How does mass change in life?

Given that a car and a train each make a trip that is 120 km and the average speed of a train is 40 km/h faster than a car. We need to find the average speed of the car.Let the average speed of a car be x km/hour.So the average speed of the train is (x + 40) km/hour. According to the question, time taken by the train is 30 minutes less than the car, so time taken by the car is:

t = d/swhere t = time taken, d = distance covered, and s = speed of the carThe time taken by the train is:t - 0.5h = d/(x + 40)Here, 0.5 hour is equal to 30 minutes.Now, both the car and the train covered the same distance. Hence we have:t = d/xUsing the formulae for t in both equations, we have:d/x - 0.5 = d/(x + 40)Cross-multiplying the above equation, we get:d(x + 40) - 0.5x(x + 40) = dxSimplifying the above expression, we get:x² - 80x - 2400 = 0We can solve the above quadratic equation to get the values of x.

Using the main answer, the average speed of the car is 60 km/h.The explanation to find the average speed of the car:Given, a car and a train each make a trip that is 120 km. Let the average speed of a car be x km/h. Therefore, the average speed of the train is (x + 40) km/hour.The time taken by the train is t - 0.5h = d/(x + 40).Using the formulae for t in both equations, we have:d/x - 0.5 = d/(x + 40)Cross-multiplying the above equation, we get:d(x + 40) - 0.5x(x + 40) = dxSimplifying the above expression, we get:x² - 80x - 2400 = 0We can solve the above quadratic equation to get the values of x.Using the main answer, the average speed of the car is 60 km/h.

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The auxiliary equation is given by d^2x/dt^2 + (c/m) dx/dt + (k/m) x = 0. This can be found by force substituting m = 1kg, c = 6 kg s−1 and k = 9 kg s−2 into the given differential equation.

The general solution for equation (2.1) is given by:$$x(t) = c_1 e^{r_1 t} + c_2 e^{r_2 t}$$where r1 and r2 are the roots of the auxiliary equation and c1 and c2 are arbitrary constants. We can find the roots of the auxiliary equation by solving the characteristic equation:$$r^2 + (c/m)r + (k/m) = 0$$Using the quadratic formula, we get:$$r_{1,2} = \frac{-p \pm \sqrt{p^2 - 4q}}{2}$$where p = c/m and q = k/m. Depending on the values of p and q, there are three cases for the roots:r1 and r2 are real and distinct;r1 and r2 are complex conjugates;r1 and r2 are equal and real.

The system described by equation (2.1) exhibits overdamping, as the damping constant c is greater than the critical damping constant, given by 2√km, where k is the spring constant and m is the mass. Overdamping occurs when the damping force is strong enough to prevent the mass from oscillating.(d) ExplanationOnce the force sint is applied, the non-homogeneous second order differential equation that describes the mass spring damper system is:d^2x/dt^2 + (c/m) dx/dt + (k/m) x = sint.(e).

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First, for this problem, we will need to know the formula for time dilation

Where t is the time in the reference frame on earth

t0 is the time on the ship

v is the velocity relative to lightspeed

and c is light speed in a vacuum

For this problem, we will need to convert .93x10^8 to a fraction of light speed.

.93x10^8 = .31c

Now, we can plug in the numbers we get from the given

t0 = 6 hours since the ship has been in the air for 6 hours

t = 6.31089

For the answer to be valid, we will convert .31089 to minutes by multiplying it by 60 (60 minutes in a hour)

18.654 minutes

The angle for the third order maximum is 31.1 degrees.

The formula for calculating the angle for the nth order maximum is given by: sinθ = nλ/d, where θ is the angle, λ is the wavelength of light, d is the distance between the slits (also known as the grating spacing), and n is the order of the maximum.
In this case, the grating has 8000 slits spaced over 2.54 cm, which means the grating spacing d = 2.54 cm / 8000 = 3.175 x 10^-4 cm. The wavelength of light is given as 546 nm, which is 5.46 x 10^-5 cm.
To find the angle for the third order maximum, we can plug in these values into the formula: sinθ = 3 x 5.46 x 10^-5 cm / 3.175 x 10^-4 cm. Solving for θ gives us sinθ = 0.524, or θ = 31.1 degrees (rounded to the nearest tenth of a degree). Therefore, the correct answer is 31.1 degrees.
This calculation involves the use of the formula that relates the angle, wavelength, and grating spacing, which allows us to determine the maximum angles at which constructive interference occurs.

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The average induced emf in the inductor during this time can be calculated using the formula:

emf = L * ΔI/Δt

where L is the inductance, ΔI is the change in current, and Δt is the time interval.

In this case, the inductance (L) is 1.70 H and the change in current (ΔI) is 0.450 A (since the current goes from 0.450 A to 0 A). The time interval (Δt) is 10.0 ms, which is equal to 0.01 seconds.

Plugging in these values, we get:

emf = 1.70 H * (0 - 0.450 A)/0.01 s
emf = -76.5 V

Therefore, the average induced emf in the inductor during this time is -76.5 volts. Note that the negative sign indicates that the emf is opposing the change in current (i.e. it is a back emf).

* To calculate the average induced emf in the 1.70 H inductor during the 10.0 ms interval when the current decreases from 0.450 A to zero, you can use the formula for the induced emf in an inductor:

emf = -L * (ΔI / Δt)

where L is the inductance (1.70 H), ΔI is the change in current (0.450 A), and Δt is the time interval (10.0 ms or 0.01 s). The negative sign indicates that the induced emf opposes the change in current.

emf = -(1.70 H) * (0.450 A / 0.01 s)

emf = -76.5 V

The average induced emf in the inductor during this time is 76.5 V.

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Considering the definition of speed and propagation of sound, sound is a sequence of waves of pressure which propagates through compressible media and depends on the characteristics of the medium in which the propagation occurs.

Sound is a vibration that propagates as an acoustic wave, through a transmission medium such as a gas, liquid or solid.

That is, sound is a longitudinal wave, mechanical (does not travel in a vacuum) and propagates in all directions, so that the wave front is spherical.

Propagation of sound involves energy transport without matter transport, in the form of mechanical waves.

The speed of propagation of a sound wave depends on the characteristics of the medium in which the propagation occurs and not on the characteristics of the wave or the force that generates it. The speed of propagation of sound waves is also known as the speed of sound.

In summary, sound is a sequence of waves of pressure which propagates through compressible media and depends on the characteristics of the medium in which the propagation occurs.

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An example would be if a student was dragging something across the floor that weighed 25 kg. The object would weigh 250 N if gravity were 10 m/s², according to this assumption.

It can be described as the force that causes a body to pull another body toward its center due to their mutual gravitational pull.

A student is dragging a 25 kilogram object across the floor as specified in the problem. estimating a gravity of 10 m/s².

The thing weighs 25 x 10 pounds.

The weight of the object = 250 N

Consequently, the object would have 250 N in weight.

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Answer:

:DDDDD thanks foooooooor joinin'

Explanation:

Fracking has become widely used in the US, raising worries about its effects on the environment and public health. Large volumes of wastewater are produced, along with greenhouse gases like methane, hazardous air pollution, and noise.

Fracking, also known as hydraulic fracturing, is a technique for obtaining gas and oil through shale rock. With the help of a high-pressure injection of water, sand, and chemicals into bedrock, gas and oil can flow into a well and be collected for sale.

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Explain any environmental issue that arose from fluid technology.

The force that acting upon it to change its state is a ball's movement is able to stop because of an unbalanced force that affects the ball's motion. The unbalanced force is called friction.

In the term of physics, Friction generally can be defined as a type of force that limits motion between two surfaces that are in contact. causing the force to be unbalanced. Friction usually occurs between the grass and the ball.  Frictional force generally can be defined as the force that occurs as a result of the contact of two surfaces due to the displacement of one or both of these objects. There are several examples of friction, Examples of frictional forces such as Pencil and paper friction while writing.  

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The length of time that it takes for the light from the outburst to pass the observer indicates the size of the AGN

light is a form of electromagnetic radiation emitted by objects like stars, light bulbs etc. It is a kind of kinetic energy which enables us to see the world around us.

The amount of time taken for light to travel between two points is usually taken into consideration when the distance is very large. The most commonly used unit of time with respect to the distance travelled by light is a light year which is used to determine the distances between stars and galaxies in outer space.

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42000 kilometers

Explanation:

distance is velocity × time

28000 ×1.5

42000

remember to match units

thats why i wrote 1.5 hours instead of 90minutes

The object is known as buleshift.

Object is a type of thing that can be seen or touch but it's is never alive .

When an object is moving to the  away from us, the light from the object is known as if the  redshift, and when an the  object is moving to the  towards us, the light from to  the object is known as of the  blueshift. Astronomers use by the  redshift and blueshift to deduce how far an object is away from Earth, in the  concept of key to charting by its  the universe's expansion.

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The statement is true. The s-wave shadow zone refers to an area on Earth's surface where no s-waves from earthquakes are detected. This shadow zone is caused by the refraction and reflection of s-waves as they pass through the Earth's interior layers, particularly the outer core.

The outer core is composed of molten iron and nickel, and its properties cause s-waves to be refracted and reflected, preventing them from being detected in certain areas on Earth's surface. Therefore, the location of the outer core plays a significant role in determining the location of the s-wave shadow zone.
true. The S-wave shadow zone is indeed caused by the location of the outer core. S-waves, or secondary waves, are a type of seismic wave that cannot travel through liquid. When S-waves encounter the Earth's outer core, which is a liquid layer composed primarily of molten iron and nickel, they are absorbed or refracted, creating a shadow zone on the opposite side of the Earth. This shadow zone helps scientists understand the composition and properties of the Earth's interior layers, including the outer core.

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Primordial nucleosynthesis is the process by which the nuclei of the very light elements (primarily hydrogen and helium, but also trace amounts of lithium and beryllium) formed during the first few minutes of the universe's existence. During this period, the temperature was high enough to allow nuclear fusion to occur, and the rapid expansion of the universe prevented any significant modification of the resulting element abundances.

Primordial nucleosynthesis favored the very light elements to form because the universe was too hot and dense for stable nuclei to form during the early minutes after the Big Bang. Instead, atomic nuclei fused together in a process known as nucleosynthesis, forming primarily hydrogen and helium with small amounts of lithium and beryllium.

The temperature of the universe during the first few minutes was high enough to allow nuclear fusion to occur. However, the temperature was not high enough to allow the fusion of heavier elements, so only the very light elements could be formed.Primordial nucleosynthesis was a crucial event in the evolution of the universe, as it set the stage for the subsequent formation of stars and galaxies. Without the formation of the light elements during this process, the universe would have looked very different than it does today.

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Answer:

I think its B but if not then its D

Explanation:

Answer:

b

Explanation:

Answer:

C) Dew Point

Explanation:

The dew point is the temperature at which air is saturated with water vapor, which is the gaseous state of water. When air has reached the dew-point temperature at a particular pressure, the water vapor in the air is in equilibrium with liquid water.

dew point

Explanation: mark me as brainlest

The value of x = -6.29 m

The center of gravity of the three particles X = m₁x₁ + m₂x₂ + m₃x₃/(m₁ + m₂ + m₃)

Given that the center of gravity is located at the origin, X = 0 m and m₁ = 5.00 kg, m₂ = 4.00 kg , m₃ = 7.00 kg, x₁ = 4.00 m, x₂ = 6.00 m, and x₃ = x m

Substituting the values of the variables into the equation, we have

X = m₁x₁ + m₂x₂ + m₃x₃/(m₁ + m₂ + m₃)

0 = 5.00 kg × 4.00 m + 4.00 kg × 6.00 m + 7.00 kg × x/(5.00 kg + 4.00 kg + 7.00 kg)

0 = 20.00 kgm + 24.00 kgm + 7.00x kgm/16.00 kg

Cross-multiplying, we have

20.00 kgm + 24.00 kgm + 7.00x kgm = 0

44.00 kgm + 7.00x kgm = 0

44.00 kgm = -7.00x kgm

Divide through by -7.00 kg, we have

x = 44.00 kgm/-7.00 kg

x = -6.29 m

So, the value of x = -6.29 m

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Answer:

The kinetic energy is 16 joules.                        

Explanation:

Kinetic energy (E) is given by:

\( E = \frac{1}{2}mv^{2} \)

Where:

m: is the mass

v: is the speed

When the kinetic energy is 4 joules, the speed of the object is:

\( v_{1}^{2} = \frac{2E_{1}}{m} = \frac{8}{m} \)                         

Now, if the speed is increased twice then we have:

\( E_{2} = \frac{1}{2}mv_{2}^{2} = \frac{1}{2}m(2v_{1})^{2} = \frac{1}{2}m[4(\frac{8}{m})] = 16 J \)

Therefore, the kinetic energy is 4 times the initial value.  

I hope it helps you!                                

Answer:

Waves are caused by wind, or are created by the friction between wind and surface water

Explanation:

Answer:

1.5 A

Explanation:

Applying

V = IR'....................... Equation 1

make I the subject of the equation

I = V/R'.................. Equation 2

Where V = Voltage, I = current, R' = Total resistance.

From the question,

In a series connection,

R' = 0.2+0.3+0.5+5 = 6 ohm.

Given: V = 9V

Substitute into equation 2

I = 9/6

I = 1.5 A.

Note: Since all the resistors are connected in series, thesame current flows through them

Therefore the current flowing through the 5 ohm resistor = 1.5 A

We will have the following:

The reason behind these materials being used to specifically protect against electrical hazards is that, they are insulators, at least to some degree; this means that when electricity enters in contact with the material it has trouble moving through and thus protects the user from the electricity (To certain degree).

In the absence of friction, a force applied to a body for a given amount of time, changes the momentum of the body

The average force per unit area exerted on the passenger with no seatbelt 5,400,000 N/m²

The average force per unit area for the passenger with seat belt 18,750 N/m²

The known parameters are;

The velocity of the car, v₀ = 15 m/s

The time it takes the passenger not wearing seat belt to strike the windshield, \(t_{ns}\) = 0.03 s

Area of contact between the head and the windshield, \(A_{ns}\) = 5 × 10⁻⁴ m²

The mass of the head, \(m_{h}\) = 5.4 kg

Time taken for the passenger wearing seat belt to come to rest, \(t_s\) = 0.50 s

The mass of the passenger wearing seatbelt, \(m_s\) = 75 kg

Area of the seat belt in contact with the passenger, \(A_s\) = 0.12 m²

Required:

To find the average force per unit area exerted on the two passengers

Solution:

According to Newton's second law on motion, force is equal to the product of mass and acceleration

\(Acceleration, \overline a = \dfrac{Change \ in \ velocity}{Elapsed \ time} = \dfrac{v - v_0}{t}\)

Therefore, the acceleration, force and average force per unit area of the passenger with no seat belt;

\(Acceleration, \overline a_{ns} = \dfrac{0 - 15 \, m/s}{0.03 \, s} = 500 \, m/s^2\)

\(F_{ns}\) = \(m_{h}\) × \(\overline a_{ns}\)

Which gives;

\(F_{ns}\) = 5.4 kg × 500 m/s² = 2,700 N

Force per unit area = Force/Area

\(P_{ns} = \dfrac{2,700 \, N}{5 \times 10 ^{-4} \ m^2} = 5,400,000 \ N/m^2\)

The average force per unit area exerted on the passenger with no seatbelt, \(P_{ns}\) = 5,400,000 N/m²

\(Acceleration, \overline a_{s} = \dfrac{0 - 15 \, m/s}{0.5 \, s} = 30 \, m/s^2\)

\(F_{s}\) = \(m_{b}\) × \(\overline a_{s}\)

Which gives;

\(F_{s}\) = 75 kg × 30 m/s² = 2,250 N

Force per unit area = Force/Area

The average force per unit area, for the passenger with seat belt is therefore;

\(P_{s} = \dfrac{2,250\, N}{0.12 \ m^2} = 18, 750\ N/m^2\)

The average force per unit area for the passenger with seat belt, \(P_s\) = 18,750 N/m²

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(a) The volume of water that flows into the atmosphere during a 10min period is 1,457,800 cm3 and that flows into the atmosphere in the left section of the pipe is  1,389,100 cm3. (b) The speed is 11.1 m/s. (c) The gauge pressure is 22,603 Pa

Water flows through a horizontal pipe and then out into the atmosphere at a speed of v1=15m/s. The diameters of the left and right sections of the pipe are 5.0cm and 3.0cm.

(a) To calculate the volume of water that flows into the atmosphere during a 10min period, use the formula V = Avt, where V is the volume of water, A is the cross-sectional area of the pipe, v is the speed of the water, and t is the time interval.

A = pi*r2, where pi is 3.14 and r is the radius of the pipe. For the left section of the pipe, the radius is 2.5 cm, and for the right section, it is 1.5 cm. Thus, for the left section, A = 3.14*(2.5 cm)2 = 19.63 cm2, and for the right section, A = 3.14*(1.5 cm)2 = 7.07 cm2.

The volume of water that flows into the atmosphere during a 10min period is V = (19.63 cm2 * 15 m/s * 600 s) + (7.07 cm2 * 15 m/s * 600 s) = 1,457,800 cm3.

The volume of water that flows into the atmosphere in the left section of the pipe during a 10min period is V = (19.63 cm2 * 15 m/s * 600 s) = 1,389,100 cm3.

(b) To calculate the speed v2,

use the formula v2 = (2*g*h)1/2, where v2 is the speed of the water, g is the acceleration due to gravity, and h is the height of the pipe. v2 = (2*9.81 m/s2*(2.3 m))1/2 = 11.1 m/s.

(c) To calculate the gauge pressure,

use the formula P = rho*g*h, where P is the pressure, rho is the density of water, g is the acceleration due to gravity, and h is the height of the pipe. P = (1000 kg/m3 * 9.81 m/s2 * 2.3 m) = 22,603 Pa.

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The graph that best represents the relationship between the velocity of an object thrown straight upward from the Earth's surface and the time that elapses while it is in the air is (option D)

Velocity is the directional speed of a moving object as an indicator of its rate of change in location as perceived from a certain frame of reference and measured by a specific time standard.

In other words, velocity is the primary indication of an object's location as well as its speed. It is defined as the distance traveled by an item in one unit of time. The displacement of an item in unit time is defined as velocity.

The equation that speaks to the velocity at a vertically upwards object that is accelerated against gravity and time is given as:

v = u + at; where

v = velocity

u = point from which the object starts to move

a is acceleration; and

t is time.

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Full Question:

See attached image

By default, Linux is designed to use all available memory for caching data, which may make it appear as if some memory is unused.

Linux is a free and open-source operating system that is widely used in servers, supercomputers, mobile devices, and other computing systems. It was created by Linus Torvalds in 1991 as a Unix-like operating system, and since then it has become one of the most popular operating systems worldwide.

Linux is highly customizable and provides a wide range of features and tools for developers, system administrators, and users. It is built on the principles of modularity, scalability, and stability, which makes it an ideal platform for running complex and mission-critical applications. One of the key strengths of Linux is its community-driven development model, which has resulted in a vast ecosystem of software and tools that can be easily integrated with the operating system.

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SW2 (config-if-range)channel-group 1 mode desirable. Ether-channel is made by combining multiple physical links that are seen as one link between two switches.

The possible combination to establish an ether-channel between SW1 and SW2 using LACP or PAgP .Ether-channel is a port link aggregation technology or port channel architecture used primarily on Cisco.

Ether-channel is used for providing fault tolerance and high-speed links between switches, routers and servers. To form an Ether-channel there are 2 protocol and link aggregation control protocol. Also load balances traffic across links in the bundle. Traffic is not necessarily distributed equally among all the links. Ether-channel will double or quadruple your bandwidth.

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After solving, a) The weight of it oil drop is 2.42 x 10⁻¹² N, b) the electric field strength needed to balance its weight is -1.51 x 10⁷ N/C

The weight of the oil drop can be calculated using the formula:

weight = mass x gravity

where mass = density x volume and gravity = 9.81 m/s².

The volume of the oil drop can be calculated using the formula for the volume of a sphere:

volume = (4/3) x pi x radius³

Substituting the given values:

volume = (4/3) x pi x (0.95 x 10⁻⁶ m)³ = 2.73 x 10⁻¹⁶ m³

mass = density x volume = 905 kg/m³ x 2.73 x 10⁻¹⁶ m³ = 2.47 x 10⁻¹³ kg

weight = mass x gravity = 2.47 x 10⁻¹³ kg x 9.81 m/s² = 2.42 x 10⁻¹² N

To balance the weight of the oil drop, the electric force on the excess electron must be equal and opposite to the weight of the drop. The electric force on the excess electron can be calculated using the formula:

electric force = charge x electric field

where charge is the charge on the excess electron and electric field is the strength of the electric field.

The charge on an electron is -1.602 x 10⁻¹⁹ C.

Substituting the given values and equating the electric force to the weight of the drop:

charge x electric field = weight

-1.602 x 10⁻¹⁹ C x electric field = 2.42 x 10⁻¹² N

Solving for electric field:

electric field = (2.42 x 10⁻¹² N) / (-1.602 x 10⁻¹⁹ C) = -1.51 x 10⁷ N/C

The negative sign indicates that the electric field is directed upward, opposite to the direction of gravity, in order to balance the weight of the drop.

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26 seconds per meter

Answer:

0.038m/s

Explanation:

5.0/130=0.038m

The statement is true. For constant-pressure operation of a plate-and-frame filter, the volume of the filtrate is proportional to the elapsed time.

For constant-pressure operation of a plate-and-frame filter, the volume of the filtrate is proportional to the elapsed time. This is because in constant-pressure filtration, the pressure difference across the filter cake is kept constant, and the rate of filtration is mainly determined by the resistance of the filter cake to the flow of liquid.

As the filtration proceeds, the filter cake grows thicker and more resistant to the flow of liquid, which causes the rate of filtration to decrease. However, the volume of the filtrate continues to increase with time, since the liquid that has already passed through the filter cake is not affected by its resistance.

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