How many mL of a 0.75 N KOH solution
should be added to a 500 mL flask to make
500 mL of a 0.300 M KOH solution?

The final concentration of I ions in the resulting solution is approximately 0.0311 M, expressed with three significant figures.

To determine the final concentration of I ions in the resulting solution, we need to consider the stoichiometry and volumes of the solutions being mixed.Given:

Volume of NH4l solution = 129.13 mL

Concentration of NH4l solution = 112.9 mM = 0.1129 M (converting from millimolar to molar)

Volume of Mgl2 solution = 105.31 mL

Concentration of Mgl2 solution = 0.87 M

First, we need to determine the moles of NH4l and Mgl2 in their respective solutions:

Moles of NH4l = Volume of NH4l solution * Concentration of NH4l solution

Moles of NH4l = 0.12913 L * 0.1129 M = 0.01459 moles NH4l

Moles of Mgl2 = Volume of Mgl2 solution * Concentration of Mgl2 solution

Moles of Mgl2 = 0.10531 L * 0.87 M = 0.09157 moles Mgl2

Next, we determine the limiting reagent, which is the reactant that is completely consumed and determines the maximum amount of product formed. In this case, the limiting reagent is NH4l because it has fewer moles than Mgl2.

The balanced chemical equation for the reaction between NH4l and Mgl2 is:

2 NH4l + Mgl2 → 2 NH4+ + MgI2

From the balanced equation, we can see that for every 2 moles of NH4l, we get 1 mole of MgI2.

Since the moles of NH4l is the limiting reagent, it will be completely consumed, and the moles of MgI2 formed will be half of the moles of NH4l.

Moles of MgI2 = 0.01459 moles NH4l * (1 mole MgI2 / 2 moles NH4l) = 0.007295 moles MgI2

Finally, we calculate the final concentration of I ions in the resulting solution:

Volume of resulting solution = Volume of NH4l solution + Volume of Mgl2 solution

Volume of resulting solution = 0.12913 L + 0.10531 L = 0.23444 L

Final concentration of I ions = Moles of MgI2 / Volume of resulting solution

Final concentration of I ions = 0.007295 moles / 0.23444 L = 0.0311 M

Therefore, the final concentration of I ions in the resulting solution is approximately 0.0311 M, expressed with three significant figures.

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Answer:

lead is the right answer

The net ionic equation for the reaction between potassium sulfide and magnesium iodide is S2- + Mg2+ -> MgS, as the potassium and iodide ions are spectator ions and do not participate in the reaction.

To determine the net ionic equation for the reaction between potassium sulfide (K2S) and magnesium iodide (MgI2), we first need to identify the ions present in each compound and then determine the products formed when they react.

Potassium sulfide (K2S) dissociates into two potassium ions (K+) and one sulfide ion (S2-):

K2S -> 2K+ + S2-

Magnesium iodide (MgI2) dissociates into one magnesium ion (Mg2+) and two iodide ions (I-):

MgI2 -> Mg2+ + 2I-

Now, we need to determine the possible products when these ions combine. Since potassium (K+) has a +1 charge and iodide (I-) has a -1 charge, they can combine to form potassium iodide (KI):

K+ + I- -> KI

Similarly, magnesium (Mg2+) and sulfide (S2-) can combine to form magnesium sulfide (MgS):

Mg2+ + S2- -> MgS

Now, we can write the complete ionic equation by representing all the ions present before and after the reaction:

2K+ + S2- + Mg2+ + 2I- -> 2KI + MgS

To obtain the net ionic equation, we remove the spectator ions, which are the ions that appear on both sides of the equation and do not participate in the actual reaction. In this case, the spectator ions are the potassium ions (K+) and the iodide ions (I-).

Thus, the net ionic equation for the reaction between potassium sulfide and magnesium iodide is:

S2- + Mg2+ -> MgS

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The concept ideal gas equation is used here to determine the volume of the carbondioxide. Combustion reactions are generally highly exothermic reactions. The volume of CO₂ is

A combustion is a chemical reaction in which a fuel undergoes oxidation as a result of the reaction with an oxidizing agent which causes the release of energy in the form of heat.

15.0 °C = 288 K

The ideal gas equation is:

PV = nRT

V = nRT / P

V = 354 × 0.0821 × 288 / 0.995 = 8412.3 L

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Given that,

we are to find

we know that,

and

moles ratio of NH3 to H2O is 4:6

if 4=6

1. ?

1 * 6 /4 = 1.5

1.5 moles of water

Answer:

Preventing erosion – Land Reclamation

Protecting nesting areas – Protecting Biodiversity

Preventing littering – Land Reclamation

Preventing habitat disruption – Protecting Biodiversity

Protecting native species – Protecting Biodiversity

Preventing contamination of soil – Land Reclamation

Explanation:

I really hope I'm right! I tried my hardest, please give me brainliest :)

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Answer:

17. transformational energy

Answer:

Explanation:

As a result, the reaction of propane (C H) 3 8 and oxygen should produce carbon dioxide, water, and heat as products, and the balanced chemical equation will be: C H3 8 + 5O2 3CO2 + 4H O2 + heat. Reactants have the next highest potential power level when compared to materials.

Answer:

water and carbon dioxide

Explanation:

Propane undergoes combustion reactions in a similar fashion to other alkanes. In the presence of excess oxygen, propane burns to form water and carbon dioxide.

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The growth of the new plant depicts the asexual reproduction characteristic. The characteristic that describes the growth of the new plant in Stephan's mother cutting a twig from a rose bush and planting it in the soil is asexual reproduction.

Asexual reproduction is the mode of reproduction by which organisms generate offspring that are identical to the parent's without the fusion of gametes. Asexual reproduction is a type of reproduction in which the offspring is produced from a single parent.

The offspring created are clones of the parent plant, meaning they are identical to the parent.The new plant in Stephan’s mother cutting a twig from a rose bush and planting it in the soil depicts the process of asexual reproduction, which is the ability of a plant to reproduce without seeds. In asexual reproduction, plants can reproduce vegetatively by cloning themselves using their roots, bulbs, or stems.

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Answer: The mass of product, \(H_2O\) is, 36.0 grams.

Explanation : Given,

Mass of \(H_2\) = 4.0 g

Mass of \(O_2\) = 32.0 g

Molar mass of \(H_2\) = 2 g/mol

Molar mass of \(O_2\) = 32 g/mol

First we have to calculate the moles of \(H_2\) and \(O_2\).

\(\text{Moles of }H_2=\frac{\text{Given mass }H_2}{\text{Molar mass }H_2}\)

\(\text{Moles of }H_2=\frac{4.0g}{2g/mol}=2.0mol\)

and,

\(\text{Moles of }O_2=\frac{\text{Given mass }O_2}{\text{Molar mass }O_2}\)

\(\text{Moles of }O_2=\frac{32.0g}{32g/mol}=1.0mol\)

Now we have to calculate the limiting and excess reagent.

The balanced chemical equation is:

\(2H_2+O_2\rightarrow 2H_2O\)

From the balanced reaction we conclude that

2 mole of \(H_2\) react with 1 mole of \(O_2\)

From this we conclude that, there is no limiting and excess reagent.

Now we have to calculate the moles of \(H_2O\)

From the reaction, we conclude that

2 moles of \(H_2\) react to give 2 moles of \(H_2O\)

Now we have to calculate the mass of \(H_2O\)

\(\text{ Mass of }H_2O=\text{ Moles of }H_2O\times \text{ Molar mass of }H_2O\)

Molar mass of \(H_2O\) = 18 g/mole

\(\text{ Mass of }H_2O=(2.0moles)\times (18g/mole)=36.0g\)

Therefore, the mass of product, \(H_2O\) is, 36.0 grams.

No of molecules:-

\(\\ \rm\rightarrowtail 0.75(6.022\times 10^{23})\)

\(\\ \rm\rightarrowtail 4.5165(10^{23}) molecules\)

The number of KNO₃ molecules present in 0.750 mole of KNO₃ is 4.5×10²³.

Avogadro's numbers are those numbers which tells about the number of atoms present in one mole of any substance and it is equal to the 6.022 × 10²³.

Given moles of KNO₃ = 0.75 mole

No.of molecules of KNO₃ in given moles = 0.75 × 6.022 × 10²³ = 4.5×10²³

Hence required number of molecules are 4.5 × 10²³.

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Answer:

\(Positron\rightarrow _{1} ^{0}e\)

Explanation:

lets take the particle is X, the given decay reaction can be written as follows

\(_{25} ^{49}Mn\rightarrow _{24}^{49}Cr+X\)

Now by using mass balancing:

The sum of the mass of right hand side=The sum of the mass of left hand side

49=49+M

M=0

Now by using atomic number balancing:

Atomic number on right side=Atomic number on left side

25 = 24 + Z

Z=1

Therefore we can say that , the mass of that unknown particle is 0 unit and atomic number is 1.

Thus that particle will be positron.

\(Positron\rightarrow _{1} ^{0}e\)

Answer

476.16 g of oxygen atoms

Explanation

The reaction can be represented in the equation as shown below.

O₂ + H₂ → H₂O₂

According to the information given;

1 mole of O₂ reacts with 1 mole of H₂

1 mole of O₂ = 31.998 g/mol

1 mole of H₂ = 2.016 g/mol

This implies;

(1 mol x 31.998 g/mol) = 31.998 g of O₂ reacts with (1 mol x 2.016 g/mol) = 2.016 g of H₂

So, x g of O₂ will require 30 g of H₂

To get x, cross multiply and divide both sides by 2.016 g of H₂

Hence, 476.16 g of oxygen atoms is required to react completely with 30 g Of hydrogen atoms

The correct option is (d) To express very large or very small number.

What is the Scientific Notation?

Scientific notation is a way to present numbers that are too large or too small to be easily written in decimal form. The three components of  scientific notation are coefficient, base and exponent. The proper format to write a scientific notation is a x 10^b, where a is a number or decimal number and b is the power of 10 to make scientific notation equivalent to original number. When a number between 1 and 10 is multiplied by a power of 10 then the number is expressed in scientific notation. For example,  10000000 can be written as 10⁷, which is the scientific notation and the exponent is positive here. Similarly, for the negative exponent 0.000001 can be can be represented as 10-⁷.                             Hence, the scientific notation is used to express very large or very small numbers.

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Explanation:

All precipitation gravimetric analyses share two important attributes. First, the precipitate must be of low solubility, of high purity, and of known composition if its mass is to reflect accurately the analyte's mass. Second, it must be easy to separate the precipitate from the reaction mixture.

Approximately 4.37 x 10^23 molecules of HCl would be required to form 34.52 g of MgCl₂.

To determine the number of molecules of HCl required to form 34.52 g of MgCl₂, we need to use the molar mass and stoichiometry of the balanced equation:

Mg(OH)₂(s) + 2 HCl(aq) → 2 H₂O(l) + MgCl₂(aq)

The molar mass of MgCl₂ is 95.21 g/mol.

First, we need to calculate the number of moles of MgCl₂ formed:

Moles of MgCl₂ = mass of MgCl₂ / molar mass of MgCl₂

Moles of MgCl₂ = 34.52 g / 95.21 g/mol

Moles of MgCl₂ = 0.363 mol

According to the balanced equation, the stoichiometric ratio between HCl and MgCl₂ is 2:1. Therefore, the moles of HCl required can be calculated as follows:

Moles of HCl = 2 * Moles of MgCl₂

Moles of HCl = 2 * 0.363 mol

Moles of HCl = 0.726 mol

To calculate the number of molecules, we need to use Avogadro's number, which is approximately 6.022 x 10^23 molecules/mol.

Number of molecules of HCl = Moles of HCl * Avogadro's number

Number of molecules of HCl = 0.726 mol * 6.022 x 10^23 molecules/mol

Number of molecules of HCl = 4.37 x 10^23 molecules

Therefore, approximately 4.37 x 10^23 molecules of HCl would be required to form 34.52 g of MgCl₂.

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Answer:

1.An atom is the defining structure of an element, which cannot be broken by any chemical means. A typical atom consists of a nucleus of positively-charged protons and electrically neutral neutrons with negatively-charged electrons orbiting this nucleus.

2.a chemical process is a method or means of somehow changing one or more chemicals or chemical compounds.

3. a process that involves rearrangement of the molecular or ionic structure of a substance, as opposed to a change in physical form or a nuclear reaction.

The partial pressure of the remaining gas that was not measured is 0.8 atm.

This is the individual pressure exacted by each gas in the containing vessel. This partial pressure of individual gases make up the total pressure.

Pt = P₁ + P₂ + P₃ + P₄

5 = 1.2 + 2 + 1 + P₄

5 = 4.2 + P₄

P₄ = 5 - 4.2

P₄ = 0.8 atm

Thus, the partial pressure of the remaining gas that was not measured is 0.8 atm.

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The density of the ethanol is 0.384 g/mL.

We define density as the ratio of the mass to the volume of the ethanol. One of the common ways that we can measure the density of a liquid is to measure the mass of the liquid and then its volume and obtain the ratio .of the both values in a procedure similar to the one outlined above.

Hence;

Mass of the ethanol = 19.17 grams -  15.25 grams = 1.92 g

Volume of the ethanol = 5.00 mL

Density of ethanol = mass/volume = 1.92 g/5.00 mL = 0.384 g/mL

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Explanation: The rate law for a chemical reaction is an equation that relates the rate of the reaction to the concentrations of the reactants. To determine the rate law for a reaction, experiments are typically conducted with different initial concentrations of the reactants and the initial rate of the reaction is measured.

From the data provided, it appears that the reaction is of the form X + Y → C. And the concentration of X and Y are varied in three trials and the corresponding Initial rate is measured.

In the first trial, [X] = 0.01 M and [Y] = 0.015 M, and the initial rate of the reaction is 7.83x10-5 M/s.

In the second trial, [X] = 0.01 M and [Y] = 0.03 M, and the initial rate of the reaction is 3.13x104 M/s.

In the third trial, [X] = 0.02 M and [Y] = 0.015 M, and the initial rate of the reaction is 1.57x10 M/s.

Given the data, the rate law for this reaction is OR = KX²M. This is because when the concentration of X is doubled, the rate of the reaction is quadrupled, which is consistent with a rate law of the form OR = k[X]^2.

To solve such this we must know the concept of combination reaction. Therefore, the given reaction CH\(_4\)+Br\(_2\) \(\rightarrow\)CH\(_3\)Br+ HBr is a combination reaction.

Chemical reaction is a process in which two or more than two molecules collide in right orientation and energy to form a new chemical compound. The mass of the overall reaction should be conserved. There are so many types of chemical reaction reaction like combination reaction, double displacement reaction.

CH\(_4\)+Br\(_2\) \(\rightarrow\)CH\(_3\)Br+ HBr

The above reaction is a combination reaction. In combination reaction, more than one reactant combine to form a product. Because new chemicals are created during combination reactions, they are often referred to as synthesis.

Therefore, the given reaction is a combination reaction.

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Answer:

How do amoeba respire.

Define Diffusion.

The metal X has an approximate molar mass of 42.36 g/mol and the metal is most likely calcium.

The molar mass of the metal carbonate XCO₃ and identify the metal X, we need to calculate the number of moles of XCO₃ and CO₂ using the given masses and molar masses.

The molar mass of CO₂ (carbon dioxide) is 12.011 g/mol (for carbon) + 2 * 15.999 g/mol (for oxygen) = 44.01 g/mol.

The number of moles of CO₂ can be calculated using the formula:

moles of CO₂ = mass of CO₂ / molar mass of CO₂

moles of CO₂ = 0.855 g / 44.01 g/mol

moles of CO₂ ≈ 0.01944 mol

Since the reaction stoichiometry is 1:1 between XCO₃ and CO₂, the number of moles of XCO₃ is also approximately 0.01944 mol.

molar mass of XCO₃ = mass of XCO₃ / moles of XCO₃

molar mass of XCO₃ = 2.012 g / 0.01944 mol

molar mass of XCO₃ ≈ 103.38 g/mol

The molar mass of XCO₃ is approximately 103.38 g/mol.

To determine the metal X:

molar mass of X = molar mass of XCO3 - molar mass of CO3

molar mass of X = 103.38 g/mol - (12.011 g/mol + 3 * 15.999 g/mol)

molar mass of X ≈ 42.36 g/mol

Metal X is most likely Calcium that has a molar mass of 40 g/mol

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Answer:

When the weather is nice, many people begin to work on their yards and homes. For many projects, sand is needed as a foundation for a walk or to add to other materials. You could order up twenty million grains of sand and have people really stare at you. You could order by the pound, but that takes a lot of time weighing out. The best bet is to order by the yard, meaning a cubic yard. The loader can easily scoop up what you need and put it directly in your truck.

Avogadro’s Number

It certainly is easy to count bananas or to count elephants (as long as you stay out of their way). However, you would be counting grains of sugar from your sugar canister for a long, long time. Atoms and molecules are extremely small – far, far smaller than grains of sugar. Counting atoms or molecules is not only unwise, it is absolutely impossible. One drop of water contains about 10 22 molecules of water. If you counted 10 molecules every second for 50 years without stopping you would have counted only 1.6 × 10 10 molecules. Put another way, at that counting rate, it would take you over 30 trillion years to count the water molecules in one tiny drop.

Explanation:

Answer:

8.0g

Explanation:

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