were each 8.7 inches long. They all used beads that were each 2 centimeters long. how much beads would the girls use to fit all of the necklaces they made?

Alice:_______
Maggie:_______
Luna:_______
Zeinab:_______

There are 95,040 different ways for the first five cars to go through the toll booth.

The first car can be chosen in 12 ways. After the first car has been chosen, the second car can be chosen in 11 ways. This process continues, so the third car can be chosen in 10 ways, the fourth car can be chosen in 9 ways, and the fifth car can be chosen in 8 ways.

So the total number of ways to choose the first five cars is as follows:

12 x 11 x 10 x 9 x 8 = 95,040

Therefore, there are 95,040 different ways for the first five cars to go through the toll booth.

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Answer:

18

Step-by-step explanation:

Given:

Triangle ABC is mapped onto triangle ADE.

Required:

The transformation that maps triangle ADE similar to triangle ABC.

Explanation:

A dilation process from A by a factor 3 maps triangle ABC onto triangle ADE.

In the dilation process, the transformed angle value remains constant.

Also,

Therefore above transformation makes triangle ABC similar to triangle ADE.

Answer:

Thus from the explanation given above, the above transformation makes triangle ABC similar to triangle ADE.

Answer:

Step-by-step explanation:

It's not that clear on my screen

Answer:

The answer would be -12, I'm not to sure what simplify means

None of the wind gusts (17, 22, 8, 13, 19, 36, and 14) fall below -0.5 or above 35.5, there are no outliers in this data set. Therefore, the correct answer is D) none.

To identify any outliers in the data set, we can use a common method called the 1.5 interquartile range (IQR) rule.

The IQR is a measure of statistical dispersion and represents the range between the first quartile (Q1) and the third quartile (Q3) of a dataset. According to the 1.5 IQR rule, any value below Q1 - 1.5 × IQR or above Q3 + 1.5 × IQR can be considered an outlier.

To determine if there are any outliers in the given data set of wind gusts (17, 22, 8, 13, 19, 36, and 14), let's follow these steps:

Sort the data set in ascending order: 8, 13, 14, 17, 19, 22, 36.

Calculate the first quartile (Q1) and the third quartile (Q3).

Q1: The median of the lower half of the data set (8, 13, 14) is 13.

Q3: The median of the upper half of the data set (19, 22, 36) is 22.

Calculate the interquartile range (IQR).

IQR = Q3 - Q1 = 22 - 13 = 9.

Step 4: Identify any outliers using the 1.5 IQR rule.

Values below Q1 - 1.5 × IQR = 13 - 1.5 × 9 = 13 - 13.5 = -0.5.

Values above Q3 + 1.5 × IQR = 22 + 1.5 × 9 = 22 + 13.5 = 35.5.

Since none of the wind gusts (17, 22, 8, 13, 19, 36, and 14) fall below -0.5 or above 35.5, there are no outliers in this data set.

Therefore, the correct answer is D) none.

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-Write a ratio

tan 0 = opposite side / adjacent side

Substitution

tan 40 = 18 / x

Solve for x

x = 18 / tan 40

x = 18 / 0.839

Result

x = 21.45

Simplified form of fourth root of 2401x¹²y¹⁶  is  7x³y⁴

Equation is the defined as mathematical statements that have a minimum of two terms containing variables or numbers is equal.

Given,

⁴√2401 x¹² y¹⁶=⁴√7*7*7*7 (x³)⁴(y⁴)⁴

                       =⁴√(7)⁴ (x³)⁴(y⁴)⁴

                       =⁴√(7 x³y⁴)⁴

                       =  7 x³y⁴

Therefore, Simplified form  fourth root of 2401x¹²y¹⁶  is  7x³y⁴.

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In order to determine 1/11 as a decimal you need to divide 1 by 11. This would equal 0.0909090909090909. Rounding this number to three decimal places would equal 0.091.

The given expression is

Remember that i = -1, so.

We know by definition that all powers with even exponents give a positive number. So,

Answer:cube root 381.7

Then half it too find the radius.

Step-by-step explanation:

Positive curve graphs will be upward-sloping.

Negative curve graphs will be downward-sloping.

Both graphs in the first image attached below, show curves sloping upward from left to right. As with upward-sloping straight lines, we can say that generally the slope of the curve is positive. While the slope will differ at each point on the curve, it will always be positive.

In the graphs in the second image attached, both of the curves are downward sloping. Straight lines that are downward sloping have negative slopes; curves that are downward sloping also have negative slopes. The slopes change from point to point on a curve, but all of the slopes along these two curves will be negative.

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Straight lines that are downward sloping have negative slopes; curves that are downward sloping also have negative slopes. The slopes change from point to point on a curve, but all of the slopes along these two curves will be negative.

The system of the equation that has only one solution is \rm 5x-4y=8 and  3x+2y=8.

We have to determine;

Which system of equations has exactly one solution?

According to the question

A  system of linear equations can have one solution if there is a single point that makes every equation in the system true.  This means that there is one point that can satisfy all of the equations at the same time.

The system of equations has exactly one solution is;

\(\rm 5x-4y=8\\\\ 3x+2y=8\)

From equation 1

\(\rm 5x-4y=8\\\\ 5x = 8+4y \\\\x = \dfrac{8+4y}{5}\)

Substitute the value of x in equation 2

\(\rm3x+2y=8\\\\3(\dfrac{8+4y}{5})+2y=8\\\\\dfrac{24+12y}{5}+2y=8\\\\24+12y+10y=8\times5\\\\24 + 22y = 40\\\\22y = 40-24\\\\22y = 16\\\\y = \dfrac{16}{22}\\\\y = \dfrac{8}{11}\\\\\)

Substitute the value of b in equation 1,

\(\rm 3x+2y=8\\\\3x + 2\dfrac{8}{11}=8\\\\3x = 8 - \dfrac{16}{11}\\\\3x = \dfrac{88-6}{11}\\\\x = \dfrac{82}{33}\)

Hence, the system of equation that has only one solution is \rm 5x-4y=8 and  3x+2y=8.

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Answer:3.46 km

Step-by-step explanation:

Given

shape of hill \(y=-2(x-3)^2+6\)

at the bottom y=0 i.e.

\(0=-2(x-3)^2+6\\(x-3)^2=3\\x-3=\pm\sqrt{3}\\x=3\pm\sqrt{3}\)

width of the bottom

\(3+\sqrt{3}-[3-\sqrt{3}]=2\sqrt{3}\ km\ or\ 3.46\ km\)

Answer:

Top to bottom

1

30

9

45

Step-by-step explanation:

The car οvertakes twο buses οn its way tο the city center with the given time and distance.

On its jοurney tο the city centre, the autοmοbile wοuld never pass any buses if it mοved at the same pace as the bus. This is due tο the fact that if bοth the autοmοbile and the bus are mοving at the same speed, their separatiοn will remain cοnstant. Hence, withοut passing any buses, the autοmοbile wοuld arrive in the city centre at the same time as the bus.

Let us suppοse the distance = p.

The distance travelled by the bus in 60 minutes is d/60.

The distance cοvered by the bus in 35 minutes is:

d/60(35)

Fοr the first bus:

It leaves 60 minutes befοre car, thus the distance travelled is:

(d/60) x 60.

If the car οvertakes thus bus by an additiοnal distance x, then the distance travelled by car is:

d = (d/60) x 35 + (d/60) x 60 + x

d = (5/12)d + x

x = 7/12 d

Fοr the secοnd bus:

The bus wοuld have left the airpοrt 120 minutes befοre the car:

(d/60) x 120

The distance cοvered by car with additiοnal distance y is:

d = (d/60) x 35 + (d/60) x 60 + (7/12)d + y

d = (5/6)d + y

y = 1/6d

The car οvertakes the bus thus,

(7/12)d + (1/6)d = d

d = 12/5

Therefοre, the car οvertakes twο buses οn its way tο the city centre.

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Answer:

0.3 is the answer to your question

The fraction 30/100 simplifies to 3/10.

We have to simplify the fraction 30/100

we can reduce it by dividing both the numerator and the denominator by their greatest common divisor (GCD).

The greatest common divisor of 30 and 100 is 10.

By dividing both 30 and 100 by 10, we get:

30/100

= (30 ÷ 10) / (100 ÷ 10)

= 3/10

Therefore, the fraction 30/100 simplifies to 3/10.

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The length of the segment BE is 2 units.

A quadrilateral with parallel sides that are equal to one another and four equal vertices is known as a rectangle.

Given:

Quadrilateral ABCD is a rectangle.

BE=3x−7 and AC=8x−20.

E is the intersection point of the diagonals.

So,

AC/2 = BE

(8x−20)/2 = 3x−7

4x - 10 = 3x - 7

x = 3

So, BE = 2

Therefore, BE = 2 units.

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The area is 109.9 square centimeters.

For a segment of a circle of radius R, defined by an angle a, the area is:

A = (a/360°)*pi*R²

where pi= 3.14

Here we know that:

a = 56°

R = 15cm

Then the area is:

A = (56°/360°)*3.14*(15cm)²

A = 109.9 cm²

That is the area.

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Answer:x≥−5

Step-by-step explanation:

Answer:

(3x-4)(x+3) = 0

x = -3, 4/3

Step-by-step explanation:

3x^2 + 5x = 12

3x^2 + 5x - 12 = 0

(3x-4)(x+3) = 0

x = -3, 4/3

If the standard deviation of a set of data is 6, then the value of variance is 36

The formula for determining variance is variance = √Standard deviation

Variance of a set of data is equal to square of the standard deviation.

If the standard deviation of a set of data is 6 then we get variance by putting the value of standard deviation in the formula

variance = √Standard deviation

Take square root on both sides

Standard deviation² = 6²

Standard deviation= 36

Hence,  standard deviation of a set of data is 6, then the value of variance is 36

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In order to calculate the slope of a line that passes through the points (-2, 6) and (8, 4), we can use the formula:

Where (x1, y1) and (x2, y2) are the points coordinates. So we have:

So the slope of the line is -1/5.

Answer:

Hi help in what?

Step-by-step explanation: