How does increasing the amount of charge on an object affect the electric force it exerts on another charged object?

The y component of the vector is 37.7 N and the angle between the vectors is 26.2⁰.

The y component of the vector will be determined from the resultant vector and the x component of the vector.

R² = Y² + X²

Y² = R² - X²

Where;

Y² = 85.2² - 76.4²

Y² = 1,422.08

Y = √1,422.08

Y = 37.7 N

θ = arc tan (Y/X)

θ = arc tan (37.7/76.4)

θ = 26.2⁰

Thus, the y component of the vector is 37.7 N and the angle between the vectors is 26.2⁰.

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The term that describes the given graph is a negative correlation, linear, inversely proportional relationship

Regression evaluation is a similar method for inspecting the connection between a final results variable and one or extra threat elements or confounding variables (confounding is mentioned later). The end result variable is likewise referred to as the reaction or based variable, while the threat elements and confounders are referred to as predictors, explanatory variables, or unbiased variables. The based variable in regression evaluation is indicated with the aid of using "Y," whilst the unbiased variables are denoted with the aid of using "X."

The path of the hyperlink is indicated with the aid of using the signal of the correlation coefficient. The correlation coefficient's price displays the electricity of the hyperlink.

It is vital to spotlight that whilst there can be a non-linear dating among non-stop variables, calculating a correlation coefficient does now no longer display this. As an end result, it's miles usually vital to investigate the statistics well earlier than setting up a correlation coefficient. Graphical representations are very powerful for investigating relationships among variables.

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Answer:

The answer is A. 10

Explanation:

Given

f(x) = 3x - 11

So,

f(7) = 3 * 7 - 11

= 21 - 11

= 10

Answer:

Approximately \(3.5\; \rm kN\) in each of the two ropes.

Explanation:

Let \(F_1\) and \(F_2\) denote the tension in each of the two ropes.

Refer to the diagram attached. The tension force in each rope may be decomposed in two directions that are normal to one another.  

The first direction is parallel to resultant force on the barge.

These two components would be in the same direction. The resultant force in that direction would be the sum of these two components: \(\displaystyle \frac{F_1 + F_2}{\sqrt{2}}\). That force should be equal to \(5\; \rm kN\).

The second direction is perpendicular to the resultant force on the barge.

These two components would be in opposite directions. The resultant force in that direction would be the difference of these two components: \(\displaystyle \frac{F_1 - F_2}{\sqrt{2}}\). However, the net force on the barge is normal to this direction. Therefore, the resultant force should be equal to zero.

That gives a system of two equations and two unknowns:

The second equation suggests that \(F_1 = F_2\). Hence, replace the \(F_2\) in the first equation with \(F_1\) and solve for \(F_1\!\):

\(F_1 = \displaystyle \frac{5\; \rm kN}{2\, \sqrt{2}} \approx 3.5\; \rm kN\).

Because \(F_1 = F_2\) (as seen in the second equation,) \(F_2 = F_1 \approx 3.5\; \rm kN\).

In other words, the tension in each of the two ropes is approximately \(3.5\; \rm kN\).

The tension in each of the rope is 3,535.5 N

The given expression:

the resultant force, R = 5 kN = 5000 N

the angle in between the forces, α = 45

To find:

The tension in  each of the ropes  is calculated as follows;

The tension in vertical direction

\(F_y = F \times sin(\alpha)\\\\F_y = 5000 \times sin(45)\\\\F_y = 5000 \times 0.7071\\\\F_y = 3,535.5 \ N\)

The tension in horizontal direction;

\(F_x = F \times cos(\alpha)\\\\F_x = 5000 \times cos(45)\\\\F_x = 5000 \times 0.7071\\\\F_x = 3,535.5 \ N\)

Thus, the tension in each of the rope is 3,535.5 N

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Answer:

The drop in temperature overnight causes a decrease in the average kinetic energy of the air molecules inside the tires. According to the ideal gas law, this leads to a decrease in tire pressure. The low tire pressure light in vehicles is triggered when the pressure falls below a certain threshold, alerting the driver to check and adjust the tire pressure.

Explanation:

The ideal gas law, represented by the equation PV = nRT, relates the pressure (P), volume (V), number of moles (n), and temperature (T) of an ideal gas. In this case, we can analyze how the drop in temperature affects the tire pressure.

When the temperature drops, according to the ideal gas law, the pressure of a gas will decrease if the volume and the number of moles remain constant. This is because the decrease in temperature causes a decrease in the average kinetic energy of the gas particles, leading to less frequent and less forceful collisions with the tire walls, resulting in a decrease in pressure.

In the context of the tire pressure, the air inside the tires behaves as an ideal gas. When the temperature drops overnight, the air inside the tires also cools down, causing a decrease in its temperature. As a result, the average kinetic energy of the air molecules decreases, leading to a decrease in pressure inside the tires.

The low tire pressure light comes on as a result of this drop in pressure. The tire pressure monitoring system in modern vehicles is designed to detect significant deviations from the recommended tire pressure. When the pressure drops below a certain threshold, typically due to temperature changes or a puncture, the light is triggered to alert the driver to check and adjust the tire pressure.

Therefore, the drop in temperature overnight causes a decrease in the average kinetic energy of the air molecules inside the tires, resulting in a decrease in tire pressure, which triggers the low tire pressure warning light.

Hope this helps!

Since The table shows the traits of four tomato plant varieties. The plant that is best is Plant 2 and Plant 4.

A taxonomic rank beneath species is variety. In agriculture, a variety refers to a population of plants of a particular species that have been chosen and grown, frequently for millennia, to generate traits that are suitable for human use.

The tomato is an edible berry that is produced by the Solanum lycopersicum plant, also referred to as the tomato plant. Western South America, Mexico, and Central America are where the species first appeared. The Spanish term tomate, from which the English word tomato descended, was derived from the Mexican Nahuatl word tomatl.

Therefore, some typical tomato types include:

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A farmer wants to create a new breed of tomato that is sweet-tasting, has a very low quantity of seeds, and grows well in the hot and humid Georgia climate.

The table shows the traits of four tomato plant varieties. Which is best

Answer:

When buying a margarine, people should look for trans fat and saturated fat content. If it is over 2%, then it is not healthy. If it is lower that means it is healthy and fresh!

Explanation:

Answer:

Explanation:

ω = v / R

where ω is angular speed of a point situated at distance R from axis and having a linear speed of v .

Given v = 150 m/s ; R =.10 m

ω = 150 / .10

= 1500 radian /s .

Final angular speed is 1500 radian /s .

Answer:

\(\omega '=-13.5rad/s\)

Explanation:

From the question we are told that:

Time \(t=4sec\)

Angular displacement \(\theta= 161 rad\)

Final Angular velocity  \(\omega = 100 rad / s\)

Let

Angular acceleration \(\alpha\)  

Generally the equation for Initial Angular velocity  \(\omega '\) is mathematically given by

\(-\omega '^2=2 \alpha \theta -\omega^2\)

\(\omega '^2= \alpha 328 +11236\)

Also,Initial Angular velocity  \(\omega '\) is mathematically given by

\(\omega '=\omega - \alpha t\)

Therefore substitution

\(-\omega '^2=2 \alpha \theta -\omega^2\)

\(\omega '=\omega - \alpha t\)

\((\omega - \alpha t)^2=2 \alpha \theta -\omega\)

\(-16\alpha^2+848\alpha+11236= \alpha 328 -11236\)

\(16\alpha^2-520\alpha=0\)

\(\alpha=29.875rads/s^2\)

Substitution in the 2nd equation for Initial Angular velocity  \(\omega '\)

\(\omega '=106-(29.875rads/s^2*4)\)

\(\omega '=-13.5rad/s\)

Answer:

The prediction for its maximum potential energy is 109,375 J

Explanation:

Given;

mass of the coaster car, m = 350 kg

speed of the coaster car at the lowest point, v = 25 m/s

The coaster car will have maximum kinetic energy at the lowest point and based on law of conservation of mechanical energy, the maximum kinetic energy of the coaster car at the lowest point will be equal to maximum potential energy at the highest point.

\(K.E_{max} = P.E_{max}\)

\(K.E_{max} = \frac{1}{2} mv^2\\\\K.E_{max} = \frac{1}{2} (350)(25)^2\\\\K.E_{max} =109,375 \ J\)

\(Thus, P.E_{max} = 109,375 \ J\)

Therefore, the prediction for its maximum potential energy is 109,375 J

The crate is being pulled by a total force of 160 N. the box is being subjected to a 350 N frictional force. The crate is being movement to a 96.99 N force of friction.

A rope pulls a 60 kg 60 kg container across the floor with a constant force applied of 250 N. Under the impact of this coercion and the compressive stress the floor exerts on the crate, it is seen that the speed of the crate increases from 1 m/s to 3 m/s to 3 m/s in a period of 2 seconds.\($a = \frac{\Delta v}{\Delta t} =\frac{9}{ \text m/s - 1} \text m/s^2, \text s = 4, \text{and} \ \text m/s 2$\)

The following formula can be used to determine the net force on the crate:

\(\rm F_{net }= ma = (40kg)(4m/s) = 160 N\)

As a result, the crate is being pulled by a total force of 160 N.

The degree of kinetic friction is inversely correlated with the level of normal force and the level of irregularity in between sliding surfaces. The magnitude of static friction is inversely related to the amount of normal force and the measure of roughness between of sliding surfaces.\((40 \text kg) = $N = mg 9.81 \text m/s^2= 392.4 \text N$\)

As the coefficient of friction factor between the crate and the floor is not provided, we are unable to directly calculate it. Yet, we are aware that the 350 N force exerted by the rope must be balanced by a force of friction that is both equal to and directed in the opposite direction. Hence, it is possible to compute the frictional force's magnitude as follows:

\(355 \text N, $F friction\)

As a result, the box is being subjected to a 350 N frictional force.

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Answer:

a)   x = 2.46 m

b)   318.2 N

c)    177.8 N

Explanation:

Need to resolve the tension of the string at end say B.

The vertical upward force at B due to tension is 450 sin 45°.  

Using Principle of Moments, with the pivot at A,

Anti clockwise moments = Clockwise moments

450 sin 45° X 3.2   = 220 X (3.2/2) + (270 X x)  

x = 2.46 m

(b) The horizontal force is only due to the wire's tension, so it is  

450 cos 45° = 318.2 N

(c) total downward forces = 270 + 220 = 496 N  

Total upward forces = 450 sin 45° (at B) + upForce (at A)

Equating, upForce = 496 - 318.2  

= 177.8 N

Explanation:

c because there is element

Answer:

C. H2 and N2 would react to produce more NH3

Explanation:

A.P.E.X

Answer:

  about 3.17647 hours

Explanation:

The appropriate relation is ...

  time = distance/speed

  time = (270 km)/(85 km/h) = 3 3/17 h ≈ 3.17647 h

It will take Derek about 3.17647 hours to drive the distance.

The coefficient of static friction places a limit of approximately 3.42 seconds on the minimum time required for the car to accelerate from rest to 60.0 mph (26.8 m/s).

To find the limit that the coefficient of static friction places on the minimum time required for a car to accelerate from rest to 60.0 mph (26.8 m/s), we need to consider the maximum acceleration the car can achieve due to the friction between the rear tires and the pavement.

The maximum acceleration can be determined using the formula:

a_max = μs * g

where μs is the coefficient of static friction and g is the acceleration due to gravity (approximately 9.8 m/s²).

In this case, since the car's engine only turns the two rear wheels, the maximum acceleration is limited by the friction force between the rear tires and the pavement.

Now, to calculate the minimum time required to accelerate to 60.0 mph (26.8 m/s), we can use the following kinematic equation:

v = u + a * t

where v is the final velocity (26.8 m/s), u is the initial velocity (0 m/s), a is the acceleration, and t is the time.

Rearranging the equation, we have:

t = (v - u) / a

Plugging in the values, we get:

t = (26.8 m/s - 0 m/s) / a_max

t = 26.8 m/s / (μs * g)

Substituting the given value for the coefficient of static friction (μs ≈ 0.800) and the acceleration due to gravity (g ≈ 9.8 m/s²), we can solve for the minimum time required:

t = 26.8 m/s / (0.800 * 9.8 m/s²)

t ≈ 3.42 seconds

Therefore, the coefficient of static friction places a limit of approximately 3.42 seconds on the minimum time required for the car to accelerate from rest to 60.0 mph (26.8 m/s).

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Answer:

We show concern and show support

The statements that apply are;

We know that the pressure can be taken as the force with which the molecules of the substance are able to hit the walls of the container in this case, we need to obtain the  pressure of the ethanol vapor when the volume has been reduced.

Using

P1 = initial pressure

P2 = final pressure

V 1 = initial volume

V2 = final volume

By the use of the Boyle's law we have;

P1V1 = P2V2

P2 = P1V1 /V2

P2 = 67.0 * 529/344

P2 = 103 mmHg

Thus, as the volume is reduced there would be an increase in the pressure and some of the ethanol would condense and we would have liquid ethanol in the system.

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Answer:

Explanation:

Assuming you mean a = 16 m/s²

s = ½at²

t = √(2s/a)

t = √(2(201)/16)

t = 5.012484...

t = 5.0 s

Answer:

1 correct

2 wrong

3 wrong

4 correct

5 correct

Explanation:

Hope my answers help

Modern LCD and LED screens have taken the role of the Cathode Ray Tubes (CRTs) that were once used in televisions. The magnitude of the electric field (in V/m) in the region between the plates is 1.88 x 10^6 V/m.

The CRT is made up of an electron gun that produces a beam of electrons that are then directed by an electric field towards a fluorescent screen at the end of the tube. The electric field between the plates of a CRT (Cathode Ray Tube) has to be found. The plates are 1.30 cm apart and there is a potential difference of 24.5 kV between the plates. Here’s how to find the electric field: The formula to calculate the electric field between the plates is: `E = V/d`, where E is the electric field.

Substitute the given values in the formula: E = V/d = 24.5 kV/0.013 m= 1.88 x 10^6 V/m. Therefore, the magnitude of the electric field (in V/m) in the region between the plates is 1.88 x 10^6 V/m.

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Answer:

Potential Energy = x = m g h

Kinetic energy = 1/2 m v^2

Assuming the mass fall from rest

1/2 m v^2 = m g h

v^2 = 2 g h

So the speed attained is independent of the mass

Also, x / v   does not have the units of mass

So the solution is none of the above.

Answer:

Answer:

x=22.57 m

Explanation:

Given that

35 m in W of S

angle = 40 degrees

25 m in east

From the diagram

The angle

\(\theta=90-40=50^o\)

From the triangle OAB

\(cos40^o=\frac{35^2+25^2-x^2}{2\times 35\times 25}\)

\(1340.57=35^2+25^2-x^2\)

x=22.57 m

Therefore the answer of the above problem will be 22.57 m

Answer: Skinfold testing

Explanation:

Skinfold testing, is also referred to as calliper testing and it's used to know the body fat percentage. Skinfold testing is an inexpensive, portable, and common way to assess body fat in the fitness industry.

It is typically done with the use of caliper tapes, marker pens which makes it cheap. Skinfold testing isn't usually accurate which is as a result of human errors.

The hypothesis is, the thickness of transparent glass affects how much light passes through. Option A is correct.

A hypothesis is a proposed explanation or prediction for a phenomenon or observation that is based on limited evidence and subject to testing and validation through further investigation. It is an essential part of the scientific method, which involves developing a research question, making observations, and forming a hypothesis to explain the observed phenomenon.

The hypothesis should be testable, falsifiable, and based on evidence and reasoning. Testing the hypothesis involves designing experiments and collecting data, which can either support or refute the hypothesis. If the hypothesis is supported by the data, it may be further developed into a scientific theory, which is a widely accepted explanation of a natural phenomenon that has been extensively tested and validated. Option A is correct.

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Answer: The depth of the ocean is 650 feets at the bottom of the sunlight zone.

The distance travelled by echo sound is given by the formula -

Speed = 2×distance/time

So, calculating the speed of sound from the formula using distance and time

Speed = 2×25/(1/100)

Speed = 50×1000

Speed of sound = 5000 feet/second

Now, calculating the distance or depth of ocean at the bottom of the sunlight zone -

Distance = (speed×time)/2

Distance = (5000×26/100)/2

Distance = 1300/2

Distance = 650 feets

Hence, the depth of ocean is 650 feets.

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Answer:

We can start by using the formula:

distance = speed x time

where distance is twice the depth of the ocean at the bottom of the Sunlight Zone (since the pulse travels down to the seafloor and then back up), speed is the speed of sound in water, and time is the round-trip time of the pulse.

The speed of sound in water is approximately 1,500 meters per second (or 4,921 feet per second).

Converting the round-trip time to seconds, we have:

26 seconds - 1 second = 25 seconds

Substituting the values into the formula:

2 x depth = 4,921 feet/second x 25 seconds

2 x depth = 123,025 feet

depth = 61,512.5 feet

Therefore, the ocean at the bottom of the Sunlight Zone is about 61,512.5 feet deep.

The work done in part (b) is approximately 63.27% greater than the work done in part (a).

(a) The work done by the gas on the bullet as the bullet travels the length of the barrel can be calculated using the formula:

W = ∫F(x)dx

where F(x) is the force exerted by the gas on the bullet at position x along the barrel.

Substituting the given force expression, we have:

W = ∫(20000x - 11000\(x^2\))dx (from x=0 to x=0.58m)

W = [10000\(x^2\) - (11000/3)\(x^3\)] from 0 to 0.58m

W = [10000\((0.58)^2\) - (11000/3)\((0.58)^3\)] - [10000\((0)^2\) - (11000/3)\((0)^3\)]

W ≈ 1237.92 J

Therefore, the work done by the gas on the bullet as the bullet travels the length of the barrel is approximately 1237.92 J.

(b) If the barrel is 1.05 m long, we need to modify the limits of integration in the above formula to cover the new distance. Therefore, we have:

W = ∫(20000x - 11000\(x^2\))dx (from x=0 to x=1.05m)

W = [10000\(x^2\) - (11000/3)\(x^3\)] from 0 to 1.05m

W = [10000\((1.05)^2\) - (11000/3)\((1.05)^3\)] - [10000\((0)^2\) - (11000/3)\((0)^3\)]

W ≈ 2703.44 J

Therefore, the work done by the gas on the bullet as the bullet travels a 1.05 m long barrel is approximately 2703.44 J.

(c) The percent difference between the work done in parts (a) and (b) can be calculated as follows:

% difference = \(|(Wb - Wa)/((Wa+Wb)/2)| \times 100%\)

where Wa is the work done in part (a) and Wb is the work done in part (b).

Substituting the values, we have:

% difference = \(|(2703.44 - 1237.92)/((1237.92+2703.44)/2)| \times 100%\)

% difference ≈ 63.27%

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