Answer:
the path the object follows is called its trajectory so A. trajectory
What are the properties of mars
Answer:
Explanation:
Its surface is rocky, with canyons, volcanoes, dry lake beds and craters all over it. Red dust covers most of its surface. Mars has clouds and wind just like Earth
Put the following types of electromagnetic radiation in order from longest to shortest wavelength:
Radio waves, microwaves, infrared, visible light, ultraviolet, x-rays and finally gamma rays is the order of longest to shortest wavelength of electromagnetic spectrum.
What is electromagnetic spectrum ?The oscillations between an electric field and a magnetic field produce waves known as electromagnetic waves, or EM waves. In other words, magnetic and electric fields that are oscillating make up EM waves. Electromagnetic spectrum is a set of electromagnetic waves generated by sources of the electromagnetic field that propagate at the speed of light.
The parts of the electromagnetic spectrum are referred to as gamma rays, X-rays, ultraviolet radiation, visible light, infrared radiation, and radio waves, in that sequence from highest to lowest energy.
Radio waves, microwaves, infrared, visible light, ultraviolet, x-rays and finally gamma rays is the order of longest to shortest wavelength of electromagnetic spectrum.
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kylie leans a 30-foot ladder against a wall so that it forms an angle of 74 ∘ ∘ with the ground. what’s the horizontal distance between the base of the ladder and the wall? round your answer to the nearest hundredth of a foot if necessary.
To find the horizontal distance between the base of the ladder and the wall, we need to use trigonometry. The horizontal distance is the adjacent side of the triangle formed by the ladder, the wall, and the ground. The ladder is the hypotenuse of the triangle, and the angle formed between the ladder and the ground is 74 degrees.
We can use the cosine function to find the adjacent side:
cos(74) = adjacent / 30
adjacent ≈ 8.27 feet
Therefore, the horizontal distance between the base of the ladder and the wall is approximately feet. Rounded to the nearest hundredth of a foot, the answer is 8.27 feet.
To find the horizontal distance between the base of the ladder and the wall, we can use the trigonometric function cosine. Given that Kylie leans a 30-foot ladder against a wall, forming an angle of 74° with the ground, we can apply the cosine function as follows:
Step 1: Identify the known values:
- Adjacent side (the horizontal distance) = x
- Hypotenuse (the ladder) = 30 feet
- Angle between the ground and the ladder = 74°
Step 2: Apply the cosine function:
cos(74°) = adjacent side (x) / hypotenuse (30 feet)
Step 3: Solve for x:
x = 30 feet * cos(74°)
Step 4: Calculate the value of x:
x ≈ 30 * 0.2756 ≈ 8.27 feet (rounded to the nearest hundredth of a foot)
So, the horizontal distance between the base of the ladder and the wall is approximately 8.27 feet.
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A 4.0 kg object will have a weight of approximately 14.8 N on Mars. What is the gravitational field strength on M
Answer:
Gravitational field strength =weight/mass
Explanation:
14.8N/4.0kg
3.7N/kg
In the product 602, what does the coefficient mean?
O There are 12 molecules of O2,
O There are 8 molecules of O2,
O There are 6 molecules of O2.
O There are 2 molecules of O2.
Answer:
c. there are 6 molecules of O2
Explanation:
Answer:
yup what he said
Explanation:
What is the force two changed objects exert on one another if they are 9 meters apart and one has a charge of 2.5 x 10^-6 C and the second has a charge 0f 4.5 x 10^-7 C
Answer:
The force exerted between the two charges is 0.0001248N
Explanation:
we will be using Columb's law to solve this problem.
Columb's law explains that the Force between two charged bodies is directly proportional to the product of their charges and inversely proportional to the square of the distance between them.
Mathematically,
\(F = K\frac{Q_1 \times Q_2}{r^2}\)
WHere K = constant of proportionality = \(8.9875 \times 10^9 N m^2/c^2\)
\(F = 8.9875 \times 10^9 \times\frac{2.5 \times10^{-6} \times 4.5 \times 10^{-7}}{9^2}= 0.0001248N\)
The force exerted between the two charges is 0.0001248N
The voltage between two parallel plates separated by a distance of 3. 0 cm is 120 v. the electric field between the plates is:__________
The electric field between the plates is 4000V/m.
To find the answer, we have to know more about the electric field.
How to find the electric field?We have the expression for electric field as,\(E=\frac{V}{L} \\\)
It is given that the voltage between two parallel plates separated by a distance of 3. 0 cm is 120 v.We have to find the electric field.\(E=\frac{120}{3*10^{-2}} =4000V/m\)
Thus, we can conclude that, the electric field between the plates is 4000V/m.
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A progressive wave equation is represented by y=Asin2π(0. 15t-0. 1x). Find the
period,
amplitude,
frequency,
wavelength,
velocity
Given that the progressive wave equation is represented by y=Asin2π(0.15t-0.1x). Let's find the period, amplitude, frequency, wavelength, and velocity.
The wave equation is represented by y=Asin2π(0.15t-0.1x). The standard wave equation can be written asy = Asin(kx-ωt + Φ)Where,k = wave numberω = angular frequencyΦ = phase angle for the given equation, k = 0.1 and ω = 0.15.Amplitude:
Amplitude = A = maximum displacement from the mean position.A = 1Frequency: Frequency is the number of complete oscillations made by a point on the wave in one second. It is denoted by f.f = ω/2πFrequency, f = 0.15/2π = 0.0238 HzPeriod: Period is the time taken by one complete oscillation.
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If you determined the electric field intensity in a field using a test charge of 1.0×10−6 C and then repeated the process with a test charge of 2.0×10−6 C, would the forces on the charges be the same? Would you find the value for E?
The force F exerted by an electric field on a test charge q is given by:
\(F=qE\)From this equation we notice that if we change the test charge then the force will change as well.
Therefore, the forces on the charges will not be the same.
We can't determine the electric field without further information on the problem; we need the force on one of the test charges to determine the magnitude of the field.
Highway safety engineers want to design roadside barriers that will crumple in the event that a car drives off the road and collides with them, slowing down the car more gradually. The average person has a mass of 68 kg and travels on a highway at a velocity of 27 m/s. If the engineers know that the maximum force that a person can safely withstand is 1180 N, approximately how much time is required to crumple the barrier to safely slow the person with this force?
It would take 1.556 seconds for the barrier to crumple and safely slow down the person with a force of 1180 N.
To calculate the time required to crumple the barrier and safely slow down the person, we can use the concept of impulse.
The impulse, denoted by J, is defined as the product of force and time, and it represents the change in momentum of an object. In this case, the impulse required to safely slow down the person can be calculated using the maximum force and the person's initial momentum.
The momentum of a person is given by the product of their mass and velocity:
Momentum = mass × velocity
Given that the person's mass is 68 kg and their velocity is 27 m/s, the initial momentum is:
Initial momentum = 68 kg × 27 m/s
To safely slow down the person, the impulse provided by the barrier should be equal to the change in momentum.
Therefore, we have:
Impulse provided by barrier = Final momentum - Initial momentum
Since the person is brought to rest, the final momentum is zero. Thus, we have:
Impulse provided by barrier = -Initial momentum
Now we can express the impulse in terms of force and time:
Impulse provided by barrier = Force × Time
Plugging in the known values, we can solve for time:
-Initial momentum = Force × Time
68 kg × 27 m/s = 1180 N × Time
Simplifying the equation, we find:
Time = (68 kg × 27 m/s) / 1180 N
Evaluating the expression:
Time = 1836 kg·m/s / 1180 N
Finally, converting kg·m/s to seconds, we get:
Time ≈ 1.5559 seconds
Therefore, it would take approximately 1.556 seconds for the barrier to crumple and safely slow down the person with a force of 1180 N.
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Imagine that you have been chosen to fly on the first
space shuttle that could travel at the speed of light.
Write a story about the trip that you would take
through space. Be sure to mention ALL of the
celestial objects that you see along the way, where
they are found, and their relative size.
My Trip through Space...
To imagine that you were chosen to fly the first space shuttle that could travel at the speed of light and write a story about the trip, it is necessary to research astronomy in more detail to generate a more consistent essay.
What would it be like to travel at the speed of light?In science fiction films, it is common to portray stars as white, illuminated and stretched lines, demonstrating speed, but this is an unfounded reasoning, since light has no color and stars do not move at that speed.
Therefore, a trip at the speed of light would be common, the only difference would be the reduction of time when arriving at the places, as for example, according to research, a trip from Earth to Pluto at the speed of light would take about five and a half hours.
It would also not be possible to see the stars as in the movies, as their photons are not visible.
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What is the mass of a crate if a net force of 12 N gives the crate an acceleration of 0.20 m/s2?
a person stands on a scale in an elevator. his apparent weight will be the greatest when the elevator a person stands on a scale in an elevator. his apparent weight will be the greatest when the elevator is moving upward at constant velocity. is moving downward at constant velocity. is standing still. is accelerating downward. is accelerating upward.
His apparent weight will be the greatest when the elevator accelerating upward.
What is accelaration?acceleration is the rate of to the change of the velocity of an object with respect by time.
When a person stand in an elevator moving upwards, he feels heavier because the elevator's floor presses harder on his feet, and the scale will show a higher reading than when the elevator is at rest.
According to Newton's second law
R = mg + ma
where;
R is the reading of the scale = apparent weight of the person
mg is the normal weight of the person
ma is the upward force acting on the person
Therefore, his apparent weight will be the greatest when the elevator is accelerating upward
(c) is accelerating upward
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A 1100 N crate slides 12 m down a ramp that
makes an angle of 31° with the horizontal. If the crate slides at a constant speed, how much thermal energy is created?
Answer: When a crate slides down a ramp at a constant speed, it means that the net force acting on the crate is zero. In this case, the force of gravity acting downward is balanced by the force of friction acting upward along the ramp. The work done by friction in this scenario converts mechanical energy into thermal energy, resulting in an increase in thermal energy.
To calculate the amount of thermal energy created, we need to determine the work done by friction. The work done by friction can be calculated using the formula:
Work = Force × Distance × Cosine of the angle between the force and the displacement
In this case, the force of friction is equal to the force of gravity component parallel to the ramp, which can be calculated as:
Force of gravity parallel to the ramp = Weight of the crate × Sin(θ)
where θ is the angle of the ramp (31°) and the weight of the crate is equal to its mass multiplied by the acceleration due to gravity.
Weight of the crate = mass × acceleration due to gravity
Once we calculate the force of friction, we can then determine the work done by friction using the given distance (12 m).
The thermal energy created is equal to the work done by friction. Remember that work and energy are measured in the same units (joules).
Let's calculate the thermal energy created step-by-step:
Calculate the weight of the crate:
Weight of the crate = mass × acceleration due to gravity
Calculate the force of gravity parallel to the ramp:
Force of gravity parallel to the ramp = Weight of the crate × Sin(θ)
Calculate the work done by friction:
Work = Force of friction × Distance × Cos(θ)
The thermal energy created is equal to the work done by friction.
Please provide the mass of the crate, and I can help you calculate the thermal energy created.
a thin lens with f=+15 cm is used to project the image of an object on a screen which is placed 80 cm from the object. find the two possible object distances and for each of the values state/show whether the image is (real or virtual), (upright or inverted), and (larger or smaller). please state all three of these last options for the values.
The two possible object distances for the given thin lens with f=+15 cm are 55 cm and 125 cm. For an object distance of 55 cm, the image formed is real, inverted, and smaller. For an object distance of 125 cm, the image formed is virtual, upright, and larger.
Focal length (f) = +15 cm
Distance from object to screen (dₒ) = 80 cm
To find the object distances, we can use the lens formula:
1/f = 1/dₒ + 1/dᵢ
where dᵢ is the distance from the lens to the image.
For the first object distance:
1/f = 1/dₒ + 1/dᵢ
1/15 = 1/80 + 1/dᵢ
Simplifying the equation, we find:
1/dᵢ = 1/15 - 1/80
1/dᵢ = (80 - 15) / (15 * 80)
1/dᵢ = 65 / (15 * 80)
dᵢ = 1 / (65 / (15 * 80))
dᵢ = (15 * 80) / 65
dᵢ = 1200 / 65
dᵢ ≈ 18.46 cm
Therefore, the first object distance is approximately 55 cm.
For the second object distance:
1/f = 1/dₒ + 1/dᵢ
1/15 = 1/80 + 1/dᵢ
Simplifying the equation, we find:
1/dᵢ = 1/15 - 1/80
1/dᵢ = (80 - 15) / (15 * 80)
1/dᵢ = 65 / (15 * 80)
dᵢ = 1 / (65 / (15 * 80))
dᵢ = (15 * 80) / 65
dᵢ = 1200 / 65
dᵢ ≈ 18.46 cm
Therefore, the second object distance is approximately 125 cm.
Now, let's analyze the characteristics of the images formed for each object distance.
For the first object distance (55 cm):
The image formed is real since the image distance (dᵢ) is positive. It is inverted because the image distance is positive, indicating that the image is formed on the opposite side of the lens compared to the object. It is smaller because the object distance is closer to the lens than the focal point, resulting in a diminished image.
For the second object distance (125 cm):
The image formed is virtual since the image distance (dᵢ) is negative. It is upright because the image distance is negative, indicating that the image is formed on the same side of the lens as the object. It is larger because the object distance is farther away from the lens than the focal point, resulting in an enlarged image.
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On a separate sheet of paper:
17. David kicks a football at 43.0° to the horizontal at 67.0 m/s from the ground.
a) How high did Aaron kick the ball?
b) Find the time of travel.
c) How far away does it hit the ground?
18. Emiliano kicks a soccer ball to score a goal at 18.0° to the horizontal at 43.0 m/s from the
ground. She is standing 100 m away from the goal.
a. How high did Hailey kick the ball?
b.
Find the time of travel in the air.
c. How far away does it hit the ground? Will she score
Answer of the all following horizontal force question as follows.
What is horizontal force?Horizontal force is a type of force that acts parallel to the ground, or in a horizontal direction. It is also known as a lateral force. This type of force is often encountered in everyday life and in physics.
a) The height of Aaron's kick can be calculated using the equation: h = (v^2sin2θ)/2g, where v is the initial velocity, θ is the angle of projection and g is the acceleration due to gravity. Plugging in the given values, we get h = (67^2sin(43))/ (2*9.8) = 36.3 m.
b) The time of travel can be found using the equation: t = (2v sinθ)/g. Plugging in the given values, we get t = (2*67sin(43))/9.8 = 7.72 s.
c) The distance of the kick can be found using the equation: d = (v^2sin2θ)/g. Plugging in the given values, we get d = (67^2sin(2*43))/9.8 = 130.3 m.
18-
a. Hailey kicked the ball to a height of 21.5 m.
b. The time of travel in the air was 2.5 s.
c. The ball hit the ground 91 m away from the goal. Since she was standing 100 m away, she will not score a goal.
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Which has more momentum: a 20,000 kg cement truck traveling at 5 m/s or a 1000 kg race car traveling at 90 m/s
Hi there!
Recall the equation for momentum:
\(\large\boxed{p = mv}\)
p = linear momentum (kgm/s)
m = mass (kg)
v = velocity (m/s)
We can calculate each object's momentum and compare.
Cement truck:
\(p = 20000 \cdot 5 = 100000kg\frac{m}{s}\)
Race car:
\(p = 1000 \cdot 90 = 90000 kg\frac{m}{s}}\)
Since 100,000 > 90,000, the cement truck has the greater momentum.
उत्तोलक हुन् ?
Calculate the load arm and effort arm from the following figure if the lever is in
balanced condition. In which class of lever do spoon and scissor belong to.(Ans: 3m, 15 m)2+1
Answer:
The length of the load arm is 3 m
The length of the effort arm is 15 m
Spoons and scissors are class 1 levers
Explanation:
The data given in the force diagram of the lever (machine) are;
The length of the lever = 18 m = (Length of effort arm) + (Length of load arm)
The force applied at the effort = 100 N
The load lifted by the lever = 500 N
The mechanical advantage, MA is given as follows;
MA = Load/Effort = (Length of effort arm)/(Length of load arm)
∴ MA = 500 N/(100 N) = 5
Let 'x' represent the length of the effort arm, and let 'y', represent the length of the load arm, we have;
x + y = 18...(1) (given)
MA = 5 = x/y
∴ x = 5·y...(2)
Substituting the value of 'x' in equation (1) with x = 5·y gives;
x + y = 5·y + y = 6·y = 18
∴ y = 18/6 = 3
y = 3
The length of the load arm, y = 3 m
x = 5·y = 5 × 3 = 15
x = 15
The length of the effort arm, x = 15 m
When lifting food with a spoon, the fulcrum, which can be taken as the edge of the plate or the supporting finger, is in between bowl of the spoon and the point of application of the thumb towards the extremities of the spoon handle
Therefore a spoon is a class 1 lever
The pivot of a scissors is in between the item being cut (the load) and the holes where the finger applies an effort
Therefore, a scissors is a class 1 lever.
A 230 v mains powered electrical drill draws a current of 2.5 A calculate the power of the drill at use
Compared to the inertia of a 2.0 kg ball, the inertia of a 4.0 kg ball is
A) Half as great
O B) twice as great
the same
OD) four times as great
A car is driving down the road at 30 MPH. A bug hits the windshield with a force of 50N. With what force does the car hit the bug?
Group of answer choices
80N
20N
50N
300N
Answer:
80 N
Explanation:
The windshield is a part of the car and the bug hits it so the bug hits the car. they both are in opposite directions so their total force will be 80N
Which phase changes are endothermic?
A person on a bicycle travels a distance of 12.5 km in 2.1 hrs, what was the speed of the person on the bicycle?
Answer:
5.9 km/hour
Explanation:
divide 12.5 by 2.1 and the answer is 5.9
The position of an object with respect to time, moving along the x-axis is given by x = b t3. Calculate the acceleration of the object if b = 3 m/s3.
Answer:
The acceleration of the object measured in \(\frac{m}{s^{2}}\), as a function of time is equal to:
\(a = 18\cdot t\)
Explanation:
The acceleration function is obtained by deriving position function twice:
\(a = \frac{dv}{dt} = \frac{d^{2}x}{dt^{2}}\)
\(x = 3\cdot t^{3}\)
\(v = 9 \cdot t^{2}\)
\(a = 18\cdot t\)
The acceleration of the object, measured in \(\frac{m}{s^{2}}\), as a function of time is equal to:
\(a = 18\cdot t\)
Can somebody help me understand this
A spoon becomes warmer as it rests in a cup of hot soup.
conduction
convection
radiation
convection
The correct response is conduction.
Conduction provides an explanation for how heat is transferred from the hot soup to the spoon. The mechanism of heat transfer is known as conduction. It involves materials or objects coming into direct touch with one another.
In this instance, the spoon is in direct contact with the hot soup, allowing heat energy to transfer from the soup to the spoon. The particles of the spoon vibrate more vigorously as particles in the soup have a higher temperature, which raises the temperature of the spoon.
Whereas convection is the process of transferring heat by the circulation or stirring of a fluid, such as hot soup. In this situation, radiation which is the transfer of heat by electromagnetic waves is not happening. Examples of radiation: are sunrays, microwaves from an oven, X-rays from an X-ray tube, and gamma rays from radioactive elements.
Correct question:
"A spoon becomes warmer as it rests in a cup of hot soup." Choose the phenomenon causing this among the given options:
conduction
convection
radiation
convection
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determine the volume of one mole of an ideal gas at 25 c and at 0.915 kpa
The volume of one mole of an ideal gas at 25°C and 0.915 kPa is approximately 0.2709 cubic meters.
To solve this problemWe can use the ideal gas law equation:
PV = nRT
Where
P = Pressure (in Pascals)V = Volume (in cubic meters)n = Number of molesR = Ideal gas constant (8.314 J/(mol·K))T = Temperature (in Kelvin)The provided temperature must first be converted from Celsius to Kelvin:
T(K) = T(°C) + 273.15
T(K) = 25 + 273.15
T(K) = 298.15 K
Now, we can rearrange the ideal gas law equation to solve for V:
V = (nRT) / P
The pressure (P) is given to us as 0.915 kPa. The ideal gas law, however, calls for pressure to be expressed in Pascals, thus we must convert it:
P(Pa) = 0.915 kPa * 1000
P(Pa) = 915 Pa
Now, we can substitute the values into the equation:
V = (1 mol * 8.314 J/(mol·K) * 298.15 K) / 915 Pa
Calculating the expression:
V ≈ 0.2709 cubic meters
So, the volume of one mole of an ideal gas at 25°C and 0.915 kPa is approximately 0.2709 cubic meters.
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why does somthing fall faster if it is heavier
why does something fall faster if it is heavier?
➪ First of all I would like to inform you that this statement is not true. The acceleration does not depend on the mass of the object. Heavier things have a greater gravitational force AND heavier things have a lower acceleration. It turns out that these two effects exactly cancel to make falling objects have the same acceleration regardless of mass.
Lets see
According to Newton's second law
\(\\ \rm\rightarrowtail F=ma\)
F denotes to forcem denotes to massa denotes to acceleration\(\\ \rm\rightarrowtail F\propto m\)
If mass is more force of gravity is more.\(\\ \rm\rightarrowtail m\propto \dfrac{1}{a}\)
If mass is more acceleration is less or air resistance is less .So heavier objects fall faster than lighter ones .
You lift a 10-kg box to a height of 1m. How much work do you do on the box when you lift it from the ground? (g= 9.81 m/s2)
Answer:
98.1 Joule
Explanation:
Solution,
⇒Mass(m)=10kg
⇒Weight(F)=Mg=10×9.81=98.1N
⇒Distance(d)=1m
Now,
Work done=F×d
=98.1×1
=98.1J
The work done on the box when lifting it from the ground is 98.1 Joules (J).
To calculate the work done on the box when you lift it from the ground, you can use the formula:
Work (W) = Force (F) × Distance (d) × cos(θ)
In this case, the force (F) is the weight of the box, which is equal to its mass (m) multiplied by the acceleration due to gravity (g):
F = m × g
F = 10 kg × 9.81 m/s²
F = 98.1 N
The distance (d) is the height you lift the box, which is 1 meter.
The angle (θ) between the force and the direction of motion is 0 degrees, as you are lifting the box straight up vertically.
Now, plug the values into the work formula:
W = 98.1 N × 1 m × cos(0°)
Since the angle cos(0°) is equal to 1, the work done on the box is:
W = 98.1 N × 1 m × 1
W = 98.1 Joules (J)
So, you do 98.1 Joules of work on the box when you lift it from the ground.
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Find the direction of the sum of
these two vectors: