A 50-kg ice skater turns a bend at 7 m/sec. If the radius of the curve is 5 m, what is the centripetal force in Newtons provided by the friction between the blade of the skate and the ice?
The centripetal force in Newtons provided by the friction between the blade of the skate and the ice is 490 N
How do i determine the centripetal force?The following data were obtained from the question:
Mass of ice skater (m) = 50 KgVelocity (v) = 7 m/sRadius (r) = 5 metersCentripetal force (F) =?The centripetal force can be obtained as illustrated below:
F = mv²/r
= (50 × 7²) / 5
= (50 × 49) / 5
= 2450 / 5
= 490 N
Thus, we can concluded that the centripetal force is 490 N
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Is there a difference between shapes when plotting Uniform acceleration towards (+)directtion,Uniform acceleration towards (-)direction, Uniform deceleration towards (+) direction and Uniform deceleration towards (-) direction in displacement time graph.Can you draw the shapes for each type ?
Explanation:
Yes, there are differences in the shapes of position-time graphs for uniform acceleration and uniform deceleration in different directions. Let's consider each case separately:\(\hrulefill\)
(1) - Uniform acceleration towards the positive direction:
In this case, the object is moving in the positive direction with a constant acceleration. The displacement-time graph will typically be a curve that starts from an initial position and shows a steady increase in displacement over time. The shape of the graph will depend on the specific acceleration value.
(2) - Uniform acceleration towards the negative direction:
In this case, the object is moving in the negative direction with a constant acceleration. The displacement-time graph will also be a curve, but it will show a steady decrease in displacement over time.
(3) - Uniform deceleration towards the positive direction:
In this case, the object is initially moving in the positive direction but is slowing down with a constant deceleration. The displacement-time graph will be a curve that starts with a positive slope and gradually levels off.
(4) - Uniform deceleration towards the negative direction:
In this case, the object is initially moving in the negative direction but is slowing down with a constant deceleration. The displacement-time graph will be a curve that starts with a negative slope and gradually levels off.
How do solar systems, galaxies, and the universe show different frames of reference about space?
Answer:
Many people are not clear about the difference between our Solar System, our Milky Way Galaxy, and the Universe.
Let’s look at the basics.
Our Solar System consists of our star, the Sun, and its orbiting planets (including Earth), along with numerous moons, asteroids, comet material, rocks, and dust. Our Sun is just one star among the hundreds of billions of stars in our Milky Way Galaxy. If we shrink the Sun down to smaller than a grain of sand, we can imagine our Solar System to be small enough to fit onto the palm of your hand. Pluto would orbit about an inch from the middle of your palm.
Artist diagram of Milky Way galaxy
On that scale with our Solar System in your hand, the Milky Way Galaxy, with its 200 – 400 billion stars, would span North America (see the illustration on the right). Galaxies come in many sizes. The Milky Way is big, but some galaxies, like our Andromeda Galaxy neighbor, are much larger.
The universe is all of the galaxies – billions of them! NASA’s telescopes allow us to study galaxies beyond our own in exquisite detail, and to explore the most distant reaches of the observable universe. The Hubble Space Telescope made one of the deepest images of the universe, called the Hubble Extreme Deep Field (image at the top of this article). Soon the James Webb Space Telescope will be exploring galaxies forming at the very beginning of the universe.
You are one of the billions of people on our Earth. Our Earth orbits the Sun in our Solar System. Our Sun is one star among the billions in the Milky Way Galaxy. Our Milky Way Galaxy is one among the billions of galaxies in our Universe. You are unique in the Universe!
You can observe objects in our solar system and even see other galaxies at a star party near you-and rest assured that everything you are seeing is a part of the same universe as you!
Explanation:
A solar system is the system of celestial bodies built around a central star, the Sun. All of the system bodies, be they dwarf planets, small bodies and large planets, are held in a gravitational bond around the central star. Our solar system has eight large planets:
Four inner planets which are terrestrial, made entirely of rock and metal: Mars, Mercury, Earth and Venus;
Four outer planets which are gas and ice giants: Jupiter and Saturn (composed entirely of helium and hydrogen), Uranus and Neptune (composed of ices such as water, ammonia and methane).
The solar system also contains asteroid belts and the natural satellites of some of the planets. The trans-Neptunian region has the Kuiper belt, home to several dwarf planets, Pluto among them. Our solar system is located on the Orion Arm and is part of the Milky Way Galaxy. It was formed 4.6 billion years ago.
A galaxy is made out of billions of stars and their solar systems, held together by gravity, with a super- massive black hole at the center. Our Solar System is called the Milky Way; it is a spiral galaxy and the black hole in the center is called Sagittarius A*. Apart from the spiral shape, galaxies can also be elliptical or irregular in form. Galaxies gather in groups, clusters and super-clusters and there are billions of Galaxies in the Universe.
Some of these other galaxies are visible to the naked eye on a dark night and from places away from artificial light sources. The Andromeda Galaxy is the most recorded one throughout time and all over the world, its existence having been noted since the 10th century by Persian astronomer Al-Sufi, and having been the object of debate among other great thinkers up to the moment when the technology caught up to the discourse.
Solar System vs Galaxy
So what is the difference between a solar system and a galaxy?
A solar system represents the group of planets gravitationally bound to the central star. A galaxy has billions of stars and their solar systems. This difference in size is not only visible in the number of stars it is made out of, but also by how long it takes to cross it. It takes one light year to cross our solar system, and 100,000 light years to cross the galaxy.
While the biggest thing inside a solar system is the central sun, the biggest thing inside a galaxy is a massive black hole. The planets in a solar system orbit the sun, which is at the center, and the Sun, in turn, orbits the center of the Milky Way.
Comparison Chart
Solar system Galaxy
A group of planets orbiting the central sun A group of planetary systems whose central Suns are orbiting the center of the Galaxy
Gravitationally bound Gravitationally bound
Can be crossed in 1 light year Can be crossed in 100,000 light years
Most of the system mass is taken up by the central sun It hosts a super massive black hole, Sagittarius A*
More solar systems make up galaxies More galaxies make up the Universe
Homeboy Joe is riding his skateboard and playing Among Us. Because he's distracted he doesn't notice he's about to skate right off the 69.0 m cliff he's on. If he lands 22.0 m from the cliff, how fast was he skating?
A rocky meteoroid is on a collision course with planet Earth. The meteoroid is only 0.10 m in diameter.
The meteoroid will most likely not reach the surface of the Earth because
A.
it will be struck by lightning.
B.
it will collide with a shooting star.
C.
it will be intercepted by a space vehicle.
D.
it will burn up in the Earth's atmosphere.
Answer:
it will burn up in the Earth's atmosphere.
Explanation:
The structure of the Earth's atmosphere protects the surface from frequent meteoroid strikes. As a meteoroid enters the atmosphere from outer space, it moves at very high speeds. At such speeds, intense amounts of friction and heat result. This process usually causes small meteoroids to burn up in the Earth's atmosphere before ever reaching the surface.
A different group is worried that the motion detector will not
effectively track the falling object, so they decide to roll a round
object down a ramp instead of dropping it. They measure the initial
height to calculate gravitational potential energy, use the motion
detector to track the final velocity, and calculate the kinetic energy of
the object at the end.
Despite all their careful measurements, it appears that energy is not
conserved! The object is not moving as fast at the bottom as the
initial gravitational potential would have led them to predict. Which
of the following suggestions is possible? Select all that apply.
The energy is not conserved because:
1. Energy may still be leaving the system through friction.
2. There could be measurement error that account for the missing energy
Given that a different group roll a round object down a ramp instead of dropping it. They measure the initial height to calculate gravitational potential energy, use the motion detector to track the final velocity, and calculate the kinetic energy of the object at the end.
Despite all their careful measurements, it appears that energy is not
conserved because
1. Energy may still be leaving the system through friction. In which the energy lost will be converted to thermal energy
2. There could be measurement error that account for the missing energy. The may occur due to systematic error or parallax error
The object is not moving as fast at the bottom as the initial gravitational potential would have led them to predict. This is not as a result of rotational energy. There is nothing like rotational energy.
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A pipe drips at 155 mL/min.
Express this is units of gallons/day.
1. 2.34 gal/day
2. 15.7 gal/day
3. 942 gal/day
4. 58.9 gal/day
5. 223 gal/day
6. 377 gal/day
7. 0.223 gal/day
We have that the total pipe drip of \(X=155 mL/min.\) expressed in gallons/day is
\(X=58.96gal/day\)
From the Question we are told that
Pipe Drip\(=155 mL/min.\)
Generally
We have that for mL to gallons conversion
\(1mL=0.000264172\)
And
A minute to day con version is
\(1min=0.000694444\)
Therefore
\(X=155 mL/min.\)
\(X=155(\frac{0.000264172}{0.000694444})\)
\(X=58.96gal/day\)
In conclusion
The total pipe drip of \(X=155 mL/min.\) expressed in gallons/day is \(X=58.96gal/day\)
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Without friction between the road and the tires of a car it would be like driving on which surface?A. IceB. DirtC. GravelD. Asphalt
Answer:
A. Ice
Explanation:
In Ice there is almost no friction, so without friction between the road and the tires, it would be like driving on ice. In ice, there is a smooth surface such that there isn't a force that goes against the car's movement.
With explanation pls
Answer:
\((x \times 1) = (400 \times 2.5) \\ x = 1000 \: newtons\)
\(y = 0\)
Calculate the net force on the particle q1.
Answer:
-12.1
Explanation:
i’m almost sure this is it, i’m checking my old answers
if not let me know and i’ll give you some more answers
formula for calcium chloride
c. is what percent of 125?
Answer:
Step 1: We make the assumption that 125 is 100% since it is our output value.
Step 2: We next represent the value we seek with $x$.
Step 3: From step 1, it follows that $100\%=125$.
Step 4: In the same vein, $x\%=125$.
Step 5: This gives us a pair of simple equations:
$100\%=125(1)$.
Explanation:
Plzz answer this question correctly
Answer:
by reducing friction.....
The number of hours
of daylight tat a location receives varies depending on how far north or south it is from the
Answer:
equator
Explanation:
in south & north pole you could have 20+ hours daylight or night, everyday!
a rock hanging from a string has a net force of zero acting on it ? true or false ?
Answer:
true cuase it is true its not false
If the diameter of the pie is ten inches, the approximate arc length of one slice of pie is select one.
The arc length of one slice of pie is either 5.24 inches for 6 slices or 3.93 inches for 8 slices.
The arc length of one slice of pie can be found by dividing the circumference of the pie by the number of slices it is cut into.
The circumference of the pie can be found using the formula
C = πd
Where d is the diameter of the pie.
Substituting d = 10 inches,
we get:
C = π × 10 inches ≈ 31.42 inches
If we assume that the pie is cut into n equal slices, then the arc length of one slice is approximately:
Arc length ≈ C/n
If we want an approximate value for the arc length, we can use a value of n that is easy to work with,
such as n = 6 for 6 slices or n = 8 for 8 slices.
For n = 6, the arc length of one slice is approximately:
Arc length ≈ 31.42 inches / 6 ≈ 5.24 inches
For n = 8, the arc length of one slice is approximately:
Arc length ≈ 31.42 inches / 8 ≈ 3.93 inches
Therefore, the approximate arc length of one slice of pie is either 5.24 inches for 6 slices or 3.93 inches for 8 slices.
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A typical home uses approximately 1600 kWh of energy per month. If the energy came from a nuclear reaction, what mass would have to be converted to energy per year to meet the energy needs of the home
Answer:
7.68×10^25kg
Explanation:
The formula for energy used per year is calculated as
Energy used per year =12 x Energy used per month
By substituting Energy used per month in the above formula, we get
Energy used per year =12 x 1600kWh
= 19200kWh
Conversion:
From kWh to J:
1 kWh=3.6 x 10^6 J
Therefore, it is converted to J as
19200 kWh =19200 x 3.6 x 10^6 J
= 6.912×10^10 J
Hence, energy used per year is 6.912×10^10 J
To find the mass that is converted to energy per year.
E = MC^2 ............1
E is the energy used per year
C is the speed of light = 3.0× 10^8m/s
Where E= 6.912×10^10 J
Substituting the values into equation 1
6.912×10^10 J = M × 3.0× 10^8m/s
M = 6.912×10^10 J / (3.0× 10^8m/s)^2
M = 6.912×10^10 J/9×10^16
M = 7.68×10^25kg
Hence the mass to be converted is
7.68×10^25kg
i. If the Potential Energy of a given student midwife is = mgh. Where m = Mass of the student, g = acceleration due to gravity (app 10m/s2) and h = Height of the s tudent above the ground. Find the P.E of the student of mass 200kg standing on a building floor, 15m above the ground
The potential energy of the student standing on the building floor, 15 m above the ground, is 30,000 Joules.
How to determine potential energy?To calculate the potential energy (P.E) of the student standing on a building floor, use the formula P.E = mgh, where m = mass of the student, g = acceleration due to gravity, and h = height above the ground.
Given:
Mass of the student (m) = 200 kg
Acceleration due to gravity (g) = 10 m/s^2
Height above the ground (h) = 15 m
Using the formula, calculate the potential energy as follows:
P.E = mgh
= 200 kg x 10 m/s² x 15 m
= 30,000 kg·m²/s²
= 30,000 J (Joules)
Therefore, the potential energy of the student standing on the building floor, 15 m above the ground, is 30,000 Joules.
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A car traveling 13 m/s to the north collides with a car traveling 19 m/s to the
south. Each car has a mass of 1250 kg. If the system is defined as the two
cars, what is the change in momentum of the system due to the collision?
O A. 16,250 kg-m/s
O B. 0 kg•m/s
O C. 40,000 kg•m/s
D. 23,750 kg•m/s
Answer: B. 0 kg*m/s
Explanation:
For the system of Problem3.18, determine the amount of energy transfer by heat, in kJ per kg of refrigerant.[Problem3.18A closed, rigid tank contains a two‐phase liquid–vapor mixture of Refrigerant 22 initially at−20°Cwith a quality of 50.36%. Energy transfer by heat into the tank occurs until the refrigerant is at a final pressure of 6 bar. Determine the final temperature, in°C. If the final state is in the superheated vapor region, at what temperature, in°C, does the tank contain only saturated vapor?]
Answer:
35.625° C
Explanation:
See attachment
a) Final temperature is 35.625° C
b) 0°
What type of image can be larger or smaller than the object?
A. An expansion
B. A magnification
C. A reduction
D. An enlargement
A 0.0780 kg lemming runs off a
5.36 m high cliff at 4.84 m/s. What
is its potential energy (PE) when it
lands?
The potential energy of the lemming when it lands is 0.9108672 J.
To determine the potential energy (PE) of the lemming when it lands, we need to consider the conservation of energy. The potential energy of an object is given by the formula PE = mgh, where m is the mass of the object, g is the acceleration due to gravity, and h is the height.
Given:
Mass of the lemming (m) = 0.0780 kg
Height of the cliff (h) = 5.36 m
First, let's calculate the potential energy when the lemming is on the cliff. Using the given formula, we have:
PE = mgh
PE = 0.0780 kg * 9.8 m/s² * 5.36 m
PE = 0.413616 J
Next, we need to determine the final kinetic energy of the lemming just before it lands. We can use the equation for kinetic energy (KE) given by KE = (1/2)mv², where v is the velocity of the lemming.
Given:
Velocity of the lemming (v) = 4.84 m/s
Calculating the kinetic energy, we have:
KE = (1/2) * 0.0780 kg * (4.84 m/s)²
KE = 0.9108672 J
According to the conservation of energy, the potential energy at the top of the cliff is equal to the kinetic energy just before landing.
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A certain car traveling at 97 km/h can stop in 47 m on a level road find the coefficient of friction
The coefficient of friction between the road and the car's tire is determined as 0.78.
Acceleration of the carThe acceleration of the car is calculated as follows;
v² = u² - 2as
0 = u² - 2as
a = u²/2s
where;
u is the initial velocity = 97 km/h = 26.94 m/sa = (26.94)²/(2 x 47)
a = 7.72 m/s²
Coefficient of frictionμ = a/g
μ = (7.72)/9.8
μ = 0.78
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The refractive indices of materials A and B have a ratio of nA/nab=1,33. The speed of light in material A is 1.25 times 10^8m/s. What is the speed of light in material B?
The speed of light in material B is 1.6625 × 108 m/s.
The refractive index of a material is its optical density relative to that of a vacuum.
Material B has a refractive index of nB, and its speed of light is vB.
The speed of light in material A is given as 1.25 x 108 m/s.
The refractive indices of materials A and B have a ratio of nA/nB = 1.33.
We will use the formula:
nA/nB = vB/vA = nA/nB.
Therefore, nA/nB = vB/1.25 x 108 m/s.
This equation can be rearranged to give the speed of light in material B:
vB = nA/nB × 1.25 x 108 m/s.
Therefore, vB = 1.33 × 1.25 × 108 m/s.
We will perform this calculation:
vB = 1.6625 × 108 m/s.
Therefore, the speed of light in material B is 1.6625 × 108 m/s.
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A motorcycle travels a distance of 420 miles in 8.5 hours. Give the average speed of the motorcycle
Answer:
As per Provided Information
Distance travelled by motorcycle is 420 miles
Time taken by motorcycle is 8.5 hours
we have been asked to determine the average speed of the motorcycle .
\( \bf \: Speed_{(Average)} = \cfrac{total \: distance \: travelled}{time \: taken} \)
Now let's put the given value to find the average speed of motorcycle
\( \longrightarrow \sf \: Speed_{(Average)} \: = \cfrac{420}{8.5} \\ \\ \\ \longrightarrow \sf \: Speed_{(Average)} \: = \cfrac{4200}{85} \\ \\ \\ \longrightarrow \sf \: Speed_{(Average)} \: = \cancel\cfrac{4200}{85} \\ \\ \\ \longrightarrow \sf \: Speed_{(Average)} \: = 49.41 \: miles \: per \: hour\)
Therefore,
Average speed of the motorcycle is 49.41 miles per hour .Experiments carried out on the television show Mythbusters determined that a magnetic field of 1000 gauss is needed to corrupt the information on a credit card's magnetic strip. (They also busted the myth that a credit card can be demagnetized by an electric eel or an eelskin wallet.) Suppose a long, straight wire carries a current of 5.0 A .
How close can a credit card be held to this wire without damaging its magnetic strip?
Answer:
his distance is too small (r = 0.01 mm), therefore the cut can be at any distance
Explanation:
For this exercise let's use the ampere law.
Let's use a cylinder as the circulating surface
∫ B. ds = μ₀ I
in this case the field is circular and ds is circular therefore the angle between them is zero and cos 0 = 1
B 2π r = μ₀ I
r = \(\frac{\mu_o I}{2\pi B}\)
The field needed to demagnetize the card is B = 1000 gauss = 0.1 T
r = \(\frac{4\pi 10^{-7} 5.0 }{2\pi \ 0.1}\)
r = 2 10⁻⁷ 5.0/0.1
r = 1 10⁻⁵ m
this distance is too small (r = 0.01 mm), therefore the cut can be at any distance
A system absorbs 1500J of heat energy from its surroundings. Determine the change in the internal energy of the system when: (i) system performs 2200J of work on the surroundings (ii) the surroundings perform 2200J of work on the system
(a) When the system does work on the surroundings, the change in the internal energy is - 700 J.
(b) When the surroundings performs work on the system, the change in the internal energy is 3,700 J.
What is the change in the internal energy of the system?
The change in the internal energy of the system is determined by applying the first law of thermodynamics as shown below.
Mathematically, the formula for first law of thermodynamics is given as;
ΔU = Q ± W
where;
ΔU is the change in the internal energy of the systemQ is the heat gain or loss of the systemW is the work done by or done on the systemWhen the system does work on the surroundings, the equation is given as;
ΔU = Q - W
ΔU = 1500 J - 2200 J
ΔU = -700 J
When the surroundings performs work on the system, the equation is given as;
ΔU = Q + W
ΔU = 1500 J + 2200 J
ΔU = 3,700 J
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A copper wire has a diameter of 1.947 mm. What magnitude current flows when the drift velocity is 1.79 mm/s
Answer:
72.5 A
Explanation:
There are about 13.6 coulombs of free electron charges in each cubic mm of copper. So, the rate of movement of charge is that quantity multiplied by the volume in the flow.
V = πr²h . . . . . volume of a cylinder
V = π(1.947 mm/2)²(1.79 mm/s) = 5.329 mm³/s
Then the charge flow rate is ...
(13.6 C/mm³)(5.329 mm³/s) = 72.5 C/s
The magnitude of the current is about 72.5 amperes.
______
Additional comment
The volume of free charge in copper can be computed from the density, molar mass, number of atoms in a mole, number of charges in a coulomb, and the number of free charges per atom. Some of the combinations of necessary calculations can be found with a web search, so it is not unreasonable to presume that the charge density is known.
If you make multiple measurements of your height, you are likely to find that the results vary by nearly half an inch in either direction due to measurement error and actual variations in height. You are slightly shorter in the evening, after gravity has compressed and reshaped your spine over the course of a day. One measurement of a man's height is 6 feet and 1 inch. Express his height in meters, using the appropriate number of significant figures.
Answer:
H = 1.85 m
Explanation:
First, we will convert the height completely into inches. 1 feet contains 12 inches in it. Therefore:
H = (6 feet)(12 inch/1 feet) + 1 inch
H = 73 inches
Now, we will convert this height from inches to meters. 1 inch is equivalent to 0.0254 m. Therefore:
H = (73 inches)(0.0254 m/1 inch)
H = 1.85 m
What does the scientific method help test in environmental science?
Edmentum/Plato answer please
Answer:
The scientific method helps test and arrive at conclusions for a variety of hypotheses that are created when studying environmental science.
Explanation:
What is the scientific method in environmental science?
The scientific method is a method of research with defined steps that include experiments and careful observation. One of the most important aspects of this method is the testing of hypotheses by means of repeatable experiments. A hypothesis is a suggested explanation for an event, which can be tested.