HELP ASAP!!!!!! I NEED HELP

1. Label each of the following organs on the picture below: pancreas, liver, stomach, small intestine,
large intestine.
2. In the space provided, describe the function of each organ you labeled.

HELP ASAP!!!!!! I NEED HELP 1. Label Each Of The Following Organs On The Picture Below: Pancreas, Liver,

Answers

Answer 1

The organs of the digestive system such as the pancreas, liver, stomach, small intestine, and large intestine help in the digestion of food.

What are organs?

Organs are a collection of tissues that are closely related and which perform a related function.

The role and function of the organs of the digestive system are as follows:

Pancreas - produces pancreatic juice which contain digestive enzymesLiver - produces bile for the emulsification of fatStomach - serves as a temporary store of food and produces digestive juicesSmall intestine - functions in food digestionLarge Intestine - helps to remove undigested food from the body

Therefore, the organs of the digestive system such as the pancreas, liver, stomach, small intestine, and large intestine help in the digestion of food.

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HELP ASAP!!!!!! I NEED HELP 1. Label Each Of The Following Organs On The Picture Below: Pancreas, Liver,

Related Questions

2. How can we deposit a thin layer of silver on an iron spoon? What is the process called? Explain with a labelled diagram.​

Answers

Answer:

ELECTROPLATING

Explanation:

In silver plating, object (iron spoon) to be electroplated is made cathode, metal to be used for coating (bar of silver metal) as anode and silver nitrate solution  as electrolyte. When current passes, positive ions moved toward the cathode and thus silver is coated to the spoon.

The process of depositing a layer of any desired metal on another material, by means of electricity is called electroplating.

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diagram

2.How can we deposit a thin layer of silver on an iron spoon? What is the process called? Explain with

What are the answers

What are the answers

Answers

Answer: A, C, E, and F

Explanation: water is a reactant it can react with anything. Hydrocarbon can also do the same. O2 and CO2 does the same.

A 10.0 g gold ring with a specific heat 0.129 at 24.00°C is placed in a calorimeter with 118 g of water at 1.00°C.
What will be the final temperature of the system?

Answers

Answer:

1.06 °C

Explanation:

From the question given above, the following data were obtained:

Mass of gold (M₉) = 10 g

Specific heat capacity of gold (C₉) = 0.129 J/gºC

Initial temperature of gold (T₉) = 24 °C

Mass of water (Mᵥᵥ) = 118 g

Specific heat capacity of water (Cᵥᵥ) = 4.184 J/gºC

Initial temperature of water (Tᵥᵥ) = 1 °C

Equilibrium temperature (Tₑ) =?

The equilibrium temperature of the system can be obtained as follow:

Heat loss by the gold = heat gained by the water

M₉C₉(T₉ – Tₑ) = MᵥᵥCᵥᵥ(Tₑ – Cᵥᵥ)

10 × 0.129 (24 – Tₑ) = 118 × 4.184 (Tₑ – 1)

1.29(24 – Tₑ) = 493.712 (Tₑ – 1)

Clear bracket

30.96 – 1.29Tₑ = 493.712Tₑ – 493.712

Collect like terms

30.96 + 493.712 = 493.712Tₑ + 1.29Tₑ

524.672 = 495.002Tₑ

Divide both side by 495.002

Tₑ = 524.672 / 495.002

Tₑ = 1.06 °C

Therefore, the temperature of the system is 1.06 °C

The amount of heat of the system is measured by a device called a calorimeter. The final temperature of the system will be 1.06 degrees celsius.

What is equilibrium temperature?

The equilibrium temperature is the temperature that follows the law of thermodynamics and is said to be the system that has alike temperatures.  

Given,

Mass of Ag \(\rm (M_{g})\) = 10g

Specific heat capacity of Ag \((\rm C_{g})\) = \(\rm 0.129 J/g^{\circ}C\)

The initial temperature of Ag \((\rm T_{g})\) = \(24 ^{\circ}\;\rm C\)

Mass of water \((\rm M_{w})\) = 118 g

Specific heat capacity of water \((\rm C_{w})\) = \(4.184 \rm \;J/g^{\circ}\;\rm C\)

The initial temperature of water \((\rm T_{w})\) = \(1 ^{\circ}\;\rm C\)

Equilibrium temperature = \((\rm T_{e})\)

The equilibrium temperature can be shown as, heat loss by the gold = heat gained by the water:

\(\rm \rm M_{g}C_{g}(T_{g} - T_{e}) = M_{w}C_{w}(T_{e}-C_{w})\)

Substituting values in the equation:

\(\begin{aligned} 10 \times 0.129 (24 - \rm T_{e}) &= 118 \times 4.184 (\rm T_{e} - 1)\\\\\rm 1.29(24 - T_{e}) &= 493.712 (\rm T_{e} - 1)\\\\524.672 &= 495.002 \;\rm T_{e}\end{aligned}\)

Now divide both the sides by 495.002:

\(\begin{aligned} \rm T_{e} &= \dfrac{524.672 }{495.002}\\\\\rm T_{e} &= 1.06 \;^{\circ}\rm C\end{aligned}\)

Therefore, the final temperature of the system is 1.06 degrees celsius.

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Calculate the mass percent of hydrogen in 70 g of C4H8O3?​

Answers

Answer:

7.14%

Explanation:

From the question,

percentage by mass hydrogen in C₄H₈O₃ (h)   = mass of hydrogen present in C₄H₈O₃(m)/molar mass of C₄H₈O₃ (m')

h = (m'/m)×100..................... Equation 1

Given: m' = (14×4)+(1×8)+(16×3) = 56+8+48 = 112 g, m =  (1×8) = 8 g

Substitute these values into equation 1

h = (8/112)×100

h = 7.14%.

Hence the percentage of hydrogen in 70 g of C₄H₈O₃ is 7.14%

Lenses are made to have different focal points. What two properties of a lens
affect the focal length?
A. Where the object is located
O B. Whether the image is virtual or real
O C. The material the lens is made from
O D. The centers of curvature of the two sides of the lens

Answers

The correct answer is letter C

aldehydes plus potassium permanganate with explanation

Answers

\( \large \sf \: answer\)

You can identify the aldehyde from acidic potassium permanganate. Purple colour of acidic potassium permanganate is changed to colourless because aldehyde is oxidized by acidic potassium permanganate.

What is the chemical formula for Manganese (IV) biphosphate?
Group of answer choices

Mn(HPO4)2

Mn2(HPO4)4

Mn4(HPO4)2

Mg2(HPO4)4

No correct response

Answers

I believe its the first one because manganese is mn and IV is 4 but the cross thing thing will making it the second one but then you have to simplify making it the first one i hope that helps:)

name any
three kinds of mixtures with example​

Answers

Answer:

Here are a few more examples:

Smoke and fog (Smog)

Dirt and water (Mud)

Sand, water and gravel (Cement)

Water and salt (Sea water)

Potassium nitrate, sulfur, and carbon (Gunpowder)

Oxygen and water (Sea foam)

Petroleum, hydrocarbons, and fuel additives (Gasoline)

Heterogeneous mixtures possess different properties and compositions in various parts i.e. the properties are not uniform throughout the mixture.

Examples of Heterogeneous mixtures – air, oil, and water, etc.

Examples of Homogeneous mixtures – alloys, salt, and water, alcohol in water, etc.

Explanation:

Answer:

smog,mud, cement?

Explanation:

Smoke and fog (Smog)

Dirt and water (Mud)

Sand, water and gravel (Cement)

How many molecules of methane gas (CH4) are in 32.1 grams of methane

Answers

Answer:

There are 1.8021⋅1024 molecules of CH4 in 48 grams of CH4 .

Explanation:

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Observation of balloon rub with cloth?

Answers

Answer:

When rubbing a balloon with a wool cloth, it puts negative charges on the balloon. Negative charges attract to positive charges. ... When both balloons are rubbed with the wool cloth, the both receive negative charges, so they will repel each other.

1
Give two reasons that show sugar is a compound
2
What is the difference between carbon (charcoal and suga? Compra ad 1​

Answers


Sugar is compound because it gets compressed

Determine the enthalpy of reaction for HCl(g) + NaNO₂(s) → HNO₂(l) + NaCl(s) 2NaCl(s) + H₂O(l) → 2HCl(g) + Na₂O(s) ∆H° = -507.1 kJ/mol NO(g) + NO₂(g) + Na₂O(s) → 2NaNO₂(s) ∆H° = -427.0 kJ/mol NO(g) + NO₂(g) → N₂O(g) + O₂(g) ∆H° = -43.01 kJ/mol 2HNO₂(l) → N₂O(g) + O₂(g) + H₂O(l) ∆H° = +34.02 kJ/mol

Answers

the enthalpy of reaction for HCl(g) + NaNO₂(s) → HNO₂(l) + NaCl(s) 2NaCl(s) + H₂O(l) → 2HCl(g) + Na₂O(s) ∆H° = -507.1 kJ/mol NO(g) + NO₂(g) + Na₂O(s) → 2NaNO₂(s) ∆H° = -427.0 kJ/mol NO(g) + NO₂(g) → N₂O(g) + O₂(g) ∆H° = -43.01 kJ/mol 2HNO₂(l) → N₂O(g) + O₂(g) + H₂O(l) ∆H° = +34.02 kJ/mol the enthalpy of reaction for the given reaction is -39.1 kJ/mol.

We can use the given reactions and their enthalpies to find the enthalpy of reaction for the given equation.

The given equation is:

HCl(g) + NaNO₂(s) → HNO₂(l) + NaCl(s)

We can break down this reaction into several steps using the given reactions as follows:

Na₂O(s) + 2HCl(g) → 2NaCl(s) + H₂O(l) (reverse of the given reaction)

∆H° = +507.1 kJ/mol (reverse the sign of given reaction)

2NaCl(s) + H₂O(l) → Na₂O(s) + 2HCl(g)

∆H° = -507.1 kJ/mol (given reaction)

NO(g) + NO₂(g) + Na₂O(s) → 2NaNO₂(s)

∆H° = -427.0 kJ/mol (given reaction)

2HNO₂(l) → N₂O(g) + O₂(g) + H₂O(l)

∆H° = +34.02 kJ/mol (given reaction)

NO(g) + NO₂(g) → N₂O(g) + O₂(g)

∆H° = -43.01 kJ/mol (given reaction)

Now, we can add these equations and their enthalpies to get the overall enthalpy of the given reaction:

HCl(g) + NaNO₂(s) → HNO₂(l) + NaCl(s)

H₂O(l) + 2NaCl(s) → Na₂O(s) + 2HCl(g) ∆H° = -507.1 kJ/mol

Na₂O(s) + NO(g) + NO₂(g) → 2NaNO₂(s) ∆H° = -427.0 kJ/mol

2HNO₂(l) → N₂O(g) + O₂(g) + H₂O(l) ∆H° = +34.02 kJ/mol

NO(g) + NO₂(g) → N₂O(g) + O₂(g) ∆H° = -43.01 kJ/mol

HCl(g) + NaNO₂(s) → HNO₂(l) + NaCl(s) ∆H° = -39.1 kJ/mol

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Why is The Law of Conservation of Matter a law and not a theory? will brainlist

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During a chemical reaction, matter cannot be created nor destroyed, matter can change form through physical and chemical changes, but through any of these changes, matter is conserved; even though the matter may change from one form to another, the same number of atoms exists before and after the change takes place. <3

Q5 Synthesis gas may be prepared by a continuous, noncatalytic conversion of any
hydrocarbon by means of controlled partial combustion in a fire-brick lined reactor. In the basic
form of this process, the hydrocarbon and oxidant (oxygen or air) are separately preheated and
charged to the reactor. Before entering the reaction zone, the two feed stocks are intimately mixed
in a combustion chamber. The heat produced by combustion of part of the hydrocarbon pyrolyzes
the remaining hydrocarbons into gas and a small amount of carbon in the reaction zone. The reactor
effluent then passes through a waste-heat boiler, a water-wash carbon-removal unit, and a water
cooler-scrubber. Carbon is recovered in equipment of simple design in a form which can be used
as fuel or in ordinary carbon products. Prepare a simplified flow sheet for the process, with
temperatures and pressure conditions at each piece of equipment. Note that standard symbols
should be used for all equipment.

Answers

Flow sheet for synthesis gas production process: Hydrocarbon preheater → Combustion chamber Reactor → Waste-heat boiler → Carbon removal unit → water-cooler scrubber → Synthesis Gas.

                   

Temperature and Pressure Conditions:

Hydrocarbon Preheater: High temperature (depends on the specific hydrocarbon used)

Combustion Chamber: High temperature (due to controlled partial combustion)

Reactor: High temperature (to promote pyrolysis and gas formation)

Waste-heat Boiler: Moderate temperature (to recover heat from reactor effluent)

Carbon-Removal Unit: Moderate temperature (to remove carbon from gas)

Water Cooler-Scrubber: Low temperature (to cool and scrub the gas)

Synthesis Gas: At atmospheric pressure (or specified process pressure).

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Help me plssssssssss

Help me plssssssssss

Answers

Answer:

The answer for this selection is 4

Explanation:

- What is the atmospheric pressure?

Answers

Answer:

Atmospheric Pressure:

- It is the force exerted on a surface by the air above it as gravity pulls it to Earth. Atmospheric pressure is commonly measured with a barometer. In a barometer, a column of mercury in a glass tube rises or falls as the weight of the atmosphere changes.

Explanation:

Hope this helps

how can landforms be weathered?

Answers

Answer:

they can become smaller or start fall apart or aroud

Explanation:

Compared to water, metals heat up faster because they have

Compared to water, metals heat up faster because they have

Answers

Answer: the answer would be a lower specific heat.

Explanation:

which of the following early events in biofilm formation by pseudomonas aeruginosa involves the extension and retraction of a specific pilus?

Answers

The correct answer is : The early event in biofilm formation by Pseudomonas aeruginosa that involves the extension and retraction of a specific pilus is called twitching motility.

Explanation:
Biofilm formation is a process in which microorganisms attach to surfaces and form a protective layer. One of the key steps in this process is the extension and retraction of a specific pilus, which is a hair-like structure found on the surface of certain bacteria.

In the case of Pseudomonas aeruginosa, this pilus is called the type IV pilus and is involved in a process called twitching motility. This process allows the bacteria to move along surfaces and is crucial for the early stages of biofilm formation.

As the bacteria move, they secrete a slimy substance called an exopolysaccharide, which helps them to adhere to surfaces and form a protective layer. This is an important step in the formation of biofilms, which can have serious implications for human health, as they are often resistant to antibiotics and can cause infections.

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Please help ( show work if needed)

Please help ( show work if needed)

Answers

Hope you could understand.

If you have any query, feel free to ask.

Please help ( show work if needed)

Which is a chemical property of trasistion elements?

A) brightly colored
B) denser than alkali metals
C) great ductility
D) reacts little with oxygen

Answers

Answer:

Maybe D? B?

Explanation:

Sorry if I made u get it wrong

In the Hall-Heroult process, a large electric current is passed through a solution of aluminum oxide Al2O3 dissolved in molten cryolite Na3AlF6, resulting in the reduction of the Al2O3 to pure aluminum. Suppose a current of 100.A is passed through a Hall-Heroult cell for 41.0 seconds. Calculate the mass of pure aluminum produced. Round your answer to 3 significant digits. Also, be sure your answer contains a unit symbol.

Answers

Answer:

0.382g

Explanation:

Step 1: Write the reduction half-reaction

Al³⁺(aq) + 3 e⁻ ⇒ Al(s)

Step 2: Calculate the mass of Al produced when a current of 100. A passes through the cell for 41.0 s

We will use the following relationships.

1 A = 1 C/s1 mole of electrons has a charge of 96486 C (Faraday's constant)1 mole of Al is produced when 3 moles of electrons pass through the cell.The molar mass of Al is 26.98 g/mol.

The mass of Al produced is:

\(41.0s \times \frac{100C}{s} \times \frac{1mole^{-} }{96486C} \times \frac{1molAl}{3mole^{-} } \times \frac{26.98gAl}{1molAl} = 0.382gAl\)

according to the law of energy conservation, the total amount of energy is constant, then why does the chemical energy in electric cells got used up?

Answers

Answer:

The law of conservation of energy states that energy can neither be created nor destroyed - only converted from one form of energy to another.

Explanation:

This means that a system always has the same amount of energy unless it's added from the outside. is the total internal energy of a system.

-Convert 6.02 x 1020 formula units of MgCl₂ to mol of MgCl₂:​

Answers

6.02 x \(10^{20\) formula units of MgCl₂ is equal to 0.1 moles of MgCl₂.

To convert formula units of MgCl₂ to moles of MgCl₂, we need to use Avogadro's number, which relates the number of formula units to the number of moles.

Avogadro's number (NA) is approximately 6.022 x 10^23 formula units per mole.

Given that we have 6.02 x 10^20 formula units of MgCl₂, we can set up a conversion factor to convert to moles:

(6.02 x 10^20 formula units MgCl₂) * (1 mol MgCl₂ / (6.022 x 10^23 formula units MgCl₂))

The formula units of MgCl₂ cancel out, and we are left with moles of MgCl₂:

(6.02 x 10^20) * (1 mol / 6.022 x 10^23) = 0.1 mol

Therefore, 6.02 x 10^20 formula units of MgCl₂ is equal to 0.1 moles of MgCl₂.

It's important to note that this conversion assumes that each formula unit of MgCl₂ represents one mole of MgCl₂. This is based on the stoichiometry of the compound, where there is one mole of MgCl₂ for every one formula unit.

Additionally, this conversion is valid for any substance, not just MgCl₂, as long as you know the value of Avogadro's number and the number of formula units or particles you have.

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Sometimes people have to cry out all their tears, to make room for a heart full of smiles.​

Answers

True. I am always sad but my heart is always happy cuz it knows there are good things ahead

H2O2(aq)+ClO4−(aq)→ClO2−(aq)+O2(g)
Express your answer as a net ionic equation including phases in basic solution

Answers

Answer:

H

2

O

2

(aq)+ClO

4

(aq)⟶O

2

(g)+ClO

2

(aq)

All atoms except H and O are balanced.

The oxidation number of Cl changes from 7 to 3. The change in the oxidation number is 4.

The oxidation number of O changes from -1 to 0. The change in oxidation number per O atom is 1.

Total change in the oxidation number for 2 oxygen atoms is 2.

To balance the increase in oxidation number with decrease in the oxidation number, multiply H

2

O

2

and O

2

with coefficients 2.

2H

2

O

2

(aq)+ClO

4

(aq)⟶2O

2

(g)+ClO

2

(aq)

To balance O atoms, add 2 water molecules on RHS.

2H

2

O

2

(aq)+ClO

4

(aq)⟶2O

2

(g)+ClO

2

(aq)+2H

2

O(l)

The oxygen atoms are already balanced.

This is the balanced chemical equation

what is the concentration of H+ in pH 3 moldm^-3​

Answers

Answer:

0.001 mol/dm^3.

Explanation:

The pH of a solution is defined as the negative base-10 logarithm of the concentration of hydrogen ions (H+) in moles per liter (M).

The pH of 3 moldm^-3 means the concentration of hydrogen ions in the solution is:

[H+] = 10^(-pH) mol/L

[H+] = 10^(-3) mol/dm^3

[H+] = 0.001 mol/dm^3

Therefore, the concentration of H+ in pH 3 moldm^-3 is 0.001 mol/dm^3.

Question 1
Given the equation: Q = mcAT
Q = heat (in Joules)
m = mass (in grams)
C = 4.18 (specific heat capacity)
AT change in temperature (°C)
How many Joules of heat energy are absorbed when 200 grams of water are heated from 20 C to 60 C.

Question 1Given the equation: Q = mcATQ = heat (in Joules)m = mass (in grams)C = 4.18 (specific heat

Answers

The amount of heat energy absorbed when 200 grams of water are heated from 20 C to 60 C is 33,440 Joules.

To find the amount of heat energy absorbed when 200 grams of water are heated from 20 C to 60 C, we can use the equation Q = mcAT.
First, we need to find the value of m, which is the mass of the water in grams. In this case, it is given as 200 grams.
Next, we need to find the value of AT, which is the change in temperature in degrees Celsius.

This can be calculated by subtracting the initial temperature from the final temperature, which gives us 60 C - 20 C = 40 C.
The specific heat capacity of water, C, is given as 4.18 Joules per gram per degree Celsius.
Now we can plug in the values into the equation:
Q = mcAT
Q = (200 g) x (4.18 J/g°C) x (40°C)
Q = 33,440 J
Therefore, the amount of heat energy absorbed when 200 grams of water are heated from 20 C to 60 C is 33,440 Joules.

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A current of 3.91 A is passed through a Pb(NO3)2 solution for 1.70 h . How much lead is plated out of the solution?

Answers

The mass (in grams) of lead that will plate out of the solution, given that 3.91 A is passed through the solution for 1.7 h is 25.66 g

How do I determine the mass of lead?

First, we shall determine the charge flowing through the solution. This is shown below:

Current (I) = 3.91 ATime (t) = 1.70 h = 1.7 × 60 × 60 = 6120 sCharge (Q) = ?

Q = It

Q = 3.91 × 6120

Q = 23929.2 C

Finally, we shall determine the mass of lead that will plate out of the solution. Details below:

Balanced equation

Pb²⁺ + 2e —> Pb

Molar mass of Pb = 207 g/mol Mass of Pb from the balanced equation = 1 × 207 = 207 gNumber of faraday = 21 faraday = 96500 C2 faraday = 2 × 96500 = 193000 C

From the balanced equation above,

193000 C plated 207 g of lead

Therefore,

23929.2 C will plate = (23929.2 × 207) / 193000 = 25.66 g of lead

Thus, the mass of lead that  will plate out is 25.66 g

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hydrogen bond is a strong dipole interaction for example water and other molecules true or false

Answers

Answer:

hydrogen bond is a type of dipole-dipole interaction; it is not a true chemical bond it is a mere electrostatic attraction. These attractions can occur between molecules or within different parts of a single molecule. Intramolecular hydrogen bonds are those which occur within one single molecule.

Explanation:

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What situation does Charles II want to prevent by getting rid of very narrow streets and keeping lanes and alleys to a minimum