Answer:
Zero Solutions
Step-by-step explanation:
Step 1: Simplify both sides of the equation.
3x+13=3(x+6)+1
3x+13=(3)(x)+(3)(6)+1(Distribute)
3x+13=3x+18+1
3x+13=(3x)+(18+1)(Combine Like Terms)
3x+13=3x+19
3x+13=3x+19
Step 2: Subtract 3x from both sides.
3x+13−3x=3x+19−3x
13=19
Step 3: Subtract 13 from both sides.
13−13=19−13
0=6
Answer:
There are no solutions.
Please make sure it’s right I only have five questions
Answer:
your answer is 72°
Hope it helps you
Answer:
72 degrees
Step-by-step explanation:
There are 180 total degrees in a triangle, 70 plus 38 is 108. 72 i
Approximately how many employers have ruled candidates out based on their online presence? 40 percent 60 percent 50 percent 70 percent
Approximately 70 percent of employers have ruled out candidates based on their online presence.
Studies and surveys have consistently shown that employers increasingly consider candidates' online presence as part of their hiring process. According to various reports, including surveys conducted by CareerBuilder and other reputable sources, around 70 percent of employers have admitted to rejecting job candidates based on what they find online.
With the widespread use of social media platforms and the ease of accessing information online, employers often use online searches and social media screening as a way to gather additional insights about candidates beyond their resumes and interviews. They may look for any red flags, such as inappropriate content, unprofessional behavior, or contradictory information, which can influence their hiring decisions.
Given the prevalence of online searches and the importance placed on a candidate's digital footprint, it is estimated that approximately 70 percent of employers have ruled out candidates based on their online presence. It highlights the significance of maintaining a professional and positive online image when seeking employment opportunities in today's digital age.
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have two one-quart jars; the first is filled with water, and the second is empty. I pour half of the water in the first jar into the second, then a third of the water in the second jar into the first, then a fourth of the water in the first jar into the second, then a fifth of the water in the second jar into the first, and so on. How much water in quarts is in the first jar after the $10^{\textrm{th}}$ pour? Express your answer as a common fraction.
Answer:
water in quarts is in the first jar after 10th pour = 12/11
Step-by-step explanation:
Let X represent first jar and Y represents second jar.
have two one-quart jars; the first is filled with water, and the second is emptyLets give the initial value of 2 to the first jar which is filled with water. Lets say there are two liters of water in first jar.
Lets give the initial value of 0 to the second as it is empty.
So before any pour, the values are:
X: 2
Y: 0
pour half of the water in the first jar into the secondAfter first pour the value of jar X becomes:
Previously it was 2.
Now half of water is taken i.e. half of 2
2 - 1 = 1
So X = 1
The value of jar Y becomes:
The half from jar X is added to second jar Y which was 0:
After first pour the value of jar Y becomes:
0 + 1 = 1
Y = 1
a third of the water in the second jar into the firstAfter second pour the value of jar X becomes:
Previously it was 1.
Now third of the water in second jar Y is added to jar X
1 + 1/3
= (3 + 1)/3
= 4/3
X = 4/3
After second pour the value of jar Y becomes:
Previously it was 1.
Now third of the water in Y jar is taken and added to jar X so,
1 - 1/3
= (3 - 1)/3
= 2/3
Y = 2/3
a fourth of the water in the first jar into the secondAfter third pour the value of jar X becomes:
Previously it was 4/3.
Now fourth of the water in the first jar X is taken and is added to jar Y
= 3/4 * (4/3)
= 1
X = 1
After third pour the value of jar Y becomes:
Previously it was 2/3
Now fourth of the water in the second jar X is added to jar Y
= 2/3 + 1/4*(4/3)
= 2/3 + 4/12
= 1
Y = 1
a fifth of the water in the second jar into the firstAfter fourth pour the value of jar X becomes:
Previously it was 1
Now fifth of the water in second jar Y is added to jar X
= 1 + 1/5*(1)
= 1 + 1/5
= (5+1) / 5
= 6/5
X = 6/5
After fourth pour the value of jar Y becomes:
Previously it was 1.
Now fifth of the water in Y jar is taken and added to jar X so,
= 1 - 1/5
= (5 - 1) / 5
= 4/5
Y = 4/5
a sixth of the water in the first jar into the secondAfter fifth pour the value of jar X becomes:
Previously it was 6/5
Now sixth of the water in the first jar X is taken and is added to jar Y
5/6 * (6/5)
= 1
X = 1
After fifth pour the value of jar Y becomes:
Previously it was 4/5
Now sixth of the water in the first jar X is taken and is added to jar Y
= 4/5 + 1/6 (6/5)
= 4/5 + 1/5
= (4+1) /5
= 5/5
= 1
Y = 1
a seventh of the water in the second jar into the firstAfter sixth pour the value of jar X becomes:
Previously it was 1
Now seventh of the water in second jar Y is added to jar X
= 1 + 1/7*(1)
= 1 + 1/7
= (7+1) / 7
= 8/7
X = 8/7
After sixth pour the value of jar Y becomes:
Previously it was 1.
Now seventh of the water in Y jar is taken and added to jar X so,
= 1 - 1/7
= (7-1) / 7
= 6/7
Y = 6/7
a eighth of the water in the first jar into the secondAfter seventh pour the value of jar X becomes:
Previously it was 8/7
Now eighth of the water in the first jar X is taken and is added to jar Y
7/8* (8/7)
= 1
X = 1
After seventh pour the value of jar Y becomes:
Previously it was 6/7
Now eighth of the water in the first jar X is taken and is added to jar Y
= 6/7 + 1/8 (8/7)
= 6/7 + 1/7
= 7/7
= 1
Y = 1
a ninth of the water in the second jar into the firstAfter eighth pour the value of jar X becomes:
Previously it was 1
Now ninth of the water in second jar Y is added to jar X
= 1 + 1/9*(1)
= 1 + 1/9
= (9+1) / 9
= 10/9
X = 10/9
After eighth pour the value of jar Y becomes:
Previously it was 1.
Now ninth of the water in Y jar is taken and added to jar X so,
= 1 - 1/9
= (9-1) / 9
= 8/9
Y = 8/9
a tenth of the water in the first jar into the secondAfter ninth pour the value of jar X becomes:
Previously it was 10/9
Now tenth of the water in the first jar X is taken and is added to jar Y
9/10* (10/9)
= 1
X = 1
After ninth pour the value of jar Y becomes:
Previously it was 8/9
Now tenth of the water in the first jar X is taken and is added to jar Y
= 8/9 + 1/10 (10/9)
= 8/9 + 1/9
= 9/9
= 1
Y = 1
a eleventh of the water in the second jar into the firstAfter tenth pour the value of jar X becomes:
Previously it was 1
Now eleventh of the water in second jar Y is added to jar X
= 1 + 1/11*(1)
= 1 + 1/11
= (11 + 1) / 11
= 12/11
X = 12/11
After tenth pour the value of jar Y becomes:
Previously it was 1.
Now eleventh of the water in Y jar is taken and added to jar X so,
= 1 - 1/11
= (11-1) / 11
= 10/11
Y = 10/11
Answer:
6/11
Step-by-step explanation:
1/2 + (1/2)(2/11) = 6/11
sus
Find the area of a triangle with base of 10 inches and altitude to the base of 16 inches. 135 in 2 160 in 2 80 in 2
For a triangle with base of 10 inches and altitude of 16 inches, its area will be 80 in² (third option).
Calculation For the Area of the Triangle:
It is given that,
The base of the triangle, B = 10 inches
The altitude from the base of the triangle or height, H = 16 inches
Now, the formula used for finding the area of a triangle is given as follows,
Area, A = (1/2) × B × H
Substituting the given values of B and H in the above formula for area, we get,
A = (1/2) × (10 inches) × (16 inches)
A = 5 × 16 inches²
A = 80 inches²
Thus, the area of the triangle have base 10 inches and altitude 16 inches is 80 square inches.
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Please help me solve this please
Answer:
im grade 6 I don't no whats that sorry
Find the shortest distance from the point (2,0,-3) to the plane x+y+z=1
Shortest distance from the point (2, 0, -3) to the plane x + y + z = 1 is √3 units.
How to find the shortest distance from a point to a plane?To find the shortest distance between a point and a plane, we can use the formula:
distance = |ax + by + cz + d| / √(a² + b² + c²)
where a, b, and c are the coefficients of the plane's equation, d is the constant term, and (x, y, z) is the coordinates of the point.
In this case, the plane is x + y + z = 1, so a = 1, b = 1, c = 1, and d = -1. The point is (2, 0, -3), so x = 2, y = 0, and z = -3. Plugging in these values, we get:
distance = |1(2) + 1(0) + 1(-3) - 1| / √(1² + 1² + 1²)
= 3 / √3
= √3
Therefore, the shortest distance from the point (2, 0, -3) to the plane x + y + z = 1 is √3 units.
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What is the percent of
change from 5 to 4?
Answer:-20
Step-by-step explanation:
6x – 2 + 2x = 2(4x – 3) + 4.
Answer:
x = 0
Step-by-step explanation:
6x – 2 + 2x = 2(4x – 3) + 4
Collect like terms.8x - 2 = 8x - 6 + 4
8x - 2 = 8x - 2
8x = 8x + 0
0x = 0
x = 0
Answer:
0=0
Step-by-step explanation:
1. Combine Like Terms
6−2+2=2(4−3)+4
8x-2=2(4x-3)+4
2. Distribute
8x-2=2(4x-3)+4
8x-2=8x-6+4
3. Add the Numbers
8x-2=8x-6+4
8x-2+8x-2
4. Add 2 to both sides of the equation
8x-2=8x-2
8x-2+2=8x-2+2
5. Simplify
8−2+2=2(4−3)+4
8x=8x-2+2
8x=8x-2+2
8x=8x
6. Subtract 8x from both sides of the equation
8x-8x = 8x-8x
Answer= 0=0
Which value for S makes the equation true?
PQ= RQ and PS= RS a=?
The measure of angle a is 15 degrees and this can be determined by using the properties of the isosceles triangle.
What are interior angles?In geometry, interior angles are formed in two ways. One is inside a polygon, and the other is when parallel lines cut by a transversal. Angles are categorized into different types based on their measurements.
Given:
The length of the segment PQ is equal to the length of the segment RQ.The length of the segment PS is equal to the length of the segment RS.The following steps can be used in order to determine the measure of angle a:
Step 1 - According to the given data, it can be concluded that triangle PQR and triangle PSR are isosceles triangles.
Step 2 - Apply the sum of interior angle property on triangle PQR.
\(\angle\text{Q}+\angle\text{P}+\angle\text{R}=180\)
\(\angle\text{Q}+2\angle\text{R}=180\)
\(2\angle\text{R}=180-60\)
\(\angle\text{R}=60^\circ\)
Step 3 - Now, apply the sum of interior angle property on triangle PSR.
\(\angle\text{P}+\angle\text{S}+\angle\text{R}=180\)
\(\angle\text{S}+2\angle\text{R}=180\)
\(2\angle\text{R}=180-90\)
\(\angle\text{R}=45^\circ\)
Step 4 - Now, the measure of angle a is calculated as:
\(\angle\text{a}=60-45\)
\(\angle\text{a}=15\)
The measure of angle a is 15 degrees.
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BASED ON THE GRAPH, WHAT STATEMENT APPEARS TO BE TRUE?
would it be reasonable to use this information to generalize about the distribution of weights for the entire population of high school boys? why or why not?
The entire population of high school boys, a larger and more representative sample, selected using random sampling techniques, would be needed.
It would not be reasonable to use this information to generalize about the distribution of weights for the entire population of high school boys. The sample size of 100 is relatively small compared to the total population of high school boys, and it is possible that the sample is not representative of the entire population. Additionally, the sample was not randomly selected, which introduces the possibility of sampling bias. In order to generalize about the distribution of weights for the entire population of high school boys, a larger and more representative sample, selected using random sampling techniques, would be needed.
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PLEASE HELP I AM BEHIND!!!!
If the solution to an equation is x = −5, what could the original equation be?
A. x + 3 = 8
B. x − 3 = 8
C. x + 8 = 3
C. x − 8 = 3
(sorry if this is easy for you, I'm bad at math.)
Answer:
The answer is c definitely
Answer:
C. x + 8 = 3
Step-by-step explanation:
x + 8 = 3
x + 8 - 8 = 3 - 8 ( so do the same thing you do on both the left and right side )
x = -5
So C is correct but you can always say 3 - 8 to figure out that the answer in c is the right one.
HOPE THIS HELPED
which of the following basic functions is equivalent to the piecewise-defined function f(x)= x if x≥0 −x if x<0 ? question content area bottom part 1 a. f(x)= 1 x b. f(x)=x c. f(x)=x2 d.
The basic function equivalent to the piecewise-defined function f(x) = x if x ≥ 0 and -x if x < 0 is f(x) = |x|, which represents the absolute value of x.
The given piecewise-defined function f(x) has different expressions for different intervals. For x greater than or equal to zero, f(x) takes the value of x. For x less than zero, f(x) is equal to -x. We need to find a basic function that captures this behavior.
Among the options provided, f(x) = |x| is equivalent to the given piecewise function. The absolute value function, denoted by |x|, returns the positive value of x regardless of its sign. When x is non-negative, |x| equals x, and when x is negative, |x| is equal to -x, mirroring the conditions of the piecewise-defined function.
The function f(x) = |x| represents the absolute value of x and matches the behavior of the given piecewise-defined function, making it the equivalent basic function.
In summary, the basic function equivalent to the piecewise-defined function f(x) = x if x ≥ 0 and -x if x < 0 is f(x) = |x|, which represents the absolute value of x.
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3.4+2.9y=2.82 what is y in the equation?
The value of the y in the linear equation becomes -0.2.
According to the statement
We have to find that the value of the y in the equation.
So, For this purpose, we know that the
The definition of a linear equation is an algebraic equation in which each term has an exponent of one and the graphing of the equation results in a straight line.
From the given information:
The given equation is :
3.4+2.9y=2.82
Then we have to solve it
Then
3.4+2.9y=2.82
2.9y = 2.82 - 3.4
2.9y = -0.58
y = -0.58/2.9
y = -0.2.
Then
The value of the y becomes the -0.2.
So, The value of the y in the linear equation becomes -0.2.
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The apothem of the square 4 in. Find the radius, perimeter and area of the square.
Answer:
Perimeter: 32in. Radius: 5.656in. Area: 64in.
Step-by-step explanation:
Apothem is half the length of one side, therefor each side is 8 inches. Using this I can get my answers to the 3 questions.
the square root of $x$ is greater than 3 and less than 4. how many integer values of $x$ satisfy this condition?
6 integers that satisfy the given condition are 10,11,12,13,14,15.
Inequality is a relation that makes a non-equal comparison between two numbers or other mathematical expressions. It is used most often to compare two numbers on the number line by their size
we have the number X
Of which the square root is greater than 3 and less than 4
so,
\(3 < \sqrt{X} < 4\)
on squaring both sides
\(3^2 < (\sqrt{X})^{2} < 4^2\)
\(9 < X < 16\)
so the integer that satisfies the condition is 10,11,12,13,14,15.
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Answer:
6
Step-by-step explanation:
Because 4 > √x > 3, we know that 16 > x > 9. Thus, the integers from 10 to 15 inclusive satisfy this inequality, which means 6 integers satisfy the condition in the problem.
The refinery melt 1.25 tons of trash in 2 hours. How many tons of trash would be melted in 12 hours? HELP ME PLEASE :_)
Answer:
7.5 tons I think
Step-by-step explanation:
Find the value of (a+b)²-2ab when a=3 and b=2
Answer:
(a+b)^2-2ab= a^2+b^2+2ab-2ab=a^2+b^2= 3^2+2^2= 9+4= 13
hope it helps
The function g is defined by the following rule.
g(x) = 6^x
Find g(x) for each x-value in the table
-2
-1
0
1
2
\( &x &y \\ &-2 &\frac{1}{36} \\ &-1 &\frac{1}{6} \\ &0 &1 \\ &1 &6 \\ &2 &36\)
Step-by-step explanation:Given:
\(g(x) = 6^x\)
Solutions:
\(g(-2) = 6^{-2} \\ g(-2) = \frac{1}{6^2} \\ g(-2) = \frac{1}{36}\)
\(g(-1) = 6^{-1} \\ g(-1) = \frac{1}{6}\)
\(g(0) = 6^0 \\ g(0) = 1\)
\(g(1) = 6^1 \\ g(1) = 6\)
\(g(2) = 6^2 \\ g(2) = 36\)
the distribution of the amount of money spent by students on textbooks in a semester is approximately normal in shape with a mean of 477 and a standard deviation of 35.according to the standard deviation rule, approximately 95% of the students spent between $ and $ on textbooks in a semester
Approximately 95% of the students spent between $407 and $547 on textbooks in a semester, based on the standard deviation rule and the given mean and standard deviation.
To estimate the range of money spent by students on textbooks in a semester using the standard deviation rule, we can utilize the concept of the empirical rule.
According to the empirical rule, in a normal distribution, approximately 68% of the data falls within one standard deviation of the mean, approximately 95% falls within two standard deviations, and approximately 99.7% falls within three standard deviations.
Given that the mean is $477 and the standard deviation is $35, we can calculate the range for approximately 95% of the students.
One standard deviation from the mean is $477 ± $35, which gives us a range of $442 to $512.
Two standard deviations from the mean is $477 ± (2 × $35), which gives us a range of $407 to $547.
Therefore, Approximately 95% of the students spent between $407 and $547 on textbooks in a semester, based on the standard deviation rule and the given mean and standard deviation.
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can someone help me w this angle side relationships in triangles geometry question
The angle measure of triangle DEF in order of smallest to largest is m∠E = 36.03°, m∠F = 70.72° and m∠D = 73.25°.
The answer is: m∠E < m∠F < m∠D
How to find the measure of the angles in the triangle?The angle of a triangle can be found given its 3 sides using the cosine rule.
The formula is: cos(C) = (a² + b² -c²) / 2ab
where c is the length of the side opposite angle C, a and b are the lengths of the other two sides, and cos(C) is the cosine of angle C.
DE = f = 69 miles, EF = d = 70 miles and DF = e = 43 miles
cos (F) = (d² + e² -f²) / 2de
cos (F) = (70² + 43² -69²) / (2*70*43)
cos (F) = 71/215
F = cos⁻¹(71/215)
F = 70.72°
cos (E) = (d² + f² -e²) / 2df
cos (E) = (70² + 69² -43²) / (2*70*69)
cos (E) = 93/115
E = cos⁻¹(93/115)
E = 36.03°
DE = f = 69 miles, EF = d = 70 miles and DF = e = 43 miles
cos (D) = (e² + f² - d²) / 2ef
cos (D) = (43² + 69² - 70²) / (2*43*69)
cos (D) = 285/989
D = cos⁻¹(285/989)
D = 73.25°
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Exercise 10
You randomly choose one of the tiles. Without replacing the first tile, you choose a second tile. What is the probability of the compound event? Write your answer as a fraction or percent rounded to the nearest tenth.
The probability of choosing a 5 and then a 6 is 1/49
Finding the probability of the compound eventFrom the question, we have the following parameters that can be used in our computation:
The tiles
Where we have
Total = 7
The probability of choosing a 5 and then a 6 is
P = P(5) * P(6)
So, we have
P = 1/7 * 1/7
Evaluate
P = 1/49
Hence, the probability of choosing a 5 and then a 6 is 1/49
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Question
You randomly choose one of the tiles. Without replacing the first tile, you choose a second tile. Find the probability of the compound event. Write your answer as a fraction or percent rounded to the nearest tenth. The probability of choosing a 5 and then a 6
please explain how i would figure out where to place it
Answer:
i cant see it wdym
Step-by-step explanation:
Find four fractions between 1/10 and 1/8
9514 1404 393
Answer:
5/48, 5/46, 5/44, 5/42
Step-by-step explanation:
We can choose unit fractions with denominators between 8 and 10, separated by (10-8)/5 = 0.4 units:
1/8.4 = 5/42
1/8.8 = 5/44
1/9.2 = 5/46
1/9.6 = 5/48
__
Check
1/8 = 0.1255/42 ≈ 0.1195/44 ≈ 0.1145/46 ≈ 0.1095/48 ≈ 0.1041/10 = 0.100_____
Additional comment
There are an infinite number of such fractions. We are given unit fractions with different denominators, so it works reasonably well to choose denominators between those given. Then the trick is to convert the fraction to a ratio of integers. In this case, multiplying by (5/5) does the trick.
__
Another approach is to write the fractions with a common denominator, then choose numerators between the ones given. For example, 1/10 = 4/40, and 1/8 = 5/40, so you could write some fractions with numerators between 4 and 5. Possibilities are 4.1/40 = 41/400, 4.3/40 = 43/400, 4.7/40 = 47/400, 4.9/40 = 49/400.
a line intercepts the point ( -11, 4) and has a slope of -2 fill in the formula y - ? = ? (x - ? )
The point-slope form is;
\(y-4\text{ = -2(x+11)}\)Here, we want to write the slope intercept formula for the given line and point
We have the general point-slope form as;
\(\begin{gathered} y-y_1=m(x-x_1) \\ \\ m\text{ is slope = -2} \\ (x_1,y_1)\text{ = (-11,4)} \\ \\ y-4\text{ = -2(x-(-11))} \\ y\text{ - 4 = -2(x+11)} \end{gathered}\)can you help me on this
Answer:
1mi =1.61 km
Step-by-step explanation:
the second from the top
Fiona’s engagement ring from Prince Harry is valued at more than $3 million.
Write a response to the following questions:
What are two possible values for the price of the ring? Explain
How can you use a number sentence to represent this amount?
Since the value of the ring is “more than” $3 million, the possible values have to be greater than $5 million. There are many possibilities but two examples could be $4 million or $3.5 million.
Write a response to the following questions:
How can you determine if you use “equal to” in your inequality comparison?
Can an equation, with an equal sign, have more than one solution? Explain.
At the end of this assignment you should have answers to the four questions as stated above as they correlate with the statements given:
What are two possible values for the price of the ring? Explain
How can you use a number sentence to represent this amount?
How can you determine if you use “equal to” in your inequality comparison?
Can an equation, with an equal sign, have more than one solution? Explain.
Create a document to capture your responses. Make sure to explain each question with at least 3 complete sentences. Upload to Dropbox when complete.
Yes, The equation has two valid solutions.The value of Fiona’s engagement ring from Prince Harry may be more than $3 million,
but this information does not directly relate to the concept of equations with more than one solution.
an equation with an equal sign can have more than one solution. This happens when there are different values that can satisfy the equation, making them all valid solutions.
These types of equations are known as conditional equations. When solving a conditional equation, it is important to take into account any restrictions that may apply to the domain of the variable.
This helps to avoid extraneous solutions that may not work for the equation.For example, consider the equation x² - 9 = 0. This equation can be solved by taking the square root of both sides of the equation, which gives x = ±3.
This means that there are two solutions to the equation, x = 3 and x = -3. Both values can be substituted back into the equation and will satisfy it.
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find the rank of a 5 x 6 matrix a for which ax = 0 has a two-dimensional solution space.
Therefore, the rank of matrix 'a' in this case would be 5.
To find the rank of a matrix, we need to perform row reduction to obtain its row echelon form (REF) or reduced row echelon form (RREF). However, since the matrix 'a' is not provided, I cannot perform the calculations or determine its rank.
The rank of a matrix is equal to the number of non-zero rows in its row echelon form or reduced row echelon form. If the system of equations 'ax = 0' has a two-dimensional solution space, it means that the rank of matrix 'a' is less than the number of columns (6) but greater than 4 (since the solution space is two-dimensional).
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write the equation in spherical coordinates. (a) 3x^2 - 2x + 3y^2 + 3z^2 = 0 (b) 2x + 4y + 5z = 1
The equation in spherical coordinates is a) 3sin²ϕ - 2sinϕcosθ/ρ - 3cos²ϕ = 0
b) 2sinφcosθ + 4sinφsinθ + 5cosφ = 1/ρ
a) The equation in Cartesian coordinates is 3x² - 2x + 3y² - 3z² = 0. To convert to spherical coordinates, we use the following substitutions:
x = ρsinϕcosθ
y = ρsinϕsinθ
z = ρcosϕ
Substituting these values into the Cartesian equation gives:
3(ρsinϕcosθ)² - 2(ρsinϕcosθ) + 3(ρsinϕsinθ)² - 3(ρcosϕ)² = 0
3ρ²sin²ϕcos²θ - 2ρsinϕcosθ + 3ρ²sin²ϕsin²θ - 3ρ²cos²ϕ = 0
3ρ²sin²ϕ(cos²θ + sin²θ) - 2ρsinϕcosθ - 3ρ²cos²ϕ = 0
3ρ²sin²ϕ - 2ρsinϕcosθ - 3ρ²cos²ϕ = 0
Simplifying and dividing by ρ² gives:
3sin²ϕ - 2sinϕcosθ/ρ - 3cos²ϕ = 0
(b) The equation in rectangular coordinates is 2x + 4y + 5z = 1. To write it in spherical coordinates, we use the same conversion formulas as before:
2(ρsinφcosθ) + 4(ρsinφsinθ) + 5(ρcosφ) = 1
Simplifying and dividing by ρ, we get:
2sinφcosθ + 4sinφsinθ + 5cosφ = 1/ρ
This is the equation in spherical coordinates.
Learn more about spherical coordinates here
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