310.56 grams of sodium sulfate will be formed if you start with 175.0 grams of sodium hydroxide and have an excess of sulfuric acid.
To determine how many grams of sodium sulfate will be formed starting with 175.0 grams of sodium hydroxide and an excess of sulfuric acid, follow these steps:
1. Write the balanced chemical equation: 2 NaOH + H2SO4 → Na2SO4 + 2 H2O
2. Calculate the molar mass of sodium hydroxide (NaOH): (22.99 g/mol for Na) + (15.99 g/mol for O) + (1.01 g/mol for H) = 40.00 g/mol
3. Calculate the moles of sodium hydroxide (NaOH): 175.0 g / 40.00 g/mol = 4.375 moles
4. Determine the mole ratio between sodium hydroxide (NaOH) and sodium sulfate (Na2SO4): From the balanced equation, 2 moles of NaOH react to produce 1 mole of Na2SO4.
5. Calculate the moles of sodium sulfate (Na2SO4) produced: (4.375 moles NaOH) x (1 mole Na2SO4 / 2 moles NaOH) = 2.1875 moles Na2SO4
6. Calculate the molar mass of sodium sulfate (Na2SO4): (2 x 22.99 g/mol for Na) + (32.07 g/mol for S) + (4 x 16.00 g/mol for O) = 142.04 g/mol
7. Calculate the mass of sodium sulfate (Na2SO4) formed: (2.1875 moles Na2SO4) x (142.04 g/mol) = 310.56 grams
Therefore, 310.56 grams of sodium sulfate will be formed if you start with 175.0 grams of sodium hydroxide and have an excess of sulfuric acid.
To know more about sodium sulfate refer here: https://brainly.com/question/14464099#
#SPJ11
the initial concentration of reactant in a first-order reaction is 0.27 m and has a rate constant of 0.75 s-1. what is the concentration (mol/l) of reactant after 0.75 s?
After 0.75 s, the reactant's final concentration was 0.0672 mol/L.
Log [Initial concentration] = - rate constant time + log [Initial concentration] has been supplied as the rate reaction for the first-order reaction. [Last-ditch effort]
The reaction described has:
0.27 M for the first concentration
0.75 s/rate constant
Time = 0.75 s
One can provide the ultimate concentration by:
log [0.27] = - 0.75 *0.75 + log [Final concentration]
log [0.27]=-0.5625+log [Final concentration]
log [0.27] + 0.5625 = log [Final concentration]
log [Final Concentration]=1.31+0.5625
log [Final concentration] = 1.8725
Final concentration: 0.0672 mol/L
After 0.75s, the reactant's final concentration was 0.0672 mol/L.
To learn more about concentration, refer:-
https://brainly.com/question/10725862
#SPJ4
Which of the following does NOT move thermal energy
through convection currents on Earth?
a the ocean
b the atmosphere
€ molten rock
What is the elements don’t bond with other elements because their outer shell is filled?
Answer:
Inert gases or noble gases
Explanation:
These gases have 8 outer shells meaning their full so they won't allow chemical reactions therefore providing an inert environment hence the name inert gas.
On the locating the epicenter exploration what city was near the epicenter?
A)Rio de Janeiro
B) Buenos Aires
C)Valparaiso
D)Lima
13 POINTS!! Helpp
How does acid base extraction work.
Answer:
it can be done using the method of lithium paper
A sample of unknown element X contains the following isotopes: 80% of C -64, 15% of X - 65, and 5% of X-66. What is the average atomic mass of element X? Can somebody help me with this question. Will mark brainliest.
Answer:
64.25
Explanation:
Average atomic mass = percentage × mass of all isotopes/ 100
Relative atomic mass = 80*64+15*65+5*66/100
=5120+975+330/100
=6425/100
64.25
¿Por qué crees que es importante conocer nuestra condición económica antes de practicar actividades físicas regularmente?
Answer:
el ejercicio físico ayuda a gente a perder peso y reduce el riesgo de desarrollar algunas enfermedades. el ejercicio físico regular el reducen los riesgos de ciertas enfermedades como obesidad, diabetes tipo 2 e hipertensión el ejercicio físico puede ayudar a mantener el cuerpo en un peso saludable pero a veces algunos tienen enfermedades al corazón o asma y les afecta a ser demasiado práctica esa actividad
which group of elements are found as diatomic molecules?
The group of elements found as diatomic molecules at standard conditions (room temperature and pressure) is known as the diatomic elements. These elements exist naturally as diatomic molecules, meaning they form stable molecules by bonding two atoms of the same element together.
The diatomic elements are:
1. Hydrogen (H₂)
2. Nitrogen (N₂)
3. Oxygen (O₂)
4. Fluorine (F₂)
5. Chlorine (Cl₂)
6. Bromine (Br₂)
7. Iodine (I₂)
These elements are all found in Group 17 (Group VIIA) of the periodic table, except for hydrogen which is in Group 1 (Group IA). Diatomic molecules are formed due to the sharing of electrons through covalent bonding between the atoms of the same element.
It's important to note that under certain conditions, some elements can exist as diatomic molecules temporarily, but not under standard conditions. For example, elements such as sulfur (S₈) and phosphorus (P₄) can form diatomic molecules under specific temperature and pressure conditions.
The diatomic nature of these elements has important implications for their reactivity and chemical properties.
for more questions on diatomic
https://brainly.com/question/15067534
#SPJ8
Calculate mass of unhydrous copper 2 sulphate in 55cm3 of a 0,20 mol/dm3 solution of copper 2 sulphate
The mass of anhydrous copper(II) sulfate in 55 cm³ of a 0.20 mol/dm³ solution is approximately 1.76 grams.
To calculate the mass of anhydrous copper(II) sulfate in a given solution, we need to consider the molar concentration of the solution and the volume of the solution.
Given:
Molar concentration of the solution (c) = 0.20 mol/dm³
Volume of the solution (V) = 55 cm³
First, we need to convert the volume from cm³ to dm³:
1 dm³ = 1000 cm³
55 cm³ = 55/1000 dm³ = 0.055 dm³
Next, we can use the formula:
Mass = Molar concentration × Volume × Molar mass
The molar mass of anhydrous copper(II) sulfate (CuSO₄) is:
Atomic mass of Cu = 63.55 g/mol
Atomic mass of S = 32.07 g/mol
4 × Atomic mass of O = 4 × 16.00 g/mol = 64.00 g/mol
Total molar mass = 63.55 + 32.07 + 64.00 = 159.62 g/mol
Now we can calculate the mass:
Mass = 0.20 mol/dm³ × 0.055 dm³ × 159.62 g/mol
Mass ≈ 1.76 grams
Therefore, the mass of anhydrous copper(II) sulfate in 55 cm³ of a 0.20 mol/dm³ solution is approximately 1.76 grams.
Learn more about anhydrous copper here
https://brainly.com/question/29027527
#SPJ11
are chemical reactions always dangerous
Answer:
Sometimes they are and sometimes they are not
PLEASE HELP ME QUICKLY!
Imagine you are at your favorite beach. The sun is shining and you are enjoying the ocean breeze. The temperature is about 89F. You take your shoes off and realize that the sand is almost too hot to walk on. You run to the water's edge to wet your feet after the walk over the sand and realize that the water is almost too cold. Explain the temperature difference between the sand and water using Thermodynamics.
Answer:
The specific heat of water is more specific than the heat of sand, therefore, it will take more energy to raise the same amount of water with the same temperature.
Explanation:
The temp is 89 F so, 31.67° C
The specific heat of the water is 4.184 J/g° C
The specific heat of the sand is 0.290 J/ g° C
The heat is the amount of energy that is needed to raise the temp. of the substance
You will need a lot more energy to raise the temp of the water then of the same amount of sand, therefore, because of the specific lower heat of the sand it will raise it's temperature quicker compared to water.
What is the molar mass for Cr(NO3)2
To find the molar mass of the given compound, we have use the molar masses of each element present in the molecule and multiply them by the number of atoms of each element in the molecule. Once we have these values, add them.
It means that we have to multiply the molar mass of Cr times 1, the molar mas of N times 2 and the molar mass of O times 6:
\(52g/mol\cdot1+14g/mol\cdot2+16g/mol\cdot6=176g/mol\)It means that the molar mass of Cr(NO3)2 is 176g/mol.
A boy kicks a ball with a force of 40 n. at exactly the same moment, a gust of wind blows in the opposite direction of the kick with a force of 40 n.what happened to the ball?
The ball would experience a net force of 0 N and would not move in either direction.
When the boy kicks the ball with a force of 40 N, he applies a force in one direction. At the same moment, a gust of wind blows in the opposite direction of the kick with a force of 40 N. These two forces act in opposite directions, and therefore cancel each other out.
According to Newton's first law of motion, an object at rest will remain at rest, and an object in motion will continue in motion in a straight line at a constant speed, unless acted upon by a net external force. In this case, the net force on the ball is 0 N, which means that the ball will not move in either direction.
This scenario highlights the importance of understanding net forces when analyzing the motion of objects. In the absence of a net force, the ball will not accelerate, and its velocity will remain constant.
To know more about Newton's first law, refer here:
https://brainly.com/question/29775827#
#SPJ11
The hydroxide ion concentration in an aqueous solution at 25 ∘
C is 0.026M. The hydronium ion concentration is M. The pH of this solution is The pOH is 1. The formula for the conjugate acid of Cl −
is 2. The formula for the conjugate base of NH 4
+ is
The hydronium ion concentration is \(3.85 \times10-13M\). The formula for the conjugate acid of Cl− is HCl, and the formula for the conjugate base of NH4+ is NH3.
The hydroxide ion concentration in an aqueous solution at 25 ∘C is 0.026M.
The pOH is 1.
Since \(pH + pOH = 14,\)
therefore,
\(pH = 14 - pOH\)
\(pH = 14 - 1\)
\(pH = 13.\)
Therefore, the pH of this solution is 13.
Now, we will calculate the hydronium ion concentration, using the relation;
\(Kw = [H+][OH-]\)
Where
\(Kw = 1.0 \times 10-14[H+][OH-]\)
\(Kw = 1.0 \times10-14[H+][0.026]\)
\(Kw = 1.0 \times10-14[H+]\)
\(Kw = \frac{ (1.0 \times 10-14)}{[0.026][H+]}\)
\(Kw = 3.85 \times 10-13M\)
Therefore, the hydronium ion concentration is \(3.85 \times10-13M.\)
The formula for the conjugate acid of Cl− is HCl, and the formula for the conjugate base of NH4+ is NH3.
For such more questions on hydronium ion
https://brainly.com/question/31742102
#SPJ8
Chaperonins such as the GroEL/ES system function ____
A) with thermophilic proteins only
B) at low pH
C) in an ATP-dependent fashion
D) in vitro only
E) in a non-aqueous environment
The GroEL/ES system, a type of chaperonin, functions in an ATP-dependent fashion. It is not limited to thermophilic proteins, low pH conditions, or in vitro environments. Moreover, chaperonins like GroEL/ES operate in an aqueous environment, not a non-aqueous one.
Chaperonins, such as the GroEL/ES system, play a crucial role in protein folding and assembly. They assist in the folding of newly synthesized or denatured proteins, ensuring proper conformation and preventing aggregation. The GroEL/ES system functions through an ATP-dependent mechanism. ATP binding and hydrolysis provide the energy necessary for conformational changes and the release of folded proteins. Unlike some other chaperones that may be specific to thermophilic proteins, the GroEL/ES system is not limited to such proteins. It can assist in the folding of a wide range of substrates. Similarly, chaperonins like GroEL/ES are not confined to low pH conditions. While changes in pH can influence protein stability and folding, chaperonins operate efficiently across a broad pH range. Furthermore, chaperonins function in vivo within the cellular environment, ensuring proper protein folding and preventing misfolding or aggregation. While they can also be studied in vitro, their primary role is to assist in protein folding in living cells. Additionally, chaperonins like GroEL/ES operate in an aqueous environment, as proteins require water for their proper folding and function. Non-aqueous environments are generally unsuitable for protein folding and can disrupt the folding process. In summary, the GroEL/ES system functions in an ATP-dependent manner, assisting in the folding of a diverse range of proteins within the aqueous environment of living cells. It is not limited to thermophilic proteins, low pH conditions, or in vitro studies.
Learn more about thermophilic here: brainly.com/question/31714645
#SPJ11
D) 7
20 points
2. How does the concept of conservation of mass apply to chemical
reactions? (hint: the Law of Conservation of Mass) *
a) the reactants and products have exactly the same molecules
b) the change in the amount of matter is equal to the change in energy
o
c) the reactants and products have exactly the same atoms
d) the change in the amount of matter is only a small percentage of the total mass
W
3. How many Oxygen (O) atoms are in the chemical formula below?. *
Answer:
the reactants and products have have exactly the same molecules
The reactants and products have exactly the same atoms, therefore the concept of conservation of mass applies to chemical reactions. Therefore, option (b) is correct.
What is the law of conservation of matter?According to this law, matter can neither be created nor destroyed, but can be converted from one form to another. So the same number and type of atoms in a chemical reaction before and after the chemical change are present.
The initial substances or reactants change into different substances or products in any chemical change. Both the reactants and products are made up of atoms as all matter is made up of atoms.
The matter is conserved as the equal number of atoms of each element in the reactants and products, and the total mass of the reactants must equal the total mass of the products.
The law of conservation of mass can be only followed in a chemical reaction if the reactants and products have exactly the same atoms.
Learn more about the law of conservation of matter, here:
brainly.com/question/13383562
#SPJ2
15. The specific heat of silver is 0.24 J/g*^ 0 C How many joules of energy are needed to warm 4.37 g of silver from 25.0C to 27.5 degrees * C ? 0.14 J 46 J 0.022 J
2.62J of energy will be required to warm a silver metal from a temperature of 25°C to 27.5°C.
How to calculate joules?The energy required in a calorimetry can be calculated using the following formula:
Q = m × c × ∆T
Where;
Q = quantity of heat absorbed or releasedm = mass of substancec = specific heat capacity∆T = change in temperatureAccording to this question, 4.37 g of silver should be heated from 25°C to 27.5°C. The heat required is as follows:
Q = 4.37 × 0.24 × (27.5 - 25)
Q = 1.0488 × 2.5
Q = 2.62J
Therefore, 2.62J of energy will be required to warm a silver metal from a temperature of 25°C to 27.5°C.
Learn more about energy at: https://brainly.com/question/1932868
In response to a rapid increase of organic acid in the body, you would expect to observe:
In response to a rapid increase of organic acid in the body, you would expect to observe acidosis.
An increase in organic acid levels in the body can lead to a condition called acidosis. Acidosis occurs when there is an excess accumulation of acid or a decrease in the body's ability to remove acid effectively. This disrupts the normal pH balance in the body, shifting it towards the acidic side. The main indicators of acidosis include a decrease in blood pH and an increase in hydrogen ion concentration.
The body maintains a delicate acid-base balance, and any disruption to this balance can have adverse effects on various physiological processes. Acidosis can have several causes, such as metabolic disorders, kidney dysfunction, or respiratory conditions. The symptoms of acidosis can vary depending on the severity and underlying cause but may include fatigue, confusion, shortness of breath, increased heart rate, and potentially more severe complications if left untreated. Prompt medical attention is necessary to identify the cause of acidosis and restore the acid-base balance in the body to prevent further complications.
Learn more about pH balance here: brainly.com/question/29775377
#SPJ11
h0 = 176 kj·mol-1 and i:!.g0 = 91.2 kj·mol-1 at 298 k. what is the value of i:!.g at 1000 k?
The value of ΔG at 1000 K is approximately 123643.2 kJ·mol\(^(-1)\).
How to calculate ΔG at 1000 K?To calculate the value of ΔG at 1000 K, we can use the equation:
ΔG2 = ΔG1 + ΔH(T2 - T1)
Where:
ΔG2 is the change in Gibbs free energy at the desired temperature (1000 K)
ΔG1 is the change in Gibbs free energy at the initial temperature (298 K)
ΔH is the change in enthalpy (heat) of the reaction
T2 and T1 are the desired and initial temperatures, respectively.
Given:
ΔH0 = 176 kJ·mol\(^(-1)\)
ΔG0 = 91.2 kJ·mol\(^(-1)\)
T1 = 298 K
T2 = 1000 K
Substituting the values into the equation:
ΔG2 = ΔG1 + ΔH(T2 - T1)
ΔG2 = 91.2 kJ·mol\(^(-1)\) + 176 kJ·mol\(^(-1)\)(1000 K - 298 K)
Now, let's calculate ΔG2:
ΔG2 = 91.2 kJ·mol\(^(-1)\)+ 176 kJ·mol\(^(-1)\)(702 K)
ΔG2 = 91.2 kJ·mol\(^(-1)\) + 123552 kJ·mol\(^(-1)\)
ΔG2 = 123643.2 kJ·mol\(^(-1)\)
Therefore, the value of ΔG at 1000 K is approximately 123643.2 kJ·mol\(^(-1)\).
Learn more about value of ΔG
brainly.com/question/13700386
#SPJ11
40 POINTS!! AND IF YOU DONT GET IT RIGHT IMMA REPORT YOU AND PLEASE HELP ME
Once upon a time, a mother duckling sat on her eggs with great impatience. How long would it be before they hatched? Finally, one summer day, the mother duckling watched as the eggs cracked, and her cute, yellow ducklings waddled into the world. She was filled with joy until she noticed that one egg, which was larger than all of the others, remained. After many hours, the egg cracked. A large, gray duckling emerged. The mother duck was horrified at the duckling's appearance. The mother duck's only comfort was that the ugly duckling could swim and dive under the water.
As the ugly duckling grew, many animals in the pond criticized him. His feathers were too dark, his neck was too long, and his body was too big. His fellow ducklings refused to recognize that underneath the feathers, the ugly duckling was kind, good, and gentle. The ugly duckling shed many tears because none of the other animals would play with him.
One day, the ugly duckling decided to run far away and find a place where the animals would look past his appearance and be kind and friendly. He came to a pond and sighted three beautiful swans. Their white feathers, long necks, and kind eyes made them look like royalty. The ugly duckling sighed in disappointment. He believed that the swans would never be his friends and looked down into the pond in despair. Then, his eyes opened wide, for he saw his reflection. To his great astonishment, the ugly duckling discovered that he was a beautiful, royal swan! The swans welcomed their new friend, whose lovely appearance was matched only by his kind heart. He now felt like he belonged.
Read the fairy tale The Princess and the Pea.
Once upon a time, there was a handsome prince. The prince lived with his mother and father in a luxurious castle that overlooked a valley of wildflowers and a distant forest. As the prince grew up, he began to long for a princess. However, the prince wanted to be sure that the princess was a real princess. The queen and king searched far and wide for a real princess, but the prince always found something wrong with the princesses they found.
One evening, there was a terrible storm. The wind howled, thunder shook the stone walls, and lightning filled the dark night sky. Through the pelting of the rain, there came a knock at the door. When the king opened the door, he saw a bedraggled girl, soaked to the skin and covered in mud. He ushered her into the castle so that she could warm herself by the fire.
"Why is a young servant girl like you wandering about on such a ferocious night?" queried the king.
The disheveled maiden looked at the king in disbelief. "I am a princess, come to see the prince," she explained, all the while shivering.
The king summoned his wife, the queen, for advice. The queen looked at the hideous creature in disbelief, thinking that no princess would ever allow herself to be found in such a state. She thought quickly and came up with a clever plan. The queen put a small pea at the bottom of a bed and piled twenty mattresses on top of it. When the girl arrived at the room, she had to climb a ladder to reach the top of the bed, where she collapsed in exhaustion.
Bright and early the next morning, the king and queen arrived at the girl's bedchamber. The queen asked the girl how she had slept the night before.
"Absolutely terribly!" bemoaned the maiden. "I have spent the entire night tossing and turning. I don't know whether there is something hard in the bed, or your mattresses are rocks, but my body is black and blue."
The queen and the king stared at the maiden in astonishment. Only a real princess would have such delicate skin that she could feel a pea under twenty mattresses. The queen and king brought her to the prince, who was thrilled to meet a real princess with such an independent spirit.
How do the authors use similar and different events in each fairy tale to illustrate the theme that people should not be judged based on their appearances? Use complete sentences and evidence from the text to support your answer.
Answer:
MAIN IDEA
What the authors meant is not to judge people by their looks.
_____________________________________________________________
THE UGLY DUCKLING
The ugly duckling doesn't fit with the other ducklings and grows up, to be a fabulous bird. In the beginning, he is teased because of his looks, in a quote, "As the ugly duckling grew, many animals in the pond criticized him. His feathers were too dark, his neck was too long, and his body was too big. His fellow ducklings refused to recognize that underneath the feathers, the ugly duckling was kind, good, and gentle. The ugly duckling shed many tears because none of the other animals would play with him."
Near the end, however, it states, "He believed that the swans would never be his friends and looked down into the pond in despair. Then, his eyes opened wide, for he saw his reflection. To his great astonishment, the ugly duckling discovered that he was a beautiful, royal swan! The swans welcomed their new friend, whose lovely appearance was matched only by his kind heart. He now felt like he belonged." Throughout the course of the story, the other birds' views change since now they realize how awful they felt for mistreating the ugly duckling.
_____________________________________________________________
THE PRINCESS AND THE PEA
The king and queen didn't believe that she was a princess, so they had her endure the trial of sleeping on twenty mattresses with a pea under the very bottom one. Near the beginning of the story, it states, "The disheveled maiden looked at the king in disbelief. "I am a princess, come to see the prince," she explained, all the while shivering. The king summoned his wife, the queen, for advice. The queen looked at the hideous creature in disbelief, thinking that no princess would ever allow herself to be found in such a state. She thought quickly and came up with a clever plan. The queen put a small pea at the bottom of a bed and piled twenty mattresses on top of it. When the girl arrived at the room, she had to climb a ladder to reach the top of the bed, where she collapsed in exhaustion." This is when the king and queen were in doubt that she was a princess.
However later on it stated, "Bright and early the next morning, the king and queen arrived at the girl's bed-chamber. The queen asked the girl how she had slept the night before. "Absolutely terribly!" bemoaned the maiden. "I have spent the entire night tossing and turning. I don't know whether there is something hard in the bed, or your mattresses are rocks, but my body is black and blue." The queen and the king stared at the maiden in astonishment. Only a real princess would have such delicate skin that she could feel a pea under twenty mattresses. The queen and king brought her to the prince, who was thrilled to meet a real princess with such an independent spirit." As you can see the king and queen believed that she was a princess now because they stated, "Only a real princess would have such delicate skin that she could feel a pea under twenty mattresses."
_____________________________________________________________
CONCLUSION
Both stories focus on how the main character is doubted or mistreated because of how they look, but throughout the stories, the main character proves them wrong.
Explanation:
Have a great rest of your day
#TheWizzer
what is a tidal barrage
plase explaine
Answer:
A dam like structure used to capture energy from masses of water moving in or out of a bay of rivers due to tidal force is called tidal barrage.
Explanation:
It may help you to solve question.
An atom of a certain element has 12 protons, 14 neutrons, and 2 valence electrons. What is the name of this element?
Given :
An atom of a certain element has 12 protons, 14 neutrons, and 2 valence electrons.
To Find :
The name of this element.
Solution :
We know, element with atomic number ( number of protons ) 12 and valance electrons is Magnesium.
Now, isotope of magnesium of proton with 14 neutrons is Mg-16 .
Therefore, name of element is Mg-16 .
Hence, this is the required solution.
Define kinetic energy. A) energy associated with the temperature of an object B) energy associated with the motion of an object C) energy associated with the force of an object D) energy associated with the gravity of an object E) energy associated with the position or composition of an object 2) Determine the density of an object that has a mass of 1498 g and displaces 12.1 mL of water when placed in a graduated cylinder. A) 8.08 g/mL B) 1.38 g/mL C) 12.4 g/mL D) 18.1 g/mL E) 11.4 g/mL 3) How many significant figures are in the measurement, 20.300 m?! A)3 B) 4 C) 5 D) 1 E)2 4) What does "X" represent in the following symbol? 80 358 A) mercury B) chlorine C) scandium D) bromine E) selenium 5) Write the formula for copper (II) sulfate pentahydrate. A) Cu2SO3 H5 B) Cu2S'H20 C) CuS 5H20 D) (CuSO4)5 E) CuSO4'5H20
1. B, the energy associated with the motion of an object
2. C, 12.4 g/mL
3. C, 5
1) B) Kinetic energy is energy associated with the motion of an object.
2) B) Density equals mass divided by volume: 1.38 g/mL
3) C) There are 5 significant figures in 20.300
4) A) 80 is the atomic number for mercury on the periodic table.
5) E) The formula for copper (II) sulfate pentahydrate is CuSO4•5H2O
So in summary:
• Kinetic energy is the energy of a moving object due to its motion.
• Density is calculated by dividing an object's mass by its volume.
• Significant figures refer to the known precision of a measurement based on the digits reported.
• Atomic symbols represent elements on the periodic table.
• Chemical formulas use symbols of the elements to show the proportions of atoms in a compound.
Can somebody help me with this please?
Answer:
So what you want to do is to place sulfur on top with the two fluorine's on the bottom left and right hand side at slight angles. You don't want to make it look interconnected as one whole bond. Draw a single line from each "F" to the "S" to model two fluorine atoms bond to one sulfur atom (Single bond, only one electron is being shared between each).
In a container with volume of 25.0 L, there are 40 g of CH4 gas. If the number of gas is reduced to 15.0 L, what is the new amount inmole?
Answer
1.50 mol
Explanation
Given:
Initial volume, V₁ = 25.0 L
Mass of CH4 gas in 25.0 L container = 40 g
Final volume, V₂ = 15.0 L
From the Periodic Table; molar mass of CH4 = 16.04 g/mol
What to find:
The new amount in mole.
Step-by-step solution:
According to Avogadro’s law: For a confined gas, the volume (V) and number of moles (n) are directly proportional if the pressure and temperature both remain constant. That is:
\(\frac{V_1}{n_1}=\frac{V_2}{n_2}\)n₁ = Mass/Molar mass = (40.0g/16.04 g/mol) = 2.493765586 mol
n₂ is the new amount in mole and can be calculated as follows:
\(\begin{gathered} \frac{25.0\text{ L}}{2.493765586\text{ mol}}=\frac{15.0\text{ L}}{n_2} \\ \text{Cross multiply} \\ n_2\times25.0\text{ L }=15.0\text{ L }\times2.493765586\text{ mol} \\ \text{Divide both sides by 25.0 L} \\ \frac{n_2\times25.0\text{ L}}{25.0\text{ L}}=\frac{15.0\text{ L }\times2.493765586\text{ mol}}{25.0\text{ L}} \\ n_2=1.496259352\text{ mol} \\ To\text{ 3 significant digits} \\ n_2=1.50\text{ mol} \end{gathered}\)The new amount in moles is 1.50 moles
Sodium easily combines with chorine is reactivity
answer
yes
Explanation:
How many moles of oxygen gas would be needed to react with 155 g of propane gas,
C3Hg, in a combustion reaction?
C3H8 (g) + 502 (g)
+
-> 3CO2 (g) + 4H20 (1)
Taking into account the reaction stoichiometry, 17.61 moles of O₂ is required to react with 155 grams of C₃H₈.
Reaction stoichiometryIn first place, the balanced reaction is:
C₃H₈ + 5 O₂ → 3 CO₂ + 4 H₂O
By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:
C₃H₈: 1 mole O₂: 5 moles CO₂: 3 moles H₂O: 4 molesThe molar mass of the compounds is:
C₃H₈: 44 g/moleO₂: 32 g/moleCO₂: 44 g/moleH₂O: 18 g/moleThen, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:
C₃H₈: 1 mole ×44 g/mole= 44 gramsO₂: 5 moles ×32 g/mole= 160 gramsCO₂: 3 moles ×44 g/mole= 132 gramsH₂O: 4 moles ×18 g/mole= 72 gramsMass of O₂ requiredThe following rule of three can be applied: if by reaction stoichiometry 44 grams of C₃H₈ react with 5 moles of O₂, 155 grams of C₃H₈ react with how many moles of O₂?
\(moles of O_{2} =\frac{155 grams of C_{3} H_{8}x5 moles of O_{2} }{44 grams of C_{3} H_{8}}\)
moles of O₂= 17.61 moles
Finally, 17.61 moles of O₂ is required to react with 155 grams of C₃H₈.
Learn more about the reaction stoichiometry:
brainly.com/question/24741074
brainly.com/question/24653699
Calculate the expected heterozygosity for a population with four alleles at a given locus, given the following allele frequencies: P-0.3 P2= 0.2 D3 -0.2 P-0.3
The expected heterozygosity for the population with four alleles at the given locus, based on the provided allele frequencies, is approximately 0.74.
To calculate the expected heterozygosity (He) for a population with four alleles at a given locus, we can use the formula:
He = 1 - Σ(pi2), where pi represents the frequency of each allele in the population.
Zygosity is the degree to which both copies of a chromosome or gene have the same genetic sequence. In other words, it is the degree of similarity of the alleles in an organism. Given the allele frequencies:
P1 = 0.3
P2 = 0.2
D3 = 0.2
P4 = 0.3
We can substitute these values into the formula:
He = 1 - [(0.3^2) + (0.2^2) + (0.2^2) + (0.3^2)]
He = 1 - [0.09 + 0.04 + 0.04 + 0.09]
He = 1 - 0.26
He ≈ 0.74
To know more about heterozygosity, click here:-
https://brainly.com/question/30636623
#SPJ11
Polyelectrolytes are typically used to separate oil and water in industrial applications. The separation process is dependent on controlling the pH. Fifteen (15) pH readings of wastewater following these processes were recorded. Is it reasonable to model these data using a normal distribution? 1.0 1.0 1.0 1.0 1.0 1.0 1.0 1.0 1.0 10.0 10.5 7.6 11.4 11.4 10.0 Yes, it passes the "fat pencil" test. Therefore, a normal distribution is a reasonable model. No, it does not pass the "fat pencil" test. Therefore, a normal distribution is not a reasonable model. O Yes, it passes the "fat pencil" test. Therefore, a normal distribution is not a reasonable model. O No, it does not pass the "fat pencil" test. Therefore, a normal distribution is a reasonable model.
No, it does not pass the "fat pencil" test. Therefore, a normal distribution is not a reasonable model. Option B is the correct answer.
The "fat pencil" test is a quick visual check to determine if a dataset can be reasonably approximated by a normal distribution. In this case, the pH readings of wastewater show a significant deviation from a normal distribution. The presence of several low pH values (1.0) and a few high pH values (10.0, 10.5, 11.4) indicate a non-normal distribution with skewness and potential outliers. Therefore, it is not reasonable to model these data using a normal distribution.
Option B is the correct answer.
You can learn more about normal distribution at
https://brainly.com/question/4079902
#SPJ11
please help Due today!
Answer: Wrote the answers below
Explanation:
The balanced equation for Number 1 is:
Fe2O3(s) + 3H2(g) --> Fe(s) + 3H2O(l)
Step 1:
moles ratio of iron (III) oxide and hydrogen is 1:3
step 2:
work out mr (molar mass) of fe2o3: 111.68+ 48 = 159.68
moles of iron (III) oxide: 33.5g divided by 159.68 = 0.21 mol
Step 3:
1:3 ratio so 0.21 times 3 = 0.63 mol of hydrogen
Step 4:
mass of hydrogen = mol times mr
0.63 times 2 = 1.26g
mass of hydrogen = 1.26g or 1.27g depending on whether you used 1.00 or 1.01 for the mr of hydrogen