77.5 grams of phosphorus (P) are in 2.50 moles of Phoshorus.
The mole is an amount unit similar to familiar units like pair, dozen, gross, etc. It provides a specific measure of the number of atoms or molecules in a bulk sample of matter.
A mole is defined as the amount of substance containing the same number of atoms, molecules, ions, etc. as the number of atoms in a sample of pure 12C weighing exactly 12 g.
Given,
Moles of P = 2.5
Atomic mass of P = 31
Moles = mass / atomic mass
mass = moles × atomic mass
= 2.5 × 31
= 77.5 g
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Using the Language of Science prefix and suffix lists, figure out the meanings of the following words:
Example: cardiology – heart study or science (study of the heart)
Osteocyte-
Dermatitis-
Epidermis-
Hematology-
Neuritis-
Protozoa-
Polysaccharide-
Macronutrients-
Intracellular-
Carnivore-
Based on the Language of Science prefix and suffix lists, the meanings of the following words are:
Osteocyte - bone cell (osteo- means bone and -cyte means cell)Dermatitis - skin inflammation (derma- means skin and -itis means inflammation)Epidermis - outer layer of skin (epi- means on top of and -dermis means skin)Hematology - study of blood (hema- means blood and -ology means study of)Neuritis - nerve inflammation (neuri- means nerve and -itis means inflammation)Protozoa - single-celled microorganisms (proto- means first or primitive and -zoa means animals)Polysaccharide - complex carbohydrate made up of many sugar units (poly- means many and -saccharide means sugar)Macronutrients - nutrients required in large amounts by organisms (macro- means large and -nutrient means food substance)Intracellular - located or occurring within a cell (intra- means within and -cellular means relating to cells)Carnivore - an animal that feeds on flesh (carni- means flesh and -vore means eater)What are polysaccharides?Long-chain polymeric carbohydrates known as polysaccharides are made up of monosaccharide units joined by glycosidic bonds.
Osteocytes are cells that make up the bone's mineralized tissue.
Macronutrients, often known as fat, protein, and carbohydrates, are the nutrients we require in greater amounts to give us energy.
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Calculate the mass of hydrochloric acid needed to react with 15.8 moles of zinc.
HCl + Zn -> H2 + ZnCl2
Answer:
240.1428
Explanation:
I hope this helps! :<
How many protons will there be if an atom has an atomic number of 6?
How many grams are in 7.07 x 1022 molecules of dinitrogen pentoxide?
Answer:
7198
Explanation:
this is the answer it is the correct one
In a 3.21g sample of the hydrate, CuSO4 • 10H2O (339.8 g/mol), how many grams of water are expected?
Therefore, 9.49 grams of water is expected in the given 3.21 g sample of CuSO4 • 10H2O.
To determine the number of water molecules in the given hydrate, CuSO4 • 10H2O, we'll need to find out the molar mass of the compound and the molar mass of water to make a comparison.
The molar mass of CuSO4 • 10H2O is calculated as:
CuSO4 → 159.6 g/mol10H2O → 180.16 g/mol (18.016 g/mol × 10)CuSO4 • 10H2O → 159.6 g/mol + 180.16 g/mol
= 339.76 g/mol (rounded to three significant figures)
Thus, we can see that the molar mass of CuSO4 • 10H2O is 339.76 g/mol.
We know that this hydrate consists of ten molecules of water, each having a molar mass of 18.016 g/mol (which is the same as the molar mass of water), and one molecule of CuSO4 with a molar mass of 159.6 g/mol.
Therefore, the number of moles of water in the sample is:
(10 × 18.016 g/mol) ÷ 339.76 g/mol = 0.527 moles
So, the mass of water is equal to its molar mass multiplied by the number of moles.
The mass of water is:
0.527 mol × 18.016 g/mol = 9.49 g
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2. Your school club sold 600 tickets to a chili supper. The chili recipe for 10 persons
requires 2 teaspoons of chili powder. How many teaspoons of chili powder will you
need altogether?
Answer: 120 Teaspoons
Explanation:
TS = Teaspoons; R = Recipe ; S=Servings
(2 TS/R)/(10S/R) = (10S/2TS)
(600S)/(10S/2TS) = 120 TS
the ratio of the heat added to the system to the corresponding temperature change of the system is referred to as the . group of answer choices internal energy enthalpy specific heat heat capacity
The ratio of the heat added to the system to the corresponding temperature change of the system is referred to as the d) heat capacity.
Heat capacity measurementThe heat capacity present in most systems is not constant, but depends on various conditions of the thermodynamic system. The heat capacity depends on the temperature itself, as well as the pressure and volume of the system.
Various ways to measure heat capacity can be done, which are generally carried out under conditions of constant pressure or constant volume. So that the specific capacity symbol is adjusted, becoming Cp for the specific capacity at constant pressure, and CV for the specific capacity at constant volume.
Gases and liquids are generally measured at constant volume. Measurements at constant pressure will produce a larger value because the constant pressure value also includes the heat energy used to do work to expand the volume of a substance when the temperature is increased.
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A 2.50 L sample of butane gas (C4H10), measured at 22.0
oC and 1.20 atm pressure, is combusted completely and
the carbon dioxide gas collected at the same pressure and
temperature. What volume of CO2 is produced?
Answer:
Same i guess hdjekfhkshfjfkr
The resultant volume of the carbon dioxide gas which is produced by the combustion of butane is 14.4L.
How do we calculate the moles of gas?Moles of any gas will be calculated by using the ideal gas equation as:
PV = nRT, where according to qustion for butane gas
P = pressure = 1.20 atm
V = volume = 2.50L
n = moles = ?
R = universal gas constant = 0.082 L.atm / K.mol
T = temperature = 22 degree celsius = 295.15 K
On putting values we get
n = (1.20)(2.50) / (0.082)(295.15) = 0.124 moles
Given chemical equation is:
C₄H₁₀ + 13/2O₂ → 4CO₂ + 5H₂O
From the stoichiometry of the reaction, it is clear that,
1 mole of C₄H₁₀ = produces 4 moles of CO₂
0.124 mole of C₄H₁₀ = produces 4×0.124=0.496 moles of CO₂
Now we calculate the volume for the carbon dioxide gas at the given pressure and temperature as:
V = (0.496)(0.082)(295.15) / (1.20) = 14.4 L
Hence required volume of CO₂ is 14.4 L.
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How do I convert μg/l to mol/kg?
Answer
To convert μg/l to mol/kg?
Step 1: from the mass in grams, find the number of moles by diving the mass by its molar mass
Step 2: To go from L to kg, take the volume given multiply it by density in kg/L
Use Hamilton’s Rule (Br>C) to determine which of the following values of "cost" yields evidence for altruism when B = 20 and r = 0.5.
a. Cost = 40
b. Cost = 30
c. Cost = 20
d. Cost = 15
e. None of the above
According to Hamilton's Rule (Br > C), altruism is supported when the cost (C) is less than the benefit (B) multiplied by the relatedness coefficient (r). Among the given options with B = 20 and r = 0.5, the value of cost that satisfies the condition for altruism is c. Cost = 20.
According to Hamilton's Rule (Br > C), altruistic behavior is favored when the benefit (B) multiplied by the relatedness coefficient (r) is greater than the cost (C). In this case, B = 20 and r = 0.5.
To determine the evidence for altruism, we need to compare the value of cost (C) to the value of B multiplied by r (Br). Let's evaluate each option:
a. Cost = 40:
Since 20 (B) multiplied by 0.5 (r) is equal to 10 (Br), which is less than 40 (C), altruism is not supported.
b. Cost = 30:
Again, 20 (B) multiplied by 0.5 (r) equals 10 (Br), which is less than 30 (C). Therefore, altruism is not supported.
c. Cost = 20:
With a cost of 20, 20 (B) multiplied by 0.5 (r) equals 10 (Br). Since 10 (Br) is equal to 20 (C), this satisfies the condition of Hamilton's Rule, suggesting evidence for altruism.
d. Cost = 15:
With a cost of 15, 20 (B) multiplied by 0.5 (r) equals 10 (Br), which is greater than 15 (C). Thus, altruism is not supported.
e. None of the above:
Since option c (Cost = 20) satisfies the condition of Hamilton's Rule (Br > C), indicating evidence for altruism, the correct answer is not "None of the above."
Therefore, based on Hamilton's Rule (Br > C), the value of cost that yields evidence for altruism in this scenario is c. Cost = 20.
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which of the following is a strong acid in aqueous solution? a. h3po4 b. hclo c. h3po3 d. hno2 e. hbr
The correct option is Hydrobromic acid (hbr), This is the strong Acid when compared to the other acids
Hydrobromic acid is the term for aqueous HBr.
Hydrogen bromide will be the name if there is no water, or if it is not aqueous, while hydrobromic acid will be the name if it is acidic and aqueous. Because it is acid, the suffix ic is used, and because it is aqueous, the suffix hydro is used.
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27. Interpreting Concepts One way to make lemonade is
to start by combining lemon juice and water. To make
the lemonade taste better you could add some sugar.
Is your lemonade-sugar combination classified as a
compound or a mixture? Explain your answer.
Explanation:
compound is already together use your brain man you take multiple things. to make lemonade aka a mixture of powder and water cmon man u gotta think about it logically
think about like this a bartebder asjs you what drink your having what is he going to do next ? hes going to make the drink so you can have another right? yha
observe what happens next
the bartender grabs a cup and goes to the ice and scoops it up he takes a bottle of vodka and puts it into the shot cup "a preset cup for alcohol measurement " he takes stawberry puraee (strawberry mix) and pyrs it into the drink and mixes it around by shaking it . puts a extractor on top of it and takes a glass and pours the drink in front of you into the glass. you dont see the vodka in there do you ? no you dont because its mixed in there same thing with lemonade.
if 5 half-lives have gone by and you have .03125 grams of an unstable parent substance, how many grams of stable daughter product should you have?
Answer:
Explanation:
The amount of daughter product that should be present after 5 half-lives depends on the specific radioactive decay process involved and the initial amount of the parent substance. In general, after each half-life, the amount of the parent substance decreases by half, and the corresponding amount of the daughter product increases by half.
In this case, with 5 half-lives gone by, the amount of the parent substance should have decreased by a factor of 2^5 = 32. Hence, the amount of the parent substance should be .03125/32 = 0.0009765625 grams.
Since the amount of daughter product is proportional to the amount of the parent substance that decays, the amount of daughter product should be 0.0009765625 * 32 = 0.03125 grams.
which statements correctly describe the changes that occur when an ionic solid dissolves in water? select all that apply.
The statements that describe the changes that occur when an ionic solid dissolves in water are an ionic solid is converted into ions when it dissolves in water and the ions of an ionic solid are hydrated by water molecules.
When an ionic solid dissolves in water, the ionic solid dissociates into its constituent ions. The positive ions are attracted to the negative pole of the water molecule while the negative ions are attracted to the positive pole of the water molecule. Consequently, the individual ions are surrounded by water molecules, forming a hydration sphere.
The following statements are correct regarding the changes that occur when an ionic solid dissolves in water:
1. An ionic solid is converted into ions when it dissolves in water.
2. The ions of an ionic solid are hydrated by water molecules.
3. Dissolution is an exothermic process that releases energy.
4. The solubility of an ionic solid in water is dependent on temperature and pressure.
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Calcium has a density of 2.72 g/ml. What is the mass of 24.9 ml of calcium?
for the hg spectra, there are 2 pairs of closely separated lines (one yellow-orange and the other being violet). why arent you able to distinguish the 2 violet lines while the two yellow lines could be "distinguished?" could you think of a way to distinguish the 2 violet lines?
The reason why the two yellow-orange lines can be distinguished while the two violet lines cannot be distinguished is due to the limitations of our eyes and the resolution of the instrument used to observe the spectra.
The two yellow lines are further apart in wavelength than the two violet lines, which means they are easier for our eyes and instruments to differentiate.
To distinguish the two violet lines, one possible solution is to use a higher resolution instrument that can resolve smaller differences in wavelength. Another solution could be to use a filter that blocks out one of the violet lines, allowing the other to be observed more clearly. Alternatively, using a technique called spectral deconvolution, where mathematical algorithms are applied to the spectra to separate the closely spaced lines, could also help to distinguish the two violet lines.
Overall, distinguishing closely spaced lines in a spectrum requires careful observation and the use of appropriate instruments and techniques.
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the orbital notation for nitrogen showed that in the valence shell there are ______ paired electrons and ______ unpaired.
The orbital notation for nitrogen showed that in the valence shell there are 3 paired electrons and 1 unpaired.
The electronic configuration of nitrogen is:
1s²2s²2p⁶.
Nitrogen has five valence electrons with 2 electrons in the 2s orbital and 3 electrons in the 2p orbital.
The 2p orbital has three orbitals, which can accommodate six electrons.
The electronic configuration of nitrogen can be represented as:
1s²2s²2p³Nitrogen has a valence shell of 5 electrons, with 3 of those electrons in the 2p orbitals.
There are three unpaired electrons in the 2p orbitals.
The valence shell electronic configuration of nitrogen can be shown using orbital notation as shown below:
Orbital notation is a symbolic representation of the configuration of electrons in the orbitals of an atom or molecule.
It represents the electron configuration of an atom by showing the energy level and sublevel for each electron in an atom.
It uses arrows to represent electrons and boxes to represent orbitals.
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the influence of a cerium additive on ultrafine diesel particle emissions and kinetics of oxidation.
The influence of a cerium additive on ultrafine diesel particle emissions and kinetics of oxidation can be significant. Cerium additives, such as cerium oxide (CeO2), are often used in diesel fuel as combustion catalysts to improve fuel efficiency and reduce emissions.
When cerium additives are introduced into diesel fuel, they can enhance the oxidation process of diesel particles. The cerium particles act as catalysts, promoting the conversion of hydrocarbons and carbon monoxide into less harmful gases like carbon dioxide. This helps to reduce the emissions of ultrafine particles, which are known to have adverse health effects.
The addition of cerium can also influence the kinetics of oxidation. It can lower the activation energy required for the oxidation reaction to occur, thereby increasing the rate of oxidation. This means that the diesel particles can be oxidized more quickly, leading to a reduction in particle emissions.
Furthermore, cerium additives have been found to have regenerative properties. They can form a protective layer on the surface of diesel particles, preventing the aggregation and growth of particles. This can help to maintain the small size of ultrafine particles, which are less harmful to human health compared to larger particles.
In conclusion, the addition of a cerium additive to diesel fuel can have a positive impact on ultrafine diesel particle emissions and the kinetics of oxidation. It can enhance the oxidation process, reduce particle emissions, and prevent particle growth. However, it is important to note that the specific effects may vary depending on the concentration of the additive, engine conditions, and other factors.
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Suppose 2.5 g of Compound A and 6.5 g of Compound B are consumed in a reaction that produces only one product, Compound C. Calculate the theoretical yield of C. Round your answer to the nearest 0.1 g. Suppose 6.0 g of C are actually isolated at the end of the reaction What is the percent yield of Compound C? Round your answer to the nearest whole percent. x ?
According to the given statement 70% is the percent yield of Compound C.
What are instances and compounds?A composite is a material made of two maybe more components. Examples of compounds includes carbon dioxide, water, and table salt.
Briefing:According to the information provided, a reaction that results in the production of Compound C uses 2.5 g of Compound A and 6.0 g of Compound B. We can presume that the mass of A and B that are both entirely consumed to form C has been calculated using the limiting reactant.
The sum of a masses of the reactants equals the total of the masses of the products according to the rule of mass conservation. so:
Theoretical yield
= sum of the reacting masses
Theoretical yield = (2.5 + 6.0) g
Theoretical yield = 8.5g
Percentage yield
= (actual yield/theoretical yield) * 100%
Percentage yield = (6.0 g / 8.5 g) * 100%
Percentage yield = 70%
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PLZZZZZZZZZZZZZZZZZZ15. As much as 90 percent of the oxygen in our atmosphere is the result of
a. photoperiodism
c. thigmotropism
b. respiration
d. photosynthesis
Answer:
The correct answer is - option D. photosynthesis.
Explanation:
It is shown by the study that most of the atmospheric oxygen comes from the photosynthesis by plants as oxygen is the byproduct of the photosynthesis. Photosynthesis is the process that uses light energy, carbon dioxide, and water to produce food or glucose/sugar and release oxygen as the byproduct.
Many scientists believe that oceanic phytoplankton that releases oxygen by the photosynthesis process makes 80 to 85% of the total oxygen of the atmospheric oxygen.
Answer:
D. photosynthesis.
Explanation:
A) Calculate the number of molecules in a deep breath of air whose volume is 2.25 L at body temperature, 37 ∘C, and a pressure of 740 torr .
B) The adult blue whale has a lung capacity of 5.0×103L. Calculate the mass of air (assume an average molar mass 28.98 g/mol) contained in an adult blue whale’s lungs at 0.5 ∘C and 1.03 atm , assuming the air behaves ideally.
The mass of air contained in an adult blue whale’s lungs at 0.5∘C and 1.03 atm, assuming the air behaves ideally is 6.03 kg.
a) Calculation for the number of molecules in a deep breath of air whose volume is 2.25 L at body temperature, 37∘C and a pressure of 740 torr, can be given by the following steps:
Volume of air in a deep breath,
V = 2.25 L
Temperature of air in a deep breath, T = 37+273 = 310 K
Pressure of air in a deep breath, P = 740 torr
Convert torr to atm. 1 atm = 760 torr
Pressure of air in a deep breath, P = 740/760 = 0.973 atm
The number of molecules in the deep breath, n = PV/RT
Where R is the gas constant. R = 0.08206 L atm K⁻¹ mol⁻¹
n = (0.973 atm × 2.25 L)/(0.08206 L atm K⁻¹ mol⁻¹ × 310 K)
n = 0.0925 mol
Number of molecules = n × Na
Where Na is Avogadro's number which is equal to 6.022 × 10²³ mol⁻¹
Number of molecules = 0.0925 mol × 6.022 × 1023 mol⁻¹
Number of molecules = 5.563 × 1022 molecules.
Therefore, the number of molecules in a deep breath of air whose volume is 2.25 L at body temperature, 37∘C, and a pressure of 740 torr is 5.563 × 10²² molecules.
b) Calculation for the mass of air contained in an adult blue whale’s lungs at 0.5∘C and 1.03 atm, assuming the air behaves ideally, can be given by the following steps:
Lung capacity of an adult blue whale = 5.0 × 103L
Volume of air in blue whale's lungs, V = 5.0 × 103L
Temperature of air in blue whale's lungs, T = 0.5+273 = 273.5 K
Pressure of air in blue whale's lungs, P = 1.03 atm
The number of moles of air, n = PV/RT
n = (1.03 atm × 5.0 × 103L)/(0.08206 L atm K⁻¹ the mass of air contained in an adult blue whale’s lungs at 0.5∘C and 1.03 atm, assuming the air behaves ideally is 6.03 kg.mol⁻¹ × 273.5 K)
n = 208.37 mol
The mass of air contained in an adult blue whale’s lungs, m = n × MM
Where MM is the average molar mass of air which is equal to 28.98 g mol⁻¹m = 208.37 mol × 28.98 g mol⁻¹ m
= 6034.58 g or 6.03 kg.
Therefore, the mass of air contained in an adult blue whale’s lungs at 0.5∘C and 1.03 atm, assuming the air behaves ideally is 6.03 kg.
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At the threshold of activation (aka critical firing level), which ion has stronger net pressure (combined effects of the forces of EP and Diffusion) acting upon it?a. Na+b. K-c. Na-d. Cl+e. K+
At the threshold of activation, the ion with the stronger net pressure acting upon it is a. Na+. This is because at the threshold of activation, there is a higher concentration of Na+ ions outside the cell compared to inside the cell, creating a net inward pressure on the Na+ ion.
This is because, at the threshold of activation, the membrane potential reaches a level where voltage-gated sodium channels open, allowing Na+ ions to flow into the cell due to their electrochemical gradient. The combined forces of EP and diffusion create a strong net inward pressure for sodium ions, which leads to the depolarization phase of the action potential.
Additionally, the electrostatic force (EP) acting on Na+ is also inward due to the positively charged extracellular environment. The combined effects of these two forces create a stronger net pressure on Na+ compared to the other ions listed.
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What is one way that you could increase the rate of a chemical reaction occurring between two solutions (dissolved in liquid)? You must explain your answer in terms of particle behavior and collisions for the point.
Answer:
Putting fire below them
Explanation:
Fire is a method used for burning stuff faster as the heat transforms into energy
what is the standard cell notation of a galvanic cell made with zinc and aluminum
Answer:
Explanation:
0.76 V
The voltmeter shows that the standard cell potential of a galvanic cell consisting of a SHE and a Zn/Zn2+ couple is E°cell = 0.76 V.
________ is the major intermolecular attraction responsible for the relatively high boiling points of alcohols.
Answer:
Hydrogen bonding is the major intermolecular attraction responsible for the relatively high boiling points of alcohols.
a solution is made by dissolving 2.3g ethanol (c2h5oh) in 16.2 g water. what is the mass percent of ethanol?
The solution's ethanol has a molality of 3.70 mol/kg. The amount of material that must be dissolved in a given mass of a solvent is related to a solution's molality.
From the information provided:
water mass = 16.2 g
mass of ethanol = 2.3 g
1000 g make up 1 kilogram of water. There are 0.0162 kilogram of water in 16.2 g of water.
As a result, ethanol's molality is:
= 3.70 mol/kg
Molality is determined by dividing the kilograms of solvent by the moles of solute (the substance being dissolved) (the substance used to dissolve).
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he hybridization of one s and one p orbital will result in the formation of _____ sp hybrid orbitals. This will leave _____ unhybridized p orbital(s), which is/are at right angles to the hybrid orbitals. The formation of a group of sp2 hybrid orbitals leaves _____ unhybridized p orbital(s). Multiple choice question. two; two; no two; two; one three; two; one one; two; one
The complete statement is "The hybridization of one s and one p orbital will result in the formation of two sp hybrid orbitals. This will leave two unhybridized p orbital(s), which is/are at right angles to the hybrid orbitals. The formation of a group of sp2 hybrid orbitals leaves one unhybridized p orbital(s). " Option B. This is further explained below.
What is hybridization?Generally, hybridization is simply defined as hybridization describes the offspring produced when one species of plant or animal mates with another.
In conclusion, After a cluster of sp2 hybrid orbitals forms, there is still one p orbital that is not hybridized (s).
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A 58. 6g sample of metal is heated to 95. 2C and then placed in a calorimeter containing 100. 0g of water (specific heat=4. 184 J/gC). The initial temperature of water is 21. 6C. If the final temperature of the water and metal is 25. 4C, what is the specific heat of the metal?
The specific heat of the metal is approximately \(\(0.397 \, \text{J/g°C}\)\). The specific heat capacity of a substance is a measure of how much heat energy is required to raise the temperature of a given amount of the substance by 1 degree Celsius.
In this case, we can use the principle of conservation of energy to determine the specific heat of the metal. First, we need to calculate the heat absorbed by the water in the calorimeter. We can use the equation:
\(\(q_{\text{water}} = m_{\text{water}} \cdot c_{\text{water}} \cdot \Delta T_{\text{water}}\),\)
where \(\(m_{\text{water}}\)\) is the mass of the water, \(\(c_{\text{water}}\)\) is the specific heat of water, and \(\(\Delta T_{\text{water}}\)\) is the change in temperature of the water.
Plugging in the given values, we find:
\(\(q_{\text{water}} = 100.0 \, \text{g} \cdot 4.184 \, \text{J/g°C} \cdot (25.4 - 21.6) \, \text{°C} = 1586.88 \, \text{J}\).\)
Next, we can calculate the heat lost by the metal, which is equal to the heat gained by the water:
\(\(q_{\text{metal}} = -q_{\text{water}}\).\)
Using the equation for heat transfer, \(\(q = m \cdot c \cdot \Delta T\)\), we can rearrange it to solve for the specific heat of the metal, \(\(c_{\text{metal}}\)\):
\(\(c_{\text{metal}} = \frac{{q_{\text{metal}}}}{{m_{\text{metal}} \cdot \Delta T_{\text{metal}}}}\).\)
Plugging in the given values, we find:
\(\(c_{\text{metal}} = \frac{{-1586.88 \, \text{J}}}{{58.6 \, \text{g} \cdot (25.4 - 95.2) \, \text{°C}}} \approx 0.397 \, \text{J/g°C}\).\)
Therefore, the specific heat of the metal is approximately \(\(0.397 \, \text{J/g°C}\)\).
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Which body systems within marching band members are interacting so they can play their instruments while walking in the parade? List the systems below.
Squirrel: Digestive, Circulatory, Muscular, and Nervous systems.
Soccer: Skeletal/muscular, circulatory, respiratory, and body systems.
What is body systems?For Squirrel:
The digestive system functions to break food down into smaller pieces that are more suitable for swallowing and absorbing the available nutrients. It transports to various cells of living organisms.
musculature allows animals to keep their balance on branches and avoid falling.
The nervous system controls all living things. The nervous system controls all physical activity. Among many other functions, it is involved in maintaining balance and maintaining alertness during meals.
Soccer player:
This person is trying to hit the ball to score a goal. He seems to be adjusting his arms and legs to allow this.
The muscular and skeletal systems work together to support and strengthen the body. They allow the movement of the whole body to reach the target.
The respiratory system is also involved in this person's running performance. He has to breathe constantly to get enough oxygen while running and exhaling exhaust fumes.
The circulatory system transports oxygen to various cells in the body that use it on demand, especially muscle cells. The system also removes waste.
The nervous system controls all physical activity. It performs a variety of functions, including maintaining balance and coordination while running, alerting other players and focusing on the ball, and controlling a player's thoughts and strategies during the game.
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How many grams of NaBr is needed to make 2.00L of 0.50M solution?
4g
1g
0.25g
103g
102.89 grams of NaBr is needed to make 2.00 L of 0.50 M solution.
What is NaBr ?
NaBr is the chemical formula for sodium bromide, which is an ionic compound made up of sodium cations (Na+) and bromide anions (Br-).
To calculate the number of grams of NaBr needed to make a 0.50 M solution of 2.00 L, we can use the formula:
mass = moles × molar mass
Where moles = volume × concentration, and the molar mass of NaBr is 102.89 g/mol.
So, moles of NaBr = 2.00 L × 0.50 mol/L = 1.00 mol
mass of NaBr = 1.00 mol × 102.89 g/mol = 102.89 g
Therefore, 102.89 grams of NaBr is needed to make 2.00 L of 0.50 M solution.
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