How many mols are in 6.73 x 1024 particles of Cu? A. 6.02 x 1023 mols of Cu B. 11.18 mols of Cu C. 1.12 mols of Cu D. 10 mols of Cu\

The percent ionization of a 2M solution of acetic acid at 25˚C is 0.0036%.

Acetic acid is a weak acid and it ionizes only partially in an aqueous solution, meaning not all of the acetic acid molecules will dissociate into ions. The percent ionization of a weak acid can be calculated using the formula:

[H3O+]/[HA] = Ka

Acetic acid Ka = 1.8 x \(10^{-5}\) at 25°C

[H3O+] = Ka x [HA] = 1.8 x \(10^{-5}\) x 2 = 0.000036

% ionization = ( [H3O+]/[HA]) x 100 = 0.0036%

It's worth noting that Percent ionization is a small number, typically less than 1% for weak acids.

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Answer:Explanation:

In compounds, all other atoms are assigned an oxidation number so that the sum of the oxidation numbers on all the atoms in the species equals the charge on the species.

Answer:

= 62g

Explanation:

We have been asked to find the mass of Na2O having 6.02 x 10^23 units.

We know that one mole of a substance contains 6.02 x10^23 units/particles.

That means we have one mole of Na2O.

To find the mass of Na2O we use the formula,

mass = number of moles x formula mass

= 1 mole x 62g/mol

= 62g

Therefore the mass of Na2O with 6.02 x 10^23 units is 62g.

Answer:

i dont have a answer im just answering so you can give the person who answered brailiest :)

Explanation:

3M

3M is the molarity of a koh solution if 200 ml of the solution contains 0. 6 moles KOH.

Molarity : Molarity is defined as the number of moles of solute present in one liter of solution.

We know that,

Molarity = \(\frac{n*1000}{v}\)

where,

n = moles of solute of KOH = 0.6

V= volume of solution in ml= 200 ml

Now on substituting the values in the molarity formula,

molarity = \(\frac{0.6*1000}{200}\) = 3M/L

Therefore, molarity = 3M

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Nicholas earned $25 or less approximately 30% percent of the time from his babysitting jobs last year.

Nicholas began babysitting last year to earn extra spending money. Throughout the summer, he diligently tracked his earnings for each babysitting job. The provided box plot illustrates the range of his earnings, with values ranging from $10 to $60. Analyzing the plot, we can determine that Nicholas earned $25 or less approximately 30% of the time. This indicates that nearly one-third of his babysitting jobs resulted in earnings not exceeding $25.

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In the formation of ionic compounds, a metal will lose electrons to form an ion with the same number of electrons as the nearest noble gas.

Ionic compounds are formed through the transfer of electrons between a metal and a non-metal. Metals, which are located on the left side of the periodic table, tend to have few valence electrons. These valence electrons are loosely held and can be easily removed, resulting in the formation of positively charged ions, known as cations.

When a metal reacts with a non-metal, such as an element from the halogen group, the metal atom loses one or more electrons to attain a stable electron configuration. The number of electrons lost corresponds to the difference between the number of valence electrons in the metal atom and the number of electrons needed to achieve the electron configuration of the nearest noble gas.

Noble gases, found in Group 18 of the periodic table, possess a complete outer electron shell, making them highly stable and unreactive. By losing electrons, the metal ion achieves the same electron configuration as the noble gas nearest to it in the periodic table. This transfer of electrons from the metal to the non-metal results in the formation of an ionic bond, where the oppositely charged ions are attracted to each other, forming a crystal lattice structure.

In summary, metals lose electrons in the formation of ionic compounds to attain the electron configuration of the nearest noble gas, ensuring greater stability for the resulting ions.

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Answer:

pee

Explanation:

ppppppppppppppppppppppppppppppppppppp

when ph decrease that means acidity increase

when ph increase that means basicity increase

Answer:

An easy way to work out the charge of an atom is to look at the periodic table. Elements on the left side of the table usually become positively charged ions and elements on the right side of the table typically have a negative charge. However, you can use a scientific formula to determine the formal charge of an atom.

Explanation:

1.78 grams of silver can be produced from 1.40 g silver nitrate and excess copper. The balanced chemical equation for the reaction of copper with silver nitrate (use cu2) is as follows: Cu + 2AgNO₃ → Cu(NO₃)₂ + 2Ag

To determine how many grams of silver can be produced from 1.40 g of silver nitrate and excess copper, we first need to calculate the limiting reactant.

The stoichiometry of the reaction is such that 2 moles of silver nitrate react with 1 mole of copper to produce 2 moles of silver. The molar mass of silver nitrate is 169.87 g/mol while that of copper is 63.55 g/mol,

therefore, the number of moles of silver nitrate present in 1.40 g can be calculated as follows:Number of moles of silver nitrate = mass/molar mass= 1.40/169.87= 0.008240 molSimilarly, the number of moles of copper required to react with this quantity of silver nitrate is 0.004120 mol (half of the number of moles of silver nitrate).

Since there is an excess of copper, it will not limit the reaction and hence the limiting reactant is silver nitrate.To calculate the mass of silver produced, we use the molar mass of silver, which is 107.87 g/mol.Mass of silver produced = number of moles of silver x molar mass= 0.01648 x 107.87= 1.78 g

Therefore, 1.78 grams of silver can be produced from 1.40 g silver nitrate and excess copper.

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Answer:

im pretty sure it is D

Explanation:

this is an old term for a microscopic organisms that included bacteria, protozoans, and very small animals

The solubility of mercury(II) iodide (HgI₂) in pure water is determined by its Ksp value, which is 2.9 x 10⁻²⁹.

In a 3.0 M solution of NaI, assuming (HgI₄)₂₋is the only significant species, the solubility of HgI₂can be calculated using the Ksp and K values.

The solubility of HgI2 in pure water can be calculated using its solubility product constant (Ksp). The Ksp value for HgI₂ is given as 2.9 x 10⁻²⁹. Solubility product constant represents the equilibrium constant for the dissolution of a sparingly soluble salt. By solving the equilibrium expression for HgI₂, we can determine its solubility in pure water.

In a 3.0 M solution of NaI, assuming the formation of (HgI₄)₂₋ is the only significant Hg-containing species, the solubility of HgI2 can be calculated using the Ksp and K values. The K value given for(HgI₄)₂₋ - is 6.8 x 10²⁹. By setting up an equilibrium expression considering the dissociation of HgI₂ into (HgI₄)₂₋  ions, we can determine the solubility of HgI₂in the presence of the NaI solution.

These calculations involve using the principles of equilibrium and the relationship between concentrations of dissolved species and their equilibrium constants. Solubility is defined as the maximum amount of solute that can be dissolved in a given solvent under specific conditions. By applying the relevant equilibrium expressions and values, we can determine the solubility of HgI₂ in each situation.

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Answer:

6 pH is a weak acid

Explanation:

Generally, a strong acid has a pH of about zero to 3.

The pH scale typically ranges from 1 to 14, with lower numbers representing acids, higher numbers, bases. Neutral liquids like water have a pH of 7.

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To clean powder fouling, corrosion, and dirt from outside parts of the lower receiver and extension assembly, one should use the best quality cleaning materials and methods.

Powder fouling, corrosion, and dirt can accumulate on the outside parts of the lower receiver and extension assembly, making it hard to maintain the rifle. It is essential to clean the weapon regularly to maintain its efficiency and longevity.

The following cleaning materials are required for the cleaning process:

Cleaning solvent

Cleaning brush

Microfiber cloth

Lubricant

The best solvent to use when cleaning the rifle is a powder solvent. This is because it is specifically designed to remove fouling from firearms. It is also essential to use a cleaning brush made of brass, nylon, or synthetic material to avoid damaging the parts of the lower receiver and extension assembly.

Brass brushes are best for removing fouling, while nylon and synthetic brushes are gentle on the metal parts and help prevent corrosion. Avoid using a steel brush when cleaning the rifle since it may scratch or damage the surface of the metal.Lubricant is also essential in maintaining the rifle. It helps keep the moving parts smooth and minimizes friction between metal parts.

A high-quality lubricant should be used, and the excess should be wiped off with a microfiber cloth. To clean the weapon, apply the cleaning solvent onto the brush and scrub the outside parts of the lower receiver and extension assembly, then wipe it off with a microfiber cloth. Ensure the surface of the metal parts is dry before applying lubricant. Apply lubricant to moving parts of the weapon.

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The law of diminishing marginal rate of substitution indicates that the rate at which one input can be substituted for another decreases as the quantity of one input increases, leading to isoquants being bent toward the origin.

In other words, as the quantity of one good increases, the individual is willing to sacrifice fewer units of the other good to obtain an additional unit of the first good. This reflects a diminishing rate of substitution between the two goods.

The reason why the law of diminishing marginal rate of substitution suggests that isoquants must be bent toward the origin is rooted in the concept of diminishing marginal utility. As more units of a particular input (e.g., labor or capital) are added while holding other inputs constant, the additional output gained from each additional unit of the input will decrease. This diminishing marginal productivity leads to a decreasing MRS.

When isoquants (which represent different combinations of inputs that produce the same level of output) are bent toward the origin, it reflects the fact that as more of one input is used, the amount of the other input that needs to be substituted decreases. This bending signifies the diminishing MRS and captures the idea that a larger quantity of one input can be substituted for a smaller quantity of the other input to maintain the same level of output.

Overall, the law of diminishing marginal rate of substitution indicates that the rate at which one input can be substituted for another decreases as the quantity of one input increases, leading to isoquants being bent toward the origin.

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Answer:

a. 5.82km

b. 7.2956cm

Explanation:

Answer: The vapor pressure of ethanol at \(26.3^{o}C\) is 238.3 torr.

Explanation:

Given: \(\Delta H_{vap}\) = 38.6 kJ/mol

\(T_{1} = 26.3^{o}C = (26.3 + 273) K = 299.3 K\)

\(T_{2} = 78.4^{o}C = (78.4 + 273) K = 351.4 K\)

Formula used to calculate the vapor pressure of ethanol is as follows.

\(ln\frac{P_{2}}{P_{1}} = \frac{\Delta H_{vap}}{R} [\frac{1}{T_{1}} - \frac{1}{T_{2}}]\\\)

Substitute the values into above formula as follows.

\(ln\frac{P_{2}}{P_{1}} = \frac{\Delta H_{vap}}{R} [\frac{1}{T_{1}} - \frac{1}{T_{2}}]\\ \\ln \frac{760 torr}{P_{1}} = \frac{38600 J}{8.314 J/mol K}[\frac{1}{299.3} - \frac{1}{351.4}]\\\frac{760}{P_{1}} = 3.18\\P_{1} = 238.3 torr\)

Thus, we can conclude that the vapor pressure of ethanol at \(26.3^{o}C\) is 238.3 torr.

Answer:

Any two reasons will be :

1:- It is based on atomic number.

2:-Problem regarding Position of isotopes is resolved.

Hope this helped

Hope this helped ALL THE BEST !!

Answer:

The modern periodic table has more info and more elements

Explanation:

The resulting solution of buffer solution is prepared by mixing 250 mL of 1.00 M nitrous acid with 50 mL of 1.00 M sodium hydroxide is a buffer solution. Thus, the correct answer is "Yes, the resulting solution is a buffer solution".

The resulting solution is a buffer solution because it contains both a weak acid (nitrous acid) and its conjugate base (the nitrite ion formed from the reaction with sodium hydroxide). The addition of sodium hydroxide does not significantly change the pH of the solution due to the presence of the buffer system.

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Answer: 4.48L of CH4 at STP is equal to 1.2×10^23 molecules

Explanation:

Answer:

Chemical reaction, a process in which one or more substances, the reactants, are converted to one or more different substances, the products.

A chemical reaction rearranges the constituent atoms of the reactants to create different substances as products.

Chemical reactions are an integral part of technology, of culture, and indeed of life itself. Burning fuels, smelting iron, making glass and pottery, brewing beer, and making wine and cheese are among many examples of activities incorporating chemical reactions that have been known and used for thousands of years. Chemical reactions abound in the geology of Earth, in the atmosphere and oceans, and in a vast array of complicated processes that occur in all living systems.

Explanation:

hope it help

plss brainlys me

Answer:

Chemical reaction, a process in which one or more substances, the reactants, are converted to one or more different substances, the products

Explanation:

Substances are either chemical elements or compounds. A chemical reaction rearranges the constituent atoms of the reactants to create different substances as products.

Answer:

Explanation:

El hielo encierra la primavera antes de espolvorear la sal.

Cuando se rocía sal sobre el hielo, disminuye el punto de fusión del hielo 32 ° F a un poco por debajo de 32 °, por lo tanto, se acumula.

A medida que el hielo se vuelve a congelar, encierra la primavera

The gas occupies a volume of approximately 28.18 liters at a temperature of 28°C and a pressure of 1.631 atm

To determine the volume the gas occupies at a temperature of 28°C and a pressure of 1.631 atm, we will use the Ideal Gas Law, which is defined as PV = nRT. In this equation, P represents pressure, V represents volume, n represents the number of moles of the gas, R is the ideal gas constant, and T is the temperature in Kelvin.

First, we need to convert the temperature from Celsius to Kelvin: T(K) = T(°C) + 273.15. In this case, T(K) = 28 + 273.15 = 301.15 K.

Now, we can use the Ideal Gas Law to find the volume of the gas. The ideal gas constant (R) is 0.0821 L atm/mol K. Therefore, we have:

1.631 atm (V) = 3 moles (0.0821 L atm/mol K) (301.15 K)

To find the volume (V), we can rearrange the equation and isolate V:

V = (3 moles * 0.0821 L atm/mol K * 301.15 K) / 1.631 atm

V = 45.98271 L/mol / 1.631 atm

V ≈ 28.18 L

So, the gas occupies a volume of approximately 28.18 liters at a temperature of 28°C and a pressure of 1.631 atm.

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Answer:

A. 1.73 m = 172 cm

B. 7,651.27 m = 7.65127 Km

Answer:

1. atom

2. element

3. pure substances

4. mixture

5. Homogenous Mixture/Heterogenous/Heterogenous

6. Basic

7. Similar: Both made up of atoms, have bonds connecting the atoms together, and are pure substances Different: Compounds are made up of different elemnts in a ratio, elements are distinguished by their atomic number, elements cannot be broken down into further elements

8. Heterogenous

9. Yes, as long as the elements don't have a chemical reaction with each other. Breahting air is the most common exmaple. There are many different elements in the air yet they do not react.

10. The mixture can be put through a filter to get the sugar and the black pepper by itself as the pebbles would be too large to pass through the filter. Next, the mixture can be set in water and stirred to have the sugar dissolve in the water. Since black pepper does not dissolve in water, the black pepper can be further filtered to get only the black pepper on its own. Finally, the sugar water can be evaporated to get the sugar on its own.

Explanation:

Answer:

B

Explanation:

The comparison between the class barometer data and the air pressure shown in the weather report serves as a means to evaluate the accuracy and effectiveness of the barometer's measurements.

The comparison between the data from the class barometer and the air pressure shown in the weather report revealed a correlation between the two measurements. The class barometer readings were likely taken at the same time as the weather report's air pressure measurement to ensure accurate comparison.

If the class barometer readings closely matched the air pressure indicated in the weather report, it would suggest that the barometer was functioning correctly and providing reliable measurements. This would indicate that the class barometer could be used as a reliable tool for monitoring air pressure changes.

However, if there were significant discrepancies between the class barometer readings and the air pressure reported in the weather report, it could indicate a calibration issue with the barometer or potential inaccuracies in its measurements. In such a case, it would be necessary to investigate the reasons behind the discrepancies and determine the reliability of the class barometer for future use. It helps to determine the barometer's reliability as a tool for monitoring air pressure changes in the local environment.

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Covalent compounds have low melting points, can be solid only at room temperature, exist as solids, liquids, or gases at room temperature, and have low electrical conductivity.

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