How high did a worker lift a 25 kg bag of sand if it now has 2940 of gravitational potential energy

Answer:7.904*10^-4

Explanation:

Trust me

Answer:

B. Negative acceleration means this car is slowing down.

Explanation:

for the other screenshot

Average acceleration = change in velocity /change in time.

[a = ∆V/∆t] —this the formula.

NOTE:

u = initial velocity (velocity it started with)

v = final velocity (velocity it ended with)

t = time {the time you were given)

a = acceleration.

listing out our givens:

u =o —(the unit is m/s)

v = 40 —(the unit is also m/s)

t = 0.08 —(the unit is s) "s" means second(s).

Soo

a = 40-0 / 0.08 = 500 m/s² ( unit for velocity is m/s²)

( Remember when using the formula we subtract the initial from the final velocity.........I mean we remove the initial from final) if not you will get a negative answer or wrong answer).

also note: final velocity is always bigger in value than initial velocity EXCEPT it is in deceleration meaning for example a car that was speeding is gradually stopping then initial (the one it started with) will be bigger than the one it ended with (because as it gradually stops the speed reduces).

VELOCITY is speed in a specified direction.

you're super free to ask any questions

Good luck ✅.

Answer:

KE = 225000000 J

Explanation:

Answer:

10.954. from equation. KE=1/2m(v^2)

2KE=m(v^2) 6000=50(v^2) (v^2)=6000/50

(v^2)=120. square root for all v=10.954 m/s

When waves strike a reflective surface at an angle other than 90°, the law of reflection dictates their behavior, resulting in a change of direction and potential interference patterns depending on the specific conditions of the situation.

When waves strike a reflective surface at an angle other than 90°, a phenomenon known as the "law of reflection" governs their behavior. According to this law, the angle of incidence (the angle between the incoming wave and a line perpendicular to the surface) is equal to the angle of reflection (the angle between the reflected wave and the same perpendicular line). This principle applies to various types of waves, including light, sound, and water waves.

As a result of the law of reflection, waves reflecting off a surface at an angle other than 90° will change direction, maintaining the same angle with the reflective surface as they had upon striking it. This behavior is responsible for various optical effects and can influence sound propagation in rooms or the movement of water waves in bodies of water with irregularly shaped boundaries.

In some cases, multiple reflections can occur, leading to complex wave patterns and interference. This can create constructive or destructive interference, depending on the phase alignment of the waves. Constructive interference occurs when waves combine to produce a higher amplitude, while destructive interference occurs when waves combine to produce a lower amplitude or cancel each other out.

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The working formula for the electric charge is given by:
q = CεE
where q is the electric charge, C is the constant involving the properties of the gas environment, the plastic sphere, and the electric field chamber, ε is the permittivity of the gas environment, and E is the electric field strength.

The properties involved in the constant C are:

1. The radius of the plastic sphere (r) - measured in meters (m)

2. The pressure of the gas environment (P) - measured in Pascals (Pa)

3. The temperature of the gas environment (T) - measured in Kelvin (K)

4. The number density of the gas environment (n) - measured in number of particles per cubic meter (m-3)

5. The mobility of the ions in the gas environment (μ) - measured in meters squared per Volt-second (m2V-1s-1)

These properties are combined in the constant C to give the electric charge of the plastic sphere in the electric field chamber.

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The coefficient of friction is the ratio of frictional force to the normal force. The normal force acting on 15 Kg object is 147 N and the coefficient of friction is 0.149.

Friction is a kind of resistive force acting on a body that resist it from motion. Thus, frictional force will be always opposite to the applied force for the displacement of an object.

The normal force acting on a body of mass m is mg. Where, g is the acceleration due to gravity. Normal force acting on 15 kg object is :

N = mg

   = 15 × 9.8 m/s²

   = 147 N.

The coefficient of friction = Normal force / frictional force

                                          = 22 N/147 N

                                          = 0.149

Therefore, the coefficient of friction for an object with 15 kg and 22 N frictional force is 0.149.

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According to the NEC, a class 1 power limited circuit must be supplied from a source having a rated output of not more than 30 volts and 1000 volt-amperes.

NEC stands for National Electrical Code. It is a part of National Fire Protection Association (NFPA) of united states. NEC provides the standard and code for the safe installation of electrical wiring and equipment.

Class 1 power limited has a device that controls or regulates the current from the power source. This device prevents the overflow of the current in the circuit and thereby also prevents the short circuiting, overload, ground fall, etc.

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The temperatures measured using an uncalibrated probe and a calibrated probe in the ice-and-water bath showed a noticeable difference.

When comparing the temperatures measured with an uncalibrated probe and a calibrated probe in the ice-and-water bath, a significant difference was observed. An uncalibrated probe refers to a temperature-sensing device that has not been adjusted or standardized to ensure accurate readings.

It may have inherent inaccuracies due to factors such as manufacturing variations or drift over time. On the other hand, a calibrated probe has undergone a calibration process, where its readings have been adjusted to match a known reference or standard. Calibration involves comparing the probe's measurements to a known temperature source and making necessary adjustments to ensure accurate and reliable readings.

Due to the absence of calibration, the uncalibrated probe may display inaccurate temperature readings. The difference observed between the temperatures measured using the two probes could be attributed to this lack of calibration. The calibrated probe, having undergone the calibration process, is likely to provide more precise and reliable temperature measurements.

Therefore, it is essential to calibrate temperature-sensing devices regularly to ensure accurate results in scientific experiments, research, or any situation where precise temperature measurements are crucial. Calibration helps to minimize errors and discrepancies, allowing for more reliable data analysis and informed decision-making.

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Answer: The force the tractor exerts on the trailer is 8100 N.

Given that positive x axis is directed toward the direction of motion. The force the tractor exerts on the trailer can be found from Newton's second law which states that Force (F) = mass (m) × acceleration (a).

Here, the acceleration of the system is 1.5 m/s². To find the mass, we need to find the total force acting on the trailer. The forces acting on the trailer are the weight of the trailer and the tension in the tow bar.

The weight of the trailer is given by W = mg = 720 kg × 9.81 m/s² = 7063.2 N, where g is the acceleration due to gravity.Tension in the tow bar is equal to the force exerted by the tractor on the trailer.

Using Newton's second law, we have F = m × a. Therefore, the total force on the trailer is F = ma + W = 1080 N + 7063.2 N = 8143 N. The force the tractor exerts on the trailer is equal in magnitude to the tension in the tow bar.

Therefore, the force the tractor exerts on the trailer is F = 8143 N. Thus, the force the tractor exerts on the trailer is 8100N.

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Wave D has the lowest amplitude. The highest point of a wave is called amplitude.

The distance between from the crest of a wave to the next crest is known as the amplitude. It is denoted by a.

The standard equation for the SHM is found as;

\(\rm y = asin \omega t\)

Where, a represent the amplitude of the wave.

In the wave D it is observed that the distance from center axis to the highest point of the wave is smallest. Hence, wave D has the lowest amplitude.

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Answer:

To summarize what the expert answer said, it's the last box.

Explanation:

Answer:

\(a=190\ m/s^2\)

Explanation:

Mass of a hockey puck, m = 0.17 kg

Force exerted by the hockey puck, F' = 35 N

The force of friction, f = 2.7 N

We need to find the acceleration of the hockey puck.

Net force, F=F'-f

F=35-2.7

F=32.3 N

Now, using second law of motion,

F = ma

a is the acceleration of the hockey puck

\(a=\dfrac{F}{m}\\\\a=\dfrac{32.3}{0.17}\\\\a=190\ m/s^2\)

So, the acceleration of the hockey puck is \(190\ m/s^2\).

The magnitude of acceleration of the hockey puck is 190 m/s² .

Given data:

The mass of hockey puck is, m = 0.17 kg.

the magnitude of external force on the puck is, F = 35.0 N.

The magnitude of force of friction is, f = 2.7 N.

We need to find the net force acting on the puck first. For that consider the applied force in the x-direction. Then net force is,

F' = F - f

Solving as,

F' = 35.0 - 2.7

F' = 32.3 N

Now, use the Newton's Second law to obtain the magnitude of acceleration (a) as,

F' = ma

Solving as,

32.3 = 0.17 (a)

a = 32.3/0.17

a = 190 m/s²

Thus, we can conclude that the magnitude of acceleration of the hockey puck is 190 m/s² .

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The product among alcohol, gasoline, travel souvenirs, cigarettes that will have elastic demand is cigarettes.

Elastic demand refers to a situation in which a change in the price of a good or service results in a more significant change in the amount demanded. When the percentage change in quantity demanded is greater than the percentage change in price, the demand for the product is said to be elastic.

When the quantity demanded of a product decreases significantly when the price rises, the demand for the product is said to be elastic. Similarly, when a slight change in price causes a significant change in quantity demanded, the demand is said to be elastic. Conversely, if a product's price increases by a small percentage, and the demand for the product decreases by a smaller percentage, the demand for the product is said to be inelastic.

Cigarettes, of all the products listed above, are likely to have an elastic demand.

This is because smokers who are addicted to cigarettes are more likely to quit smoking or reduce their consumption in response to an increase in the price of cigarettes compared to the other goods.

Thus, a slight increase in the price of cigarettes is likely to cause a significant decrease in the number of cigarettes consumed.

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Based on the data provided, the thermal energies at the given time intervals are as follows:

The law of conservation of energy states that the total energy in an isolated system is conserved.

For a ball undergoing energy conversion between kinetic and potential energy, the sum of the energy remains constant.

Any reduction in total energy is due to conversion of some energy to thermal energy.

At time t = 0.0 secs

Thermal energy = 15.2 - (15.2 + 0.0)

Thermal energy = 0.0 J

At time, t = 0.8 secs

Thermal energy = 15.2 - (4.7 + 10.5)

Thermal energy = 0.0 J

At time, t = 2.0 secs

Thermal energy = 15.2 - (7.4 + 3.9)

Thermal energy = 3.9 J

At time, t = 2.8 secs

Thermal energy = 15.2 - (8.5 + 0.0)

Thermal energy = 6.7 J

Therefore, the thermal energies at the given time intervals are as follows:

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Answer:

Kinetic energy is the energy possessed in a body in motion

Answer:

wind energy is also called kinetic energy

The merry-go-round takes approximately 29.41 seconds to complete 2.00 rotations.

Given data:

Acceleration (α) = 0.135 rad/\(s^2\)

Number of rotations (θ) = 2.00

To find the time taken (t) for 2.00 rotations, we need to use the formula:

θ = 0.5 * α * \(t^2\)

Rearranging the formula, we get:

\(t^2\) = (2 * θ) / α

Plugging in the given values, we have:

\(t^2\) = (2 * 2.00) / 0.135

\(t^2\) = 29.63

Taking the square root of both sides, we find:

t ≈ √29.63

t ≈ 5.439

Therefore, the time taken for the merry-go-round to complete 2.00 rotations is approximately 5.439 seconds.

Note: It's important to round the final answer to an appropriate number of significant figures, considering the given data. In this case, we have used four significant figures in the final answer.

However, if we want to adhere to the given significant figures in the acceleration (0.135 rad/\(s^2\)), the answer should be rounded to three significant figures. In that case, the final answer would be approximately 5.44 seconds.

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Answer:

Explanation:

F = ma, so filling in:

15000 = 30000a and

a = .50 m/s/s

The acceleration of a train is 0.50 \(m/s^{2}\).

Acceleration is the rate of change of the velocity of an object with respect to time.

F = ma

a = F/m

a = 15000/30000

a = 0.50 \(m/s^{2}\)

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The expression for Q in terms of N is Q = 0.99N

Sure! Here are the details step-by-step:

The initial number, N, is increased by 10% to obtain P. This means that P is equal to N plus 10% of N.

  Mathematically, this can be written as: P = N + 0.10N.

The number P is then reduced by 10% to get Q. This means that Q is equal to P minus 10% of P.

  Mathematically, this can be written as: Q = P - 0.10P.

Substituting the value of P from step 1 into the equation in step 2:

  Q = (N + 0.10N) - 0.10(N + 0.10N).

Simplifying the expression:

  Q = N + 0.10N - 0.10N - 0.01N.

Combining like terms:

  Q = N - 0.01N.

Factoring out N:

  Q = (1 - 0.01)N.

Simplifying the expression:

  Q = 0.99N.

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The unit vector in the direction of the given vector is [-1, 1/2].

A unit vector in the direction of the given vector [−56/105], we need to normalize the vector by dividing each component by its magnitude.

The magnitude of the vector [−56/105] can be calculated as:

|[-56/105]| = \(\sqrt {((-56/105)^2)\) = \(\sqrt {(3136/11025)\) =\(\sqrt {(56^2 / 105^2\)) = 56/105

Normalize the vector, we divide each component by the magnitude:

[-56/105] / (56/105) = [-56/105] * (105/56) = [-1, 1/2]

a unit vector, we divide each component of the vector by its magnitude.

Dividing [-56/105] by (56/105) yields [-56/105] * (105/56) = [-1, 1/2].

A unit vector in the direction of the given vector is [-1, 1/2]. This means that the vector [-1, 1/2] has the same direction as the original vector [-56/105], but its length or magnitude is equal to 1.

Unit vectors are useful as they represent only the direction of a vector, allowing for easy comparison and calculation without concerns for the vector's scale or magnitude.

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A cart moving at a constant speed of 25 m/s possesses 438 J of kinetic energy, and the mass of the car is 1.6 kg.

The energy an object has as a result of motion is known as kinetic energy. A force must be applied to an object to accelerate it. We must put in the effort to apply force. After the work is finished, energy is transferred to the item, which then moves at a new, constant speed.

Definition: When an object is moving at a constant speed—that is, its speed does not change—we say it is moving at a constant speed. steady rate

Given:

KE = 500 J

v = 25 m/s

The formula for Kinetic Energy is given:

KE = ½ mv²

where: KE - Kinetic Energy

m - mass

v - velocity

Substituting the value of KE and v in the formula,

500 J = (½)(m)(25 m/s)²

m = (500 J)(2)/(25 m/s)²

m = 1.6 kg

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Answer: Jay

Explanation:

1 km in .1 hours is the same as 1 km in 6 minutes

1/4 km in .05 hours is the same as 1/4 km in 3 minutes or 1 km in 12 minutes

Answer: The Sun's energy is more concentrated on the equator than the poles. This is because the Sun's energy (in the form of warmth) is more direct at the equator, and less direct at the poles.

Explanation: You can see this with a flashlight. When you point the flashlight directly toward a tale, the light is very concentrated and right. However, when you point the flashlight toward the table at an angle, the light becomes more spread out and less concentrated.  This is why even though sometimes the North Poles and South Poles have 24 hours of sunlight, it never actually reaches a high temperature and instead, keeps it's cold temperature.

The Kingda Ka roller coaster at Six Flags NJ is the tallest steel roller coaster. The car has a mass of 9750 kg with passengers. Amount of kinetic energy must the coaster have  13.3megajoules.

To determine the amount of kinetic energy the Kingda Ka roller coaster must have before climbing the incline, we need to calculate the potential energy at the top of the incline. The mass of the car with passengers is 9750 kg, and the height of the incline is 139 m. We can ignore friction and air resistance for this calculation. The potential energy at the top of the incline is equal to the kinetic energy the coaster must have before climbing. The formula for potential energy is given by:

\(Potential Energy = mass * gravity * height\)

In this case, the mass of the car with passengers is 9750 kg, the acceleration due to gravity is 9.8 m/s², and the height of the incline is 139 m.

Substituting these values into the formula, we can calculate the potential energy:

Potential Energy = 9750 kg * 9.8 m/s² * 139 m

P.E = K.E = 9750 x 139 x 9.8 = 13,281,450J

= 13.3megajoules

Once we calculate the potential energy, we can consider it as the amount of kinetic energy the coaster must have before going up the incline, as the initial kinetic energy is converted to potential energy as the coaster climbs.

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To determine the relative humidity, dew point, and lifting condensation level (LCL) for the given conditions, we can use the provided temperature and water vapor values.

Here are the calculations for each scenario:

1. Temperature: 30°F, Water Vapor: 3.5 g/kg   - Relative Humidity (RH): N/A (Need the actual vapor pressure or saturation vapor pressure)

  - Dew Point: N/A (Need the actual vapor pressure or saturation vapor pressure)   - LCL: N/A (Need the temperature and dew point)

2. Temperature: 50°F, Water Vapor: 5.70 g/kg

  - Relative Humidity (RH): N/A (Need the actual vapor pressure or saturation vapor pressure)   - Dew Point: N/A (Need the actual vapor pressure or saturation vapor pressure)

  - LCL: N/A (Need the temperature and dew point)

3. Temperature: 70°F, Water Vapor: 3.5 g/kg   - Relative Humidity (RH): N/A (Need the actual vapor pressure or saturation vapor pressure)

  - Dew Point: N/A (Need the actual vapor pressure or saturation vapor pressure)   - LCL: N/A (Need the temperature and dew point)

4. Temperature: 80°F, Water Vapor: 5.60 g/kg

  - Relative Humidity (RH): N/A (Need the actual vapor pressure or saturation vapor pressure)   - Dew Point: N/A (Need the actual vapor pressure or saturation vapor pressure)

  - LCL: N/A (Need the temperature and dew point)

5. Temperature: 80°F, Water Vapor: 11.56 g/kg   - Relative Humidity (RH): N/A (Need the actual vapor pressure or saturation vapor pressure)

  - Dew Point: N/A (Need the actual vapor pressure or saturation vapor pressure)   - LCL: N/A (Need the temperature and dew point)

6. Temperature: 30°F, Mixing Ratio: 3.5

  - Relative Humidity (RH): N/A (Need the actual vapor pressure or saturation vapor pressure)   - Dew Point: N/A (Need the actual vapor pressure or saturation vapor pressure)

  - LCL: N/A (Need the temperature and dew point)

7. Temperature: 70°F, Mixing Ratio: 8.32   - Relative Humidity (RH): N/A (Need the actual vapor pressure or saturation vapor pressure)

  - Dew Point: N/A (Need the actual vapor pressure or saturation vapor pressure)   - LCL: N/A (Need the temperature and dew point)

8. Temperature: 70°F, Mixing Ratio: 3.66

  - Relative Humidity (RH): N/A (Need the actual vapor pressure or saturation vapor pressure)   - Dew Point: N/A (Need the actual vapor pressure or saturation vapor pressure)

  - LCL: N/A (Need the temperature and dew point)

9. Temperature: 80°F, Mixing Ratio: 17.59   - Relative Humidity (RH): N/A (Need the actual vapor pressure or saturation vapor pressure)

  - Dew Point: N/A (Need the actual vapor pressure or saturation vapor pressure)   - LCL: N/A (Need the temperature and dew point)

10. Temperature: 50°F, Mixing Ratio: 6.54

   - Relative Humidity (RH): N/A (Need the actual vapor pressure or saturation vapor pressure)    - Dew Point: N/A (Need the actual vapor pressure or saturation vapor pressure)

   - LCL: N/A (Need the temperature and dew point)

To calculate the relative humidity, dew point, and LCL, we require

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Force is positive if the mass accelerates downward. Use the formula T = M x A to determine the tension in the rope.

That direction is the pull that is referred to as tension. As a result, the tension will point toward the string or rope and away from the mass.

A mass suspended by a string is pulled upward by the string, exerting an upper force that shifts the tension to the upper side.

For instance, you should know that T = 9g x 2m/s2 = 18gm/s2 or 18N when trying to calculate T in a straightforward pulley system with a linked mass of 9g and an upward acceleration of 2m/s2 (newtons). The direction in which a string expands changes when it passes over an ideal massless pulley, but the string's tension is unaffected.

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Both caesium-137 and iodine-131 emit ionizing radiation, which can damage living tissue and increase the risk of cancer.

Isotopes are members of the same element's family but have variable numbers of neutrons despite having the same number of protons.

Iodine-131 and caesium-137 both produce ionizing radiation, which can harm living things and raise the risk of cancer.

Due to their varied half-lives and processes of decay, each isotope's danger has changed between 1986 and 2018 despite this.

Caesium-137 degrades gradually over time since it has a longer half-life of roughly 30 years. Iodine-131, on the other hand, degrades swiftly because of its significantly lower half-life of only around 8 days.

Thus, the risk has diminished over time as a result of radioactive decay.

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The displacement amplitude of a sound wave in air with a pressure amplitude of 4.00 × 10⁻³ Pa and a frequency of 10.0 kHz is approximately 2.05 × 10⁻⁷ m.

Sound waves propagate as variations in pressure and result in the displacement of air particles. The relationship between pressure amplitude and displacement amplitude in a sound wave is determined by the properties of the medium through which the wave travels. In air, the relationship can be described using the formula:

Displacement amplitude = Pressure amplitude / (angular frequency * speed of sound)

First, we need to convert the given frequency of 10.0 kHz to angular frequency. Angular frequency (ω) is calculated as 2π times the frequency. Therefore, ω = 2π * 10.0 kHz = 2π * 10,000 Hz.

The speed of sound in air at room temperature is approximately 343 m/s. Using the formula mentioned earlier, we can calculate the displacement amplitude:

Displacement amplitude = 4.00 × 10⁻³ Pa / (2π * 10,000 Hz * 343 m/s) ≈ 2.05 × 10⁻⁷ m.

Therefore, the displacement amplitude of the sound wave with a pressure amplitude of 4.00 × 10⁻³ Pa and a frequency of 10.0 kHz is approximately 2.05 × 10⁻⁷ m.

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The energy method is a technique used to determine the deflected shape of a rectangular plate subjected to a concentrated load. In this case, the plate is simply supported along each edge and carries a concentrated load F at a position (r1, y).

To find the deflected shape of the plate, we can use the series representation DO MAT nay Amn sin sin b TIL.

Now, let's break down the steps to determine the deflected shape using the energy method:

1. First, we need to calculate the bending moment caused by the concentrated load F. The bending moment can be given by the formula M = F * (b - r1),

where b is the width of the plate and r1 is the distance of the concentrated load from one edge.

2. Next, we need to find the deflection function, which represents the shape of the plate when it is deflected.

The deflection function can be represented by the series DO MAT nay Amn sin sin b TIL, where DO is the maximum deflection, A is a constant, m and n are positive integers, and a and b are the dimensions of the plate.

3. Now, we substitute the deflection function into the plate's governing equation. The governing equation for a rectangular plate simply supported along each edge is given by the biharmonic equation:

   ∇^4w = 0,

  where ∇^4 represents the Laplacian operator.

4. By substituting the deflection function into the biharmonic equation and solving for the unknown coefficients, we can determine the specific form of the deflection function that satisfies the boundary conditions.

5. Finally, with the determined coefficients, we can calculate the deflected shape of the plate by evaluating the deflection function at different points on the plate.

It's important to note that the exact determination of the coefficients Amn requires solving an infinite series of equations.

However, in practical applications, only a few terms of the series are usually considered, resulting in an approximation of the deflected shape.

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