Answers
In order to calculate the energy needed, we can use the formula below:
\(Q=m\cdot c\operatorname{\cdot}\Delta T\)Where Q is the heat needed (in Joules), m is the mass, c is the specific heat and DeltaT is the change of temperature.
So, using the given information, we have:
\(\begin{gathered} Q=8.56\operatorname{\cdot}4186\operatorname{\cdot}(61.13-33.52)\\ \\ Q=8.56\operatorname{\cdot}4186\operatorname{\cdot}27.61\\ \\ Q=989325.94\text{ J} \end{gathered}\)Therefore the energy needed is 989325.94 Joules.
Related Questions
a wheel has angular velocity 4.00 rad/s. which of the following is closest to the number of revolutions that the wheel makes in 15.0 s?
a.10 revolutions
b.20 revolutions
c.15revolutions
d.25 revolutions
e. 5 revolutions
f. i dont know yet
Answers
Answer:
10 revolutions
Explanation:
By using the equation Δ=Δ, we get that Δ=(4.00rad/s)(15.0s)=60.0rad. Since there are 2 radians per revolution, this angular displacement corresponds to (60.0rad)/(2rad/rev)=9.55rev.
The angular velocity of the wheel is 4 rad/s and the time interval is 15 s. Then the number of rotations in radians is 60 radians. This is equal to 9.5 revolutions.
What is angular velocity ?Angular velocity is a physical quantity that describes the speed of an object in an angular path. It is the rotational o revolutional analogue of of the linear velocity.
The angular velocity of an object is the product of the linear velocity and the radius of the angular path.
Given that, the angular velocity of the wheel = 4 rad/s
time = 15 s
then, number of radians = 4 rad/s × 15 s = 60 radians.
1 revolution = 2π radians.
then 60 radians = 60/2π = 9.5 revolutions.
Therefore, the number of revolutions for the wheel in 15 s is 9.5 revolutions.
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Explain why the atomic mass of an element is weighted average mass
Answers
Explanation:
The mass written on the periodic table is an average atomic mass taken from all known isotopes of an element. This average is a weighted average, meaning the isotope's relative abundance changes its impact on the final average. The reason this is done is because there is no set mass for an element.
If F =GMm/R2
What is the dimension of the stress?
What is the unit of frequency?
Answers
The dimension of stress is M1 L-1 T-2 and the unit of frequency is Hz.
What is the frequency?
The frequency with which something happens over a specific time frame or sample
Let us find out the dimension of stress.
Stress = Force/Area
Force = mass * acceleration
Stress= M * L * T-2/ L2
Therefore, Stress = M L-1 T-2
As for the second question,
The unit of frequency is Hz (Hertz)
Hence, the dimension of the stress = M L-1 T-2 and the unit of frequency is hertz.
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A 15 year old boy requires eyeglasses with lenses of 2 diopters power in order to read a book at 25 cm. Five years later he finds that while wearing the same glasses, he must hold a book 40 cm from his eyes. What power of lenses does he require at 20 years in order to read a book at 25 cm?
Answers
At 20 years old, the boy would require eyeglasses with lenses of approximately -1.49 diopters power in order to read a book at 25 cm.
How to solve for the power of lenses1/f1 = 1/v - 1/u1
1/f1 = 1/∞ - 1/0.25 (converting 25 cm to meters)
1/f1 = 0 - 4
1/f1 = -4
f1 = -1/4
f1 = -0.25 meters
The initial lens power (P1) is the reciprocal of the focal length:
P1 = 1/f1
P1 = 1/-0.25
P1 = -4 diopters
Now let's calculate the final focal length (f2) using the final distance (v2) of 40 cm:
1/f2 = 1/v2 - 1/u1
1/f2 = 1/0.40 - 1/0.25
1/f2 = 2.5 - 4
1/f2 = -1.5
f2 = -1/1.5
f2 = -0.67 meters
The final lens power (P2) is the reciprocal of the focal length:
P2 = 1/f2
P2 = 1/-0.67
P2 ≈ -1.49 diopters
Therefore, at 20 years old, the boy would require eyeglasses with lenses of approximately -1.49 diopters power in order to read a book at 25 cm.
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2.
A ball player hits a home run, and the ball just clears the wall which is 22.0 m high.
The ball is hit at an angle of 37.0" with a velocity of 45.0 m/s. If the ball is hit from
a height of 0.750 m above the ground, (a) How long is the ball in the air until it
clears the wall while on its way down? (b) How far is the wall from home plate?
Answers
a.) the ball was going up at 0.95 seconds and coming down at 4.58 seconds
b.) the distance of the wall from the plate is 34 m
Given that a ball player hits a home run, and the ball just clears the wall which is 22.0 m high. The ball is hit at an angle of 37.0" with a velocity of 45.0 m/s.
Since the ball is hit at an angle of 37.0 degrees, We need to find the vertical and horizontal component of the velocity.
\(U_{y}\) = 45 Sin 37 = 27.08 m/s
\(U_{x}\) = 45 cos 37 = 35. 94 m/s
Let us first calculate the maximum height reached.
\(V^{2}\) = \(U_{y} ^{2}\) - 2gH
At maximum height, V = 0
0 = \(27.08^{2}\) - 2 x 9.8H
19.6H = 733.3
H = 733.33/19.6
H = 37.4 m
If the ball is hit from a height of 0.750 m above the ground,
(a) To calculate the time the ball stays in the air until it clears the wall while on its way down, we will use the formula below.
h = \(U_{y}\)t - 1/2g\(t^{2}\)
Substitute for all the parameters
22 - 0.75 = 27.08t - 0.5 x 9.8 x \(t^{2}\)
21.25 = 27.08t - 4.9\(t^{2}\)
4.9\(t^{2}\) - 27.08t + 21.25
We will use quadratic formula
a = 4.9
b = - 27.08
c = 21.25
t = \(\frac{-b+/- \sqrt{b^{2} - 4ac } }{2a}\)
t = \(\frac{27.08 +/- \sqrt{27.08^{2} - 4 * 4.9 * x^{2} 21.25 } }{2 * 4.9}\)
t = \(\frac{27.08 +/-\sqrt{733.3 - 416.5} }{9.8}\)
t = \(\frac{27.08 +/- 17.8}{9.8}\)
t = 44.88/9.8 or 9.28 / 9.8
t = 4.58 s or 0.95 s
This means that the ball was going up at 0.95 seconds and coming down at 4.58 seconds
(b) The distance of the wall from home plate will be the range which is
R = \(U_{x}\)t
R = 35.94 x 0.95
R = 34.143 m
Therefore, the distance of the wall from the plate is 34 m approximately
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Some dragonflies splash down onto the surface of a lake to clean themselves. After this dunking, the dragonflies gain altitude, and then spin rapidly at about 1100 rpm to spray the water off their bodies. When the dragonflies do this "spin-dry," they tuck themselves into a "ball" with a moment of inertia of 2.0×10−7kg⋅m2 . How much energy must the dragonfly generate to spin itself at this rate?
Answers
The dragonfly must generate approximately 4.8 × 10^-4 Joules of energy to spin itself at a rate of 1100 rpm.
Start by converting the rotational speed from rpm (revolutions per minute) to rad/s (radians per second). Since 1 revolution is equal to 2π radians, we can use the conversion factor:
Angular speed (ω) = (1100 rpm) × (2π rad/1 min) × (1 min/60 s)
ω ≈ 115.28 rad/s
The moment of inertia (I) is given as 2.0 × 10^-7 kg⋅m².
Use the formula for rotational kinetic energy:
Rotational Kinetic Energy (KE_rot) = (1/2) I ω²
Substituting the given values:
KE_rot = (1/2) × (2.0 × 10^-7 kg⋅m²) × (115.28 rad/s)²
Calculate the value inside the parentheses:
KE_rot ≈ (1/2) × (2.0 × 10^-7 kg⋅m²) × (13274.28 rad²/s²)
KE_rot ≈ 1.331 × 10^-3 J
Round the result to the proper number of significant figures, which in this case is three, as indicated by the given moment of inertia.
KE_rot ≈ 4.8 × 10^-4 J
Therefore, the dragonfly must generate approximately 4.8 × 10^-4 Joules of energy to spin itself at a rate of 1100 rpm.
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An Eagar resident is driving down the road late at night at a velocity of 14 m/s. Suddenly an elk runs out in front of the car and the driver slams on the brakes. If the car comes to a stop (velocity final = 0 m/s) in 32 m, what is the acceleration of the car?
Answers
The acceleration of the car is approximately -3.06 m/s^2.
To find the acceleration of the car, we can use the kinematic equation:
v^2 = u^2 + 2as
Where:
v = final velocity = 0 m/s
u = initial velocity = 14 m/s
a = acceleration (to be determined)
s = displacement = 32 m
Plugging in the values into the equation, we can solve for acceleration:
0^2 = 14^2 + 2a(32)
Simplifying:
0 = 196 + 64a
Rearranging the equation:
64a = -196
Dividing both sides by 64:
a = -196/64
a ≈ -3.06 m/s^2
This means that every second, the car's velocity decreases by 3.06 meters per second. The negative sign indicates that the acceleration is in the opposite direction of the initial velocity, opposing the car's motion and bringing it to a stop.
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Can someone help please. I have the question on the attachment
Answers
The average acceleration of the car, given that it has an average velocity of 15.6 m/s is –3.71 m/s²
How to determine the average accelerationAcceleration is defined as follow:
a = (v – u) / t
a is the acceleration v is the final velocity u is the initial velocity t is the timeWith the above formula, we can determine the average acceleration of the car as illustrated below:
Initial velocity (u) = 15.6 m/sFinal velocity (v) = 0 m/sTime (t) = 4.2 s Average acceleration (a) =?a = (0 – 15.6) / 4.2
a = –15.6 / 4.2
a = –3.71 m/s²
Thus, from the calculation made above, we can conclude that the average acceleration is –3.71 m/s²
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What happens if you are riding your bike and hit something (like a curb) with the front wheel
Answers
A string has mass 5.0 grams, and is stretched with 180 N of tension. A wave travels on this string with frequency 260 Hz and wavelength 0.60 m. Determine the length of the string.
Answers
Answer:
3.68×10¯⁶ m
Explanation:
The following data were obtained from the question:
Mass (m) = 5 g
Tension (T) = 180 N
Frequency (f) = 260 Hz
Wavelength (λ) = 0.60 m.
Length (L) =?
Next, we shall determine the period of the wave. This can be obtained as follow:
Period is simply defined as the time taken to complete 1 oscillation. Mathematically, it is represented as:
Period (T) = 1/frequency (f)
T = 1/f
Thus, with the above formula, the period of the wave can be obtained as shown below:
Frequency (f) = 260 Hz
Period (T) =?
T = 1/f
T = 1/260
T = 3.85×10¯³ s
Finally, we shall determine the length of the string as follow:
Period (T) = 3.85×10¯³ s
Acceleration due to gravity (g) = 9.8 m/s²
Pi (π) = 3.14
Length (L) =?
T = 2π√(L/g)
3.85×10¯³ = 2 × 3.14 × √(L/9.8)
3.85×10¯³ = 6.28 × √(L/9.8)
Divide both side by 6.28
3.85×10¯³ / 6.28 = √(L/9.8)
Take the square of both side
(3.85×10¯³ / 6.28)² = L/9.8
Cross multiply
L = (3.85×10¯³ / 6.28)² × 9.8
L = 3.68×10¯⁶ m
Therefore, the length of the string is 3.68×10¯⁶ m
Part-II Work out Step by step clearly (6%) 5. A 5kg mass starts from rest at xo = -1 and moves under the action of a variable force F(x) = √1-x² to point xf = 1. Calculate the total work done by the force? (1%)
Answers
If a 5kg mass starts from rest at xo = -1 and moves under the action of a variable force F(x) = √1-x² to point xf = 1. Then the total work done by the force is equal to π/2 + 1.
To calculate the total work done by the force in this scenario, we can use the formula for work:
Work = ∫F(x) dx
where F(x) is the force as a function of position and dx represents an infinitesimal displacement.
In this case, the force is given by F(x) = √(1 - x²), and we need to find the total work done as the object moves from xo = -1 to xf = 1.
Let's break down the calculation step by step:
Write the integral for work:
Work = ∫F(x) dx
Substitute the given force:
Work = ∫√(1 - x²) dx
Integrate with respect to x:
To integrate the square root of (1 - x²), we use the trigonometric substitution. Let's substitute x = sin(θ) and dx = cos(θ) dθ.
Work = ∫√(1 - sin²(θ)) cos(θ) dθ
Simplify the integrand:
Using the trigonometric identity sin²(θ) + cos²(θ) = 1, we can rewrite the integrand as cos²(θ).
Work = ∫cos²(θ) dθ
Apply the power-reducing formula:
The power-reducing formula states that cos²(θ) = (1 + cos(2θ)) / 2. We can use this formula to simplify the integrand further.
Work = ∫(1 + cos(2θ))/2 dθ
Integrate the terms separately:
Work = (1/2) ∫dθ + (1/2) ∫cos(2θ) dθ
The first integral, ∫dθ, is simply θ, and the second integral, ∫cos(2θ) dθ, can be calculated as sin(2θ)/2.
Work = (1/2) θ + (1/2) (sin(2θ)/2) + C
Evaluate the integral limits:
To find the total work done, we need to evaluate the integral at the upper and lower limits of integration.
At xf = 1, the angle θ is π/2, and at xo = -1, the angle θ is -π/2.
Work = (1/2) (π/2) + (1/2) (sin(2(π/2))/2) - [(1/2) (-π/2) + (1/2) (sin(2(-π/2))/2)]
Simplifying further:
Work = π/4 + (1/2) - (-π/4 + (1/2))
Work = π/4 + 1/2 + π/4 + 1/2
Work = π/2 + 1
Therefore, the total work done by the force is equal to π/2 + 1.
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PLEASE ANSWER FASG I WILL MARK BRAINELIST PLEASEEEEE
The number of protons in the nucleus of an atom determines the species of the atom, i.e., the element to which the atom belongs. An atom has the same number of protons and neutrons. But the electron number cannot be used instead because (5 points)
a. electrons are not within the nucleus
b. electrons are negatively charged
c. electrons can be removed from or added to an atom
d. electrons are lighter than protons
Answers
The electron number cannot be used instead because electrons can be removed from or added to an atom (option C)
Why the electron number cannot be used instead?The element of an atom is determined by its proton count, while the electron count can exhibit variability. Take, for instance, a sodium atom, which encompasses 11 protons and 11 electrons. However, it has the capacity to relinquish one electron, transforming into a sodium ion housing only 10 electrons.
This occurs due to the relatively loose binding of electrons to the nucleus, enabling their removal through the influence of an electric field or alternative mechanisms.
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An atom has two more electrons than protons. What is the charge of the atom?
Answers
Answer:
If it has more electrons than protons it has a net negative charge and is known as an anion.
as the sun rotates, an individual sunspot can be tracked across its face. from eastern to western limb, this takes about as the sun rotates, an individual sunspot can be tracked across its face. from eastern to western limb, this takes about 12 hours. a week. two weeks. a month. 5.5 years.
Answers
A specific sunspot can be followed as it moves over the Sun's surface as it revolves. This takes approximately from eastern to western limb.
While moving over the Earth-side of the sun, super sunspot AR2192 generated 10 major solar flares, six of which were X-class and four of which were above M5-class. These photos from NASA's SDO, taken between October 17 and October 29, 2014, show a sunspot that is the largest since November 1990 moving across the front of the sun. Try restarting your device if playback doesn't start right away. These photos from NASA's SDO, taken between October 17 and October 29, 2014, show a sunspot that is the largest since November 1990 moving across the front of the sun. Try restarting your device if playback doesn't start right away. Your watched videos might be added to.
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In the diagram, q1, q2, and q3 are in a striaght line. each of these particles has a charge of -2.35 x 10^-6 C. Particles q1 and q2 are separated by 0.100 m and particles q2 and q3 are separated by 0.100 m. What is the net force on particle q1?
PLEASE ANSWER IVE BEEN STUCK ON THIS SECTION FOR A WEEK
Answers
The net force on q1 is 9.94 N.
What is the net force on q1?From Coulomb's Law, the force between two point charges is given by:
F = (k * q1 * q2) / r²where;
F is the force,k is Coulomb's constant (9 * 10⁹ N * m²/C²),q1 and q2 are the charges,r is the distance between the charges.All the charges have the same charge and magnitude and are separated by the same distance.
The force between q1 and q2 is:
F12 = (9 * 10⁹ N * m²/C²) * (-2.35 x 10⁻⁶ C)² / (0.100 m)²
F12 = 4.97 N
The positive sign indicates that the force is repulsive
Similarly, the force between q2 and q3 is:
(9 * 10⁹ N * m²/C²) * (-2.35 x 10⁻⁶ C)² / (0.100 m)²
F12 = 4.97 N
The positive sign indicates that the force is repulsive
The net force on q1 will be:
Fnet = F12 + F23
Fnet = 4.97 N + (4.97)
Fnet = 9.94 N
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The picture shows an object resting on a balance.
The object on the balance weighs 0.500 kilograms.
The weight of an object is given by F = mg, where g = 9.8 m/s2. With what force does the object push down on the balance?
Choose the correct answer.
9.3 kg⋅m/s2
9.3 kg⋅m/s, 2
9.8 kg⋅m/s2
9.8 kg⋅m/s, 2
4.90 kg⋅m/s2
4.90 kg⋅m/s, 2
0.500 kg⋅m/s2
0.500 kg⋅m/s, 2
Skip to navigation
Answers
Answer:
4.90kgm^-2
Explanation:
Select ALL the
correct answers.
Which two examples describe ways that corporations can give large donations to presidential candidates?
A corporation leader makes
direct payment to the candidate.
A corporation creates another company to accept candidate contributions
A corporation collects moneys from its employees to contribute to
A corporation contributes to a Super PAC that
a PAC
accepts contributions
for a candidate,
Reset
Next
Answers
Answer: Hope this helps ;) don't forget to rate this answer !
Explanation:
There are two correct answers:
A) A corporation leader makes direct payment to the candidate.
D) A corporation contributes to a Super PAC that a PAC accepts contributions for a candidate.
Option A describes a scenario where a corporation directly donates money to a presidential candidate, which is allowed as long as it is done within the limits set by campaign finance laws.
Option D describes a scenario where a corporation donates money to a Super PAC, which is a type of political action committee that can accept unlimited donations from individuals, corporations, and other organizations. The Super PAC can then use the money to support or oppose a particular candidate, but it is not allowed to coordinate directly with the candidate or the candidate's campaign.
I hope this helps! Let me know if you have any other questions.
which statement about force is incorrect
Answers
Answer:
What are the options?
Explanation:
A woman 1.2 m tall lies along the axis of a space vehicle traveling at 0.87c. What is her height as measured by a stationary observer?
Answers
Answer:
L = L0 (1 - v^2/c^2) where L0 is proper length and L the measured length
L = 1.2 (1 - .87^2)^1/2 m = .59 m
OOOO
What are some of the factors that can cause a person to have a single-gene disease or disorder?
Answers
Explanation:
When a certain gene is known to cause a disease, we refer to it as a single gene disorder or a Mendelian disorder. For example, you may have heard of cystic fibrosis, sickle cell disease, Fragile X syndrome, muscular dystrophy, or Huntington disease. These are all examples of single gene disorders.
Answer: mitochondrial inheritance patterns, autosomal inheritance patterns, mutations.
Explanation:
I’ve been struggling with this question, help!
Answers
The masses of the two objects MA and MB in the binary system are 4 Mo respectively.
How can the masses of the binary systems be calculated?The masses of binary systems can be calculated using Kepler's laws of planetary motion and observations of the system.
Let's denote the masses of the two objects as MA and MB, where MA is the mass of object A and MB is the mass of object B. We know that the total mass of the binary system is 8 Mo, so:
MA + MB = 8 Mo
We also know that the ratio of the distances between the two objects is 1/3. Let's denote the distance between the two objects as d, so we have:
d(A to B) / d(Binary System) = 1/3
We can simplify this equation by using the fact that the distances between the objects and the binary system add up to the total distance between the objects:
d(A to B) + d(B to binary system) = d(Binary system)
Since we know the ratio of the distances, we can substitute 1/3d for d(B to binary system):
d(A to B) + 1/3d = d(Binary system)
3d(A to B) + d = 3d(Binary system)
Substituting d(A to B) for d(Binary system) - d(B to binary system), we get:
3d(A to B) + d = 3(d(A to B) + d(B to binary system))
2d(A to B) = 2d(B to binary system)
d(A to B) / d(B to binary system) = 1
So the two objects are at the same distance from the binary system center of mass. This means that the masses of the two objects are equal:
MA = MB
Substituting this into the first equation, we get:
2MA = 8 Mo
MA = MB = 4 Mo
Therefore, the mass of each object is 4 Mo.
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The hour hand on a certain clock is 8.1 cm long.
Find the tangential speed of the tip of this hand.
Answers
The tangential speed of the tip of the hour hand is 4.05 cm/minute.
What is Tangential speed?
Tangential speed, also known as linear speed, is the speed at which an object travels along a circular path. It is defined as the distance traveled per unit of time along an arc or circular path, with the direction of motion tangential to the circle. Tangential speed is dependent on the radius of the circular path and the angular speed, which is the rate at which the object rotates around the center of the circle.
The tangential speed of the tip of the hand is given by:
v = rω
where r is the length of the hour hand and ω is the angular velocity of the hand.
To find ω, we need to convert the time elapsed to an angle. The hour hand completes one revolution (360 degrees) in 12 hours, or 720 minutes. Therefore, the angle swept out by the hour hand in one minute is:
θ = 360 degrees / 720 minutes = 0.5 degrees/minute
At any given time, the angle swept out by the hour hand is proportional to the elapsed time since the last hour mark. If t is the time elapsed in minutes since the last hour mark, then the angle swept out is:
θ = 0.5 degrees/minute * t
Since the hour hand is 8.1 cm long, its tangential speed is:
v = rω = r(dθ/dt)
Substituting for θ, we get:
v = 8.1 cm * (0.5 degrees/minute) = 4.05 cm/minute
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How does a positive charge and a negative charge interact when they are brought close together
Answers
A positive charge and a negative charge will attract when they are brought close together.
What is Law of magnetism?The law of magnetism states that like poles repel one another and unlike poles attract each other.
This is commonly tested using a magnet in the laboratory by scientists in which the North pole and the South attract each other while similar poles such as North and North will repel each other. In this scenario, a positive charge and a negative charge interacting will lead to attraction which is therefore the reason why it was chosen as the correct choice.
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A man climbs on to a wall that is 3.6 m high and gains 2222.64 J of potential
energy. What is his mass?
63 kg
17.5 kg
405 kg
617.4 kg
Answers
What do you see as Michael Collins’s leadership traits? Which of these do you consider a strength? A weakness?
Answers
Collins's visionary leadership and strategic thinking were his key strengths, while his risk taking nature could be seen as a weakness.
Michael Collins’s leadership traitsMichael Collins, the Irish revolutionary and politician, displayed several leadership traits throughout his career. Here are some key traits associated with Collins:
Visionary: Collins had a clear vision for an independent Ireland and worked tirelessly to achieve it. He played a crucial role in shaping the strategies and tactics of the Irish Republican Army (IRA) during the Irish War of Independence.Determination: Collins was highly determined and committed to his cause. He demonstrated unwavering dedication to the pursuit of Irish independence, even in the face of significant challenges and risks.Strategic thinking: Collins was a strategic thinker who possessed a keen understanding of the political and military landscape. He implemented innovative guerrilla warfare tactics, such as intelligence gathering and targeted assassinations, to disrupt British rule in Ireland.Charismatic communication: Collins had strong communication skills and charisma, which enabled him to inspire and rally others to his cause. His ability to articulate his vision and mobilize support was instrumental in gaining public backing for the IRA.Boldness and risk-taking: Collins was known for taking bold risks and making daring decisions. For example, he authorized the intelligence organization known as the "Squad" to carry out targeted assassinations of British agents, which significantly weakened British intelligence capabilities in Ireland.Learn more on leadership traits here https://brainly.com/question/12522775
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A wave travels at a consent speed. how does the frequency change if the wavelength is reduced by a factor of 4?
Answers
Answer:
The frequency increases by 4 because it is inversely proportional to the wavelength.
A jet aircraft is accelerating at 3.8 m/s2 as it climbs at an angle of 18∘ above the horizontal. (a) Determine the magnitude of the total force that the cockpit seat exerts on the 76- kg pilot? (b) Determine the angle between the positive x axis and the total force that the cockpit seat exerts on the 76- kg pilot, measured counterclockwise.
Answers
a. The magnitude of the total force that the cockpit seat exerts on the 76- kg pilot is 288.8 N.
b. The angle between the positive x axis and the total force that the cockpit seat exerts on the 76- kg pilot is 67⁰.
Force exerted on the pilot by the cockpit
The force exerted on the pilot by the cockpit is calculated as follows;
F = ma
where;
m is mass of the pilot
a is acceleration of the jet
F = 3.8 m/s² x 76 kg
F = 288.8 N
The total force exerted on the pilot is equal to the normal reaction of the pilot.
F = Fn
F = mg cosθ
cos θ = F/mg
cos θ = (288.8) / (76 x 9.8)
cos θ = 0.3878
θ = arc cos (0.3878)
θ = 67⁰
Thus, the magnitude of the total force that the cockpit seat exerts on the 76- kg pilot is 288.8 N.
The angle between the positive x axis and the total force that the cockpit seat exerts on the 76- kg pilot is 67⁰.
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Complete ▼ Part A Rank in order, from the most to the least, the number of significant figures in the tollowing numbers. For example, ifb has more than c, c has the same number as a and a has more than d you would give your answer as b>c=a»d a 8200 b 00052 c 0430 d 4321 x 10" Completed O Type here to search
Answers
The correct response for the number of significant digits in the following numbers, from most to least, is d>c>b=a.
The number of digits in a particular value or measurement required to determine the accuracy and precision of measurement are known as significant figures (or significant digits).They are crucial for technical or scientific measurements.Significant denotes significance. In the supplied number, they make reference to the trustworthy digits that are adequate to transmit precise information. They also aid in the rounding off of measurement readings and calculating results.The quantity of digits necessary to assess the accuracy and precision of a measurement, such as length, mass, or volume, is known as significant figures (or significant digits).
Complete question: Rank in order, from the most to the least, the number of significant figures in the following numbers. For example, ifb has more than c, c has the same number as a and a has more than d you would give your answer as b>c=a»d a) 8200 b) 00052 c) 0430 d )4321 x 10" Completed O Type here to search
a)d>c>b=a b)a=d>c>b c)d>c>a>b d)b=d>c>a e)a=b=d>c
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The number of hours
of daylight tat a location receives varies depending on how far north or south it is from the
Answers
Answer:
equator
Explanation:
in south & north pole you could have 20+ hours daylight or night, everyday!
What must be the length of a simple pendulum if its oscillation frequency is to be equal to that of an air-track glider of mass 0.250 kg attached to a spring of force constant 9.75 N/m
Answers
Answer:
the length of the simple pendulum is 0.25 m.
Explanation:
Given;
mass of the air-track glider, m = 0.25 kg
spring constant, k = 9.75 N/m
let the length of the simple pendulum = L
let the frequency of the air-track glider which is equal to frequency of simple pendulum = F
The oscillation frequency of air-track glider is calculated as;
\(F = \frac{1}{2\pi } \sqrt{\frac{k}{m} } \\\\F = \frac{1}{2\pi } \sqrt{\frac{9.75}{0.25} } \\\\F = 0.994 \ Hz\)
The frequency of the simple pendulum is given as;
\(F = \frac{1}{2\pi} \sqrt{\frac{g}{l} } \\\\2\pi(F) = \sqrt{\frac{g}{l} } \\\\2\pi (0.994) = \sqrt{\frac{9.8}{l} } \\\\6.2455 = \sqrt{\frac{9.8}{l} } \\\\(6.2455)2 = \frac{9.8}{l} \\\\39.006 = \frac{9.8}{l} \\\\l = \frac{9.8}{39.006} \\\\l = 0.25 \ m\)
Thus, the length of the simple pendulum is 0.25 m.