How much propane is used to produce 1000 grams of water

The theoretical yield of Ca(OH)₂ : 42.032 g

Given

31.8 g of CaO

Required

The theoretical yield of Ca(OH)₂

Solution

Reaction

CaO + H₂O⇒Ca(OH)₂

mol CaO (MW=56 g/mol) :

= mass : MW

= 31.8 g : 56 g/mol

= 0.568

From equation, mol Ca(OH)₂ = mol CaO = 0.568

Mass Ca(OH)₂ (MW=74 g/mol) :

= 0.568 x 74

= 42.032 g

Answer:

it was too broad

Explanation:

mark me as the brainliest

ANSWER

it was too broad

Answer:

A complete deletion of the AR gene, would lead to a condition known as androgen insensitivity syndrome.

Explanation:

In such individuals, injection of testosterone (androgen) would not be sensitive to androgens and become less responsive to these hormones or unable to use these hormones at all.

E°cell for each reaction, and rank the strengths of the oxidizing and reducing agents:

Complete the given reaction

\($$\mathrm{N}_{2} \mathrm{O}(g)+2 \mathrm{H}^{+}(a q)+2 \mathrm{Au}(s) \longrightarrow \mathrm{N}_{2}(g)+\mathrm{H}_{2} \mathrm{O}(l)+2 \mathrm{Au}^{+}(a q)$$\)

Write the oxidation reaction

\($$\mathrm{Au}(s) \longrightarrow \mathrm{Au}^{+}(a q)+e^{-}$$\)

\($$E_{a c d}=-1.69 \mathrm{~V}$$\)

Write the reduction reaction

\($$3 \mathrm{~N}_{2} \mathrm{O}(g)+2 \mathrm{H}^{+}(a q)+2 \mathrm{e}^{-} \longrightarrow \mathrm{N}_{2}(g)+\mathrm{H}_{2} \mathrm{O}(l) \quad E_{r e d}=+1.77 \mathrm{~V}$$\)

Calculate the standard cell voltage

\($$E_{c ell}=E_{r e d}+E_{o x d}$$\)

Substitute the value

\($$\begin{aligned}&E_{c e l l}=1.77-1.69 \\&E_{c e l l}=0.08 \mathrm{~V}\end{aligned}$$\)

Hence the standard cell potential is \($0.08 \mathrm{~V}$\)

Oxidizing agent in this reaction is

\($$\mathrm{N}_{2}(g), \mathrm{N}_{2} \mathrm{O}(g)$$\)

Reducing agent in this reaction is

\($$\mathrm{Au}^{+}(a q), \mathrm{Au}(s)$$\)

The potential difference between the two electrodes of an electrochemical cell, which develops when electrons are sent via the external circuit of a cell that has not reached equilibrium, is known as the cell potential.

A chemical process known as an oxidation-reduction (redox) reaction includes the exchange of electrons between two substances. Any chemical reaction in which the oxidation number of a molecule, atom, or ion changes due to the gain or loss of an electron is referred to as an oxidation-reduction reaction.

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Three examples of environmental, industrial and bio-chemistry are listed below:

Chemistry can be defined as a branch of science which is concerned with the substances matter is composed of, their properties and reactions,

Chemistry also deals with the use of such reactions to form new substances.

In conclusion, Three examples of environmental, industrial and bio-chemistry are listed anove

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Answer:

a force of friction would be like something moving that suddenly stops because of the texture of another object while a force of gravity would be something falling and gravity pulling it down :) hope this helps

Explanation:

The ionizations of H2PHO3 produce HPO32- and PO43- ions, with respective ionization constants Ka1 and Ka2, in aqueous solutions.

Phosphorous acid, H2PHO3, is a diprotic acid which means it can donate two hydrogen ions (H+) in aqueous solutions. The ionizations of H2PHO3 can be represented as follows:

1. H2PHO3 + H2O ⇌ H3O+ + HPO32-

2. HPO32- + H2O ⇌ H3O+ + PO43-

The first ionization reaction produces the HPO32- ion which is a weak acid that can undergo a second ionization to produce PO43- ion which is a very weak base. The expressions for the ionization constants (Ka) for the two reactions are:

Ka1 = [H3O+][HPO32-]/[H2PHO3]

Ka2 = [H3O+][PO43-]/[HPO32-]

where [H3O+] represents the concentration of hydronium ions, [H2PHO3] represents the concentration of phosphorous acid, [HPO32-] represents the concentration of hydrogen phosphite ions and [PO43-] represents the concentration of phosphate ions.

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Answer:

Q = 30 calories

Explanation:

We have,

The specific heat of ice is 0.5 calories/gram.

The heat require to raise the temperature is given by :

\(Q=mc\Delta T\)

m = 60 grams, c = 0.5 calories/gram °C, \(\Delta T=1\ C\)

So,

\(Q=60\times 0.5\times 1\\\\Q=30\ \text{calories}\)

So, 30 calories of heat is required to raise the temperature by 1 C.

B.) Plant adaptations are changes that help a plant species survive in its environment. Aquatic plants that live underwater have leaves with large air pockets inside that allow the plant to absorb oxygen from the water. The leaves of aquatic plants are also very soft to allow the plant to move with the waves.

*I literally just took it today I know the answer B is correct. (Broad leaves that float)

The ionic compounds that would have a name that contains the Roman numeral I is CuI.

The term ionic compound has to do wit a compound that is composed of ions. This implies that the particles that we have in the compound ate just ions that have come together.

It is important to show the oxidation state of each of the species that are involved in the compound and this is all the more necessary when we have one of the elements in the compound that could have two or more oxidation states.

If we look at the options that we have up there in the question, we can see that copper could have two oxidation states copper I and copper II. We can now see that the oxidation state of copper that has the formula CuI is copper I iodide.

As such, the ionic compounds that would have a name that contains the Roman numeral I is CuI.

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Wine was produced 37 years ago (1984 as usual year 15,2021) that is shown in the calculations below.

Reaction rate is calculated using the formula rate = Δ[C]/Δt, where Δ[C] is the change in product concentration during time period Δt. The rate of reaction can be observed by watching the disappearance of a reactant or the appearance of a product over time.

The time can be represented as follows:

t= 2.303\∧ log A0/A

∧= 0.693/t 1/2

The rate of a reaction is proportional to the reciprocal of the time taken. Rate α 1 time Rate is inversely proportional to time. Units: s-1, min-1 etc.

The given parameters are as follows:

t1/2=12.3

A0=5.5

A=0.688

t= 2.303/(0.693/12.3) log (5.5/0.688)

t=36.9

t=37 years

Thus, wine was produced 37 years ago (1984 as usual year 15,2021)

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A non-spontaneous process is one in which the overall entropy change is negative.

Thermodynamic principles are used to optimize the performance of our houses' heating and cooling systems, other buildings' engines, and even the motor cars we drive.

The amount of thermal energy per unit of temperature in a system that is not accessible for doing beneficial work. The quantity of entropy is also a gauge of a system's molecular disorder, or unpredictability, since work is produced by organized molecular motion.

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Answer:

I'm pretty sure you'll be fine

Explanation:

I've swallowed more than a small amount and I'm ok sort of

The proton is a postitive charge, therefore, being 1 (proton) matched to positive. Whilst neutron (2) is matched to neutral. Thus electron (3) is matched to negative.

Answer:

A

Explanation:

Nitrogen can ionically bond with the unknown element X of group 2. These ions of element X are required to form stable ionic compounds with 3 nitrogen.

An ionic bond is formed by the sharing of electrons between two atoms of her that are chemically bonded.

In ionic bonding, an attractive force occurs between oppositely charged ions, resulting in a strong attractive force between the ions. Therefore, ionic bonds are the strongest bonds.

Ionic bonds are always formed between metals and non-metals.

Nitrogen (non-metal) in this compound has oxidation state -3 and element X (metal) has oxidation state +2.

The least common multiple of 3 and 2 is 6.

Number of nitrogen atoms = 6 ÷ 3. number of nitrogen atoms = 2,

It has two nitrogen atoms.

Atomic number X:

6 ÷ 2 = 3.

For example, Mg₃N₂; magnesium nitride. Nitrogen has an oxidation number of -3 and magnesium has an oxidation number of +2.

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Answer:

Diastereomers can have different physical properties and reactivity. They have different melting points and boiling points and different densities.

Answer: A molecule of hydrochloric acid, for example, is composed of a hydrogen atom and a chlorine atom. When these molecules dissolve into water, they separate into a positively charged hydrogen ion and a negatively charged chlorine ion. ... Only some of the molecules of weak acids disassociate when added to water.

Explanation:

The two compounds that give the condensation product ~OCICH through a mixed Claisen condensation are:

A) \(CoHSCCHzCH; and HCO2CHzCH.\)

In a mixed Claisen condensation, one of the reactants is an ester and the other is a compound with an alpha hydrogen. In this case, CoHSCCHzCH; is the ester and HCO2CHzCH is the compound with an alpha hydrogen. The alpha hydrogen in HCO2CHzCH is deprotonated and the resulting enolate ion attacks the carbonyl carbon of CoHSCCHzCH, forming an alkoxide intermediate. The intermediate then undergoes intramolecular rearrangement and elimination of the leaving group to form the final condensation product ~OCICH.

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the energy required to convert 1 mole of liquid argon from 5°C below its boiling point to 1 mole of gaseous argon at 5°C above its boiling point is 6735 J/mol.

To calculate the energy required to convert 1 mole of liquid argon from 5°C below its boiling point to 1 mole of gaseous argon at 5°C above its boiling point, we need to consider two steps:

Heating the liquid argon from 5°C below its boiling point to its boiling point and converting it to gaseous argon at its boiling point.

Heating the gaseous argon from its boiling point to 5°C above its boiling point.

Step 1: To heat the liquid argon from 5°C below its boiling point to its boiling point, we need to supply energy equal to the heat of vaporization of argon, which is 6506 J/mol. This energy is used to overcome the intermolecular forces between the argon molecules and convert the liquid to gaseous state. Since the specific heat of liquid argon is 25.0 J/mol·°C, the energy required to heat 1 mole of liquid argon from 5°C below its boiling point to its boiling point is:

q1 = (25.0 J/mol·°C) x (5°C) = 125 J/mol

Adding the energy required for vaporization, the total energy required for step 1 is:

q1_total = 6506 J/mol + 125 J/mol = 6631 J/mol

Step 2: To heat the gaseous argon from its boiling point to 5°C above its boiling point, we need to supply energy equal to the product of its specific heat and the temperature change. Since the specific heat of gaseous argon is 20.8 J/mol·°C, the energy required to heat 1 mole of gaseous argon from its boiling point to 5°C above its boiling point is:

q2 = (20.8 J/mol·°C) x (5°C) = 104 J/mol

The total energy required to convert 1 mole of liquid argon from 5°C below its boiling point to 1 mole of gaseous argon at 5°C above its boiling point is the sum of the energies required for step 1 and step 2:

q_total = q1_total + q2 = 6631 J/mol + 104 J/mol = 6735 J/mol

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Precipitation and color change can occur when mixing a cation and anion, depending on solubility and complex formation.

At the point when a cation and anion are combined as one, there might be two noticeable changes that happen:

Precipitation: In the event that the cation and anion structure an insoluble salt, it might hasten out of the arrangement as a strong. This should be visible as an overcast or obscure appearance in the blend. For instance, while blending silver nitrate (AgNO3) and sodium chloride (NaCl), the development of silver chloride (AgCl) is insoluble and brings about a white encourage.

Variety change: The blending of specific cations and anions can bring about an adjustment of variety because of the development of a perplexing particle. This happens when the cation and anion join to shape a coordination compound that has an unexpected variety in comparison to the first cation or anion.

For instance, while adding potassium permanganate (KMnO4) to an answer containing oxalate particles (C2O4 2-), the purple shade of KMnO4 vanishes and is supplanted by an earthy colored tone because of the development of a manganese oxalate complex.

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The complete question is:

Experiment 5 Formation and Naming of lonic Compounds QUESTIONS PRE LAB 1. List two visible changes that may occur in this experiment when a cation and anion are mixed together. 2. Which abbreviation will you use to indicate there was no visible change when a cation and anion were mixed? 3. How many drops of anion are placed into a well in the well plate? 4. List the cations used in this experiment.

Among the given options, the molecule with a linear molecular geometry is HCN. Therefore, the correct option is 5.HCN.

The molecular geometry of a molecule is determined by the arrangement of its atoms in three-dimensional space. A molecule with a linear molecular geometry will have all its atoms in a straight line.

Now let's analyze each option:

1. H₂O: This molecule has a bent or V-shaped molecular geometry due to the presence of two lone pairs of electrons on the central oxygen atom. It is not linear.

2. SO₂: This molecule has a bent or V-shaped molecular geometry. The sulfur atom is surrounded by two oxygen atoms, and it also has one lone pair of electrons. It is not linear.

3. All of the molecules listed: This option suggests that all the molecules listed would have a linear molecular geometry. However, we have already determined that H₂O and SO₂ do not have a linear geometry, so this option is incorrect.

4. None of the molecules listed: This option suggests that none of the molecules listed would have a linear molecular geometry. Since H₂O and SO₂ do not have linear geometry, this option is correct.

5. HCN: This molecule has a linear molecular geometry. It consists of a carbon atom bonded to a hydrogen atom and a nitrogen atom, with a triple bond between carbon and nitrogen. The atoms are arranged in a straight line.

So, the correct option is 5.HCN.

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Finding electrons is a fundamental concept in the study of physics and chemistry. Electrons are the negatively charged particles that orbit the nucleus of an atom. They are the building blocks of matter and are responsible for many of the properties and behavior of materials.

One way to find electrons is through a cathode ray tube. A cathode ray tube is a device that uses an electric current to create a stream of electrons that can be directed toward a screen. This is the basic principle behind old-fashioned televisions and computer monitors. The electrons in the cathode ray tube cause the phosphors on the screen to glow, creating the image we see.

Another way to find electrons is through a scanning electron microscope. A scanning electron microscope is an instrument that uses a beam of electrons to produce high-resolution images of the surface of a material. This allows scientists to see the details of the surface at a tiny scale and to study the properties of electrons on the surface.

A third way to find electrons is through a particle accelerator. A particle accelerator is a machine that uses high-energy electromagnetic fields to accelerate particles, such as electrons, to very high speeds. These high-speed electrons can then be directed toward a target, where they can be used to study the properties of atoms and molecules.

Overall, there are many ways to find electrons and study their properties, from the cathode ray tube, scanning electron microscope, and particle accelerator, to other methods such as electron diffraction and electron microscopy. Each method offers different advantages and allows scientists to study electrons differently.

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Molecule (a or b) in each pair has the higher boiling point also indicate force, hydrogen bonding (h), dipolar (p), or dispersion (d) is responsible for the difference so in NH₃ and PH₃ the a molecule is high melting point and forces are dispersion force and in C₂H₅OH and CH₃OHCH₃ the molecule a has high melting point and has a dispersion force and C₄H₈ and C₁₀H₂₀ the b molecule has high melting point and has a dispersion force and in HCl and F₂ the a molecule has high boiling point and has a dipolar dipole interaction forces

The forces are electrostatic force between oppositely charged ions as in ionic bonds or through the sharing of electrons as in covalent bonds and there are four type of forces

So here given molecule in that we have to seen the forces and high melting point so

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Answer:

Sometimes peoples like to say that atom is like a cell in living things,is it true?comment below,letss goo!!

Explanation:

A greek philosopher known as Democritus was the first to consider the idea that matter is made up of small particles ,about 400BC.

Since there was no experimental evidence to support his idea,it was not accepted.

About 2000 years later an English man called John Dalton revived the discussion.He used experimental evidence to support his idea to convince people that matter is made up of particles called atoms.It accepted!.

An English man called John Dalton revived the discussion.He used experimental evidence to support his idea to convince people that matter is made up of particles called atoms.It was accepted ,he conclude the following theories: