HELP NOW PLEASE ANSWER THE QUESTION THE PICTURE IS ATTACHED BELOW

HELP NOW PLEASE ANSWER THE QUESTION THE PICTURE IS ATTACHED BELOW

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Answer 1

Answer:

C

Explanation:


Related Questions

How long will it take a person walking at 2.1 m/s to travel 13 m?

Answers

Answer:

I gonna give you the number so but you need to round 6.19047619048

Explanation:

This is a speed formula so you would use the formula speed=distance/timeYou need to rearrange it to time=distance/speedSo you need to divide 13m by 2.1 m/s

Would one way more or less on Earth's moon than on the dwarf planet Pluto?Hint: Earth's moon is slightly larger than pluto

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Despite the fact that the moon is slightly larger than Pluto, the two bodies are vastly different, and their unique characteristics make them both interesting objects of study for astronomers and space scientists.

Yes, the way things work on Earth's moon would be different from the way they work on Pluto, despite the fact that Earth's moon is slightly larger than Pluto's. This is because the characteristics of a celestial body depend on various factors such as its size, mass, density, and distance from the sun.

One major difference between the two is the gravitational force. The gravitational force on the moon is about one-sixth of that on Earth, while on Pluto, it is about one-fifteenth of that on Earth. This means that objects on the surface of the moon would weigh less than those on Pluto, and they would also fall more slowly.

Another significant difference is the surface conditions. The moon has a relatively smooth surface with little atmosphere and extreme temperature variations, while Pluto has a much more rugged terrain, a thin atmosphere, and a much colder surface with temperatures reaching -240°C.

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Escribir usando prefijos, en unidades del Sistema Internacional: longitud del ecuador, radios del núcleo y átomo, segundos de un milenio, edad de la Tierra, volumen de una pulga, masa del Sol, distancia de la estrella más cercana a la Tierra (después del Sol).

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la característica de los elementos

explain why many houses in hot areas like Mombasa should be painted white while those in colder places like timboroa should be painted with dark colours​

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Answer:

 In places of hot climate, it is advised that the outer walls of house be painted white because white color does not absorb any heat radiation from the sun which keep inside cool even if there is hot climate outside the house.

How much work is done by an engine to accelerate an
800 kg vehicle from 10 m/s to 20 m/s?

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We are unable to directly determine the work performed by the engine because the distance over which the force acts is unknown.

What work is involved in accelerating an 800 kg automobile from 5 meters per second to 10 meters per second?

This indicates that the effort expended to increase the car's speed will be equivalent to the change in kinetic energy of the vehicle. Thus, 30 kJ of effort must be performed.

What is the recipe for getting stuff done?

The work W is equal to the force f times the distance d, or W = fd, to mathematically describe this idea.

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You push with 10.0 N on a 5.0-kg block and there are no opposing forces. How fast will the block accelerate?

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To find the acceleration of the block, we'll use Newton's second law of motion, which states that the net force acting on an object is equal to its mass times its acceleration (F = m * a).

Given:
Force (F) = 10.0 N
Mass (m) = 5.0 kg

We need to find the acceleration (a) of the block. Since there are no opposing forces, the net force is equal to the force you are applying (10.0 N).

Using the formula F = m * a, we can solve for the acceleration:

10.0 N = 5.0 kg * a

Now, divide both sides by the mass (5.0 kg) to isolate the acceleration:

a = (10.0 N) / (5.0 kg)

a = 2.0 m/s²

So, the 5.0-kg block will accelerate at a rate of 2.0 m/s² when you apply a 10.0 N force without any opposing forces.

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a receiver in a football game is standing still, having just caught a pass. before he can move, a tackler, running at a velocity of 4.0 m/s, grabs him. the tackler holds onto the receiver, and the two move off together with a velocity of 3 m/s. the mass of the tackler is 100 kg. assuming that momentum is conserved, find the mass of the receiver.

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According to the law of conservation of momentum, the total momentum before the collision is equal to the total momentum after the collision.

Let's assume the mass of the receiver is denoted as "m" (in kg).

Before the collision:

Momentum of the tackler (p1) = mass of the tackler (m1) * velocity of the tackler (v1)

Momentum of the receiver (p2) = mass of the receiver (m) * velocity of the receiver (0, as the receiver is standing still)

After the collision:

Total momentum = momentum of the tackler + momentum of the receiver

The total momentum after the collision is:

Total momentum = (mass of the tackler + mass of the receiver) * velocity after the collision (3 m/s)

Since momentum is conserved, we can equate the total momentum before and after the collision:

p1 + p2 = (m1 * v1) + (m * 0) = (m1 * v1) = (m1 + m) * 3

Simplifying the equation, we get:

m1 * v1 = m1 * 3 + m * 3

m1 * v1 = 3 * (m1 + m)

Now we can substitute the given values into the equation. Given:

m1 = 100 kg

v1 = 4.0 m/s

Substituting the values, we have:

100 * 4.0 = 3 * (100 + m)

Simplifying the equation:

400 = 300 + 3m

3m = 100

m = 100 / 3 ≈ 33.33 kg

Therefore, the mass of the receiver is approximately 33.33 kg.

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How does the angle at which a ray of light strikes a pane of window glass compare with the angle at which it passes out the other side?.

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The angle at which a ray of light strikes a pane of window glass is smaller than the angle at which it passes out the other side.

When light go through window glass it will experience refraction due to change of light speed. The relation between angle of incidence and angle of refraction is given by the Snell's law:

n₁ sin∅₁ =  n₂ sin∅₂

Where:

n₁ = incident index (refractive index of medium 1)

n₂ = refraction index ((refractive index of medium 2)

∅₁ = incident angle

∅₂ = refraction angle

Typical refractive index for glass is around 1.5 while refractive index for air is 1.000273.

In the given case, the ray of light is from the window glass and pass out the other side. Hence,

n₂ = air

n₁ = glass

Since  n₁ > n₂ , the velocity in the air is greater than the velocity in the window glass. Hence, ∅₁ < ∅₂  or the incident angle is smaller than the refracted angle.

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How does the angle at which a ray of light strikes a pane of window glass compare with the angle at which


5. A ball rolls off a 1.5 m tall horizontal table and lands on the floor 0.70 m away.
A. How much time is the ball in the air?
B. How does that time compare with the time it takes for a dropped ball to fall that same distance.
C. What is the ball's velocity while it was on the table top?
D. What is the horizontal component of its velocity just prior to impact?
E. What is the vertical component of its velocity just prior to impact?
F. What is the magnitude of its velocity just prior to impact?
G. What is the direction of its velocity just prior to impact?

Answers

Take the starting position of the ball 1.5 m above the floor to be the origin. Then at time t, the ball's horizontal and vertical positions from the origin are

x = v₀ t

y = -1/2 gt²

where v₀ is the initial speed with which it rolls off the edge and g = 9.8 m/s².

A. The floor is 1.5 m below the origin, so we solve for t when y = -1.5 m :

-1.5 m = -1/2 gt²

⇒   t² = (3.0 m)/g

⇒   t = √((3.0 m)/g) ≈ 0.55 s

B. It would take the same amount of time.

C. The ball travels a horizontal distance of 0.70 m before reaching the floor, so we solve for v₀ with t = 0.55 s :

0.70 m = v₀ (0.55 s)

⇒   v₀ = (0.70 m) / (0.55 s) ≈ 1.3 m/s

D. At time t, the ball has horizontal and vertical velocity components

v[x] = 1.3 m/s

v[y] = -gt

so the horizontal component of the ball's final velocity vector is the same as the initial one, 1.3 m/s.

E. The vertical component of velocity would be

v[y] = -g (0.55 s) ≈ -5.4 m/s

F. The magnitude of the final velocity would be

√((1.3 m/s)² + (-5.4 m/s)²) ≈ 5.6 m/s

G. The final velocity vector makes an angle θ with the horizontal such that

tan(θ) = (-5.4 m/s) / (1.3 m/s)

⇒   θ = arctan(-5.4/1.3) ≈ -77°

i.e. approximately 77° below the horizontal.

What property of the wave is labeled H?
amplitude
crest
wavelength
trough

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Where’s the picture? Well I’ll still answer.if it’s at the top of the wave it’s crest, at the bottom of the wave, trough, if it’s the wave length, (the distance between each wave), amplitude is the highly of the wave

explain how muscles and bones work together to help bend the arm.

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Answer:

Bones make sure the arms structure is stable while the muscle is the one actively moving it and carrying out actions.

Is a tomatoes a substance of a acid or a base

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I think tomato is acid

Answer:

acid

Explanation:

tomatoes contain acids such as citric acid, ascorbic acid, abscisic acid etc.

this indicates that they are  acidic

water flows through a 2.9-cm -diameter hose 3.5 m/s . how long, in minutes, will it take to fill a 600 l child's wading pool?

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The time taken by a 2.9cm diameter water hose to fill the 600-liter pool is 4.58 minutes.

The diameter of the hose, d =2.9 cm. Velocity, v=3.3 m/s= 330 cm/s. The amount of water following through the cross-sectional area of the hose = πr². Diameter = 2.9 cm so radius, r=1.45 cm. A= 3.14×2.10 = 6.601 cm². The cross-sectional area of the hose is approximately 6.601 cm². To the volume of water that flows through the hose each second, multiply its velocity by the cross-sectional area of the hose. Volume/ second = 330×6.601=2178.61 cm³/sec . There are 1000 cm³ in one liter.  Total volume =600×1000 =600000 cm³. To determine the time in seconds, divide the total volume by the volume per second, t = 600000/2178.61 =275.40 sec. This is roughly 275 seconds.  Now convert 275 seconds into minutes, t (mins) = 275/60 =4.58 minutes.

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one of the students heads down to street level with another water balloon to meet the physics instructor. they stare each other down at a distance of 10.0 m apart (they are roughly the same height). after not too long of this, the physics instructor proceeds to run in the opposite direction. if the fastest speed at which the instructor can run is 7.80 m/s, at what speed must the student throw the balloon at 30.0 in order to land a headshot? rubric

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To calculate the required speed at which the student must throw the balloon to hit the physics instructor, we can use the concept of relative motion.

The physics instructor is running away from the student at a speed of 7.80 m/s. Therefore, to hit the instructor, the student must throw the water balloon with a velocity that cancels out the instructor's velocity and covers the distance of 10.0 m.

Since the distance and time are provided, we can use the formula:

Velocity = Distance / Time

Velocity = 10.0 m / 30.0 s = 0.333 m/s

To hit the instructor, the student must throw the water balloon with a velocity of 0.333 m/s.

Note: It's important to note that this calculation assumes ideal conditions and neglects factors such as air resistance and the exact trajectory of the balloon.

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A pinball bangs against a bumper of a pinball machine with a speed of 0.46 m/s. If the ball has a mass of 0.058 kg, what is the ball's kinetic energy?


This needs to be done in 3 mins

Answers

Answer:

Okay I might be wrong and sorry if i am either its 12 or 0.402

Explanation:

* I recommend the second one cause its more logical

Be aware I might be wrong

A garden boy holding a horse pipe ar 1m away from the ground is watering flowers on the ground .,3m away from his feet .if the pipe i sheld horizontally ,calculate the speed of the water from the pipe?

Answers

The speed of the water coming out of the pipe can be determined using the principles of projectile motion. The speed of the water is approximately 6.67 m/s.

To calculate the speed of the water coming out of the pipe, we can analyze the horizontal and vertical components of the motion separately. Since the garden boy is holding the pipe horizontally, the vertical component of the initial velocity is zero.

Considering the horizontal motion, the horizontal distance from the pipe to the flowers is 3 meters. Assuming no air resistance, the horizontal velocity remains constant throughout the motion. Therefore, the speed of the water equals the horizontal velocity.

To determine the horizontal velocity, we can use the equation of motion s = ut + 0.5at^2, where s is the horizontal distance (3 meters), u is the initial horizontal velocity, t is the time, and a is the horizontal acceleration (zero in this case).

Since the initial horizontal velocity (u) is equal to the speed of the water, we need to solve the equation for time (t) when the water reaches the flowers. The time can be calculated using the equation t = s/u.

Plugging in the values, we have t = 3 meters / u. Given that the vertical distance is 1 meter, the time taken for the water to reach the ground is the same as the time taken for it to reach the flowers.

Considering the vertical motion, we can use the equation s = ut + 0.5gt^2, where s is the vertical distance (1 meter), u is the initial vertical velocity (zero in this case), t is the time, and g is the acceleration due to gravity (approximately 9.8 m/s^2).

Plugging in the values, we have 1 meter = 0.5 × 9.8 m/s^2 × t^2. Solving for t, we find t ≈ 0.45 seconds.

Using the time calculated, we can substitute it into the equation t = 3 meters / u to solve for the speed of the water (u). Rearranging the equation, we have u ≈ 3 meters / t ≈ 3 meters / 0.45 seconds ≈ 6.67 m/s.

Therefore, the speed of the water coming out of the pipe is approximately 6.67 m/s.

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A large bar magnet (mass of 0.4 kg) exerts a 5 N force on a small bar magnet (mass of 0.1 kg) located 20 cm away. Calculate the force exerted by the small bar magnet on the large one *

Answers

Answer:

5 N

Explanation:

Given that,

A large bar magnet of mass 0.4 kg exerts a 5 N force on a small bar magnet (mass of 0.1 kg) located 20 cm away.

We need to find the force exerted by the small bar magnet on the large one.

We know that, every action has an equal and opposite reaction. Both action and reaction occur in pairs. The force acting on one object to another is same and in opposite direction on the other object.

Hence, the force exerted by the small bar magnet on the large one is also 5 N.

What is the Goldilocks zone?
A. It is the depth within the Earth’s crust where gold can be found.
B. It is a range of distance from a star where temperatures are right for liquid water to exist.
C. It is the distance from a star where pressures are right for an atmosphere to form.
D. It is the temperature range where porridge is just right.

Answers

The Goldilocks zone is a range of distance from a star where temperatures are right for liquid water to exist (option B).

What is the Goldilocks zone?

The Goldilocks zone is a zone around a star where a planet could experience temperatures like those on Earth, allowing for the possible existence of liquid water and of life.

The Goldilocks Zone also called habitable zone refers to that range of distance with the right temperatures for water to remain liquid.

Only one planet so far is known to be habitable for life and that planet is Earth. On Earth, water is a critical ingredient for life.

If a planet’s orbit takes it too close to its parent star, then it will be too hot for liquid water to exist, and if it’s too far out it will be too cold. However, the actual distances involved, that define habitable or Goldilocks zone vary between stars.

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If you have 5 protrons and 6 neutrons how many electrons would you need to make a neutral atom

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5 electrons
Don’t be confused about the neutron number because it doesn’t have a charge!
Proton number should equal electron number

PLEASEE helppp I really need it!

PLEASEE helppp I really need it!

Answers

Answer:

the correct answer is Jupiter has moons orbiting it

if a current is in a loop of wire and also in a magnetic field--the loop wants to ___.

Answers

If a current is in a loop of wire and also in a magnetic field, the loop wants to rotate.

This phenomenon is known as the principle of operation of a DC motor. The current-carrying loop placed in a magnetic field experiences torque, and this torque will cause the loop to rotate.

A DC motor is a type of electric motor that converts electrical energy into mechanical energy. It works on the principle that a current-carrying conductor in a magnetic field experiences a force that causes it to rotate. It consists of a stator, which generates a magnetic field, and a rotor, which carries the current and rotates.

The commutator is a device that allows the current to flow in the correct direction through the rotor windings. As the rotor rotates, the brushes on the commutator change the direction of the current flow, allowing the rotor to continue to rotate.

The speed of the DC motor can be controlled by varying the applied voltage or the strength of the magnetic field. The direction of rotation can be reversed by reversing the polarity of the applied voltage or by changing the polarity of the magnetic field.

DC motors are used in a variety of applications, including electric vehicles, robotics, and industrial machinery.

In summary, when a current-carrying loop is placed in a magnetic field, it experiences a torque that causes it to rotate. This principle is the basis for the operation of a DC motor.

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An industrial sized helium tank holds helium at a pressure of Po = 190 atm. From the tank, a volume of Vo = 0. 31 L expands to fill a birthday balloon at a pressure of Pf = 1. 19 atm. Determine the volume Vf that the helium takes up inside the balloon.

Answers

The volume of helium that the balloon can hold is 0.00182 L or 1.82 ml

The volume of helium inside a balloon can be determined by the initial volume of the tank, the pressure of the tank, the pressure of the balloon, and the final volume of the balloon. If the initial pressure of the helium tank is Po and the volume is Vo, the amount of helium in the tank is given by n = \frac{(Po)(Vo)}{(RT)}, where R is the ideal gas constant and T is the absolute temperature. To determine the volume of helium inside a balloon, the amount of helium in the tank must be equal to the amount of helium in the balloon. At constant temperature, the relationship between pressure and volume is given by the ideal gas law PV = nRT. Solving for the final volume of the balloon,

Vf = \frac{(Pf)(Vo)(RT)}{[(Po)(T)]}

Vf =\frac{ (1.19 atm)(0.31 L)(0.0821 L.atm/mol.K)(298 K)}{[(190 atm)(298 K)}]

Vf = 0.00182 L

Hence,The volume of helium that the balloon can hold is 0.00182 L or 1.82 ml.

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What is the magnitude of the net force on the first wire in (figure 1)? express your answer in newtons

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0.00025 N is the magnitude of the net force on the first wire in (figure 1).

What is net force?

The total of all forces exerted on an item is known as the net force. A mass can accelerate due to net force. A body is subject to another force whether it is at rest or in motion. When there are a lot of forces acting on a system, the phrase "net force" is employed.

From the diagram, first wire has an attracting force from third wire at 0.04 m distance and a repelling force from second wire at 0.02 m distance.

Expression of the force is -

F = [µ ×π×(I)² × L] / (2πd)

When d = 0.02 m,

or, F = [4 ×π× 10⁻⁷(10)² × 0.50] / (2π × 0.02)

or, F = 0.0005 N

And when d = 0.04 m,

or, F = [4 ×π× 10⁻⁷(10)² × 0.50] / (2π × 0.04)

or, F =  0.00025 N

So, the net force on first wire  = 0.005 - 0.00025

= 0.00025 N repelling or upward.

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The complete question is as follows:

What is the magnitude of the net force on the first wire in (Figure 1)?

Express your answer in newtons.

What is the magnitude of the net force on the first wire in (figure 1)? express your answer in newtons

Please help I'm so lost.
Erbium-165 has a half-life of 10.4 hours. If you start with 1,000 grams of erbium-165, how much time will it take to have 125 grams of erbium-165 left in the sample?

A. 41.6 hours
B. 31.2 hours
C. 10.4 hours
D. 20.8 hours

Answers

If you start with 1,000 grams of erbium-165, the time it  will take to have 125 grams of erbium-165 left in the sample is 20.8 hours.

option D is the correct answer.

What is half life?

Half life is the time that it takes for half of the original value of some amount of a radioactive element to decay.

If you start with 1,000 grams of erbium-165, the time it  will take to have 125 grams of erbium-165 left in the sample is calculated as follows;

1,000 ---------- 0 time

500 ----------- 10.4 hours

125 ------------- 20.8 hours

Thus, from the calculation done above, we can see that If you start with 1,000 grams of erbium-165, the time it  will take to have 125 grams of erbium-165 left in the sample is 20.8 hours.

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which of the following best explains the picture

Answers

According to the illustration, the graphic illustrates the arrow and the intended target.

To target something or someone means to aim at them specifically. To aim a gun at a shooting range is an example of a target. To focus all of your efforts on one objective is an example of a target. verb. A target is an item or objective that is the subject of an aim.

Two or three arrows have been depicted in the green area of the image, which is located very distant from the red location. Given that they are all in the same location, this illustrates the idea of weak or low precision and excessive precession.

As a result, choice B is accurate.

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Problem 3. High concentration of coliform bacteria is detected in a water well in Oklahoma. Shock chlorination was applied to disinfect the well by supplying a high concentration of chlorine to the water over a short period. After the disinfection treatment, the concentration of coliform bacteria c , is expected to decrease according to \[ c=77 e^{-1.5 t}+20 e^{-0.08 t} \] Where t is time in hours, and c is the bacteria concentration in ppm. Determine the time required for the bacteria concentration to be reduced to 15ppm using the Newton's method with an initial guess of t=6 and a stopping criterion of 1% (tol=0.01). Check your result with fsolve function in Python's scioy library.

Answers

The time required for the bacteria concentration to be reduced to 15ppm using the Newton's method is 8.12 hours.

Finding the roots of a differentiable function F, which are answers to the equation F (x) = 0, using Newton's technique is an iterative process. To solve this problem, we can use Newton’s method with an initial guess of t=6 and a stopping criterion of 1% (tol=0.01). The formula for Newton’s method is:

xₙ₊₁ = xₙ - f(xₙ)/f'(xₙ)

where xₙ₊₁ is the next approximation, xₙ is the current approximation, f(xₙ) is the function value at xₙ, and f'(xₙ) is the derivative of the function at xₙ.

For this problem, we have:

f(t) = 77 \(e^{-1.5 t}\) +20 \(e^{-0.08 t}\) - 15

f’(t) = -115.5 \(e^{-1.5 t}\) - 1.6 \(e^{-0.08 t}\)

After using the Newton’s method with an initial guess of t=6 and a stopping criterion of 1% (tol=0.01), the results are as follows:

t = 4.139 hours

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PLS PLS HELP I'LL MARK YOU BRAINLISTTT!!!!

PLS PLS HELP I'LL MARK YOU BRAINLISTTT!!!!

Answers

Answer:

i think it might be 5

sry if im wrong

I think it might be ,5


-15 +20 =5

If red light of wavelength 700 min in air enters glass with index of refraction 1 5 what wavelength lambda of the light in the glass? Express your answer in nanometers to three significant figures. lambda nm Two important things happen to light when it strikes a tram parent boundary it gets reflected and it gets refracted When you see your reflection in glass, you are seeing the result of reflection from a transparent boundary In the figure the ray moving toward the air/glass interface is called the incident ray The ray leaving the boundary in air is called the reflected ray. The ray leaving Air the boundary inside the glass is called the refracted ray Rejection from a mirror and reflection from a transparent boundary Both obey the law of reflection theta_a = theta_r. where theta_a is the angle of incidence (the angle between the incoming ray and the normal to the surface), and theta_t, is the angle of reflection (the angle between the normal time and the reflected ray) If Iight strikes the airless interface at an angle 32.0 degree to the normal what is the angle of reflection theta_1? Express your answer in degrees to three significant figures ANSWER theta_1 = degrees The second important effect of light striking a transparent boundary is refraction is the bending of light caused by the difference in the speed of light between materials when light moves into a medium with a higher index of refraction (i. e. tower spend of light), the refracted ray has a smaller angle to the normal than the incident ray Snell's law this angle of refraction, theta_b, n_a sin(theta_a) = n_b, sin(theta_b) Since we are assuming that the speed of light in air is very close to the speed of light in vacuum, you will use n_a = 1.00 in this problem

Answers

Hi! I understand you have two questions related to light entering a glass with an index of refraction 1.5. Let's address them one by one. The wavelength of the red light in the glass is approximately 467 nm to three significant figures. The angle of reflection (theta_1) is 32.0 degrees to three significant figures.


1) You want to find the wavelength (lambda) of red light with a wavelength of 700 nm in air, when it enters glass with an index of refraction 1.5.

To find the wavelength of light in the glass, use the formula:

λ_glass = λ_air / n

where λ_glass is the wavelength in the glass, λ_air is the wavelength in air (700 nm), and n is the index of refraction (1.5).

λ_glass = 700 nm / 1.5

λ_glass ≈ 466.7 nm

So, the wavelength of the red light in the glass is approximately 467 nm to three significant figures.

2) You want to find the angle of reflection (theta_1) when the light strikes the air-glass interface at an angle of 32.0 degrees to the normal.

The law of reflection states:

theta_a = theta_r

where theta_a is the angle of incidence (32.0 degrees) and theta_r is the angle of reflection.

Since the angles are equal according to the law of reflection:

theta_1 = theta_a = 32.0 degrees

So, the angle of reflection (theta_1) is 32.0 degrees to three significant figures.

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The Kentucky Derby is a 1¼ mile race. Mandaloun ran it in 1.52 minutes. Hot Rod Charlie ran at a speed of .79 miles per minute. Who won the race?

Answers

Answer:

Mandaloun won the race.

Explanation:

First, we will calculate the time taken by the Hot Rod Charlie:

\(s = vt\\t = \frac{s}{v}\)

where,

t = time taken by Hot Rod Charlie = ?

s = distance covered = 1.25 miles

v = speed of Hot Rod Charlie = 0.79 miles/min

Therefore,

\(t = \frac{1.25\ miles}{0.79\ miles/min} \\t = 1.58 min\)

Since Hot Rod Charlie took more time (1.58 min) than the Mandaloun (1.52 min).

Therefore Mandaloun won the race.

an experiment was conducted to determine the effect of alcohol on driving. subjects consumed varying amounts of alcohol. then they drove around barrels. judges rated their performances. the independent variable in the experiment was the group of answer choices type of car they drove amount of alcohol consumed difficulty of driving around the barrels performance of the subjects

Answers

In the described experiment, the independent variable would be the amount of alcohol consumed. The researchers manipulated this variable by varying the amounts of alcohol consumed by the subjects.

The other answer choices mentioned are not independent variables in this context:

Type of car they drove: The type of car driven by the subjects is not manipulated in this experiment. It could be considered as a potential confounding variable that should be controlled or accounted for in the study design.Difficulty of driving around the barrels: This is not an independent variable since it is not being systematically manipulated by the researchers. The difficulty level could be a controlled factor in the experiment, but it is not the main variable of interest.Performance of the subjects: Performance is the dependent variable in this experiment. It is the variable being measured or observed to determine the effect of alcohol consumption. The researchers would collect data on the subjects' driving performance and judges' ratings to assess the impact of alcohol.

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