have fun with the points just spam bruh tho ​

Answer:

C) SAS

Lines BC and CD are congruent, Angles 1 and 2 are congruent, and the triangles share a side. Thus, the triangles are congruent because of Side-Angle-Side.

Answer:

10

Step-by-step explanation:

4x+8+3x+12=90

x=10

this is the solution hope it's helpful

\(\mathfrak{\huge{\orange{\underline{\underline{AnSwEr:-}}}}}\)

Actually Welcome to the concept of area of sector.

Area of sector = theta/360° * πr^2

==> theta = 62°

hence, area = (62/360)* π*(15)^2

==> Area of sector = 121.67 cm^2

hence Area = 121.67 cm^2

Answer:

C) I only

Step-by-step explanation:

( -1, -2) and (0,4)

Slope:

m=(y2-y1)/(x2-x1)

m=(4+2)/(0+1)

m=6/1

m=6

Slope-intercept:

y - y1 = m(x - x1)

y + 2 = 6(x + 1)

y + 2 = 6x + 6

y = 6x + 4

y - 16 = 6(x - 2)

y - 16 = 6x - 12

y = 6x + 4

Answer:

A

Step-by-step explanation:

The first angle (a) is 15 less than twice the second angle (b)

So, twice the second angle is 15 more than the first:

2b = a+15

Simplify:

2b - 15 = a

The  variable x represent the length of rectangle.

A branch of mathematics known as algebra deals with symbols and the mathematical operations performed on them.

Variables are the name given to these symbols because they lack set values.

In order to determine the values, these symbols are also subjected to various addition, subtraction, multiplication, and division arithmetic operations.

Given:

Perimeter= 64 units

let the length be x.

So, width = x - 3

So, Perimeter of rectangle = 2 ( l + w)

64 = 2( x+ x -3)

32 = 2x -3

29= 2x

x= 29/2

Hence, the variable x represent the length of rectangle.

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Answer:

que

Step-by-step explanation:

no Tengo carnitas yo quero sopes

The solutions (x, y) will represent the complex numbers z that satisfy the equation z^3 - 4√3 - 4i = 0.

What is Counter clock wise?

The clockwise and counterclockwise rotation directions are as follows: Clockwise Rotations (CW) mimic the path of a clock's hands. Negative numbers are used to represent these rotations. Counterclockwise rotations (CCW) follow the path of a clock's hands in the opposite direction.

To solve the equation z^3 - 4√3 - 4i = 0, we can use the method of solving a cubic equation.

Let's denote z = x + yi, where x and y are real numbers.

Substituting this into the equation, we have:

(x + yi)^3 - 4√3 - 4i = 0

Expanding and equating the real and imaginary parts, we get:

x^3 - 3xy^2 - 4√3 = 0 (real part)

3x^2y - y^3 - 4 = 0 (imaginary part)

From the first equation, we can solve for x in terms of y:

x = ∛(3xy^2 + 4√3)

Substituting this into the second equation, we can solve for y:

3(∛(3xy^2 + 4√3))^2y - y^3 - 4 = 0

This equation can be solved numerically to find the values of y. Once we have the values of y, we can substitute them back into the equation x = ∛(3xy^2 + 4√3) to obtain the corresponding values of x.

The solutions (x, y) will represent the complex numbers z that satisfy the equation z^3 - 4√3 - 4i = 0.

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Answer:

\(x = \frac{-7 +\sqrt{489} }{2}\)

\(x = \frac{-7 - \sqrt{489} }{2}\)

Step-by-step explanation:

2x² +21x-61 = (x+7)²

expand

2x² + 21x - 61 = x² + 14x +49

move everything to one side

x² + 7x - 12 = 0

use quadratic formula

\(x = \frac{-b +- \sqrt{b^{2}-4ac } }{2a}\)

plug in the values

\(x = \frac{-7 +- \sqrt{7^{2}-4(1)(-110) } }{2(1)}\)

solve

\(x = \frac{-7 +- \sqrt{49-4(1)(-110) } }{2}\)

\(x = \frac{-7 +- \sqrt{49 + 440 } }{2}\)

\(x = \frac{-7 +- \sqrt{489} }{2}\)

to be honest i dont remember srry

Answer:

Polynomials are algebraic expressions that contain more than two terms. AN example would be: f(x) = x^3 + x^2 + x +1. This equation contains three terms, with the 3rd degree as its highest term. It also means that the graph passed three x-intercepts. This depends in the highest degree. So, the first thing you do is plot the intercepts because for sure, the graph will pass there.

Step-by-step explanation:

The factorized terms of the given expression  ax - a + x - 1 by grouping the terms in pairs is given by  (x - 1)(a + 1) .

Expression is equal to,

ax - a + x - 1

To factorize the expression ax-a+x-1 by grouping terms in pairs.

First group the first two terms and the last two terms together we get,

⇒ ax - a + x - 1 = ( ax - a ) + ( x - 1 )

Now factor out the common factor of 'a' from the first group.

And the common factor of '1' from the second group we get,

⇒ ax - a + x - 1 = a(x - 1) + 1(x - 1)

Both the groups have a common factor of (x - 1).

Take out  common factor we have,

⇒ ax - a + x - 1 = (x - 1)(a + 1)

Therefore, the factorized expression is equal to,

 ax - a + x - 1 = (x - 1)(a + 1)

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Answer:

\(y = \frac{5}{4} x - 5\)

In the equation y=mx+c m= the gradient of the line and our m=5 so gradient of the line is 5

The gradient of line L is 5

"y = mx + c, where m is the slope and c is the y-intercept."

For given question,

We have been given an equation of the line L  y = 5x + 12

Comparing above equation with the slope-intercept form of the line,

we have m = 5 and c = 12

Here, slope of the line L is 5

We know that the slope of the line is the  the change in the y coordinate with respect to the change in the x coordinate of the line.

This means, the gradient of the line L is 5

Therefore, the gradient of line L is 5

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Answer:

a. 4 (or maybe like 3.5)

b. 6

Step-by-step explanation:

a. Going from x = 0 to x = 8, it is obvious that y goes down 4 or 4.5 units during this stretch. This gives an approximate slope of -3/8. With this in mind, it can be easily calculated that going the remaining distance from x = 8 to x = 10, the value of y will be approximately 4 or so.

b. A dot literally is right next to (6, 6).

Answer:

3x+5x=40

=8x=40

=x=5

then no.of boys= 3×5 = 15

and no. of girls= 5×5=25

girls more than boys= 25-15=10

mark me brainliest

pls it takes too much time to solve this

Answer:

There will be 10 more girls than boys in the class.

Step-by-step explanation:

5x+3x=40

8x = 40

8x/8 = 40/8

x = 5

5*2 = 10

Answer:

3×(-45+6) 23²+1⁴

= - 61892

Step-by-step explanation:

Answer:

multiply both the x value and y value by -1

Answer: 234 degrees

Step-by-step explanation:

Angle formed by a chord and a tangent has half the measure as the arc formed by the chord

The value of measure of arc DEF is,

⇒ 234 degree

An angle is a combination of two rays (half-lines) with a common endpoint. The latter is known as the vertex of the angle and the rays as the sides, sometimes as the legs and sometimes the arms of the angle.

Given that;

Line t is tangent to the circle.

Hence, We know that;

The angle formed by a chord and a tangent is equal to 1/2 the measure of the intercepted arc.

Thus, The value of measure of arc DEF is,

⇒ 2 x 117 degree

⇒ 234 degree

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Answer:

b) 16 ÷ 4 × (11 - 7)

Step-by-step explanation:

Given statement,

→ quotient of 16 & 4 times 7 less than 11.

Forming the expression,

→ 16/(4(11 - 7))

→ 16 ÷ 4 × (11 - 7)

Evaluating the following,

→ 16 ÷ 4 × (11 - 7)

→ 16 ÷ (4 × 4)

→ 16 ÷ 16 = 1

Hence, option (b) is correct.

Answer:

14

Step-by-step explanation:

Answer:

55

Step-by-step explanation:

The horse travels 10 miles and hour and all ready travel 15, so do this equation.

y = 10x + 15 (plug in 4)

y = 10(4) + 15

y = 40 + 15

y = 55

Hope the Helps!!

under the restrictions that c is negative to ensure strict concavity, the utility function u(w) = -(b - w)c displays increasing absolute risk aversion.

To ensure that u(w) is strictly increasing, we need the derivative of u(w) with respect to w to be positive for all values of w. Taking the derivative, we have du(w)/dw = -c. For u(w) to be strictly increasing, -c must be positive, which implies c must be negative.

To ensure that u(w) is strictly concave, we need the second derivative of u(w) with respect to w to be negative for all values of w. Taking the second derivative, we have d²u(w)/dw² = 0. Since the second derivative is constant and negative, u(w) is strictly concave.

Now, let's examine the concept of increasing absolute risk aversion. If a utility function u(w) exhibits increasing absolute risk aversion, it means that as wealth (w) increases, the individual becomes more risk-averse.

In the given utility function u(w) = -(b - w)c, when c is negative (as required for strict concavity), the absolute risk aversion increases as wealth (w) increases. This is because the negative sign implies that the utility function is concave, indicating that the individual becomes more risk-averse as wealth increases.

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Answer:

Step-by-step explanation:

Y=1/2x+3

Answer:

A reflection over the line x=3

Step-by-step explanation:

Answer:

70 +60muinte= 13

Step-by-step explanation:

so that the ans

In h hours you will go 70h far from the original position and domain of the function is the amount of hours you drive option (C) is correct.

It is defined as a special type of relationship, and they have a predefined domain and range according to the function every value in the domain is related to exactly one value in the range.

The question is incomplete.

The complete question is:

Driving on the highway, you can safely drive 70 miles per hour. “How far can you drive in ‘h’ hours?” What is the domain of the function which defines this situation?

A.)The amount of gas you use.

B.) 70.

C.) The amount of hours you drive.

D.)The distance you drive

We have:

Driving on the highway, you can safely drive 70 miles per hour.

The speed of the vehicle = 70 miles per hour

As we know,

Distance = speed×time

1 hour → 70 miles

h hour → D miles

D(t) = 70h

The above expression represents the situation.

Thus, in h hours you will go 70h far from the original position and domain of the function is the amount of hours you drive option (C) is correct.

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Answer:

{ x : x = 2^n -1 , n ∈ N}

Where N is the set of natural numbers

Step-by-step explanation:

Mathematically, we can rewrite each term in the set as follows;

1 = 2^1 - 1

3 = 2^2 -1

7 = 2^3 -1

15 = 2^4-1

31 = 2^5-1

63 = 2^6 -1

so we can conclude that the nth term is 2^n -1

So writing this in set builder notation, we have;

{ x : x = 2^n -1 , n ∈ N}

Where N is the set of natural numbers

The vertex of the function defined as g(x) = f(x+2) is (8, 4).

From the question, we have the following parameters that can be used in our computation:

Vertex of f(x) = (6, 4)

For the function defined as g(x) = f(x+2), we have

Vertex = (x + 2, y)

Where

x = 6 and y = 2

Substitute the known values in the above equation, so, we have the following representation

Vertex = (6 + 2, 4)

Evaluate

Vertex = (8, 4)

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The schedule is as follows:

T1 -> T2 -> T1 -> T3 -> T1 -> T2 -> T1.

To construct a schedule using the Earliest Deadline First (EDF) scheduling algorithm, we need to consider the execution time, period, and deadline of each task and assign them priorities based on their deadlines. The task with the earliest deadline will be scheduled first. Let's create a schedule for the given task set:

Task T1: Execution time (e) = 2 ns, Period (P) = 5 ns, Deadline (D) = 5 ns

Task T2: Execution time (e) = 4 ns, Period (P) = 7 ns, Deadline (D) = 7 ns

Task T3: Execution time (e) = 7 ns, Period (P) = 7 ns, Deadline (D) = 7 ns

We have a period of 22 ns, and we need to schedule these tasks within that period. Let's start with the task with the earliest deadline:

At time 0 ns: Execute T1 (2 ns)

At time 2 ns: Execute T2 (4 ns)

At time 6 ns: Execute T1 (2 ns)

At time 8 ns: Execute T3 (7 ns)

At time 15 ns: Execute T1 (2 ns)

At time 17 ns: Execute T2 (4 ns)

At time 21 ns: Execute T1 (2 ns)

This completes the execution of all tasks within the given period of 22 ns. The schedule is as follows:

T1 -> T2 -> T1 -> T3 -> T1 -> T2 -> T1

In this schedule, we have followed the EDF algorithm by selecting tasks based on their deadlines. The task with the earliest deadline is always scheduled first to meet the timing requirements of the system.

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Answer:

8 pints

Step-by-step explanation:

A pint is 16 ounces = 2 cups

8 pints is then 16 cups

So the maximum number of edges in an undirected graph with 100 vertices is 4950.

In an undirected graph, each edge connects two vertices, and as such, it is counted twice, once for each vertex it connects. Therefore, the total number of edges in the graph is the sum of the degrees of all vertices, divided by 2.

In a complete graph with n vertices, every vertex is connected to every other vertex, except itself, and so the degree of each vertex is n-1 (it is connected to n-1 other vertices). Therefore, the total number of edges in the graph is:

n * (n-1) / 2

Substituting n = 100, we get:

100 * 99 / 2 = 4950

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