Skater A skates toward Skater B and gently pushes Skater B away. If the skaters are in a closed system, which statement is correct about the total momentum of the system? A. Total momentum may increase or decrease depending on the duration of the collision. B. Total momentum remains the same. C. Total momentum increases. D. Total momentum decreases.
Answer:
option B is correct
Explanation:
according to law of conservation of momentum the total momentum in a closed system remains constant before and after collision
If the skaters are in a closed system the total momentum remains the same.
In a closed system the total momentum is always conserved.
By applying the principle of conservation of linear momentum, the total momentum before the push of skater A, will be equal to the total momentum after the push.
The equation is given as;
Initial momentum = final momentum
\(m_au_a + m_bu_b = m_av_a + m_bv_b\)
where;
u and v represents the initial and final velocity of both skaters.Thus, we can conclude that if the skaters are in a closed system the total momentum remains the same.
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A ray of light, incident on an equilateral glass prism of refractive index √3, moves parallel to the base line of the prism inside it. Find the angle of incidence
As the ray of light moves parallel to the base line of the prism inside it, so angle of refraction = r = 30° (equilateral prism)
Now, we know that:
\({:\implies \quad \sf \sin (i)=\mu \sin (r)}\)
\({:\implies \quad \sf \sin (i)=\sqrt{3}\sin (30^{\degree})}\)
\({:\implies \quad \sf \sin (i)=\dfrac{\sqrt{3}}{2}}\)
\({:\implies \quad \sf \sin (i)=\sin (60^{\degree})}\)
Therefore, angle of incidence is 60°
Given ,
\(r = \sqrt{3}\)
Now ,
\( \longrightarrow \sin(i) = \sqrt{3} \: \sin(30°)\)
\( \: \: \: \: \: \: \: \: \: \: \: \: \)
\(\longrightarrow \sin(i)= \sqrt{ \frac{3}{2} }\)
\( \: \: \: \: \: \: \: \: \: \: \: \: \)
\( \longrightarrow \: i = 60°\)
The angle of incidence is 60°.
Physics help please !!!
Answer:
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Homework: Writing an Argument About
Australia's Skin Cancer Rate
G
4
You now have enough evidence to explain why Australia's skin cancer rate is so high. Review your
argument from Chapter 2 and think about how you will convince the AHA that both Claim 2 and
Claim 3 are accurate. You will use your completed Reasoning Tool from Activity 3 to revise and add to
your argument.
Question: Why is the skin cancer rate in Australia so high?
Water runs into a fountain, filling all the pipes, at a steady rate of 0.757 m3/s. (A) How fast will it shoot out of a hole 4.51cm in diameter? (B) At what speed will it shoot out if the diameter of the hole is three times as large?
(A)The water will shoot out of the hole at a speed of 4.77 m/s, and the pressure of the water at the hole will be 9.91 × 10^4 Pa, and (B) The water will shoot out of the larger hole at a speed of 0.529 m/s, and the pressure of the water at the hole will be 1.012 × 10^5 Pa.
We can use Bernoulli's equation to solve this problem, which relates the pressure, velocity, and height of a fluid. The equation states that:
P + (1/2)ρv^2 + ρgh = constant
where P is the pressure, ρ is the density of the fluid, v is the velocity of the fluid, g is the acceleration due to gravity, and h is the height of the fluid.
(A) The diameter of the hole is 4.51 cm, which corresponds to a radius of 2.255 cm = 0.02255 m. The area of the hole is A = πr^2 = 1.587 × 10^-4 m^2. The volume flow rate of water is Q = 0.757 m^3/s.
We can calculate the velocity of the water as it exits the hole using the equation:
Q = Av
where A is the area of the hole and v is the velocity of the water. Solving for v, we get:
v = Q/A = 4.77 m/s
Now, we can use Bernoulli's equation to find the pressure of the water at the hole. Assuming that the height of the fountain is negligible compared to the height of the atmosphere, we can set the height term to zero. Also, we can assume that the pressure at the surface of the fountain is atmospheric pressure, which we can take as P = 1.013 × 10^5 Pa. Then, the equation becomes:
P + (1/2)ρv^2 = constant
Solving for P, we get:
P = constant - (1/2)ρv^2
At the hole, the velocity of the water is v = 4.77 m/s, and the density of water is ρ = 1000 kg/m^3. Substituting these values, we get:
P = 1.013 × 10^5 Pa - (1/2) × 1000 kg/m^3 × (4.77 m/s)^2 = 9.91 × 10^4 Pa
So, the water will shoot out of the hole at a speed of 4.77 m/s, and the pressure of the water at the hole will be 9.91 × 10^4 Pa.
(B) If the diameter of the hole is three times as large, then the area of the hole will be nine times as large. Therefore, the volume flow rate of water will be distributed over a larger area, resulting in a lower velocity. The new area of the hole is A = 9 × 1.587 × 10^-4 m^2 = 1.43 × 10^-3 m^2. The volume flow rate of water is still Q = 0.757 m^3/s.
Using the equation Q = Av, we can find the new velocity of the water:
v = Q/A = 0.529 m/s
Using Bernoulli's equation, we can find the pressure of the water at the larger hole:
P = 1.013 × 10^5 Pa - (1/2) × 1000 kg/m^3 × (0.529 m/s)^2 = 1.012 × 10^5 Pa
So, the water will shoot out of the larger hole at a speed of 0.529 m/s, and the pressure of the water at the hole will be 1.012 × 10^5 Pa.
Hence, Water will flow out of the smaller hole at a speed of 0.529 m/s and a pressure of 1.012 × 10^5 Pa, and the water will shoot out of the hole at a speed of 4.77 m/s and a pressure of 9.91 × 10^4 Pa.
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A cat runs in a straight line. Which of the following statements about the cat's motion must be true?
Answer:
I would think it's A cat runs in a straight line.
Explanation:
The correct statement regarding the motion of the cat is option c. The speed of the cat is zero at the points a and c. Where the position meets 0 m.
What is position -time graph ?A position - time graph is really helpful to determine the position of an object with respect to time. Thus, we can clearly calculate how much distance is covered within a given time. Similarly if the velocity of motion can be easily determined from this graph.
From the given graph, the cat starts walking from the point a. Then from a to b it walks in a straight line with an increasing velocity with time. At the point b, it reaches to its maximum displacement.
Then the cat starts walking down where the distance in m is decreasing with time, At the point c, it stops walking and it has zero speed as it is in point a. Therefore, the correct statement about the motion of the cat is option c.
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The complete question is attached below.
When an atom that has no charge loses two electrons, it becomes a
positive ion.
negative ion.
positive isotope.
negative isotope
Considering the definition of ion, option A is correct: when an atom that has no charge loses two electrons, it becomes a positive ion or cation.
Definition of ionAn ion is an electrically charged particle that is made up of an atom or molecule that is not electrically neutral, that is, that in its constitution has gained or lost electrons.
In other words, an ion is a molecule or atom that has a positive or negative electrical charge. That is, an ion is an atom whose electrical charge is not neutral.
If the electrical charge is positive, it is called a cation while if the electrical charge is negative, it is called a anion.
This caseCations are positively charged ions. They are formed as a result of the loss of electrons. This means that cations always have more protons than electrons.
Finally, option A is correct: when an atom that has no charge loses two electrons, it becomes a positive ion or cation.
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Answer:
positive ion
Explanation:
A horizontal force is applied to a 4.0 kg box. The box starts from rest, moves a horizontal distance of 10.0 meters, and obtains a velocity of 7.0 m/s. The change in the kinetic energy is:_____.
Answer:
98 J
Explanation:
Applying,
Change in kinetic energy = Final kinetic energy- initial kinetic energy
ΔK.E = mv²/2-mu²/2..............Equation 1
Where ΔK.E = Change in kinetic energy, m = mass of the box, u = initial velocity of the box, v = final velocity of the box.
From the question,
Given: m = 4.0 kg, u = 0 m/s, v = 7 ,0 m/s
Substitute these values into equation 1
ΔK.E = (4(7²)/2)-(4(0²)/2)
ΔK.E = (2×49)-0
ΔK.E = 98 J
Hence the change in kinetic energy 98 J
On a warm summer day, a large mass of air (atmospheric pressure 1.01×105Pa) is heated by the ground to a temperature of 25.0 ∘C and then begins to rise through the cooler surrounding air. Calculate the temperature of the air mass when it has risen to a level at which atmospheric pressure is only 8.70×104 Pa. Assume that air is an ideal gas, with γ=1.40. (This rate of cooling for dry, rising air, corresponding to roughly 1 ∘C per 100 m of altitude, is called the dry adiabatic lapse rate.)
The temperature of the air mass when it has risen to a level at which atmospheric pressure is only 8.70×10⁴ Pa is approximately 14.3°C.
Using the ideal gas law, we can write: PV = nRT, where P is the pressure, V is the volume, n is the number of moles of gas, R is the gas constant, and T is the absolute temperature. Since the mass of air is not changing, we can write: PV = constant.
Applying this to the situation where the air mass rises to a level where the pressure is 8.70×10⁴ Pa, we get:
(1.01×10⁵ Pa)×V = (nR/T1)×T1(8.70×10⁴ Pa)×V = (nR/T2)×T2Dividing the second equation by the first and using the fact that γ=Cp/Cv=1.40 for air, we get:
(T2/T1) = [(P2/P1)^(γ-1)/γ] = [(8.70×10⁴ Pa)/(1.01×10⁵ Pa)]^(1.4/1.4) = 0.813Solving for T2, we get:
T2 = T1×(P2/P1)^(γ-1)/γ = (25+273) K×0.813 ≈ 287.3 K ≈ 14.3°CThus, the temperature of the air mass when it has risen to a level at which atmospheric pressure is only 8.70×10⁴ Pa is approximately 14.3°C.
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As a boss, knowing your employees’ personality types can help you
Explanation:
but where's the options?
7. Particle A (mass = m, charge = Q) and B (mass = m, charge = 5 Q) are released from rest with the distance between them equal to 1.0 m. If Q = 12 C, what is the kinetic energy of particle B at the instant when the particles are 3.0 m apart?
Ans: 4.32J
The kinetic energy of particle B at the instant when the particles are 3.0 m apart is 4.32 J.
How to determine kinetic energy?The total energy of the system is conserved. The initial energy of the system is the electrostatic potential energy, which is given by:
U = k × (Q₁ × Q₂) / r
where:
U = potential energy in joules
k = Coulomb's constant (8.988 x 10⁹ N m²/C²)
Q₁ and Q₂ = charges in coulombs
r = distance between the charges in meters
In this case:
U = 8.988 x 10⁹ N m²/C² × (12 C × 5 Q) / (1.0 m) = 5.375 x 10⁻⁷ J
The final energy of the system is the kinetic energy of particle B. The kinetic energy is given by:
KE = 1/2 × m × v²
where:
KE = kinetic energy in joules
m = mass in kilograms
v = velocity in meters per second
Solve for the velocity of particle B using the conservation of energy equation:
KE = U
Substituting the expressions for KE and U gives:
1/2 × m × v² = 5.375 x 10⁻⁷ J
Solving for v gives:
v = √(2 × 5.375 x 10⁻⁷ J / m)
= 1.53 m/s
The kinetic energy of particle B is then:
KE = 1/2 × m × v²
= 1/2 × m × (1.53 m/s)²
= 4.32 J
Therefore, the kinetic energy of particle B at the instant when the particles are 3.0 m apart is 4.32 J.
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A 682-kg elevator starts from rest and moves upward for 3.10 s with constant acceleration until it reaches its cruising speed, 1.80 m/s.
(a) What is the average power of the elevator motor during this period? (Answer in horsepower)
(b) How does this amount of power compare with its power during an upward trip with constant speed? (Give the power during an upward trip with
constant speed.) (answer in horsepower)
a) the average power of the elevator motor during this period is 0.1696 hp
b) The power during an upward trip with constant speed is 16.13 horsepower.
To calculate the average power of the elevator motor during the period of acceleration, we need to find the work done by the motor and divide it by the time taken.
Given:
Mass of the elevator (m) = 682 kg
Acceleration (a) = (1.80 m/s - 0) / 3.10 s = 0.5806 m/s²
Time taken for acceleration (t) = 3.10 s
(a) First, let's calculate the displacement (d) using the formula for uniformly accelerated motion:
d = 0.5 * a * t^2
= 0.5 * 0.5806 m/s² * (3.10 s)^2
= 1.0153 m
Next, we can calculate the work done (W) by the elevator motor:
W = m * a * d
= 682 kg * 0.5806 m/s² * 1.0153 m
= 391.55 J
Now, to find the average power (P), we divide the work done by the time taken:
P = W / t
= 391.55 J / 3.10 s
= 126.36 W
To convert the power to horsepower, we can use the conversion factor: 1 horsepower (hp) = 745.7 watts.
Therefore, the average power of the elevator motor during this period is:
P = 126.36 W / 745.7
= 0.1696 hp
(b) During an upward trip with constant speed, the elevator does not accelerate, so the power required is only to counteract the force of gravity and friction. The power during an upward trip with constant speed is equal to the power required to overcome the force of gravity and friction.
The force of gravity (Fg) can be calculated using:
Fg = m * g
= 682 kg * 9.8 m/s²
= 6683.6 N
The power (P) required is given by the formula:
P = Fg * v
= 6683.6 N * 1.80 m/s
= 12030.5 W
To convert the power to horsepower:
P = 12030.5 W / 745.7
= 16.13 hp
Therefore, the power during an upward trip with constant speed is 16.13 horsepower.
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Find the final velocity if the initial velocity of 8 m/s with an acceleration of 7 m/s2 over a 3 second interval?
I don't know about it your answer will give another people
Answer: Let the final velocity be v.
Given,
Initial velocity(u)=8m/s
Acceleration(a)=7m/s2
Time(t)=3 sec
Then,
v=u+at
=8+7*3 m/s
=29m/s
Therefore, the final velocity is 29m/s.
Aria is riding her bike. She is bent slightly over, holding onto her handlebars. She wants to go faster. Which best explains what she should do? She should bend her hips so her head is closer to the handlebars. She should sit straight up on the bike, keeping her arms tight to her body. She should spread her arms wide while sitting straight in her seat. She should flap her arms up and down like a bird.
Answer:
She should bend her hips so her head is closer to the handlebars
Explanation:
Answer:
Yea its A
Explanation:
In the figure, a red car and a green car, identical except for the colour, move toward each other in adjacent lanes and parallel to the xâaxis. At time t=0, the red car is at x r =0, and the green car is at x g =220m. If the red car has a constant velocity of 20km/h, the cars pass each other at x=44.5m, and if it has a constant velocity of 40km/h, they pass each other at x=76.6m. What is the constant acceleration of the green car?
The constant acceleration of the green car which passes red color car is 2.81 m/s^2.
In this problem, the initial positions of the red and green cars are xr = 0 and xg = 220 m, respectively, and their initial velocities are vr = 20 km/h and vg = 0. When the red car has a velocity of 20 km/h, the cars pass each other at x = 44.5 m, and when the red car has a velocity of 40 km/h, they pass each other at x = 76.6 m.
We can use these two equations to solve for the acceleration of the green car. First, we convert the velocities from kilometers per hour to meters per second by dividing by 3.6. This gives us vr = 5.56 m/s and vg = 0 m/s.
Then, we can substitute these values into the equation for position and solve for the acceleration. When the red car has a velocity of 20 km/h, the equation becomes:
x = 0 + 5.56t + 1/2at^2
x = 44.5
Solving for a, we find that the acceleration of the green car is a = 2.61 m/s^2.
When the red car has a velocity of 40 km/h, the equation becomes:
x = 220 + 11.11t + 1/2at^2
x = 76.6
Solving for a, we find that the acceleration of the green car is a = 2.61 m/s^2.
When the red car has a velocity of 40 km/h, the equation becomes:
x = 220 + 11.11t + 1/2at^2
x = 76.6
Solving for a, we find that the acceleration of the green car is a = 3.02 m/s^2.
Since the acceleration is the same in both cases, we can take the average of these two values to find the constant acceleration of the green car. The average of 2.61 m/s^2 and 3.02 m/s^2 is 2.81 m/s^2.
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Find the induced voltage in the conductor of the Figure below where B = 0.04 ay Tan
U = 2.5 sin 103t az m/s.
The induced e.m.f is -0.02sin(10^3t) (V) which is option D
What is Induced Voltage?Induced voltage refers to the electrical voltage that is generated in a conductor or coil due to a changing magnetic field.
This phenomenon is known as electromagnetic induction and is the basis for many electrical devices such as generators and transformers.
Induced voltage can be calculated using Faraday's law, which states that the induced electromotive force (EMF) is equal to the rate of change of magnetic flux.
The induced voltage can be either positive or negative depending on the direction of the changing magnetic field and the orientation of the conductor or coil.
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What is the formula to calculate the thickness of a test tube?
Answer:
Having the inside dimensions (ID) and the outside dimensions (OD) will allow you to figure out the wall thickness on tubing. You would need to subtract the ID from the OD and then divide by two. This number is the wall thickness.
Explanation:
How does the ecotourism industry act as an ecosystem service that benefits tourists, the people that live in the area, and the people that work in the industry?
It promotes enjoyable experiences for both guests and hosts; It lessens the negative effects of tourism on the environment; It increases local residents' access to work and financial prospects; It promotes conservation by offering financial advantages in its direction.
What is ecotourism?The World Tourism Organization defines ecotourism as all forms of nature-based travel in which visitors' primary interests are in observing and appreciating the environment as well as the local cultures that are still practiced in natural settings.
Here are a few instances of ecotourism:
Visit places where there is nature (think of the flora, animals, and resources)discovering the heritage of the local culture.Ecologically sound wilderness excursions.volunteering or watching nature.trips devoted to environmental preservation efforts, like beach clean-ups.Learn more about ecotourism here:
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What type of circuit is shown
=When three resistors are connected in parallel, they form a parallel circuit. In a parallel circuit, each resistor is connected across the same two points, with the current split between the resistors.
In this configuration, the voltage across each resistor is the same, but the current through each resistor can be different. The total resistance of the circuit is calculated using the equation:
1/R_total = 1/R1 + 1/R2 + 1/R3
where R1, R2, and R3 are the resistance values of the individual resistors.
The total current in the circuit is equal to the sum of the currents through each resistor:
I_total = I1 + I2 + I3
where I1, I2, and I3 are the currents through each resistor.
The total power dissipated in the circuit can be calculated using the equation:
P_total = V² / R_total
where V is the voltage across the resistors.
In summary, when three resistors are connected in parallel, they form a parallel circuit, with each resistor connected across the same two points, and the current split between them. The total resistance, current, and power dissipated in the circuit can be calculated using the equations provided.
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an arrow is shot horizontally from the top of a tower at a speed of 15m/s and hits the ground with a speed of 25m/s. calculate the height of the tower
The height of the tower is 20.41 m.
To determine the height of the tower, we need to understand the concept of the energy conservation principle since the speed and acceleration due to gravity are involved in the system.
What is the energy conservation principle?The principle of energy conservation lets us know that in an isolated system, energy can neither be created nor destroyed.
It can be expressed using the formula:\(\mathbf{mgh = \dfrac{1}{2}mv_1^2 = \dfrac{1}{2}mv_2^2}\)
From the parameters given:The initial speed \(v_1\) = 15 m/sThe final speed \(v_2\) = 25 m/sBy applying the energy conservation principle, we have:
\(\mathbf{gh +\dfrac{1}{2}v_1^2 = \dfrac{1}{2}v_2^2}\)
\(\mathbf{h = \dfrac{v_2^2- v_1^2 }{2 \times g}}\)
\(\mathbf{h = \dfrac{25^2-15^2 }{2 \times 9.8}}\)
h = 20.41 m
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A device that changes only the direction of force is known as_____.
Answer:
The answer is a fixed pulley
A box of mass 210 kg is pulled from rest with a string of tension 1300n inclined at 35° to the horizontal. if the box moved with a speed of 10m/s and frictional force between the box and surface is 100 n, calculate the distance covered.
If A box of mass 210 kg is pulled from rest with a string of tension 1300n inclined at 35° to the horizontal. if the box moved with a speed of 10m/s and the frictional force between the box and surface is 100 n, Then the distance covered by the box is 10.89 meters.
To calculate the distance covered by the box, we need to analyze the forces acting on it and apply the work-energy principle.
Given:
Mass of the box, m = 210 kg
Tension in the string, T = 1300 N
The angle of inclination, θ = 35°
Frictional force, f = 100 N
Initial speed, u = 0 m/s
Final speed, v = 10 m/s
First, let's resolve the tension force into components parallel and perpendicular to the incline. The parallel component of the tension force can be calculated as:
T_parallel = T * cos(θ)
Next, let's calculate the net force acting on the box along the incline. The net force is given by:
Net force = T_parallel - f
Now, using Newton's second law, we can calculate the acceleration (a) of the box:
Net force = m * a
From the given information, we have the final velocity (v), initial velocity (u), and acceleration (a). We can use the following kinematic equation to calculate the distance covered (s):
v^2 = u^2 + 2as
Rearranging the equation, we get:
s = (v^2 - u^2) / (2a)
Now, let's plug in the given values and calculate the distance covered:
T_parallel = 1300 N * cos(35°) ≈ 1067.35 N
Net force = 1067.35 N - 100 N = 967.35 N
a = (967.35 N) / (210 kg) ≈ 4.61 m/s^2
s = (10 m/s)^2 - (0 m/s)^2 / (2 * 4.61 m/s^2) ≈ 10.89 m
Therefore, the distance covered by the box is approximately 10.89 meters.
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QUESTION 9
What determines the evolutionary path a star takes through its life?
O a. Diameter
O b. Who made it
O c. Color
O d. Mass
Answer:
Mass
Explanation:
In the core of the red giant, helium fuses into carbon. All stars evolve the same way up to the red giant phase. The amount of mass a star has determines which of the following life cycle paths it will take from there. The life cycle of a low mass star (left oval) and a high mass star (right oval).May 7, 2015
please teach me reflection of light
The speed of sound
Medium Air (0C) Air (20°C) Helium (0°C) Ethyl alcohol Water Human tissue (ultrasound Lead Aluminum Granite Diamond
Speed (m/s) 331 343 970 1170 1480 1540 1200 5100 6000 12.000
Oil explorers set off explosives to make loud sounds, then listen for the echoes from underground oil deposits. Geologists suspect that there is oil under 480-m-deep Lake Physics. It's known that Lake Physics is carved out of a granite basin. Explorers detect a weak echo 0.930 ss after exploding dynamite at the lake surface. Part A If it's really oil, how deep will they have to drill into the granite to reach it
Answer:
Explanation:
Let the required depth be d .
Sound will first travel trough 480 m deep lake . Then it will enter granite layer . Sound travelling through granite will reach oil level , get reflected and come back to the surface of lake as echo . Total time taken by sound to travel total distance is .93 s
Total distance = 2d + 2 x 480 m
= 2d + 960 m
speed of sound in granite is given as 6000 m / s and speed through water is 1480 m /s
total time taken
= 2d / 6000 + 960 / 1480 = .93
2d / 6000 + .6486 = .93
2d / 6000 = .2814
d= 844.2 m
What is the period of a blender blade that spins around 400 times in 5.0s
Answer:
f = 400 / 5 s = 80/sec frequency of revolution
P = 1/f = 1/(80/sec) = .0125 sec period of revolution
Water at 100 is taken off the stove and allowed to cool for 10 minutes. In this 10 minutes, the temperature decreased to 65. Given that the room temperature is 21, find the temperature of the water in degrees Celsius after an additional 5 minutes waiting time and on condition that the Newton’s Law of cooling is not violated.
Newton's Law of Cooling states that the rate of cooling of an object is proportional to the temperature difference between the object and its surroundings.
The rate of cooling of the water can be described as:dQ/dt = -k(T - Troom)
where Q is the amount of heat in the water, t is time, k is a constant, T is the temperature of the water, and Troom is the room temperature.
Using the given information, we can set up the following system of equations:
100 = k(100 - 21) (at t = 0) 65 = k(100 - 21) e⁽⁻¹⁰⁾k (at t = 10)
Solving for k in the first equation gives k = 1/79. Plugging this value into the second equation and solving for T gives T = 36.1 degrees Celsius.
Now, to find the temperature after an additional 5 minutes, we can use the same equation with a new time value:
T = (65 - Troom) e^(-k(10+5)) + Troom
Plugging in the values we know gives T = 30.4 degrees Celsius.
Therefore, the temperature of the water after an additional 5 minutes of cooling is approximately 30.4 degrees Celsius
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Please provide explanation!!!
Thank you.
Answer:
(a) 102 cm/s
(b) 0.490 cm²
Explanation:
(a) Use Bernoulli equation.
P₁ + ½ ρ v₁² + ρgh₁ = P₂ + ½ ρ v₂² + ρgh₂
0 + ½ ρ v₁² + ρgh₁ = 0 + ½ ρ v₂² + 0
½ ρ v₁² + ρgh₁ = ½ ρ v₂²
½ v₁² + gh₁ = ½ v₂²
½ (25.0 cm/s)² + (980 cm/s²) (5.00 cm) = ½ v²
v = 102 cm/s
(b) The flow rate is constant.
v₁ A₁ = v₂ A₂
(25.0 cm/s) (2.00 cm²) = (102 cm/s) A
A = 0.490 cm²
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Yes you are members of community
report of "fan made of plastic bottle" with string
Fan made of plastic bottle is an innovative way to reuse plastic bottles and can be easily made at home. This can be done by following simple steps, and a few materials are required to make it. The fan can be created by using a plastic bottle, scissors, string, a ruler, and a marker.
First, the bottle needs to be cut into half, and the upper part needs to be cut into three equal sections, then fold each section to make a blade. With the help of a ruler and marker, make a mark on each section, then make a hole in the center of each blade. Insert a string through the holes and tie the ends of the strings. The fan is ready to use by holding the string and swinging it back and forth.
The use of plastic bottle fans can significantly reduce the number of plastic waste and provide a practical solution to avoid environmental pollution. Besides, it is easy to make, and the materials are readily available, which can be used for various occasions, such as picnics, camping, or any outdoor activities.
In conclusion, the creation of a fan made of plastic bottle with string is an excellent way to reuse plastic bottles and can be made with simple steps. This project encourages everyone to contribute to environmental protection by utilizing what is available at home and reducing the number of plastic wastes.
For more such questions on Fan, click on:
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